The equation of the plane in general form is: 2x - 16y - 16z + 16t + 416 = 0
How to find the equation of a plane?
To find the equation of a plane passing through a point and perpendicular to a vector, we can use the point-normal form of the equation of a plane:
Ax + By + Cz = D
where (A, B, C) is the normal vector to the plane, and (x, y, z) is any point on the plane.
In this case, the point given is (8t, 8 – t, 9 + 3t), and the vector perpendicular to the plane is (2, 0, 1).
First, we need to find the normal vector to the plane. We can do this by taking the cross product of the given vector and the vector formed by the line:
(2, 0, 1) x ((8, -1, 0) - (0, 8, 9)) = (2, -16, -16)
Now we can use the point-normal form with the given point and the normal vector we just found:
2x - 16y - 16z = D
To find the value of D, we can substitute in the coordinates of the given point:
2(8t) - 16(8 - t) - 16(9 + 3t) = D
16t - 128 + 16t - 288 - 48t = D
-16t - 416 = D
So the equation of the plane in general form is: 2x - 16y - 16z + 16t + 416 = 0
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PLS HELP AND FAST!!! also it needs to be simplified!!
Answer:
I think it's B because the bigger numbers stay the same an u subtract the smaller numbers
What is the highest power of 2 that is less than 1000? Enter result of 2
∧
N, not just the power N. Question 4 Express this hexadecimal number in decimal: 4AF
Question 1: The highest power of 2 that is less than 1000 is 2^9 = 512.
Question 4: The decimal equivalent of the hexadecimal number 4AF is 1199.
Question 1: What is the highest power of 2 that is less than 1000?
We know that,
2^ {10} = 1024 which is the smallest number greater than 1000.
Therefore, the highest power of 2 that is less than 1000 is 2^ 9
2^ (9) = 512
Question 2: Express this hexadecimal number in decimal: 4AF
To convert hexadecimal number to decimal number, we multiply each digit of the hexadecimal number by its place value and add the products. We can start from the right and work our way to the left.
4AF in hexadecimal is equal to:
(4 × 16²) + (10 × 16¹) + (15 × 16⁰)
= 1024 + 160 + 15
= 1199
Therefore, the decimal equivalent of the hexadecimal number 4AF is 1199.
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If 7x + 6y = 8 is a true equation, what would be the value of 7x + 6y - 5?
Answer:
I’m going to guess and say that it’s 3? Not sure sorry!
there are 3,681 students at west school. Three grades attend this school. There are the same number of students in each grade. How many students are in each grade.
Answer:
1,227
Step-by-step explanation:
3,000 divided by 3 is 1,000
600 divided by 3 is 200
80 divided by 3 is 26 r2
1 + r2 =3
and 3 divided by 3 is 1
1,000 + 200 + 26 + 1 = 1,227
What is the slope of the line that models this situation
Answer:
-6.67
Step-by-step explanation:
slope is change in y/change in x so using (4, 60) and (1, 80), the slope is:
\(\frac{80-60}{1-4} =\frac{-20}{3} =-6.67\)
\(3x-y=17\\x+4y=10\) how can you tell that there is only one solution
Ahmad starts hiking at an elevation of -50 feet and then stops to the rest at the elevation of 85 ft. which expression represents in elevation from start to his resting place. 50-85. -50-85. -85-(-50). 85-50
Answer: 50 + 80 = 130 So the answer would be |-85-(-50)|.
Use conditional proof and the eighteen rules of inference to derive the conclusions of the following symbolized arguments. Having done so, attempt to derive the conclusions without using conditional proof.
1. N ⊃ O
2. N ⊃ P / N ⊃ (O • P)
The conclusion of the symbolised argument is that N implies (O and P). This can be proven using conditional proof and the eighteen rules of inference, or using the rule of conjunctive simplification.
The symbolic argument's conclusion is that N implies (O and P). This can be demonstrated using conditional proof and the eighteen inference rules.
Proof:
1. N ⊃ O (Premise)
2. N ⊃ P (Premise)
3. N (Assumption)
4. O (1,3 Modus Ponens)
5. P (2,3 Modus Ponens)
6. O•P (4,5 Conjunction)
7. N ⊃ (O•P) (3-6 Conditional Proof)
8. N ⊃ (O•P) (2,7 Disjunctive Syllogism)
This leads us to the conclusion that N implies (O and P).
Without the use of conditional proof, the identical result can be reached. The conjunctive simplification rule can be used to do this.
Proof:
1. N ⊃ O (Premise)
2. N ⊃ P (Premise)
3. N (Assumption)
4. O (1,3 Modus Ponens)
5. P (2,3 Modus Ponens)
6. O•P (4,5 Conjunction)
7. N ⊃ (O•P) (Conjunctive Simplification)
Therefore, we have derived the conclusion that N implies (O and P).
Complete Question:
Use conditional proof and the eighteen rules of inference to derive the conclusions of the following symbolized arguments. Having done so, attempt to derive the conclusions without using conditional proof.
1. N ⊃ O
2. N ⊃ P / N ⊃ (O • P)
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Which is a stretch of an exponential growth function?
Of(x) =
22
(x)
3
2.
=
O f(x) =)
O f(x)=
O fx) =
2
312
Which is a stretch of an exponential growth function?
A stretch of an exponential growth function is one that contains a constant factor that affects the rate of growth. Of the three functions given, only O fx) = 2^312 meets this criteria.
To determine which of these functions is a stretch of an exponential growth function, we need to look for the presence of a constant factor or coefficient that affects the rate of growth. In the first function, Of(x) = 22(x)3, we see that there is no constant factor present. The base of the exponential function is simply 2, which means that the rate of growth is constant and does not change.
Similarly, in the second function, Of(x) = 3, there is no exponential term present, and therefore no growth or decay is occurring. This function simply returns a constant value of 3 for any input value of x.
In the third function, Of(x) = 2^312, we see that there is a constant factor present in the base of the exponential function. This means that the rate of growth is being affected by this factor, resulting in a steeper curve than the first two functions. Therefore, O fx) = 2^312 is a stretch of an exponential growth function.
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The correct expression for an exponential growth function with a stretch is Of(x) = 2^12x.
Explanation:
The correct expression for an exponential growth function is Of(x) = 212x.
This is because the exponent, 12x, represents the rate at which the function is growing.
A larger value for the exponent results in a steeper growth rate, which indicates a stretch of the exponential growth function.
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Which compound inequality has a solution set of all real numbers?
x > -2 or x < 1
x < -1 and x > 2
x > -4 and x < 5
x < -3 or x > -2
The compound inequality that has a solution set of all real numbers is: x > -2 or x < 1
A mathematical expression known as a compound inequality consists of two or more inequalities linked together by the logical operators "and" or "or." It represents a set of values that simultaneously meet each of the stated inequalities. Take the compound inequality 2x + 3 7 and x - 4 > -2, for instance. We treat this compound inequality as two separate inequalities, 2x + 3 7 and x - 4 > -2, in order to solve it. We first determine the intersection of the solution sets after solving each inequality separately. The values of x in this situation that meet both inequality are: 0 x 3.
1. A compound inequality is an inequality that combines two or more simple inequalities using the words "and" or "or."
2. The solution set of all real numbers means that any number on the number line is a solution to the inequality.
3. In the given inequality, x > -2 or x < 1, we have two simple inequalities connected by "or."
4. If x > -2, we have all numbers greater than -2 (to the right of -2 on the number line) as solutions.
5. If x < 1, we have all numbers less than 1 (to the left of 1 on the number line) as solutions.
6. Since we're using "or," a number only needs to satisfy one of these conditions to be a solution. So, all real numbers satisfy either x > -2 or x < 1, making this the compound inequality with a solution set of all real numbers.
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match the values with the statistical measures for these data points.
34, 37, 39, 32, 48, 45, 53, 62, 58, 61, 60, 41
46.5
62
34
59
48
60
32
38
upper quartile
arrowRight
maximum
arrowRight
minimum
arrowRight
lower quartile
arrowRight
median
arrowRight
Answer:
lower quartile - 38
upper quartile - 59
maximum - 62
median - 46.5
minimum - 32
I hope this help. Have a great day!
Graph the system of equations. y = 2x y = –x + 6 Two lines on a coordinate plane that intersect at the point 2 comma 4. One line has y intercept 0 and the other has y intercept 6. Two lines on a coordinate plane that intersect at the point negative 2 comma negative 4. One line has y intercept 0 and the other has y intercept negative 6. Two lines on a coordinate plane that intersect at the point 1 comma 2. One line has y intercept 0 and the other has y intercept 3. Two lines on a coordinate plane that intersect at the point 3 comma 3. One line has y intercept 0 and the other has y intercept 6.
The solution to the systems of equations graphically is (2, 4)
Solving the systems of equations graphicallyFrom the question, we have the following parameters that can be used in our computation:
y = 2x
y = -x + 6
Next, we plot the graph of the system of the equations
See attachment for the graph
From the graph, we have solution to the system to be the point of intersection of the lines
This points are located at (2, 4)
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Can you please match the number and explain thank you your saving a grade
Answer:
3/5
Step-by-step explanation:
put into fraction form: 21/35
21/35 (divide by 7/7)
3/5
Answer:
We just have to make the ratio into a fraction and simplify:
\(21:35=\frac{21}{35}=\frac{3}{5}\)
\(12:15=\frac{12}{15} =\frac{4}{5}\)
\(8:20=\frac{8}{20}=\frac{2}{5}\)
\(2:10=\frac{2}{10} =\frac{1}{5}\)
plsssssssssss help me
Answer: 40
Step-by-step explanation:
38+ 52=90
230-90=40
The equation exdydx=yexdydx=y is linear, but dydx+x2exy=exdydx+x2exy=ex is not linear.
It has proved that the equation \(e^{(x)} * (dy/dx) = y * e^{(x)} * (dy/dx)\) is linear and the equation \((dy/dx) + x^2 * e^{(x)} * y = e^{(x)}\) is not linear.
The equation \(e^{(x)} * (dy/dx) = y * e^{(x)} * (dy/dx)\) is linear because it can be written in the standard form of a linear first-order ordinary differential equation, which is:
dy/dx + P(x) * y = Q(x)
In this case, we can divide both sides of the equation by \(e^{(x)}\) to obtain:
dy/dx = y * (dy/dx)
Now, we can compare this to the standard form and observe that P(x) = 0 and Q(x) = y * (dy/dx).
Since the equation is in the standard form, it is linear.
On the other hand, the equation \((dy/dx) + x^2 * e^{(x)} * y = e^{(x)}\) is not linear.
While it may seem similar to the standard linear form, the presence of the \(x^2 * e^{(x)} * y\) term is what makes it non-linear.
In a linear equation, the term involving y should be of the form P(x) * y, where P(x) is a function of x only.
However, in this case, the term \(x^2 * e^{(x)} * y\) involves both x and y, making the equation non-linear.
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2. Use mathematical induction to show that n(n+1)(2n+1) is divisible by 6 for all positive integers n.
The given statement: n(n+1)(2n+1) is divisible by 6 for all positive integers n.
Step-by-step explanation: We need to prove that n(n+1)(2n+1) is divisible by 6 for all positive integers n using mathematical induction.
Step 1: First, lets prove the statement for the smallest possible value of n. The smallest value of n is 1. So, let's check whether the given statement is true for n = 1 or not.
\(LHS = 1(1+1)(2*1+1) = 6\)
It is divisible by 6. Hence, the statement is true for n=1.
Step 2: Let's assume that the statement is true for n=k. So, we can say that n(n+1)(2n+1) is divisible by 6 for n=k. i.e., n(n+1)(2n+1) = 6a (for some integer a).
Step 3: We need to prove the statement is true for n=k+1.
So, we need to prove that (k+1){(k+1)+1}[2(k+1)+1] is divisible by 6
Using the assumption we made in step 2.
\(LHS = (k+1){(k+2)}[2k+3] = (k+1)(k+2)(2k+3)LHS = (2k+3)k(k+1)(k+2)LHS = 2[k(k+1)(k+2)] + 3[k(k+1)]\)
Now, k(k+1)(k+2) is divisible by 6 using the assumption made in step 2.
So, LHS = 2[k(k+1)(k+2)] + 3[k(k+1)] is also divisible by 6.
Hence, the statement is true for n=k+1.
Step 4: Using steps 1 to 3, we can say that the given statement is true for n=1 and if it is true for n=k, then it is also true for n=k+1.
Hence, by mathematical induction, we can say that the statement is true for all positive integers n.
Hence, it is proved that n(n+1)(2n+1) is divisible by 6 for all positive integers n.
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54 is 32% of what number? Round to the nearest hundredth if necessary.
Answer:
The answer 168.75 without rounding and rounding its also 168.75
Find the missing side lengths
Answer:
x = 11√3
y = 11
Step-by-step explanation:
Let 60 be the reference angle
sin 60 = p/h
√3/2 = x/22
or, 22√3 = 2x
or, x = (22√3)/2
so, x = 11√3
now
\(h^2 = p^2 + b^2\\or, 22^2 = (11\sqrt{3} )^2+y^2\\or, 484 = 363 + y^2\\or, 484-363 = y^2\\or, 121 = y^2\\or, \sqrt{121} = y\\so, y = 11\)
in how many positive four-digit integers that are not multiples of $1111$ do the digits form an arithmetic sequence? (the digits must form an arithmetic sequence, in order. for example, the number $5137$ does not count.)
$8\times9\times8\times9 = 5184$
There are a total of $8\times9\times8\times9 = 5184$ positive four-digit integers that are not multiples of 1111 and form an arithmetic sequence. To explain further, the first digit can be any integer from 1 to 8 (not 0 as the number must be four-digits long). Once the first digit is chosen, the second digit can be any integer from 1 to 9. Once both the first and second digits are chosen, the third digit can be any integer from 1 to 8, and finally the fourth digit can be any integer from 1 to 9. Therefore, the total number of four-digit integers that are not multiples of 1111 and form an arithmetic sequence is $8\times9\times8\times9 = 5184$.
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If f(x)=8^x and g(x) =9 , what is (f divided g ) (x)
A.8^x-9
B.8^x/9
C.(8/9)^x
D.9(8^x)
Answer:
f(x) / g(x) = 8^x / 9 --> B
Step-by-step explanation:
You just need to plug in the values
Answer:
B. 8^2/-9
Step-by-step explanation:
I think the first guy is right
Find the solution of the system of equations. -4x - y = -28
x+y=4
The solutions of the system of equations are 8 and -4.
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
Example:
2x + 4 = 9 is an equation.
We have,
-4x - y = -28 _____(1)
x + y = 4 _____(2)
x = 4 - y _____(3)
Substituting (3) in (1) we get,
-4(4 - y) - y = -28
-16 + 4y - y = -28
-16 + 3y = -28
3y = -28 + 16
3y = -12
y = -4
Substituting y = -4 in (3) we get,
x = 4 - (-4)
x = 4 + 4
x = 8
Thus,
The value of x is 8.
The value of y is -4.
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3 cards are drawn from a standard deck without replacement. what is the probability that at least one of the cards drawn is a 3? express your answer as a fraction or a decimal number rounded to four decimal places.
When drawing 3 cards from a standard deck without replacement, there is approximately a 16.60% chance of drawing at least one 3 card.
The probability of drawing at least one 3 card from a standard deck of 52 cards without replacement can be calculated using the concept of complementary probability.
We can find the probability of not drawing any 3 cards and subtract it from 1 to get the probability of drawing at least one 3 card.
To find the probability of not drawing any 3 cards, we first determine the number of ways to choose 3 cards from the 52-card deck without replacement, which is denoted as C(52, 3) or "52 choose 3." This can be calculated as:
C(52, 3) = 52! / (3! * (52-3)!) = 22,100.
Now, let's determine the number of ways to choose 3 cards from the 49 non-3 cards in the deck, which is denoted as C(49, 3) or "49 choose 3." This can be calculated as:
C(49, 3) = 49! / (3! * (49-3)!) = 18,424.
Therefore, the probability of not drawing any 3 cards is given by:
P(not drawing any 3 cards) = C(49, 3) / C(52, 3) = 18,424 / 22,100 = 0.8340 (rounded to four decimal places).
Since we want the probability of drawing at least one 3 card, we can subtract the probability of not drawing any 3 cards from 1:
P(at least one 3 card) = 1 - P(not drawing any 3 cards) = 1 - 0.8340 = 0.1660 (rounded to four decimal places).
Therefore, the probability that at least one of the cards drawn is a 3 is approximately 0.1660 or 16.60%.
To summarize, when drawing 3 cards from a standard deck without replacement, there is approximately a 16.60% chance of drawing at least one 3 card.
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If a test has 40 questions and you get 200 points for the whole test, how many points are each question worth?
Answer:
5
Step-by-step explanation:
To find the points for each question, you must divide the number of points (200) by the number of questions (40) to get the number of points for each question
\(\frac{200}{40}\)
Divide 200 by 40 to get
\(\frac{5}{1}\) or \(5\)
Hope this helps. If you have any follow-up questions, feel free to ask.
Have a great day!
Answer:
5 points
Step-by-step explanation:
200points / 40 questions = 5points/1question
then:
1 questión worths 5 points
Carson invested $3,900 in an account paying an interest rate of 2.1% compounded
monthly. Assuming no deposits or withdrawals are made, how much money, to the
nearest ten dollars, would be in the account after 14 years?
Answer:
5230
Step-by-step explanation:
The amount of money in Carson's account after 14 years would be $5231.6
What is compound interest?"Compound interest is the interest which is calculated from the original principal plus accumulated interest."
The formula to calculate the compound interest:\(A=P(1+\frac{r}{n} )^{nt}\)
where,
A : Final amount
P : Initial amount (principal)
R : interest rate in percentage
r : interest rate (R/100)
n: number of times the interest is compounded
t : the overall tenure
For given question,
P = $3900, R = 2.1%, n = 12 (as compounded monthly), t = 14
for R = 2.1%,
\(r=\frac{2.1}{100} \\r=0.021\)
Now, we need to find the value of A.
Using the formula of compound interest,
⇒ \(A=3900 \times (1+\frac{0.021}{12} )^{12\times 14}\)
⇒ \(A=3900\times (1+0.00175)^{168}\)
⇒ \(A=3900\times(1.00175)^{168}\)
⇒ \(A=3900\times 1.3414\)
⇒ \(A=5231.61\)
⇒ \(A\approx \$ 5231.6\)
Hence, there would be $5231.6 in the account after 14 years.
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Can someone help me make sense of the problem. Provide an explanation and answer if at all possible
Answer:
1.728×10¹⁵
Step-by-step explanation:
You may recall from 3rd grade that multiplying by 10 adds a zero to the right of a number (moves the decimal point 1 place to the right).
An exponent is used to signify repeated multiplication. These facts together are used to translate to/from scientific notation.
10 = 1 × 10
100 = 1 × 10 × 10 = 1 × 10²
__
Continuing in like fashion, 5.4×10⁸ represents 5.4 × (1 followed by 8 zeros).
Similarly, 3.2×10⁶ = 3.2 × (1 followed by 6 zeros)
The product will be ...
(5.4×10⁸)×(3.2×10⁶) = (5.4×3.2) × (1 followed by 8+6 = 14 zeros)
= 17.28 × 10¹⁴
= (1.728 × 10) × 10¹⁴ . . . moving the decimal point so there's 1 digit to its left
Adding that extra zero into the count we already have, this becomes ...
= 1.728×10¹⁵
_____
Additional comment
Your scientific or graphing calculator will have a mode for showing numbers in scientific notation. You can enter these numbers directly into your calculator and have it show you the result in scientific notation.
Or, you can use a spreadsheet with appropriate output cell formatting.
Answer:
1.728×10¹⁵ is the answer
the following table contains figures on the monthly volume and unit costs for a random sample of 16 items from a list of 2,000 inventory items. the company classifies products with annual dollar volume of $10,000 or more as a items and products with annual dollar volume of $2,000 or less as c items. a) develop an abc classification for these items. a file labeled abc data.csv is available on t-learn. b) what is the percentage of items stocked in each classification group?
A: 75% of items are classified as C items, 18.75% as B items, and 6.25% as A items.
A-B-C examination is an instrument utilized for stock administration, which orders things into three classifications: A, B, and C, in light of their worth and significance. Classification A things have a high worth however a low volume, and their administration requires close consideration and control. Class B things have moderate worth and volume and require moderate control. Classification C things have a low worth yet a high volume, and their administration can be loose. The reason for the examination is to recognize which things need the most consideration and control, and which things can be dealt with less consideration and cost-actually. The examination assists in streamlining with reviewing levels, decreasing expenses, and expanding benefits.
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21. Let a and b be real numbers. If
(a+bi)-(3-5i) = 7-4i,
what are the values of a and b?
A. a-10, b=-9
B. a 10, b=1
C. a=4, b=-9
D. a=4, b=1
Answer:
A. a = 10, b = -9
Step-by-step explanation:
Pre-SolvingWe are given:
(a+bi)-(3-5i) = 7-4i
We know that a and b are both real numbers, and we want to find what a and b are.
SolvingFor imaginary numbers, a is the real part, and bi is the imaginary part. This means that we consider the real numbers like terms, and the imaginary numbers like terms.
So to start, we can open the equation to become:
a + bi - 3 + 5i = 7 - 4i
Based on what we mentioned above:
a - 3 = 7
+ 3 +3
_____________
a = 10
And:
bi + 5i = -4i
-5i -5i
____________j
bi = -9i
Divide both sides by i.
bi = -9i
÷i ÷i
_________
b = -9
So, a = 10, b= -9. The answer is A.
6 cm
6cm
6 cm
5 cm
4 cm
8cm
Solid B
Solid A
Which of the above solids has the larger surface area?
O O A. Solid A
O
B. Solid B
C. They have the same surface area.
Answer:
Solid A
Step-by-step explanation:
Surface area of a cube: 6 x a², where a is the side.
= 6 x 6²
= 6 x 36
= 216 cm²
Surface area of the cuboid/rectangular prism: 2(lw + wh + lh), where l is the length, w is the width, h is height.
= 2((5 x 4) + (4 x 8) + (5 x 8))
= 2(20 + 32 + 40)
= 2(92)
= 184 cm²
Therefore, Solid A has the larger surface area compared to Solid B.
Develop a POQ solution and calculate total relevant costs for the data in the following table.
Period 1 2 3 4 5 6 7 8 9 10 11 12
Gross requirements 30 40 30 70 20 10 80 50
fill in the table and calculate total costs.
*Holding cost =$ 3.50 / unit/week; setup cost =$ 200 ; lead time =1 week; beginning inventory =40 . a lot-for-lot solution (enter your responses as whole numbers).
Using the information provided in the table, The total holding cost is $547.50, the total setup cost is $600 and the total cost is $1,147.50.
How to calculate the total costTo develop a POQ (Periodic Order Quantity) solution use a lot-for-lot solution, which means that we will order exactly what we need for each period.
The missing values can be found on the attached table.
From the table, the total holding cost which is the sum of the holding costs for all periods is $547.50 while the total setup cost which is the sum of the setup costs for all periods is $600.
Therefore, the total cost is the sum of the holding cost and the setup cost and it is calculated as $1,147.50.
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A clock face a circumference of 166 cm. what is the diameter
Answer: Approximately 52.87 cm.
Step-by-step explanation:
Circumference is diameter times pie to divide the circumference by pie.
166/3.14 use 3.14 as an approximation for pie.
166/3.14 = 52.87 rounded to the nearest hundredth
The answer should be 52.8662420382cm you can round however needed
diamete = circumferance divided by pi