Find the error(s). After finding the student’s error(s) you do not need to solve the triangle. A student uses the triangle shown to calculate m

Answer:

112

Step-by-step explanation:

To find the area, you must multiply the width and the length. 14 times 8 is 112.

The probability of seeing a shooting star during the first 15 minutes of the hour is approximately 19.95%

To solve this problem, we need to use conditional probability. We want to find the probability of seeing a shooting star during the first 15 minutes of the hour given that the chances of seeing a shooting star in any given hour are 80%.

First, we need to determine the probability of seeing a shooting star in the first 15 minutes of the hour. Since the probability is uniform for the entire hour, we can assume that the probability of seeing a shooting star in any given minute is 80% divided by 60 (the number of minutes in an hour), which is approximately 1.33%.

To find the probability of seeing a shooting star during the first 15 minutes of the hour, we need to add up the probabilities of seeing a shooting star in each of the 15 minutes. This can be calculated as follows:

P(seeing a shooting star in the first 15 minutes) = P(seeing a shooting star in minute 1) + P(seeing a shooting star in minute 2) + ... + P(seeing a shooting star in minute 15)
= 15 x 1.33%
= 19.95%

Therefore, the probability of seeing a shooting star during the first 15 minutes of the hour is approximately 19.95%. This means that if you go out star gazing again and the chances of seeing a shooting star are 80%, there is a 19.95% chance that you will see one during the first 15 minutes of the hour you are out.

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The alternating series error bound is 0.05.

Firstly, let us recall what the alternating series means. An alternating series is a series whose terms are alternatively positive and negative. Mathematically, an alternating series is represented as:

s = a1 - a2 + a3 - a4 + a5 - ...

Where a1, a2, a3, ... are positive real numbers.

Now, let us suppose that the alternating series converges to a limit s. In that case, we know that the sequence of partial sums {Sn} converges to s as well. Mathematically, we can represent this as:

lim n→∞ Sn = s

In the question, we are given the values of the partial sum for four values of n. Let us suppose that these values are:

s2 = 2

s4 = 3.1

s6 = 3.45

s8 = 3.55

Therefore, we know that |a9| is less than or equal to |a8|. Mathematically, we can represent this as:

|a9| <= |a8|

Therefore, the alternating series error bound is given by:

|s - s8| <= |a9| <= |a8|

Now, to determine the error bound, we need to find the value of |a8|. To do this, we can use the fact that:

a8 = s9 - s8

From the values given in the table, we know that s9 = 3.6. Therefore,

|a8| = |s9 - s8| = |3.6 - 3.55| = 0.05

This means that if we use s8 to approximate the value of the series, the actual value of the series is within 0.05 of the approximation.

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The probability of not selecting a green marble is equal to the total number of non-green marbles in the bag divided by the total number of marbles in the bag.

To calculate the probability: there are three green marbles out of a total of twenty-five marbles, so the probability of selecting a green marble is 3/25.

The likelihood of not selecting a green marble is then 1 - 3/25 = 22/25.

This is equal to 22/25 * 100 = 88% as a percentage.

As a result, P(not green) = 88%

Probability denotes the possibility of something happening. It is a mathematical branch that deals with the onset of a random event. The value ranges from zero to one. Probability has been tried to introduce in mathematics to predict the probability of events occurring. Probability is defined as the degree to which something is likely to occur. This is the fundamental probability theory, which is also used in probability distribution, in which you will learn about the possible outcomes of a random experiment.

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i cant see anything

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

Answer:

x = -1/7

Step-by-step explanation:

Solve for x

9-17x-5-4x=7

Combine like terms

-21x +4 = 7

Subtract 4 from each side

-21x-4+4 = 7-4

-21x = 3

Divide each side by -21

-21x/-21 = 3/-21

x = -1/7

Check

9 - 17(-1/7) -5 -4(-1/7) =7

9 + 17/7 -5 + 4/7 =7

4 +21/7 = 7

4+3 = 7

7=7

Answer: Samantha is 13 years old and Jennifer’s age is 10 years old.

Because it said she was 3 years older, which means 13 +10 = 23.

Step-by-step explanation:

I think.

Samantha age is 7 years and Jennifer age is 4 years.

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

Samantha is 3 years older than Jennifer.

let Jennifer age be x.

So, Samantha age= x + 3

Now, The square of Jennifer's age plus Samantha's age is equal to 23.

x²+ (x+ 3) = 23

x² + x + 3 = 23

x² + x - 20 = 0

(x- 4) ( x + 5) = 0

x= 4, -5

Hence, Samantha age is 7 years and Jennifer age is 4 years.

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Answer:

x=10

Step-by-step explanation:

18x=180

x=10

if my answer helps please mark as brainliest.

Answer:

Step-by-step explanation:

7(c-13)

the product of 7, and, c-13

Answer: c7-7 13

13 is smaller and is right next to the 7

Step-by-step explanation:

7(c-13)

c7-7 13

Answer:

\(\bold{f(x)=-\frac{1}{2}}\)

Step-by-step explanation:

\(f(x)= x^2-\frac{3}{2}\)              replace x with -1

\(f(x)= -1^2-\frac{3}{2}\)           solve exponents

-1² = -1 × -1 = 1

\(f(x)= 1-\frac{3}{2}\)                subtract

\(\bold{f(x)=-\frac{1}{2}}\)

AB is not perpendicular to CD

Perpendicular lines are two separate lines that cross one other at a right angle, or a 90° angle. Example: Because AB and XY overlap at a 90° angle, AB is perpendicular to XY in this instance.

Lines that cross one other at an angle are known as perpendicular lines. Their slopes are the reciprocal opposites of one another.

Given A (-2, 4, 0),B(1, 1, 1),C(2, 3, 4),D (3, 21, -8)

(-1,3,-1) for AB

(-1,-18,12) for CD

For the lines AB and CD to be perpendicular

a 1a2+b1b2+c1c2=0

-1(-1)+3(-18)+(-1)(12)

=1-54−12=-65not equal to 0

∴ AB not perpendicular to CD

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Answer:

hence the required minimum production level is 12units

Step-by-step explanation:

Given the cost function expressed as c(x) = x^3 - 24x^2 + 30,000x

The average cost function will be c(x)/x

Dividing the cost function through by x

Average cost function = c(x)/x = x³/x - 24x²/x + 30,000x/x

Average cost function = x²-24x + 30,000

A(x) = x²-24x + 30,000

If the average cost is minimized, hence dA/dx = 0

dA/dx = 2x - 24

0 = 2x - 24

-2x = -24

Divide both sides by -2

-2x/-2 = -24/-2

x = 12

For the second deriviative

d²A/dx² = 2 which is greater than zero

Hence a production level that will minimize the average cost per item of making x items is 12

The production level that will minimize the average cost per item of making x items is  x = 12

To find the minimum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

Putting those values of x in the second rate of function, if results in negative output, then at that point, there is maxima. If the output is positive then its minima and if its 0, then we will have to find the third derivative (if it exists) and so on.

For this case, the function in consideration is: \(c(x) = x^3 - 24x^2 + 30000x\)

This is cost function for x items' manufacturing.

The average cost per item would be c(x) / x

This gives us a function a(x) as:

\(a(x) = c(x)/x = x^2 -24x + 30000\)

For finding  the minimum of a(x), getting its first two derivatives as:

\(a'(x) = 2x - 24\\a''(x) = 2 > 0\)

Equating first rate to 0,

\(a'(x) = 2x - 24 = 0\) critical point.

Since second rate is positive, the point x = 12 is point of minima, and since only one critical point is there, it is the point on which a(x) is minimum.

Thus, the production level that will minimize the average cost per item of making x items is  x = 12

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The steps to algebraically solve a system of linear and quadratic equations involve solving each equation for y, solving for x, setting the two equations equal to each other, and inserting the x value back into one of the equations to find the corresponding y value.

1. To algebraically solve a system of linear and quadratic equations, the following steps can be used: 1) Solve each equation for y. 2) Solve for x. 3) Set the two equations equal to each other. 4) Insert the value of x back into one of the equations to find the corresponding y value.

2. To begin solving a system of linear and quadratic equations, it is often helpful to isolate the variable y in both equations. This involves rearranging the equations so that y is on one side and all other terms are on the other side. Once both equations are solved for y, we can move on to the next step.

3. The next step is to solve for x. With the equations in terms of y, we can substitute one equation into the other, setting them equal to each other. This allows us to eliminate the variable y and solve for x. By solving the resulting equation, we obtain the value of x.

4. After finding the value of x, we can proceed to the final step. We substitute this x value back into one of the original equations to determine the corresponding y value. This completes the process of solving the system of equations, providing us with the solution in terms of x and y.

5. In summary, the steps to algebraically solve a system of linear and quadratic equations involve solving each equation for y, solving for x, setting the two equations equal to each other, and inserting the x value back into one of the equations to find the corresponding y value. These steps help in finding the values of x and y that satisfy both equations simultaneously, giving the solution to the system of equations.

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The answer is 3 to the 3/4 power.

To prove that g is abelian, we need to show that for any two elements a and b in g, ab = ba.

Given that n is normal to g, it means that for any element g' in g and any element n' in n, the product g'n'g^(-1) is also in n. (Definition of normality)

We are given that the quotient group g/n is isomorphic to the group Z/5Z. This means that g/n has the same structure as Z/5Z, and elements in g/n can be represented by residue classes modulo 5.

Similarly, since n is isomorphic to Z/2Z, elements in n can be represented by residue classes modulo 2.

Let's consider two elements a and b in g. These elements can be written as a = gn1 and b = gn2, where n1 and n2 are elements in n.

Using the isomorphism between g/n and Z/5Z, we can write a and b as a = g' + 5Z and b = g'' + 5Z, where g' and g'' are residue classes modulo 5.

Similarly, using the isomorphism between n and Z/2Z, we can write n1 and n2 as n1 = z1 + 2Z and n2 = z2 + 2Z, where z1 and z2 are residue classes modulo 2.

Now, we can express a and b as a = g' + 5Z = (g' + z1 + 2Z) + 5Z = g'z1 + 10Z + 5Z = g'z1 + 15Z = g'z1 + 5Z = g'z1 + n1 and b = g'' + 5Z = (g'' + z2 + 2Z) + 5Z = g''z2 + 10Z + 5Z = g''z2 + 15Z = g''z2 + 5Z = g''z2 + n2.

Now, let's calculate the product ab = (g'z1 + n1)(g''z2 + n2). Since n is normal to g, we can use the fact that g'n'g^(-1) is in n for any g' in g and n' in n.

Using this fact, we can rewrite ab as (g'z1g''z2)(g'z1n2)(n1g''z2)(n1n2).

Since g'z1g''z2, g'z1n2, n1g''z2, and n1n2 are all in n, we can simplify ab as ab = (g'z1g''z2)(g'z1n2)(n1g''z2)(n1n2) = (g'z1)(g''z2)(g'z1)(n2)(n1)(g''z2)(n1)(n2).

We can regroup the terms to get ab = (g'z1)(g'z1)(g''z2)(g''z2)(n1)(n1)(n2)(n2).

Since the operation in g is associative, we can rearrange the terms to get ab = (g'g')z1z1(g''g'')z2z2(n1n1)(n2n2).

Since g' and g'' are residue classes modulo 5, and z1 and z2 are residue classes modulo 2, their products will also be residue classes modulo 5 and 2 respectively.

Additionally, since n1 and n2 are residue classes modulo 2, their products will be residue classes modulo 2.

Therefore, we can simplify ab as ab = (g'g')z1z1(g''g'')z2z2(n1n1)(n2n2) = g'g'z1z1g''g''z2z2n1n1n2n2.

Finally, since the operation in g is commutative, we have g'g' = g'g' and g''g'' = g''g'', and n1n1 = n1n1 and n2n2 = n2n2.

This simplifies ab as ab = g'g'z1z1g''g''z2z2n1n1n2n2 = g'g'z1z1g''g''z2z2n1n1n2n2 = g'z1g'z1g''z2g''z2n1n1n2n2.

Since g'z1g'z1g''z2g''z2n1n1n2n2 is an element in n, we can write ab as ab = g'z1g'z1g''z2g''z2n1n1n2n2 = g'z1g'z1g''z2g''z2 + n.

Notice that g'z1g'z1g''z2g''z2 is a product of residue classes modulo 5, and since the operation in Z/5Z is commutative, we have g'z1g'z1g''z2g''z2 = g'g'z1z1g''g''z2z2.

Therefore, ab = g'z1g'z1g''z2g''z2 + n = g'g'z1z1g''g''z2z2 + n = (g'g')(z1z1)(g''g'')(z2z2) + n.

Since g'g'z1z1g''g''z2z2 is an element in g, we can write ab as ab = (g'g')(z1z1)(g''g'')(z2z2) + n = (g'g')(z1z1)(g''g'')(z2z2) + n = (g'g')(z1z1)(g''g'')(z2z2)n.

The expression (g'g')(z1z1)(g''g'')(z2z2)n is a product of elements in g, and since the operation in g is commutative, we have (g'g')(z1z1)(g''g'')(z2z2)n = (g'g')(g''g'')(z1z1)(z2z2)n.

Since g'g' and g''g'' are residue classes modulo 5, and z1z1 and z2z2 are residue classes modulo 2, their products will also be residue classes modulo 5 and 2 respectively.

Additionally, since n is a subgroup of g, any element in n multiplied by an element in g will still be in n.

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Answer:

Triangle CED is congruent to Triangle CAB

Step-by-step explanation:

Took the test

The convolution of £^{3264+10) and [8] is [8] (1/(3264+10)e^(3264+10)u) + C.

To use the convolution theorem, we need to find the convolution of the given functions. Let's calculate them step by step:

(a) [+ {92+2} [8]

According to the convolution theorem, the convolution of two functions f(t) and g(t) is given by:

(f * g)(t) = ∫[f(u)g(t-u)]du

In this case, f(t) = [+ {92+2} and g(t) = [8]. Let's substitute these functions into the convolution integral:

([+ {92+2} * [8])(t) = ∫[+ {92+2}8]du

Since [8] is a constant function, we can simplify the integral:

([+ {92+2} * [8])(t) = [8] ∫[+ {92+2}]du

Now, let's perform the integral:

([+ {92+2} * [8])(t) = [8] ∫(9u + 2)du

= [8] (9∫u du + 2∫1 du)

= [8] (9(u^2/2) + 2u) + C

= [8] (9/2 u^2 + 2u) + C

Therefore, the convolution of [+ {92+2} and [8] is [+ {8(9/2 u^2 + 2u)}.

(b) £^{3264+10) ) [8]

Similarly, let's find the convolution of the given functions:

(£^{3264+10) * [8])(t) = [8] ∫[£^{3264+10)}(u)£^(t-u)]du

Since [8] is a constant function, we can simplify the integral:

(£^{3264+10) * [8])(t) = [8] ∫[£^{3264+10)}(u)]du

Now, let's perform the integral:

(£^{3264+10) * [8])(t) = [8] ∫(e^(3264+10)u)du

= [8] (1/(3264+10)e^(3264+10)u) + C

= [8] (1/(3264+10)e^(3264+10)u) + C

Therefore, the convolution of £^{3264+10) and [8] is [8] (1/(3264+10)e^(3264+10)u) + C.

Note: Please note that the convolution theorem is used to find the convolution of functions, which is a mathematical operation. It is not used to find specific numerical values. The expressions provided above represent the convolution of the given functions.

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Answer:

a. f = 72/p

b. 14.4

Step-by-step explanation:

a. bringing in constant k,

f = k/p

cross multiplying

k = fp

k = 8×9

k = 72

the formula for f;

f = 72/p

b. Using the formula for f

f = 72/p

f = 72/5

f = 14.4

Answer:

The slope would be 25/1 or 25.

Step-by-step explanation:

Use the formula y2-y1 over x2-x1. Or use rise over run.

Answer:

Hey buddy whatsup? All good

Coming to the question fig 1 and 3 aren't functions

Coz.... Reason for fig 1... Every distinct element of domain must have a unique element in codomain, but in this fig the same element has more than two unique elements which is a relation not a function.

Reason for fig 3 every element in domain must have an unique element in codomain but in this fig the element c doesn't have any unique element hence it isn't a function.....

Thank you

Answer:

fig 1 is not function because x-componet (A) has two range

Answer:

x = 5, x = 3

Step-by-step explanation:

Hello!

For the equation (x-5)(7x - 21) = 0, we can use the zero-product property to solve the equation.

The zero product property states that for factors when multiplied equal to 0, you can set each factor to 0 and solve for the variable inside.

Using this property, we can say:

The solutions are x = 5, and x = 3.

Answer:

5÷98=98/5 or.. 19 3/5

2÷72=1/36

9÷58=9/58

7÷82=7/82

Step-by-step explanation:

hope this helped!!<3

Answer:

14

Step-by-step explanation:

A trapezoid is a quadrilateral (has four sides and four angles) with a pair of opposite parallel sides. The pair of opposite parallel side is known as the base.

An isosceles trapezoid is a trapezoid with equal legs. The diagonals are also equal and both the upper and lower base angles are congruent.

From the question:

KV = IE = 2x + 6 (diagonals of a trapezoid are congruent)

From line segment addition postulate:

KV = KN + NV

substituting:

2x + 6 = 10 + x

2x + 6 - x = 10

x + 6 = 10

x = 10 - 6

x = 4

KV = 2x + 6

substituting x = 4:

KV = 2(4) + 6

KV = 14

False. To calculate a percent increase, the portion is not the missing element. The portion refers to the initial or original value, while the missing element is the final or increased value.

The formula for calculating a percent increase is:

Percent Increase = (Final Value - Initial Value) / Initial Value * 100

In this formula, the initial value is the portion that represents the starting or original value. The final value is the missing element, as it represents the increased or final value after the increase.

By subtracting the initial value from the final value, we obtain the difference between the two. Dividing this difference by the initial value gives us the relative increase as a decimal or fraction. Multiplying by 100 converts it into a percentage, representing the percent increase.

Therefore, the portion in calculating a percent increase is the known value or initial value, while the missing element is the final value that we are trying to determine or find.

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Step-by-step explanation:

the correct answer is option a 6a-7

The measures of dispersion mean , median , mode and range of the data are 3.79, 2, 2 and 9.75 respectively

The mean is the ratio of the sum of all the values and the number of values in the dataset .

The mean = (1 + 0.8 + 2 + 2.5 + 1.5 + 5 + 10 + 5.1 + 3 + 2.25 + 0.5 + 0.25 + 1.8 + 4.1 + 2 + 2 + 7) / 14 = 3.79

This is the middle value of the distribution after it has been rearranged in order of magnitude.

Rearranged data : 0.25, 0.5, 1, 1.5, 1.8, 2, 2, 2, 2.25, 3, 4.1, 5, 5.1, 7, 10

median = 2

This is the most frequently occurring value in the dataset . The modal value here is 2 with a frequency of 4

Mode = 2

This is the difference between the maximum and minimum values

Range = 10 - 0.25 = 9.75

Therefore, the range of the data is 9.75

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Answer:

\(\boxed {a_{24} = - 70}\)

Step-by-step explanation:

According to the following pattern sequence (\(-1, -4, -7, -10\) ), it is Arithmetic Sequence, because every negative number is subtracted by \(3\). So, to find the 24th term, you need to use the Arithmetic Sequence Formula and solve to find the 24th term:

\(a_{n} = a_{1} + (n - 1) d\)

\(a_{n}\): nth term in the sequence

\(a_{1}\): 1st term

\(n\): term position

\(d\): Common difference

-Apply to the formula:

\(a_{24} = -1 - 3 (24 - 1)\)

\(a_{n} = a_{24}\)

\(a_{1} = -1\)

\(n = 24\)

\(d = -3\)

-Solve:

\(a_{24} = -1 - 3 (24 - 1)\)

\(a_{24} = -1 - 3 (23)\)

\(a_{24} = -1 - 69\)

\(\boxed {a_{24} = - 70}\)

Therefore, the 24th term is \(-70\).

Answer:

x=16

Step-by-step explanation:

x+15=6x-65

x+80=6x

80=5x

16=x

hope this helps :P

Answer:

D

Step-by-step explanation:

I think