Find the domain & range of the relation

{(-5,13), (6,18), (2,-7), (1,4), (-3,-1)}

The approximate height of the pole in centimeters is 17,500 centimeters.

We have,

Let's start by calculating the total length of the pole, which is buried plus the part that protrudes from the ground.

We know that the part that protrudes is 25 meters and that it represents one-seventh of the total length.

25 = L/7

where L is the total length of the pole.

We can solve for L by multiplying both sides of the equation by 7:

L = 7 x 25

  = 175 meters

Now we need to convert this length to centimeters.

Since 1 meter is equal to 100 centimeters,

175 meters x 100

= 17,500 centimeters

Therefore,

The approximate height of the pole in centimeters is 17,500 centimeters.

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The complete question.

The Clarisse company, dedicated to the telephone business, is expanding its coverage, due to this, it is placing poles, where the seventh part of a pole is buried, and protrudes 25 meters from the ground. Calculate the approximate height of the pole in centimeters.

Answer:

5400

Step-by-step explanation:

Answer:

the answer is 2 :)

have a good day !!

Step-by-step explanation:

Answer:

6ft

Step-by-step explanation:

javahvpaiudbajbd;kjbzcuvbjkabr;kabga

Answer:

2 2/3 ft

Step-by-step explanation:

w = A/l

plug in the values

w = 16/6

solve.

2.6... = 2 2/3

therefore the width of the rug is 2 2/3 ft

The sum that Mahesh borrowed was Rs. 22,800, the interest that Mahesh has to pay was Rs. 6,492, the interest that Rakesh has to pay was Rs. 7,550, and the percentage by which Rakesh pays more interest than Mahesh was 16.3%.

a) Sum borrowed by Mahesh

Let us suppose that the principal sum borrowed by Mahesh from the bank at 9% per annum is Rs. x.

Hence, we can write that

Simple Interest = (P × R × T )/ 100

= (x × 9 × 3)/100

= 27x/100

Therefore, the amount that Mahesh has to pay after 3 years, including the interest, is

A = P + SI

= x + 27x/100

= 127x/100

Again, Mahesh invests the same amount of Rs. x to Rakesh at 10% per annum, which is compounded annually, for three years.

Hence, the total amount after three years that Rakesh has to pay Mahesh is:

Amount after 3 years = x (1 + R/100)³

= x (1 + 10/100)³ = 1.331 x

Therefore, Mahesh made a profit of Rs. 7,550 by investing Rs. x at 10% per annum, compounded annually, for three years.

Hence, we can write that

Compound Interest = Amount - Principal

CI = 1.331x - x = 0.331x

Therefore, 0.331x = Rs. 7,550=>

x = Rs. 22,800

Thus, Mahesh borrowed Rs. 22,800 from the bank.

b) Interest that Mahesh has to pay

Interest = P × R × T/100

= Rs. 22,800 × 9 × 3/100 = Rs. 6,492

Therefore, Mahesh has to pay Rs. 6,492 as interest.

c) Interest that Rakesh has to pay

The total amount that Rakesh has to pay to Mahesh is Rs. 30,350 [= (22,800 + 7,550)].

Therefore, interest that Rakesh has to pay = Total Amount - Principal

= Rs. 30,350 - Rs. 22,800 = Rs. 7,550

Therefore, Rakesh has to pay Rs. 7,550 as interest.

d) Percentage by which Rakesh pays more interest than Mahesh

Let us calculate the percentage difference between the interest paid by Rakesh and the interest paid by Mahesh.

Thus, the percentage difference can be calculated as

% Difference = (|Interest paid by Rakesh - Interest paid by Mahesh|/ Interest paid by Mahesh) × 100

% Difference = (|7,550 - 6,492|/6,492) × 100

% Difference = 16.3%

Therefore, Rakesh pays more interest than Mahesh by 16.3%.

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Answer:Surface

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

the sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

a hexagon has 6 sides , then

sum = 180° × (6 - 2) = 180° × 4 = 720°

12

the polygon has 5 sides , so

sum = 180° × (5 - 2) = 180° × 3 = 540°

sum the interior angles and equate to 540

y + 90 + 120 + 90 + 110 = 540

y + 410 = 540 ( subtract 410 from both sides )

y = 130

13

the polygon has 7 sides , so

sum = 180° × (7 - 2) = 180° × 5 = 900°

sum the interior angles and equate to 900

p + 90 + 141 + 130 + 136 + 123 + 140 = 900

p + 760 = 900 ( subtract 760 from both sides )

p = 140

we just need to reflect the graph of g(x) around the y-axis, and then shift the whole graph 5 units upwards.

Here we have two functions:

\(g(x) = ln(x)\\\\f(x) = ln(-x) + 5\)

Ok, let's start with g(x), which graph we know. If we reflect it around the y-axis, then the new function will be:

f(x) = g(-x)

If now we shift it up 5 units, then we get:

f(x) = g(-x) + 5

Replacing g(x):

f(x) = ln(-x) + 5

Which is our function

So we just need to reflect the graph of g(x) around the y-axis, and then move the whole graph 5 units upwards.

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Answer:

Retainers have been designed to be used as an end of treatment to help retain your teeth in their new position. ... These are removable and fixed retainers. The reason why retainers can't be used to close a gap is because they are fitted at the end of treatment and are made to fit the straight teeth mould.

hope it help u

itz by Riddhi

Answer:

yes

Step-by-step explanation:

Answer: 22

Step-by-step explanation:

\(f(f^{-1}(x))=f^{-1}(f(x))=x\)

Answer:

The answer is "Option a"

Step-by-step explanation:

In the given scenario, the z-score value is used as the score which is used to shows that how many standard deviation units in this score were uses as the from mean  and whenever this score is above or below by the mean, therefore the given statement is true.

Answer:89

Step-by-step explanation:

Answer:

YES DOOD TY FOIR THE COINS DOOD

Step-by-step explanation:

There is only 1 possible 11-card hand that can be formed from a 20-card deck.

To determine the number of 11-card hands possible with a 20-card deck, we can use the concept of combinations.

The number of combinations, denoted as "nCk," represents the number of ways to choose k items from a set of n items without regard to the order. In this case, we want to find the number of 11-card hands from a 20-card deck.

The formula for combinations is:

nCk = n! / (k!(n-k)!)

Where "!" denotes the factorial of a number.

Substituting the values into the formula:

20C11 = 20! / (11!(20-11)!)

Simplifying further:

20C11 = 20! / (11! * 9!)

Now, let's calculate the factorial values:

20! = 20 * 19 * 18 * ... * 2 * 1

11! = 11 * 10 * 9 * ... * 2 * 1

9! = 9 * 8 * 7 * ... * 2 * 1

By canceling out common terms in the numerator and denominator, we get:

20C11 = (20 * 19 * 18 * ... * 12) / (11 * 10 * 9 * ... * 2 * 1)

Performing the multiplication:

20C11 = 39,916,800 / 39,916,800

Finally, the result simplifies to:

20C11 = 1

Consequently, with a 20-card deck, there is only one potential 11-card hand.

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Answer:

32 degrees

Step-by-step explanation:

One straight line equals 180 degrees

if one angle from one side is 148, then 180-148=32

Answer:

Step-by-step explanation:

-25/4(x)= -25/8

x= -(25/8) X (4/-25)= 1/2

According to the given statement the greatest common factor is -1(x+10).

Examples involving linear equations are 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, and 3x - y + z = 3. The concept of linear equations, the including that for linear equations involving one parameter, two independent variables, or three variables, and examples of each will all be explored in detail in this article.

A linear equation has the slope-intercept form y = mx + b. When x is 0, the integers m and b provide the line's slope (m) and also the value of y. (b). It y-intercept is indeed the value that y has when x is 0 because (0,y) is the point at which the line crosses the y-axis.

= -x – 10

= -1(x+10)

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Answer:

Distance from the base of the cliff to the point on the ground = 7608 feet

Step-by-step explanation:

Given: Height of the cliff is 532 feet, angle of depression from the top of the cliff to a point on the ground is equal to 4 degrees.

To find: distance from the base of the cliff to the point on the ground

Solution:

In ΔABC,

\(\angle ACB=4^{\circ}\)  (Alternate interior angles)

For any angle \(\theta\), \(\tan \theta =\) side opposite to angle/side adjacent to angle

\(\tan C=\frac{AB}{BC}\)

Put \(AB=532\,,\,\angle C=4^{\circ}\)

\(\tan 4^{\circ}=\frac{532}{BC}\\\\BC=\frac{532}{\tan 4^{\circ}}\\\\=7607.95\\\\\approx 7608\,\,feet\)

Distance from the base of the cliff to the point on the ground = 7608 feet

The value of the equation f(x) = 2.5x - 10.5 and g(x) = 64(0.5x) are calculated as x = 2: f(x) = 2.5(2) - 10.5 = -5.5 and g(x) = 64(0.5(2)) = 64.

The substitution method is a quick and easy way to identify the variables' solutions to a set of linear equations. It entails, as the name implies, determining the value of the x-variable in terms of the y-variable from the first equation, and then substituting or replacing the value of the x-variable in the second equation. So, we may solve the equation and determine the value of the y-variable. Finally, we can use any of the above equations with the value of y to determine x. It is also possible to solve for x first, then for y, in the opposite order.

The given equation are f(x) = 2.5x - 10.5 and g(x) = 64(0.5x).

Substituting the value of x we have the value in the table as follows:

x = 2:

f(x) = 2.5(2) - 10.5 and g(x) = 64(0.5(2))

f(x) = -5.5                     g(x) = 64

For x = 3:

f(x) = 2.5(3) - 10.5 and g(x) = 64(0.5(3))

f(x) = -3                         g(x) = 96

For x = 4:

f(x) = 2.5(4) - 10.5 and g(x) = 64(0.5(4))

f(x) = -0.5                     g(x) = 128

For x = 5:

f(x) = 2.5(5) - 10.5 and g(x) = 64(0.5(5))

f(x) = 2                          g(x) = 160

For x = 6:

f(x) = 2.5(6) - 10.5 and g(x) = 64(0.5(6))

f(x) = 4.5                       g(x) = 192

Hence, the value of the equation f(x) = 2.5x - 10.5 and g(x) = 64(0.5x) are calculated as x = 2: f(x) = 2.5(2) - 10.5 = -5.5 and g(x) = 64(0.5(2)) = 64.

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The equation 7.5s + 1.6t - 4.2s is simplified to give a result of

The given equation 7.5s + 1.6t - 4.2s is simplified by following the mathematical operator that is acting on the values after a consideration of like terms

The variables in the equation are t and s

terms in t: 1.6

terms in s: 7.5, -4.2

collecting like terms

this will lead to rearranging the equation to give

7.5s - 4.2s + 1.6t

using the mathematical operator (addition and subtraction)

= 3.3s + 1.6t

unlike terms cannot be operated on, because of this the answer is 3.3s + 1.6t

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Answer:

1. 7.3

2. 33.3

3. 21.3

4. 31.9

5. 25.6

6. 11.0

7. 42°

8. 64°

9. 13°

10. 51°

Step-by-step explanation:

make sure if you're using a math calculator that it is in degree mode.

SIN, COS, OR TAN. SOH CAH TOA. Sin is Opposite/hypotenus.

Cos is Adjacent(next to it)/hypotenus.

Tan is Opposite/Adjacent.

~~

PROBLEM 1:

So we have 63°, 16 as hypotenus, and x as one of the legs.

1. Figure out whether it is Sin, Cos, or Tan. (It's adj and hyp. of the angle degree (63° listed so it's cos.)

2. Once you set it up, it is Cos 63°= x/16 then flip it around. which makes it 16 COS 63= X.

3. Input it into your calculator as 16cos(63, then it will give you.. 7.263847996

4. Don't forget to round to the nearest tenth, which gives you

x = 7.3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 2:

Given: 39°, 27 is opposite of the °, and adj is x. So this is Tan.

1. Set it up, Tan 39° = 27/x can't solve this way so fix it.

2. rewritten as X = 27/tan39

3. round ur answer.

x = 33.3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 3:

Given: 49°, adj is 14, hyp is x. So this is Cos.

1. Set up according to CAH, Cos 49=(14/x).

We can't solve it this way since the X is on the bottom. So we have to fix it!

2. Turns into X Cos 49 = 14, which then turns into X= 14/cos49.

3. Put it in your calculator as 14 DIVIDED BY cos 49. ( Put image example)

4. Round.

x= 21.3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 4:

Given: 15°, 33 hyp, adj x. Which is Cos.

1. Cos 15= x/33 and rewrite.

2. Input as 33 cos(15 into calculator = 31.875...

3. Round to tenth.

x = 31.9

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 5:

Given: 52°, 20 adj of °, and x opp of °. Will use TAN.

1. Tan 52° = x/20

2. 20 Tan(52 into calculator

3. Round

x = 25.6

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 6:

Given: 27°, opp of ° is 5, hyp is x. Will use Sin.

1. Write out as I have the last few times, Sin 27 = 5/x rewrite cause x can't be at the bottom.

2. Input into calculator as: 5/sin 27 which equals 11.01...

3. Round.

x = 11.0

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 7:

Given: x°, 6 as hyp, 4 opp. now we have to solve this different since we don't know the degree. Now when we input into the calculator you will press 2nd, then sin/cos/tan so it will be negative this is depending on which one ur solving for.

We will be using SIN, x is still a °.

1. Sin X = 4/6 Rewrite.

2. X= Sin^-1 (4/6)

Make sure ur sin is negative in calculator when doing this.

3. It SHOULD give you 41.81, round.

x = 42°

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 8:

Given: x°, 29 opp, 14 adj. TAN.

1. Tan x°= 29/14 or..

2. X = Tan^-1(29/14) solve..

3. gives u 64.23.... round.

x = 64°

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 9:

Given: x°, hyp 54, opp 12. SIN

1. Sin x°=(12/54)

2. X= Sin^-1(12/54) solve. (dont put x= into calculator.)

3. Don't Forget to round, answer unrounded: 12.839..

x = 13°

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

PROBLEM 10:

Given: x°, adj 25, hyp 40. COS

1. Cos x°=25/40 rewrite.

2. X= Cos^-1(25/40) Solve.

3. Round.

X= 51°

Answer: 0.7 is 10 times larger than 0.07

Step-by-step explanation:

Answer:

Rs. 1680

Step-by-step explanation:

34km -----  1190

48km -----  x?

34x = 1190*48

x = 1190*48/34

x = 1680

Answer:

1st expression= rational 2nd expression= rational 3rd expression = irrational

Step-by-step explanation:

The first and second expressions are rational because they both equal whole numbers (4 and 3) while the last expression equals a decimal that goes on forever with no end, thus making it irrational.

Answer:

$3,500 + $50x < y

Step-by-step explanation:

Answer:

h(1)= -90 h(n)=h(n-1) ⋅ 6

Step-by-step explanation:

Im smart :D

The mode will not change.

Given data,

58,60,53,54,60,35,58,60

Outlier is the value in a set of data that much higher or lower than other values in data.

from given data, outlier is 35.

Mode is the value in a set of data that occurs more frequently in set of data.

from given data, 60 occurs more frequently.

Hence, 60 is the mode of data.

If outlier is removed from the data set then it will not affect the mode of the data

Thus, the mode will not change.

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