Find the component form of the resultant vector.
a= (-6, -5)
Unit vector in the opposite direction of a

Answer:

2x-1

Step-by-step explanation:

(10x-5)-(8x+6)

10x-8x-5+6

2x-1

Answer:

3 \(\frac{46}{81}\)

Step-by-step explanation:

change 1 \(\frac{8}{9}\) to an improper fraction

1 \(\frac{8}{9}\) = \(\frac{17}{9}\) , thus

\(\frac{17}{9}\) × \(\frac{17}{9}\) = \(\frac{289}{81}\) = 3 \(\frac{46}{81}\) or 3.57 ( to 2 dec. places )

Answer:

3.57

Step-by-step explanation:

1 8/9 =

(17/9)^2

17/9 x 17/9

17 x 17/ 9 x 9

17^2/ 9^2

289/81

3.567901

3.567901 Rounded is 3.57

Hope this helps!

Plz name brainliest if you can!

The estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.

To estimate the area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints, we can use the right Riemann sum method.

The width of each rectangle, Δx, is given by the interval width divided by the number of rectangles.

In this case, Δx = (π/2 - 0)/4 = π/8.

To calculate the right endpoint values, we evaluate f(x) at the right endpoint of each rectangle.

For the first rectangle, the right endpoint is x = π/8.

For the second rectangle, the right endpoint is x = π/4.

For the third rectangle, the right endpoint is x = 3π/8.

And for the fourth rectangle, the right endpoint is x = π/2.

Now, let's calculate the area for each rectangle by multiplying the width (Δx) by the corresponding height (f(x)):

Rectangle 1: Area = f(π/8) * Δx = 5cos(π/8) * π/8

Rectangle 2: Area = f(π/4) * Δx = 5cos(π/4) * π/8

Rectangle 3: Area = f(3π/8) * Δx = 5cos(3π/8) * π/8

Rectangle 4: Area = f(π/2) * Δx = 5cos(π/2) * π/8

Now, let's calculate the values:

Rectangle 1: Area = 5cos(π/8) * π/8 ≈ 0.2887

Rectangle 2: Area = 5cos(π/4) * π/8 ≈ 0.3142

Rectangle 3: Area = 5cos(3π/8) * π/8 ≈ 0.2887

Rectangle 4: Area = 5cos(π/2) * π/8 ≈ 0

Finally, to estimate the total area, we sum up the areas of all four rectangles:

Total Area ≈ 0.2887 + 0.3142 + 0.2887 + 0 ≈ 0.8916

Therefore, the estimated area under the graph of f(x) = 5 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right endpoints is approximately 0.8916.

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Answer: 4/15

Step-by-step explanation: just multiply

Let us solve for x in each of the inequalities.

The first inequality.

subtracting 5 from both sides gives

finally, multiplying both sides by -2 reverse the direction of the inequality to give

which is our answer!

The second inequality

Dividing both sides by -3 gives

finally, adding -5 to both sides gives

which is our answer!

Answer:

15

Step-by-step explanation:

32 + 2* -4 - 9

32 - 8- 9

32 - 17

=15

Answer:

C

Step-by-step explanation:

32 + 2n - 9

23 + 2n

23 + 2(-4)

23 - 8

15

Best of Luck!

Answer:

vertex = (1, - 9 )

Step-by-step explanation:

The x- coordinate of the vertex is at the midpoint of the zeros.

Given

f(x) = (x - 4)(x + 2)

Find the zeros by letting f(x) = 0 , that is

(x - 4)(x + 2) = 0

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 4 = 0 ⇒ x = 4

Then

\(x_{vertex}\) = \(\frac{-2+4}{2}\) = \(\frac{2}{2}\) = 1

Substitute x = 1 into f(x) for corresponding y- coordinate

f(1) = (1 - 4)(1 + 2) = (- 3)(3) = - 9

Vertex = (1, - 9 )

Answer:

5 and 6

Step-by-step explanation:

26/5 = 5 1/5

so it's between 5 and 6

Answer:IM 90% SURE its 5 and 6

Step-by-step explanation: just 90% sure tho

The sum of the first 10 terms is approximately 414.66667. The estimated error is less than or equal to 0.00008.

The sum of the first 10 terms of the series can be approximated by evaluating the expression 9 + n\(^5\) for n = 1 to 10 and summing the results.

The calculated sum is 1 + 32 + 243 + 1024 + 3125 + 7776 + 16807 + 32768 + 59049 + 100000, which equals 41466667.

To estimate the error, we can use the remainder term formula Rn ≤ (1/x\(^5\)) where x is the value of n.

Substituting x = 10, we get R10 ≤ 1/10\(^5\) = 0.00001.

Rounding the estimated error to five decimal places, we have an error of 0.00001.

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Answer:

1. AB ~= DF

2. Definition of Congruent

3. Reflexive Property of Congruency

4 BD=BD

6. AB+BD=AD; DF+BD=BF

7. Substitution Property of Equality

8. Definition of Congruent

Step-by-step explanation:

1. The given always goes first, and that's the first reason, so AB ~= DF must be the first statement (that should be the congruency symbol).

2. The definition of congruent is that if they are congruent then they are equal. Since that statement made two congruent lines equal, it must be the definition.

3. The reflexive property means something is congruent to itself, and BDis BD, therefore it is the reflexive property.

4. Remember if something is congruent then it is equal.

6. The segment addition postulate states that if we are given two points on a line segment, then AB+AC=AC.

7. In this statement AD was substituted for DF+BD. This can be done because of AB=DF and BD=BD as aforementioned.

8. If two things are congruent then they are equal by definition of congruency.

Answer:

C

Step-by-step explanation:

Got it right

The number of black - footed Mizjigs in Ragon's colony can be found to be A. 185 black - footed Mizjigs

First, find the number of one - headed Red - footed Mizjigs to be :

= 213 - 105

= 108 one - headed Red - footed Mizjigs

This means that the number of two - headed Mizjigs in the colony are:

= 435 - 213

= 222 two - headed Mizjigs

The number of two - headed black - footed Mizjigs are:

= 222 - 142

= 80 two - headed black - footed Mizjigs

The total black - footed Mizjigs are:

= 105 + 80

= 185 black - footed Mizjigs

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(I) The characteristic polynomial of matrix A is p(λ) = 2λ² - 2λ. (II) Two eigenvalues: λ = 0 and λ = 1 (III) The eigenspace corresponding to λ = 0 is the zero vector. The eigenspace corresponding to λ = 1 is spanned by the vector [2, 0]. (IV) The algebraic multiplicity is 2 and the geometric multiplicity is 0. The algebraic multiplicity is also 2 and the geometric multiplicity is 1.

(V) The matrix A is not diagonalizable. (VI) There is need to calculate A¹⁰ using a different approach. (VII) Aᵏ = Aᵏ ᵐᵒᵈ ⁵ for all non-negative integers k. (VIII) A¹⁰ × b = [-2, 2]. (IX) A is similar to B, and there is an invertible matrix P such that P⁻¹ × A × P = B.

(I) To find the characteristic polynomial of matrix A, we need to calculate the determinant of the matrix (A - λI), where λ is the eigenvalue and I is the identity matrix.

A - λI =

[1 - λ]

[1 - λ]

[-1 - λ]

[1 - λ]

det(A - λI) = (1 - λ)(1 - λ) - (1 - λ)(-1 - λ)

= (1 - λ)² - (-1 - λ)(1 - λ)

= (1 - λ)² - (λ + 1)(1 - λ)

= (1 - λ)² - (1 - λ²)

= (1 - λ)² - 1 + λ²

= (1 - 2λ + λ²) - 1 + λ²

= 2λ² - 2λ

Therefore, the characteristic polynomial of matrix A is p(λ) = 2λ² - 2λ.

(II) To find the eigenvalues of matrix A, we set the characteristic polynomial equal to zero and solve for λ:

2λ² - 2λ = 0

Factorizing the equation, we have:

2λ(λ - 1) = 0

Setting each factor equal to zero, we find two eigenvalues:

λ = 0 and λ = 1

(III) To find a basis for the eigenspaces of matrix A, we need to find the eigenvectors corresponding to each eigenvalue.

For λ = 0:

(A - 0I)v = 0, where v is the eigenvector.

Simplifying the equation, we have:

A × v = 0

Substituting the values of A and v, we get:

[1 0] [v1] = [0]

[1 -1] [v2] [0]

This gives us the system of equations:

v1 = 0

v1 - v2 = 0

Solving these equations, we find v1 = 0 and v2 = 0.

Therefore, the eigenspace corresponding to λ = 0 is the zero vector.

For λ = 1:

(A - I)v = 0

Substituting the values of A and v, we get:

[0 0] [v1] = [0]

[1 -2] [v2] [0]

This gives us the system of equations:

v2 = 0

v1 - 2v2 = 0

Solving these equations, we find v1 = 2 and v2 = 0.

Therefore, the eigenspace corresponding to λ = 1 is spanned by the vector [2, 0].

(IV) The algebraic multiplicity of an eigenvalue is the power of its factor in the characteristic polynomial. The geometric multiplicity is the dimension of its eigenspace.

For λ = 0, the algebraic multiplicity is 2 (since (λ - 0)² appears in the characteristic polynomial), and the geometric multiplicity is 0.

For λ = 1, the algebraic multiplicity is also 2 (since (λ - 1)² appears in the characteristic polynomial), and the geometric multiplicity is 1.

(V) To show that the matrix is diagonalizable, we need to check if the algebraic and geometric multiplicities are equal for each eigenvalue.

For λ = 0, the algebraic multiplicity is 2, but the geometric multiplicity is 0. Since they are not equal, the matrix is not diagonal

izable for λ = 0.

For λ = 1, the algebraic multiplicity is 2, and the geometric multiplicity is 1. Since they are not equal, the matrix is not diagonalizable for λ = 1.

Therefore, the matrix A is not diagonalizable.

(VI) To find A¹⁰ × b, we can write b as a linear combination of eigenvectors of A and use the fact that Aᵏ × v = λᵏ × v, where v is an eigenvector corresponding to eigenvalue λ.

We have two eigenvectors corresponding to the eigenvalue λ = 1: [2, 0]. Let's denote it as v1.

b = [-2, 2] = (-2/2) × [2, 0] = -1 × v1

Using the fact mentioned above, we can calculate A¹⁰ × b:

A¹⁰ × b = A¹⁰ × (-1 × v1)

= (-1)¹⁰ × A¹⁰ × v1

= 1 × A¹⁰ × v1

= A¹⁰ × v1

Since A is not diagonalizable, we need to calculate A¹⁰ using a different approach.

(VII) To find a formula for Aᵏ for all non-negative integers k, we can use the Jordan canonical form of matrix A. However, without knowing the Jordan canonical form, we can still find Aᵏ by performing repeated matrix multiplications.

A² = A × A =

[1 0] [1 0] = [1 0]

[1 -1] [1 -1] [1 -2]

A³ = A² × A =

[1 0] [1 0] = [1 0]

[1 -2] [1 -1] [-1 2]

A⁴ = A³ × A =

[1 0] [1 0] = [1 0]

[-1 2] [-1 2] [-2 2]

A⁵ = A⁴ × A =

[1 0] [1 0] = [1 0]

[-2 2] [-1 2] [0 0]

A⁶ = A⁵ × A =

[1 0] [1 0] = [1 0]

[0 0] [0 0] [0 0]

As we can see, starting from A⁵, the matrix Aⁿ becomes the zero matrix for n ≥ 5.

Therefore, Aᵏ = Aᵏ ᵐᵒᵈ ⁵ for all non-negative integers k.

(VIII) Using the formula from (VII), we can find A¹⁰ × b:

A^10 * b = A¹⁰ ᵐᵒᵈ ⁵ × b

= A⁰ × b

= I × b

= b

We previously found that b = [-2, 2].

Therefore, A¹⁰ × b = [-2, 2].

(IX) To determine if A is similar to B, we need to check if there exists an invertible matrix P such that P⁻¹ × A × P = B.

Let's calculate P⁻¹ × A × P and check if it equals B:

P = [v1 v2] = [2 0]

[0 0]

P⁻¹ = [1/2 0]

[ 0 1]

P⁻¹ × A × P =

[1/2 0] [1 0] [2 0] = [0 0]

[ 0 1] [1 -1] [0 0] [0 0]

The result is the zero matrix, which is equal to B.

Therefore, A is similar to B, and we found an invertible matrix P such that P⁻¹ × A × P = B. In this case, P = [2 0; 0 0].

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Answer:

1

Step-by-step explanation:

\((\frac{8}{11})^{7- 2*3 - 1} = (\frac{8}{11})^{7- 6 - 1}\\\\=(\frac{8}{11})^{7- 7}\\\\=(\frac{8}{11})^{0}\\\\=1\)

Answer:

Step-by-step explanation:

\(\dfrac{|AC|}{\sin B}=\dfrac{|AB|}{\sin C}\\\\\dfrac{9}{\sin38^o}=\dfrac{11}{\sin C}\\\\\dfrac{\sin38^o}9=\dfrac{\sin C}{11}\\\\\sin C=\frac{11}9\sin38^o =\frac{11}9\cdot0,6157=0,7525(2)\\\\\sin C\approx0,7525\quad\iff\quad |\angle C|\approx48^o48'\\\\|\angle A|=180^o-|\angle B|-|\angle C|\\\\|\angle A|=180^o-38^o-48^o48'\\\\|\angle A|=93^o12'\approx93^o\)

Changing the order of the factors does not change the product, according to the commutative property of multiplication.

Changing the order of the factors does not change the product, according to the commutative property of multiplication. Here's an illustration: 4 × 3 = 3 × 4 4 x 3 = 3 x 4, or 4 x 3 = 3 x 4.

The distributive property of binary operations in mathematics generalizes the distributive law, which states that in elementary algebra, equality is always true. For instance, in basic mathematics, one has to According to one, addition is distributed more evenly than multiplication.

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Part A: A reasonable domain to plot the growth function would be from d = 0 to d = 11.

Part B: The y-intercept of the graph of the function f(d) is 7

Part C: The average rate of change of the function f(d) from d = 4 to d = 11 is approximately 0.64 mm/day.

The domain of a function represents the set of input values for which the function is defined and can produce a meaningful output.

The y-intercept of a function represents the value of the function when the input is equal to zero.

The average rate of change of a function from x = a to x = b is given by the slope of the secant line passing through the points (a, f(a)) and (b, f(b)).

Here we have

A biologist is studying the growth of a particular species of algae. She writes the following equation to show the radius of the algae, f(d), in mm, after d days:

=> f(d) = 7(1.06)^d

Since it is given that the radius of the algae was approximately 13.29 mm when the biologist concluded her study, we can set f(d) = 13.29  

=> 13.29 = \(7(1.06)^{d}\)

=> ln(13.29/7) = d ln(1.06)

=> d = ln(13.29/7)/ln(1.06) ≈ 11  

Therefore, A reasonable domain to plot the growth function would be from d = 0 to d = 11.

Part B: The y-intercept of the graph of the function f(d) represents the value of the function when d = 0.

Substituting d = 0 into the given equation, we get:

f(0) = 7(1.06)⁰ = 7

Therefore, The y-intercept of the graph of the function f(d) is 7

Part C: The average rate of change of the function f(d) from d = 4 to d = 11 is given by the slope of the secant line passing through the points (4, f(4)) and (11, f(11)). Using the given equation, we can evaluate f(4) and f(11):

f(4) = 7(1.06)⁴ ≈ 8.84

f(11) = 7(1.06)¹¹ ≈ 13.29

The slope of the second line passing through these two points is:

Slope = (f(11) - f(4))/(11 - 4) = [ 13.29 - 8.84]/7 = 0.64

Therefore,

The average rate of change of the function f(d) from d = 4 to d = 11 is approximately 0.64 mm/day.

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We can see here that according to the partial W-2 form, the money that was paid in FICA taxes is: B. $1789.87.

Governments impose taxes as obligatory financial charges or levies on citizens, businesses, and other organizations to pay for public expenses and fund government operations.

FICA taxes are comprised of Social Security and Medicare taxes.

The Social Security tax rate is 6.2% and the Medicare tax rate is 1.45%. The total FICA tax rate is 7.65%.

The breakdown of the FICA taxes paid:

Social Security tax: $1430.20

Medicare tax: $359.67

Total FICA taxes: $1789.87

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After answering the presented question, we can conclude that where the equation center is (-3, 5) and the radius is 8.

An equation is a mathematical statement that validates the equivalent of two expressions linked by the equal symbol '='. For example, 2x - 5 = 13. 2x-5 and 13 are two phrases. The character '=' is used to connect the two expressions. An equation is a mathematical formula that has two algebras on either side of an assignment operator (=). It illustrates the equivalency relationship between the left and middle formulas. In any formula, L.H.S. = R.H.S. (left side = right side).

\(x^2 + 6x + 9 = (x + 3)^2\\y^2 - 10y + 25 = (y - 5)^2\\(x + 3)^2 + (y - 5)^2 = 64\\(x - (-3))^2 + (y - 5)^2 = 8^2\)

where the center is (-3, 5) and the radius is 8.

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The profit-maximizing price and quantity for the monopolist are $350 and 150 units, respectively ,The expected return is greater than the initial investment And the producer surplus is $33,750, consumer surplus is $31,875, and firm profit is $37,500.

Ignoring the time value of money and discounting, the expected value of the lottery winnings each year is 2% × $1 million = $20,000, and this goes on for 10 years.

Thus, the expected value of the investment is 10 × $20,000 = $200,000.

Hence, the expected return is greater than the initial investment, and there is a condition under which the investment can be made.

The monopolist’s total cost can be represented as:

TC = 300 + 200Q + 3Q².

The demand function for the monopolist is given as:

Q = 500 - P,

which can be rearranged to derive the price function as:

P = 500 - Q.

From the total cost function, we can obtain the marginal cost (MC) as the derivative of TC with respect to Q, and it can be represented as follows:

MC = dTC/dQ = 200 + 6Q.

From the marginal cost, we can set the marginal revenue (MR) equal to MC to get the profit-maximising quantity as follows:

MR = dTR/dQ = P + Q(500 - P) = 500 - Q + 500Q - Q² = 1000Q - Q² - 500 = MC = 200 + 6Q.

Substituting P = 500 - Q in the above expression and rearranging yields the following:

Q = 150, and hence, P = $350.

Therefore, the profit-maximising price is $350, and the quantity is 150. We can verify that the solution is a maximum by computing the second-order condition, which is negative.

To calculate the producer surplus, we first need to obtain the area above the marginal cost and below the price.

Thus, we have:

PS = ∫ MC to QdQ

= ∫ (200 + 6Q) dQ from 0 to 150

= [200Q + 3Q²] from 0 to 150

= $33,750.

Similarly, the consumer surplus can be computed as the difference between the market value of the product and what the consumers paid for it. The area below the price line and above the demand curve yields the consumer surplus.

Thus, we have:

CS = ∫ P to QdQ

= ∫ (500 - Q) dQ from 0 to 150

= [(500 × Q) - (Q²/2)] from 0 to 150

= $31,875.

Finally, the firm profit can be obtained by multiplying the profit-maximizing quantity by the profit-maximizing price and subtracting the total cost.

Thus, we have:

Profit = TR - TC = Q × P - TC = (150 × $350) - (300 + 200 × 150 + 3 × 150²) = $37,500.

Hence, the producer surplus, consumer surplus, and firm profit are $33,750, $31,875, and $37,500, respectively.

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The answer is H0: At the 10% significance level, we conclude that the CFA designation is more lucrative than an MBA.

a. Set up the hypotheses to test if a CFA designation is more lucrative than an MBA at the 10% significance level.

The null hypothesis is: H0: μ1 ≤ μ2

The alternative hypothesis is: H1: μ1 > μ2So, the answer is (c) H0: μ1 − μ2 ≤ 0; HA: μ1 − μ2 > 0. b-1. Calculate the value of the test statistic.

The formula to find the test statistic is given by,

\[{\rm{T}} = \frac{{\left( {{\overline X _1} - {\overline X _2}} \right) - \left( {{\mu _1} - {\mu _2}} \right)}}{{\sqrt {\frac{{{\rm{s_1}^2}}}{n} + \frac{{{\rm{s_2}^2}}}{n}} }}\]Substituting the given values,\[{\rm{T}} = \frac{{\left( {146 - 133} \right) - \left( 0 \right)}}{{\sqrt {\frac{{{{\left( {53} \right)}^2}}}{41} + \frac{{{{\left( {26} \right)}^2}}}{52}} }} = 2.417\]

So, the value of the test statistic is 2.417.b-2. Find the p-value.

We need to find the p-value for a one-tailed test at a 10% significance level.

Since the alternative hypothesis is μ1 > μ2, the p-value is the area to the right of the test statistic.

Using a t-distribution table with 91 degrees of freedom (rounded to the nearest integer), we get the p-value as 0.010.

Since the p-value is less than the significance level, we reject the null hypothesis and conclude that the CFA designation is more lucrative than an MBA.

Therefore, the answer is H0: At the 10% significance level, we conclude that the CFA designation is more lucrative than an MBA.

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Answer:

Siswe

Step-by-step explanation:

\(\frac{1}{3} = \frac{4}{12}\\\\\frac{1}{4} = \frac{3}{12}\\\\\frac{5}{12} =\frac{5}{12}\)

Answer:

siswe gets more juice

Step-by-step explanation:

i hope this helps

Answer:

16 + x > 31, so x > 15

16 + 31 > x, so x < 47

Combining these inequalities, we have

15 < x < 47.

Since x is the shortest side of this triangle, and since the triangle is not isosceles,

15 < x < 16. So one possible value of x is 15.1.

Answer:

Multiply the denominator of the fractional part by the whole number, and add the result to the numerator.

Step-by-step explanation:

You can add or subtract mixed numbers by turning them to improper fractions first. Improper fractions are fractions where the numerator is greater than the denominator.