Find the area of the square (A = length width) field. Write an expression which

represents the area of this rectangle, then simplify the expression.

- (x + 4) feet

Answer:

6,5

Step-by-step explanation:

Answer:

8.324

Step-by-step explanation:

The 8 serves as the first digit and the "and " represents a decimal point  the remaining numbers go behind that decimal point therefore 8.324.

The range of the function (f+g)(x) = x² - 1 will be ( -1, ∞ ). The correct option is B.

The range of values that we are permitted to enter into our function is known as the domain of a function.

The x values for a function like f make up this set (x). A function's range is the set of values it can take as input. After we enter an x value, the function outputs this set of values.

Given that the function is f(x) = x²+2x-5. The function g(x) will be calculated by the data given in the table.

x           -6    -3     -1    4

g(x)       16    10    6   -4

The function g(x) will be:-

g(x) = mx + c

m = ( 10 - 16 ) / ( -3 + 6 )

m = -6 / 3

m = -2

c = y - mx

c = 10 - 6

c = 4

g(x) = -2x + 4

The function ( f + g)(x) will be:-

( f + g)(x) = f(x) + g(x)

( f + g)(x) = x²+ 2x - 5 - 2x + 4

( f + g)(x) = x² - 1

At x = 0, the value ( f + g)(x) is -1. The range of the function is ( -1, ∞).

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Answer:

let the third side be x

Using pythagoras theorem we get,

(58)^2 = (42)^2 + (x)^2

3364=1764+x^2

x^2=3364-1764

x^2= 1600

x=√(1,600)

x=40

\(\pink{\sf Third \: side \: of \: the \: triangle = 40}\)

As, the given triangle is a right angled triangle,

Hence, We can use the Pythagoras' Theorem,

\(\star\:{\boxed{\sf{\pink {H^{2} = B^{2} + P^{2}}}}}\)

Here,

In given triangle,

Now, by Pythagoras' theorem,

\(\star\:{\boxed{\sf{\pink {H^{2} = B^{2} + P^{2}}}}}\)

\( \sf : \implies (58)^{2} = (42)^{2} + P^{2}\)

\( \sf : \implies 58 \times 58 = 42 \times 42 + P^{2} \)

\( \sf : \implies 3364 = 1764 + P^{2}\)

\( \sf : \implies P^{2} = 3364 - 1764\)

\( \sf : \implies P^{2} = 1600\)

By squaring both sides :

\( \sf \sqrt{P^{2}} = \sqrt{1600}\)

\( \sf : \implies P^{2} = \sqrt{1600}\)

\( \sf : \implies P^{2} = \sqrt{(40)^{2}}\)

\( \sf : \implies P^{2} = 40 \)

\(\pink{\sf \therefore \: Third \: side \: of \: the \: triangle \: is \: 40}\)

━━━━━━━━━━━━━━━━━━━━━

Refer to the image for the graph of the lines.

The common form of the equation of a line is y = mx + c, where m is the slope of the line and c is a constant.

We need to draw any line with a slope m = 2, and

another line with a slope m = -2.

Disclaimer: Let us assume that the constant c = 0.

Then the equation to the line with a slope of "positive" 2 is given by

y = 2x

Then the equation to the line with a slope of "negative" 2 is given by

y = -2x

Refer to the attached image for the graph of the lines with the slope of "positive" 2 and "negative" 2.

f: green line indicates a line with a slope of "positive" 2.

g: blue line indicates a line with a slope of "negative" 2.

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The value of cosec A / cot A - sec A, we'll first express cosec A, cot A, and sec A in terms of the given value of tan A.The value of cosec A / cot A - sec A, using the given value of tan A = 4/3, is 1 + √(9/7)/3.

We know that cosec A is the reciprocal of sin A, and sin A is the reciprocal of cosec A. Similarly, cot A is the reciprocal of tan A, and sec A is the reciprocal of cos A.

Using the Pythagorean identity, sin^2 A + cos^2 A = 1, we can find the value of cos A. Since tan A = 4/3, we can find sin A as well.

Given:

tan A = 4/3

Using the Pythagorean identity:

sin^2 A + cos^2 A = 1

We can solve for cos A as follows:

(4/3)^2 + cos^2 A = 1

16/9 + cos^2 A = 1

cos^2 A = 1 - 16/9

cos^2 A = 9/9 - 16/9

cos^2 A = -7/9

Taking the square root of both sides, we get:

cos A = ± √(-7/9)

Since cos A is positive in the first and fourth quadrants, we take the positive square root:

cos A = √(-7/9)

Now, using the definitions of cosec A, cot A, and sec A, we can find their values:

cosec A = 1/sin A

cot A = 1/tan A

sec A = 1/cos A

Substituting the values we found:

cosec A = 1/sin A = 1/√(1 - cos^2 A) = 1/√(1 - (-7/9)) = 1/√(16/9) = 1/(4/3) = 3/4

cot A = 1/tan A = 1/(4/3) = 3/4

sec A = 1/cos A = 1/√(-7/9) = -√(9/7)/3

Now, let's calculate the expression cosec A / cot A - sec A:

cosec A / cot A - sec A = (3/4) / (3/4) - (-√(9/7)/3)

= 1 - (-√(9/7)/3)

= 1 + √(9/7)/3

Therefore, the value of cosec A / cot A - sec A, using the given value of tan A = 4/3, is 1 + √(9/7)/3.

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Step-by-step explanation:

Hey there!

From the above right angled triangle ABC;

Taking Angle ABC as reference angle;

Angle ABC = ???

Perpendicular (p) = AC = 15

Base (b) = AB = 47

Now;

Taking ratio of sin;

\( \tan( \alpha ) = \frac{p}{b} \)

Keep value;

\( \tan( \alpha ) = \frac{15}{47} \)

Simplify it;

\( \tan( \alpha ) = 0.3191489\)

Take tan to next side;

Angle ABC (alpha) = tan'(0.3191489)

Therefore, the measure of angle ABC is 17.70°.

Hope it helps!

Answer:

14

Step-by-step explanation:

-4,-5

2,3

-4-2= -6

-5-3= -8

-6+-8= 14

Answer:

the answer to this question is 10

Step-by-step explanation:

May i have brainliest

The area of each section of the given circle of radius 10 meter is 25π sq. meter

A circle is a shut two-layered figure wherein the arrangement of the relative multitude of focuses in the plane is equidistant from a given point called "center". Each line that goes through the circle frames the line of reflection evenness. Additionally, it has rotational balance around the middle for each point.

there are 4 sections of the circle, radius of circle(r)=10 meter

We know that

Area of circle(A) = π(r)^2

A = π(10)^2

A = 100π sq. meter

Now the area of each section = area of circle/4

area of each section = 100π sq. meter/4 = 25π sq. meter

Thus, required area of section is 25π sq. meter.

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Answer:

450 miles in total during her training

Step-by-step explanation:

Since it does say she has 30 days to train and she said she will ride her bike 15 miles everyday she trains so she will have ridden her bike for 450 miles in total

30 days to train x 15 miles per day = 450 miles in total

Answer:

Factor form: (2x-5)(2x+5)

If you olny simplify: 8x-25

Step-by-step explanation:

Since the algae grow exponentially with doubling time of 4 days, then the population will be quadruple in size in 8 days and will be triple in size in  6.34 days.

The easiest way is to consider the situation as a geometric sequence. If the population doubles its size in 4 days, then it will be quadruple in:

2 x 4 days = 8 days.

In general, we can use the growth formula:

P(t) = Po . 2^(t/Td)

Where:

P(t) = population at time t

Po = initial population

Td = doubling time

Parameters given:

Td = 4 days

P(t) = 3Po

Plug those parameters into the formula:

3 Po = Po . 2^(t/4)

3 = 2^(t/4)

log 3 = (t/4) log 2

t = 4 . log 3 / log 2 = 6.34 days.

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Answer:

the one that shows the commutative property of addition is

m + n = n + m

Answer:

3

Step-by-step explanation:

8 people

3 slices per person

8 × 3 = 24

They need 24 slices.

1 pizza has 10 slices.

24/10 = 2.4

They need 2.4 pizzas. Since they need to order a whole number of pizzas, they need to order 3 pizzas.

Answer: 3

Answer:The nearest thousand is 6,0000Step-by-step explanation:

True, the x-intercept and the y-intercept will never be the same ordered pair because they have different x- and y-coordinates

Explanation:The statement is true. The x-intercept and the y-intercept for a line will never be the same ordered pair because they are two distinct points. The x-intercept is the point where a line crosses the x-axis, which means that the y-coordinate of this point is zero.

The y-intercept, on the other hand, is the point where the line crosses the y-axis, which means that the x-coordinate of this point is zero. Therefore, the x-intercept and the y-intercept will never be the same ordered pair because they have different x- and y-coordinates.

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The transformation shown is Translation.

Transformation of geometrical figures or points is the manipulation of a given figure to some other way.

Different types of transformations are Rotation, Reflection, Glide reflection, Translation and Dilation.

Given options are rotation, reflection, translation and dilation.

Rotation of a figure is when we rotate a figure about a certain degree.

So it is not rotation.

Reflection of a figure occurs when the figure is reflected over a line.

So it is not rotation.

Dilation is the enlarging or reduction of the size of figures.

So it is not dilation.

Translation of a figure is when we slide a figure in any direction.

Given transformation is translation.

Hence the transformation illustrated in the graph is translation.

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yw^^

Given:

The fraction of treaters dressed up us halloween, x=2/15.

Let the total trickers be taken as 1.

Now, the proportion of treakers that were not dressed up as spiderman is,

Answer:

$75

Step-by-step explanation:

let the amt. earned by timmy be x.

amt. earned by timmy=x

amt. earned by tommy=x +$24

therefore, x+x+$24=$174

or,2x +$24=$174

2x=$174-$24

2x=$150

x=$150/2

therefore, x or amt. earned by timmy=$75

Answer:

$75

Step-by-step explanation:

let the amt. earned by timmy be x.

amt. earned by timmy=x

amt. earned by tommy=x +$24

therefore, x+x+$24=$174

or,2x +$24=$174

2x=$174-$24

2x=$150

x=$150/2

therefore, x or amt. earned by timmy=$75

Answer: 2/5

Step-by-step explanation:

Number of cans of red paint = 3

Number of cans of blue paint = 5

Number of cans of green paint = 8

Number of cans of yellow paint = 4

Total number of cans of paint = 20

The probability that Eduardo will

choose a can of red paint or a can of blue will be:

= P(red) + P(blue)

= 3/20 + 5/20

= 8/20

= 2/5

The probability is 2/5.

The solution to the equation \((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\) is 10.3891

From the question, we have the following parameters that can be used in our computation:

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\)

Using the following trigonometry ratio

sin²(x) + cos²(x) = 1

We have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = (\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + 1 + e^2\)

The sum to infinity of a geometric series is

S = a/(1 - r)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = \frac{1/2}{1 - 1/2} + \frac{9/10}{1 - 1/10} + 1 + e^2\)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 1 + 1 + 1 + e^2\)

Evaluate the sum

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 3 + e^2\)

This gives

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 10.3891\)

Hence, the solution to the equation is 10.3891

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Answer:

3 days

Step-by-step explanation:

20 day x 300 dollar ＝6000 dollars

6000 dollar - 5910 dollar ＝90 dollar

Can be fined 80 dollar because 20 is even number

So,days can be fined:

60 dollar divide 20 dollar ＝3 days

We get: v - h + k - s = Ce^(-s/2) or y - x - (h - k) = Ce^(-(x-h-s)/2).

This is the general solution to the original differential equation, in terms of h, k, and C.

To solve the differential equation

dy/dx = (x-y-1)/(x+y+1)

       dy/dx = dv/ds + k

       x - y - 1 = h + s - v - k - 1 = s - v + (h - k - 1)

        x + y + 1 = h + s + v + k + 1 = s + v + (h + k + 1)

        dv/ds + k = [(h + s - v - k - 1) - (s - v + (h - k - 1))] / [(h + s + v + k + 1) -

        (s + v + (h + k + 1))]

       dv/ds + k = [(2h - 2k - 2)s - 2v] / [-2]

       or

       dv/ds = (v - h + k - s) / 2

        dv/ds = du/ds

        and the equation becomes:

        du/ds = -u/2

        v - h + k - s = Ce^(-s/2)

        or

        y - x - (h - k) = Ce^(-(x-h-s)/2)

This is the general solution to the original differential equation, in terms of h, k, and C.

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Answer:

7/3

Step-by-step explanation:

Option D has a non-zero component function in the y-direction and a zero component function in the x-direction.

The vector field →F is normal to the line x=2, so it must be tangent to the line y-axis at every point. This means that the component function of →F in the x-direction should be 0 and the component function of →F in the y-direction should be non-zero.

Option D has a non-zero component function in the y-direction and a zero component function in the x-direction, so it satisfies the given property. Therefore, the answer is: D. →F=(0,y)

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Answer:

It is one to one function

hope this will help you ☺️☺️

f(x)=2/3x^3-3/2x^2+x+C

Step-by-step explanation:

thus it's B

The computation shows that the placw on the hill where the cannonball land is 3.75m.

To find where on the hill the cannonball lands

So 0.15x = 2 + 0.12x - 0.002x²

Taking the LHS expression to the right and rearranging we have:

-0.002x² + 0.12x -.0.15x + 2 = 0.

So we have -0.002x²- 0.03x + 2 = 0  

I'll multiply through by -1 so we have

0.002x² + 0.03x -2 = 0.

This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.

The second solution y = 0.15 * 25 = 3.75

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Complete question:

The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

Answer:

Since, the coordinates of the midpoint of line GH are M(\frac{-13}{2}, -6)(

2

−13

,−6) .

The coordinates of endpoint G are (-4,1)

We have to determine the coordinates of endpoint H.

The midpoint of the line segment joining the points (x_1, y_1)(x

1

,y

1

) and (x_2, y_2)(x

2

,y

2

) is given by the formula (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})(

2

x

1

+x

2

,

2

y

1

+y

2

) .

Here, The endpoint G is (-4,1) So, x_1 = -4 , y_1=1x

1

=−4,y

1

=1

Let the endpoint H be (x_2,y_2)(x

2

,y

2

)

The midpoint coordinate M is (\frac{-13}{2}, -6)(

2

−13

,−6) .

So, \frac{-13}{2} = \frac{-4+x_2}{2}

2

−13

=

2

−4+x

2

{-13} = {-4+x_2}−13=−4+x

2

{-13}+4 = {x_2}−13+4=x

2

{x_2}=9x

2

=9

Now, -6 = \frac{1+y_2}{2}−6=

2

1+y

2

-12 = {1+y_2}−12=1+y

2

y_2= -13y

2

=−13

So, the other endpoint H is (-9,-13).