Factors that affect the force of gravity between objects include their distance apart and their ___________________________?

Question 1 options:

A. mass

B. strength

C. magnetism

D. matter

Answer:

1.5024

Explanation:

Draw a diagram. Put the two cells in series. Now draw 3 resistors. Two of them equal 0.26 ohms each. The third one is the lightbulb which is 12 ohms.

R = 0.26 + 0.26 + 12 = 12.52

The bulb has a voltage of 2.88 volts across it. You can get the current from that.

i = E / R

i = 2.88 / 12 =

i = 0.24 amps.

Now you can get the voltage drop across the two cells.

E = ?

R = 0.26

i = 0.24 amps

E = 0.26 * 0.24

E = 0. 0624

Finally divide the 2.88 by 2 to get 1.44

Each cell has an emf of 1.44 + 0.0624 = 1.5024

The string vibrates the surrounding air, which produces a longitudinal wave.

Brainly if correct? Please and thank you :D

The guitar string vibrates the surrounding air, which produces a transverse wave.

A transverse wave can be used to represent the motion of a guitar string since it oscillates up and down perpendicular to its axis of motion.

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Answer:

is the first one right

Explanation:

Answer:

yes

Explanation:

Yes, it is theoretically possible for an observer to travel fast enough so that in his system the earthquake happens also exactly now. This is due to the fact that time slows down as an object approaches the speed of light, a phenomenon known as time dilation.

The equation for time dilation states that the elapsed time T observed in the frame of reference of an observer travelling at velocity v is given by

\(T = T0 / \sqrt{(1 - v^2/c^2)}\) ,

where ,T0 is the elapsed time as observed from the reference frame of an observer at rest relative to the travelling object, c is the speed of light, and v is the velocity of the travelling object. Therefore, the greater the velocity of the travelling object, the slower the elapsed time in its reference frame.

For an observer to travel fast enough so that in his system the earthquake happens also exactly now, he would need to travel at a velocity equal to or greater than the speed of light. This is impossible according to Einstein's theory of relativity, since nothing can travel faster than the speed of light in a vacuum.
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Answer:

there is no list of "the following" you might want to re-upload your question.

Racial formations are defined as the social historical concepts by which radial identities are created lived out, transformed, and destroyed.

Race is the way of separating groups of people based on social and biological aspects. It is the process through which a specific group of people is defined as race.

Racial formations explain the definition of specific race identities. It examines the race as a dynamic social construct with structural barriers ideology etc.

This theory gives attempt to determine the difference between people based on how they live rather than how they look. Hence, in the racial formations essay reading, race is defined as a socio-historical concept.

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Answer:

When there's no external force, the total momentum of system remains the same before and after collision

Less than the kinetic energy of the system before the collision

Explanation:

Definition of conservation of momentum

: the total linear momentum of a system of particles not acted upon by external forces is constant in magnitude and direction irrespective of any reactions among the parts of the system

Definition of inelastic collision:An inelastic collision is a collision in which there is a loss of kinetic energy.

Brainliest please

Each scenario affects photographs by altering exposure, contrast, or focus, leading to partial or uneven exposure, decreased sharpness, or distorted images.


a. Half of the lens on your camera is covered by a piece of paper: This will cause uneven exposure, with one half of the image being darker due to the obstruction.
b. The negative is placed in the enlarger with half of it covered by a piece of tape on the inside: This will result in uneven contrast, with half of the image being less detailed and darker due to the blocked light.
c. Half of the lens on the enlarger is covered by a piece of paper: Similar to scenario (a), this will cause uneven exposure in the final print, with one half of the image being darker.
d. The camera lens is replaced by a diverging lens with the same focal length: This will lead to a distorted image, as the diverging lens causes light rays to spread out, resulting in decreased sharpness and focus.

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The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.

The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.

Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.

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The distance from the axis of the force applied is 2.05 m.

The distance from the axis of the force applied is calculated as follows;

The formula for torque;

τ = Fr

where;

Another formula for torque is given as;

τ = Iα

where;

τ = (mr²)α

τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)

τ = 39.36 Nm

The distance is calculated as;

r = τ/F

r = ( 39.36 Nm ) / (19.2 N)

r = 2.05 m

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Based on the Mann-Whitney U test results, there is a statistically significant difference in median survival times between large and small cell lung cancers. The estimated difference between the two medians is 89.5, suggesting that the median survival time for one group is longer than the other by 89.5 units.

Based on the Mann-Whitney U test results, the difference in median survival times between large and small cell lung cancers is statistically significant. The test statistic (W) is 1375.00 and the P-value is less than 0.001, indicating that the difference is unlikely to have occurred by chance. Additionally, the estimate of the difference between the two medians is 89.5, suggesting that the median survival time for small cell lung cancers is significantly shorter than that for large cell lung cancers.

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Answer:

B

Explanation:

If you dident pay for the no ad thing its okay all u have to do is answer one person's question every day befor you ask a question no ad's just answers you gotta do it every day tho

Answer:

Second option is correct.

The initial and the final velocity for the graph is

initial=2.5m/s; final=2.5m/s.

Explanation:

The graph plotted between velocity and time, is called velocity time graph.

Hence, second option is correct.

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Both of the bullets will hit the ground at the same time.

If we ignore any kind of air resistance and assume the surface of earth to be completely flat.

Let us first analyze the motion of the dropped bullet,

The initial velocity U is zero, if the height is h, and the acceleration is only because of gravity so it is g, then the time t is,

We can write,

H = ut + 1/2gt²

H = 1/2at²

t = √(2H/g)

Now, let us assume that the bullet is fired with some initial velocity u,

We have to notice that the velocity here is completely in the horizontal direction, so, analyzing the vertical motion,

We can write,

H = ut+1/2gt²

There is no initial velocity in vertical direction,

t = √(2H/g)

So, the time to hit the ground is same in both the cases.

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Answer:

can gravity from waves

Explanation:

yes gravity can froms way

The soil loss in  \(Mg ha^{-1}\) (Ton/ha) if the bulk density of the soil is 1.01  \(Mg m^{-3}\)  is option a. 0.202 Mg/ha.

For expressing the soil loss in \(Mg ha^{-1}\), need to convert the units appropriately. First, convert the soil loss from millimetres (mm) to meters (m) by dividing it by 1,000 (1 mm = 0.001 m). Thus, the soil loss is 0.0002 m.

Next, calculate the volume of soil lost per unit area (ha). The volume can be obtained by multiplying the soil loss (0.0002 m) by the area (ha). Since the bulk density of the soil is given as 1.01 \(Mg m^{-3}\), can convert the volume to mass by multiplying it by the bulk density.

Using the formula:

Soil loss (Mg ha-1) = Soil loss (m) × Bulk density (\(Mg m^{-3}\)) × Area (ha)

Substituting the values:

Soil loss (\(Mg ha-1\)) = 0.0002 m × 1.01 \(Mg m^{-3}\) × 1 ha

Calculating the result:

Soil loss (\(Mg ha-1\)) = 0.0002 × 1.01 = 0.000202 \(Mg ha-1\)

Therefore, the correct answer is option a. 0.202 Mg/ha.

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Answer:

Explanation:

Set specific, achievable goals: Break down your larger goal into smaller, more manageable targets that you can work towards each day. When you accomplish these smaller goals, it will give you a sense of accomplishment and motivation to continue working towards your larger goal.

Visualize your success: Imagine yourself successfully achieving your goal and all of the positive feelings that come along with it. This visualization can help keep you focused and motivated when distractions arise.

Find an accountability partner: Find someone who shares your goals and who can help you stay focused and motivated. This could be a friend, family member, or a coach. Having someone to share your progress with and to hold you accountable can be a powerful motivator.

Reward yourself: Set up a system of rewards for yourself when you reach certain milestones on the way to your goal. These rewards could be something as simple as a treat or a movie, or something more substantial like a new piece of workout equipment.

Get organized: Plan out your workouts and stick to a routine. Having a clear plan and structure can help you stay focused and motivated, as you can see how each workout is helping you to reach your goal.

Surround yourself with positive influences: Surround yourself with people who support and encourage your goals. Having positive influences in your life can help you stay motivated and inspired to reach your goals.

Answer:

Geothermal power plants require high-temperature (300°F to 700°F) hydrothermal resources that come from either dry steam wells or from hot water wells. People use these resources by drilling wells into the earth and then piping steam or hot water to the surface. The hot water or steam powers a turbine that generates electricity. Some geothermal wells are as much as 2 miles deep.

Explanation:

To calculate the tensile strength (T), we need to use the formula:

T = Force/Area

In this case, we are given the peak compressive force as 2084 N. However, we need to convert this to tensile force since we want to calculate the tensile strength. Tensile force is equal in magnitude but opposite in direction to compressive force.

Therefore, T = 2084 N

Next, we need to calculate the cross-sectional area (A) of the material. Given that the diameter of the material is 1 inch, we can calculate the radius (R) as half of the diameter:

R = 1 inch / 2 = 0.5 inch

We need to convert the radius to meters since the SI unit of force is Newton (N) and the SI unit of area is square meters (m^2). Since 1 inch is equal to 0.0254 meters, we can convert the radius as follows:

R = 0.5 inch * 0.0254 meters/inch = 0.0127 meters

Now, we can calculate the cross-sectional area (A) of the material using the formula for the area of a circle:

A = π * R^2

A = 3.1416 * (0.0127 meters)^2

A ≈ 0.0005087 square meters

Finally, we can calculate the tensile strength (T) using the formula:

T = 2084 N / 0.0005087 square meters

T ≈ 4,093,981.8 N/m^2

Therefore, the tensile strength (T) is approximately 4,093,981.8 N/m^2.

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Answer:

In a longitudinal wave, a compression is a region when the particles are closest together. A rarefaction is an area in a longitudinal wave where the particles are the furthest distant from one another. A compression is a zone where the medium is compressed, while a rarefaction is a region where the medium is spread out.

For the transistor model in the following figure, obtain the Thevenin equivalent is \(V_{th}\)=-700V and \(R_{th}=5\)kohm.

To find the Thevenin equivalent ,

By temporarily removing the load resistance from the original circuit and reducing what is left to an analogous circuit made up of a single voltage source and series resistance, Thevenin's theorem can simplify this analysis.

After reconnecting the load resistance to the Thevenin equivalent circuit, calculations can be performed as if the entire network were just a straightforward series circuit.

Now, the voltage given is 21V

\(R_{1}=3\) kohm

\(R_{2}=5\) kohm

as, V=ir

So, I=\(\frac{21}{R_{1} }\)

I=\(\frac{21}{3}\)

I=7mA

\(V_{th}\)=-20I×\(R_{2}\)

\(V_{th}\)=-20×7×5

\(V_{th}\)=-700V

and to find the value of \(R_{th}\)

i=0A

20i=0 means it is short circuit.

\(R_{th}=R_{2}=5\) kohm

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As stars get bigger and brighter, the closer they are to their end of life.

Because they have already used all the elements they can in nuclear fusion. Iron cannot be fused, its too heavy.

The most accurate graph here would be the third one.

Answer: The frequency increases as the pitch increases, and the amplitude increases as the volume increases

Explanation:

Waves have the property of:

v = f*λ

where v is the speed of the wave (which is almost constant for soundwaves, v = 340 m/s)

f is the frequency of the wave, and λ is the wavelength.

Now, we know that when the pitch of a note increases, also does the frequency of the soundwave (so the wave oscillates faster).

Now, we also want to include the amplitude of the soundwave in this.

The amplitude is related to the volume of the soundwave (actually is related to the energy, and as higher is the energy, more "loud" is the sound).

As the high pitch part is usually "louder", we can assume that we have an amplitude increase.

Then the answer would be:

"The frequency increases as the pitch increases, and the amplitude increases as the volume increases"

Therefore, the claims that are untrue are that increasing the temperature of the coal lump causes the emission to peak at a longer wavelength and increasing the temperature of the coal lump causes the emission to peak at a higher wavelength.

The separation between two identical points (adjacent crests) in subsequent cycles—determines whether it is transmitted via space or along a wire. In wireless systems, this length is often expressed in metres (m), centimetres (cm), or millimetres (mm) (mm). Radio waves, light waves, and infrared (heat) waves are examples of electromagnetic radiation that travel through space and leave behind characteristic patterns. Every wave is unique in its size and shape. Wavelength is defined as the distance between peaks (high points).

By measuring that distance between two identical locations on adjacent waves, the wavelength is always found. When determining the wavelength of the a longitudinal wave, the distance from one compression to the following or from one rarefaction to the following is measured.

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It is assumed that even if Europa has life, the total amount of that life will be small. This is due to the fact that Europa is a relatively small moon compared to other planetary bodies, and also because it lacks a substantial atmosphere that could support larger and more complex forms of life.

Additionally, the harsh environment on Europa, including its icy surface and potential for radiation exposure, would likely limit the growth and reproduction of any organisms that do exist. Therefore, while there may be some form of life on Europa, it is likely to be in small numbers and in less complex forms than what we see on Earth.

The total amount of life on Europa is assumed to be small because the harsh conditions on its surface and the potential limited resources within its subsurface ocean make it difficult for life to thrive. The lack of sunlight and energy sources also limit the potential for complex life forms to develop.

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(a) The speed of the ball at the lowest point is 1.97 m/s.

(b) The tension in the rod at the lowest point is 1.29 N since the ball is weightless at that instant.

(c) The angle at which the tension in the rod equals the weight of the ball is 81.4 degrees.

(d) The answer to (c) remains the same if the mass of the ball is increased.

(a) To find the speed of the ball at its lowest point, we can use the conservation of energy. At the highest point, the ball has potential energy equal to mgh, where m is the mass of the ball, g is the acceleration due to gravity (9.81 m/s²), and h is the height of the ball above its lowest point. At the lowest point, all of this potential energy is converted into kinetic energy, so we can set mgh = (1/2)mv², where v is the speed of the ball at its lowest point.

Solving for v, we get:

mgh = (1/2)mv²

v² = 2gh

v = √(2gh)

Plugging in the values, we get:

v = √(2 x 9.81 x 0.62) = 1.97 m/s

Therefore, the speed of the ball at its lowest point is 1.97 m/s.

(b) To find the tension in the rod at the lowest point, we can use Newton's second law. At the lowest point, the ball is moving in a circular path with a constant speed, so the net force on the ball is the centripetal force:

F_net = mv²/r

where r is the length of the rod. The only force acting on the ball at the lowest point is tension in the rod, so we can write:

T - mg = mv²/r

Solving for T, we get:

T = mv²/r + mg

Plugging in the values, we get:

T = (0.092 kg) x (1.97 m/s)² / 0.62 m + (0.092 kg) x (9.81 m/²) = 1.29 N

Therefore, the tension in the rod at the lowest point is 1.29 N.

(c) To find the angle at which the tension in the rod equals the weight of the ball, we can use trigonometry. Let θ be the angle between the rod and the vertical. At this angle, the tension in the rod is equal to the weight of the ball, so we can write:

T = mg sin(θ)

where m is the mass of the ball and g is the acceleration due to gravity.

Solving for θ, we get:

θ = \(sin^{(-1)\)T/mg)

Plugging in the values, we get:

θ = \(sin^{(-1)\)(1.29 N / (0.092 kg x 9.81 m/s²)) = 81.4 degrees

Therefore, the angle at which the tension in the rod equals the weight of the ball is 81.4 degrees.

(d) If the mass of the ball is increased, the answer to (c) will remain the same. This is because the tension in the rod and the weight of the ball both increase by the same factor, so their ratio remains the same.

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