Factorize: cos4θ + sin3θ . cosθ

Answer:

It would be -6 degrees Celsius.

Step-by-step explanation:

Answer:

Step-by-step explanation:

I reformatted the question to clarify the statements.  Please check for accuracy.

Given that D(x) = 2x, select all of the following that are true statements.

1.  D( x) is a direct variation.

2.  D( x) is a function.

3.  D( x) is a rule for the set of points (5, 10), (6, 12) and (-2, -4).

4.  x is the dependent variable.

5.  D(6) = 3

----------

1.  D( x) is a direct variation.   YES.  D(x) will always be 2 times x.

2.  D( x) is a function.   YES. Each calculated D(x) will have a unique point.

3.  D( x) is a rule for the set of points (5, 10), (6, 12) and (-2, -4).   YES.  Each (x,y) shows a value of y that is 2 times x, as per the equation's instructions.

4.  x is the dependent variable.   YES.  y depends on what value is chosen for x.

5.  D(6) = 3   NO.    d(6) = 2*(6) or 12  

The length of the gardens and the total area of Lisa's backyard is 26 ft. Therefore, option D is the correct answer.

The area of a trapezoid can be calculated if the length of its parallel sides and the distance (height) between them is given. The formula for the area of a trapezoid is expressed as, A = ½ (a+b)×h.

where (A) is the area of a trapezoid, 'a' and 'b' are the bases (parallel sides), and 'h' is the height (the perpendicular distance between a and b).

Given that, the vegetable garden and flower garden have an area of 216 ft

Here, the vegetable garden and flower garden is in the shape of trapezium with bases 10 ft and x ft and height is 12 ft

Here, area = 1/2 (10+x)×12

216=6(10+x)

(10+x)=36

x=26 ft

Therefore, option D is the correct answer.

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There  are no prime numbers between7,608 and 7,620

A prime number is a whole number greater than 1 whose only factors are 1 and itself

The numbers between 7608 and 7620 are:

7609,7610,7611,7612,7613,7614,7615,7616,7617,7618,7619

Here we have to check these numbers are prime number or not

Prime factorization

7609=7×1087

7610=2×5×761

7611=3×43×59

7612=2×2×11×173

7613=23×331

7614=2×3×3×3×3×47

7615=5×1523

7616=2×2×2×2×2×2×7×17

7617=3×2539

7618=2×13×293

7619=19×401

Hence, proved that there are no prime numbers between7608 and 7620

i) The dispersion relation for the given equation is ± (v / 6) * k.

ii) The group velocity for the given equation is ± v / 6.

iii) The phase velocity is ± v / 6.

To find the dispersion relation, as well as the group and phase velocities for the given equation, let's start by rewriting the equation in a standard form:

82y(x, t) - 8\(t^2\) + 84y(x,t) = -2 * 8\(x^4\)

Simplifying the equation further:

8(2y(x, t) - \(t^2\) + 4y(x,t)) = -16\(x^4\)

Dividing both sides by 8:

2y(x, t) - \(t^2\) + 4y(x,t) = -2\(x^4\)

Rearranging the terms:

6y(x, t) = \(t^2\) - 2\(x^4\)

Now, we can identify the coefficients of the equation:

Coefficient of y(x, t): 6

Coefficient of \(t^2\): 1

Coefficient of \(x^4\): -2

(i) Dispersion Relation:

The dispersion relation relates the angular frequency (ω) to the wave number (k). To determine the dispersion relation, we need to find ω as a function of k.

The equation given is in the form:

6y(x, t) = \(t^2\) - 2\(x^4\)

Comparing this with the general wave equation:

A * y(x, t) = B * \(t^2\) - C * \(x^4\)

We can see that A = 6, B = 1, and C = 2.

Using the relation between angular frequency and wave number for a linear wave equation:

\(w^2\) = \(v^2\) * \(k^2\)

where ω is the angular frequency, v is the phase velocity, and k is the wave number.

In our case, since there is no coefficient multiplying the y(x, t) term, we can set A = 1.

\(w^2\) = (\(v^2\) / \(A^2\)) * \(k^2\)

Substituting the values, we get:

\(w^2\) = (\(v^2\) / 36) * \(k^2\)

Therefore, the dispersion relation for the given equation is:

ω = ± (v / 6) * k

(ii) Group Velocity:

The group velocity (\(v_g\)) represents the velocity at which the overall shape or envelope of the wave propagates. It can be determined by differentiating the dispersion relation with respect to k:

\(v_g\) = dω / dk

Differentiating ω = ± (v / 6) * k with respect to k, we get:

\(v_g\) = ± v / 6

So, the group velocity for the given equation is:

\(v_g\) = ± v / 6

(iii) Phase Velocity:

The phase velocity (\(v_p\)) represents the velocity at which the individual wave crests or troughs propagate. It can be calculated by dividing the angular frequency by the wave number:

\(v_p\) = ω / k

For our equation, substituting the dispersion relation ω = ± (v / 6) * k, we have:

\(v_p\) = (± (v / 6) * k) / k

\(v_p\) = ± v / 6

Therefore, the phase velocity for the given equation is:

\(v_p\) = ± v / 6

To summarize:

(i) The dispersion relation is ω = ± (v / 6) * k.

(ii) The group velocity is \(v_g\) = ± v / 6.

(iii) The phase velocity is \(v_p\) = ± v / 6.

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The solution to the inequality is the interval notation:

(-∞, 3] ∪ [4, +∞)

To solve the rational inequality:

x^2 - 4x - 7x + 12 ≤ 0

We can start by factoring the quadratic expression:

(x - 4)(x - 3) ≤ 0

Now, we can determine the critical points by setting each factor equal to zero:

x - 4 = 0 => x = 4

x - 3 = 0 => x = 3

These critical points divide the number line into three intervals: (-∞, 3), (3, 4), and (4, +∞).

To determine the sign of the inequality within each interval, we can choose test points. For example, we can choose x = 0 for the interval (-∞, 3):

(0 - 4)(0 - 3) ≤ 0

(-4)(-3) ≤ 0

12 ≤ 0

Since 12 is not less than or equal to 0, the inequality is not satisfied for x = 0 within this interval.

Next, we can choose x = 3 for the interval (3, 4):

(3 - 4)(3 - 3) ≤ 0

(-1)(0) ≤ 0

0 ≤ 0

Since 0 is equal to 0, the inequality is satisfied for x = 3 within this interval.

Finally, we can choose x = 5 for the interval (4, +∞):

(5 - 4)(5 - 3) ≤ 0

(1)(2) ≤ 0

2 ≤ 0

Since 2 is not less than or equal to 0, the inequality is not satisfied for x = 5 within this interval.

Therefore, the solution to the inequality is the interval notation:

(-∞, 3] ∪ [4, +∞)

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Answer:

y≥−3/2x−2

Step-by-step explanation:

the inequality is represented by the graph is y≥−3/2x−2

Answer:

6+15t

Step-by-step explanation:

3(2+5t)

3(2)+3(5t)

6+3(5t)

6+15t

We have a differential equation as 6x5sin(2x)y′′−2x2cos(6x)y′=0 given that y1=2 and y2=cos2(6x) sin2(6x) are the solutions.

To prove this we can check whether both solutions satisfy the given differential equation or not. We know that the second derivative of y with respect to x is the derivative of y with respect to x and is denoted as "y′′. Now, we take the derivative of y1 and y2 twice with respect to x to check whether both are the solutions or not. Finding the derivatives of y1:Since y1 = 2, we know that the derivative of any constant is zero and is denoted as d/dx [a] = 0. Therefore, y′ = 0 . Now, we can differentiate the derivative of y′ and obtain y′′ as d2y1dx2=0. Thus, y1 satisfies the given differential equation. Finding the derivatives of y2:Now, we take the derivative of y2 twice with respect to x to check whether it satisfies the given differential equation or not. Differentiating y2 with respect to x, we get y′=12sin(12x)cos(12x)−12sin(12x)cos(12x)=0. Differentiating y′ with respect to x, we get y′′=−6sin(12x)cos(12x)−6sin(12x)cos(12x)=−12sin(12x)cos(12x)Therefore, y2 satisfies the given differential equation.
Hence, both y1 = 2 and y2 = cos^2(6x) sin^2(6x) are the solutions to the given differential equation 6x^5 sin(2x)y′′ − 2x^2 cos(6x)y′ = 0. Both y1 = 2 and y2 = cos^2(6x) sin^2(6x) are the solutions to the given differential equation 6x^5 sin(2x)y′′ − 2x^2 cos(6x)y′ = 0. To prove this, we checked whether both solutions satisfy the given differential equation or not. We found that the second derivative of y with respect to x is the derivative of y with respect to x and is denoted as y′′. We differentiated the y1 and y2 twice with respect to x and found that both y1 and y2 satisfy the given differential equation. Both y1 = 2 and y2 = cos^2(6x) sin^2(6x) are the solutions to the given differential equation.

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\( \: \: \: \: \: \: \: \)

GCF OF 48

The greatest common factor of 8, 28, and 48 is 4.

The largest common factor out of all the numbers in the given set is known as Greatest Common Factor.

Factors of 8, \(8=2\times 2\times 2\)

Factors of 28, \(28=2\times 2\times 7\)

Factors of 48, \(48=2\times 2\times 2\times 2\times 3\)

The common factors in the above set of numbers are 2and 2.

So, the Greatest Common Factor of 8, 28, and 48 is  \(2\times 2=4\).

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The bounds for a 95% confidence interval could be option (B) 72 and 79

We know that the 98% confidence interval has bounds of 73 and 80. This means that if we were to repeat the same experiment many times, we would expect that 98% of the time, the true population mean would fall within this range.

To find the bounds for a 95% confidence interval, we can use the fact that a higher confidence level corresponds to a wider interval, and a lower confidence level corresponds to a narrower interval.

Since we want a narrower interval for a 95% confidence level, we can expect the bounds to be closer to the sample mean. We can calculate the sample mean as the midpoint of the 98% confidence interval

(sample mean) = (lower bound + upper bound) / 2 = (73 + 80) / 2 = 76.5

Next, we can use the formula for a confidence interval:

(sample mean) ± (z-score) × (standard error)

where the z-score depends on the desired confidence level, and the standard error depends on the sample size and sample standard deviation. Since we don't have this information, we can assume that the sample size is large enough (i.e., greater than 30) for the central limit theorem to apply, and we can use the formula

standard error = (width of 98% CI) / (2 × z-score)

For a 98% confidence interval, the z-score is 2.33 (found using a standard normal distribution table or calculator). Plugging in the values, we get

standard error = (80 - 73) / (2 × 2.33) = 1.70

Now, we can use this standard error to calculate the bounds for a 95% confidence interval

(sample mean) ± (z-score) × (standard error) = 76.5 ± 1.96 × 1.70

Simplifying, we get

(lower bound) = 76.5 - 3.33 = 73.17

(upper bound) = 76.5 + 3.33 = 79.83

Therefore, the correct option is (B) 72 and 79

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Answer: The right answer would be 125x125 because 5^6 is the same as 5^3 x 5^3 (5^3 = 125).

Step-by-step explanation:

Answer:

88 people

Step-by-step explanation:

Start with the equation of

\(3,000\geq 33x+80\)

subtract 80

\(3.000\geq 33x\)

then divide by 33

\(88.48\geq x\)

round down

\(x=88\)

Answer:

The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero). The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero).

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

just answered it !

Answer:

The y-intercept is at (0, 8).

Answer: (0,8)

Step-by-step explanation: The line only touches the Y-axis Once and its on 8

Step-by-step explanation:

-5x+2y= 4         <==== Multiply entire equation by -3 to get:

15x-6y = -12  

2x+3y= 6          <====  Multiply entire equation by 2 to get :

4x+6y = 12    Add the two underlined equations to eliminate 'y'

19x = 0     so x = 0

sub in x = 0 into any of the equations to find:  y = 2

(0,2)

The correct answer is b) Decrease SSwithin and increase the size of the F-ratio.

If an analysis of variance is used for the following data (M1 = 10, M2 = 20, SS1 = 90, SS2 = 70), the effect of changing the value of SS1 to 50 would be:

a) Increase SSwithin and decrease the size of the F-ratio

Calculate the SSwithin (sum of squares within) using the original data: SSwithin = SS1 + SS2 = 90 + 70 = 160
Change the value of SS1 to 50, as specified in the question.
Recalculate SSwithin using the new SS1 value: SSwithin_new = SS1_new + SS2 = 50 + 70 = 120
Compare the original SSwithin and the new SSwithin: SSwithin_new < SSwithin, so SSwithin has decreased.
The F-ratio is calculated as MSbetween / MSwithin, where MSbetween is the mean square between groups, and MSwithin is the mean square within groups. Since SSwithin has decreased, MSwithin will also decrease, leading to an increase in the F-ratio.

So, the correct answer is b) Decrease SSwithin and increase the size of the F-ratio.

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Answer:

a quadratic function

Step-by-step explanation:

A quadratic function is a second-degree polynomialfunction, and when graphed is called a parabola.

The quarterly dividend payment per share based on the question above will be: $0.02.

The close price for the week will be: $5.45.

For one to find the closing price for the week, we have to divide the total cost of the shares by using the number of shares that was bought so it will be:

Close price = Total cost / Number of shares

                    = $2,790.40 / 512

                    = $5.45

To know the quarterly dividend payment per share, we have to calculate the annual dividend payment per share before we can get it so it will be:

Annual dividend per share = Total annual dividend / Number of shares

                                              = $40.96 / 512

                                                = $0.08

From the question, the dividend was paid quarterly, we then divide the annual dividend per share by 4 so as to get the quarterly dividend per share:

Quarterly dividend per share = Annual dividend per share / 4

                                                  = $0.08 / 4

                                                   = $0.02

Hence the quarterly dividend payment per share will be: $0.02.

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See text below

Ignoring commission, 512 shares of Targa Resources (TRGP) were purchased for $2,790.40 at the clos for the week. Find the close price for the week. Then, find the quarterly dividend payment per share if the annual dividend amount paid was $40.96. (7pts)

EARNINGS

52-WEEK

TICK

VOL.

WEEK'S

LATEST

THIS NEXT DIV

High Low

Name

Sym.

100s

Yld.

P/E Last Chg.

Year

Year

Year

Amt

8.50

3.20

Targa Resources

TRGP

412574 1.8

PO

dd

+0.41

0.25

0.18

0.12

The smallest rational number among -5/16, -13/24, -3/4, and -7/12 is -3/4.

We have,

To determine the smallest rational number among -5/16, -13/24, -3/4, and -7/12, we need to compare their values.

Let's convert all the given rational numbers to have a common denominator of 48:

-5/16 = -15/48

-13/24 = -26/48

-3/4 = -36/48

-7/12 = -28/48

Now, the values of these rational numbers, when expressed with a common denominator, are:

-15/48, -26/48, -36/48, -28/48

Among these values, the smallest one is -36/48, which is equivalent to -3/4.

Therefore,

The smallest rational number among -5/16, -13/24, -3/4, and -7/12 is -3/4.

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Step-by-step explanation:

the function is

d(n) = sqrt(1.49×n)

so,

85 = sqrt(1.49×n)

85² = 1.49×n

n = 85²/1.49 = 7225/1.49 = 4,848.993289... ft

≈ 4,849 ft

Answer: 1/2

Step-by-step explanation:

Use the slope-intercept form

y

=

m

x

+

b

to find the slope

m

.

m

=

1

2

Answer:

the cashier would have 15000 dollars at the end of the year.

Step-by-step explanation:

is that what you were asking?

Answer:

105 cm

Step-by-step explanation:

3/7 = 45/x

cross-multiply:

3x = 315

x = 105

Answer:

18x = -100 is the simplified form

Step-by-step explanation:

(3/4x) + 5 = (5/6)

3/4x (*24) + 5 (*24) = 5/6 (*24)

18x + 120 = 20

The measure angle EBF is (5b-24)°.

Adjacent angles are those angles that are always placed next to each other in such a way that they share a common vertex and a common side but they do not overlap each other.

Give that, m∠ABF =(7b-24)° and m∠ABE =2b°.

From the figure,

m∠ABF =m∠ABE + m∠EBF

(7b-24)°=2b° + m∠EBF

m∠EBF = 7b-24-2b

m∠EBF = (5b-24)°

Therefore, the measure angle EBF is (5b-24)°.

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The ratios of (a) square kens to square meters (1 ken² / 1 m²) is 3.88

For given question,

We have been given the unit conversion.

A traditional unit of length in Japan is the ken

and 1 ken = 1.97 m

We need to find the the ratios of (a) square kens to square meters.

First we find the square of 1 ken.

⇒ 1 square kens = (1.97 m)²

⇒ 1 square kens = 1.97 × 1.97 m²

⇒ 1 square kens = 3.88 m²                  ..................(1)

And 1 square meters = 1 m²                 ................. (2)

Now we take the ratio of square kens to square meters.

From (1) and (2),

⇒ 1 ken² / 1 m² = 3.88 / 1

⇒ 1 ken² / 1 m² = 3.88

Therefore, the ratios of (a) square kens to square meters (1 ken² / 1 m²) is 3.88

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