Explain a lever and a pivot in a full sentence​

Answer:

The flux through the sphere will remain the same, and the magnitude of the electric field will increase by four times.

Explanation:

The electric flux is the number of electric field, passing through a given area. It is proportional to the electric field strength and the area through which this field passes.

If the radius of the sphere is halved, the area of the sphere will reduce by square of the reduction, which will be four times. The electric field lines will become closer together, or technically increase by a fourth of its initial value. The resultant effect is that the electric flux will remain the same.

If originally,

Φ = EA cos∅

where Φ is the electric flux through the sphere

E is the electric field on the sphere

A is the area of the sphere.

If the area of the sphere is reduced to half, then,

the area reduces to A/4,

and the electric field increases to be 4E on the sphere.

The flux now becomes

Φ = 4E x A/4 cos∅

which reduces to

Φ = EA cos∅

which is the initial electric flux on the sphere.

Explanation:

CON EL TEOREMA DE PITÁGORAS

v = \(\sqrt{(12 km/h)^{2} + (25 km/h)^{2}}\) = 27.7 km/h

 The average kinetic energy of CO2 molecules with a root-mean-square speed of 629 m/s is 49.4 kJ/mol.

The   thermodynamics root-mean-square (rms) speed of gas molecules is a measure of their average speed and is related to their kinetic energy. The kinetic energy of a gas molecule is proportional to the square of its speed.

Therefore, the rms speed can be used to calculate the average kinetic energy of the gas molecules. In this case, we are given the rms speed of CO2 molecules as 629 m/s. Using this value, we can calculate the average kinetic energy of CO2 molecules using the formula:

average kinetic energy = 1/2 * m * (rms speed)^2

where m is the molar mass of CO2, which is 44.01 g/mol. Converting this to kg/mol and substituting the values, we get:

average kinetic energy = 1/2 * (0.04401 kg/mol) * (629 m/s)^2 = 49.4 kJ/mol

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Answer:

C. Newton

Explanation:

hope this helped:)

Answer:

ok

Explanation:

Paine's Rejection of British Protection.

Upakar Thapa

What does Paine say about the argument that Britain has defended the colonies in the past? A. That the colonists should have protected Britain B. That the colonists never really needed the help OC. That Britain only did so out of self-interest D. That Britain created conflict so its protection seemed needed

The reference to "Paine" likely refers to Thomas Paine, a political activist and writer who was a key figure in the American Revolution. In his influential pamphlet "Common Sense," which was published in 1776, Paine argued for American independence from Britain.

Regarding the argument that Britain has defended the colonies in the past, Paine argues that this is not a valid reason for the colonies to remain under British rule. He asserts that Britain's protection of the colonies was motivated by its own self-interest, rather than a genuine concern for the well-being of the colonists.

Paine argues that Britain has actually done more harm than good for the colonies, pointing to the various restrictions and regulations that the British government has placed on the colonies. He also asserts that the colonies are perfectly capable of defending themselves, and that they should not rely on Britain for protection.

Overall, Paine's argument is that the colonies should seek independence from Britain in order to secure their own freedom and self-determination.

Upakar Thapa

The First Law of Thermodynamics is generally referred to as _____.

First Law of Motion

Joule's Law E = IR2

Law of Conservation of Matter and Energy

Universal Gravitation

The First Law of Thermodynamics is generally referred to as the "Law of Conservation of Matter and Energy."

Upakar Thapa

Consider a gas at STP in a container of 22.4 L. If you apply the ideal gas law, what is the approximate value of n?

a. 1

b. 8.31

c. 224

d. 0.5

At STP (Standard Temperature and Pressure), the conditions are defined as 1 atmosphere of pressure and 0°C (273.15 K) of temperature.

Using the ideal gas law, we have:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

At STP, the pressure is 1 atm, the volume is 22.4 L, and the temperature is 273.15 K.

Substituting these values into the ideal gas law, we get:

(1 atm) (22.4 L) = n (8.31 J/mol·K) (273.15 K)

Simplifying, we get:

n = (1 atm) (22.4 L) / (8.31 J/mol·K) (273.15 K)

n = 1

Therefore, the approximate value of n is a. 1.

Answer:

they will increase why because they go from warm cold warm meaning they have to adapt back to the previous location

Explanation:

When birds sit on a single power line, they are not grounded, which means they do not provide a path for current to flow from the high voltage power line through their body to the ground. But if they were to place one foot on each of two lines, they would complete a circuit, and current would flow through their body, and they would receive a terrible shock.

Electricity flows through a circuit when there is a path for current to flow from a power source to the ground. The power lines carry high voltage electricity, which can be dangerous to living organisms, including birds. However, birds sitting on a single power line don't get shocked because they are not providing a path for current to flow from the power line through their body to the ground.The reason birds are not grounded when they sit on a single power line is that they have only one point of contact with the power line.

Therefore, the current cannot flow through their body and reach the ground. In other words, they are not part of the circuit.In conclusion, birds sitting on a single power line do not get shocked because they are not grounded and do not provide a path for current to flow through their body to the ground. However, if they were to place one foot on each of two lines, they would complete a circuit, and current would flow through their body, resulting in a terrible shock.

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If I'm understanding the picture, it looks like the riders add up to 117.8 .

The same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.

Let us understand what these terms mean:

In statistical analysis, multicollinearity is the high correlation among predictors in a regression model. It is problematic because of its adverse effects on the model, including making it difficult to determine the effect of an independent variable, coefficients becoming insensitive to small changes in the model, and reducing the reliability of the model.

In regression analysis, independent predictors are those variables that contribute to the prediction of the dependent variable or outcome, and their inclusion in the model improves the accuracy of the prediction of the model.

In a regression model, it is an assumption that predictors are independent, which means that the predictors have little to no correlation with each other. If this assumption is violated, it is known as multicollinearity.

Therefore, the same thing could reasonably be said about multicollinearity. Specifically, the reason for this is due to the violation of the assumption of independent predictors.

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In order to chill a 750mL bottle of champagne using a bucket of ice at 0 degrees Celsius, approximately 249 grams of ice must melt. The specific heat capacity of ice is approximately 2.09 J/g°C.

To determine the amount of ice that needs to melt, we can use the principles of thermodynamics. First, we need to calculate the heat lost by the champagne and the heat gained by the melting ice. The heat lost by the champagne can be calculated using the equation Q = mcΔT, where Q is the heat lost, m is the mass of the champagne, c is the specific heat capacity of champagne, and ΔT is the change in temperature. Similarly, the heat gained by the ice can be calculated using the same equation, where m is the mass of the ice and c is the specific heat capacity of ice.

Given that the initial temperature of the champagne is 25 degrees Celsius and the final temperature is 8 degrees Celsius, ΔT for the champagne is 25 - 8 = 17 degrees Celsius. The specific heat capacity of champagne is approximately the same as water, which is 4.18 J/g°C. Therefore, the heat lost by the champagne is Q = (750g)(4.18 J/g°C)(17°C) = 53,595 J.

Since the ice is at 0 degrees Celsius, ΔT for the ice is 0 - (-8) = 8 degrees Celsius. The specific heat capacity of ice is approximately 2.09 J/g°C. Therefore, the heat gained by the ice is equal to the heat lost by the champagne, which is 53,595 J. Using the equation Q = mcΔT and solving for the mass of ice (m), we can rearrange the equation to m = Q / (cΔT). Plugging in the values, we get m = 53,595 J / (2.09 J/g°C * 8°C) ≈ 249 grams.

Therefore, approximately 249 grams of ice must melt in order to chill the champagne from 25 degrees Celsius to 8 degrees Celsius in a bucket of ice at 0 degrees Celsius.

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If you could somehow travel at a jet-plane speed of 2800 km/h, it would take approximately 1.20 × 10^9 years to cover a distance equivalent to one light-year.

To determine the time it would take to travel a certain distance at jet-plane speed, we need to know the distance that needs to be covered. However, in this case, the distance mentioned is one light-year, which is approximately 9.46×10^12 km.

If we consider traveling at a jet-plane speed of 2800 km/h, it is still significantly slower compared to the immense distance of one light-year. Let's calculate the time it would take to cover this distance.

Time = Distance / Speed

Time = (9.46×10^12 km) / (2800 km/h)

Converting the units, we have:

Time = (9.46×10^12 km) / (2800 km/h) * (1 h / 3600 s) * (1 year / 365 days) * (1 day / 24 h)

Calculating this, we get:

Time ≈ 1.20 × 10^9 years

Therefore, if you could somehow travel at a jet-plane speed of 2800 km/h, it would take approximately 1.20 × 10^9 years to cover a distance equivalent to one light-year.

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Answer:

I believe it is false I took the test

Answer:

false

Explanation:

If both the speed and radius of a circular path of a body  are doubled then centripetal acceleration will also be doubled.

The characteristic of an object moving in a circular path is known as centripetal acceleration. Centripetal acceleration is the term for any moving object whose acceleration vector is directed toward the center of the circle. The centripetal acceleration formula is as follows:

\(a_c=v^2 /r\)

where v is the angular speed and r is the radius.

Now for the given question,

Original centripetal acceleration,

\(a=v^2 /r\)

New centripetal acceleration,

\(a^{'} =(2v)^2 /2r\\\\=2v^2/r\\=2a\)

Hence, centripetal accelearation is also doubled.

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   ​

Work must be done on the particle to cause it to move to the right at 33 m/s  is 5.54 J

What is work done?

When we apply force "F" to a block, the body moves with some acceleration or, additionally, its speed increases or decreases depending on the direction of the force. The system's kinetic energy changes as speed increases or decreases. Since we are aware that energy cannot be created or destroyed, it must be changed into another form. This perspective refers to it as completed work. When negative energy is finished, the energy declines, and when positive energy is finished, the energy rises. Now, we'll see how to gauge the amount of work done.

Work Done on a Particle:

The change in a particle's kinetic energy is what is referred to as work done on a particle. The particle has an initial kinetic energy if it is originally moving. However, there is also a change in the particle's kinetic energy if its direction of travel changes.

u=29m/s

v=43m/s

from work- energy theorem

W=change in K.E

= 1/2mv^2 -1/2mu^2

= 1/2m(v^2 - (-u)^2)

=0.5*0.011*(43*43-29*29)

W=5.54 J

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After oxygen has been administered, the next priority intervention the nurse would initiate for a patient with a pulmonary embolus is the administration of IV Heparin.

Heparin is a prescription medicine used to treat and prevent symptoms of blood clots caused by medical conditions or medical procedures. Heparin may be used alone or with the other medications. Heparin belongs to a class of drugs called the Anticoagulants, Cardiovascular, Anticoagulants, Hematologic.

Heparin may cause serious side effects including:

skin warmth or discoloration,

chest pain,

irregular heartbeats,

shortness of breath,

dizziness,

anxiety,

sweating,

unusual bleeding or bruising,

severe pain or swelling in your stomach, lower back/growing

dark or blue-colored skin on your hands/feet,

nausea,

vomiting,

loss of appetite,

unusual tiredness,

bleeding that will not stop,

nosebleed,

blood in the urine or stool,

black or tarry stools,

coughing up blood or vomit that looks like the coffee grounds,

skin changes where the medication was injected,

fever,

chills,

runny nose,

watery eyes,

easy bruising,

purple or red spots under your skin,

sudden numbness or weakness,

problems with vision or speech, and

swelling or redness in an arm or leg

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The Mach number for the plane is approximately 3.51.

To find the speed of the plane, we can use the equation:

Speed of sound = Speed of the plane / Time taken

Given: Speed of sound (v) = 344 m/s

Time taken (t) = 3.51 seconds

Let's calculate the speed of the plane:

Speed of plane = Speed of sound × Time taken

Speed of plane =\(344 m/s * 3.51 s\)

Speed of plane ≈ 1206.44 m/s

Rounded to 2 decimal places, the speed of the plane is approximately 1206.44 m/s.

To find the Mach number of the plane, we need to divide the speed of the plane by the speed of sound:

Mach number = Speed of plane / Speed of sound

Mach number ≈ \(1206.44 m/s / 344 m/s\)

Mach number ≈ 3.51

Rounded to 2 decimal places, the Mach number for the plane is approximately 3.51.

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Answer:

\(displacement = ( + 100) + ( - 40) \\ = 60 \: m\)

Answer:

60m

Explanation:

Major faunal extinctions occurred several times in the geologic past. The boundaries between eras were drawn were mass extinctions events occurred. The earlier of these two extinctions occurred at the end of the Permian Period, 252 million years ago.5 fossil groups that bacame extinct at this time Trilobites,Foraminifera,Blastoids,Brachiopods,Fusulinids.

List of five fossil groups that became extinct at this time are as follows:

Trilobites: These were one of the most diverse and abundant arthropod groups with a long fossil record. Trilobites were one of the first fossil groups to appear in the Cambrian Period and they disappeared during the end-Permian extinction.

Foraminifera: These were a type of single-celled protozoa that form small shells. They were common in shallow water environments and were abundant in the Permian.

Blastoids: These were extinct, stemmed echinoderms which were abundant in the Mississippian Period. They declined during the Pennsylvanian and disappeared during the Permian.

Brachiopods: These are marine invertebrates which have a two-part shell. Brachiopods were abundant throughout the Paleozoic Era and many species became extinct during the Permian.

Fusulinids: These were a type of single-celled protozoa that formed large shells. They were abundant in the late Carboniferous and Permian and disappeared during the end-Permian extinction.

Thus, these were the five fossil groups that became extinct during the end of the Permian period.

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Answer:

B: Solids

Explanation:

I have notes from EDG and I looked it up on the internet

I hope this helps

In the solids, convection can not occur. Convection can only be done in the fluids.

Under the effect of gravity, hotter, less dense material rises while colder, denser stuff sinks, resulting in heat transfer"Convection is the ultimate mode of energy transmission to the surface"

There are three modes of the heat transfer;

1. Conduction

2. Convection

3. Radiation

Convection occurs in the fluid which is liquid and gases. Convection never occurs in the solid.

Hence option B is correct.

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In the process, small particles, including sand and silt, are blown away, leaving behind a flat and barren surface. The removal of soil particles by wind can leave the underlying rocks exposed, which are then further eroded by the wind. The process by which the ground surface is lowered by wind erosion is called deflation.

The process by which the ground surface is lowered by wind erosion is called deflation.What is wind erosion?Wind erosion is a geological process that refers to the displacement or removal of surface material, including rock and soil, as a result of wind activity. The process occurs through the action of saltation, abrasion, and suspension.What is deflation?The process of lowering the ground surface by wind erosion is referred to as deflation. The action of deflation on soil and rock surface occurs when the wind removes the topmost layer of soil, leaving behind a flatter surface.This process is facilitated when the wind attains high velocity, which makes it capable of transporting a considerable amount of particles in its path. In the process, small particles, including sand and silt, are blown away, leaving behind a flat and barren surface. The removal of soil particles by wind can leave the underlying rocks exposed, which are then further eroded by the wind.

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Rolanda needs to advise her friend to place the note about mass in region z and the note about charge in region x to fix the mistake in the Venn diagram. Therefore, the correct answer is option A.

Rolanda should suggest to her friend that the note about mass belongs in region z, and the note about charge belongs in region x. This correction is necessary because gravitational force depends on mass, while electrical force depends on charge.

The x in the circle on the left with infinite reach and depends on mass is incorrect because gravitational force does not have infinite reach. It only acts between objects with mass that are in close proximity to each other. The y in the intersecting area is also incorrect because there is no force that is common to both gravitational and electrical forces.

On the other hand, the z in the circle on the right with depends on charge is correct because electrical force depends on the charge of the objects involved. By suggesting that the note about mass belongs in region z and the note about charge belongs in region x, the Venn diagram will accurately represent the differences between gravitational and electrical forces.

In summary, Rolanda should suggest to her friend that the note about mass belongs in region z and the note about charge belongs in region x. Therefore, the correct answer is option A.

This will correct the error in the Venn diagram and accurately represent the differences between gravitational and electrical forces. It is important to understand these differences in order to properly understand the behavior of objects in our world.

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Answer:

Should be a rotation, but if that isn't on there it might be a revolution.

Explanation:

I could be wrong but im about 90 percent sure this is right

The method used when an entire mole is removed for examination under a microscope is called an excisional biopsy.

This method involves the surgical removal of the entire mole and some surrounding skin which is then examined under a microscope to check for any abnormal cells or signs of cancer. This method is typically used when a mole is suspected to be malignant or when it cannot be clearly diagnosed as benign through other methods such as a shave or punch biopsy.

The key benefit is that, as opposed to an incisional biopsy, when a bit of the tissue is taken to provide a diagnosis but it will likely still need to be treated later, the aberrant tissue may be identified, diagnosed, and removed in one operation.

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3. The relative humidity of the air parcel at 18°C with an actual water vapor content of 9g/kg is approximately 25.71%.

4. The relative humidity of the air parcel at 31°C with an actual water vapor content of 27g/kg is approximately 87.10%.

Explanation:-

To calculate the relative humidity (RH) in both scenarios, we need to compare the actual water vapor content of the air to the maximum capacity at the given temperature.

3.  Temperature: 18°C

Actual water vapor content of the air: 9g/kg

Maximum capacity at 18°C: 35g/kg

RH = (Actual water vapor content / Maximum capacity) * 100

RH = (9g/kg / 35g/kg) * 100

RH ≈ 25.71%

Therefore, the relative humidity of the air parcel at 18°C with an actual water vapor content of 9g/kg is approximately 25.71%.

4.  Temperature: 31°C

Actual water vapor content of the air: 27g/kg

Maximum capacity at 31°C: 31g/kg

RH = (Actual water vapor content / Maximum capacity) * 100

RH = (27g/kg / 31g/kg) * 100

RH ≈ 87.10%

Therefore, the relative humidity of the air parcel at 31°C with an actual water vapor content of 27g/kg is approximately 87.10%.

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Answer:

6 units

Explanation:

Gravitational force between two objects is given by the equation

\(F = G \dfrac{m_1m_2}{r^2}\)

where

\(G =\)universal gravitational constant
\(m_1\), \(;m_2\) are the masses of the objects

\(r\) = distance between the objects

We are given that F = 18 units.

If m₁ is tripled and r is also tripled then

new F = F':

\(F' = G \dfrac{3m_1 \cdot m_2}{(3r)^2}\\\\\\F' = G \dfrac{3m_1 \cdot m_2}{9r^{2}}\\\\\\So \dfrac{F'}{F} = G \dfrac{3m_1 \cdot m_2}{9r^{2}} \div G \dfrac{m_1 \cdot m_2}{r^{2}}\)

\(= \dfrac{3}{9} = \dfrac{1}{3}\\\)

Therefore the new F is 1/3 of the old f

In this case that would be 18/3 = 6 units

Answer:

in the nucleus of the atom

Explanation:

a p 3 x

The skydiver experiences a downward acceleration of 9.80 m/s^2 during her descent due to the force of gravity.

When the skydiver jumps off the plane, she experiences a downward force due to gravity. The force of gravity can be calculated using the formula F = m * g, where m is the mass of the skydiver and g is the acceleration due to gravity. In this case, the mass of the skydiver is 80.0 kg and the acceleration due to gravity is 9.80 m/s^2.

Using the formula, we can calculate the force of gravity:

F = (80.0 kg) * (9.80 m/s^2)

= 784.0 N

This is the force pulling the skydiver downward. As a result, the skydiver experiences a downward acceleration of 9.80 m/s^2.

Throughout her descent, the skydiver will continue to accelerate downward until she reaches her terminal velocity. The terminal velocity is the maximum speed at which the force of gravity is balanced by the air resistance. At terminal velocity, the net force on the skydiver becomes zero, and she falls at a constant speed.

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\(w = F * S\)

\(F = 20\\S = 10\\F * S = 20 * 10 = 200\) Joules <- 1st answer

\(w = F * S\)

\(1234 = F * 100\)

\(F = \frac{1234}{100}\)

\(F = 12.34 N\)  <- 2nd answer

The solution to the differential equation is then:

x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t)

And the system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.

The force required to stretch a spring is directly proportional to the amount the spring is stretched. This relationship is known as Hooke’s Law. It can be expressed mathematically as:

F = -kx

Where F is the force applied to the spring, x is the displacement of the spring from its equilibrium position, and k is the spring constant.

For a mass-spring system under the influence of a damping force, the differential equation governing the system is:

m(d2x/dt2) + c(dx/dt) + kx = 0

where m is the mass of the object attached to the spring, c is the damping coefficient, and k is the spring constant.

The given force of 2 lb stretches the spring by 1 ft, so the spring constant is given by k = F/x = 2/1 = 2 lb/ft.

The 8-lb weight is released 4 in. above the equilibrium position, which is 0.25 ft. The initial displacement is therefore x(0) = 0.25 ft, and the initial velocity is v(0) = 0. The damping force is given by f_d = -3/2v. Using the values given, the differential equation for the system is:

m(d2x/dt2) + c(dx/dt) + kx = 0 (1)

The values of m, k, and c are given by

m = 8/g = 8/32.2 = 0.248 kg

k = 2/lb/ft * 0.4536 kg/lb * 0.3048 m/ft = 0.294 kg/sm = 0.248 kgc = 3/2

The equation of motion is then:

d2x/dt2 + 12.05dx/dt + 1.186x = 0 (2)

where we have substituted the values of m, c, and k into equation (1).

The characteristic equation is:

r2 + 12.05r + 1.186 = 0 (3)

Solving for the roots of the characteristic equation, we find:

r = (-12.05 ± √(12.052 - 4(1.186)))/2= -6.025 ± 2.181i

The roots are complex conjugates, so the solution to the differential equation can be written as:

x(t) = e⁽⁻⁶·⁰²⁵t⁾(C₁ cos(2.181t) + C₂ sin(2.181t)) (4)

The initial displacement and velocity are given by x(0) = 0.25 and v(0) = 0.

Substituting these values into equation (4) and taking the derivative, we get:

x(0) = C₁ = 0.25dx/dt|t=0 = -6.025

C₂ = 0

Solving for C₁ and C₂, we get:

C₁ = 0.25C2 = 0

The solution to the differential equation is then:

x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t) (5)

The system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.

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Answer: b

Explanation:

The gravitational pull between two objects depends on their mass and distance. Distance meant by :

B. How close the two objects are located, meaning that closer objects have a stronger gravitational pull.

Gravitational force depends directly on the mass of two objects and inversely on the square of the distance between them. This means that gravity increases when mass increases, but decreases when the distance between objects increases. g = GM/r2, where M is the mass of the Earth, r is the radius of the Earth (or the distance between the centre of the Earth ). and you are standing on its surface), and G is the gravitational constant. G (without subscript) is the gravitational constant and c is the speed of light.

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