Evaluate the integral using integration by parts. Do not use any other method. You must show your work. Vu x sin(x) dx

Answer:

Median: 9

Mode: 10

Range: 4

Step-by-step explanation:

Median

Line up all the numbers from smallest to biggest and take the one in the middle. In this case it's both 8 and 10. So you would do (8+10)/2. which is 9

Mode

it's the number that occurs the most number of times, which is 10.

Range

Range is 10-6, so it's 4.

A mean is an arithmetic average of a set of observations. The mean, median, and the range of the given data set 6, 8, 10, 10 are 8.5, 9, and 4 respectively.

A mean is an arithmetic average of a set of observations. it is given by the formula,

Mean = (Sum of observations)/Number of observations

The mean, median and range of the given data set 6, 8, 10, 10 is,

Hence, the mean, median, and the range of the given data set 6, 8, 10, and 10 are 8.5, 9, and 4 respectively.

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Answer:

21 Oreos

Step-by-step explanation:

2 × 3 = 6

7 × 3 = 21

hope this helps

Answer:

A:4.5

Step-by-step explanation:

all you need to do is count the spaces

(a) The predictor variable is Fall in feet and the response variable is Duration in seconds.

(b) The slope is in seconds per foot.

(c) The slope may be negative, as greater drop heights generally result in longer travel times.

(a) The predictor variable in this regression is Drop, which represents the drop height of the roller coaster, in feet, in feet. The response variable is Duration, which represents the duration of the trip, in seconds, in seconds.

(b) The units of slope in this regression are seconds per foot. This means that for each unit of increase in descent height in feet, the travel time will increase or decrease the value of the slope, measured in seconds per foot.

(c) The slope can be negative, as greater drop heights generally result in longer ride times, and the Tower of Terror roller coaster, which was exceptionally short despite its large drop height, has were removed from the analysis.

Therefore, the remaining 90 roller coasters in the dataset likely exhibit a negative relationship between drop height and time, meaning that as drop height increases, ride time decreases .

The Low R-value squared 29.4% means that the relationship between roller coaster drop and ride time in the data set is highly variable, but the negative slope indicates a general downward trend.

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Answer:

Lol same

Step-by-step explanation:

alright ima try uhm i think they have 3 children every 2 years so times 3 children with 2 years untill u get 21?

Answer:

ok this is what I think the first child we'll take his or her age to beX the second child will be x+ 2 and the third child will be x + 4 so it's means to get the ages you have to add all of them and quit it to 21 so it will be x + x + 2 + x + 4 is equals to 21 collect the like terms x + x + x + 2 + 4 is equals to 21 3x + 6 is equals to 21 sum of 6 over the equals sign to have 3x is equals to 21 - 6 3 x is equals to 15 divide both sides by 3 so x is 5 then substitute

Answer:

2.666

Step-by-step explanation:

Just use a third the amount your recipe calls for if you're swapping dried herbs for fresh.

Answer:

9 times.

Step-by-step explanation:

56 multiplied by 9 is 504, and if you add another 56, the number would be greater than 512, so the answer is 9 times.

Answer:

9.14285714286

Step-by-step explanation:

512 ÷ 56 = 9.14285714286

Answer:

\( {3x}^{4} + 4x\)

Step-by-step explanation:

The first number's exponenet represents the degree and 2 terms are present, one is 3x^4 and the other is 4x.

Answer: Associative property

Step-by-step explanation:

Answer:

Division C = 9%

Division E = 10%

Step-by-step explanation:

From the pie chart attached,

Let the missing percentage of division C and E are c% and e% respectively.

Since, division B + division C + division D = 50%

[Divisions on one half of the circle]

23% + c% + 18% = 50%

41% + c% = 50%

c = 50 - 41

c = 9%

Similarly, division A + division F + division E = 50%

27 + 13 + e = 50

40 + e = 50

e = 10%

When words are strung together in speech, deviations from ideal pronunciation can occur due to various factors such as coarticulation, assimilation, elision, and reduced vowel sounds.

When words are spoken in rapid succession, coarticulation plays a significant role in shaping the pronunciation of individual words. Coarticulation refers to the influence of neighboring sounds on the production of a particular sound. For example, in the phrase "black cat," the /k/ sound in "black" may be influenced by the following /k/ sound in "cat," resulting in a slight modification or assimilation of the sound.

Assimilation occurs when sounds become more similar to nearby sounds. For instance, in the phrase "handbag," the /n/ sound in "hand" may assimilate to the /b/ sound in "bag," making it nasal (as in "hambag") or even causing complete elision of the /n/ sound. Elision refers to the omission or deletion of sounds, often in unstressed or weak positions, such as the reduction of the /ə/ vowel sound in "a" or "the" to a schwa sound, as in "uh" or "thuh."  

Additionally, when words are strung together, certain vowel sounds may be reduced or shortened to accommodate the natural rhythm of speech. This reduction can result in changes to the stress patterns and lengths of vowels within words. Overall, these deviations from ideal pronunciation in connected speech are a natural part of spoken language and contribute to the fluidity and efficiency of communication.

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Answer:

The answer is all three angles are similar to the original one

Step-by-step explanation:

Because they the three triangles are the same triangles, all you did was move it to different place by reflecting and rotating (there is a change in their position and coordinates). If it was dilation, there would be a change in size, but still there wouldn't be a change in the angles.

The other number will be when added the two number = 38

What is Number?

A number is a mathematical object that can be used to count, measure, and label things. The natural numbers 1, 2, 3, 4, and so on are the original examples. Number words can be used to represent numbers in language.

Given,

The sum was 83

The one number is 45

Let's say the number we be = x

The sum of 45 and x  must be 83 so we can say

x + 45 = 83

Now we can solve for x while keeping the equation balanced:

x + 45 -45 = 83-45

x +0 = 38

x = 38

The other number will be = 38

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Claire fed Folly at 2 pm, gave Folly to Max at 2:10 pm. Folly belonged to either Max or Claire at 2:05 pm. Neither Mar nor Claire fed Folly at 2 pm or 2:05 pm. The event occurred between 1:55 pm and 2:05 pm. At 2 pm, Max took Folly from Claire. Folly wasn't hungry at 2 pm but was at 3 pm.

1. student(Mar) ∧ ¬pet(Mar)2. fed(Claire, Folly, 2pm) ∧ gave(Claire, Folly, Max, 2:10pm)3. (belongs(Folly, Max, 2:05pm) ∨ belongs(Folly, Claire, 2:05pm))4. ¬(fed(Mar, Folly, 2pm) ∨ fed(Claire, Folly, 2pm) ∨ fed(Mar, Folly, 2:05pm) ∨ fed(Claire, Folly, 2:05pm))5. between(2pm, 1:55pm, 2:05pm)6. ¬hungry(Folly, 2pm) ∧ hourLater(Folly, 2pm, 3pm)

1. Student(Mar) ∧ ¬Pet(Mar)2. Fed(Claire, Folly, 2pm) ∧ Gave(Claire, Folly, Max, 2:10pm)3. BelongsTo(Folly, Max, 2:05pm) ∨ BelongsTo(Folly, Claire, 2:05pm)4. ¬(Fed(Mar, Folly, 2pm) ∨ Fed(Claire, Folly, 2pm) ∨ Fed(Mar, Folly, 2:05pm) ∨ Fed(Claire, Folly, 2:05pm))

5. Between(2:00pm, 1:55pm, 2:05pm)6. Gave(Max, Folly, Claire, 2pm) ∧ ¬Hungry(Folly, 2pm) ∧ Hungry(Folly, 3pm)

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Answer:

infinity many solutions is the correct answer of this question .

plz mark my answer as brainlist plzzzz vote me also

it's 100% correct answer

Answer:

15. -4

16. -2

17. 3

18. -3

19. 6

20. 0

21. 3

22. 4

23. 12

Step-by-step explanation:

f = -15

g = 5

h = -45

15. -20/ 5 = -4

16. 90/ -45 = -2

17. -45/ -15 = 3

18. (-15) (5) = -75/ 25 = -3

19. -15 - (-45) = 60/10 = 6

20. 5 - 5/ -1 = 0

21. - (15)/ 5 = 3

22. -45 - 3 (5)/ -15 = -60/ -15 = 4 [note: do parenthesis first)

23. -15 + (-45) = -60/ -(5) = 12

90÷h

90÷(-45)

-2

hope it helps...!!!

The Runge-Kutta methods are a family of numerical methods used for solving ordinary differential equations (ODEs).

These methods approximate the solution of an ODE by calculating a sequence of values. If the vector is of length m, then the Runge-Kutta method will calculate a vector of length m at each step.

The general form of the Runge-Kutta methods is given by: y_{n+1} = y_n + h*(a_1*k_1 + a_2*k_2 + ... + a_m*k_m) where y_n is the value of the solution at time t_n, h is the step size, k_i are intermediate values calculated using the function f(t,y), and a_i are coefficients that determine the accuracy of the method.

The answer to your question is that if the vector is of length m, then the Runge-Kutta method will calculate a vector of length m. This vector represents the approximate solution of the ODE at the next time step.

The method is often used in numerical analysis because of its high accuracy and robustness. It is a popular choice for solving ODEs in a wide range of applications, from physics to engineering and biology.

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Answer:

6 1/3 Is a mixed fraction

Yes, if is a critical point of a function with continuous second derivatives, then it is a stationary point.

This means that the function's derivative is equal to 0 at that point and it is neither increasing or decreasing.

A stationary point is a point on the graph of a function where the function's derivative is equal to 0. This is an important property of a function and it can be used to determine the properties of the function.

At a stationary point, the rate of change of the function is equal to 0, so the function is neither increasing or decreasing. In other words, the function is neither increasing or decreasing at that point.

This property can be used to analyze the function and determine its characteristics. For example, it can be used to identify local minima or maxima.

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The total amount expected to be deposited in the restaurant's bank account during the month of January from cash, credit card, and debit card sales is equal to the total sales revenue, which is $X.

Cash sales: 40%

Credit card sales: 40%

Debit card sales: 20%

Requirement 1: How much of the total sales revenue is expected to be paid in cash?

Assuming the total sales revenue for January is $X, the amount expected to be paid in cash is 40% of X.

Cash sales = 0.4 × X

Requirement 2: How many customer transactions does the company expect in January?

The number of customer transactions can vary, and the information provided doesn't specify a particular value. You would need to have additional data or assumptions to determine the number of transactions.

Requirement 3: How much of the total sales revenue is expected to be paid with credit cards?

Assuming the total sales revenue for January is $X, the amount expected to be paid with credit cards is 40% of X.

Credit card sales = 0.4 × X

Requirement 4: How many customer transactions will be paid for by customers using credit cards?

Similar to Requirement 2, the number of customer transactions paid for by credit cards would require additional data or assumptions to determine.

Requirement 5: When budgeting for January's operating expenses, how much should the restaurant expect to incur in credit card transaction fees?

To calculate the credit card transaction fees, we need to consider two components: a fixed fee per transaction and a percentage fee based on the amount charged.

Assuming the number of credit card transactions is Y, and the average amount charged per transaction is Z, the credit card transaction fees can be calculated as:

Credit card transaction fees = (0.50 × Y) + (0.02 × Z × Y)

Requirement 6: How much of the total sales revenue is expected to be paid with debit cards?

Assuming the total sales revenue for January is $X, the amount expected to be paid with debit cards is 20% of X.

Debit card sales = 0.2 × X

Requirement 7: How many customer transactions will be paid for by customers using debit cards?

Similar to Requirement 2 and Requirement 4, the number of customer transactions paid for by debit cards would require additional data or assumptions to determine.

Requirement 8: When budgeting for January's operating expenses, how much should the restaurant expect to incur in debit card transaction fees?

Similar to Requirement 5, the debit card transaction fees can be calculated using the same formula but with different values for the fixed fee per transaction and the percentage fee based on the amount charged.

Requirement 10: What is the total amount of money that the restaurant expects to deposit in its bank account during the month of January from cash, credit card, and debit card sales?

Assuming the total sales revenue for January is $X, the total amount expected to be deposited in the bank account is the sum of cash sales, credit card sales, and debit card sales.

Total deposits = Cash sales + Credit card sales + Debit card sales

= 0.4 × X + 0.4 × X + 0.2 × X

= X

Therefore, the total amount expected to be deposited in the restaurant's bank account during the month of January from cash, credit card, and debit card sales is equal to the total sales revenue, which is $X.

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Answer:

C

Step-by-step explanation:

Both median and mean would decrease

Answer:

Step-by-step explanation:y = 4x - 2

y = -x + 3

Answer:

C., G, and J

Step-by-step explanation:

Answer:

Step-by-step explanation:

28 kg + 750 g = 28*1000 + 750

                          28000 + 750

                       = 28750 g

Number of sack = Total quantity of sugar ÷ quantity of sugar in a sack

                           = 28750 ÷ 500

                           =  57 sacks

Answer:

57 sacks

Step-by-step explanation:

28750 ÷ 500 =

57 sacks

Glad to help! :)

Answer:

b pizza hut

Step-by-step explanation:

sorry im wrong

The double integral can be written as:

∫∫R f(x,y) dA = ∫a^b ∫f(x)g(x) f(x,y) dy dx

Without specific values for y0 and x, I'll provide the general formulas for setting up iterated integrals over a region R bounded by y = g(x), y = f(x), and the vertical line x = a using both vertical and horizontal cross-sections.

a) Vertical cross-sections:

If we want to integrate a function f(x,y) over the region R using vertical cross-sections, we need to integrate with respect to x first. Each vertical cross-section is a rectangle with base dx and height (g(x) - f(x)). Therefore, the double integral can be written as:

∫∫R f(x,y) dA = ∫a^b ∫f(x)g(x) f(x,y) dy dx

b) Horizontal cross-sections:

If we want to integrate a function f(x,y) over the region R using horizontal cross-sections, we need to integrate with respect to y first. Each horizontal cross-section is a rectangle with base (g(y) - f(y)) and height dy. Therefore, the double integral can be written as:

∫∫R f(x,y) dA = ∫c^d ∫f(y)g(y) f(x,y) dx dy

Here, a, b, c, and d are the appropriate bounds for the region R.

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Answer:

The answer is (A)

Step-by-step explanation:

The extreme values of f(x, y) = xy occur at the points (2, 1) and (-2, -1) on the ellipse \(3x^{2} +2y^{2} =1\).

To find the extreme values of f(x, y) = xy on the ellipse \(3x^{2} +2y^{2} =1\), we can use the method of Lagrange multipliers.

Define the function g(x, y) = \(3x^{2} +2y^{2} -1\). We need to find points (x, y) where the gradient of f is proportional to the gradient of g:

∇f = λ∇g

The gradient of f is ∇f = (y, x), and the gradient of g is ∇g = (6x, 4y). Therefore, we have the following system of equations:

y = 6λx
x = 4λy

Substitute the second equation into the first:

y = 6λ(4λy)
y = \(24λ^{2y}\)

If y ≠ 0, then 1 = \(24λ^{2}\), and λ = ±1/2. Plugging this value into the second equation gives x = ±2. Thus, we have two potential extreme points: (2, 1) and (-2, -1).

Now consider the case when y = 0. The constraint equation becomes \(3x^{2} =1\), and x = ±1/√3. However, these points correspond to f(x, y) = 0, which is not an extreme value.

Therefore, the extreme values of f(x, y) = xy occur at the points (2, 1) and (-2, -1) on the ellipse \(3x^{2} +2y^{2} =1\).

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