Answers
SOLUTION
We will simply substitute the known values of x and y into the given expression
abd get our answer.
\(\begin{gathered} \lvert5x+3y\rvert \\ \text{when x=5 and y=2} \end{gathered}\)The expression will become:
\(\begin{gathered} =\lvert5(5)+3(2)\rvert \\ =\lvert25+6\rvert \\ =\lvert31\rvert \\ =31 \end{gathered}\)The answer is 31.
Related Questions
In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-shaped and has a mean of 55 and a standard deviation of 3. Using the empirical rule, what is the approximate percentage of daily phone calls numbering between 52 and 58?
Answers
The answer is very simple. .
Applying the empirical rule involves following the steps:
Construct the intervals of the rule
Since the mean is 55 and the standard deviation is 3, then the intervals are:
[µ – s, µ + s] = [55 – 3, 55 + 3] = [52, 58]
The empirical rule defines the following intervals:
68.27% of the data are in the interval: [µ - s, µ + s]
The answer is:
The approximate percentage of daily phone calls is 68.27 %
Find two square numbers that total 45
Answers
x^2+^2=45
if ×=3 and y=6
then 9+36=45
Write 3 1/2 cups as a multiplication expression using the unit, 1 cup, as a factor.
I ABSOLUTELY NEED HELP BY TOMORROW!!! I AM GIVING 100 POINTS
Answers
3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.
How to Write 3 1/2 cups as a multiplication expression using the unit, 1 cup, as a factor.To express 3 1/2 cups as a multiplication expression using the unit "1 cup" as a factor, you can write it as:
3 1/2 cups = (3 + 1/2) cups = 3 cups + 1/2 cup
Since there are 1 cup in each term, we can rewrite it as:
3 cups + (1/2) cup
Now, we can express each term as a multiplication expression:
3 cups = 3 * 1 cup = 3
(1/2) cup = (1/2) * 1 cup = 1/2
Putting it all together, the multiplication expression is:
3 * 1 cup + (1/2) * 1 cup = 3 + 1/2
Therefore, 3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.
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10. Prime numbers from 1 to 100 are running a restaurant - PRIME SPOT, near a tourist point. On a winter holiday, 1 and the composite numbers up to 100 enter the restaurant for dinner after their picnic at the same point. The dining hall has tables with seating capacity 15 for each. If they occupy tables without leaving any chair free, how many tables are required? If each prime number attender has to serve equal number of customers, how many customers should each one get to serve?
Answers
6 tables are required. Each prime number attender should serve 3 customers each.
The prime numbers between 1 and 100 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.
All the numbers other than prime numbers are composite numbers.
The composite numbers from 1 to 100 are: 1, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100.
Now, as there are 25 primes and 75 composites in the group that visited the restaurant, we can calculate the number of tables required by dividing the number of people by the seating capacity of each table.
Each table has a seating capacity of 15, so the number of tables required will be: Number of tables = (Number of customers)/(Seating capacity of each table)Number of customers = 25 (the number of primes) + 75 (the number of composites) = 100Number of tables = 100/15 = 6 tables
Therefore, 6 tables are required.
Now, as each prime number attender has to serve an equal number of customers, we need to calculate how many customers each one should serve.
Each prime attender has to serve 75/25 = 3 customers each, as there are 75 composites and 25 primes.
Thus, each prime number attender should serve 3 customers each.
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6. Error Analysis Dakota said the third term of the expansion of (2g + 3h) is 36g2h². Explain Dakota's error. Then correct the error.
Answers
The binomial expansion is solved and the error in Dakota's statement is the incorrect substitution of 36g^2h^2 for the correct expression
Given data ,
Dakota made a mistake because the third term of the expansion of (2g + 3h) should have been 36g2h2. The binomial theorem asserts that the expansion of (2g + 3h) is as follows:
( x + y )ⁿ = ⁿCₐ ( x )ⁿ⁻ᵃ ( y )ᵃ
Here, x = 2g and y = 3h. Since term numbers begin at 0, since we are seeking for the third term, r = 2.
So , on simplifying the equation , we get
= nC2 * (2g)⁽ⁿ⁻²⁾ * (3h)²
= (n! / (2! * (n - 2)!)) * (2g)⁽ⁿ⁻²⁾ * (3h)²
= ((n * (n - 1)) / 2) * (2g)⁽ⁿ⁻²⁾ * (3h)²
Hence , the correct expression for the third term of the expansion of (2g + 3h) is ((n * (n - 1)) / 2) * (2g)^(n - 2) * (3h)², where n is the exponent in the binomial expansion.
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what is the equation of this graph
Answers
Answer:
y=-(2/3) + 1
Step-by-step explanation:
-(2/3) is slope
1 is y intercept
help
The perimeter of a rectangle is 430 meters. Express the area A as a function of the length L, and state the domain of this function
A(L) = ? m²
Answers
Let L be the length of the rectangle and W be the width. The perimeter is given by 2(L + W) = 430. Solving for W, we have W = (430 - 2L)/2. The area A is given by the product of the length and the width:
A(L) = L * W = L * (430 - 2L)/2 = 215L - L^2.
So the area A is a function of the length L with the equation A(L) = 215L - L^2.
The domain of this function is the set of all real numbers L such that the width W is positive, i.e., 0 < W < ∞. This implies that 0 < 215 - 2L < ∞, or 0 < 215 < 2L. Hence, the domain of the function A is L > 107.5.
Answer:
A(L) = - L² + 215L
Domain
0 < L < 215
or
(0, 215) in interval notation
Step-by-step explanation:
Let L represent the length and W the width
Perimeter of a rectangle = 2(L+W) and is given as 430 meters
Therefore 2(L + W) = 430
L + W = 430/2
L + W = 215
W = 215-L
The area A is given by L x W
Substituting for W in terms of L this becomes
A = L x(215 - L)
A = 215L - L²
which can be expressed as a function of in the form
A(L) = 215L - L² or in standard form(highest degree first)
A(L) = - L² + 215L
The domain of this function are the values of L which result in a defined , real value for A
Without restrictions, the domain for L is -∞ < L < ∞. However real world facts coming into play
1. Area cannot be zero
So A(L) > 0 (upper bound on area)
-L² + 215L > 0
-L² > - 215L Move 215L to right side
L² < 215L (dividing by -1 changes signs of variables and also inequality)
L < 215 (divide by L both sides)
2. Length cannot be negative
So lower bound on L is L > 0
Together the domain is
0 < L < 215
or
(0, 215) in interval notation
Find the length of the side labeled x. Round intermediate values to the
nearest tenth. Use the rounded values to calculate the next value. Round
your final answer to the nearest tenth.
Answers
Answer:
(D). 16.6 units
Step-by-step explanation:
hay 1230 personas, entre hombres y mujeres. Si se sabe que el número de mujeres, supera en 150 al número de hombres. ¿Cuántos hombres están habitando la mini ciudad?
Answers
There are 540 men living in the mini city.
x + (x + 150) = 1230
Simplifying this equation, we get:
2x + 150 = 1230
Subtracting 150 from both sides, we get:
2x = 1080
Dividing both sides by 2, we get:
x = 540
Therefore, there are 540 men living in the mini city.
To check our answer, we can substitute x = 540 into our original equation:
540 + (540 + 150) = 1230
690 = 1230
This is false, so there must be an error in our calculation. We can double-check our work by trying a different approach.
We know that the number of women exceeds the number of men by 150, so we can represent the number of women as (x + 150). We also know that the total number of people is 1230, so we can set up an equation:
x + (x + 150) = 1230
Simplifying this equation, we get:
2x + 150 = 1230
Subtracting 150 from both sides, we get:
2x = 1080
Dividing both sides by 2, we get:
x = 540
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Which expression is equal to the polynomial below 2x^4+5x^3-8x-20
Answers
The expression that is equal to the given Polynomial expression is (x^3-4)(2x+5).
The polynomial expression given is 2x^4+5x^3-8x-20. We have to identify the expression that is equal to this given polynomial expression.
We will factor the given polynomial expression to determine the equivalent expression. We can use factorization by grouping to factor the expression completely and determine the equivalent expression .
Factorization by grouping:
We can group the first two terms 2x^4 and 5x^3 together and factor out x^3 from them. We can also group the last two terms -8x and -20 together and factor out -4 from them.
This gives us;2x^4+5x^3-8x-20= x^3(2x+5)-4(2x+5) =(x^3-4)(2x+5)
Therefore, the expression that is equal to the given polynomial expression is (x^3-4)(2x+5).
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A survey shows that in one year, the average number of bilingual employees in an office was 12. Assume that the standard deviation is 3 and the number of bilingual employees is Normally distributed. Include an appropriately labeled and shaded Normal curve for each part.
Required:
a. What percentage of offices have more than 12 bilingual employees?
b. What percentage of offices have less than 10 bilingual employees?
c. What percentage of offices have between 8 and 14 bilingual employees?
Answers
Answer:
b
Step-by-step explanation:
Previously: Multiplying
Polynomials
(x - 1)(x² + 3x - 4) = x³ + 2x² − 7x + 4
Answers
Solving the provided question, we can say that the quadratic equation is \((x - 1)(x^{2} + 3x - 4)\) = \(x^{3} + 2x^{2} - 7x + 4\) and the roots of the polynomial are x = 1, -1, 4.
A quadratic equation is what?A quadratic polynomial in a single variable is represented by the equation \(ax^{2}+bx+c=0\). a 0. Since this polynomial is of second order, the Fundamental Theorem of Algebra guarantees that it has at least one solution. There are both simple and complex solutions.
A quadratic equation is just that—quadratic. It has at least one word that has to be squared, as shown by this. One of the often used solutions for quadratic equations is "ax2 + bx + c = 0." where X is an undefined variable and a, b, and c are numerical coefficients or constants.
the quadratic equation is
\((x - 1)(x^{2} + 3x - 4)\) = \(x^{3} + 2x^{2} - 7x + 4\)
On multiplying,
⇒ \(x (x^{2} + 3x - 4) - (x^{2} + 3x - 4)\)
⇒ \(x^{3} + 3x^{2} - 4x - x^{2} - 3x + 4\)
⇒ \(x^{3} + 2x^{2} - 7x + 4\)
∴ We can say that LHS = RHS.
From given equation, the roots of the equation will be -
\((x - 1)(x^{2} + 3x - 4)\)
⇒ x - 1 = 0
⇒ x = 1
\(x^{2} + 3x - 4 = 0\)
⇒ \(x^{2} - 4x + x - 4\)
⇒ \(x(x - 4) + 1(x - 4)\)
⇒ (x + 1) (x - 4)
⇒ x = -1, x = 4
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2×+9y=-1 4x+ y=15 By elimination help please
Answers
Step-by-step explanation:
see in the figure given above
which statement is true about the polynomial after it has been simplified. -10m^4n^3+8m^2n^6-6m^2n^6
Answers
Answer: 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )
Step-by-step explanation:
ok, so just let me, uh, make this a little easier on my eyes lol:
-10m^4n^3+8m^2n^6-6m^2n^6 ----> (-10m^4)(n^3) + (8m^2)(n^6) - (6m^2)(n^6)
I just put in parentheses. nothing changed. just parentheses.
Since the leading coefficients, -10 , 8 , and 6 are multiples of two,
we can take out 2 from each... [-10/2 = 5 , 8/2 = 4 , 6/2 = 3 ]
= 2 x [ (-5m^4)(n^3) + (4m^2)(n^6) - (3m^2)(n^6) ]
Looking at it now...
we can take out m^2 from each... m^4 , m^2 , and m^2
m^2 [m^2 , 1 , 1]
since m^4 /m^2 = m^2 , m^2 /m^2 = 1 , m^2 /m^2 = 1
= 2(m^2) x [ (-5m^2)(n^3) + (4x1)(n^6) - (3x1)(n^6) ]
= 2(m^2) x [ (-5m^2)(n^3) + (4)(n^6) - (3)(n^6) ]
Finally, one more step...
we can take out n^3 from each term.... n^3 , n^6 , and n^6
n^3 [1 , n^2 , n^2] since n^3 /n^3 = 1 , n^6 /n^3 = n^2 , n^6 /n^3 = n^2
= 2(m^2)(n^3) [ (-5m^2)(1) + (4)(n^2) - (3)(n^2) ]
= 2m^2n^3 x [ (-5m^2) + (4n^2) - (3n^2) ]
= 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )
ANSWER: 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )
keep this parentheses. seriously.
solve the following inequality for z. write your answer in simplest form. -9-(2z-7)>-2z-6-5z
Answers
Answer:
z > -4/5
Step-by-step explanation:
-9 - (2z - 7) > -2z - 6 - 5z
Get rid of the parenthesis
*There is the number one in front of the parenthesis.-9 - 2z + 7 > -2z - 6 - 5z
Combine like terms:
-2 - 2z > -7z - 6
+2 > +2
Add 2 to both sides.
-2z > -7z - 4
+7z > +7z
Add 7 to both sides.
5z > -4
Divide both sides by 5 to get z.
z > -4/5
The sign stays the same unless you divide by a negative number---------------------------------
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For the dashed graph, describe the key features.
Maxima or Minima?……..
Number of solutions:………..
Solution(s)?…………
The width is Wider? Or Narrower?
than the graph of f(x)? (solid).
Answers
The key features of the dashed graph are
Minima at (4, 3)No solution andWidth is narrower than graph of f(x)What is a graph?A graph is a pictorial representation of a function
To describe the key features of the dashed graph, we proceed as follows.
First, we notice that the dashed graph has a lowest point or vertex. This is at (4, 3). So, this is its minima at (4,3).Also, the dashed graph does not cut the x-axis, so, it has no solutionFinally, we can see that the dashed graph is narrower than the other undashed graphedSo, the key features of the dashed graph are
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a salesman earns 25% commission he sells amount to 2450 shillings after giving a buyers 2% discount . calculate his commission. Suppose all the goods were sold at marked price , what would be is earnings?
Answers
Answer:
Step-by-step explanation:
A) Commission = 2450 shillings * 25 % = 2450 shillings * (25/100) = 2450 shillings * (0.25) = 612.50 shillings
Commission = 612.50 shillings
B) If the total sale is 2,450.00 shillings, after the seller gives buyers a 2% discount. We must re-enter the discount:
2,450.00 shillings = X - X * 2% = X - 0.02 X --->
------> 0.98 X = 2,450.00 shillings
------>X= 2,450.00 / 0.98
------> X = 2,500.00 shillings
NEW COMMISSION = 2,500.00 shillings * 25 % = 2,500.00 shillings *(25/100) =2,500.00 shillings * (0.25) = 625 shillings
NEW COMMISSION = 625 shillings
Figure 1 has vertices (-3, 4), (-1, 3), (-3, 1), and (-5, 2). Rotate it 180° to form Figure 2.
Give the coordinates for the vertices of Figure 2.
Answers
3. If a 35-foot cable were run from the top of the pole and anchored to the ground at a distance from the pole, about how far away from the pole would it be anchored?
Answers
The distance from the pole at which the cable is anchored is about 25 feet from the pole .
Given that a 35-foot cable is run from the top of the pole and anchored to the ground at a distance from the pole. The problem is to determine about how far away from the pole would it be anchored.
Let AB be the pole of length 40 feet, and CD be the 35-foot long cable anchored to the ground at D and attached to the top of the pole at C. Let E be the point on the ground at which the cable is taut and is anchored. The distance ED is to be determined.
we can see that ∆CDE is a right-angled triangle with ∠CED = 90°.
Using Pythagoras Theorem, we have:CD² = CE² + DE²35² = (40 - ED)² + DE² .
Simplifying the above equation
1225 = 1600 - 80ED + ED²
1225 - 1600 + 80ED - ED² = 0ED² - 80ED + 375 = 0
Factorizing the above quadratic equation
ED² - 25ED - 15ED + 375 = 0ED(ED - 25) - 15(ED - 25)
= 0(ED - 15)(ED - 25) = 0So, ED = 15 ft or ED = 25 ft.
The negative value of ED is extraneous since it represents a point below the ground, which is not possible. Therefore, the distance from the pole at which the cable is anchored is about 25 feet from the pole.
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Please help, marking brainliest for the correct answer
Answers
Answer:
none of the above
Step-by-step explanation:
they're same side interior
Find the volume of the following con used 3.14 for pie
Answers
Answer:
the first one
Step-by-step explanation:
PLEASE HELP 50 POINTS!!
The sum of two consecutive numbers is 157. This equation, where n is the first number, represents the situation:
2n + 1 = 157.
What is the first number?
A. 77
B. 78
C. 79
D. 80
Answers
If u add them n+(n+1) you get 157
So,
n+n+1=157
2n=156
n=78
What’s the area and the circumference of a circle with diameter 8m?
Answers
Answer:
50.24
Step-by-step explanation:
8÷2 is the radius. 3.14×4^2=50.24 m^2
^= where the exponent is supposed to go
Find the area and the circumference of a circle with diameter 8 m .
Given : -Diameter of circle = 8 mTo Find : -Area of circleCircumference of circleFormula Used :1)
\( \pink{\boxed{ \sf{Area \: of \: circle = \pi r {}^{2} }}}\)
2)
\( \pink{\boxed{\sf{Circumference of circle = 2\pi r}}}\)
So Starting Our Solution :We know that radius of circle is always halves of its diameter . So radius of circle :
8/24 m1) Finding area :
πr²3.14 × 4 × 43.14 × 1650.24 m²Therefore, area of circle is 50.24 m² .
2) Finding circumference :
2πr2 × 3.14 × 46.28 × 425.12 mTherefore, circumference of circle is 25.02 m
#Keep LearningIvanna drove 420 miles using 18 gallons of gas. At this rate, how many gallons of gas would she need to drive 357 miles?
Answers
Answer:
15.3 GAL.
Step-by-step explanation:
Please need help thank you
Answers
Answer: The answer is 9 flowers. Hope this helps!
Step-by-step explanation:
If x and y are negative integers, then which of the following is
the largest?
a) 2x
b) x+y
c) -1/y³
d) 1/x³
Answers
3(2x+1)=7x-2 find the value of x
Answers
Answer:
5
Step-by-step explanation:
3(2x+1)=7x-2
6x + 3 = 7x - 2
6x - 7x = -2 - 3
-x = -5 /(-1)
x = 5
Answer:
5
Step-by-step explanation:
3 ( 2x + 1 ) = 7x - 2
Step 1 : Remove the parentheses
6x + 3 = 7x - 2
Step 2 : Move the variable to the left-hand side and move extra number the right-hand side
6x + 3 = 7x - 2
-7x -3 -7x -3
6x - 7x = -2 - 3
Step 3 : Combine like terms
-x = -5
Step 4 : Change the sign to make x positive
x = 5
SOLUTION : x = 5
Hope this helps :)
The price technology stock dropped to $9.71 today. Yesterday's price was $9.82. Find the percentage decrease.
Answers
9.71 - 9.82 x 100%= 0.11
Please do the first question thank you in advanced
Answers
Points X and Y lie in both plane P and plane Q. What object defines the intersection of the two planes
Answers
A straight line defines the intersection of the two planes.
What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.Given is that Points {X} and {Y} lie in both plane P and plane Q.
Two common points can only lie on a straight line. So, a straight line defines the intersection of the two planes.
Therefore, a straight line defines the intersection of the two planes.
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