etermine the resonant frequency of the following system, compute its resonant peak, then sketch its bode plot. 5 G(s) 382 + 6s + 49

20

Explanation:

Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A​

Answer:

the magnitude of the velocity when t = 3 s is 10.54 m/s.

Explanation:

To solve this problem, we can use the following kinematic equation that relates velocity, acceleration, and time:

v = vo + at

where:

v = final velocity

vo = initial velocity

a = acceleration

t = time

First, we need to find the velocity of the object at time t = 3 s. To do this, we can substitute the given values into the kinematic equation and solve for v:

v = vo + at

v = 8i + (-0.2i+2j+1.5k) x 3

v = 8i - 0.6i + 6j + 4.5k

v = 7.4i + 6j + 4.5k

The magnitude of the velocity is given by:

|v| = sqrt(vx^2 + vy^2 + vz^2)

where:

vx, vy, vz = the x, y, and z components of the velocity vector

Substituting the values from above, we get:

|v| = sqrt((7.4)^2 + 6^2 + (4.5)^2)

|v| = sqrt(54.81 + 36 + 20.25)

|v| = sqrt(111.06)

|v| = 10.54 m/s (approx)

Answer:

While driving in reverse gear it necessary to have reverse audible alarm , a spotter and a rear view mirror.

Explanation:

It is prefer that to not drive a vehicle in reverse. But if we are driving in reverse gear it is necessary to have a reverse audible alarm , a spotter and a rear view mirror.

False. Fire extinguishing equipment cannot be frozen according to Ref. 213/91.

According to Ref. 213/91, fire extinguishing equipment cannot be frozen. Fire extinguishers are essential safety devices designed to combat fires effectively. They contain pressurized agents that are specifically formulated to extinguish different types of fires. Freezing temperatures can significantly impair the functionality of fire extinguishers and render them ineffective in emergency situations.

When fire extinguishing equipment freezes, several issues can arise. First, the contents of the extinguisher may expand as they freeze, potentially leading to ruptures or leaks in the container. This can cause the extinguisher to malfunction or become hazardous when used. Second, freezing temperatures can affect the performance of the extinguishing agent itself. Certain agents, such as water-based solutions, can solidify or lose their effectiveness when exposed to extreme cold.

It is crucial to store fire extinguishers in suitable environments that are above freezing temperatures. This ensures that the equipment remains in optimal condition and is ready for immediate use during emergencies. Regular inspections and maintenance are also essential to identify any signs of damage or deterioration that may compromise the functionality of fire extinguishers.

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Incomplete question. However, I inferred you referring to the online article "How automakers can survive the self-driving era."

Explanation:

According to the article, as a result of the perceived demand for autonomous cars in the next few years, this has led to a heightened desire among commercial carmakers to develop driverless technology.

For example, carmakers such as Audi, Toyota have stated projections about the commercial availability of driverless cars.

yes it will

Explanation:

The color of white light bends the most when it is refracted by a prism is green after the violet.

The shorter the wavelength of the mild, the greater its miles refracted. As a result, crimson mild is refracted the least, and violet mild is refracted the most - inflicting the colored mild to unfold out to shape a spectrum.

The hues of white mild withinside the order of lowering wavelength are crimson orange-yellow inexperienced blue indigo violet. Fro the listing we are given withinside the alternatives inexperienced has the shortest wavelength than others. Therefore inexperienced will bend the most.

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Technician A is correct because the automotive batteries can be recycled and the materials used to make new batteries.

Materials present in the battery;

Lead-acid batteries are used to store chemical energies and they are highly recyclable.

To recycle a lead-acid battery, first step is to break it into smaller fragments such as lead, plastic coating and the toxic material (sulfuric acid).

Thus, we can conclude that Technician A is correct because the automotive batteries can be recycled and the materials used to make new batteries.

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The type of fracture that occurs by rapid crack propagation and without appreciable macroscopic deformation is called brittle fracture.

Brittle fractures typically happen in materials that lack significant plastic deformation capacity, such as ceramics and some brittle metals. When a brittle material is subjected to high stress or sudden impact, cracks can propagate rapidly through the material without any noticeable deformation. This type of fracture is characterized by a clean break surface, often with little or no plastic deformation, and is prone to occur in materials with high strength but low toughness. Examples of brittle fractures include glass shattering or a brittle ceramic breaking into pieces without any significant distortion.

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Answer:

Explanation:

To determine the required size of standard schedule 40 steel pipe to carry 192 m³/hour of water with a minimum velocity of 6.0 m/sec, we can use the following formula:

Q = A × v

where Q is the volumetric flow rate of water, A is the cross-sectional area of the pipe, and v is the velocity of water.

First, we need to convert the volumetric flow rate from m³/hour to m³/sec.

192 m³/hour = 0.0533 m³/sec

Next, we can rearrange the formula to solve for the cross-sectional area:

A = Q / v

A = 0.0533 m³/sec / 6.0 m/sec

A = 0.0089 m²

The cross-sectional area of the pipe is 0.0089 m².

Standard schedule 40 steel pipe has a nominal inside diameter (ID) of 1.049 inches, which is approximately 0.0266 meters. The cross-sectional area of the pipe can be calculated using the formula for the area of a circle:

A = π × (ID/2)²

A = 3.14 × (0.0266/2)²

A = 5.58×10^-4 m²

To determine the required size of the pipe, we can rearrange the formula for the area of a circle to solve for the diameter:

ID = 2 × √(A/π)

ID = 2 × √(0.0089/π)

ID = 0.106 meters

Therefore, the required size of standard schedule 40 steel pipe to carry 192 m³/hour of water with a minimum velocity of 6.0 m/sec is a nominal size of 4 inches, with an inside diameter of 0.102 meters (or 102 millimeters).

Acrylic overlay is a popular technique used by nail technicians to give a protective layer to the natural nail or enhance the appearance of the nails. It involves applying a mixture of liquid and powder acrylic on the nails, which hardens to create a durable and long-lasting coating.

When applying an acrylic overlay, the nail is typically divided into three zones: the free edge, the stress area, and the nail bed. The free edge is the tip of the nail that extends beyond the fingertip, the stress area is the middle section of the nail that experiences the most pressure and tension, and the nail bed is the area closest to the cuticle. The free edge is the zone where the acrylic is applied the thinnest, usually just a thin layer of clear acrylic to protect the natural nail. The stress area is where most of the acrylic is applied, creating a thicker layer to provide strength and durability. The nail bed is the zone where the acrylic is applied the thickest, often in a light pink shade to create a natural-looking base for nail polish.

In conclusion, when applying an acrylic overlay, the nail is typically divided into three zones: the free edge, the stress area, and the nail bed. This division allows the nail technician to apply the acrylic in a way that provides maximum protection and durability while still creating a natural-looking finish.

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Answer:

y'(x) = 7 ;

y'(x) = 15x²

Explanation:

Differentiation from first principle :

y = 7x

Formula to obtain derivative from first principle:

y'(x) = lim(h - - > 0) : [y(x + h) - y(x)] / h

Obtain : y(x + h)

y(x) = 7x

y(x + h) = 7(x + h)

Substitute into formula :

y'(x) = lim(h - - > 0) : [7(x + h) - 7x] / h

Expand :

y'(x) = lim(h - - > 0) : [7x + 7h - 7x] / h

y'(x) = lim(h - - > 0) : 7h/ h

y'(x) = 7

2.)

y = 5x³

y'(x) = lim(h - - > 0) : [y(x + h) - y(x)] / h

Obtain : y(x + h)

y(x) = 5x³

y(x + h) = 5(x + h)³

Substitute into formula :

y'(x) = lim(h - - > 0) : [5(x + h)³ - 5x³] / h

Expand :

y'(x) = lim(h - - > 0) : [5(x³ + 3x²h + 3xh² + h³) - 5x³] / h

y'(x) = lim(h - - > 0) : [5x³ + 15x²h + 15xh² + 5h³ - 5x³] / h

y'(x) = lim(h - - > 0) : [15x²h + 15xh² + 5h³] / h

y'(x) = lim(h - - > 0) : h(15x² + 15xh + 5h²) / h

y'(x) = lim(h - - > 0) : (15x² + 15xh + 5h²)

y'(x) = 15x²

One of the determining factors that permits machine countersinking when flush riveting is the thickness of the material being joined.

Machine countersinking is a process used in flush riveting, where a conical recess is created on the surface of a workpiece to accommodate the rivet head. This allows the rivet to sit flush with the surface, providing a smooth and aerodynamic finish. The ability to perform machine countersinking depends on various factors, and one crucial factor is the thickness of the material being joined.
When the material thickness is within a certain range, typically determined by the capabilities of the countersinking machine, machine countersinking becomes feasible. The machine is designed to remove a specific amount of material to create the countersink, and it needs sufficient material thickness to achieve the desired result.
If the material is too thin, there may not be enough material to form a proper countersink, resulting in weak joint integrity or potential damage to the material. On the other hand, if the material is too thick, it may exceed the capabilities of the machine, making it difficult or impossible to achieve a proper countersink.
Therefore, the thickness of the material being joined is a critical determining factor in determining whether machine countersinking can be successfully performed during flush riveting. It is important to consider the material thickness to ensure the proper application of machine countersinking for effective and reliable riveted joints.

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When traveling on a multilane roadway with traffic moving in opposite directions, drivers should use the shared center lane for making left turns or U-turns.

This lane is designated for vehicles in both directions to use when turning, allowing for smoother traffic flow and reducing the chances of collisions. The shared center lane is marked by broken yellow lines on both sides, indicating that vehicles from either direction can use it for turning purposes.

Drivers should signal their intention to turn, merge into the center lane when it is safe to do so, and proceed with caution while making their turn. It is important to note that the shared center lane should not be used for passing or as a travel lane.

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The amount of steel you would expect to have per square foot of building space in an 8-story office building is 10 psf.

In an 8-story office building, the weight of steel per square foot of building space can vary depending on the design and construction specifications. However, as a general guideline, a typical steel-framed office building would have around 10 pounds of steel per square foot of building space. This includes the weight of structural steel columns, beams, and other components necessary to support the building's weight and provide structural integrity.

It's important to note that the actual weight of steel can vary based on factors such as the building's design, height, and intended use. Therefore, it's always recommended to consult with a structural engineer or architect for a more precise estimation based on the specific requirements of your project.

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Engineers or architects can be asked to draw a sketch of a bridge-design on a graph sheet or A4 paper to communicate their ideas and scale their drawings.

Architectural sketches are about the communication of ideas. Engineers and architects use hand sketching to clarify elements of the design to the contractor or client.

It should be noted that drawings can also be drawn on a graph sheet or A4 paper to represent the detail before it's eventually constructed.

Scale drawings are used for the illustration of items that are not convenient to draw their actual size. In the construction industry, scales are used depending on the nature of the drawing. Drawings can be made on a graph or A4 paper due to the ease of printing, reproducing, and resizing the drawings.

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Answer:

Here! I did an assignment about this a long time ago.

Answer:

Explanation:

Consider the outer surface of the roof to be \(T_{out}\)

Since, the heat conducted is equal to the sum of the heat transferred through convection and the rest by radiation

\(Q_{cond}=Q_{rad}+Q_{conv}\)

Rewrite the equation as follows

\(kA_s\frac{\Delta T}{L} =\epsilon \sigma A_s(T_s^4-T_{\infty}^4)+hA_s \Delta T\\\\k\frac{\Delta T}{L} =\epsilon \sigma (T_s^4-T_{\infty}^4)+h \Delta T\)

\(k\frac{T_{in}-T_{out}}{L} =\epsilon \sigma (T_{out}^4-T_{rad}^4)+h(T_{out}-T_{\infty})\)

subsititute

k = 2 W/m

\(15^o C=T_{in}\)

0.22 for L

\(0.9 = \epsilon\)

\(5.67\times 10^{-8}W/m^2.K^4=\sigma\)

\(255=T_{rad}\)

\(15W/m^2.K = h\)

\(10^oC=T_{\infty}\)

\(2\times \frac{15 -T_{out}}{0.22} =[0.9\times(5.67\times10^-^8)\times((T_{out}+273)^4-255^4)]+[15\times(T_{out}-10)]\\\\T_{out}=7.7^oC\)

Hence, the temperature of outer surface of the roof is \(T_{out}=7.7^oC\)

Calculate the surface area of the roof

\(A_s=b\times l\)

Here, b is the width , l is the length

substitute 15 for b , 20 for l

\(A_s=15 \times 20\\\\=300m^2\)

Write the equation for conduction

\(Q_{cond}=kA_s\frac{\Delta T}{L}\)

substitute 2W/m.K for k

\(300m^2 \ \ for \ A_s\\\\(15-7.7)^oC \ \ for \ \Delta T\\\\0.22m \ for \ L\)

\(Q_{cond}=2\times 300 \times \frac{15-7.7}{0.22}\\\\=19,000\)

Therefore, the total heat transferred through conduction is \(Q_{cond}=19,9009W\)

Consider the amount of  natural gas required be R and the cost incurred in running  the furnace through the night be M

\(R=\frac{Q_{cond}}{0.85} \times T\)

Duration of time T = 14 x 3600s

\(R=\frac{19909\times(14\times3600)}{0.85}kJ\\\\= \frac{19909\times(14\times3600)}{0.85\times105500}therm\\\\=11.2 \ therm\)

And the required money for the gas M = 11.2 x $1.2

= $13.44

Therefore, the money lost through the roof due to the heat transfer M=$13.44

Let's first define some terms.

An integer N can be split into two non-empty parts by cutting it between any pair of consecutive digits. After such a cut, a pair of integers A, B is created.

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Answer:

volunteer coordinator

Explanation:

because they are volunteering for that and in most of the cases they do not expect to be paid

Answer:

Amplifier gain is equal to 10.67.

Explanation:

Voltage gain of an amplifier can be expressed as this equation:

A_v = (V_output) / (V_input)

Where A_v is the gain, V_output is the output voltage, and V_input is the input voltage.

For this we will solve:

A_v = 128 mV / 12 mV

A_v = 10.67

So the amplifier's gain is 10.67.

Cheers.

Answer:

what is the question you need to be answered

Answer:

The correct HTML for creating a hyperlink is <a> symbol.

The GIS operation that refers to the area of spatial proximity around a point is called:

b. Buffer.

GIS stands for Geographic Information System. It is a system designed to catch, store, manipulate, analyze, manage, and exhibit all kinds of spatial or geographical data. GIS is an effective method for analyzing and interpreting spatial data, which comprises data linked to location or geographic coordinates. GIS involves an arrangement of spatial and statistical methods for analyzing and displaying geographical data.

There are different GIS operations like clip, select by location, buffer, etc. Among these operations, buffer operation is used to make an area of spatial proximity around a point. Buffering allows for areas of spatial proximity to be outlined around geographic features. The term "proximity" refers to the distance around the original geographic feature that falls within a specific range of distance from that feature. The answer is b. Buffer.

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The given statement, "The order settlement process in production involves having the actual cost of the production order being settled in cost accounting" is True.

Order settlement is the process of allocating and processing actual costs that have arisen from business operations to individual orders, products, cost centers, projects, or investment orders.

Cost accounting is the process of measuring, recording, analyzing, and allocating costs associated with the production of a product or provision of a service. It is an essential tool for managerial accounting as it helps in planning, budgeting, and controlling expenses.

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Answer:

Burj Khalifa is located in dubai UAE at over 828m

Explanation:

828 metres

Answer:

The Burji Khalifa, known as the Burj Dubai prior to its inauguration in 2010, is a skyscraper in Dubai, United Arab Emirates. With a total hight of 829.8 m and a roof hight of 828 m, the Burji Khalifa has been the tallest structure and building in the world since its topping out in 2009.

Alloys of aluminium find use in aircraft industry because of its: B) low specific gravity.

An alloy simply refers to a homogenous mixture (substance) that is produced by melting or joining two or more chemical elements together, with at least one of the elements being a metal.  

Generally, some examples of the components of alloys include the following:

In the aircraft industry, alloys of aluminum typically find use because of its low specific gravity.

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Answer:

d) phase sequence of the voltage applied to the motor stator windings

Explanation:

The direction of rotation of a three-phase squirrel-cage induction motor depends on the phase sequence of the voltage applied to the motor stator windings.

The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.

The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;

∑F = 0

F - μF_n = 0

We are given;

F_n = 5 kN = 5000 N

μ = 0.2

Thus;

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;

Minimum force = Total force/number of turns of rope

Since rope is wrapped three and half times, then;

number of turns = 3.5

Thus;

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

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The line plot would have a number line ranging from 7 to 9.5 with increments of 0.5. There would be data points plotted at 7.5, 9.5, 9.0, 8.0, 8.5, and 9.0, with multiple points at certain values.

The line plot would visually represent the distribution of leaf lengths.

Here is a textual representation of the line plot based on the given data:

7.5    |   X

7.75   |

8.0    |   X

8.25   |

8.5    |   X   X

8.75   |

9.0    |   X   X   X   X

9.25   |

9.5    |   X   X   X

9.75   |

In the line plot, each X represents a data point from the given list. The vertical axis represents the count or frequency of each length, while the horizontal axis represents the range of lengths.

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