The As-I bond length from the data, compare your value to the experimental is 2.55 A°.
The equilibrium separation between the nuclei of two bound atoms in a molecule is referred to as the bond length. The length of the bond increases with increasing atom size. Bond multiplicity causes a reduction in bond length. Rotational spectroscopy, X-ray diffraction, and other methods are used to measure it.
The average distance between the nuclei of two bound atoms in a molecule is referred to as bond length or bond distance in molecular geometry. It is a transferrable quality of a bond between fixed-type atoms that is mostly unrelated to the other molecules in the molecule.
The length of the bond is determined by the number of bonded electrons ( the bond order). generally, the length of the bond between two atoms is approximately the sum of the covalent radii of the two atoms.
As --- I Bond length in AsI3 is 2.55 angstrom A0.
Now, entimate the difference between the atomic radii of arsenic and iodine.
Arsenic ( As ) here has an atomic radius of 1.19 angstroms , Iodine ( I ) atomic radius is 1.39 angstroms.
The distance between these two atoms can be found by summing the atomic radii.
1.19 + 1.39 = 2.58 angstroms (A0).
This value is very close to the experimental value, 2.55 Angstroms.
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Consider only transitions involving the n=1 through n=4 energy levels for the hydrogen atom (using the diagram in Study Question 17).
a) How many emission lines are possible, considering only the four quantum levels?
b) Photons of the lowest energy are emitted in a trastion from the level with n=___ to a level with n=___.
c) The emission line having the shortest wavelength corresponds to a transition from the level with n=___ to the level with n=____
a) To determine the number of possible emission lines, we need to consider the transitions between the energy levels. The formula to calculate the number of possible transitions is given by:
Number of transitions = n*(n-1)/2
where n is the number of energy levels. In this case, considering the four energy levels (n = 1, 2, 3, 4), we have:
Number of transitions = 4*(4-1)/2 = 6
Therefore, there are six possible emission lines considering only the four quantum levels.
b) The lowest energy transition occurs from the level with n=4 to the level with n=1. This transition represents the largest energy drop and therefore emits photons of the lowest energy.
c) The emission line with the shortest wavelength corresponds to the transition with the highest energy. In this case, it occurs from the level with n=4 to the level with n=1. The transition from a higher energy level to a lower energy level results in the emission of a photon with a shorter wavelength.
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Chemists can identify the composition of some unknown salts by conducting a flame test. When potassium salts are heated in a flame, a purple color is observed.
This is due to the movement of electrons between energy levels. What is the electron configuration of a potassium atom at ground state?
answer choices
1s2; 2s2; 2p6; 3s2; 3p6; 4d1
1s2; 2s2; 2p6; 3s2;3p6; 3d1
1s2; 2s2; 2d6; 3s2; 3d6; 4s1
1s2; 2s2; 2p6; 3s2; 3p6; 4s1
The electron configuration of a potassium atom at ground state is 1s²2s²2p⁶3s²3p⁶4s¹. Therefore, option D is correct.
What is an electronic configuration?The electron configuration of an element can be explained as electrons being occupied in different energy levels of an atom of a specific element. In the electron configuration, the electrons are usually written as a superscript of atomic subshells. For example, the electron configuration of Helium can be represented as 1s²2s².
The sequence of completely filled subshells similar to neighboring the electronic configuration of a noble gas is represented by square brackets. The principal quantum number (n) will be used to denote the maximum number of electrons in an electron shell.
The total number of electrons occupied in the given electronic configuration 1s²2s²2p⁶3s²3p⁶4s¹ is 19. The atomic number of potassium is 19 therefore it is the configuration of potassium.
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Five observable properties for separating mixtures are ______________, _______________, ______________, _____________, ______________.
Five observable properties for separating mixtures are particle size, colour, texture, shape, magnetic attraction.
Mixtures are compounds that are made up of two or more chemical compounds which are not linked to each other chemically. They can be easily separated.
The mixtures can be separated by properties like particle size, colour, density, shape, magnetic attraction.
Sieving can be used to separate compounds based on particle size. Chromatography can be used to separate compounds based on colour as each colour would have differences in properties. Flotation can be used to separate compounds based on density like oil in water. Centrifugation can be used to separate compounds based on shape. Magnetic separation can be used to separate metals from non-metal compounds in a mixture.
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A sample of Si weighs 64.6 grams. Will a sample of Ag that contains the same number of atoms weigh more or less than 64.6 grams
Silver (Ag) will weigh more than silicon (Si) that contains the same number of atoms as the latter. According to the given statement, we have a sample of Si that weighs 64.6 grams. Silicon and silver have different molar masses, which means that the same number of atoms of the two substances will weigh differently.
It can be proved using Avogadro's number. According to Avogadro's law, one mole of any substance contains Avogadro's number of particles (atoms or molecules) and the molar mass of any substance is equal to the mass of one mole of the substance. The molar mass of silicon (Si) is 28.08 g/mol and the molar mass of silver (Ag) is 107.87 g/mol.Therefore,1 mole of Si weighs 28.08 g and contains 6.022 × 1023 atoms of Si, and1 mole of Ag weighs 107.87 g and contains 6.022 × 1023 atoms of Ag.Therefore, if a sample of Si weighs 64.6 g, we can calculate how many moles of Si are present in that sample. We can use the formula:n = m/Mwhere,n = number of moles of the substancem = mass of the substanceM = molar mass of the substanceSo, number of moles of Si present in the sample of Si = 64.6 g / 28.08 g/mol= 2.3 molThe sample of Ag containing the same number of atoms as Si will weigh the same as one mole of Ag. So, the weight of the sample of Ag can be calculated as follows:
Weight of Ag sample = number of moles of Ag × molar mass of Ag= 2.3 mol × 107.87 g/mol≈ 248.7 gThe weight of the sample of Ag that contains the same number of atoms as Si is 248.7 g, which is more than 64.6 g.
Therefore, a sample of Ag that contains the same number of atoms as Si will weigh more than 64.6 g.
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how many of the carbons originally present in glucose continue to other reactions after glycolysis?
Only three of the carbons originally present in glucose continue to other reactions after glycolysis.
During glycolysis, which is the metabolic pathway that converts glucose into pyruvate, the six-carbon glucose molecule is converted into two three-carbon molecules of pyruvate.
More specifically, during glycolysis, glucose is phosphorylated by the enzyme hexokinase to form glucose-6-phosphate, which is then converted into fructose-6-phosphate. Fructose-6-phosphate is then cleaved into two three-carbon molecules of glyceraldehyde-3-phosphate (G3P), which are subsequently converted into pyruvate through a series of enzymatic reactions.
Since each molecule of pyruvate contains three carbons, only three of the six carbons in the original glucose molecule are present in the pyruvate molecules produced during glycolysis. These three carbons are oxidized during subsequent metabolic reactions, such as the Krebs cycle (also known as the citric acid cycle) and oxidative phosphorylation, to generate ATP and other cellular energy sources.
In summary, only three of the six carbons originally present in glucose continue to other reactions after glycolysis. These three carbons are present in the pyruvate molecules produced during glycolysis, which are subsequently oxidized during other metabolic reactions to produce ATP and other cellular energy sources.
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if you want to make 1500 grams of a 2.8% by mass glucose solution how many grams of glucose do you need to add (i will give brainliest)
You need to add 42 grams of glucose to make 1500 grams of a 2.8% glucose solution.
To calculate the amount of glucose you need to add to make 1500 grams of a 2.8% glucose solution, you first need to determine what 2.8% by mass means.
2.8% by mass means that there are 2.8 grams of glucose per 100 grams of solution.
So, if you want to make 1500 grams of a 2.8% glucose solution, you can use the following equation:
mass of glucose = (percent by mass / 100) x total mass of solution
mass of glucose = (2.8 / 100) x 1500
mass of glucose = 42 grams
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If ethanol (S.G. = 0.790) were used rather than water in measuring the density of the irregular objects, how would that have affected the results? Explain.
If ethanol was used to measure the density of the irregular objects, it would not have affected the results at all.
The volume of irregular objects is obtained by displacement method. A known volume of a liquid is measured out and added to a measuring cylinder.
The irregular solid is now added to the set up and the change in volume is noted. This change in volume corresponds to the volume of the object.
If the mass of the irregular object has been previously determined, the density of the object is:
Density = mass/volume
The kind of liquid (ethanol or water) used to determine the density does not affect the results.
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How you can minimize human impact on the environment?
Look at the following equation.
Au O3 → _Au +_02
In order to follow the law of conservation of mass, this equation must have which set of coefficients, in order from left to right?
Answer:
Explanation: possible oxidation numbers of Au are +I and +III
Au2O3 ⇒ 2 Au + 3 O2
why did we choose these particular salts to test how the soap reacts with hard water?
Epsom Salt is used to test how the soap reacts with hard water because it forms precipitates with hard water
Epsom salt also known as magnesium sulfate is used to check the reaction of soap with hard water because it separates into ions giving us Mg2+ and SO4 2- ions.
Now, when we add soap to this water, soap combines with the magnesium ions and form solid particles that accumulate in clusters that become insoluble. These clusters are called precipitates which can be observed physically.
Hence, it proves the hardness of water and explains why particular salts to test how the soap reacts with hard water.
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When a sodium atom reacts with a chlorine atom to
form a compound, the electron configurations of the
ions forming the compound are the same as those in
which noble gas atoms?
1) krypton and neon
3) neon and helium
2) krypton and argon
4) neon and argon
Answer:
4) Neon and Argon
Explanation:
Sodium has 11 electrons, Chlorine has 17.
For both of them to complete their shells Sodium will give one electron to chlorine.
Sodium will become 2,8 in the reaction.
Chlorine will become 2,8,8 in the reaction.
2,8 is the electron configuration of Neon.
2,8,8 is the electron configuration of Argon
sigh.....................................
Answer:
what wrong
Explanation:
Answer:
That is a nice picture i love it plus if you need help just ask we can help :3
Explanation:
One atom of an element possesses 80 protons, 80 electrons, and 121 neutrons. Given this information, what is the atomic mass of the element?
a)160
2) 281
3)201
4) 41
Answer:
I think the answer is 4) 41
Explanation:
APE= atomic number, proton and the electrons are the same number
MAN= mass = atomic number - neutrons
121 - 80 = 41
i haven't done this in a while so hope this helps :)
A student masses a sample of clay on a balance. She successfully creates it into the shape of an ice cream cone, a donut, and a hollow ball, massing the clay after each creation. Which clay creation will have the greatest mass?
A. Ice Cream Cone
B. Hollow Ball
C. Donut
D. The mass will be the same for all
Answer:
D
Explanation:
Because she is continuously using the same piece of clay, the mas does not change.
Identify 3 physical conditions that can optimize rate of diffusion of a gas across a membrane, and relate these to Fick’s Law of Diffusion. Please describe 3 ways animal respiratory systems have evolved in order to maximize the exchange of O2 and CO2 across their membranes.
Physical conditions that can optimize rate of diffusion of a gas across a membrane and relate these to Fick’s Law of Diffusion are The partial pressure difference of gases, The surface area of the membrane, The thickness of the membrane, Ventilation and Increased surface area
Physical conditions that can optimize rate of diffusion of a gas across a membrane and relate these to Fick’s Law of Diffusion are the following:
The partial pressure difference of gases: It is the main driving force behind gas exchange. Fick's Law of Diffusion states that the rate of diffusion of a gas is directly proportional to the pressure gradient. The greater the partial pressure difference, the faster the rate of gas diffusion.
The surface area of the membrane: Fick's Law of Diffusion states that the rate of gas diffusion is proportional to the surface area of the membrane. The more surface area available for gas exchange, the faster the rate of gas diffusion.
The thickness of the membrane: Fick's Law of Diffusion also states that the rate of gas diffusion is inversely proportional to the thickness of the membrane. The thinner the membrane, the faster the rate of gas diffusion.
Animal respiratory systems have evolved in order to maximize the exchange of O2 and CO2 across their membranes in the following ways:
Ventilation: The movement of air or water over the respiratory surface increases the partial pressure gradient of gases. This increases the rate of diffusion of gases across the membrane.
Increased surface area: Respiratory surfaces have evolved to have a large surface area to increase the rate of diffusion of gases across the membrane.Thin respiratory surfaces: Respiratory surfaces have evolved to be thin to reduce the diffusion distance for gases. This increases the rate of diffusion of gases across the membrane.
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Which om sled below is amplo dl an abelis laeler in an evünment?
ban
B. droganty
C. ar temperatura
D. cation
Answer:
Explanation:
i got D
A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?
Answer:
\(\boxed {\boxed {\sf 40.4299 \ Joules}}\)
Explanation:
Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.
\(PE= m \times g \times h\)
The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.
m= 1.85 kg g= 9.8 m/s²h= 2.23 mSubstitute the values into the formula.
\(PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m\)
Multiply the first 2 numbers together.
\(PE=18.13 \ kg*m/s^2 *2.23 \ m\)
Multiply again.
\(PE= 40.4299 \ kg*m^2/s^2\)
1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J) Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J\(PE= 40.4299 \ J\)
The textbook has 40.4299 Joules of potential energy.
Which property of matter is conserved in chemical reactions and shown by balanced equations?
The property of matter that is conserved in chemical reactions and shown by balanced equations is known as the Law of Conservation of Mass. According to this law, mass can neither be created nor destroyed in a chemical reaction; it can only be transformed from one form to another.For instance, when two substances are combined, they react and form a new substance.
The products that are formed contain the same number of atoms as the reactants, but in different configurations. To keep track of the number of atoms on either side of the equation, we use coefficients, which indicate the number of molecules or atoms of each substance in the reaction. However, when a chemical equation is written, it must adhere to the law of conservation of mass.The law of conservation of mass is critical in chemical reactions because it ensures that the amount of reactants that go into a reaction equals the amount of products that come out of it. This means that the total mass of reactants must equal the total mass of the products. As a result, the balanced chemical equation must reflect this law.For example, consider the reaction between hydrogen gas and oxygen gas, which forms water. The balanced chemical equation is as follows:2H2 + O2 → 2H2OIn this reaction, two molecules of hydrogen gas react with one molecule of oxygen gas to produce two molecules of water. The coefficients in the balanced chemical equation indicate that two molecules of hydrogen and one molecule of oxygen combine to form two molecules of water, obeying the law of conservation of mass.In conclusion, the Law of Conservation of Mass is a fundamental principle in chemistry that is used to balance chemical equations. It is critical in chemical reactions because it ensures that the total mass of reactants equals the total mass of products, allowing scientists to accurately predict the outcome of a chemical reaction.For such more question on chemical reaction
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How do i solve this?
We must first identify the limiting reactant before we can calculate the output of Nitrogen. As a result, 3.365 grammes of Nitrogen are created.
What chemical compound is required to produce ammonia?Three moles of hydrogen are combined with one mole of nitrogen to produce ammonia gas. 5000 moles exist, though. As a result, since it controls how much product is produced, hydrogen acts as a reactant limiter. Hydrogen will therefore control how much ammonia forms.
Using their molar masses, we must first convert the given masses of Hydrogen peroxide and Hydrazine to moles:
molar mass Hydrogen peroxide = 34.0147 g/mol
molar mass Hydrazine = 32.0452 g/mol
moles Hydrogen peroxide = 8.17 g / 34.0147 g/mol = 0.2402 mol
moles Hydrazine = 6.97 g / 32.0452 g/mol = 0.2174 mol
The amount of Nitrogen produced from each reactant can then be calculated using the stoichiometry of the balanced chemical equation:
From Hydrogen peroxide: 1 mol Hydrogen peroxide produces 1/2 mol Nitrogen
mol Nitrogen produced from Hydrogen peroxide = 0.2402 mol Hydrogen peroxide x 1/2 = 0.1201 mol Nitrogen
From Hydrazine: 1 mol Hydrazine produces 1 mol Nitrogen
mol Nitrogen produced from Hydrazine = 0.2174 mol Hydrazine x 1 = 0.2174 mol Nitrogen
The amount of Nitrogen created is 0.1201 mol from Hydrogen peroxide, which is the smaller value. Lastly, by applying the molar mass of Nitrogen, we may convert this quantity to grams:
molar mass Nitrogen = 28.0134 g/mol
g Nitrogen produced = 0.1201 mol Nitrogen x 28.0134 g/mol = 3.365 g Nitrogen
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In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine the percentage yield if 9.77 g of carbon dioxide was obtained in the lab.
Answer:
89.3 %
Explanation:
M(CH4) = 12+ 4*1 = 16 g/mol
M(O2) = 2*16 = 32 g/mol
M(CO2) = 12 + 2*16 = 44 g/mol
8.50 g * 1 mol/16 g = 0.5313 mol CH4
15.9 g * 1 mol/32 g = 0.4969 mol O2
9.77 g * 1 mol/44 g = 0.2220 mol CO2
1) CH4 + 2O2 -----> CO2 + 2H2O
from reaction 1 mol 2 mol
given 0.5313 mol (0.4969 mol)
1 mol CH4 --- 2 mol O2
0.5313 mol CH4 --- x mol O2
x= 2*0.5313 = 1.0626 mol O2
We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.
2) CH4 + 2O2 -----> CO2 + 2H2O
from reaction 2 mol 1 mol
given 0.4969 mol x mol
x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield
3)
Practical yield CO2 = 0.2220 mol
Theoretical yield CO2 = 0.2485 mol
% yield = (0.2220/0.2485)*100% = 89.3 %
What is the formula mass/molar mass of H2CO2
H - 1.01
C - 12.01
0 - 16.00
2(1.01) + 12.01 + 2(16.00) = 46.03 g/mol
Relative and average atomic mass both describe properties of an element related to its different isotopes. Out of these two Relative atomic mas is more accurate. Therefore, 46.03 g/mol is the formula mass/molar mass of H\(_2\)CO\(_2\).
What is mass?Mass defines the quantity of a substance. It is measured in gram or kilogram. Average mass is the mass of atoms of an element that are isotopes. It can be calculated by multiplying mass of a isotope to natural abundance of that isotope.
molar mass of Hydrogen - 1.01
molar mass of Carbon- 12.01
molar mass of Oxygen - 16.00
Molar mass =2×molar mass of H +1×molar mass of C+2×molar mass of O
substituting all the values, we get
2(1.01) + 12.01 + 2(16.00) = 46.03 g/mol
Therefore, 46.03 g/mol is the formula mass/molar mass of H\(_2\)CO\(_2\).
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11. A 150 gram sample of radon-222 goes through alpha decay. The half-life of
radon-222 is 3.82 days. How much radon will be left after 3.82 days?
Answer:
The correct answer is - 75 grams.
Explanation:
Half-life is the amount of time that is used by the given amount of substance or element to make it half of the initial amount of a particular radioactive substance.
Equation for alpha decay for radon
\(^222_{86}Rn\Rightarrow^{218}_{84}Po \)
we need to calculate the left amount of radon after given time
using formula half life
\(N(t)=N_{0}e^{-\lambda t}\)
\(\lambda =\dfrac{0.693}{3.82}\)
\(\lambda=0.1814\)
\(N(3.82)=150\times e^{-0.1814\times3.82}\)
\(N(3.82)=75.0\ g\)
Thus, the left amount of radon is - 75 grams.
the formation of large molecules from small repeating units is known as what kind of reaction?
The formation of large molecules from small repeating units is known as a polymerization reaction.
It is a fundamental process in which monomers, which are the individual building blocks, undergo chemical reactions to form a polymer chain.
Through this reaction, monomers are joined together by covalent bonds to create a complex, three-dimensional structure.
Polymerization reactions can occur through different mechanisms, such as addition polymerization and condensation polymerization, depending on the nature of the monomers involved.
The resulting polymers can have a wide range of properties and applications, making polymerization a crucial process in various fields, including materials science, chemistry, and biology.
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For some material, the heat capacity at constant volume Cv at 29 K is 0.81 J/mol-K, and the Debye temperature is 303 K. Estimate the heat capacity (in J/mol-K) (a) at 56 K, and (b) at 495 K.
The estimated heat capacity for a material at 56 K is approximately 1.58 J/mol-K, and at 495 K is approximately 3.47 J/mol-K, using the Debye model.
To estimate the heat capacity at a temperature T, we can use the Debye model:
Cv = 9Nk(θD/T)³ ∫\(0^{(\theta D/T)\) (\(x^4 e^x\) / (\(e^x\) - 1)²) dx
where N is the number of atoms per mole, k is Boltzmann's constant, θD is the Debye temperature, and x is a dimensionless variable (x = hν/kT, where h is Planck's constant and ν is the frequency of the vibration mode).
(a) To estimate the heat capacity at 56 K, we can use the same formula with T = 56 K:
Cv = 9Nk(θD/T)³ ∫\(0^{(\theta D/T)\) (\(x^4 e^x\) / (\(e^x\) - 1)²) dx
= 9Nk(303 K/56 K)³ ∫\(0^{(303 K/56 K)}\) (\(x^4 e^x\) / (\(e^x\) - 1)²) dx
≈ 1.58 J/mol-K
Therefore, the estimated heat capacity at 56 K is approximately 1.58 J/mol-K
(b) To estimate the heat capacity at 495 K, we can again use the same formula with T = 495 K:
Cv = 9Nk(θD/T)³ ∫\(0^{(\theta D/T)}\) (\(x^4 e^x\) / (\(e^x\) - 1)²) dx
= 9Nk(303 K/495 K)³ ∫\(0^{(303 K/495 K)}\) (\(x^4 e^x\) / (\(e^x\) - 1)²) dx
≈ 3.47 J/mol-K
Therefore, the estimated heat capacity at 495 K is approximately 3.47 J/mol-K.
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What are some ways organism adapt to survive in the desert?
Answer: Animals survive in deserts by living underground or resting in burrows during the heat of the day. Some creatures get the moisture they need from their food, so they don’t need to drink much water, if any. Others live along the edges of deserts, where there are more plants and shelter.
Explanation:
what is S in the equation G= H-T delta S?
Answer:
C
Explanation:
∂S represents change in entropy.
State the law of moment of force.
Explanation:
when in equilibrium condition the total sum of anti clockwise moment is equal to the sum of clock wise moment
Answer:
Newton's First Law of Motion states that in order for the motion of an object to change, a force must act upon it. This is a concept generally called inertia.
Newton's Second Law of Motion defines the relationship between acceleration, force, and mass.
Newton's Third Law of Motion states that any time a force acts from one object to another, there is an equal force acting back on the original object. If you pull on a rope, therefore, the rope is pulling back on you as well.
Explanation:
please hep!! water has a density of 1.0 g/mL. a plastic cup floats when it is placed into a container of water. what can you conclude about the density of the plastic cup? (look at the picture)
Water has a density of 1.0 g/mL. A plastic cup floats when it is placed into a container of water as it is less denser than water.
Density is a key notion in physics and material science that quantifies how tightly packed a substance's particles or molecules are within a certain volume. It is a measure of the mass contained in a certain amount of space that gives useful information about the properties of various materials.
It is vital to highlight that density is a material attribute that remains constant regardless of sample size. A little piece of iron, for example, has the same density as a huge iron block, despite the larger block having more mass.
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given that benzaldehyde is a meta- director, in the same marvin editor draw all three resonance structures for the carbocation intermediate that results from step 2 in the electrophilic aromatic substitution reaction when benzaldehyde reacts with br2 in the presence of febr3. if you do not remember the structure of the benzene derivative, consult the l3 complete lecture notes slides
In the electrophilic aromatic substitution reaction between benzaldehyde and Br2 in the presence of FeBr3, the first step involves the generation of a carbocation intermediate. This carbocation is formed when the bromine molecule attacks the benzene ring, displacing a proton.
Since benzaldehyde is a meta-director, the carbocation intermediate will be stabilized through resonance. The resonance structures can be represented as follows:
Structure 1:
Br
|
Ph-C(+)-H
|
Structure 2:
Br
|
Ph-C-H
| |
+ Ph
Structure 3:
Br
|
Ph-C-H
| |
Ph +
In these resonance structures, the positive charge of the carbocation is delocalized throughout the benzene ring. The presence of the electron-withdrawing aldehyde group (CHO) in benzaldehyde directs the incoming bromine atom to the meta position relative to the aldehyde group.
Please note that it's always recommended to consult reliable sources and appropriate references for accurate structural representations.
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A pH scale is used to measure?
Answer:
A pH scale is used to measure acidity.
Answer:
How acidic or alkaline a substance is.
Explanation:
1 = Strong acid e.g. Stomach acid
7 = Neutral e.g. Water
14 = Strong alkaline e.g. Sodium hydroxide