Energy sources used today are mostly in what form of energy?
Select one:
O a.
electrical
O b. chemical
O c. nuclear
O d. radiant

The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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Answer:

I believe you put how you think you'd feel it's that simple

Answer:

utilizing positive values

Explanation:

The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.

This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.

The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.

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Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of scientific hypotheses (Option C).

Scientific hypotheses are explanations about questions of the real world that can be used to test them by using the scientific method, i.e., by testing them to confirm or reject their assumptions through experimental and observation procedures.

Therefore, with this data, we can see that a scientific hypothesis is formulated and tested by using the scientific method in order to confirm or reject its assumptions and thus build scientific knowledge.

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Answer:

Scientific hypothesis

Explanation:

The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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Answer:

5460000000 J OR 5460000 KJ

Explanation:

GPE = mgh

21000*10*26000

=5460000000J OR 5460000KJ

Answer:

Angular displacement=68.25 rad

Explanation:

Circular Motion

If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:

\(\displaystyle \alpha=\frac{\omega_f-\omega_o}{t}\)

The angular displacement is given by:

\(\displaystyle \theta=\omega_o.t+\frac{\alpha.t^2}{2}\)

The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:

\(\displaystyle \alpha=\frac{6-13.5}{7}\)

\(\displaystyle \alpha=\frac{-7.5}{7}\)

\(\displaystyle \alpha=-1.071 \ rad/s^2\)

Thus, the angular displacement is:

\(\displaystyle \theta=13.5*7+\frac{-1.071*7^2}{2}\)

\(\displaystyle \theta=94.5-26.25\)

\(\boxed{\displaystyle \theta=68.25\ rad}\)

Angular displacement=68.25 rad

Answer:

A B C

Explanation:just took the test

Answer:

Komal could have mixed up the labels on the vials.

Someone might have jiggled the table and made the water surface tension bubble spill over.

The water could actually have been saltwater instead of pure water.

Explanation:

...........................

Answer:

the impulse imparted to the ball is 4.158 kg.m/s

Explanation:

Please find attached image for diagram.

Given;

initial speed of the ball from point A, u = 54km/h = 15 m/s

angle of deflection of the ball along BOP, θ = 45⁰/2 = 22.5⁰

mass of the ball, m = 0.15 kg

the final speed of the ball along B,  = u (in reverse direction)

The initial momentum of the ball, P₁ = mucosθ

The final momentum of the ball is P₂ in reverse direction to P₁.

the impulse imparted to the ball = change in momentum of the ball

J = ΔP = P₂ - P₁

J = mucosθ - (-mucosθ)

J = mucosθ + mucosθ

J = 2mucosθ

J = 2(0.15)15cos(22.5⁰)

J = 4.158 kg.m/s

Thus, the impulse imparted to the ball is 4.158 kg.m/s

Answer:

It's true that organisms get energy from food.

Answer:

Explanation:

Organisms ingest large molecules, like carbohydrates, proteins, and fats, and convert them into smaller molecules like carbon dioxide and water. This process is called cellular respiration, a form of catabolism, and makes energy available for the cell to use

In order to determine the sped of Betty at the lowest position, proceed as follow:

The potential energy for a height of 1.22m is:

The potential energy at the lowest point is:

Consider that at the starting point all the mechanical energy is potential energy (559.54J). Moreover, when Betty moves through the lowest point, part of the mechanical energy becomes thermal energy and kinetic energy.

Take into account that the for the lowest point, the sum of thermal energy, kinetic energy and potential energy must be equal to the total mechanical energy:

U2 + K + Th = 559.54J

where K is the kinetic energy and Th is the thermal energy. Consider that

Th = 179J

U2 = 191.25J

Solve the equation for K and replace the values of the other contributions to the total energy:

K = 559.54J - U2 - Th

K = 559.54J - 191.25J - 179J

K = 189.29J

Next, take into account that the kinetic energy is given by:

solve the previous equation for v and replace the values of K and m:

Hence, Betty moves with a speed of approximately 2.84m/s through the lowest point.

Answer:

\( \boxed{\sf Kinetic \ energy \ (KE) = 48 \ J} \)

Given:

Mass (m) = 6 kg

Speed (v) = 4 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

\( \boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}\)

Substituting values of m & v in the equation:

\( \sf \implies KE = \frac{1}{2} \times 6 \times {4}^{2} \)

\( \sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 3 \times 16\)

\( \sf \implies KE =3 \times 16\)

\( \sf \implies KE = 48 \: J\)

Answer:

The significant figures in a measurement consist of all the certain digits in that measurement plus one uncertain or estimated digit. In the ruler illustration below, the bottom ruler gave a length with 2 significant figures, while the top ruler gave a length with 3 significant figures.

Explanation:

Answer:

velocity is the speed of something in a particular direction while time is what is measured in hours , minutes and seconds

Complete Question

A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.

Answer:

The value is  \(x = 14.6 \ MHz\)

Explanation:

From the question we are told that

  The  frequency is  \(f = 14603 \ kHz = 14603 *1000 = 14603000 \ Hz\)

Generally  

       \(1 Hz \to 1.0 *10^{-6} \ MHz\)

       \(14603000 \ Hz \to x MHz\)

=>   \(x = \frac{14603000 * 1.0*10^{-6}}{1 }\)

=>    \(x = 14.6 \ MHz\)

Answer:

Quantum theory gives the concept of

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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Answer:

\(Va-Vb=168KV\)

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the  Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D=\(\sqrt{0.3^2+0.4^2} =0.5\)

at  opposite sides

Mathematically Va can represented as

\(Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(0.00001333333-0.000004} )\)

\(Va =84000V\)

\(Va =84KV\)

Mathematically Vb is  represented as

\(Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )\)

\(Va =9*10^9(-0.00001333333+0.000004} )\)

\(Va =-84000V\)

\(Va =-84KV\)

Therefore

\(Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV\)

Answer:

Sand is a form of physical change because it shows how one object is being worn out (broken down) into another object by nature.

Explanation:

Answer:

Explanation:

To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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The charge R is positive and the charge L is negative hence, the correct option is option D.

The electric charges are of two types and they are positive and negative charge. There is an attractive force between the two charges. The electric field is formed around the charges and the electric field is denoted by using field lines around it.

The field lines are emerging from positive charge and end up in a negative charge. The field lines never intersect with each other. Hence, from the given, the field lines emerging from the positive charge(R) and end up in the negative charge(L).

Hence, the ideal solution is option D.

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-27.7 x 10⁶ N is the net force on particle q₂..

Define a charged particle

A particle with an electric charge is said to be charged particle. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. It could also be an elementary particle like as an electron, proton, or another one that is thought to have the same charge (except antimatter).

F₁₂ = kq₁q₂/r²

k is Coulomb's constant

r is the distance between q₁ and q₂

q represent charges

F₁₂ = (9x 10⁹ x 18.1 x 10⁻³ x 11.2 x 10⁻³)/(0.28)²

F₁₂ = -23* 10⁶ N

F₂₃ = kq₂q₃/r²

F₂₃ = -(9 x 10⁹ x 11.3 x 10⁻³ x 5.67 x 10⁻³)/(0.35)²

F₂₃ = 4.7 x 10⁶ N

F(net) = F₁₂ + F₂₃

         = -23* 10⁶ N + -4.7 x 10⁶ N

         =  -27.7 x 10⁶ N

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Answer: refracting telescope

Explanation: Refracting telescopes use a convex lens to gather light and focus it on an eyepiece, which magnifies the image.

Answer:

refracting

Explanation:

edge 2023 trust

It can be inferred from this statement that the detection of short bursts of radio waves or fast radio bursts is very common.

Fast or Short radio bursts, are intense, millisecond-long bursts of radio waves with unknown origins.

Since the first FRB was discovered in 2007, hundreds of these brief cosmic flashes have been shown to originate from several, far-off locations throughout the universe.

A significant portion of FRBs emit extremely brilliant radio waves that last only a few milliseconds at most before entirely vanishng, and about 10% of them have been seen to repeat and exhibit patterns.

The source's identity is still unknown due to the isolated character of the observed occurrence. Although a magnetar has been recognised as a potential source, as of 2022, there is no widely acknowledged single explanation.

Given that the bursts barely last a few milliseconds, the sources are assumed to be little larger than a few hundred kilometres.

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Answer: 3 days

Explanation:

Answer:

2.54 seconds

Explanation:

The period of a swing on a playground swing set can be calculated using the formula:

T = 2π√(L/g)

where T is the period, L is the length of the swing's chain, and g is the acceleration due to gravity, which is approximately 9.81 m/s².

Substituting the given values, we get:

T = 2π√(4.0 m/9.81 m/s²)

T = 2π√0.407

T = 2.54 s (rounded to two significant figures)

Therefore, the period of the swing is 2.54 seconds.

Hope this helps!

Answer:

λ = 1.86 x 10⁻⁴ m = 186 μm

Explanation:

The relationship between the wavelength and the frequency of a wave is given by the following equation:

\(c = f\lambda\\\\\lambda = \frac{c}{f}\)

where,

λ = wavelength of infrared radiation = ?

c = speed of infrared radiation = speed of light = 3 x 10⁸ m/s

f = frequency of infrared radiation = 1.61 THz = 1.61 x 10¹² Hz

Therefore,

\(\lambda = \frac{3\ x\ 10^8\ m/s}{1.61\ x\ 10^{12}\ Hz}\)

λ = 1.86 x 10⁻⁴ m = 186 μm