Electronic configuration An element's atomic number tells you the number of _______________ in the nucleus. The number of in an atom is equal to the number of In the first shell of an atom there are shell there are_______ electrons. In the third shell there are electrons. electrons. In the second​

Answer:

A. Condensation

Explanation:

That's the answer to this question

Answer:

A: condensation

Explanation:

it's the right answer

After 3.75 days, 6.25 grams of sodium-24 will remain.

Hope it helps ~

Answer:

3.62

Explanation:

Answer:

continental plate boundaries

Explanation:

Equilibrium is a state in a chemical reaction where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of reactants and products. It is represented by a double arrow (⇌) in chemical equations. In the given equation: H₂O (g) + CO (g) ⇌ H₂(g) + CO₂(g) + 42 KJ

To shift the equilibrium to the right, one or more of the following could occur:

Increasing the concentration of H₂ or CO₂

Decreasing the concentration of H₂O or CO

Increasing the pressure

Removing some of the products (H₂ and CO₂)

Decreasing the temperature

To shift the equilibrium to the left, one or more of the following could occur:

Decreasing the concentration of H₂ or CO₂

Decreasing the pressure

Increasing the temperature

If pressure is increased, the equilibrium will shift in the direction that produces fewer moles of gas. In this case, since there are fewer moles of gas on the right side of the equation (H₂ and CO₂), the equilibrium will shift to the right. If heat is added, the equilibrium will shift in the endothermic direction to absorb the additional heat. In this case, the forward reaction is endothermic (42 KJ on the right side), so the equilibrium will shift to the right to consume the added heat.

If CO is added, the equilibrium will shift to the right to consume the additional CO.The concentration of H₂O and CO₂ will increase, while the concentrations of H₂ and CO will decrease until a new equilibrium is reached.

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Answer: D. OH- (Edmentum)

Explanation: Took the test and got it right!

Answer:

force

Explanation:

Answer:

what dose this mean "_" is there an image that could help?

To determine the direction in which the reaction will proceed based on the given value of Qp (reaction quotient), we need to compare Qp with the equilibrium constant Kp.

The given equilibrium constant Kp is 2.7.

Qp is calculated by using the molar concentrations of the reactants and products raised to the power of their respective stoichiometric coefficients.

For the given reaction: CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

The expression for Qp is:

Qp = (PCO2 * PH2) / (PCO * PH2O)

where PCO2, PH2, PCO, and PH2O are the partial pressures of CO2, H2, CO, and H2O, respectively.

Now, let's calculate Qp using the given concentrations and the ideal gas law (assuming ideal gas behavior):

PCO2 = (moles of CO2 / total moles) * (RT / V)

PH2 = (moles of H2 / total moles) * (RT / V)

PCO = (moles of CO / total moles) * (RT / V)

PH2O = (moles of H2O / total moles) * (RT / V)

where R is the ideal gas constant (0.0821 L·atm/(mol·K)), T is the temperature in Kelvin, and V is the volume of the flask (2.0 L).

Given:

moles of CO = 0.13

moles of H2O = 0.56

moles of CO2 = 0.62

moles of H2 = 0.43

total moles = 0.13 + 0.56 + 0.62 + 0.43 = 1.74

Substituting these values into the expressions for the partial pressures:

PCO2 = (0.62 / 1.74) * (0.0821 * T / 2.0)

PH2 = (0.43 / 1.74) * (0.0821 * T / 2.0)

PCO = (0.13 / 1.74) * (0.0821 * T / 2.0)

PH2O = (0.56 / 1.74) * (0.0821 * T / 2.0)

Now we can substitute the partial pressures into the expression for Qp:

Qp = (PCO2 * PH2) / (PCO * PH2O)

Qp = [(0.62 / 1.74) * (0.0821 * T / 2.0) * (0.43 / 1.74) * (0.0821 * T / 2.0)] /

[(0.13 / 1.74) * (0.0821 * T / 2.0) * (0.56 / 1.74) * (0.0821 * T / 2.0)]

Simplifying the expression:

Qp = (0.62 * 0.43) / (0.13 * 0.56)

Now, let's calculate Qp:

Qp = 0.27

Comparing Qp with Kp:

If Qp < Kp, the reaction will proceed to the right to reach equilibrium.

If Qp > Kp, the reaction will proceed to the left to reach equilibrium.

If Qp = Kp, the reaction is already at equilibrium.

In this case, since Qp (0.27) is less than Kp (2.

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Answer:

39.2 g

Explanation:

because moles = mass / mr (mr of h is 1)

so 39.2/1= 39.2 moles

hope this helps you to understand :)

Acetic acid is more soluble in water than decanoic acid because acetic acid is smaller in size and has a lower molecular weight compared to decanoic acid.

Solubility is the ability of a substance to dissolve in a particular solvent, such as water. The solubility of a substance depends on various factors, including the chemical nature and size of the molecules or ions involve

Acetic acid (CH3COOH) is a smaller molecule compared to decanoic acid (CH3(CH2)8COOH). Acetic acid has a smaller molecular weight and a shorter chain length, which allows it to form more extensive hydrogen bonding with water molecules. This results in higher solubility of acetic acid in water.

Decanoic acid, on the other hand, is a larger molecule with a longer chain length, which reduces its ability to form hydrogen bonds with water molecules. This results in lower solubility of decanoic acid in water compared to acetic acid.

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Answer:

mu answer is A

Explanation:

i think it is a popular opinion because its the opinion of a country

Answer:

One example of an ionic bond is the formation of sodium fluoride, NaF, from a sodium atom and a fluorine atom. In this reaction, the sodium atom loses its single valence electron to the fluorine atom, which has just enough space to accept it.

Explanation:

Answer:

chemical equation balance.

Explanation:

if you need more explanation , comment.

When current is allowed to flow, the species that gets oxidized depends on the specific conditions of the system. However, based on the given options, the likely species to be oxidized would be A) Cr₂O₇²⁻.

When current flows in a system, oxidation and reduction reactions occur simultaneously at different electrode surfaces. The species that gets oxidized is the one that loses electrons. In the given options, Cr₂O₇²⁻ and MnO⁴ are both polyatomic ions with high positive oxidation states, while Cr³⁺ and Mn²⁺ have lower positive oxidation states. H³⁺ refers to a hydrogen ion, which is not a likely candidate for oxidation in this context.

In the case of Cr₂O₇²⁻, it has a higher positive oxidation state compared to Cr³⁺. Therefore, it is more likely to undergo oxidation and lose electrons when current is allowed to flow. The half-reaction for the oxidation of Cr₂O₇²⁻ to Cr³⁺ can be represented as follows:

Cr₂O₇²⁻ (aq) → 2Cr³⁺ (aq) + 3e⁻

This reaction involves the reduction of another species, which gains the electrons released during the oxidation of Cr₂O₇²⁻. It's important to note that the actual species being oxidized or reduced can vary depending on the specific conditions of the system, such as pH and the presence of other reactants.

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A. The reaction would remain in equilibrium

Given

Reaction

H₂ + I₂ ⇔ 2HI

Required

the effect of pressure changes

Solution

In the equilibrium system :

Reaction = - action  

⇒shift the reaction to the right or left.  

The pressure usually affects the gas equilibrium system(only count the number of moles of gases)

The addition of pressure, the reaction will shift towards a smaller reaction coefficient  ((the fewest moles of gas  )

Reaction

H₂ + I₂ ⇔ 2HI

The reactant side of the equation has 2 moles of a gas(1 mole H₂ and 1 mole  I₂) ; the product side has 2 moles HI

So the total number of moles from both sides is the same(2 moles) so that the change in volume (pressure) does not change the direction of equilibrium⇒No shift will occur

Answer:

A. The reaction would remain in equilibrium

Explanation:

Explanation:

In solids, the particles are tightly packed together. In liquids, the particles have more movement, while in gases, they are spread out. Particles in chemistry can be atoms, ions or molecules. It is important to understand the particle nature of matter.

At a very high pressure, the volume of occupied by a real gas  is greater than the volume predicted by the ideal gas law, because the volume of the actual particles is more significant under high pressure.

At low pressure, the distance between gas molecules is relatively far apart, but as the pressure of the gas increases, the distances between theses gaseous molecules becomes smaller.

Due to the high pressure the volume occupied by the gas molecules becomes significant compared with the volume of the container.

As a result, the total volume occupied by the gas will be greater than the volume predicted by the ideal gas law.

Thus at a very high pressure, the volume of occupied by a real gas  is greater than the volume predicted by the ideal gas law, because the volume of the actual particles is more significant under high pressure.

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Answer: The fourth answer

Explanation:

Under high pressure, real gases deviate from ideal gas behavior as their particles have a finite size and experience intermolecular forces, causing the actual volume of the gas to be lower than predicted by the ideal gas law.

Available phosphorus levels decline in lower pH, acidic soils because of the increased fixation of phosphorus by soil minerals.

In acidic soils, the pH is low, which means that the soil is more acidic.

Under these conditions, the availability of phosphorus to plants decreases.

This decrease occurs primarily due to the increased fixation or binding of phosphorus by soil minerals, particularly iron (Fe), aluminum (Al), and calcium (Ca) compounds.

When the soil pH is low, these minerals become more soluble and active in binding phosphorus.

The positively charged surfaces of these minerals attract and bind to the negatively charged phosphate ions (PO4 3-) present in the soil.

This binding process, known as phosphorus fixation, reduces the amount of available phosphorus in the soil solution, making it less accessible to plants.

Additionally, the acidic conditions in the soil can also lead to the formation of insoluble compounds, such as iron and aluminum phosphates, further reducing the availability of phosphorus for plant uptake.

To mitigate the decline in available phosphorus in acidic soils, it is common to apply phosphorus fertilizers to provide an additional source of this essential nutrient for plant growth.

Soil amendments or liming materials can also be used to raise the pH of acidic soils, which helps to reduce phosphorus fixation and improve its availability to plants.

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2.49 x \(10^{-4}\) moles is equal to 1.5×\(10^{20}\). The number of moles is equal to the number of molecules divided by Avogadro's number, 6.022×\(10^{23}\).

This means that 1.5×\(10^{20}\)moles are equal to

1.5×\(10^{20}\)/6.022×\(10^{23}\)

0.24908×\(10^{-3}\)

2.49 x \(10^{-4}\) moles.

Avogadro's number: Avogadro's number is a constant used in chemistry to represent the number of atoms or molecules in a mole of a substance. It is equal to 6.022 x \(10^{23}\). Or we can say that Avogadro's number is, the number of units in one mole of any substance (defined as its molecular weight in grams), equal to 6.02214076 × 1023. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction.

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b. The critical path refers to the longest sequence of activities from the start to the end of a project, considering the duration of each activity.

c. The total duration for the critical path activities is 18 days, which represents the expected project completion time.

The critical path is a term used in project management to refer to the sequence of activities that determines the minimum time required to complete a project. It is the longest path from the start to the end of the project, considering the duration of each activity. The critical path helps identify the activities that must be closely monitored and managed to ensure the project is completed on time.

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Answer:

Graphite and diamond are two of the most interesting minerals. They are identical chemically – both are composed of carbon (C), but physically, they are very different. Minerals that have the same chemistry but different crystal structures are called polymorphs.

The effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.

1. The class of drugs being investigated in this study is antidepressants. They enter our waterways through excretion by individuals taking the medication, and disposal of unused medication into toilets or sinks that are connected to wastewater treatment plants.

2. C-start is an evasive maneuver that young fish use when they perceive a predator. This is important for larval fish survival because it helps them to avoid being eaten by predators.

3. In this investigation, researchers are testing two hypotheses. The first is that exposure to low levels of antidepressants can affect larval fathead minnows' behavior, and the second is that the effects of exposure will be more pronounced in fish that have been raised in a less stressful environment.

4. The researchers found that exposure to antidepressants at levels found in waterways can have a significant impact on the behavior of larval fathead minnows. Specifically, they found that the fish exposed to antidepressants were less likely to respond to the presence of predators, which could increase their risk of being eaten.

They also found that the effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.

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Answer:

Methoxyethene.

count 11 isomers of C3H6O.

They are: Prop-2-en-1-ol. Allyl Alcohol

Explanation:

I dunno if his helps...

The two  constitutional isomers, which contain contain carbon–oxygen double bonds will be propenal and propanone.

Molecules with isomers have about identical chemical structures with various spatial arrangements.

The pic of isomer is shown below:

In such isomer, carbon and oxygen atom is attached with double bond. Both molecule posses three carbon atom hence, can be named as prop. Due to presence of aldehyde and ketone functional group it can be named as propenal and propanone.

The two constitutional isomers, which contain carbon-oxygen double bonds will be propenal and propanone.

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Answer: There are about 0.28 molecules in 43.9 g of carbon tetrachloride. If you are rounding up, it would be 0.3

Explanation: