Draw out a two column proof for each problem below. Complete all problems on one page and upload ONE photo of the entire assignment Make sure your file/image is clear (not blurry) and easy to read. Problem 1. Congruent Triangle Proof (10 Points) Given: NQ is the bisector of MNP and NMQ ~ ZNPQ| Prove: A MNQA PNQ 0 Problem 2. Proof Involving CPCTC (14 Points) Given: S is the midpoint of QR QR PS and RSP and QSP are right angles. Prove: PR PQ S 0​

The figure comprises of two triangles ∆LMN and ∆HJK, a rectangle OHKN, and a semicircle of arc HP, and the total area all the basic plane shape will give the area of the figure.

We can observe from the figure that LMN and HJK are two different triangles and their area can be derived by half of the multiple of their base and height.

The lines OL and HK are parallel, likewise the lines OH and NK, so OHKN is a rectangle and its area can be simply derived by multiplying its length by the width.

The area of the semicircle with arc HP can be derived using the formula πr²/2, where r is the radius.

Therefore, we can derive the area of the figure by the adding the areas for the triangles ∆LMN and ∆HJK, the rectangle OHKN, and semicircle with arc HP

Know more about area here:https://brainly.com/question/10254615

#SPJ1

Answer:

It's C! y = 7

Step-by-step explanation:

Answer:

k = - 3

Step-by-step explanation:

g(x) is really a disguise of f(x). What you have done is move 3 units down. (Just look at the minimum point of f(x)  which is 0,0) The minimum point has gone down to 0,-3

So the value of k must be - 3

The applied overhead cost for job 201 is $36,000 and total cost for job 201 under direct materials cost as allocation base is $86,000.

Allocation base is a technique utilized in accounting to designate the cost of something to its use or product to recognize the price of the finished product.

Example provides the total overhead cost at $120,000 for the period, the base data of $100,000 direct material cost and 500 direct labor hours. The base data are used to calculate the predetermined factory overhead rate, which is used to apply overhead costs to work in progress.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the base data. The predetermined factory overhead rate is multiplied by the actual activity in the allocation base to obtain the applied overhead cost.

Direct materials cost as allocation base $30,000 is the actual direct material cost used in job 201. The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct material cost, which is $120,000/$100,000=120%.

The applied overhead cost for job 201 is $30,000*120% = $36,000.

Total cost for job 201 under direct materials cost as allocation base is $30,000+$20,000+$36,000 = $86,000.

-Direct labor cost as allocation base:

The actual direct labor cost used in job 201 is $20,000. The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct labor cost, which is $120,000/$100,000=120%.

The applied overhead cost for job 201 is $20,000*120% = $24,000.

Total cost for job 201 under direct labor cost as allocation base is $30,000+$20,000+$24,000 = $74,000.

-Direct labor hours as allocation base:

The actual direct labor hours used in job 201 is 400 hours.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the direct labor hours, which is $120,000/500 hours = $240 per hour.The applied overhead cost for job 201 is $240*400 hours = $96,000.

Total cost for job 201 under direct labor hours as allocation base is $30,000+$20,000+$96,000 = $146,000.

-Physical output as allocation base: The actual output in units completed for job 201 is 2,000 shirts.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the output in units, which is $120,000/10,000 units = $12 per unit.

The applied overhead cost for job 201 is $12*2,000 units = $24,000.Total cost for job 201 under physical output as allocation base is $30,000+$20,000+$24,000 = $74,000.

-Machine hours as allocation base: The actual machine hours used in job 201 is 240 hours.

The predetermined factory overhead rate is calculated by dividing the total overhead cost for the period by the machine hours, which is $120,000/5,000 hours = $24 per hour.

The applied overhead cost for job 201 is $24*240 hours = $5,760.

Total cost for job 201 under machine hours as allocation base is $30,000+$20,000+$5,760 = $55,760.

For more such questions on cost visit:

https://brainly.com/question/31479672

#SPJ8

Answer:

Rule: dilation about the origin by a scale factor of 2

Step-by-step explanation:

Given

See attachment for QRST and Q'R'S'T

Required

The dilation rule

First, we calculate the scale factor (k)

From the attachment, we have:

\(QR = 4\)

\(Q'R' = 8\)

k, is then calculated as:

\(k = \frac{Q'R'}{QR}\)

\(k = \frac{8}{4}\)

\(k =2\)

Hence, QRST is dilated by a factor of 2

\(\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2} ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ \theta =\frac{\pi }{2}\\[1em] r=\frac{8}{3} \end{cases}\implies A=\cfrac{1}{2}\cdot \cfrac{\pi }{2}\cdot\left( \cfrac{8}{3} \right)^2 \\\\\\ A=\cfrac{1}{2}\cdot \cfrac{\pi }{2}\cdot \cfrac{64}{9}\implies A=\cfrac{16\pi }{9}\implies A\approx 5.59\)

The total number of possible outcomes is given by the expression 6n × 52, where n represents the number of marbles to choose from.

To determine the number of possible outcomes, we need to consider the number of outcomes for each event and then multiply them together.

1. Picking a marble: Let's assume there are n marbles to choose from. If there are n marbles, then the number of outcomes for this event is n.

2. Rolling a die: A standard die has 6 sides numbered 1 to 6. Therefore, the number of outcomes for this event is 6.

3. Picking a card: A standard deck of cards has 52 cards. Hence, the number of outcomes for this event is 52.

To find the total number of possible outcomes, we multiply the number of outcomes for each event together:

Total number of outcomes = (number of outcomes for picking a marble) × (number of outcomes for rolling a die) × (number of outcomes for picking a card)

Total number of outcomes = n × 6 × 52

Therefore, the total number of possible outcomes is given by the expression 6n × 52, where n represents the number of marbles to choose from.

Learn more about probability at https://brainly.com/question/13604758

#SPJ1

The probability of randomly selecting a student that didn't get an A is P = 0.61

We want to find the probability that the student did not get an A.

To get this, we need to take the quotient between the number of students that didn't get an A, and the total number of students.

In the table,  can see that there is a total of 69 students and we also can see that of these 69, 27 got an A.

Then the number that did not get an A is:

69 - 27 = 42

Then the probability is:

P = 42/69 = 0.61

Learn more about probability at:

https://brainly.com/question/25870256

#SPJ1

Counting the shaded squares, we see that 78 out of 100 is shaded.

Now,

That is

78/100

In decimal,

78/100=0.78

first answer is correct.

0.7800 --- this is correct as well because we can drop the last zeros, they aren't significant.

0.078

If you get its fraction, you will see that it is:

78/1000, which is not what we want.

Thus, this option isn't correct!

Answer:

d po

Step-by-step explanation:

sna maka tulong hheeheh

Answer:

\(\mathbf{E(p) = 1 - 3p}\)

the estimate the percent change in q when the price is raised from $2.00 to $2.10 decreases by 25%

Step-by-step explanation:

Given that:

the number of units demanded \(q = pe^{-3p}\)

Taking differentiations ; we have,

\(\dfrac{dq}{dp}=e^{-3p}+p(-3e^{-3p})\)

\(\dfrac{dq}{dp}=(1-3)e^{-3p}\)

Now; the price elasticity of demand using the differentials definition of elasticity  is:

\(E(p) = \dfrac{dq}{dp}*\dfrac{p}{q}\)

\(E(p) =[(1-3)e^{-3p}]*[\dfrac{p}{pe^{-3p}}]\)

\(\mathbf{E(p) = 1 - 3p}\)

(b)   Use your answer from part (a) to estimate the percent change in q when the price is raised from $2.00 to $2.10.

The estimate of the percentage change in price is :

\(=\dfrac{2.10-2.00}{2.00}*100 \%\)

= 5%

From (a)

\(\mathbf{E(p) = 1 - 3p}\)

Now at p = $2.00

E(2) = 1 - 3 (2.00)

E(2) = 1 - 6

E(2) = -5

The percentage change in q = -5 × 5%

The percentage change in q = -25%

Thus; we can conclude that the estimate the percent change in q when the price is raised from $2.00 to $2.10 decreases by 25%

Answer:

A)

Step-by-step explanation:

rise/run

down 5, left 3

Answer: b

Because I learned this beforeStep-by-step explanation:

Answer:

Step-by-step explanation:

\(f(3,7)=\frac{3+7}{2(3)+7}=\frac{10}{13}\\f(4,4)=\frac{4+4}{2(4)+4}=\frac{8}{12}=\frac{2}{3}\\f(1,5)=\frac{1+5}{2(1)+5}=\frac{6}{7}\)

STEP - BY - STEP EXPLANATION

What to find?

The value of the variable x.

Given:

Opposite=x

Adjacent = x

Hypotenuse = 5

Step 1

Recall the Pythagoras theorem.

Step 2

Substitute the values into the formula.

Step 3

Divide both-side of the equation by 2.

Step 4

Take the square root of both-side.

ANSWER

3.5

Answer:

Step-by-step explanation:

If order matters (much like forming... a 4 digit number-maybe for a safe?), you will be computing "permutations".  The  formula for "r" items chosen from  "n" items, where order matters is   Npermutations = nPr  =  n!/ (n-r)!

Npermutations = 10P6 =  10!/(10-6)= 10*9*8*7*6*5 = 151200

When order doesn't matter (such as in dealing a poker hand, its the cards you end up with that matter not the order in which they are dealt into your hand) you will be computing combinations.   The formula for the number of combinations of  "r "items from "n" choices is  Ncombinations =  nCr = n!/((n-r)!r!)

Ncombinations = 10C6 =  10!/((10-6)!6!) =  (10*9*8*7)/(4*3*2*1) = 210

Notice how there are far fewer combinations than permutations.  This makes sense because if you think about how 6 colors  {red, blue, green, white, black, yellow} can be arranged, there are 6!=720 ways to arrange these 6 colors if order matters.  If order doesn't matter, this set of 6 colors counts only once.
Same thing with numbers :)

Hope this helped, brainliest is always appreciated! :)

Have a nice day CX
~Mitsuna

Answer:

7/2, 5/4

Step-by-step explanation:

Answer:

x = 7/2 and y = 5/4

Step-by-step explanation:

2(5x - 2y = 15)

2x + 4y = 12

10x - 4y = 30

2x + 4y = 12                 (add)

-----------------

12x = 42

x = \(\frac{42}{12}\) = \(\frac{7}{2}\)

2x + 4y = 12         (subsitute)

2(\(\frac{7}{2}\)) + 4y = 12

7 + 4y = 12

4y = 5

y = \(\frac{5}{4}\)

answer

212 - 147 = () times 3.75

147 × 4.25 =

add them together and that's the total amount

Answer:

32.804

Expanded forms can be written like a sentence or stacked for readability as they are here.

Expanded Notation Form:

 30  

+ 2  

+   0.8

+   0.00

+   0.004

Expanded Factors Form:

 3 × 10  

+ 2 × 1  

+ 8 ×   0.1

+ 0 ×   0.01

+ 4 ×   0.001

Expanded Exponential Form:

3 × 101

+ 2 × 100

+ 8 × 10-1

+ 0 × 10-2

+ 4 × 10-3

Step-by-step explanation:

Step-by-step explanation:

70 to 85 % of his maximum

Maximum is estimated to be 220 - age  = 220 - 42 = 178

70% of this is 125

85 % is 89  151  

I believe I would go with the third choice  116-160 bpm

The rate at which the depth of the liquid is increasing when it reaches one-third of the height of the bowl is (7/3)π cm³/s.

To ascertain the rate at which the liquid's depth rises, let's find the derivative of the depth function with respect to time.

Let;

The rate of change of the volume of the liquid with respect to time is constant and equal to 7π cm³/s.

To determine the height of the bowl, we can evaluate the curve y = [-4 / (8 - x)] - 1 when x = 4 and y = 7.6 and then find the absolute difference between the values.

h = |[-4 / (8 - 4)] - 1 - [-4 / (8 - 7.6)] - 1|

Let's calculate the rate at which the depth rises when it reaches one-third of the bowl's height.

D = depth of bowl

Using this relationship from the question given;

D = (1/3) * h

In order to determine the rate at which D will change with respect to time, let's differentiate both sides of the equation.

dD/dt = (1/3) * dh/dt

Since dh/dt is the rate at which the depth of the liquid is changing, which is constant and equal to 7π cm³/s, we can substitute it into the equation:

dD/dt = (1/3) * (7π)

Simplifying, we have:

dD/dt = (7/3)π cm³/s

Learn more on rate of change of volume here;

https://brainly.com/question/22716418

#SPJ1

Answer:

O The ranges of g(x) and f(x) are the same, but their domains are not the same.

Step-by-step explanation:

The statement that best describes g(x) and f(x) is:

The domains of g(x) and f(x) are the same, but their ranges are not the same.

Option A is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The function g(x) is obtained by taking the parent function f(x) = ∛x and performing a series of transformations:

- shifting the graph horizontally 6 units to the left

- shifting it vertically 8 units downward.

Since the cube root function is defined for all real numbers, both g(x) and f(x) have the same domain, which is the set of all real numbers.

However, the transformations applied to f(x) change the shape of the graph and the range of the function.

In particular,

g(x) is shifted 8 units downward, so its range is shifted down by 8 units compared to the range of f(x).

Therefore,

The domains of g(x) and f(x) are the same, but their ranges are not the same.

Learn more about functions here:

https://brainly.com/question/28533782

#SPJ7

Answer:

Step-by-step explanation:

See attachment

Answer:

( -6, 6)

Step-by-step explanation:

Answer:

m= -1

y intercept= 1

y= - x + 1

Step-by-step explanation:

Answer: 436.8

Step-by-step explanation:

Problem Statement

The question asks us to solve the question given below:

Solution