Do the leading coefficient and degree of the polynomial functions affect the behavior of its graph?.

Answers

Answer 1

Yes, leading coefficient and degree of the polynomial functions can affect the behavior of its graph. Because of the positive leading coefficient, the graph ascends to the right. To ascertain the behavior, consider the function's degree and the sign of the leading coefficient.

Define leading coefficient.

The term with the greatest x power is the leading term in a polynomial function. The leading coefficient is the coefficient of the leading phrase.

Given,

Yes, leading coefficient and degree of the polynomial functions can affect the behavior of its graph.

The graph's final behavior is determined by a polynomial function's degree and leading coefficient. For very big or very small values, the leading coefficient is more important than the other function coefficients. The coefficient of the leading term is the leading coefficient in a polynomial. Because of the positive leading coefficient, the graph ascends to the right. To ascertain the behavior, consider the function's degree and the sign of the leading coefficient.

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Related Questions

Let there be two goods, L=2. Consider a finite number of Leontief consumers i with utility function u i

(x i
1

,x i
2

)=min{x i
1

,x i
2

} and initial endowments ω i

≫ 0 . Recall that for any price system p=(p 1
,p 2
)≫0, the demand of such a consumer satisfies x i
1

(p)=x i
2

(p)= p 1
+p 2
m i


= p 1
+p 2
pω i


. Use this information to show the following: Suppose the aggregate endowment ω=(ω 1
,ω 2
) of this economy satisfies ω 1
>ω 2
and that p=(p 1
,p 2
) is an equilibrium (market clearing) price system. Then p 1
=0 and p 2
>0.

Answers

We are given an economy with two goods and Leontief consumers who have utility functions that depend on the minimum of the two goods. The initial endowments of the consumers are positive, and we are assuming that the aggregate endowment of the economy has more of the first good than the second. If a price system p=(p1,p2) is an equilibrium with market clearing, we need to show that p1=0 and p2>0.

We start by considering the demand function for a Leontief consumer, which is given by xi1(p) = xi2(p) = (p1 + p2)mi/pi, where mi represents the initial endowment of consumer i and pi represents the price of good i.

Since the aggregate endowment ω=(ω1,ω2) of the economy satisfies ω1 > ω2, we know that the total supply of the first good is greater than the total supply of the second good.

Now, if p1 > 0, then for any positive value of p2, the demand for the second good xi2(p) will be positive for all consumers. This implies that the total demand for the second good will be greater than the total supply, leading to a market imbalance.

To achieve market clearing, where total demand equals total supply, we must have p1 = 0. This is because if p1 = 0, the demand for the first good xi1(p) will be zero for all consumers, and the total supply of the first good will match the total supply. Additionally, p2 must be positive to ensure positive demand for the second good.

Therefore, we have shown that in an equilibrium price system with market clearing, p1 = 0 and p2 > 0, given the initial endowment condition ω1 > ω2.

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Arjun and Mei each improved their yards by planting rose bushes and ivy. They bought their supplies from the same store. Arjun spent $198 on 7 rose bushes and 13 pots of ivy. Mei spent $204 on 14 rose bushes and 10 pots of ivy. what is the cost of one rose bush and the cost of one pot of ivy?

Answers

The cost of one rose bush is $5 and the cost of one pot of ivy is $ 14.

What is Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

Arjun spent $198 on 7 rose bushes and 13 pots of ivy.

Mei spent $204 on 14 rose bushes and 10 pots of ivy.

let the cost of rose bushes be x and cost of ivy pots be y.

So, 7x+ 12y = 198.....(1)

14x+ 10y = 204........(2)

Now solving above equation

x = 234/49

  ≈ 4.77551

y = 96/7

≈ 13.714286

Hence, cost of one rose bush is $5 and the cost of one pot of ivy is $ 14.

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Here are five sums. Use the distributive property to write each sum as a product with two factors. 2+7 5−10 −2^2 +++ 2−1/2

Answers

Question:

Here are five sums. Use the distributive property to write each sum as a product with two factors.

\((a)\ 2a + 7a\)      \((b)\ 5z - 10\)    \((c)\ c - c^2\)      \((d)\ r + r+ r+ r\)    \((e)\ 2x - \frac{1}{2}\)

Answer:

\((a)\ 2a + 7a = 9a\)

\((b)\ 5z - 10 = 5(z - 2)\)

\((c)\ c - c^2 = c(1 - c)\)

\((d)\ r + r + r + r = 4r\)

\((e)\ 2x - \frac{1}{2} = \frac{1}{2}(4x - 1)\)

Step-by-step explanation:

Required

Apply distributive property

\((a)\ 2a + 7a\)      

Apply distributive property [Factor out a]

\(2a + 7a = a(2 + 7)\)

\(2a + 7a = a(9)\)

Open bracket

\(2a + 7a = a*9\)

\(2a + 7a = 9a\)

\((b)\ 5z - 10\)    

Express 10 as 5 * 2

\(5z - 10 = 5z - 5*2\)

Apply distributive property [Factor out 5]

\(5z - 10 = 5(z - 2)\)

\((c)\ c - c^2\)      

Express c as c * c

\(c - c^2 = c - c * c\)

Apply distributive property [Factor out c]

\(c - c^2 = c(1 - c)\)

\((d)\ r + r+ r+ r\)    

Express r as r * 1

\(r + r + r + r = r * 1 + r * 1 + r * 1 + r *1\)

Apply distributive property [Factor out 1]

\(r + r + r + r = r(1+1+1+1)\)

\(r + r + r + r = r * 4\)

\(r + r + r + r = 4r\)

\((e)\ 2x - \frac{1}{2}\)

Express 2x as 4x/2

\(2x - \frac{1}{2} = \frac{4x}{2} - \frac{1}{2}\)

Apply distributive property [Factor out 1/2]

\(2x - \frac{1}{2} = \frac{1}{2}(4x - 1)\)

Juan needs to mail 4 party invitations to his friends. He needs three stamp for each invitation. He already has 5 stamps. How many more stamps does he need?

Answers

Answer:

7 stamps

Step-by-step explanation:

4 invitations x three stamps = 12 stamps needed

12 stamps-5 stamps = 7 stamps

Answer: 7

Step-by-step explanation:4x3=12,12-5=7

Hii can someone who is really good at math please help me with these 2 math questions. I'm struggling with them!!

Hii can someone who is really good at math please help me with these 2 math questions. I'm struggling
Hii can someone who is really good at math please help me with these 2 math questions. I'm struggling

Answers

3.3, -7 THATS the answers I think

How much 5000000 won to usd?

Answers

Answer:

3,975.16 United States Dollar

Step-by-step explanation:

open-ended - use pencil and paper. Write a situation that involves the integers - 161 and 1,470. then answer the question below .which situation(s) could be represented by - 161? select all that apply.□A. a bird 161 ft above the ground □B. Earning $161 at your summer job □C. skiing 161 ft down a mountain □D. spending $spending $161 on vacation

Answers

Solution:

If we choose a usual coordinate axis, an object going down would be traveling a negative distance, so a possible answer would be:

C. skiing 161 ft down a mountain.

On the other hand, An expense of money involves a waste of money, which is negative. So another possible answer would be:

D. spending $spending $161 on vacation.

Then, we can conclude that the correct answer would be:

C. skiing 161 ft down a mountain.

D. spending $spending $161 on vacation.

Solve the equation 8x + 7 = 6x + 15. What is the value of x?

Answers

the value of x is 4

to show your work:
8x + 7 = 6x + 15
- 7 - 7
8x = 6x + 8
-6x -6x
2x=8
divid by 2 and it’s x = 4 :)
the value of x is x= 4

Formalize the following in terms of atomic propositions r, b, and w, first making clear how they correspond to the
English text. (a) Berries are ripe along the path, but rabbits have not been seen in the area.
(b) Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.
(c) If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.
(d) It is not safe to walk along the path, but rabbits have not been seen in the area and the berries along the path are ripe.
e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to
pave been seen in the area.
Walking is not safe on the path whenever rabbits have been seen in the area and berries are ripe along the path.

Answers

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path. This is formalized by using the →(if-then) and ∧(logical and) operators.

Given information and corresponding atomic propositions:

We need to formalize the given statements in terms of atomic propositions r, b, and w, which are defined as follows:

r: Rabbits have been seen in the area.

b: Berries are ripe along the path.

w: Walking on the path is safe.

Now, let us formalize each of the given statements in terms of these atomic propositions:

a) Berries are ripe along the path, but rabbits have not been seen in the area.

b: Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.

c: If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.

d: It is not safe to walk along the path, but rabbits have not been seen in the area, and the berries along the path are ripe.

e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path.

The formalizations in terms of atomic propositions are:

a) b ∧ ¬r.b) ¬r ∧ w ∧

b.c) (b → w) ∧ (¬r → w).

d) ¬w ∧ ¬r ∧

b.e) (¬r ∧ ¬b) → w.b ∧

Berries are ripe along the path, but rabbits have not been seen in the area.

This is formalized by using the ∧(logical and) operator.

(¬r ∧ ¬b) → w: It means For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

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if a circle has a radius of 7/4 cm, what is the diameter?

Answers

Answer:

The diameter of the circle is 7/2.

Step-by-step explanation:

⭐What is the radius of a circle?

the distance from a point on the circumference of the circle to the center of the circle

What is the diameter of a circle?

the distance from a point on the circumference of the circle to another point on the circumference of the circlethe diameter must cut through the center of the circlethe diameter is double the amount of the radius

Thus, the diameter of said circle is twice the radius of said circle.

diameter = 2(radius)

diameter = 2(7/4)                   . . . . substitute known values

diameter = 14/4                      . . . . multiply the numerator & denominator

diameter = 7/2                       . . . . simplify

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HELP ASAP Of the 28 golf balls, 5/7 are white. How many golf balls are white?

Answers

Answer:

20 , Hope it Helps

Step-by-step explanation:

have a good day

5/7 of 28.

The answer is 20.

28 times 0.7 is roughly 19.6, rounded off, that’s about 20.

What is the function of rational root theorem?

Answers

A theorem which is used to find the rational solutions of a polynomial equation is known as the rational root theorem.

A polynomial expression is given and after solving them we get the two values known as the roots of the function.

These are also known as the zeros of polynomial as after putting these values in the equation we get the result as 0 .

We should use the rational root theorem only when the value of coefficients are small.

The theorem states that each rational solution x = p ⁄ q, when on simplified satisfies the below mentioned points,

p is an integer factor of the constant term a0, and

q is an integer factor of the leading coefficient an.

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True or false: It is common to denote random variables by upper-case letters and particular values of the random variables by the corresponding lower-case letters.

Answers

Hmmm... uhh true? I think sorry I don't know either:(

Answer:

True

Step-by-step explanation:

Find A Vector Normal To The Plane With Equation a. 9x - 4y - 112 = 2 b. . X-Z=0

Answers

a. To find a vector normal to the plane with the equation 9x - 4y - 112 = 2, we can take the coefficients of x, y, and z as the components of the normal vector. Therefore, a vector normal to the plane is \(\(\mathbf{N} = \begin{bmatrix} 9 \\ -4 \\ 0 \end{bmatrix}\)\).

b. To find a vector normal to the plane with the equation x - z = 0, we can take the coefficients of x, y, and z as the components of the normal vector. Therefore, a vector normal to the plane is \(\(\mathbf{N} = \begin{bmatrix} 1 \\ 0 \\ -1 \end{bmatrix}\)\).

In both cases, the vector normal to the plane represents the direction perpendicular to the plane.

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Find the midpoint of the segment with the given endpoints (-2, 10) and ( - 10,- 12).The midpoint of the segment is(Simplify your answer. Type an ordered pair.)

Answers

Given:

The given endpoints are ( -2,10) and (-10, -12).

Required:

We need to find the midpoint of te given endpoints.

Explanation:

Consider the formua to find the midpoint.

\(midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\)

Consider the points ( -2,10) and (-10, -12).

\(Substitute\text{ }x_1=-2,x_2=-10,y_1=10,\text{ and }y_2=-12\text{ in the formula,}\)

\(midpoint=(\frac{-2+(-10)}{2},\frac{10+(-12)}{2})\)

\(midpoint=(\frac{-2-10}{2},\frac{10-12}{2})\)

\(midpoint=(\frac{-12}{2},\frac{-2}{2})\)

\(midpoint=(-6,-1)\)

Final answer:

\(midpoint=(-6,-1)\)

Set up and solve an equation to find the measure of each missing angle.

Set up and solve an equation to find the measure of each missing angle.

Answers

Answer:

<A = 76°

<B = 63°

<C = 41°

Plug in the value of x

<C = 34 + 7

<C = 41°

Step-by-step explanation:

\( 63 + (2x + 8) + (x + 7) = 180 \) (sum of ∆)

Solve for x

\( 63 + 2x + 8 + x + 7 = 180 \)

Add like terms

\( 78 + 3x = 180 \)

Subtract 78 from each side

\( 78 + 3x - 78 = 180 - 78 \)

\( 3x = 102 \)

Divide both sides by 3

x = 34

<A = 2x + 8

Plug in the value of x

<A = 2(34) + 8 = 76°

<B = 63°

<C = x + 7

Plug in the value of x

<C = 34 + 7

<C = 41°

A rectangular piece of iron has sides with lengths of 7.08 × 10–3 m, 2.18 × 10–2 m, and 4.51 × 10–3 m. what is the volume of the piece of iron? 6.96 × 10–7 m3 6.96 × 107 m3 6.96 × 10–18 m3

Answers

The volume of the rectangular piece with sides of lengths of 7.08 × 10–3 m, 2.18 × 10–2 m, and 4.51 × 10–3m is 6. 96 × 10^ -7 m

What is volume?

Volume is defined as the amount of space or capacity occupied by a three-dimensional shape.

It is represented in cubic units.

How to determine the volume of a rectangle

Formula:

Volume, V = length × breadth × height

Given the values;

7. 08 × 10 ^-3m , 2.18 × 10^ -2m and 4. 51 × 10^-3m

Multiply all the lengths

Volume = 7. 08 × 10 ^-3 × 2.18 × 10^ -2 × 4. 51 × 10^-3

= 69.6 × 10^-8

= 6. 96 × 10^ -7 m

Therefore, the volume of the rectangular piece is 6. 96 × 10^ -7 m

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Answer:

A

Step-by-step explanation:

trust

what is the first term, common difference, and 16th term

what is the first term, common difference, and 16th term

Answers

Answer:

The 1st term is -67

Step-by-step explanation:

I. When Sn = \(\frac{n}{2}\)(\(a_{1} + a_{n}\))

   If  Sn = 124, n = 8 and \(a_{n}\) = 98

                124 = 8/2(a + 98)

                124 = 4(a + 98)

                124 = 4a + 392

                124 - 392 = 4a

                -268/4 = a

                -67 = \(a_{1}\)

Hope that help :D

if f and g are polynomials of degree n then f g is also a polynomial of degree at most n. True or false?

Answers

False. If f and g are polynomials of degree n, then f * g is a polynomial of degree at most 2n, not necessarily at most n.

When two polynomials f and g are multiplied, the degree of the resulting polynomial is equal to the sum of the degrees of f and g. In other words, if f has a degree of n and g has a degree of m, then f * g will have a degree of n + m.

Considering that f and g are both polynomials of degree n, we can rewrite them as f(x) = a_nx^n + a_(n-1)x^(n-1) + ... + a_1x + a_0 and g(x) = b_nx^n + b_(n-1)x^(n-1) + ... + b_1x + b_0, where a_i and b_i are coefficients.

Now, when we multiply f and g, we get f(x) * g(x) = (a_nx^n + a_(n-1)x^(n-1) + ... + a_1x + a_0) * (b_nx^n + b_(n-1)x^(n-1) + ... + b_1x + b_0).

Expanding this expression results in a polynomial of degree 2n, as the highest degree term will be (a_n * b_n) * x^(2n).

Therefore, the statement "f * g is also a polynomial of degree at most n" is false. The degree of the product of two polynomials is the sum of their individual degrees, not necessarily limited to the maximum degree among them.

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What is mean, median and mode?


4 6 7 7 9 11 13 14 15


A. Mean = 9.56 Median = 11 Mode = 7


B. Mean = 9 Median = 86 Mode = 7


C. Mean = 9.56 Median = 9 Mode = 7


D. Mean = 10.75 Median = 9 Mode = 7​

Answers

Answer: A. Mean = 9.56, Median = 11, Mode = 7

Step-by-step explanation:

The mean, median and the mode for the given data is 9.56, 9, and 7 respectively.

How to find the mean, median, and mode of the data?

Given data below:

4, 6, 7, 7, 9, 11, 13, 14, 15.

In order to find the mean, it can be calculated by dividing a sum of all the data points with the number of data points in the data set.

The formula is:

\(\bar{M}=\dfrac{\sum M}{N}\)

\(\bar{M}=\dfrac{4+6+7+7+9+11+13+14+15}{9}\)

\(\bar{M}=\dfrac{86}{9}\)

\(\bar{M}=9.56\)

Next, we will find the median.

In order to find the median, we got to place the numbers in value order and find the middle.

So,

\(\text{Median}=9\)

Lastly, we will find the mode.

To find the mode, order the numbers lowest to highest and see which number appears the most often.

So,

\(\text{Mode}=7\)

Thus, the mean, median and the mode for the given data is 9.56, 9, and 7 respectively.

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Write an equation to match this graph.

Write an equation to match this graph.

Answers

Answer:

y = x + 7

Step-by-step explanation:

Pick 2 points on the line to calculate the slope, m:  (3, 10) and (5, 12)

m = Δy/Δx = (12 - 10) / (5 - 3) = 2/2 = 1

Use the point-slope equation and the point (3, 10):   (y - y1) = m(x - x1)

(y - 10) = 1(x - 3)

y - 10 = x - 3

y = x - 3 + 10

y = x + 7

a card is drawn off a 52-card deck. let a be the event ""the card is a heart."" let b be the event ""the card is a queen."" are these two events independent or dependent?

Answers

Therefore, the correct answer is that these two events are dependent.

The given events are dependent events. To check whether the two events are dependent or independent, check the following case.

If A and B are independent events, then the conditional probability of A given B is:

P(A|B) = P(A)If A and B are dependent events, then the conditional probability of A given B is:

P(A|B) = P(A and B) / P(B)Now let's solve the problem stated in the question:

A card is drawn off a 52-card deck. Let A be the event "The card is a heart" and let B be the event "The card is a queen".

Now, let us calculate the P(A and B):

We know that,

P(B) = 4/52 = 1/13. (because there are 4 queens in a deck of cards)

For P(A and B), we need to find the probability of drawing a Queen of Hearts. That is,

P(A and B) = 1/52. (Because there is only one queen of hearts in the deck)

Now let us calculate the P(A|B):P(A|B) = P(A and B) / P(B) = (1/52) / (1/13) = 1/4 ≠ P(A)Therefore, P(A|B) ≠ P(A).

This means that events A and B are dependent events.

Therefore, the correct answer is that these two events are dependent.

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can you calculate the percent elongation of materials based only on the information given in fig. 2.6? explain.

Answers

Fig. 2.6 alone does not provide sufficient information to calculate the percent elongation of materials. Percent elongation is a measure of the increase in length of a material after it has been subjected to a tensile load, and is calculated by dividing the increase in length by the original length and multiplying by 100.

Fig. 2.6 shows stress-strain curves for different materials, which provide information about the relationship between stress and strain for those materials. While the curve shape can provide some insight into the behavior of the material under load, it does not provide information about the original length or the change in length of the material, which are necessary to calculate percent elongation.

In order to calculate percent elongation, additional information about the material's original length and the change in length after a tensile load is required. This information can be obtained through laboratory testing or from material specifications provided by the manufacturer.

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can someone answer this for me​

can someone answer this for me

Answers

Answer:

Step-by-step explanation:

6x^2 - x + 3 - 5x^2 - 10x + 1

x^2 - 11x + 4

how do you check your result after factoring a polynomial?

Answers

The original polynomial, \(x^2 + 7x + 12\), it can be seen that the two are the same, thus confirming that the polynomial was correctly factored.

To check the result after factoring a polynomial, one can use the FOIL method to ensure that the factored polynomial is equivalent to the original polynomial. The FOIL method stands for First, Outer, Inner, Last, and is used to multiply two binomials. To check the result, one would use the FOIL method to multiply the factored polynomial, and compare the result to the original polynomial. For example, let’s consider the polynomial\(x^2+7x+12\). After factoring, this can be written as (x+4)(x+3). To check the result, one would multiply the two binomials together, (x+4)\((x+3) = x^2 + 3x + 4x + 12\). Comparing this to the original polynomial, \(x^2 + 7x + 12\), it can be seen that the two are the same, thus confirming that the polynomial was correctly factored.

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Evaluate the double integrals by iteration. whre B is the region 0 ≤ ≤ 1, ² ≤ y ≤= ILževaA

Answers

The value of the double integral \(\int\int_B \frac{x}{y} e^ydA\) where, B is the region 0 ≤ x ≤ 1, x² ≤ y ≤ x by using iteration, is zero.

The given double integral is:

\(\int\int_B \frac{x}{y} e^ydA\)

where B is the region defined by 0 ≤ x ≤ 1 and x² ≤ y ≤ x.

To evaluate this double integral by iteration, we first need to set up the order of integration.

Since the limits of y depend on the value of x, we will integrate with respect to y first and then with respect to x.

Let's start by integrating with respect to y.

The limits of integration for y are x² ≤ y ≤ x.

Therefore, the inner integral becomes:

∫_(x²)^(x) (x/y)\(e^y\) dy

The value of the given double integral is 0.

To solve this integral, we can simplify the integrand:

(x/y)\(e^y\) = x\(e^y\)/y

Using the property of exponentials, we can rewrite this as:

x\(e^y\)/y = x(\(e^y\)/y)

Integrating this expression with respect to y, we get:

x∫_(x²)^(x) (\(e^y\)/y) dy

Next, we integrate this expression with respect to x.

The limits of integration for x are 0 ≤ x ≤ 1.

Therefore, the outer integral becomes:

∫_(0)^(1) [x∫_(x²)^(x) (\(e^y\)/y) dy] dx

Now we can evaluate this double integral by performing the integration in two steps: first with respect to y and then with respect to x.

To evaluate the given double integral, we will perform the integration in two steps: integrating with respect to y and then integrating with respect to x.

First, let's integrate with respect to y:

∫_(x²)^(x) (\(e^y\)/y) dy

To evaluate this integral, we can use the natural logarithm function.

The antiderivative of \(e^y\)/y is ln|y|.

Therefore, the inner integral becomes:

[x ln|y|]_(x²)^(x)

Now, we substitute the limits of integration:

[x ln|x| - x ln|x²|]

Simplifying this expression, we have:

[x ln|x| - 2x ln|x|]

Next, we integrate this expression with respect to x.

The limits of integration for x are 0 ≤ x ≤ 1.

Therefore, the outer integral becomes:

∫_(0)^(1) [x ln|x| - 2x ln|x|] dx

Integrating term by term, we get:

[1/2 x² ln|x| - 2/3 x³ ln|x|]_(0)^(1)

Substituting the limits of integration, we have:

(1/2 - 2/3) ln|1| - (0 - 0)

Simplifying further, we obtain:

(-1/6) ln(1)

Since ln(1) = 0, the final result is:

0

Therefore, the value of the given double integral is 0.

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The complete question is:

Evaluate the double integrals by iteration.

\(\int\int_B \frac{x}{y} e^ydA\)

where, B is the region 0 ≤ x ≤ 1, x² ≤ y ≤ x

simplify:

3x + 42 - 34​

Answers

Answer:

The answer is 3x + 8.

Step-by-step explanation:

1) Collect like terms.

\(3x + (42 - 34)\)

2) Simplify.

\(3x + 8\)

Hence, the answer is 3x + 8.

sin² x + cos²x = 1

Which Trigonometric Identity is given above?

- Pythagorean Identity

- Lagrange's Trigonometric Identity

- Angle Sum and Difference Identity

- Tangent Identity

Answers

The  Trigonometric Identity sin² x + cos²x = 1 is: A. Pythagorean Identity.

What is Pythagorean Identity?

The Pythagorean Identity which  tend to asserts that for every angle x, the sum of the squares of the sine and cosine of x is equal to one  is known as or called a  trigonometric identity.

The  Pythagorean identity can be expressed as:

sin² x + cos² x = 1

This identity is crucial to understanding trigonometry and tend to have several uses in numerous branches of science and engineering.

Therefore the correct option is A.

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6 11/12
- 3 9/12

A. 3 2/12
B. 9 20/12
C. 3 2/24
D. 2 2/12

Answers

Answer:

A) 3 2/12

Step-by-step explanation:

6 11/12 - 3 9/12 = 3 2/12

How would I solve this? I tried and I got a reallly crazy number... I think I messed up somewhere. The question is... Jack and Mark work together on a job, but not equal hours. Mark gets paid $11 per hour and Jack gets paid $10 per hour. Together they worked 58 hours and earn a total of $601. How many hours did each one work?

I made these equations.
m+j=58
11m+10j
The first one I rearranged to m=58-j.

Answers

37 x 10 = 370
21 x 11 = 231

Mark worked 21 Hours, Jack worked 37 Hours.

Answer:

Jack earns $37

Mark earns $21

Step-by-step explanation:

m + j = 58

11m + 10j = 601

j = 58 - m

11m + 10(58 - m) = 601

11m + 580 - 10m = 601

1m = 601 - 580

m = 21

j = 58 - m

j = 58 - 21

j = 37

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