.Distribute and combine like terms: −4(7r + 7)

The function T(n) in terms of the number of operations is:

T(n) = 2n^3 + 3n^2 + 2n + 1 and the asymptotic complexity of the matrix multiplication algorithm is O(n^3).

To analyze the provided pseudo code for matrix multiplication and determine the function T(n) in terms of the number of operations, we need to examine the code and count the number of operations performed.

The pseudo code for matrix multiplication may look something like this:

```

MatrixMultiplication(A, B):

   n = size of matrix A

   C = empty matrix of size n x n

   for i = 1 to n do:

       for j = 1 to n do:

           sum = 0

           for k = 1 to n do:

               sum = sum + A[i][k] * B[k][j]

           C[i][j] = sum

   return C

```

Let's break down the number of operations step by step:

1. Assigning the size of matrix A to variable n: 1 operation

2. Initializing an empty matrix C of size n x n: n^2 operations (for creating n x n elements)

3. Outer loop: for i = 1 to n

- Incrementing i: n operations  

- Inner loop: for j = 1 to n

- Incrementing j: n^2 operations (since it is nested inside the outer loop)

- Initializing sum to 0: n^2 operations

- Innermost loop: for k = 1 to n

- Incrementing k: n^3 operations (since it is nested inside both the outer and inner loops)

- Performing the multiplication and addition: n^3 operations

- Assigning the result to C[i][j]: n^2 operations

- Assigning the value of sum to C[i][j]: n^2 operations

Total operations:

1 + n^2 + n + n^2 + n^3 + n^3 + n^2 + n^2 = 2n^3 + 3n^2 + 2n + 1

Therefore, the function T(n) in terms of the number of operations is:

T(n) = 2n^3 + 3n^2 + 2n + 1

To determine the asymptotic (big O) complexity of the algorithm, we focus on the dominant term as n approaches infinity.

In this case, the dominant term is 2n^3. Hence, the asymptotic complexity of the matrix multiplication algorithm is O(n^3).

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Answer:

for x=5, x=4 , x=2

Step-by-step explanation:

zero points, the x values that make this formula to be zero.

5-5=0

4-4=0

2-2=0

these values satisfied

Answer: y = 14.50x + 2.99

Step-by-step explanation:

The equation is y = mx + b

y is the total cost and x is the number of shirt

We know each shirt is $14.50, and she bought x shirts, so 14.50 is the slope

The 2.99 shipping fee is the y-intercept

So our equation is

y = 14.50x + 2.99

Answer:

2+4K

Step-by-step explanation:

distribute the 2

2(1+2k)

2(1)+2(2k)

2+4K

Hopes this helps please mark brainliest

Answer:

a) y = 2x + 12. b) y = -1/2 x  -1/2.

Step-by-step explanation:

a) parallel to will have same gradient, ie gradient of 2.

y - y1 = m(x - x1)

y1 is y-coordinate of point, x1 is x-coordinate of point, m is gradient.

y - 2 = 2(x - -5) = 2 (x + 5) = 2x + 10

y = 2x +10 + 2

y = 2x + 12

b) gradient of perpendicular = -1/m = -1/2.

y - 2 = -1/2 (x - -5) = -1/2 (x + 5) = -1/2 x - 5/2

y = -1/2x  -5/2 + 2

y = -1/2 x  -1/2

The probability that the total of the two numbers is more than 32 when two of the five cards are chosen at random is 3/10.

There are 5 number cards: 19, 13, 10, 14, and 22. If 2 of the 5 cards are picked at random, what is the probability that the total of the two numbers is more than 32?

To calculate the probability that the total of the two numbers is more than 32 when two of the five cards are chosen at random, we can use the combination formula. This is as follows:

\($$\frac{\text{Number of successful outcomes}}{\text{Number of possible outcomes}}$$\)

Let's first identify the possible outcomes. We must choose 2 numbers from 5 cards, so we can use combinations to do so:

\($$\text{Number of possible outcomes} = \binom{5}{2} = 10$$\)

We can now calculate the number of successful outcomes, which is the number of ways that the sum of the two chosen numbers is greater than 32. We can start by finding the pairs of numbers that sum to 33 or more:

\($$19 + 14 = 33$$\)

\($$22 + 13 = 35$$\)

\($$22 + 19 = 41$$\)

Therefore, there are 3 successful outcomes. Thus, the probability that the total of the two numbers is more than 32 is:

\(\frac{Number of successful outcomes}{{Number of possible outcomes}}}\)\(=\frac{3}{10}$$\)

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The chances of your bar having the golden ticket are still 80%.

The chances of your bar having the golden ticket in it are still 80%.

Even though the other students have opened their bars and found no golden ticket, the probability of the golden ticket being in the remaining bar has not changed.

The fact that the other students opened their bars and found nothing does not affect the probability of your bar containing the golden ticket.

Therefore, the chances of your bar having the golden ticket are still 80%.

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Answer:

16 pies were neither apple nor peach.

Step-by-step explanation:

8/10, or 4/5 of the 80 apple pies were either apple or peach, which 4/5 of 80 is 64. The remaining pies will be neither apple nor peach. 80 - 64 = 16.

Answer:

Q9, n=8 and Q10, x=4

Step-by-step explanation:

2(5-7n)-4=-106

10-14n-4=-106

-14n+6=-106

-14n=-112

n=8

-8(1-4x)-5=115

-8+32x-5=115

32x-13=115

32x=128

x=4

It is repeated to double the previous number.

Answer:

20 square feet

Step-by-step explanation:

The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area

Step 1

We find the Length and Width of the deck

Perimeter of a rectangle = 2L + 2W

The length of a rectangular deck is five times it's width

W = Width

L = Length = 5W

P = 24 feet

Perimeter = 2(5W) + 2W

24 = 10W + 2W

24 = 12 W

W = 24/12

W = 2 feet

Solving for L

L = 5W

L = 5 × 2 feet

L = 10 feet

Step 2

We find the area of the deck

Area of the deck(Rectangle) = Length × Width

= 10 feet × 2 feet

= 20 square feet

Answer:

C

Step-by-step explanation:

Firstly, the triangle we are considering is triangle NOM

Now, the angle we are considering on this triangle is the angle O

mathematically, the sine of an angle is the ratio of the length of the opposite to the length of the hypotenuse of the angle

In this case, the hypotenuse of the angle is the sum of the squares of the two other sides according to Pythagoras’ theorem

Thus, the hypotenuse of the NOM triangle will be;

square root of 3^2 + 4^2 = square root of 25 = 5

The opposite of the angle we are considering is angle M which is 3

So, the sine of the angle we are considering is 3/5

the probability that at least flights are on time is

P(7) + P(8) + P(9) + P(10)

To calculate the probability that at least a certain number of flights are on time using the binomial distribution, we need the probability of success (p), the number of trials (n), and the desired number of successful trials.

Let's assume we have the following information:

Probability of a flight being on time: p = 0.8 (80%)

Number of flights: n = 10

To find the probability that at least a certain number of flights are on time, we need to sum the probabilities of the desired number of successful trials and all higher numbers of successful trials.

Let's say we want to find the probability of at least 7 flights being on time.

P(at least 7 flights on time) = P(7) + P(8) + P(9) + P(10)

Using the binomial probability formula: P(x) = C(n, x) * p^x * (1-p)^(n-x)

where C(n, x) represents the number of combinations of n items taken x at a time.

Calculating the probabilities: P(7) = C(10, 7) * (0.8)^7 * (0.2)^(10-7) P(8) = C(10, 8) * (0.8)^8 * (0.2)^(10-8) P(9) = C(10, 9) * (0.8)^9 * (0.2)^(10-9) P(10) = C(10, 10) * (0.8)^10 * (0.2)^(10-10)

Finally, we sum up these probabilities to get the probability of at least 7 flights being on time.

P(at least 7 flights on time) = P(7) + P(8) + P(9) + P(10)

Performing the calculations will give us the specific probabilities and the final probability.

Complete Question :- According to an​ airline, flights on a certain route are on time 75​% of the time. Suppose 24 flights are randomly selected and the number of​ on-time flights is recorded.

​(a) Explain why this is a binomial experiment.

​(b) Find and interpret the probability that exactly 14 flights are on time.

​(c) Find and interpret the probability that fewer than 14 flights are on time.

​(d) Find and interpret the probability that at least 14 flights are on time.

​(e) Find and interpret the probability that between 12 and 14 flights, inclusive, are on time.

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Answer: \(2\sqrt{37}+2\sqrt{29}+8\sqrt{2}\ \text{units}\)

Step-by-step explanation:

Given

The coordinates of the triangle are \(K(-6,-2),L(6,-4),M(2,6)\)

Distance between the two points is given by the distance formula

\(d=\sqrt{\left( x_2-x_1\right)^2+\left( y_2-y_1\right)^2}\)

Distance between K and L

\(KL=\sqrt{\left( 6+6\right)^2+\left( -4+2\right)^2}\\KL=\sqrt{\left( 12\right)^2+\left( -2\right)^2}\\KL=\sqrt{144+4}\\KL=\sqrt{148}\ \text{units}\)

For L and M

\(LM=\sqrt{\left( 2-6\right)^2+\left( 6+4\right)^2}\\LM=\sqrt{\left( -4\right)^2+\left( 10\right)^2}\\LM=\sqrt{16+100}\\LM=\sqrt{116}\)

For K and M

\(KM=\sqrt{\left( 8\right)^2+\left( 8\right)^2}\\KM=\sqrt{64+64}\\KM=8\sqrt{2}\ \text{units}\)

The perimeter of the triangle is

\(\Rightarrow \sqrt{148}+\sqrt{116}+8\sqrt{2}\\\\\Rightarrow 2\sqrt{37}+2\sqrt{29}+8\sqrt{2}\ \text{units}\)

What are you trying to say brother

Perimeter of the polygon ABCDEF is 24 units .

Given, vertices of polygons: A(1, –3), B(–1, –3), C(–1, –1), D(–4, –1), E(–4, 5) and F(1, 5).

Perimeter of the polygon is calculated by adding all the side lengths of the polygon .

According to distance formula,

\(d = \sqrt{ (x_2 - x_1)^2 + (y_2 - y_1)^2}\)

Side AB :

\(d = \sqrt{ (-1 - 1)^2 + (-3 - (-3))^2}\\d = \sqrt{4 + 0}\\d = 2 units\)

Side BC :

\(d = \sqrt{ (-1 - (-1))^2 + (-1 - (-3))^2}\\d = \sqrt{0 + 4}\\d = 2 units\)

Side CD :

\(d = \sqrt{ (-4 - (-1))^2 + (-1 - (-1))^2}\\d = \sqrt{9 + 0}\\d = 3 units\)

Side DE :

\(d = \sqrt{ (-4 - (-4))^2 + (5 - (1))^2}\\d = \sqrt{0 + 16}\\d = 4 units\)

Side EF :

\(d = \sqrt{ (1 - (-4))^2 + (5 - (5))^2}\\d = \sqrt{25 + 0}\\d = 5 units\)

Side FA:

\(d = \sqrt{ (1 - (1))^2 + (5 - (-3))^2}\\d = \sqrt{0 + 64}\\d = 8 units\)

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

Perimeter of the polygon = 2 + 2 + 3 + 4 + 5 + 8

Perimeter of the polygon = 24 units

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Decoding Forecast starting at 17:00Z:

Wind:

24014G23KT

Visibility:

5 statute miles

Weather:

Light rain showers

Clouds:

Overcast at 1500 feet

Incomplete report.

The decoded report is:

Location:

KJAX (Jacksonville International Airport)

Date/Time: 10th at 23:20Z

Wind:

00000KT

Visibility:

More than 6 statute miles

Clouds:

Scattered at 3500 feet

Forecast starting at 11:00Z:

Wind:

00000KT

Visibility:

5 statute miles

Weather:

Mist

Clouds:

Broken at 1000 feet, Broken at 2000 feet

Forecast starting at 06:00Z:

Wind:

16003KT

Visibility:

2 statute miles

Weather:

Mist

Clouds:

Broken at 500 feet, Overcast at 1000 feet

Temporary condition between 08:00Z and 12:00Z:

Visibility:

1 statute mile

Weather:

Mist

Clouds:

Overcast at 300 feet

Forecast starting at 14:00Z:

Wind:

20010G18KT

Visibility:

More than 6 statute miles

Weather:

Vicinity showers

Clouds:

Broken at 1500 feet, Overcast at 2500 feet

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Let's solve your inequality step-by-step.

x+25>50

Step 1: Subtract 25 from both sides.

x+25−25>50−25

x>25

Answer:

x>25

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Answer:   x < 12

-------------------------------------------------------------------------------------------------------

Answer:

[-3/2, infinity)

Step-by-step explanation:

The zeros of the polynomial P(x) = x³ + 7x² - x - 7  is  1 , - 1 , - 7 .

In algebraic expressions, exponents may have rational values. A polynomial, on the other hand, is an algebraic assertion with a whole number exponent on any variable. The places where a polynomial turns 0 are referred to as its zeros.

P(x) = x³ + 7x² - x - 7

Now we have to find one zero of given polynomial.

By hit and trial, we get

P(-7) = (-7)³ + 7 (-7)² - (-7) - 7

        = 0

Hence we get one zero = -7

So, -7 is the roots of the equation.

Now, by factorisation :

   P(x) = x³ + 7x² - x - 7

           = x² ( x+7 ) - 1 ( x+3 )

            = (x² - 1) ( x+7 )

            = ( x-1 )( x+1 )( x+7)

Hence the zeros of the polynomial is 1 , - 1 , - 7.

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All the real zeros of the given polynomial are integers. Find the zeros. (Enter your answers as a comma-separated list. Enter all answers including repetitions.)

P(x) = x3 + 7x2 − x − 7

Answer:

the answer should be c my one wasc

Using Stokes’ Theorem to evaluate ∫ ⃑∙⃑ ,The value of ∫ ⃑∙⃑ is π.

Let S be the part of the surface z=y² that lies within the cylinder x²+y²=2, with upward orientation. Use Stoke 's theorem to evaluate ∫(C) F·dr, where F(x,y,z)=⟨-2yz,y,3x⟩ and C is the boundary curve of S.

Stoke's theorem states that the line integral of a vector field around a closed curve is equal to the surface integral of the curl of the vector field over the surface bounded by the curve.

∫(C) F·dr=∬(S) curl(F)·dS.For F(x,y,z)=⟨-2yz,y,3x⟩, curl(F)=⟨0,-3,-2y⟩.∬(S) curl(F)·dS=∬(D) curl(F)(r(u,v))·N(r(u,v)) dAwhere D is the projection of S onto the xy plane and N(r(u,v)) is the unit normal vector to S. First, we need to determine the boundary curve of S.

The cylinder x²+y²=2 can be parameterized by x=√2 cos(t) and y=√2 sin(t), 0≤t≤2π. The surface z=y² can be parameterized by r(x,y)=⟨x,y,y²⟩. Then the boundary curve of S is C: r(t)=⟨√2 cos(t), √2 sin(t), 2⟩, 0≤t≤2π. r_x=<-√2 sin(t), √2 cos(t), 0>, r_y=<0,0,1>.So, N(r(u,v))=r_x x r_y=⟨-√2 cos(t), -√2 sin(t), -√2⟩.

Since curl(F) = ⟨0,-3,-2y⟩,curl(F)(r(t)) = ⟨0,-3,-2(2 sin(t))⟩ = ⟨0,-3,-4sin(t)⟩.Now we have ∬(S) curl(F)·dS=∬(D) curl(F)(r(u,v))·N(r(u,v)) dA=∫₀²π ∫₀√2 ⟨0,-3,-4sin(t)⟩ · ⟨-√2 cos(t), -√2 sin(t), -√2⟩ dA=12π∫₀²π(3cos(t)+4sin²(t))dt=12π(3(0)+2)=π.The value of ∫ ⃑∙⃑ is π.

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The probability of randomly selecting a tree or an insect is 3/10

From the question, we have the following parameters that can be used in our computation:

10 insects, 8 trees, 8 flowers, and 4 birds.

To find the probability of randomly selecting a tree or an insect,

We need to find the number of tree and insect cards and divide by the total number of cards.

There are 8 tree cards and 10 insect cards, for a total of 8 + 10 = 18 cards.

So the probability of randomly selecting a tree or an insect

P = 18/30

P = 3/5.

hence, the probability is 3/5.

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D. Three-point shots are attempted much more now by NBA players than players in the 1990s did.

Three-point shooting has become more prevalent in the NBA over the past few decades.

In the 1990s, teams averaged around 11 three-point attempts per game. By the 2020-2021 season, that number had increased to over 34 three-point attempts per game.

The NBA has also made changes to its rules and regulations over the years to encourage and facilitate more three-point shooting.

In contrast, slam dunks, mid-range shots, and free throws have not seen as significant a shift in attempt rates over the years.

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Answer:

Step-by-step explanation: 3×6+1,3×6 is 18+1 is 19/6 is your answer

The consumer's surplus at the unit price p = 10 for the given demand equation is $45.00, which represents the area between the demand curve and the price line up to the quantity demanded.

To calculate the consumer's surplus at the unit price p for the demand equation q = 120 - 2p, we need to find the area under the demand curve up to the price p. In this case, the given unit price is p = 10.

First, we need to find the quantity demanded at the price p. Substituting p = 10 into the demand equation, we get:

q = 120 - 2(10) = 120 - 20 = 100

So, at the price p = 10, the quantity demanded is q = 100.

Next, we can calculate the consumer's surplus. Consumer's surplus represents the difference between what consumers are willing to pay and what they actually pay. It is the area between the demand curve and the price line.

To find the consumer's surplus, we can use the formula:

Consumer's Surplus = (1/2) * (base) * (height)

In this case, the base is the quantity demanded, which is 100, and the height is the difference between the highest price consumers are willing to pay and the actual price they pay. The highest price consumers are willing to pay is given by the demand equation:

120 - 2p = 120 - 2(10) = 120 - 20 = 100

So, the height is 100 - 10 = 90.

Calculating the consumer's surplus:

Consumer's Surplus = (1/2) * (100) * (90) = 4500

Rounding the answer to the nearest cent, the consumer's surplus at the unit price p = 10 is $45.00.

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Answer:

3(3x + 2y) and 9x + 6y

Step-by-step explanation:

3(x + 3y + 2x - y)

= 3 (x + 2x) + (3y - y)

= 3 (3x + 2y)

= (3 • 3x) + ( 3 • 2y)

= 9x + 6y

If all the available assembly and testing time is used, we can assemble and test 10 of the second-type carburetors.

Let's let x be the number of the first type carburetors and y be the number of the second type carburetors.

To minimize calculation, let's focus on just one of the constraints, say the assembly time constraint. We can write: \(11x + 15y ≤ 372\)

Dividing everything by 3: (note: dividing by 3 preserves the inequality

\()4x + 5y ≤ 124\)

Rewriting this as:

\(y ≤ (-4/5)x + 24.8\)

Notice that this is the equation of a line with slope -4/5 and y-intercept 24.8.

The graph looks like this: Graph of\(y ≤ (-4/5)x + 24\).

We can see from the graph that y ≤ (-4/5)x + 24.8 is satisfied for any point under the line.

For example, \((x,y) = (20, 4)\)satisfies the inequality, but \((x,y) = (20,5)\) does not.

Now we turn our attention to the testing time constraint:2x + 9y ≤ 169

Dividing everything by 1: (note: dividing by 1 preserves the inequality)2x + 9y ≤ 169Rewriting this as

\(y ≤ (-2/9)x + 18.8\)

Notice that this is the equation of a line with slope -2/9 and y-intercept 18.8.

The graph looks like this:

Graph of \(y ≤ (-2/9)x + 18\).8

We can see from the graph that \(y ≤ (-2/9)x + 18.8\) is satisfied for any point under the line.

For example,\((x,y) = (20, 2)\) satisfies the inequality, but\((x,y) = (20,3)\)does not.

Now we need to find the point on both lines that maximizes the number of second-type carburetors y.

This point will lie on the intersection of the two lines:\(y = (-4/5)x + 24.8y = (-2/9)x + 18\).

Solving this system of equations, we get:x = 112/11 and y = 4/11Rounded down to the nearest integer, we get:x = 10 and y = 0

Therefore, if all the available assembly and testing time is used, we can assemble and test 10 of the second-type carburetors.

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The Laplace transform of f(t) is given by (2 - 4/s + 8/s^2 + 5/s).

The Laplace transform of f(t) can be found using Theorem 7.1.1, which states that the Laplace transform of a linear combination of functions is equal to the linear combination of the individual Laplace transforms.

Applying Theorem 7.1.1, we can find the Laplace transform of each term in f(t) separately and then combine them. Let's evaluate each term:

L{-4} = -4 * L{1} = -4/s

L{2} = 2 * L{1} = 2/s

L{8t} = 8 * L{t} = 8/s^2

L{5} = 5 * L{1} = 5/s

Now, combining these individual Laplace transforms, we have:

L{f(t)} = L{-4+2+8t+5} = -4/s + 2/s + 8/s^2 + 5/s

Simplifying further, we can write the Laplace transform of f(t) as:

L{f(t)} = (2 - 4/s + 8/s^2 + 5/s)

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