Determine the percentage composition (by mass) of tin in tin(II) fluoride, to three significant figures. Write the chemical formula for this substance and show your work for credit

Answer:

seismographs

Explanation:

Scientists use seismographs that record the length and strength of each earthquake to try to determine if an eruption is imminent. Magma and gas can push the volcano's slope upward.

\(LiNO_{3}\)There are 0.075 moles of \(LiNO_{3}\) in 250 mL of a 0.30 M solution.

To determine the number of moles of \(LiNO_{3}\) in 250 mL of a 0.30 M solution, we can use the formula:

moles of solute = concentration (M) x volume (L)

First, we need to convert the volume from milliliters (mL) to liters (L):

250 mL = 0.25 L

Next, we can substitute the given values into the formula:

moles of \(LiNO_{3}\) = 0.30 M x 0.25 L

moles of \(LiNO_{3}\) = 0.075 mol

Therefore, there are 0.075 moles of \(LiNO_{3}\) in 250 mL of a 0.30 M solution.

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120.3 g of benzene is required to produce 109.5 grams of maleic acid anhydride.

The reaction equation is;

2 C₆H₆(l) + 9 O₂(g) → 2 C₄H₂O₃(s) + 4 CO₂(g) + 4 H₂O(g)

Actual yield of   maleic anhydride = 109.5 g

Theoretical yield = 100 × Actual yield/% yield

Theoretical yield =  100 ×  109.5/72.6

Theoretical yield  = 150.8 g

Number of moles of maleic anhydride = mass/molar mass = 150.8 g/98.06 g/mol = 1.54 moles

From the reaction equation;

2 moles of benzene yields 2 moles of maleic anhydride

1.54 moles of benzene yields 1.54 moles of maleic anhydride

Mass of benzene required = 1.54 moles × 78.11 g/mol

Mass of benzene required = 120.3 g of benzene.

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Answer:

d

Explanation:

Becquerel showed that uranium gave off radioactivity, and the Curies discovered other radioactive elements. Therefore, option D is correct.

Radioactivity is the spontaneous emission of particles or radiation from the nucleus of an unstable atom. It occurs when the forces that hold the nucleus together are not strong enough to keep it from breaking apart, which results in the release of energy in the form of particles or radiation.

The three most common forms of radiation emitted by radioactive materials are alpha particles, beta particles, and gamma rays. Radioactivity can occur naturally, as in the case of radioactive isotopes found in rocks, soil, and living organisms, or it can be induced by artificial means, such as in nuclear reactors or nuclear weapons

Becquerel discovered that uranium emitted radiation without requiring external energy sources, and the Curies further investigated this phenomenon and discovered new radioactive elements such as polonium and radium.

The Curies also coined the term "radioactivity" to describe the emission of radiation by these elements. Hence, option D is correct.

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Leucine and methionine are nonpolar, while arginine and threonine are polar.

Amino acids are the building blocks of proteins and can be classified based on their chemical properties.

One important property is polarity, which refers to the distribution of electrical charge within a molecule.

Polar molecules have regions of partial positive and partial negative charge, while nonpolar molecules have no such regions.

Leucine and methionine are nonpolar amino acids because they have nonpolar side chains composed of mostly carbon and hydrogen atoms. These side chains do not interact with water, which is a polar solvent, and tend to be buried within the interior of proteins.

Arginine and threonine, on the other hand, are polar amino acids. Arginine has a positively charged side chain that can form ionic bonds with negatively charged molecules, while threonine has a polar, uncharged side chain that can form hydrogen bonds with other polar molecules.

These amino acids are typically found on the surface of proteins, where they can interact with the aqueous environment.

Overall, the polarity of amino acids plays an important role in determining the structure and function of proteins.

By classifying amino acids based on their polarity, we can better understand how they interact with other molecules and contribute to the complex biological processes that make life possible.

The amino acids as polar or nonpolar. Here's a breakdown:

1. Leucine: Leucine has a nonpolar side chain, so it is classified as nonpolar.

2. Arginine: Arginine has a polar side chain with a positive charge, so it is classified as polar charged.

3. Methionine: Methionine has a nonpolar side chain, so it is classified as nonpolar.

4. Threonine: Threonine has a polar side chain without a charge, so it is classified as polar neutral.

In summary:

- Polar charged: Arginine
- Polar neutral: Threonine
- Nonpolar: Leucine, Methionine

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Answer:

A. 7

(assuming the water is neutral)

The reason that methyl salicylate be much more volatile than salicylic acid is because:

Salicylic acid's COOH group is esterified with methanol in methyl salicylate (oil of wintergreen), whereas acetylsalicylic acid (aspirin) has acetic acid as the acid component of the ester and salicylic acid provides the phenolic OH group.

Note that Methyl salicylate, a volatile methyl ester of salicylic acid, can also diffuse into the atmosphere and aid in plant-plant communication.

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Answer:

The protons are located in the nucleus and have a positive charge

Explanation:

Answer:

C: was once buried underground

Explanation:

Hope this helps!

Answer:

The correct answer you are looking for is B i have got 100% on this test.

Explanation:

hop this helps! └(^o^)┘  ↖(^ω^)↗

Answer:

Electromagnetism is the study of the electromagnetic force, one of the four fundamental forces of nature. It includes the electric force, which pushes all charged particles, and the magnetic force, which only pushes moving charges.It is used in many electrical appliances to generate desired magnetic fields. It is even used in a electric generator to produce magnetic fields for electromagnetic induction to occur.

Explanation:

tell me if this helped, ill try and explain better

Answer:

Cu₂O

Explanation:

Copper(I) oxide or cuprous oxide is the inorganic compound with the formula Cu₂O. It is one of the principal oxides of copper, the other being or copper (II) oxide or cupric oxide. This red-coloured solid is a component of some antifouling paints.

Answer:

Check the electronic configuration of elements.

Explanation:

▪Valence electrons are the elwctrons present in the outermost shell of any element.

For example,

Electronic Configuration of Sodium = 2,8,1

Here , Sodium has 1 valence electrons.

▪Valency of an element is the total no. of electrons to be gained/losed in order to achieve duplet/octate state.

For example,

Electronic configuration of Sodium = 2,8,1

Sodium can achieve octate state either by losing 1 electron or gaining 7 electrons. But losing 1 electron is eay than gaining 7 electrons. So Valency of Sodium = +1

☆Metals have 1 or 2 or 3 valence electrons.

☆Non metals have 4 or 5 or 6 or 7 valence electrons.

☆Noble gases tend to stay in duplet/octate state i.e they have 2 or 8 valence electrons.

To prepare a buffer with a pH of 3.52, the appropriate choice would be Butyric acid (pKa = 4.82).  The correct option is D.

In a buffer solution, the acid and its conjugate base work together to resist changes in pH upon addition of acid or base. Since the desired pH is lower than the pKa value of Butyric acid, it indicates that the acid will be predominantly in its undissociated form and can act as an effective buffer.

Hydrocyanic acid and Hypoiodous acid have pKa values higher than the desired pH, making them unsuitable choices for preparing a buffer with a pH of 3.52. Citric acid has a pKa value of 3.13, which is close to the desired pH, but Butyric acid is a better choice as its pKa is closer to the target pH.

The correct option for preparing a buffer with a pH of 3.52 is option D: Butyric acid (pKa = 4.82).

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A buffer solution with a pH of 3.52 would require an acid with a pKa close to this value. Therefore, the appropriate acid to use to prepare the buffer would be Butyric acid (pKa=4.82).

Buffer solution: A buffer solution is a solution that can resist a change in pH when a small amount of acid or base is added to it. The pH of the buffer solution changes by a small amount when a small amount of acid or base is added to it because it contains both a weak acid and its conjugate base. pH is the measure of how acidic or basic a solution is. The pH scale ranges from 0 to 14. A solution with a pH less than 7 is acidic, while one with a pH greater than 7 is basic. A solution with a pH of 7 is neutral. Acids are substances that contribute hydrogen ions (H+) to a solution and have a pH of less than 7. Bases are substances that contribute hydroxide ions (OH-) to a solution and have a pH greater than 7.pKa valueA pKa value is a measure of the acidity of a molecule. It represents the pH at which the molecule is half-protonated and half-deprotonated. The lower the pKa value, the stronger the acid. An acid with a pKa value close to the pH of the buffer solution will be a suitable candidate for making the buffer solution. A buffer with a pH of 3.52 would require an acid with a pKa close to this value.

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The mass of the precipitate is 1.08 g and the precipitate is barium carbonate.

In chemical calculations, such as figuring out the stoichiometry of reactions, figuring out concentrations, and converting between different units of measurement, the idea of moles is crucial.

Number of moles of the barium chloride = 55/1000 L * 0.1

= 0.0055 moles

Number of moles of sodium carbonate = 40/1000 L * 0.15

= 0.006 moles

Given that the reaction is 1:1, the limiting reactant is barium chloride

Number of moles of the barium carbonate precipitate =  0.0055 moles * 197 g/mol

= 1.08 g

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The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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Answer:

[Au] = 0.171 M

Explanation:

For this question, we assume the rock is 100 % gold.

First of all, we determine the moles of gold

67.3 g . 1mol/ 196.97g = 0.342 moles

Molar concentration is defined as the moles of solute, contained in 1L of solution.

Our solution volume is 2L.

M = 0.342 mol / 2L = 0.171

Molar concentration, also called molarity of solution is the most typical unit of concentration.

Answer C

Explanation: the solute will be sugar and the solvent will be water :)

Answer:

Hydrogen

Explanation:

It is pretty much present everywhere :)

In the base-three numeration system, 100 represents one group of three, zero twos, and zero ones. In both cases, the numeral represents the same value or amount of objects, which is fourteen.

4. A set of measuring units for the base-three numeration system using the same BMU that was used in Fart 1 for the base-five numeration system can be constructed.

The chart below shows the place value chart that records the set of units.

\(\begin{array}{|r|r|} \hline \text{Place Value}&\text{Base-Three Value}\\ \hline 243&2\\ \hline 81&1\\ \hline 27&0\\ \hline 9&2\\ \hline 3&1\\ \hline 1&0\\ \hline \end{array}\)

5. The base-three numeral 121 can be built using the measuring units from problem #4. The number represents the quantity three hundred forty-two.

6. The quantity represented by the base-three numeral 100 is two hundred forty-one.

7. The value of 14 five is the same as the value of 100 three because in both cases the value of the numeral is fourteen. In the base-five numeration system, 14 represents one group of five and four ones.

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The Theoretical Yield of the reaction is 2g.

The theoretical yield is the amount of product expected to be recovered in a chemical reaction, assuming perfect conversion of all reactants to products.

To calculate the theoretical yield of your product, you need to know the mass of each of the reactants and the stoichiometry of the reaction.

Let's assume that the reaction is A + B → C. The theoretical yield is equal to the mass of reactant A multiplied by the stoichiometry of C, divided by the stoichiometry of A. The equation looks like this:

Theoretical Yield = (Mass of Reactant A) × (Stoichiometry of C) / (Stoichiometry of A)

For example, if you have 1 g of reactant A, the stoichiometry of C is 2, and the stoichiometry of A is 1, the theoretical yield would be 2 g.

Theoretical Yield = (1 g) × (2) / (1) = 2 g

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The claim that the atomic model should not be continually changed is based on the principle of scientific stability and coherence. Continually changing the atomic model can undermine the stability of scientific understanding and impede the development of robust theories.

The claim that the atomic model should not be continually changed is based on the principle of scientific stability and coherence. Continually changing the atomic model can undermine the stability of scientific understanding and impede the development of robust theories. The current atomic model, based on quantum mechanics and the understanding of subatomic particles, has provided a consistent framework that has successfully explained and predicted numerous phenomena. This model has undergone rigorous testing, verification, and refinement over the years. While scientific progress and new discoveries are essential, it is important to maintain a balance between incorporating new evidence and maintaining a stable foundation. Frequent changes to the atomic model can lead to confusion and make it difficult to build upon existing knowledge. It is preferable to refine and expand upon the current model as new evidence emerges, rather than discarding it entirely. This approach ensures continuity and progress in scientific understanding while maintaining a coherent framework for further exploration.

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The time taken for the decay rate to fall to 2.5×10³, given that the sample has a half-life of 1.83 hours is

We'll begin by obtaining the number of half lives that has passed during the decay. Details below

2ⁿ = A₀ / A

2ⁿ = 1.5×10⁵ / 2.5×10³

2ⁿ = 60

Take the log of both sides

Log 2ⁿ = log 60

nLog2 = log 60

Divide both sides by log 2

n = log 60 / log 2

n = 5.907

Finally, we shall determine the time taken. Details below

n = t / t½

5.907 = t / 1.83

Cross multiply

t = 5.907 × 1.83

t = 10.81 hours

Thus, the time taken is 10.81 hours

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C). $1,305,000. To compute Fast Inc.'s taxable income, we need to start with the corporation's gross income, which is the sales revenue of $1,879,000.

From this, we subtract the deductible expenses, such as Mrs. Ford's salary of $160,000 and other operating expenses of $414,000, which gives us a total of $1,305,000.
However, we still need to consider the interest paid on Mrs. Ford's note of $60,000 and the dividend distributed to Mrs. Ford of $100,000, both of which are not deductible expenses for the corporation.

Therefore, the corporation's taxable income would be $1,465,000 ($1,305,000 + $60,000 + $100,000), and this would be subject to the corporate tax rate based on the current tax laws and regulations.

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To solve this problem, we could use the Boyle's law since there's a sample of ideal gas and temperature is constant.

Boyle's law tells us that:

Replacing the values of the problem:

The new volume V equals 5.6L.

Answer:

1 A true

B False

C not sure about it False

D False

The answer is (70.35, 84.57) mL.

The three volumes of NaOH required to attain a pH of 7 in each of the three titrations are: 82.16, 75.79, and 75.43 mL. To estimate the mean number of milliliters required to neutralize 1 gram of the acid, a 99 percent confidence interval will be used. Let's calculate the sample mean, sample standard deviation, and margin of error using the provided data.

Sample standard deviation:

Sample Mean The sample mean of a dataset is defined as the sum of all the data points divided by the number of data points. So the sample mean will be: (82.16+75.79+75.43) / 3 = 77.46 mL. Sample Standard Deviation The sample standard deviation (s) is defined as the square root of the sample variance. To calculate s, we need to first compute the sample variance (s²):s² = ∑(x - μ)² / (n - 1)where x is the value of the observation, μ is the sample mean, and n is the sample size.s² = [(82.16 - 77.46)² + (75.79 - 77.46)² + (75.43 - 77.46)²] / (3 - 1)s² = [20.4 + 6.74 + 5.84] / 2s² = 16.49s = sqrt(16.49) = 4.06 mL.

Marginal Error The formula for the margin of error for a confidence interval for the mean is:

margin of error = t (α/2) * (s / sqrt(n)) where t(α/2) is the critical value of the t-distribution with n-1 degrees of freedom and a level of significance of α/2 (in this case, α/2 = 0.005).s is the sample standard deviation that we computed earlier. n is the sample size (in this case, n = 3). margin of error = t(α/2) * (s / sqrt(n))margin of error = 3.182 * (4.06 / sqrt(3)) = 7.11 mL. The margin of error is 7.11 mL. Confidence Interval The confidence interval formula for a population mean is: sample mean - margin of error < μ < sample mean + margin of error where μ is the population mean and sample mean is the value obtained from the sample.μ = 77.46 - 7.11 < μ < 77.46 + 7.11Thus, the 99% confidence interval for the mean number of milliliters needed to neutralize 1 gram of the acid is (70.35, 84.57) mL (rounded to three decimal places).Therefore, the answer is  (70.35, 84.57) mL.

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The flowchart showing how to separate a mixture of benzoic acid, ethyl p- aminobenzoate, and benzophenone is found in the attachment.

In order to separate a mixture of benzoic acid, ethyl p- aminobenzoate, and benzophenone, do the following:

1. Dissolve the mixture using a suitable solvent such as dichloromethane or ethyl acetate

2. Perform a liquid-liquid extraction by adding a suitable aqueous solution as follows

Benzophenone may remain in the organic layer.

Separate the aqueous layer from the organic layer using a separation funnel or other suitable separation techniques.

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Answer:

It is a observation

Explanation:

Answer:

B

Explanation:

The element which accepts an electron  is reduced fastly. Oxygen is electronegative and it easily reduce in a reaction by accepting electrons. Hence, option d is correct.

Reduction is the process of reacting with hydrogen or withdrawal of electrons to form the lower oxidation state. Atoms lose or gain electrons in a reaction based on the number of their valence electrons.

If an atom is electron deficient and it needs one or more electron to be attain octet it easily accepts electron and such atoms are called electronegative. If an atom is electron rich and have extra electrons that have to be removed from the valence shell to attain octet will lose electron.

Atoms which loses electrons are oxidised to higher oxidation states and atoms which are gaining electrons will reduce into lower oxidation state.Among the given elements, sodium and magnesium are electron rich metals and they are oxidised in a reaction.

Hydrogen is an electropositive element but reduces rarely. Oxygen reduces fast since it is an electronegative element. Thus, option d is correct.

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