Answer:
Revolutions
Explanation:
What is the vector sum of a vector T~ given by 40 m, 30 degrees and a vector U~ given by 12
m, 225 degrees?
Hence, R = 28.97 m, 24.5 degrees is the vector sum of T and U.
Is a vector at 30 degrees?A vector's direction is frequently stated as a rotation of the vector's "tail" anticlockwise with respect to due East. In accordance with this practise, a vector having a direction of 30 degrees is a vector that has been anticlockwise rotated 30 degrees with respect to due east.
Let's begin by separating the components of the vector T:
T~ = 40 m, 30 degrees
T_x = 40 cos(30) = 34.64 m
T_y = 40 sin(30) = 20 m
Let's now decompose the vector U into its constituent parts:
U~ = 12 m, 225 degrees
U_x = 12 cos(225) = -8.49 m
U_y = 12 sin(225) = -8.49 m
It is possible to combine elements of the same type (x and y):
R_x = T_x + U_x = 34.64 m - 8.49 m = 26.15 m
R_y = T_y + U_y = 20 m - 8.49 m = 11.51 m
The Pythagorean theorem can be used to determine the size of the resulting vector R:
|R~| = sqrt(R_x² + R_y²) = sqrt((26.15 m)² + (11.51 m)²) = 28.97 m
The inverse tangent function can be used to determine the direction of the resulting vector R:
theta = tan⁻¹(R_y/R_x) = tan⁻¹(11.51 m/26.15 m) = 24.5 degree.
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4. S. crossirostris's wings were made of a delicate flap of skin. If this flap of skin
tore, the animal could not fly. Use this information to explain how
S. crassirostris might have had trouble competing with bird species living during
the Mesozoic era.
Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.
What are the birds?The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.
In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.
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30 points! to who helps me out
find the potential,electric field,charge density.
Answer:
The answer is Model the charge distribution as the sum of infinitesimal point charges, dq, and add together the electric potentials, dV, from all charges, dq. ...
Calculate the electric field (either as a integral or from Gauss' Law), and use: ΔV=V(→rB)−V(→rA)=−∫BA→E⋅d→r.
Explanation:
Compare sound and earthquake waves
When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.
How do sound waves and earthquakes compare?
The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.
In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.
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Please answer these questions correctly (photo is attached) I’ll give brainliest
At the top of a flight of stairs, a woman is 16m above the ground and has 9094J of potential energy. What is the mass of the woman?
Answer:
Mass = 56.83 Kg
Explanation:
\(PE = mgh\\9094 J = 16m*10 m/s^2*mass\\mass = \frac{PE}{g*h} \\mass = \frac{9094 J}{16*10} = 56.83 kg\)
Which orbit has the highest energy?
n = 1
n = 2
n = 3
Answer:
3
Explanation:
The closer an orbit is to the nucleus the fewer energy
Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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I need help with this answer
The velocity of a particle is given by v=25t2 -80t-200, where velocity is meter per second and time is seconds. Determine the velocity for the first six seconds when acceleration is zero.
Answer:
v = 220 m / s
Explanation:
This is a kinematics exercise, the expression for velocity is
v = 25 t² - 80 t - 200
asks the velocity for time t = 6 s.
let's calculate
v = 25 6² - 80 6 - 200
v = 220 m / s
The velocity for the first six seconds when acceleration is zero is -44 m/s.
What is velocity?
The velocity of an object is the rate of change displacement with time.
The velocity of the object for the first six seconds when the acceleration is zero is calculated as follows;
\(a = \frac{dv}{dt} \\\\a = 50t - 80\\\\0 = 50t - 80\\\\50t = 80\\\\t = 1.6 \ s\)
Velocity when time = 1.6 s
\(v(1.6) = 25(1.6)^2 - 80(1.6) - 200\\\\v(1.6) = -264 \ m/s\)
The velocity for the first six seconds when acceleration is zero.
\(v = v_{a =0} + v_6\\\\v = - 264 \ + 25(6)^2 - 80(6) - 200\\\\v = -44 \ m/s\)
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Two blocks are connected to identical ideal springs and are oscillating on a horizontal frictionless surface. Block A has mass m, and its motion is represented by the graph of position as a function of time shown above on the left. Block B’s motion is represented above on the right. Which of the following statements comparing
block B to block A is correct?
(A) Because block B covers more distance per cycle than block A, block B takes more time to complete each
cycle.
(B) Because the spring attached to block B is initially stretched a greater distance, the spring constant is smaller
and therefore block B has a slower average speed than block A does.
(C) Because block B has more mass, it has a slower average speed than block A does.
(D) Because block B has more mass, its acceleration is smaller than that of block A at any given displacement
from the equilibrium position.
Hi there!
We can begin by identifying key characteristics of both graphs.
Graph A.
Looking at the graph, we can see that the maximum distance (amplitude) is 10 cm (0.1 m). Additionally, its period (T) is 2 seconds (one full cycle).
We also know that:
\(T = 2\pi \sqrt{\frac{m}{k}}\)
We can use this equation to compare with the other graph. Notice how the period does NOT depend on how far the spring is stretched. We can eliminate choice A for this reason.
Graph B.
The amplitude is 20 cm (0.2 m), and each period is 4 seconds.
We can now eliminate choice B because the springs are identical, so their spring constants are equal. Distance stretched has no impact on the spring constant.
For the other choices, we must look at forces and work.
Recall that:
Spring potential energy = \(\frac{1}{2}kx^2\)
Kinetic energy = \(\frac{1}{2}mv^2\)
Using the work-energy theorem:
\(\frac{1}{2}kx^2 = \frac{1}{2}mv^2\)
Even if the mass of Block B is greater, its displacement is larger than that of Block A. Since displacement is squared in this equation, it would have a greater effect on the speed. Thus, Choice C is incorrect.
Using Hooke's Law:
\(\Sigma F = -kx\\\\ma = -kx\\\)
\(a = \frac{-kx}{m}\)
If the mass is greater, the acceleration will be smaller. Choice D is correct.
How much work is done by the force of gravity to push a wooden box of 50 kg along the ground through a distance of 5 m?
Is the answer 2450 J?
Answer:
Yes
Explanation:
Work done = F * S
F = mg
50 * 9.81 = 490.5
490.5 * 5 = 2452.5 ≈ 2450
ACTIVITY 1: Research a Famous Chemist or Physicist
1) Do research on a famous chemist or physicist. Write a 300-500 word essay one of them. Use at least three different sources. Sources can include biographies, internet articles from universities, or journal articles. Wikipedia is not an acceptable source information.
Be sure to answer these questions:
* What did this scientist discover?
* How was it discovered?
* How does this discovery or invention impact the world today?
(Scientist: Nikola Tesla)
Answer:
What did this scientist discover?
Nikola Tesla discovered and created Bluetooth back in 19, November 5, 1898.
"The Transmission of Electrical Energy Without Wires", Electrical World and Engineer, January 7, 1905. Tesla, Nikola, World System of Wireless Transmission of Energy, Telegraph and Telegraph Age, October 16, 1927.
How was it discovered?
In 1901 Tesla began his work of a large high-voltage wireless energy transmission station called the Wardenclyffe Tower. ... Some devices already employ wireless energy transfer without the use of metal contacts. The power is transferred through the plastic cases using magnetic induction.
How does this discovery or invention impact the world today?
It changed the new age by listening to music with wireless earbuds.
6. A 25 g sample of iron (initially at 800.00°C) is dropped into 200 g of water (initially at
30.00°C). The final temperature of the system is 40.22°C. Find the specific heat of iron.
90
Answer:
\(c=0.45\ J/g^{\circ} C\)
Explanation:
Given that,
A 25 g sample of iron (initially at 800.00°C) is dropped into 200 g of water (initially at 30.00°C). The final temperature of the system is 40.22°C.
We need to find the specific heat of iron.
It can be calculated as:
Cooler water gains = hot metal loses
mc∆T = - mc∆T
Put all the values,
\(200g(4.184\ J/g^{\circ} C)(T_f-T_i) = -25g(c)(T_f-T_i) \\\\200g(4.184 )( 40.22-30.00) = -25\times (c)\times (40.22-800.00)\\\\8552.096 = 18994.5c\\\\c=\dfrac{8552.096 }{18994.5}\\\\c=0.45\ J/g^{\circ} C\)
So, the specific heat of iron is \(0.45\ J/g^{\circ} C\)
What is energy ? Use in your own words.
Answer:
the potential for causing changes
Explanation:
If a skier travels at a constant velocity downhill, this means the forces on her are: ................. A. Zero B. Negligible C. Unbalanced D. Balanced
Answer:
F = 0
Explanation:
The net force acting on an object is given by the product of mass and acceleration. We know that acceleration is equal to the rate of change of velocity.
Net force,
F = ma
\(F=\dfrac{m(v-u)}{t}\)
The skier is traveling at a constant velocity, it means there is no change in velocity i.e. acceleration is equal to 0. Hence, the force on her is 0.
Which title goes with this list: Amendments Articles Preamble?
A. Florida and County Government
B. Florida and U.S. Government
C. City and County Government
D. City and U.S. Government
A lab technician uses laser light with a wavelength of 650 nmnm to test a diffraction grating. When the grating is 42.0 cmcm from the screen, the first-order maxima appear 6.09 cmcm from the center of the pattern. How many lines per millimeter does this grating have?
Answer:
221 lines per millimetre
Explanation:
We know that for a diffraction grating, dsinθ =mλ where d = spacing between grating, θ = angle to maximum, m = order of maximum and λ = wavelength of light.
Since the grating is 42.0 cm from the screen and its first order maximum (m = 1) is at 6.09 cm from the center of the pattern,
tanθ = 6.09 cm/42.0 cm = 0.145
From trig ratios, cot²θ + 1 = cosec²θ
cosecθ = √((1/tanθ)² + 1) = √((1/0.145)² + 1) = √48.562 = 6.969
sinθ = 1/cosecθ = 1/6.969 = 0.1435
Also, sinθ = mλ/d at the first-order maximum, m = 1. So
sinθ = (1)λ/d = λ/d
Equating both expressions we have
0.1435 = λ/d
d = λ/0.1435
Now, λ = 650 nm = 650 × 10⁻⁹ m
d = 650 × 10⁻⁹ m/0.1435
d = 4529.62 × 10⁻⁹ m per line
d = 4.52962 × 10⁻⁶ m per line
d = 0.00452962 × 10⁻³ m per line
d = 0.00452962 mm per line
Since d = width of grating/number of lines of grating
Then number of lines per millimetre = 1/grating spacing
= 1/0.00452962
= 220.77 lines per millimetre
≅ 221 lines per millimetre since we can only have a whole number of lines.
A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 20
kg. The carriage has
energy. Calculate it
Answer:
Energy in carriage (Potential energy) = 4,116 J
Explanation:
Given:
Mass of baby = 20 kg
Height = 21 m
Find:
Energy in carriage (Potential energy)
Computation:
The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.
In carriage accumulated energy is potential energy.
Energy in carriage (Potential energy) = mgh
Energy in carriage (Potential energy) = (20)(9.8)(21)
Energy in carriage (Potential energy) = 4,116 J
Figure shows three blocks attached by cords that
loop over frictionless pulleys. Block B lies on a
frictionless table; the masses are ma = 6.00 kg.
mg = 8.00 kg, and mc = 10.0 kg. When the blocks are
released, what is the tension in the cord at the right?
Answer: The tension in the cord at the right is 81.7N.
Explanation:
In order to solve this we consider a system with a clockwise motion considered as positive which means that for a downward position for block C is positive and for block B rightward is positive and for Block A upward is positive)
Formula = mC g- mA g = M a (where M = mass of system = 24.0kg)
a(acceleration) = g(mC-mA)/M = 1.63m/s^2
Force on Block C = mCg -T = mCa
T = mCg(2mA+mB)/M
T = 81.7N
Hence Tension = 81.7N
Janelle pushes a box filled with books across the floor of her room. She then add some books to the box and pushes it with the same force across the same floor. How will the motion of the box change?
A . It will move slower because as mass increases, the force of friction between the surface also increases.
B. It will move faster because as mass increases, the force of friction between the surfaces decreases.
C it will move with the same speed because the mass of the object does not affect the force of friction between the surfaces.
D. It will move with the same speed because the same force was applied on the box in both of the cases
The motion of the box changes as it will move slower because as the mass increases, the force of friction between the surface also increases. Thus, the correct option is A.
What is the force of friction?Force of friction is a type of contact force. Frictional force is the force which resists the motion when the surface of one object comes in contact with the surface of another object. Example of frictional force is the force of friction between two stones which are rubbed with each other. The SI unit of frictional force is Newton (N).
Frictional force can be calculated by the formula:
f = μN
where, f = frictional force,
μ = coefficient of friction,
N = Normal force
The mass of the objects (normal force - mg) which are in motion is directly proportional to the magnitude of the frictional force. As more books are added to the box while the force of push remains same the motion of the box will change and it will move slower because as mass increases, the force of friction between the surface also increases.
Therefore, the correct option is A.
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13. A solid has a mass of 200 g in air and when partly immersed in a certain liquid it has a mass of 160 g. Given that the relative density of the liquid is 0.80, calculate the volume of the solid immersed in the liquid.
The volume of the solid immersed in the liquid is 5 x 10⁻⁵ m³.
What is the volume of the solid?The volume of the solid is calculated as follows;
V = (Ws - Wa) / (ρg)
where;
Ws is the weight of the solid in airWa is the weight of the solid in liquidρ is the density of the solidg is gravityWs = 0.2 kg x 9.8 m/s²
Ws = 1.96 N
Wa = 0.16 kg x 9.8 m/s²
Wa = 1.568 N
ρ = 0.8 x 1000 g/km³ = 800 kg/m³
The volume is calculated as;
V = (1.96 - 1.568 )/(800 x 9.8)
V = 5 x 10⁻⁵ m³
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Mass 1 strikes Mass 2 while moving in the positive-x direction, which is initially at rest. After the collision M2 moves off in the same direction but at a greater speed. Which of the following is true? A. mass 2 is larger B. mass 2 is same size C.mass 2 is smaller
Mass 1 strikes Mass 2 while moving in the positive-x direction, which is initially at rest. After the collision M2 moves off in the same direction but at a greater speed. According to conservation of momentum, The following is true : mass 2 is smaller
According to conservation of momentum, the product of mass and velocity is constant.
Since the velocity of the second mass is greater than that of the first mass
This is possible if the mass 2 is smaller than mass 1
M1V1i + M2V2i = M1V1f + M2V2f
M1V1i = M2V2
But V2f > V1i
So M1 > M2 to balance the equation.
The conservation of momentum principle asserts that the quantity of momentum inside a problem domain remains constant; momentum is not generated nor destroyed, but only modified by the action of forces as defined by Newton's equations of motion.
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Mark weighs 375 N and is carrying a full-sized cello as he climbs the stairs to a height of 4 m. It takes him 3 seconds to do this.
How does the amount of work he does change if he were to climb the same flight of stairs again in the same amount of time, but this time without the cello?
A) It depends on the weight of the cello.
B) It remains the same.
C) It increases
D) It decreases.
Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.
The correct answer is option D.
The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :
Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).
When Mark climbs the stairs with the cello, he is doing work against the force of gravity.
The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.
Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.
Therefore, mark's work decreases.
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Masses m and 2m are joined by a light inextensible string which runs without slipping over a uniform circular pulley of mass 2m and radius a. Using the angular position of the pulley as generalized coordinate, write down the Lagrangian function and Lagrange's equation. Find the acceleration of the masses.
Answer: the acceleration of the masses is given by = 0, which means the angular acceleration of the pulley is zero. This implies that the masses m and 2m move with constant velocity, they are in equilibrium.
What is the average velocity of a car that drives 50 meters to the left in 5 seconds?
Answer:
\(\boxed {\boxed {\sf 10 \ m/s \ left}}\)
Explanation:
Velocity is the speed of something in a given direction. It is a vector quantity, so it has both magnitude and direction. Velocity is calculated by dividing the displacement by the time.
\(v= \frac{d}{t}\)
The car drives 50 meters to the left in 5 seconds.
d= 50 m left t= 5 sSubstitute the values into the formula.
\(v= \frac{50 \ m \ left}{5 \ s}\)
Divide.
\(v= 10 \ m/s \ left\)
The average velocity of the car is 10 meters per second to the left.
(a) A person moves a distance of 3 km towards east, then 2 km towards north and then 3.5 km towards east.
Find :
(i) the distance covered by the person,
(ii) the displacement of this motion.
(b) Name the type of motion in which a body has uniform speed but not uniform velocity ?
Answer:
Explanation:
Answer:
The distance covered by the person is 8.5 metre and the displacement is 6.8 metre.
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A copper cable is 1.2 km long and has a cross-sectional area of 5 mm^2. Find its resistance at 80°C if at 20°C the resistivity of copper is 0.02*10^-6ohm m and its temperature coefficient of resistance is 0.004/°C
Explanation:
Equation for resistity
\(p(t)= p(0) \times (1 + a \times (change \: in \: temp))\)
\( = 0.02 \times {10}^{ - 6} \times (1 + 0.004 \times 60)\)
\( = 2.48 \times {10}^{ - 8} ohm \: m\)
\(r = (p \times l) \div a\)
\( = (2.48 \times {10}^{ - 8} \times 1200) \div \: 5 \times {10}^{ - 6} \)
\( = 5.952 \: ohms\)
The questions at the bottom are 1. Both moving at a constant a velocity.2.Both accelerating.3.Both stopped.4.Bith have a force on them so what is the answer