Create a tree diagram that shows all the possible outcomes for tossing a coin and spinning a spinner with six equal sections numbered 1 through 6.

Answer:

I think it is -12

Multiply -0.75 (3 quarters) by 16.

The negative cancels out the positive number.

Since the exponent is not saying multiply the number by itself a number of times, we could make a hypothesis that this is just multiplication.

Normally, this ↑ is not the case, but here, I could make an exception.

I hope this helps you, let me know if you need something else.

Answer:

9

Step-by-step explanation:

The answer you divide 65 by 7 which would get you 9.2857142857143. The remainder is 2.

MATHEMATICALLY WE WRITE THE PROBLEM AS

\( = \frac{65}{7} \\ \)

SOLVING FURTHER

\(65 \div 7 \\ = 9.285714286\)

BUT 7 GOES 9 TIMES IN 65 NOT CONSIDERING THE REMINDER.

HOPE THIS HELPS

Answer:

\(b. \: 16\)

Step-by-step explanation:

Divide the numbers ⬇

\((4 + 2) \times 2 + 4\)

Add the numbers ⬇

\(6 \times 2 + 4\)

Multiply the numbers ⬇

\(12 + 4\)

Add the numbers ⬇

\(12 + 4 = 16\)

OPTION B IS RIGHT :)

hope this helps!! Mark me brainliest please!

Answer: B. 16

Step-by-step explanation:

Hope this helps!

Volume data

Solution volume= V'

Original volume = V

90 mm = Volume 1 + Volume 2

Then

( V + V') + 3 = 3V

Solve and eliminate parenthesis. Find V'

3V -V - V' = 3

2V - V' = 3

Now find V , in equation

90 - V' = V

Replace V' by 2V - 3

Then

V= 90 - V' = 90 - (2V- 3)

Now isolate V

V + 2V = 90 + 3

then

3V = 93

V= 93/3= 31

Answer:

Mean: 62.75

Step-by-step explanation:

add all the numbers in the number of students and divide them by 4 (the amount of numbers shown)

The 9 adult tickets and 93 children tickets were purchased.Let's assume the number of adult tickets purchased is "a" and the number of children tickets purchased is "c."

According to the given information, children tickets cost $9 and adult tickets cost $11. So, the total cost of children tickets is 9c, and the total cost of adult tickets is 11a.

The problem also states that the total cost of all the tickets is $936. Therefore, we can write the following equation:

9c + 11a = 936

Additionally, it is mentioned that the number of children tickets purchased was three more than ten times the number of adult tickets purchased:

c = 10a + 3

We can now solve this system of equations to find the values of "a" and "c." By substituting the value of "c" from the second equation into the first equation, we have:

9(10a + 3) + 11a = 936

90a + 27 + 11a = 936

101a = 936 - 27

101a = 909

a = 909 / 101

a = 9

Substituting this value back into the second equation, we find:

c = 10(9) + 3

c = 90 + 3

c = 93.

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The solution for y in the inequality is (a) y ≥ 10

From the question, we have the following inequality expression that can be used in our computation:

42≤4.2y

Rewrite the expression properly

So, we have the following representation

42 ≤ 4.2y

Divide both sides of the inequality by 4.2

So, we have

42/4.2 ≤ 4.2y/4.2

Evaluate the quotients

So, we have the following representation

10 ≤ y

Rewrite the expression as

y ≥ 10

Hence, the solution is y ≥ 10

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Possible question

Solve for y. 42≤4.2y

y ≥ 10 y ≥ -10 y ≤ -10 y ≤ 10

This looks like a system of differential equations.

\(\begin{cases}x' + 2y' + x = 0 \\ x' - y' + y = 0 \\x(0)=0, y(0)=1\end{cases}\)

Eliminating x' gives

\((x'+2y'+x)-(x'-y'+y) = 0 - 0 \implies 3y' - y + x = 0\)

and eliminating y' gives

\((x'+2y'+x) + 2(x'-y'+y)=0+2\times0 \implies 3x' + x + 2y = 0\)

so that we can rewrite the system as

\(\begin{cases}3x' = -x - 2y \\ 3y' = -x + y\end{cases}\)

or equivalently in matrix form as

\(\begin{bmatrix}x\\y\end{bmatrix}' = \dfrac13 \begin{bmatrix}-1&-2\\-1&1\end{bmatrix} \begin{bmatrix}x\\y\end{bmatrix}\)

Compute the eigenvalues for the coefficient matrix:

\(\det\begin{bmatrix}-1-\lambda&-2\\-1&1-\lambda\end{bmatrix} = (-1-\lambda)(1-\lambda) - 2 = \lambda^2 -3 = 0 \implies \lambda=\pm\sqrt3\)

Compute the corresponding eigenvectors:

\(\lambda=\sqrt3 \implies \begin{bmatrix}-1-\sqrt3&-2\\-1&1-\sqrt3\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix}=\begin{bmatrix}0\\0\end{bmatrix} \\\\ \implies v_1=(1-\sqrt3)v_2 \implies \vec v = \begin{bmatrix}1-\sqrt3\\1\end{bmatrix}\)

\(\lambda=-\sqrt3 \implies \begin{bmatrix}-1+\sqrt3&-2\\-1&1+\sqrt3\end{bmatrix}\begin{bmatrix}v_1\\v_2\end{bmatrix}=\begin{bmatrix}0\\0\end{bmatrix} \\\\ \implies v_1 = (1+\sqrt3)v_2 \implies \vec v = \begin{bmatrix}1+\sqrt3\\1\end{bmatrix}\)

We end up multiplying the matrix by 1/3, so the eigenvalues also get scaled by 1/3 and λ = ±1/√3. The eigenvectors stay the same.

Then the characteristic solution to the system is

\(\begin{bmatrix}x\\y\end{bmatrix} = C_1 e^{t/\sqrt3} \begin{bmatrix}\frac{1-\sqrt3}3\\\frac13\end{bmatrix} + C_2 e^{-t/\sqrt3} \begin{bmatrix}\frac{1+\sqrt3}3\\\frac13\end{bmatrix}\)

Use the initial conditions to solve for the constants.

\(\begin{bmatrix}0\\1\end{bmatrix} = C_1 \begin{bmatrix}\frac{1-\sqrt3}3\\\frac13\end{bmatrix} + C_2 \begin{bmatrix}\frac{1+\sqrt3}3\\\frac13\end{bmatrix}\)

\(\implies \begin{cases}(1-\sqrt3) C_1 + (1+\sqrt3) C_2 = 0 \\ C_1 + C_2 = 3\end{cases}\)

\(\implies C_1=\dfrac{3+\sqrt3}2, C_2=\dfrac{3-\sqrt3}2\)

Then the particular solution is

\(\begin{bmatrix}x\\y\end{bmatrix} = \dfrac{3+\sqrt3}6 e^{t/\sqrt3} \begin{bmatrix}1-\sqrt3\\1\end{bmatrix} + \dfrac{3-\sqrt3}6 e^{-t/\sqrt3} \begin{bmatrix}1+\sqrt3\\1\end{bmatrix}\)

or

\(\begin{cases}x(t) = -\dfrac1{\sqrt3} e^{\sqrt3 \, t} + \dfrac1{\sqrt3} e^{-\sqrt3\,t} \\\\ y(t) = \dfrac{3+\sqrt3}6 e^{\sqrt3\,t} + \dfrac{3-\sqrt3}6 e^{-\sqrt3\,t}\end{cases}\)

Answer:

no

Step-by-step explanation:

2(2) + 3 < 2  is a False statement; therefore, 2 is not a solution

Answer:

  x + y = 6

Step-by-step explanation:

The two intercepts are given, so we can write the equation first in intercept form:

  x/x-intercept +y/y-intercept = 1

  x/6 +y/6 = 1

Multiplying by 6 gives the standard form equation:

  x + y = 6

Answer:

\(y = -3x + 6\)

Step-by-step explanation:

\(m = -3\\(4,-6)\\x = 4\\y = -6\\m = \frac{y-y_1}{x-x_1} \\-3 = \frac{y -(-6)}{x-4} \\-3 =\frac{y+6}{x-4} \\Cross-Multiply\\-3(x-4) = y+6\\-3x+12=y+6\\-3x+12-6=y\\-3x+6 = y\\y =-3x+6\)

Answer:

hi

Step-by-step explanation:

I think the answer is a number

Figuring out a common multiple of 12 and 20 we can say with the help of the factor that,

The cost of 5 one-item is equal to the cost of 3 another-item.

The cost of 10 one-item is equal to the cost of 6 another-item.

A factor is a number that divides another number, leaving no remainder

We have,

Cost of one-item = $12

Cost of another-item = $20

We can find out some common multiple of both the numbers 12 and 20.

12 x 1 = 12       20 x 1 = 20

12 x 2 = 24     20 x 2 = 40

12 x 3 = 36     20 x 3 - 60

12 x 4 = 48     20 x 4 = 80

12 x 5 = 60    20 x 5 = 100

12 x 7 = 84    20 x 6 = 120

12 x 8 = 96

12 x 9 = 108
12 x 10 = 120

We see that we have two common multiples from the above multiples.

i,e 60 and 120

Now,

The factor in the multiples are:

12 x 5 = 60

12 x 10 = 120

20 x 3 = 60

20 x 6 = 120

This means that,

The cost of 5 one-item is equal to the cost of 3 another-item.

The cost of 10 one-item is equal to the cost of 6 another-item.

Thus,

Figuring out a common multiple of 12 and 20 we can say with the help of the factor that,

The cost of 5 one-item is equal to the cost of 3 another-item.

The cost of 10 one-item is equal to the cost of 6 another-item.

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El número "Novecientos mil cuatrocientos ochenta y nueve" se representa como 900,489 en notación numérica.

Por otro lado, el número "cuarenta mil dos" se representa como 40,002.

Si estamos buscando determinar cuál de estos dos números es mayor, podemos comparar las cifras en cada posición.

Comenzando desde la izquierda, el primer dígito de 900,489 es 9, mientras que el primer dígito de 40,002 es 4.

Dado que 9 es mayor que 4, podemos concluir que 900,489 es mayor que 40,002.

En general, al comparar números, se debe observar cada posición en orden de mayor a menor importancia.

Esto significa que el primer dígito a la izquierda es el más significativo y tiene más peso en el valor total del número.

Si los dígitos en la posición más significativa son iguales, se debe pasar a la siguiente posición hasta que se encuentre una diferencia.

En este caso, dado que el primer dígito de 900,489 es mayor que el primer dígito de 40,002, no es necesario comparar los dígitos en posiciones posteriores.

Por lo tanto, podemos concluir que el número "Novecientos mil cuatrocientos ochenta y nueve" (900,489) es mayor que "cuarenta mil dos" (40,002).

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EVENT A.

We have to count in how many possible ways does the sum of the two rolls of the die add up to more than 7. The possibilities are:

6+2

6+3

6+4

6+5

6+6

5+3

5+4

5+5

5+6

4+4

4+5

4+6

3+5

3+6

2+6

Then, there is 15 ways that the sum os greater than 7. Now we have to calculate how many combinations there is in total, which is 6 possible outcomes for the first roll and other 6 for the second roll, then there is 6x6=36 possible outcomes.

The probability for event A is then 15/36 or 5/12

EVENT B:

In a similar way, we have to count how many ways there is such that the sum is even:

1+1

1+3

1+5

2+2

2+4

2+6

3+1

3+3

3+5

....

We notice that there is 3 ways for each number from the first roll. Then the total is 6*3=18 ways such that the sum is even. The total possible outomes is 6x6=36.

Hence the probability for Evenet B is 18/36 or 1/2

1.

These are Corresponding Angles, and thus by the Corresponding Angles Theorem, they are congruent.

\(4x-9=3x+29\\4x-9+9=3x+29+9\\4x=3x+38\\4x-3x=3x-3x+38\\x=38\)

2.

These are Same-Side Interior Angles and thus by the Same-Side Interior Angles Theorem they add up to 180°.

\(2x-26+7x+9=180\\9x-17=180\\9x-17+17=180+17\\9x=197\\9x/9=197/9\\x=21.9\)

3.

These are Alternate Exterior Angles and thus by the Alternate Exterior Angles Theorem they are congruent.

\(3x-2=2x+30\\3x-2+2=2x+30+2\\3x=2x+32\\3x-2x=2x-2x+32\\x=32\)

Answer:

10^8 choices

Step-by-step explanation:

You have 10 numbers to choose from for each digit of the code.

There are 8 digits of the code.

You have 10*10*10*10*10*10*10*10 = 10^8 choices in total.

Number of possible codes are  \(10^{8}\)

In mathematics, a permutation of a set is, loosely speaking, an arrangement of its members into a sequence or linear order, or if the set is already ordered, a rearrangement of its elements

Given,

Number of digits in passcode = 8

The numbers 0-9 may be used for any digit. Therefore total of 10 numbers

Here repetition is allowed.

Therefore, each of the 8 vacant place can be filled in the succession of 10 different ways

Number of possible codes are = 10×10×10×10×10×10×10×10 = \(10^{8}\)

Hence, the number of possible codes are  \(10^{8}\)

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Answer:

Step-by-step explanation:

1/2 , 2/3 , 5/6

The profit for 24 sales is $64.

The profit for 24 sales, we first need to calculate the revenue and then determine the profit based on the given information.

The revenue function is given as f(x) = 5x, where x represents the number of hamburgers sold.

To find the revenue for 24 sales, we substitute x = 24 into the revenue function:

Revenue = f(24)

= 5 × 24

= 120 dollars

Now, let's calculate the profit.

The profit is $20 less than 70% of the revenue.

We can express this mathematically as:

Profit = 0.7 × Revenue - $20

Substituting the value of Revenue we calculated earlier:

Profit = 0.7 × 120 - $20

= 84 - $20

= $64

We must first compute the revenue for 24 sales before calculating the profit based on the available data.

The revenue function is denoted by the formula f(x) = 5x, where x is the quantity of hamburgers sold.

We add x = 24 to the revenue function to get the revenue for 24 sales:

f(24) = 5 x 24 = 120 dollars is the revenue.

Let's now determine the profit.

The profit is $20 below the revenue's 70%.

This may be written mathematically as:

Revenue - $20 x Profit = 0.7

Substituting the earlier determined figure of Revenue:

Earnings = 0.7 x 120 - $20 = 84 - $20 = $64

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Answer: y = -3/2x + 5

Step-by-step explanation:

Slope-intercept form: y = mx + b

y = -3/2x + 5

Answer:

y = -3/2x + 5 totally

Step-by-step explanation:

The entire area is under the standard normal distribution curve, which is 1 by definition.

In other words, a typical normal random variable has a 100% chance of landing anywhere within its range of potential values (-∞ to +∞).

This makes sense since the area under the standard normal distribution curve, which is a continuous probability distribution, shows the likelihood that the random variable will take on any value within its range. Since the entire area under the curve is 1, the likelihood that any potential value for the random variable will occur is 1, or 100%.

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Answer & Step-by-step explanation:

In this problem, we a re given two points. These points are (-4, 3) and (-2, -1). We can use these points and put them into the slope formula.

\(Slope=\frac{y2-y1}{x2-x1}\)

Now, plug in the points to their respectful places.

\(Slope=\frac{-1-3}{-2-(-4)}\)

\(Slope=\frac{-4}{2}\)

\(Slope=-2\)

So, your slope of the the line is -2.

Answer:

Following are the solution to this question:

Step-by-step explanation:

For this set, the correlation coefficient is = -0.015.

It shows that financial variables have trust issues. Once a price rises, the other one is decreasing the value of -0,015 shows, that there are several fewer associations in the set of data among x and y and between y values. This interaction also can range between -1 to 1, to 0 being completely unrelated. But you'd never be sure, in this situation, 0.015 is very similar to 0.

It means that your prediction is nothing better than just a wild choice. Its odds of an estimated value being relatively close to the actual result are therefore much smaller as the points are it's hardly the best match.

Answer:

\(3x^2y\)

Step-by-step explanation:

The cube root of 27 is 3.

With indices, cube rooting them is the equivalent of multiplying by 1/3 so:

\(x^2y\).

Put these 2 things together and you get:

\(3x^2y\)

The table that shows the same function as the given graph is: A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 5, 6, 7.

To determine which table shows the same function as the given graph, we need to find the values of y corresponding to the given values of x on the graph.

Point A: (0, 4)

Point B: (2, 5)

Let's check each table:

A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries negative 8, negative 4, 0, 4.

A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 0, 4, 0, 4.

A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 5, 6, 7.

A 2-column table with 4 rows. Column 1 is labeled x with entries 0, 2, 4, 6. Column 2 is labeled y with entries 4, 8, 12, 16.

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Given:

Given a figure.

Required: Area of the shaded figure

Explanation:

The shaded figure can be split into two: a rectangle, triangle

The area of the shaded region is the sum of thH area of the triangleeand the area of the rectangie.

First, find the areg of thh triangle.

t of the triangle = 2 units

Base ength of te triangle = 8 units

Area of th triangle

Find the area of the rectangle.

Length of the rectangle = 4 units

Width of the rectangle = 6 units

Area of thereactanle

The ways to pack are

This is further explained below.

Generally, The science, art, and technology of packaging involves confining or safeguarding goods for distribution, storage, sale, and usage. The process of creating, analyzing, and designing packages is sometimes referred to as packaging.

In conclusion,

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hola buenas noches como estan

The lateral surface area of the figure is 456 m².

The lateral surface area of an object is the area of all the surfaces of the object, excluding its base and top (if they exist)

In this case, we have two sides triangles with a base (h) of 12 m and a height (h) of 8m each. Also, we have two side rectangles with a width (w) of 10m and a length(l) of 18m each. The rectangle at the base will be exluded.

Lateral surface area = area of 2 triangles + area of 2rectangle

Lateral surface area = 2(1/2bh + lw)

Lateral surface area = 2(1/2*12*8 + 18*10)

Lateral surface area = 2(48 + 180)

Lateral surface area = 456 m²

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Therefore, the interest portion of the seventh payment is:7,000 x (1 + r + r2 + r3 + r4 + r5 + r6) / r7 - 7,000.

We have the following payments and their corresponding times of payment:At the end of year 1: $1,000At the end of year 2: $2,000At the end of year 3: $3,000At the end of year 4: $4,000At the end of year 5: $5,000At the end of year 6: $6,000At the end of year 7: $7,000

At the end of year 8: $8,000At the end of year 9: $9,000At the end of year 10: $10,000The present value of these payments is:PMT x [(1 - (1 + r)-n) / r]where PMT is the payment, r is the interest rate per year, and n is the number of years till payment.

For the first payment (end of year 1), the present value is:1,000 x [(1 - (1 + r)-1) / r]which equals

1,000 x (1 - 1 / (1 + r)) / r = 1,000 x ((1 + r - 1) / r) = 1,000

For the second payment (end of year 2), the present value is:2,000 x [(1 - (1 + r)-2) / r]which equals 2,000 x (1 - 1 / (1 + r)2) / r = 2,000 x ((1 + r - 1 / (1 + r)2) / r) = 2,000 x (1 + r) / r2

For the seventh payment (end of year 7), the present value is:

7,000 x [(1 - (1 + r)-7) / r]

which equals

7,000 x (1 - 1 / (1 + r)7) / r = 7,000 x ((1 + r - 1 / (1 + r)7) / r) = 7,000 x (1 + r + r2 + r3 + r4 + r5 + r6) / r7

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Answer:

70

81

95

A: 46%

Step-by-step explanation:

29+41=70

135-54=81

205-110=95

A: 95 out of 205.

Divide 95 by 205.

\(\frac{19}{41}\) or 0.46341...

Switch to % and Round.

46%

I actually have no idea what b and c mean so good luck

Answer:70

81

95

Step-by-step explanation:

you subtract or add everything together to get an answer ex:29+41 thats how you get an answer of 70