3 divided by 9 is 0 with a remainder of 3, 2435 base 10 is equivalent to 3305 base 9,
To convert 2435 base 10 to base 9, we need to divide the decimal number by 9 repeatedly until the quotient is 0. We then write the remainders in reverse order as the digits of the converted number.
2435 divided by 9 is 270 with a remainder of 5, so we write down a "5" as the least significant digit (rightmost digit) of the converted number. 270 divided by 9 is 30 with a remainder of 0, so we write down a "0" as the next digit to the left.
30 divided by 9 is 3 with a remainder of 3, so we write down a "3" as the next digit to the left. 3 divided by 9 is 0 with a remainder of 3, so we write down a "3" as the most significant digit (leftmost digit) of the converted number.
Therefore, 2435 base 10 is equivalent to 3305 base 9.
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A particle moves along a straight line and its position at time t is given by s(t) = 2t^3 - 18t^2 + 30t where s is measured in feet and t in seconds. what is the total distance the particle travels between time 0 and time 10 ?
The particle travels a total distance of 120 feet between time 0 and time 10.
This particle is moving along a straight line, and its position at any time t is given by the formula s(t) = 2t^3 - 18t^2 + 30t, where s is measured in feet and t is measured in seconds.
Velocity v(t) = 6t^2 - 36t + 30.
Total distance traveled by the particle between time 0 and time 10, integrate the absolute value of the velocity function from t = 0 to t = 10.
The integral of |v(t)| from t = 0 to t = 10 is given by:
∫|v(t)|dt from 0 to 10
= ∫√(v(t)^2)dt from 0 to 10
= ∫√((6t^2 - 36t + 30)^2)dt from 0 to 10
= 120 feet
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2. The Winter Olympics have been held a total of 21 times on the continents of North America, Europe, and Asia. The number of European sites is 5 more than the total number of sites in North America and Asia. There are 4 more sites in North American than in Asia. (Source: USA Today research) Find the number of Winter Olympic sites on each continent.
Let x represent the number of winter olympics held in North America.
Let y represent the number of winter olympics held in Europe.
Let z represent the number of winter olympics held in North Asia.
The Winter Olympics have been held a total of 21 times on the continents of North America, Europe, and Asia.
This means that
x + y + z = 21
The number of European sites is 5 more than the total number of sites in North America and Asia.
This means that
y = x + z + 5
There are 4 more sites in North American than in Asia.
This means that
x = z + 4
These are the equations. We would solve simultaneously
\(\begin{gathered} x\text{ + y + z = 21} \\ y\text{ = x + z + 5} \\ x\text{ = z + 4} \\ \text{Substituting y = x + z + 5 into the first equation, it becomes} \\ x\text{ + x + z + 5 + z = 21} \\ 2x\text{ + 2z + 5 = 21} \\ \text{Substituting x = z + 4 into the above equation, it becomes} \\ 2(z\text{ + 4) + 2z + 5 = 21} \\ 2z\text{ + 8 + 2z + 5 = 21} \\ 4z\text{ + 13 = 21} \\ 4z\text{ = 21 - 13 = 8} \\ z\text{ = }\frac{8}{4} \\ z\text{ = 2} \\ We\text{ would substitute z = 2 into x = z + 4. It becomes} \\ x\text{ = 2 + 4} \\ x\text{ = 6} \\ We\text{ would substitute x = 6 and z = 2 into x + y + z = 21. It becomes} \\ 6\text{ + y + 2 = 21} \\ 8\text{ + y = 21} \\ y\text{ = 21 - 8} \\ y\text{ = 13} \end{gathered}\)The olympics was held 2 times in North America, 13 times in Europe and 6 times in Asia
Work out the value of 5 to the power of a if it equal 1/125
Answer:
a = -3
Step-by-step explanation:
Step 1: Since we're told that 5 to the power of a = 1/125, we can use the following equation to solve for a:
5^a = 1/125
Step 2: Take the log of both sides
log(5^a) = log(1/125)
Step 3: According to the power rule of logs, we can bring a down and multiply it by log(5):
a * log(5) = log (1/125)
Step 4: Divide both sides by log(5) to solve for a:
(a * log(5) = log(1/125)) / log(5)
a = -3
Optional 5: We can check our answer by plugging in -3 for a and seeing if we get 1/125 when completing the operation:
5^-3 = 1/125
1/(5^3) = 1/125 (rule of exponents states that a negative exponent creates a fraction with 1 as the numerator and the base (5) and exponent (-3 becoming 3) as the denominator
1/125 = 1/125
What’s 5x-2=25x+14? (please explain)
Answer:
x = - \(\frac{4}{5}\)
Step-by-step explanation:
Given
5x - 2 = 25x + 14 ( subtract 25x from both sides )
- 20x - 2 = 14 ( add 2 to both sides )
- 20x = 16 ( divide both sides by - 20 )
x = \(\frac{16}{-20}\) = - \(\frac{4}{5}\)
( n2 + 8n + 8 ) – ( 4n + 2 )
Answer:
2+4+6
Step-by-step explanation:
a population has a mean of 300 and a standard deviation of 18. a sample of 144 observations will be taken. what is the probability that the sample mean will be between 295 to 305?
The probability that the sample mean will be between 295 to 305 is 0.99921
Since we are given that the mean is 300 and the standard deviation of 18 and we were given a total of 144 observations.A z-score gives you a thought of how distant from the mean a data point is. A z-score can be put on a normal distribution curve. Z In arrange to utilize a z-score, you wish to know the mean μ additionally the population standard deviation σ.
The formula we are referring to for calculating the Zscore is :
Zscore = (x - mean) ÷ σ/√n
At first, let x be = 295, so the
Zscore = (295 - 300) / (18/12) = - 3.33
The probability for zscore for z<-3.33 is,
=>P(Z< - 3.33) = 0.00039
Similarly for the second part x 305, Sp
The Zscore will be (305 - 300) / (18/12) = 3.33
so the probability of z<3.33
=>P(Z< 3.33) = 0.9996
so the probability of mean between the range 295 to 305
P(Z < 3.33) - P(Z < - 3.33)
=0.9996-0.00039
= 0.99921
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Please help for 30 points
In statistical process control, when a point falls outside of control limits, the probability is quite high that the process is experiencing _____________ .
A. common cause variation
B. student t variation
C. a reduction of variables
D. special cause variation
When a point falls outside of control limits in statistical process control, the probability is quite high that the process is experiencing special cause variation.
In statistical process control (SPC), control limits are used to define the range within which a process is expected to operate under normal or common cause variation. Common cause variation refers to the inherent variability of a process that is predictable and expected.
On the other hand, special cause variation, also known as assignable cause variation, refers to factors or events that are not part of the normal process variation. These are typically sporadic, non-random events that have a significant impact on the process, leading to points falling outside of control limits.
When a point falls outside of control limits, it indicates that the process is exhibiting a level of variation that cannot be attributed to common causes alone. Instead, it suggests the presence of specific, identifiable causes that are influencing the process. These causes may include equipment malfunctions, operator errors, material defects, or other significant factors that introduce variability into the process.
Therefore, when a point falls outside of control limits in statistical process control, it is highly likely that the process is experiencing special cause variation, which requires investigation and corrective action to identify and address the underlying factors responsible for the out-of-control situation.
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given a box of 12 identical looking chocolates, six with nuts and six with strawberries, what is the probability of picking and eating three chocolates in this order: nut, nut, strawberry?
The probability of picking strawberry chocolate as the third chocolate is 6/10 or 3/5. So the overall probability of picking and eating three chocolates in the order nut, nut, strawberry is (1/2) x (5/11) x (3/5) which equals 15/110 or approximately 0.136 or 13.6%.
To find the probability of picking and eating three chocolates in the order of nut, nut, and strawberry, we'll use the concept of probability.
The probability of picking nut chocolate from the box is 6/12 or 1/2. Once a nut chocolate has been chosen and eaten, there are now 5 left in the box out of which 5/11 or approximately 0.45 are nut chocolates. So the probability of picking another nut chocolate is 5/11. Finally, once the second nut chocolate has been eaten, there are 4 left in the box out of which 6/10 or 0.6 are strawberry chocolates.
There are 12 chocolates in total: 6 with nuts and 6 with strawberries.
1. Probability of picking a nut on the first attempt: 6/12 (6 nuts out of 12 chocolates)
2. Probability of picking a nut in the second attempt: 5/11 (5 nuts out of 11 remaining chocolates)
3. Probability of picking a strawberry on the third attempt: 6/10 (6 strawberries out of 10 remaining chocolates)
To find the overall probability, multiply the individual probabilities:
Probability = (6/12) * (5/11) * (6/10) = 1/2 * 5/11 * 3/5 = 3/22
So, the probability of picking and eating three chocolates in the order of nut, nut, and strawberry is 3/22.
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In this triangle, what is the value of x?
Enter your answer,
rounded to the nearest tenth, in the box.
Answer:
x = 75.7 cm
Step-by-step explanation:
sin = opp/hyp
sin63 = x/85
multiply both sides by 85
85 * sin63 = x
Use calculator
75.735554556011268 = x
Rounded
x = 75.7 cm
If A is an mÃn matrix then ATA and AAT are both defined
If A is an m×n matrix, then both ATA and AAT are defined.
If A is an m×n matrix, then both ATA and AAT are defined.
The matrix ATA is the product of the transpose of A and A itself. It is a square matrix of size n×n.
The matrix AAT is the product of A and the transpose of A. It is a square matrix of size m×m.
Both ATA and AAT are important and commonly used in linear algebra and statistics. The matrix ATA arises in the context of least squares regression, while AAT arises in the context of principal component analysis (PCA) and singular value decomposition (SVD).
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i dont know how to do this
Option C, D, E are correct answer.
What is Sine Rule of Triangle ?
According to the sine rule ,
sinA/a = sin B/b = sin C/c
In the given question ,
the data given is
sin 90/EF = sin30 / FG= sin 60/EG
1/EF = 0.5/FG =( \(\rm \sqrt{3}\) /2 ) / EG
From this we get ,
EF = 2FG
EG = ( \(\rm \sqrt{3}\) /2 )EF
EG = \(\rm \sqrt{3}\) FG
Therefore , Option C, D, E are correct answer.
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Please help with this math problem! I am giving brainliest! :)
Answer: Heyy BFF The Answer is x= -8 or x=10
Step-by-step explanation: Stay Sliving ❤️
karl is 4 years older than danny. eigt years ago carl was twice as old as danny. How old is danny now
Answer:
Karl is 16 and Danny is 12
Step-by-step explanation:
Divide ₹960 between Manu and Swapna in the ratio 5: 7
Answer: 400 : 560
Step-by-step explanation:
add 5 and 7 = 12
960/12 = 80
multiply the numbers again to get the right ratio
(5 x 80) : (7 x 80)
= 400 : 560
Ratio gives the fractional division of a whole into a given portion. Manu's will get 400 while Swapna will get 560.
To divide 960 in the ratio 5 : 7
Sum the ratio = (5 + 7) = 12 Manu's share = 5 × (960/12) = 400Swapna's share = 7 × (960/12) = 560Therefore, Manu and Swapna's share is 400 and 560 respectively.
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3) The road centerline asignment below: Given: the distance from Point A to Pls is 222.841 the distance from Point Ply to Ply is 345.036 the distance from Point Pl
2
to b is 214.761 If the station of Point A is 3+ def ghi, determine the station of BC1,EC
1
,BC, and EC
2
The stationing of BC1, EC1, BC, and EC2 can be determined by adding the respective distances to the station of Point A.
To determine the station of BC1, EC1, BC, and EC2, we need to understand the concept of stations in road centerline alignment. In road design and construction, stations are used to measure distances along the centerline of the road. The station of a point refers to its distance from a reference point, typically the starting point of the road.
Given that the station of Point A is 3+ def ghi, we can assume that the stationing system used is based on chainage, where the main stations are represented by whole numbers and the sub-stations are represented by decimals or fractions.
Let's break down the given distances:
The distance from Point A to Pls is 222.841.
The distance from Point Ply to Ply is 345.036.
The distance from Point Pl2 to b is 214.761.
Based on the given information, we can determine the stations as follows:
Station of Point A: 3+ def ghi (given).
Station of BC1: Station of Point A + Distance from Point A to Pls = 3+ def ghi + 222.841.
Station of EC1: Station of BC1 + Distance from Point Ply to Ply = (3+ def ghi + 222.841) + 345.036.
Station of BC: Station of EC1 + Distance from Point Pl2 to b = ((3+ def ghi + 222.841) + 345.036) + 214.761.
Station of EC2: Station of BC + Distance from Point Pl2 to b = ((3+ def ghi + 222.841) + 345.036 + 214.761) + 214.761.
The above equations represent the stationing along the road centerline from Point A to BC1, EC1, BC, and EC2, respectively. By substituting the given station of Point A and the distances into the equations, we can calculate the stations of BC1, EC1, BC, and EC2.
Please note that the specific numerical values for def, ghi, and the distances are not provided in the question, so the actual station values cannot be determined without those values. However, you can substitute the known values into the equations to calculate the stations once you have the complete information.
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emily likes to read but does not want to spend more than $45 at the bookstore. paperback books cost $4.50 each and hard cover books cost $10 each. which graph best represents the number of paperback books and the number of hardcover books emily can buy?
The graph that best represents the number of paperback and hardcover books Emily can buy within her budget is a scatter plot with the points (0,4), (2,3), (4,2), (6,1), and (8,0) connected by a line.
To determine which graph best represents the number of paperback and hardcover books Emily can buy within her budget, we need to consider the cost of each type of book and her spending limit. Since Emily wants to spend no more than $45, we can create an equation to represent her budget:
4.5p + 10h ≤ 45
Where p is the number of paperback books and h is the number of hardcover books she can buy.
To graph this equation, we can first solve for h:
10h ≤ 45 - 4.5p
h ≤ 4.5 - 0.45p
This shows that the maximum number of hardcover books Emily can buy depends on the number of paperback books she purchases.
Next, we can create a table to show the different combinations of paperback and hardcover books that fit within her budget:
| # of Paperbacks | # of Hardcovers | Total Cost |
|----------------|----------------|------------|
| 0 | 4 | $40 |
| 2 | 3 | $40.50 |
| 4 | 2 | $41 |
| 6 | 1 | $41.50 |
| 8 | 0 | $42 |
From this table, we can see that Emily can buy a maximum of 8 paperback books or 4 hardcover books within her budget. To graph this information, we can create a scatter plot with the number of paperback books on the x-axis and the number of hardcover books on the y-axis. We can then plot the points (0,4), (2,3), (4,2), (6,1), and (8,0) and connect them with a line to show the maximum number of books Emily can buy within her budget. Therefore, the graph that best represents the number of paperback and hardcover books Emily can buy within her budget is a scatter plot with the points (0,4), (2,3), (4,2), (6,1), and (8,0) connected by a line.
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help ASAP I will Mark brainliest
Answer:
g=-4/5
Step-by-step explanation:
-25/32g=5/8
-200g=160
g=-4/5
Answer:
the answer is g= -4/5 if u want decimal form its g=-0.8
When tossing a two-sided, fair coin with one side colored yellow and the other side colored green, determine P(yellow).
yellow over green
green over yellow
2
one half
The calculated value of the probability P(yellow) is 0.5 i.e. one half
How to determine P(yellow).From the question, we have the following parameters that can be used in our computation:
Sections = 2
Color = yellow, and green
Using the above as a guide, we have the following:
Yellow = 1
When the yellow section is selected, we have
P(yellow) = yellow/section
The required probability is
P(yellow) = 1/2
Evaluate
P(yellow) = 0.5
Hence, the value is 0.5
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Will give brainliest
Answer:
21
Step-by-step explanation:
Consider the points below. P(θ),−4,0),Q(5,1,−2),R(6,4,1) (a) Find a nonzero vector orthogonal to the plane through the points P,Q, and R. (b) Find the area of the triangle PQR.
(a) A nonzero vector orthogonal to the plane through the points P, Q, and R is (9, -17, 35). (b) The area of triangle PQR is \(\sqrt\)(811) / 2.
(a) To determine a nonzero vector orthogonal to the plane through the points P, Q, and R, we can first find two vectors in the plane and then take their cross product. Taking vectors PQ and PR, we have:
PQ = Q - P = (5, 1, -2) - (-4, 0, 0) = (9, 1, -2)
PR = R - P = (6, 4, 1) - (-4, 0, 0) = (10, 4, 1)
Taking the cross product of PQ and PR, we have:
n = PQ x PR = (9, 1, -2) x (10, 4, 1)
Evaluating the cross product gives n = (9, -17, 35). Therefore, (9, -17, 35) is a nonzero vector orthogonal to the plane through points P, Q, and R.
(b) To determine the area of triangle PQR, we can use the magnitude of the cross product of vectors PQ and PR divided by 2. The magnitude of the cross product is given by:
|n| = \(\sqrt\)((9)^2 + (-17)^2 + (35)^2)
Evaluating the magnitude gives |n| = \(\sqrt\)(811).
The area of triangle PQR is then:
Area = |n| / 2 = \(\sqrt\)(811) / 2.
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The latitude of Independence Hall in Philadelphia is located at 39.948859°
What is the measurement in degrees, minutes, and seconds?
Round your seconds to the nearest tenth.
Remember that 1° = 60' and 1' = 60".
You must show your work to receive full credit.
The latitude of Independence Hall in Philadelphia is given as 39.948859°. Therefore, the latitude of Independence Hall can be expressed as 39° 56' 55.9"
To convert the given latitude into degrees, minutes, and seconds, we follow the conversion rules.
First, we take the whole number part of the latitude, which represents the degrees. In this case, the degrees are 39.
To find the minutes, we multiply the decimal part of the latitude by 60 since 1° is equivalent to 60 minutes. Thus, 0.948859 * 60 = 56.93154.
Next, we take the whole number part of the minutes, which is 56, to represent the minutes.
To find the seconds, we multiply the decimal part of the minutes by 60 since 1' is equivalent to 60 seconds. Thus, 0.93154 * 60 = 55.8924. Rounding this to the nearest tenth, we get 55.9.
Therefore, the latitude of Independence Hall can be expressed as 39° 56' 55.9", where the whole number part represents the degrees, the next whole number part represents the minutes, and the rounded decimal part represents the seconds.
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find the area of the shape below
Answer:
34?
Step-by-step explanation:
I think 34 because 3×3 is equal to 9. 5×5 is equal to 25. If you add 9+25, you would get 34.
Answer:
24 cm²
Step-by-step explanation:
the area = ½× (3+3) × (5+3)
= ½× 6×8
= 3×8
= 24 cm²
 The product of two consecutive odd integers is 195.
Answer:
13 and 15
OR
-15 and -13
Step-by-step explanation:
I suppose you want to find the value of the integers.
Let the smaller integer be x, and the larger be x + 2 (since they're both odd, the larger one is 2 more than the smaller)
(x)(x+2) = 195
x^2 + 2x = 195
x^2 + 2x -195 = 0
Using the quadratic formula,
x = 13 or -15
Since it did not mention whether the integers are positive or negative or both, x can be 13 or -15.
If x is 13, the 2 integers will be 13 and 15.
If x is -15, the 2 integers will be -15 and -13.
Answer:
Two consecutive odd numbers whose product is 195 is either 13 & 15 or -15 & -13.
Step-by-step explanation:
Two consecutive odd integers can be defined as: x and y.
A better way to define y is to say it = x+2, which means you have only one unknown.
We're told x*y = 195, so we can substitute y=x+2.
.
x(x+2) = 195
x^2 + 2x = 195
x^2 + 2x - 195 = 0
Factoring...
(x + 15)(x - 13) = 0
.
So, x can = -15 or 13.
.
Since the question does not say "positive consecutive odd numbers", we need to check both to ensure they're both solutions.
.
x = -15
y = x+2 = -13
(-13)*(-15) = 195
.
x = 13
y = x+2 = 15
13*15 = 195
le 1. Solve the seperable differential equation: dx 2. Solve the linear differential equation: y' + 3y = sin 2x e2xsin²y
The first differential equation, dx = 2, is a separable equation. Integrating both sides gives the solution x = 2t + C, where C is the constant of integration.
The second differential equation, y' + 3y = sin(2x)e^(2x)sin²y, is a linear equation. Using the integrating factor method, we multiply the equation by e^(3x) and rewrite it as (e^(3x)y)' = sin(2x)e^(5x)sin²y.
Integrating both sides yields e^(3x)y = ∫sin(2x)e^(5x)sin²y dx. The right side integral requires further evaluation, and the specific steps depend on the provided limits or initial conditions.
Thus, the solution to the linear equation is given by e^(3x)y = ∫sin(2x)e^(5x)sin²y dx, requiring appropriate techniques to solve the integral based on the problem's specific conditions.
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suppose that two boys named davis, three boys named jones, and four boys named smith are seated at random in a row containing nine seats. what is the probability that the davis boys will occupy the first two seats in the row, the jones boys will occupy the next three seats, and the smith boys will occupy the last four seats?
The probability that the Davis boys will occupy the first two seats in the row, the Jones boys will occupy the next three seats, and the Smith boys will occupy the last four seats is 7.937×\(10^{-4}\).
There are \(\left[\begin{array}{ccc}9\\2,3,4\\\end{array}\right]\) potential arrangements for the nine boys if we do not make a distinction amongst boys with the same last name. We are curious in the likelihood of a specific one of these configurations.
Probability = \(\frac{1}{\left[\begin{array}{ccc}9\\2,3,4\\\end{array}\right]}\)
= \(\frac{2!3!4!}{9!}\)
= 0.0007937
= 7.937×\(10^{-4}\)
Hence, the probability is 7.937×\(10^{-4}\).
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What is the value of x?
Please help
Step-by-step explanation:
\(360 = 60 + 4x \\ 360 - 60 = 4x \\ 300 = 4x \\ \frac{300}{4} = \frac{4x}{4} \\ x = 75\)
The total internal angle of the polygon is 360°. Since there are 4 unknown angles but the same, we would just add all those to 60° to equal a full 360°.
Find the vertex. f(x) = 6(x + 5)^2-10
the given equation is
\(f(x)=6(x+5)^2-10\)compare the above equation with the standard parabola equation,
\(y=a(x-h)^2+k\)here, h and k represent a vertex of the equation
compare both the expression.
h = - 5
and
k = - 10
So, the vertex of the equation is (h, k) = (-5 , -10).
combining light term's
4z-(-3z)
Answer:
7z
Step-by-step explanation:
Which of the following correlation coefficients would represent the strongest correlation? -0.9 -0.16 0.04 .78
Answer:
0.4 would represent the strongest correlation.
Step-by-step explanation:
Generally, a value of r greater than 0.7 is considered a strong correlation. Anything between 0.5 and 0.7 is a moderate correlation, and anything less than 0.4 is considered a weak or no correlation