Answer: The common difference between surface EMG and intramuscular EMG is that that former is non-invasive while the later is an invasive method
Explanation:
Electromyography (EMG) is used clinically for the examination of muscle excitations (muscle electrical activity) in both normal or abnormal conditions. There are two forms of EMG includes:
--> Surface EMT and
--> Intramuscular EMT
Surface EMT is a non invasive method of examination of muscle excitations for superficial and easily accessible muscles.
Intramuscular EMT is the invasive method of examination of muscle excitations usually for deep muscles.
The difference between the two forms of EMT includes:
- surface EMT is non- invasive while intramuscular EMT is invasive
- surface EMT is used to access superficial muscle while intramuscular EMT is used to access deep muscles.
- surface EMT requires less skill and time to carry out while intramuscular EMT requires special skills and takes more time while carrying out the procedure.
The difference between surface EMG and intramuscular EMG is that surface EMG is non-invasive while intramuscular EMG recording is an invasive method.
Electromyography is simply used for the examination of muscle excitations in both normal and abnormal conditions. It is the diagnostic procedure that is used in assessing the health of muscles.
It should be noted that surface EMT is a non-invasive method of examination of muscle excitations while intramuscular EMT is an invasive method of examination of muscle.
Also, the surface EMT is used to access superficial muscle while on the other hand, intramuscular EMT is used to access deep muscles.
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11.
How can we increase pressure?
Reducing surface area
Increasing surface area
Reducing force
If the surface area becomes smaller, the pressure becomes larger.
Steelhead trout migrate upriver to spawn. Occasionally they need to leap up small waterfalls to continue their journey. Fortunately, steelhead are remarkable jumpers, capable of leaving the water at a speed of 8.0 m/s. What is the maximum height that a steelhead can jump
Answer:
s = 3.26 m
Explanation:
Given that,
Water leaves at a speed of 8 m/s
We need to find the maximum height that steelhead can jump. Let it can jump to a height of h.
At maximum height, final speed is equal to 0. We can use third equation of motion to find the maximum height.
\(v^2-u^2=2as\)
a = -g
\(-u^2=-2gs\\\\s=\dfrac{u^2}{2g}\\\\s=\dfrac{(8)^2}{2\times 9.8}\\\\=3.26\ m\)
Hence, the maximum height is 3.26 m.
An ant crawls 0.30 m to the east and 4.60 m north. What is the ant's total distance from its starting point?
The total distance of the ant from its starting point is 4.6 m.
How to determine the distanceThe following data were obtained from the question:
Displacement 1 = 0.3 m eastDisplacement 2 = 4.6 mResultant displacement (R) =?The total distance from the starting point can be obtained by calculating the resultant displacement (R) as illustrated below:
R² = (Displacement 1)² + (Displacement 2)²
R² = 0.3² + 4.6²
R² = 0.09 + 21.16
R² = 21.25
Take the square root of both side
R = √21.25
R = 4.6 m
Thus, we can conclude that the distance of the ant from its starting point is 4.6 m.
See photo for diagram
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A cup containing 25 mL of hot water and a similar cup containing 25 mL of cold water is placed on a table in a room at 21°C. Which of the following
graphs shows the most likely change in temperature for each cup from 0 min to 40 min?
Tools -
By observing the graph we get : hot above 21 going towards 21, cold below 21 going towards 21
How to read a graph?Examine your data.
If necessary, compute an average for each of your experiment's trials.
Be sure to give each table and graph a clear label.
Put the dependent variable on the y-axis and the independent variable on the graph's x-axis.
Graphs present information to you as a picture or visual representation. This knowledge is referred to as "data." When you put data into a picture, it can appear lean or bulky, lengthy or short. In other words, there are occasions when we have a ton of data, which calls for numerous graphs.
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The much more likely temperature change for each cups from 0 min - 40 min is shown by warm above 21 heading towards 21 and chilly below 21 going near 21.
What is temperature?The temperature of the system serves as a proxy for its overall kinetic energy. The temperature of a system rises as the kinetic energy of the system begins to rise as even the particle's velocity rises. Heat is the term used to describe the energy that is transmitted between two components with different temperatures.
What is the temperature process?The temperatures of an element is the most accurate analog for something akin to the angular momentum of a particle. The average energy of an object's constituent particles can be calculated along with its temperature. As the temperature increases, the molecules travel more rapidly.
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An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
Which is the absolute location of St. Louis, Missouri?
38 ½° N, 90 ½° W
near the border of Missouri and Illinois
southwest of Chicago, Illinois
42° N, 100° W
Map of U S showing Iowa, Illinois, Indiana, Missouri, Kentucky, Chicago, Indianapolis, Saint Louis, forty degrees North, and ninety degrees West
Answer:
The first is the closest in absolute values.
The second two are vague and the last is approximate.
Find the electric field at a point midway between two charges of +40.0x10^-9C and +60.0x10^-9C separated by a distance of 30.0cm
The total electric field produced by the charges at the midpoint is
8 x 10³ N/C.
Amount of charge on the first particle, q₁ = 40 x 10⁻⁹C
Amount of charge on the second particle, q₂ = 60 x 10⁻⁹C
Distance between the charges, r = 30 cm = 0.3 m
The expression for the electric field due to the charges is given by,
E = 1/4πε₀ x q/r²
At the midpoint between the two charges, d = 0.15 m
So, the electric field produced by the charge q₁ at the midpoint is,
E₁ = 1/4πε₀ x q₁/d²
E₁ = 9 x 10⁹ x 40 x 10⁻⁹/(0.15)²
E₁ = 1.6 x 10⁴ N/C
So, the electric field produced by the charge q₂ at the midpoint is,
E₂ = 1/4πε₀ x q₂/d²
E₂ = 9 x 10⁹ x 60 x 10⁻⁹C/(0.15)²
E₂ = 2.4 x 10⁴ N/C
Therefore, the total electric field produced by the charges at the midpoint is,
E = E₂ - E₁
E = 2.4 x 10⁴- 1.6 x 10⁴
E = 8 x 10³ N/C
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Manganese-52 has a half-life of 6 days. How many days would a scientist have to wait for the radioactivity to be 12.5% the starting amount?
Answer:
Let N = N0 where N0 is the number of atoms originally present.
In 6 days N = N0 / 2
In 12 days N = N0 / 4
In 18 days N = N0 / 8 = .125 N0
So it would take 18 days.
Manganese-52 has a half-life of 6 days. a scientist has to wait 18 days for the radioactivity to be 12.5% of the starting amount
What is radioactivity?The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity. This radiation is released when a nucleus undergoes radioactive decay and transforms into a different isotope that may be radioactive (unstable) or non-radioactive depending on the number of neutrons and protons in the nucleus (stable).
As given in the problem statement Manganese-52 has a half-life of 6 days. this means after 6 days Manganese-52 will reduce to its half value
similarly, after 12 days it further reduces to 50% of the previous value which would be 25 %
Similarly, after 18 days, it will reduce 50% from the previous value which comes out to be 12.5 %
Thus, The half-life of manganese-52 is 6 days. It takes 18 days for the radioactivity to drop to 12.5% of the initial level.
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Two balls are held at a point 75m above the ground . One of the balls is projected vertically down with a velocity 10meters per second and the other released at the same time to fall freely . calculate the difference in time for the arrival on the ground . acceleration is 10 .
The difference in time for the arrival on the ground 7.5 second.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Initial height of the two balls: h = 75 meter.
Acceleration due to gravity: g = 10 m/s².
The time difference between ball vertically projected down with a velocity 10meters per second and the ball released at the same time to fall freely is = 75/10 second = 7.5 second.
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A solid cylinder of mass m and radius R rolls down a ramp, starting from rest at a height h above a nearby horizontal surface. The coefficients of kinetic and static friction and are non-zero, and sufficiently large that the cylinder rolls down the ramp without slipping. Assume that the coefficient of rolling friction is zero. As the cylinder leaves the ramp, it continues along a horizontal surface (with the same frictional coefficients as the ramp).
Required:
What is the speed V of the cylinder after it has traveled a distance D along the horizontal surface?
Answer:
the volocity is 50
Explanation:
How high must a 19.0kg object be to have 915.J of gravitational potential energy?170.m729m0.203m4.91m
The gravitational potential energy is given by:
\(U=mgh\)where m is the mass of the object, g is the gravitational acceleration (which is 9.8 meters per second per second) and h is the height.
In this case, we know that:
• The potential energy is 915 J
,• The mass is 19 kg
Plugging these values and solving for h we have:
\(\begin{gathered} 915=(19)(9.8)h \\ h=\frac{915}{(19)(9.8)} \\ h=4.91 \end{gathered}\)Therefore, the height of the object has to be 4.91 m
Three bulbs_ two of which contain different gases and one of which is empty; are connected as shown in drawing (a). Which drawing (b) - (d) best represents the system after the stopcocks are opened and the system is allowed to come to equilibrium? drawing (d) drawing (b) drawing (c}
Drawing (d) best represents the system after the stopcocks are opened and the system is allowed to come to equilibrium, as it shows equal pressure in all three bulbs.
Since the two bulbs contain different gases, the pressures in each bulb will be different. When the stopcocks are opened, the gases will flow into the empty bulb until the pressures are equalized. The final state will have equal pressure in all three bulbs.
What is an equilibrium?
An equilibrium is a state of balance or stability achieved in a chemical reaction when the forward reaction rate is equal to the reverse reaction rate. In other words, it is the point at which the concentrations of reactants and products no longer change with time, because the rates of the forward and reverse reactions are equal.
At equilibrium, the amounts of reactants and products are governed by the equilibrium constant (K), which is a measure of the relative concentrations of the reactants and products at equilibrium.
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Your friend's Frisbee has become stuck 19 m above the ground in a tree. You want to dislodge the Frisbee by throwing a rock at it. The Frisbee is stuck pretty tight, so you figure the rock needs to be traveling at least 4.1 m/s when it hits the Frisbee.
If you release the rock 1.8 m above the ground, with what minimum speed must you throw it?
Answer:
18.36 m/s
Explanation:
We can solve this using conservation of energy. The energy in the system will be conserved since there are no outside forces acting upon it so the potential energy and kinetic energy will be equal. Giving us this formula to start:
1/2mv^2=mgh
m=mass
g=gravity
h=height
v=velocity
We can start by figuring out the total height the rock travels which we can do by subtracting the height of the frisbee by the height the rock started at.
19m-1.8m=17.2m
Now we can plug in our variables to solve for velocity.
First we negate mass since its on both sides and cancels out leaving us with.
1/2v^2=gh
Plug in.
1/2v^2=(9.8)(17.2)
1/2v^2=168.56
v^2=337.12
v=18.36m/s
in 10 minutes a heart can beat 700 times at this rate in how many minutes will a heart beat 140 times at what rate can a heart beat
A gun is fired with muzzle velocity 1114 feet per second at a target 4950 feet away. Find the minimum angle of elevation necessary to hit the target. Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in degrees.
Answer:
The elevation angle is \(\theta = 3.67^o\)
Explanation:
From the question we are told that
The velocity is \(u = 1114\ ft/s\)
The range of the bullet projection is \(R = 4950 \ ft\)
The initial height of bullet is \(h_1 = 0 \ ft\)
Range of this bullet projection is mathematically represented as
\(R = \frac{u^2 sin (2 \theta )}{g}\)
=> \(\theta = \frac{sin ^{-1} [\frac{R * g }{ u^2} ]}{2}\)
Here \(g = 32 ft/s^2\)
substituting values
\(\theta = \frac{sin ^{-1} [\frac{4950 * 32 }{ 1114^2} ]}{2}\)
\(\theta = 3.67^o\)
Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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What is the potential energy of a train car that has a mass of 1600 kg sitting 120 meters above the track
Answer:
\(\boxed {\boxed {\sf 1,881, 600 \ Joules}}\)
Explanation:
Potential energy is the product of mass, gravitational acceleration, and height.
\(E_p= mgh\)
The mass is 1600 kilograms and the height is 120 meters. Assuming this is on Earth, then the gravitational acceleration is 9.8 meters per square second.
\(m= 1600 \ kg\\g= 9.8 \ m/s^2 \\h= 120 \ m\)
Substitute the values into the formula.
\(E_p= ( 1600 \ kg )( 9.8 \ m/s^2)( 120 \ m)\)
Multiply the first two numbers.
\(E_p= 15680 \ kg*m/s^2 (120 \ m )\)
Multiply again.
\(E_p= 1881600 \ kg*m^2/s^2\)
1 kg square meter per square second is equal to 1 Joule. Our answer is equal to 1881600 Joules\(E_p= 1881600 \ J\)
The train's potential energy is 1,881,600 Joules.
6.
Atorvastatin is one of the most important medications in the United States. It reacts with a liver
enzyme to cause a decrease in cholesterol levels. Provided below is a graph showing how different
daily doses of atorvastatin affects cholesterol levels over several weeks.
Which of the following conclusions can be made based on the provided graph?
Change in cholesterol
10
-10-
0
-20
-30
-40
-50
-60
-70
Baseline
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Week 2
Time
-
Week 4
0 mg
2.5 mg
5 mg
10 mg
20 mg
40 mg
80 mg
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biss to ebay
Week 6 ms embe su seu A
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A. 80 mg of atorvastatin lowered cholesterol levels the least.
B. 2.5 mg of atorvastatin lowered cholesterol levels the most.
C. The biggest change in cholesterol levels occurred between weeks 2 to 6 of any dose. in
R. The biggest change in cholesterol levels occurred during the first 2 weeks of any dose.by.A
17
I
Based on the provided information, we can make the following conclusions that C. The biggest change in cholesterol levels occurred between weeks 2 to 6 of any dose.
How to explain the informationIt should be noted that the information does not show the specific cholesterol level changes for the 2.5 mg dose. The graph only provides data up to the 40 mg dose.
The biggest change in cholesterol levels occurred between weeks 2 to 6 of any dose: This conclusion is supported by the graph. It shows a significant decrease in cholesterol levels from baseline to week 6 for all the different doses of atorvastatin.
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Based on the provided graph, we can make the following conclusions:
A. 80 mg of atorvastatin lowered cholesterol levels the least:
B. 2.5 mg of atorvastatin lowered cholesterol levels the most:
C. The biggest change in cholesterol levels occurred between weeks 2 to 6 of any dose:
D. The biggest change in cholesterol levels occurred during the first 2 weeks of any dose:
14. One major difference between the Governor of Illinois and President of the United
States is
a. the President has veto power
b.the Governor has veto power
c.the President has line-item veto power d.the Governor has line-item veto power
Win
Answer:
The power of the President to refuse to approve a bill or joint resolution and thus prevent its enactment into law is the veto. The president has ten days (excluding Sundays) to sign a bill passed by Congress. A regular veto occurs when the President returns the legislation to the house in which it originated, usually with a message explaining the rationale for the veto. This veto can be overridden only by a two-thirds vote in both the Senate and the House. If this occurs, the bill becomes law over the President's objections. A pocket veto occurs when Congress adjourns during the ten-day period. The president cannot return the bill to Congress. The president's decision not to sign the legislation is a pocket veto and Congress does not have the opportunity to override.
Answer this
a) which ink is likely to be pure? Why?
b) What does the chromatography tell us about ink Y
c) Why are the three different spots separated out from ink Y found at different heights?
Answer:
a) Ink X is likely to be pure because it only contain 1 spot.
b) The chromatography tell us about ink Y that it is a mixture as it contain more than 1 spot.
c) The three different spots are separated out from ink Y at different heights beacaus different substance have different solubility.
The different spots from Y are found at various heights because they represent different compounds.
What is chromatography?The term chromatography has to do with a method of separating the component of a substance. The term chromatography originally means color writing.
We can see that the pure ink is the ink marked X. We can see from the chromatogram that Y is a mixture of colors. The different spots from Y are found at various heights because they represent different compounds.
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A 1,500-kg truck has a net force of 4,200 N acting on it. What is the truck’s acceleration?
Answer:
Acceleration = 2.8 m/s²
Explanation:
Given the following data;
Mass = 1500 kg
Net force = 4200 Newton
To find the truck's acceleration;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
\( Acceleration = \frac {Net \; force}{mass} \)
Substituting into the formula, we have;
\( Acceleration = \frac {4200}{1500} \)
Acceleration = 2.8 m/s²
A model airplane with mass 1.3 kg hangs from a rubber band with springconstant 20 N/m. How much is the rubber band stretched when the modelhangs motionless?A. 0.78 mB. 0.23C. 0.64 mO D. 0.082 mSUBMIT
Answer:
\(x\approx0.64\text{ m}\)Step-by-step explanation:
The weight of the airplane is hanging from the rubber band is represented by the multiplication between its mass (1.3 kg) and the acceleration due to gravity, which is 9.8 m/s^2.
\(\begin{gathered} W=m\cdot g \\ W=1.3\cdot9.8 \\ W=12.74\text{ N} \end{gathered}\)This situation can be modeled by Hook's law, which states that the force acting on a spring is given by:
\(\begin{gathered} F=kx \\ \text{where,} \\ k=\text{ spring constant} \\ x=displacement\text{ of the spring with respect to its equilibrium position} \end{gathered}\)Substituting the given values, F=12.74 N and k=20 N/m.
Isolate x and solve:
\(\begin{gathered} x=\frac{12.74}{20} \\ x=0.637 \\ x\approx0.64\text{ m} \end{gathered}\)A 50gram bracelet is suspected of not being pure gold. It is dropped into a glass of water and 4 cm3of water overflows. Is the bracelet pure gold? How do you know?
Since, density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
To know if the bracelet is pure gold, we calculate the density of the bracelet and compare it to the density of pure gold (19.3 g/cm³).
That is, for the bracelet to pure gold,
Density of bracelet ≈ 19.3 g/cm³
What is Density?Density can be defined as the ratio of the mass and the volume of a substance.
The formula of Density is give as
D = m/v................... Equation 1⇒ Where:
D = Density of the braceletm = mass of the braceletv = volume of the braceletFrom the question,
⇒ Given:
m = 50 gv = 4 cm³ (an object displace an amount of water equal to it's own volume)⇒ Substitute these values into equation 1
D = 50/4D = 12.5 g/cm³Hence, since the density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.
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The amount of energy needed to a power a 0.20kw bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of
The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.
To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:
Potential energy (PE) = mass (m) × gravity (g) × height (h)
Where:
m = 2.5 kg (mass of the object)
g = 9.8 m/s² (acceleration due to gravity on Earth)
h = ? (height)
First, let's find the height (h) by rearranging the formula:
h = PE / (m × g)
Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):
Energy (E) = power (P) × time (t)
E = 0.20 kW × 1 min × 3,600 J/kW
Now, we can substitute the values into the equation to find the height:
h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)
Calculating the expression on the right side:
h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)
Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.
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which items can be classified as matter? check all that apply?
-pencil
-oxygen
-idea
-horse
-dream
Answer:horse
Explanation:
An object has a mass of 450g. What is the gravitational force of the object by earth?
Answer:
4.41N or 4.5N (check explanation)
Explanation:
450g = 0.45kg
F = ma
Using 10m/s² = 10(0.45) = 4.5N
Using 9.8m/s² = 9.8(0.45) = 4.41N
Temperatures expressed in the Kelvin scale are _______ higher than temperatures in the Celsius scale.
Answer:
273 degrees higher
Explanation: hope this helps ;)
Answer:
273°k
Explanation:
In a wire a current of 6 A is flowing for 6 seconds. How much charge has flown through the wire during that time?
For brainliest
Answer:The answer is 36 since every second it give 6 that would be 6x6 which equal 36
Explanation:
36 Coulomb of electric charge is flowing through the wire.
Explanation:
Given that,
Current flowing in the wire, I = 6 A
Time, t = 6 seconds
To find,
The charge flowing through the wire.
Solution,
The rate of flow of electric charge per unit time is called electric current. Mathematically, the electric current is given by :
\(I=\dfrac{q}{t}\\\\q=It\)
Putting all the values,
\(q=6\times 6\\\\q=36\ C\), C is coulomb
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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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Consider a ball on a circular track. The ball is slowly coming to a stop which takes 15.0 seconds. At the start, the ball was moving around with 9.13 rad/s. Calculate the angular deceleration if the ball traveled across 90 radians.
The answer should be -0.42 rad/s2
I don't know how to solve it
The angular deceleration of the ball is -0.42 rad/s².
What is angular acceleration?Angular acceleration is a measure of the rate of change of angular velocity of an object rotating about an axis. When an object rotates, its angular velocity (ω) can change as a result of various factors, such as the application of an external torque or the redistribution of mass in the object.
We can use the formula for angular acceleration:
α = (ωf - ωi) / t
where
α is the angular acceleration
ωi is the initial angular velocity
ωf is the final angular velocity (which is zero in this case since the ball comes to a stop)
t is the time it takes for the ball to come to a stop
To find the initial and final angular positions, we can use the formula:
θf - θi = ωi * t + (1/2) * α * t²
where
θi is the initial angular position (0 in this case)
θf is the final angular position (90 radians in this case)
Substtuting the given values, we have:
θf - θi = ωi * t + (1/2) * α * t²
90 - 0 = (9.13 rad/s) * 15 s + (1/2) * α * (15 s)²
Simplifying and solving for α, we get:
α = -0.42 rad/s²
Therefore, the angular deceleration of the ball is -0.42 rad/s².
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