consider a mach 3 flow at 1 atm pressure initially moving over a flat horizontal surface. the flow then encounters a 20 degree expansion corner, followed by a 20 degree compression corner that turns the flow back to the horizontal. calculate the pressure of the flow downstream of the compression corner. note: you will find that the pressure downstream of the compression corner is different from the pressure upstream of the expansion corner, even though the upstream and downstream flows are in the same direction, namely horizontal. why?

Explanation:

The three-second rule is recommended for passenger vehicles during ideal road and weather conditions. Slow down and increase your following distance even more during adverse weather conditions or when visibility is reduced. Also increase your following distance if you are driving a larger vehicle or towing a trailer.

The range of values of v0 for which the platform will remain in position is 4.151 m/s ≤ v0 ≤ 8.49 m/s.

Applying Newton's second law in the radial and tangential directions. The normal force N and the force of static friction f are the only forces acting in the radial direction. The weight W of the rider and the force T exerted by the wall are the only forces acting in the tangential direction.

In the radial direction, the net force is given by:

N - W cos θ - f = mv²/r

where m is the mass of the rider, θ is the angle between the wall and the horizontal, and r is the radius of the circle.

In the tangential direction, the net force is given by:

T - W sin θ = 0

since the rider is not accelerating in this direction.

The maximum static friction force is given by:

fmax = μN = μ(W cos θ + m v²/r)

where μ is the coefficient of static friction.

Since the platform remains in position, we know that the force of static friction is equal to the maximum static friction force. Therefore,

f = fmax

Substituting the expression for fmax into the equation for the radial direction, we obtain:

N - W cos θ - μ(W cos θ + m v²/r) = mv²/r

Solving for v², we get:

v² = r(g cos θ - μ g cos θ)/(1 - mμ)

where g is the acceleration due to gravity.

To determine the range of values of v0 for which the platform will remain in position, we need to find the minimum and maximum values of v0.

replacing the values, we get:

vmin = √(r(g - μg)/(1 - mμ)) = 4.151 m/s

vmax = √(r(g - μg/2)/(1 - mμ)) = 8.49 m/s

Therefore, the range of values of v0 for which the platform will remain in position is 4.151 m/s ≤ v0 ≤ 8.49 m/s.

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Answer:

Explanation:

The value of a will be zero as it is provided that the particle is on the x-axis.

Calculate the velocity of particles along x-axis.

\({\bf{V}} = 2{x^2}t{\bf{\hat i}} + [4y(t - 1) + 2{x^2}t]{\bf{\hat j}}{\rm{ m/s}}\)

Substitute 0 for y.

\(\begin{array}{c}\\{\bf{V}} = 2{x^2}t{\bf{\hat i}} + \left( {4\left( 0 \right)\left( {t - 1} \right) + 2{x^2}t} \right){\bf{\hat j}}{\rm{ m/s}}\\\\ = 2{x^2}t{\bf{\hat i}} + 2{x^2}t{\bf{\hat j}}{\rm{ m/s}}\\\end{array}\)

Here,

\(A = 2{x^2}t \ \ and\ \ B = 2{x^2}t\)

Calculate the magnitude of vector V .

\(.\left| {\bf{V}} \right| = \sqrt {{A^2} + {B^2}}\)

Substitute

\(2{x^2}t \ \ for\ A\ and\ 2{x^2}t \ \ for \ B.\)

\(\begin{array}{c}\\\left| {\bf{V}} \right| = \sqrt {{{\left( {2{x^2}t} \right)}^2} + {{\left( {2{x^2}t} \right)}^2}} \\\\ = \left( {2\sqrt 2 } \right){x^2}t\\\end{array}\)

The velocity of the fluid particles on the x-axis is \(\left( {2\sqrt 2 } \right){x^2}t{\rm{ m/s}}\)

Calculate the direction of flow.

\(\theta = {\tan ^{ - 1}}\left( {\frac{B}{A}} )\)

Here, θ is the flow from positive x-axis in a counterclockwise direction.

Substitute \(2{x^2}t\) as A and \(2{x^2}t\) as B.

\(\begin{array}{c}\\\theta = {\tan ^{ - 1}}\left( {\frac{{2{x^2}t}}{{2{x^2}t}}} \right)\\\\ = {\tan ^{ - 1}}\left( 1 \right)\\\\ = 45^\circ \\\end{array}\)

The direction of flow is \(45^\circ\) from the positive x-axis.

Among various types of mining, open-pit mining is often considered to create the greatest environmental damage. Open-pit mining, also known as open-cast or open-cut mining, involves the extraction of minerals or ores from the Earth's surface by removing overlying soil and rock layers.

There are several reasons why open-pit mining is associated with significant environmental damage:

Large-Scale Excavation: Open-pit mining requires the excavation and removal of vast amounts of soil, rocks, and vegetation. This process leads to the destruction of natural habitats, deforestation, and loss of biodiversity in the affected areas. The removal of topsoil and vegetation can result in long-term soil erosion and degradation.

Alteration of Landforms: Open-pit mining alters the natural topography of the land, resulting in the creation of deep pits and spoil heaps. These altered landforms can disrupt the hydrological systems, leading to changes in water flow patterns, contamination of groundwater, and the loss of aquatic habitats. The accumulation of waste rock and tailings in spoil heaps can release harmful chemicals into the environment, polluting nearby water sources.

Air and Water Pollution: The extraction and processing of minerals in open-pit mining often involve the use of explosives, heavy machinery, and chemical reagents. These activities can release dust, particulate matter, and toxic substances into the air, contributing to air pollution. The runoff from mining sites can carry sediments, heavy metals, and chemicals into nearby water bodies, causing water pollution and affecting aquatic ecosystems.

Energy Consumption and Greenhouse Gas Emissions: Open-pit mining requires significant energy inputs for excavation, transportation, and processing of minerals. The extraction and use of fossil fuels in mining operations contribute to greenhouse gas emissions, exacerbating climate change and its associated environmental impacts.

While it is important to note that the environmental impact of mining can vary depending on various factors, including the specific mineral being extracted, the location, and the mining practices employed, open-pit mining is generally considered more destructive due to its extensive scale, alteration of landforms, habitat destruction, and potential for pollution. Sustainable mining practices, strict environmental regulations, and reclamation efforts are crucial in mitigating the environmental damage associated with mining operations.

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Answer:

1) the water velocity in the tunnel for the model tests is 28 m/s

2) the expected vortex shedding frequency on the prototype is 12.5 Hz

Explanation:

Given the data in the question;

1)

using the Reynolds number relation for prototype and model,

PpVpdp/mu(Prototype) = PmVmdm/mu(for model)

but we know that, density and viscosity in prototype and model will remain same so;

Vp × dp = Vm × dm

vm = Vp × dp/dm

we substitute

vm = 7 m/s × 4

vm = 28 m/s

Therefore, the water velocity in the tunnel for the model tests is 28 m/s

2)

we make use of the Strouhal number relation as given in the question;

fp × dp/Vp = fm × dm/Vm

frequency of the prototype will be;

fp = fm × dm/Vm / dp/Vp

we substitute

fp = 200 × 7 / ( 4 × 28 )

fp = 1400 / 112

fp = 12.5 Hz

Therefore, the expected vortex shedding frequency on the prototype is 12.5 Hz

CMOS (Complementary Metal-Oxide-Semiconductor) technology is commonly used to implement logic gates. There are several types of logic gates such as AND, OR, NOT, NAND, NOR, XOR, and XNOR gates.

To draw simple logic gates with CMOS transistors, we can use a combination of p-channel and n-channel MOSFETs. For example, an AND gate can be implemented with two n-channel MOSFETs in series and two p-channel MOSFETs in parallel,

while an OR gate can be implemented with two n-channel MOSFETs in parallel and two p-channel MOSFETs in series. Similarly, NOT gates can be implemented with a single n-channel or p-channel MOSFET.

To summarize, CMOS technology is widely used to implement logic gates due to its low power consumption, high speed, and ease of manufacturing. The combination of p-channel and n-channel MOSFETs can be used to design various logic gates.

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The couple of the moment of the two forces is 3.82 N.m

We are given;

Force applied at A; F_a = 62 N

Force applied at C; F_c = 62 N

AB = BC = 200 mm = 0.2 m

Horizontal component of  F_a is; F_ax = 62 cos 50

Vertical component of  F_a is; F_ay = 62 sin 50

Horizontal component of  F_c is; F_cx = 62 cos 50

Vertical component of  F_c is; F_cy = 62 sin 50

Taking moments about point C gives;

M_c = F_ay * AB - F_ax * BC

M_c = (62 sin 50 * 0.2) - (62 cos 50 * 0.2)

M_c = 23.75 - 19.93

M_c = 3.82 N.m

Thus, the couple of the moment of the two forces is 3.82 N.m

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Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.

The grade of 12.9 bolt is known to be 1220 (176,000 psi). The alloy carbon steel is said to be one that is often used to make Metric 12.9 Hex Cap Screws that is heat-treated, quenched, as well as tempered.

Their strength is one that is comparable to alloy sockets, and with a proof load of 970 MPa and a minimum tensile strength of 1220 MPa.

Therefore, Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.

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See full question below

Tech A says that a standard grade 5 bolt is stronger than a standard grade 8 bolt. Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. Who is correct?

a. Tech A

b. Tech B

c. both

d. neither

Answer:

The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.

Explanation:

The complete statement of this question is "Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of P = 450 kN"

Each bolt is subjected to shear forces. In this case, safety factor is the ratio of the ultimate shear strength to maximum allowable shear stress. That is to say:

\(n = \frac{S_{uts}}{\tau_{max}}\)

Where:

\(n\) - Safety factor, dimensionless.

\(S_{uts}\) - Ultimate shear strength, measured in pascals.

\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.

The maximum allowable shear stress is consequently cleared and computed: (\(n = 4.2\), \(S_{uts} = 320\times 10^{6}\,Pa\))

\(\tau_{max} = \frac{S_{uts}}{n}\)

\(\tau_{max} = \frac{320\times 10^{6}\,Pa}{4.2}\)

\(\tau_{max} = 76.190\times 10^{6}\,Pa\)

Since each bolt has a circular cross section area and assuming the shear stress is not distributed uniformly, shear stress is calculated by:

\(\tau_{max} = \frac{4}{3} \cdot \frac{V}{A}\)

Where:

\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.

\(V\) - Shear force, measured in kilonewtons.

\(A\) - Cross section area, measured in square meters.

As connection consist on five bolts, shear force is equal to a fifth of the applied load. That is:

\(V = \frac{P}{5}\)

\(V = \frac{450\,kN}{5}\)

\(V = 90\,kN\)

The minimum allowable cross section area is cleared in the shearing stress equation:

\(A = \frac{4}{3}\cdot \frac{V}{\tau_{max}}\)

If \(V = 90\,kN\) and \(\tau_{max} = 76.190\times 10^{3}\,kPa\), the minimum allowable cross section area is:

\(A = \frac{4}{3} \cdot \frac{90\,kN}{76.190\times 10^{3}\,kPa}\)

\(A = 1.640\times 10^{-3}\,m^{2}\)

The minimum allowable cross section area can be determined in terms of minimum allowable bolt diameter by means of this expression:

\(A = \frac{\pi}{4}\cdot D^{2}\)

The diameter is now cleared and computed:

\(D = \sqrt{\frac{4}{\pi}\cdot A}\)

\(D =\sqrt{\frac{4}{\pi}\cdot (1.640\times 10^{-3}\,m^{2})\)

\(D = 0.0457\,m\)

\(D = 45.7\,mm\)

The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.

We have that the minimum allowable bolt diameter is mathematically given as

From the question we are told

Generally the equation for the stress   is mathematically given as

\(\mu= 320/4.2 \\\\\mu= 76.190 N/mm^2\)

Therefore

Force = Stress * area

Force = P/2

F= 425,000 N / 2 = 212,500 N

Hence area of each bolt is given as

212,500 = 76.190*( 5* area of each bolt)

area of each bolt = 557.815

Since

area of each bolt=\pi*d^2/4

\pi*d^2/4 = 557.815

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correct option is d. Control limits come from common cause process variation.

Control limits are derived from common cause process variation. These limits help determine the acceptable range of variation in a process and are used to monitor and control its performance. Common cause process variation refers to the inherent variability in a system that is expected to occur due to random factors.

By analyzing historical data and understanding the natural variability of a process, control limits can be established to identify when the process is operating within acceptable limits or when it is experiencing unusual variation.

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The true power is obtained as 70.7 VA.

We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.

Thus;

True power = PcosΦ

P =  100 VA

Φ = 45 degrees

True power =  100 VA * cos 45 degrees

True power = 70.7 VA

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The Digital Processing is not part of the OBD II implementation.

OBD II is known to be a kind of acronym for On-Board Diagnostic II. This is known to be the second generation of on-board self-diagnostic equipment that is needed for light- and medium-duty California vehicles.

The OBD-II is said to be a kind of on-board computer that handles emissions, , speed, etc.

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The efficiency of the motor is 80%.

The heat lost by the motor per minute is 7.5 kW.

The output power of the motor is given by:

P_o = τ * ω

where τ is the torque and ω is the angular velocity.

P_o = 200 N m * (2π * 600 r/min) / 60 s/min = 6000 W

The efficiency of the motor is given by:

η = P_o / P_i

where P_i is the input power.

η = 6000 W / 15 kW = 0.8

The heat lost by the motor per minute is given by:

Q = P_i - P_o

Q = 15 kW - 6000 W = 7.5 kW

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Answer:

O A. 9/16 inch

Explanation:

The magnitude of σ1 that will cause yielding according to the maximum-shear-stress theory is 9.94 ksi.

Yield stress for the zirconium-magnesium alloy, σY = 15.3 ksi

In-plane principal stresses are σ1 and σ2 = −0.54σ1

To find the maximum shear stress theory, the equation used is τ_max=1/2(σ1-σ2)

The maximum shear stress theory states that yielding begins when the maximum shear stress in a part equals or exceeds the shear strength of the material. It is represented as τ_max = τ_yield

Where τ_max is the maximum shear stress in a part and τ_yield is the shear strength of the material. In-plane principal stresses are σ1 and σ2 = −0.54σ1

Let us replace the value of σ2 in terms of σ1σ2 = −0.54σ1,σ1 = 1.85σ2

Substitute the values in the τ_max=1/2(σ1-σ2)

τ_max=1/2(σ1-(-0.54σ1))

τ_max=0.77σ1

Now, τ_yield= σY/2 = 7.65 ksi

Therefore, 0.77σ1 = 7.65

σ1 = 9.94 ksi

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A two-terminal solid-state device that allows current to flow in both directions once breakover voltage is reached and so long as holding current remains high enough is a Thyristor.

What is a thyristor?A thyristor is a solid-state device that works as a switch, rectifier, and voltage controller. Thyristors are used to regulate power and electronic signals, particularly in applications such as DC motor control, heating control, and AC power transmission. They are also used in light dimming and inrush current limiting circuits.

A thyristor can operate in various modes, including reverse blocking, forward blocking, and bidirectional. The term "thyristor" is a generic name for any device with a multilayer semiconductor structure similar to that of a diode and a controlled switch that can be turned on and off. The name "thyristor" comes from its use as a "solid-state" equivalent of the thyratron tube, a vacuum tube.

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False, Good housekeeping eliminates accident and fire hazards. It also maintains safe, healthy work conditions; saves time, money, materials, space, and effort; improves productivity and quality; boosts morale; and reflects an image of a well-run, successful organization.

Hope it helps you❤️

Answer:

Primary cell with a nominal open circuit voltage of 1.5 Volts produced in very high volumes. Chemistry based on a zinc anode and a cathode/depolariser of manganese dioxide which absorbs the liberated hydrogen bubbles which would otherwise insulate the electrode from the electrolyte.

Answer:

Explanation:

(1) The electrolyte is a paste of ammonium chloride.

(2) The positive terminal (anode) is a carbon rod surrounded bymangAnese Dioxide as a depolarised .

(3) The negative terminal is zinc container.

If |a|b then 2−2=(−)(+)|0⟺+|0

In order to close the cylinder, the plug must move down through 1 mm.The force P that must be applied to the cylinder is 1.61 x 10⁶ N.

According to Hooke's Law, the force applied to an object is inversely proportional to its extension or compression. In this instance, the aluminum cylinder compression, which is 1 millimeter, is inversely proportional to the force P.

Hooke's Law is the basis of this question. The following are the procedure's steps:

1. Calculating the force required to move the plug down 1 mm is the first step.

The Young's Modulus and cross-sectional area of the brass tube AB, respectively, and the Young's Modulus and cross-sectional area of the aluminum cylinder, respectively, are used to calculate this force using the equation

                                      P = (E₁A₁ + E₂A₂) x L.

2. The values for E₁, A₁, E₂, and A₂ must be determined next. The brass tube has a cross-sectional area of 140 mm², and its Young's Modulus is

                                      5×105 GPa.

The aluminum cylinder has a cross-sectional area of 250 mm² and a Young's Modulus of        

                                    5×72 GPa.

3. Last but not least, we need to figure out the displacement, L. L is 1 mm in this case.

4. When these numbers are added to the equation, we get

                        P = (5 ×105 ×140 + 5×72×250) x 0.001,

which gives us a force of 1.61 x 10⁶ N.

                                  P = (E₁A₁ + E₂A₂) x L

                    P = (5×105 ×140 + 5× 72× 250) x 0.001

                           P = 1.61 x 10⁶ N

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Answer:

9 1/2

Explanation:

3 4/5 is 3.8

2/5 is 0.4

divide 3.8 by 0.4 you get 9.5 which is 9 1/2 in a fraction

In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.

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As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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Answer:

\( \therefore \) The power output of the draw-works motor is 4.36 hp

Explanation:

Given that,

As the problem given, the cable is tied of the top on the oil rig and it wraps around the lower pulley and the top pulley. So, we will be using the formula below:

Differentiate it but with respect to the time. Therefore,

Thus,

Thus, the power output should be

\( P = Fv = \bigg(\frac{600}{2}\bigg) \cdot 8 = 2400 \ lb \cdot ft/s = \frac{2400}{550} = 4.36 \ hp \)

\( \therefore \) The power output of the draw-works motor is 4.36 hp

1) No matter how hard you try, Sarah will not be persuaded.

2) The kids are excited to go on vacation.

3. He opted to travel for business in September as opposed to May.

4) They pushed me work hard on my studies while I was in college.

5) I went to my neighbourhood bank to ask about obtaining a loan.

Note: Number 5's corrected sentence was puzzling. I assumed that asking about loans was the intended meaning. If you would like more information so that I can understand what you meant, please let me know.

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check photo solvecheck photo solve

Keywords Are Reserved Words Which Are Not Use As Normal Cases But Used For Special Purpose In Our Program whereas, Data Type Tells The Compiler And Interpreter How The Program Is Going To Be Executed And Can Be Used At Every Cases.

Based on how they are stored in the computer, the types produced by these keywords can be categorized into two families, integer types and floating-point types.

Bit, byte, and word are terminology that can be used to refer to either memory or data storage units in computers.

The main distinction between text fields and keyword fields is that text fields are examined during indexing, whereas keyword fields are not.

This means that while keyword fields are indexed exactly as is, text fields are split down into their constituent phrases at indexing to allow for partial matching.

A word or collection of words that an Internet user enters into a search engine or search bar to conduct a search is referred to as a keyword in the context of digital marketing.

Therefore, All data types are keywords, but all keywords are not data types.

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Yes, I have prototyped an idea.

How to prototype an idea?

STEP-1 Create Your Ideas Now: Here are some initial steps you may take to speed up the idea-generation process. Conduct in-depth research Know the market value, potential rivals, manufacturing method, and overall cost of your goods.

STEP-2 Make a Simplified Version of Your Idea: Making a straightforward representation of your idea would be the next step after conducting considerable research and settling on an idea.

STEP-3 Make a Realistic Prototype: You actually start working on your prototype at this point.

STEP-4 Develop Your Prototype Until It Is Perfect: The hardest and longest phase of them all is this one.

Hence, the prototype of an idea is given.

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Answer:

A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.

I dont know I asked this to

Explanation: