Consider a finite square-well potential well of width 3.00×10−15 m that contains a particle of mass 1.88 GeV/c2. How deep does this potential well need to be to contain three energy levels? (This situation approximates a deuteron inside a nucleus.)
Answers
The potential well needs to be at least 145.17 eV deep to contain three energy levels for a particle of mass 1.88 GeV/c2 in a well of width 3.00×10−15 m, which approximates a deuteron inside a nucleus.
How to determineTo contain three energy levels, the potential well needs to be deep enough to allow for three bound states.
The depth of the potential well can be calculated using the formula:
V0 = (π^2ħ^2)/(2mL^2)(n^2)
Where V0 is the depth of the potential well, ħ is the reduced Planck constant, m is the mass of the particle, L is the width of the well, and n is the quantum number of the energy level.
For a particle of mass 1.88 GeV/c2 and a well width of 3.00×10−15 m, we can calculate the depth of the potential well for the first three energy levels as follows:
For n=1, V0 = (π^2ħ^2)/(2mL^2) = 16.14 eV
For n=2, V0 = (π^2ħ^2)/(2mL^2)(n^2) = 64.54 eV
For n=3, V0 = (π^2ħ^2)/(2mL^2)(n^2) = 145.17 eV
Therefore, the potential well needs to be at least 145.17 eV deep to contain three energy levels for a particle of mass 1.88 GeV/c2 in a well of width 3.00×10−15 m, which approximates a deuteron inside a nucleus.
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Related Questions
During exercise, the human body breaks down atp, an energy molecule in the body. This reaction provides the energy needed for muscle movement. This process is an example of the transformation of.
Answers
During exercise, the breakdown of ATP into ADP and inorganic phosphate provides the energy needed for muscle movement. This process exemplifies the transformation of chemical energy into mechanical energy. ATP stands for adenosine triphosphate, and it is often referred to as the "energy currency" of cells.
During exercise, the human body breaks down ATP, an energy molecule, to provide the energy needed for muscle movement. This process is an example of the transformation of chemical energy.
ATP stands for adenosine triphosphate, and it is often referred to as the "energy currency" of cells. It stores and releases energy in its high-energy phosphate bonds. When the body needs energy for muscle movement during exercise, ATP is broken down into ADP (adenosine diphosphate) and inorganic phosphate through a process called hydrolysis. This reaction releases energy that can be used for muscle contraction.
The transformation of chemical energy refers to the conversion of energy stored in chemical compounds, like ATP, into a different form of energy. In this case, the chemical energy stored in ATP is transformed into mechanical energy, which allows muscles to move.
In summary, during exercise, the breakdown of ATP into ADP and inorganic phosphate provides the energy needed for muscle movement. This process exemplifies the transformation of chemical energy into mechanical energy.
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IT'S 30 POINTS!!!!!!!
1) What are the five different types of interactions between organisms?
2) What patterns do scientists observe between predator-prey relationships like the wolves and moose on Isle Royale?
3) Use the data from your graph to provide evidence for the effects of of resource availability on individuals and populations in an ecosystem.
4) Do the patterns of interactions between organisms, such as competition and predation, change when they occur in different ecosystems? Explain.
5) Predict the effects on a predator-prey relationship, such as the one between a frog and blue heron, in a wetland ecosystem in the midst of a drought.
Answers
Answer:
1. Competition and prediction
Commensalism
Parasitism
Mutualism
Amensalism
2. As the population of wolves has declined the population of the moose increase
3.
whats an energy creation that connects to deforestation?
Answers
The elements in a column of the periodic table _____.
A.have very similar chemical symbols
B.have the same atomic mass
C.have similar properties
Answers
(this is because they have the same number of electrons in the outer orbital)
An observer notices that 12 waves pass by in 4 seconds. What is the frequency of these waves? 0.33 Hz 16 Hz 48 Hz 3 Hz
Answers
Answer:
Frequency = 3 Hz
Explanation:
Frequency is a measure of Hertz. Recall that Hertz is the unit expressing cycles/second, where one second is the denominator of the fraction for simplicity. If there are 12 waves every four seconds, and one wave represents one cycle, dividing 12 waves by 4 seconds will give the answer of 3 waves (or cycles) per one second.
The frequency of these waves is 3 Hz. The correct option is D.
What is a frequency?Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is a fundamental property of waves and is directly related to the energy and wavelength of the wave. The higher the frequency of a wave, the more energy it carries and the shorter its wavelength.
The formula for frequency (f) is:
f = 1 / T
where f is the frequency in Hertz (Hz) and T is the period of the wave in seconds (s). The period is the time it takes for one complete cycle or oscillation of the wave to occur.
Here in the Question,
The frequency of the waves can be calculated using the formula:
frequency = number of waves/time
In this case, the number of waves is 12 and the time is 4 seconds. Substituting these values into the formula, we get:
frequency = 12 waves / 4 seconds = 3 Hz
Therefore, the frequency of these waves is 3 Hz.
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What safety factors should astronauts be aware of when collecting rock samples on the Moon?
Answers
Answer:
Explanation:
Astronauts face a wide range of dangers when maneuvering in space. Collecting rock samples requires breaking apart rocks on the moon's surface, which requires tools. These tools are sometimes small hammers or other times special drills. All of this process means moving and using force to break these rocks apart and every single movement can cause a mistake which can lead to a piece of the suit ripping or a failure in the machinery. Since there is no oxygen on the moon the tiniest failure in the suit can lead to the death of the astronaut. Therefore, having backup safety precautions, and quick repair scenarios is a must when collecting rock samples on the moon.
how does a parallel circuit change when a branch is added?
Answers
A(n) _____ resistance bridge has variable resistances that are adjusted so there is equal current flow through the legs of the bridge and zero potential across the bridge.
Answers
A Wheatstone bridge is a resistance bridge that has variable resistances that are adjusted so there is equal current flow through the legs of the bridge and zero potential across the bridge.
This configuration is widely used in scientific and engineering applications to precisely measure unknown electrical resistance values. The Wheatstone bridge consists of four resistors connected in a diamond shape, with a galvanometer connected between two opposite corners to detect any potential difference.
When the bridge is balanced, the ratio of the known resistances is equal to the ratio of the unknown resistances, allowing for accurate determination of the unknown resistance value. The Wheatstone bridge has been a fundamental tool in electrical measurements since its invention in the 19th century and continues to be utilized in modern electronics and instrumentation.
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A horse running at a velocity of 10 m/sec[W] accelerates at a rate of 6. 25 m/sec 2 [W] for 2 sec. What is the final velocity of the horse?
Answers
The final velocity of the horse is 22.5 m/s [W]. Velocity is a vector quantity that describes the rate at which an object changes its position. It includes both magnitude (speed) and direction.
To find the final velocity of the horse, we can use the formula for calculating velocity:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given:
Initial velocity (u) = 10 m/s [W]
Acceleration (a) = 6.25 m/s^2 [W]
Time (t) = 2 sec
Substituting the given values into the formula, we can calculate the final velocity:
v = 10 m/s + (6.25 m/s^2)(2 sec)
v = 10 m/s + 12.5 m/s
v = 22.5 m/s
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What is the total kinetic energy of a hoop of radius 1 m and mass 2 kg that rolls at an
angular velocity of 1 rad/s?
Answers
Answer:
12
Explanation:
What is the total kinetic energy of a hoop of radius 1 m and mass 2 kg that rolls at an
angular velocity of 1 rad/s?
The inner planets have a smaller diameter than the outer planets.
True
False
Answers
Answer:true
Explanation:
What occurs when air moves from an area of high pressure to an area of lower pressure
Answers
Which element has the fewest valence electrons?
O A. Nitrogen (N)
O B. Silicon (Si)
O C. Chlorine (CI)
O D. Beryllium (Be)
Answers
Answer:
A.Nitrogen
Explanation:
Because it is belong to non-metal group.
I don't knowwwww
Answer:
D.Beryllium (Be)
Explanation:
Trust
A rod is made up of copper and wood joined together.
After the rod is heated at the join in the centre for about a minute, where would the lowest temperature be?
Answers
my views
Explanation:
Figure (8) shows a rod made up of copper and wood joined together. The rod is heated at the joint in the centre for about a minute. At which point – A, B, C or D, would it show the lowest temperature? PLEASE GIVE REASONS ALSO(MINIMUM 2)
The bent wire circuit shown in the figure is in a region of space with a uniform magnetic field in the +z direction. Current flows through the circuit in the direction indicated. Note that segments 2 and 5 are oriented parallel to the z axis; the other pieces are parallel to either the x or y axis.
a) Determine the direction of the magnetic force along segment 1, which carries current in the -x direction. I know this is +y
b) Determine the direction of the magnetic force along segment 2, which carries current in the -z direction.
c) Determine the direction of the magnetic force along segment 3, which carries current in the +y direction.
d) Determine the direction of the magnetic force along segment 4, which carries current in the +x direction
e) Determine the direction of the magnetic force along segment 5, which carries current in the +z direction.
f)Determine the direction of the magnetic force along segment 6, which carries current in the +x direction.
g) Determine the direction of the magnetic force along segment 7, which carries current in the -y direction.
Answers
The bent wire circuit shown in the figure is in a region of space with a uniform magnetic field in the +z direction. Current flows through the circuit in the direction indicated. segments 2 and 5 are oriented parallel to the z-axis; the other pieces are parallel to either the x or y-axis.
The direction of the magnetic force along segment 1, which carries current in the -x direction is +y. Therefore, the answer is
b) Determine the direction of the magnetic force along segment 2, which carries current in the -z-direction. The magnetic field lines are at right angles to the direction of the current flow, so the direction of the magnetic field is in the +y direction. The current flow in segment 2 is in the -z direction and so the direction of the magnetic force is in the +x direction. Fleming's left-hand rule can be used to determine the direction of the magnetic force acting on the wire segments. The thumb points in the direction of the current, and the index finger points in the direction of the magnetic field. The direction of the magnetic force along segment 3, which carries current in the +y direction is in the +x direction.
Therefore, the answer is d) Determine the direction of the magnetic force along segment 4, which carries current in the +x direction. The direction of the magnetic force along segment 4, which carries current in the +x direction is in the +y direction.
Therefore, the answer is a) Determine the direction of the magnetic force along segment 1, which carries current in the -x direction is +y. The direction of the magnetic force along segment 6, which carries current in the +x direction is in the +z direction.
Therefore, the answer is e) Determine the direction of the magnetic force along segment 5, which carries current in the +z direction in the -x direction. The direction of the magnetic force along segment 7, which carries current in the -y direction is in the -x direction.
Therefore, the answer is f) Determine the direction of the magnetic force along segment 6, which carries current in the +x direction in the -y direction.
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Cars B and C are identical, each weighing 2820 lb (including driver), driving at the exact same speed of 58.5 ft/s on the same road that has coefficients of riction µs = 0.855 and µk = 0.715. Car B is at the bottom of a dip (radius = 775 ft) at exactly the same time car C is at the crest of a hill (radius also = 775 ft) when both drivers slam on their brakes simultaneously and both cars begin to slide
(they do not have anti-lock brakes).
a) What is the tangential acceleration (i.e., the
acceleration parallel to the road) of each car as it slides on the road at the positions described?
b) What is the magnitude of the total force that the road exerts on each car?
Answers
The tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described is -6.61 ft/s². Weight of car = 2820 lbSpeed of cars = 58.5 ft/s. Coefficient of friction,μs = 0.855μk = 0.715.
Radius of the dip, r = 775 ft.a) What is the tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described?Now, we need to find the tangential acceleration of each car during sliding.Let F be the frictional force exerted by the road on the car.Using, the following formula we can find the force exerted on the cars.
F=μs N = μs m g = 0.855 × 2820 × 32.2 lb = 80445.6 lb.a = F/ma = 80445.6 lb/2820 lba = 28.54 ft/s²The total tangential acceleration is the acceleration due to gravity subtracted by the frictional force, which is as follows,a = -g sinθ - μs g cosθa = -32.2 sin(0) - 0.855 × 32.2 cos(0)a = -27.53 ft/s²The tangential acceleration is,-6.61 ft/s².b) What is the magnitude of the total force that the road exerts on each car?The force acting on the cars can be found by,Force = mass × acceleration (F = ma)Force, F = 2820 × 6.61 lbForce, F = 18,601.4 lb.The force exerted on each car is 18,601.4 lb.
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ou connect a battery, resistor, and capacitor as in Fig. 26.20a, where ε=36.0 V, C=5.00 μF, and R=120 Ω. The switch S is closed at t=0. (a) When the voltage across the capacitor is 8.00 V, what is the magnitude of the current in the circuit? (b) At what time t after the switch is closed is the voltage across the capacitor 8.00 V? (c) When the voltage across the capacitor is 8.00 V, at what rate is energy being stored in the capacitor?
Answers
(a) 0.300 A. is the magnitude of the current in the circuit. (b) infinity is the time at which the voltage reaches 8.00 V. (c) The rate at which energy is being stored in the capacitor is 2.40 watts.
(a) To determine the magnitude of the current when the voltage across the capacitor is 8.00 V, Ohm's Law can be applied. The current (I) in the circuit can be calculated as I = ε/R, where ε is the battery voltage and R is the resistance. Substituting the given values, I = 36.0 V / 120 Ω = 0.300 A.
(b) The time it takes for the voltage across the capacitor to reach 8.00 V can be determined by considering the charging time constant of the RC circuit. The charging time constant (τ) is given by the product of the resistance and the capacitance, τ = RC. Substituting the given values, τ = (120 Ω) × (5.00 μF) = 600 μs. To find the time (t) at which the voltage across the capacitor reaches 8.00 V, we can use the formula t = τ × ln(Vf/Vi), where Vf is the final voltage (8.00 V) and Vi is the initial voltage (0 V). Solving the equation, t = 600 μs × ln(8.00/0) = infinity (the voltage across the capacitor never reaches 8.00 V in this circuit configuration).
(c) The rate at which energy is being stored in the capacitor when the voltage across it is 8.00 V can be calculated by multiplying the current flowing through the capacitor by the voltage. Using the previously calculated current value (0.300 A) and the voltage (8.00 V), the rate of energy storage is P = IV = 0.300 A × 8.00 V = 2.40 W. Therefore, when the voltage across the capacitor is 8.00 V, the rate of energy being stored in the capacitor is 2.40 watts.
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how much solar radiation does the earth intercept from the sun?
Answers
The amount of solar radiation that the Earth intercepts from the Sun varies depending on several factors, including the distance between the Earth and the Sun, the Earth's orbital eccentricity, and atmospheric conditions.
On average, the Earth intercepts about 1,366 watts per square meter (W/m²) of solar radiation outside of the Earth's atmosphere. This value is known as the solar constant. However, due to various factors, including the Earth's atmosphere, not all of this solar radiation reaches the surface. The atmosphere absorbs, scatters, and reflects a portion of the incoming solar radiation. The actual amount of solar radiation that reaches the Earth's surface depends on factors such as the angle of incidence, cloud cover, aerosols, and the specific location and time of year.
On average, about 70% of the solar radiation that reaches the top of the Earth's atmosphere makes it through the atmosphere and reaches the surface. Therefore, the average amount of solar radiation that reaches the Earth's surface is approximately 957 W/m². It's important to note that these values are averages and can vary depending on various factors and geographical locations.
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Part E
List several examples of drag, elastic force, and tension force that you've observed in your life.
Answers
Various examples of drag, elastic and tension forces are mentioned.
What is elastic and tension force?Elastic force is a type of force that occurs when an object is stretched or compressed, and it resists the deformation of the object. This force is proportional to the amount of stretching or compression, and it causes the object to return to its original shape when the force is removed.
Tension force is a type of force that is transmitted through a string, rope, wire or cable when it is pulled tight by forces acting at either end. This force acts to transmit the tension through the length of the string, keeping it taut and preventing it from breaking.
What is an example of drag that is observed in life?A person biking into a headwind experiences air resistance, which is a type of drag force.
What is an example of elastic force observed in life?A stretched rubber band or a compressed spring both exhibit elastic force.
What is an example of tension force observed in life?A person pulling a wagon by a rope exerts a tension force on the rope. Another example of tension force can be observed when a weight is hung from a rope or chain, creating tension within the rope or chain.
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Un coche que lleva una velocidad constante de 90 km/hora durante 2 horas ¿Cuánto espacio recorre?Si encuentra un obstáculo en la carrera y tiene que parar 10 segundos calcula la aceleración
Answers
Answer:
(i) El coche recorre 180 kilómetros.
(ii) El coche decelera a razón de 2.5 metros por segundo al cuadrado.
Explanation:
El problema se divide en dos partes. La primera es el coche viajando a velocidad constante y la segunda consiste en una decelaración hasta alcanzar el reposo.
Primera parte - Viaje a velocidad constante
La distancia recorrida por el coche se calcula mediante la siguiente ecuación cinemática:
\(x = v\cdot t\) (1)
Donde:
\(x\) - Distancia recorrida, en kilómetros.
\(v\) - Velocidad, en kilómetros por hora.
\(t\) - Tiempo, en horas.
Si sabemos que \(v = 90\,\frac{km}{h}\) y \(t = 2\,h\), entonces la distancia recorrida por el coche es:
\(x = v\cdot t\)
\(x = 180\,km\)
El coche recorre 180 kilómetros.
Segunda parte - Deceleración
Asumiendo que la deceleración del coche es constante, se determina mediante la siguiente ecuación cinemática:
\(a = \frac{v-v_{o}}{t}\) (2)
Donde:
\(v_{o}\) - Velocidad inicial, en metros por segundo.
\(v\) - Velocidad final, en metros por segundo.
\(t\) - Tiempo, en segundos.
Si sabemos que \(v_{o} = 25\,\frac{m}{s}\), \(v = 0\,\frac{m}{s}\) y \(t = 10\,s\), entonces la deceleración experimentada por el coche es:
\(a = -2.5\,\frac{m}{s^{2}}\)
El coche decelera a razón de 2.5 metros por segundo al cuadrado.
Greta took an IQ test and scored high in knowledge and vocabulary. Which of the following statements BEST describes Greta’s results?
Answers
Answer:
Greta scored high in knowledge and vocabulary on the IQ test.
Explanation:
This statement highlights Greta's strengths in knowledge and vocabulary specifically, indicating that she performed well in these areas during the test. However, it does not provide information about her overall IQ score or her performance in other cognitive domains that may have been assessed in th
An object moving north with an initial velocity of 14 m/s accelerates 5 m/s2 for 20 seconds. What is the final velocity of the object?
39 m/s
90 m/s
114 m/s
414 m/s
Answers
Answer:
option C
Explanation:
Final velocity of the object is 114 m / s. Hence, final velocity of the object is 114 m / s.
A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren is 500 hz relative to the police car, what is the frequency heard by an observer in the truck after the police car passes the truck? (the speed of sound in air is 343 m/s. ).
Answers
The frequency change, in accordance with the presented description, is 636 Hz.
Frequency: What is it?The quantity of occurrences of a recurring event per unit of time is its frequency. It is distinct from angular frequency, and for clarification, it is sometimes referred to as sampling rate. One occurrence per second, or hertz (Hz), is the unit of frequency.
Speed (v1) = 36 m/s
Speed (v2) = 45 m/s
Frequency (f) = 500 Hz
Speed of sound (s) = 343 m/s
We are aware of the modification of frequency formula, which
Frequency = s+v1/ s+v2(f) -------(1)
Put a value here and apply equation (1).
We'll use v2 = -45 since it's the other way.
Frequency = s+v1/ s-v2(f)
Frequency = 343+36 / 343-45(500)
Frequency = 636
Thus, the frequency shift is 636 Hz.
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The complete question is-
A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren relative to the police car is 500 Hz, what is the frequency heard by an observer in the truck after the police car passes the truck? (The speed of sound in air is 343 m/s.)
a). 396 Hz
b). 636 Hz
c). 361 Hz
d). 393 Hz
e). 617 Hz
what is the frequency range of Audible sound
Answers
Answer:20Hz to 20000Hz
Explanation:
Humans can detect sounds in a frequency range from about 20 Hz to 20 kHz.
Which object has potential energy?(1 point)
Responses
unlit lightbulb
unlit lightbulb
rock on the ground
rock on the ground
stereo speaker
stereo speaker
can of gasoline
Answers
The object that has potential energy is the can of gasoline.
What is potential energy?Potential energy is described as the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
The forms of potential energy includes:
Elastic Potential Energy.Electrical (Electromagnetic) Potential Energy.Gravitational Potential Energy.Nuclear Potential Energy.Potential energy is described as the energy a system has due to position, shape, or configuration.
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A force of 200N is creating a pressure of 50Pa on a surface. Calculate the area of the surface.
Answers
Answer:
4kg
Explanation:
pressure=50pa
force=200N
Area=?
now,
pressure=force/area
50=200/area
area=200/50
area=4kg
The pressure is the forces acting on a given area. Hence, the area of the surface with a pressure of 50 Pa by a force of 200 N is 4 m².
What is force?Force is an external agent acting on a object to deform it or to change its state form motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction. The unit of force is Newton (N).
Pressure is the force applied on unit area. Thus, as the force increases, pressure increases. Pressure can have the units in atm, pa, N/m² etc.
Pressure = Force / area.
Given that force = 200 N
pressure = 50 Pa = 50 N/m²
Therefore, area = force/pressure
= 200 N / 50 Pa
= 4 m²
Therefore, the area of the surface is 4 m².
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A curium-242 (Z= 96) can be produced by positive-ion bombardment when an alpha particle collides with which of the following nuclei? Note: A neutron is also a product of this bombardment, in addition to the curium-242.
A. Pu -239
B. U -239
C. Am-241
D. Cf-249
E. Pu-241
Answers
Answer:
A. Pu -239
Explanation:
An isotope is an element with the same atomic number but different mass number. most isotope are unstable, having short half life.
Curium-242 is an isotope produced when Plutonium 239 is bombarded by an alpha particle. This reaction between Plutonium 239 and alpha particle gives curium-242, neutron and a high amount of energy as the products.
Curium oxidizes easily, and it is a dangerous metal which can cause cancer initiation when absorbed by biological materials e.g bones or tissue.
1.If a wooden cube has length and breadth of 1.5 m each and it is exerting a pressure of 1200 pa. What is it's weight (f)?
Answers
Explanation:
Explanation:
Pressure is defined as a Force over an
Area.
p=F/A
We can rearrange this to make the Force
the subject
F = p *A
The pressure is given as 1200 Pa.
We know a pascal is 1 Newton / Square
metre = N/m²
The area of a cube will be width * breadth
= 1.5 m * 1.5 m= 2.25 m²
So the force the cube is pushing down
with (its weight) is simply
F = p * A = 1200 N/m² * 2.25 m² = 2700 N
Weight is officialy defined as a force
measured in Newtons, but when we
talk about weight we often give it in
Kilograms (a unit of mass).
To get the weight in units of
Kilogram-force you must divide by the
gravitational acceleration =9.81 m/s²
2700 / 9.81 = 275.23 Kg
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what will the volume of the helium be when the balloon rises to the point where the atmospheric pressure is 380 mmhg ? assume that the temperature and amount of the helium remain unchanged.
Answers
The volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.
To determine the volume of helium in the balloon, the combined gas law must be applied. The formula for the combined gas law is given by:
PV/T = constant
where P is pressure, V is volume, and T is temperature. Since the temperature and the amount of helium remains unchanged, the combined gas law can be written as P1V1 = P2V2 where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Given that the initial pressure P1 = 760 mmHg and the final pressure P2 = 380 mmHg, the final volume V2 can be determined using:
P1V1 = P2V2
V2 = (P1V1)/P2
V2 = (760 mL)(760 mmHg)/(380 mmHg)
V2 = 1520 mL
Hence, the volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.
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True or false. When populations do not exceed their environment carrying capacity biology communities are stable?
Answers
True
Explanation:
Biology communities are stable when populations do not exceed their environments carrying capacity. Their communities are also stable when the resources for survival are sustained.
Answer:
True
Explanation: