The torque on the loop is τ = IAB = (42 A)(0.19 m x 0.19 m) = 1.147 Nm.
The 150 turn square loop of wire, which is 19 cm on each side, carries a current of 42 A and is placed in a magnetic field of 1.75 T. By using the formula for the magnetic force on a current-carrying wire in a magnetic field (F = I L x B), we can find the total magnetic force on the loop. Since the loop is a closed system, the net force on it will be zero. However, the torque on the loop will not be zero. To calculate the torque, we use the formula τ = IAB sin(θ), where I is the current, A is the area of the loop, B is the magnetic field, and θ is the angle between the normal to the loop and the magnetic field. In this case, since the loop is perpendicular to the magnetic field, θ = 90°, and sin(θ) = 1. Therefore, the torque on the loop is τ = IAB = (42 A)(0.19 m x 0.19 m) = 1.147 Nm.
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5. An object travels with constant speed through 1km for one minutes and 20 seconds and accelerates with 0.125m/s² for 20 seconds, what is the total displacement? A) 1250 m B) 275 m C) 1275 m D) 1225m
Answer:
C) Total displacement = 1275 m or 1.275 km
Explanation:
We'll break this into two parts:
1) Displacement during constant speed, and
2) Displacement during the acceleration phase.
Constant Speed
The displacement for this segment is already stated: 1 km. But the information includes the time, which will allow us to calculate the speed of travel. We'll need this for the next phase of acceleration.
Distance = Speed x Time
Speed = Distance/Time
Time = 1 minute + 20 sec, or 80 sec.
Speed = 1 km/80 sec
Speed = 0.0125 km/sec
Since we'll be using meters (not km) in the next step, convert 0.0125 km/sec to m/sec with a conversion factor:
(0.0125 km/sec)*(1000m/1 km) = 12.5 m/sec
Acceleration Phase
The obect is moving at a speed of 12.5 m/sec (from above) and then accelerates at a rate of 0.125 m/sec^2 for 20 seconds.
The distance (s) an object travels during this acceleration (a) is gven by:
s = vi*t + (1/2)a*t^2,
where vi is the initial velocity (12.5 m/sec in this case), a is the acceleration (0.125 m/sec^2), and t is the time (20 seconds).
s = (12.5 m/sec)(20 sec) + (1/2)(0.125 m/sec^2)*(20 sec)^2
s = 275 meters
Now add the two distances:
1) Constant Speed Phase = 1000 m
2) Acceleration Phase = 275 m
Total displacement = 1275 m or 1.275 km
a planet has 1/2 the mass of earth and 2 times the radius of earth. what is the acceleration due to gravity?
The acceleration due to gravity on a planet with 1/2 the mass of Earth and 2 times the radius of Earth would be one fourth of the acceleration due to gravity on Earth.
What is accelaration?Acceleration is the rate of change of velocity in a given direction. It is a vector quantity, meaning it has both a magnitude (or amount) and a direction associated with it. Acceleration is caused by forces, such as gravity, friction, engine thrust, or any other unbalanced force. It is measured in meters per second squared (m/s2). Acceleration can also be negative, meaning that it is in the opposite direction of the velocity. When an object is accelerating, its speed is increasing but its direction can be changing or staying the same.
This is because the acceleration due to gravity is inversely proportional to the square of the radius, and directly proportional to the mass. Therefore, the acceleration due to gravity on the planet would be (1/2)(1/4) = 1/8 of Earth's gravity.
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Which galaxy helps show scientists how stars and star cluster are formed
w many significant figures does the following number have: 100.00210
Answer:
Number of Significant Figures: 8
The Significant Figures are 1 0 0 0 0 2 1 0
Explanation:
We have that 100.00210 has a 8 significant figure from the rules of Significant figures
8 significant figure
From the question we are told
How many significant figures does the following number have: 100.00210
Generally
Non zeros Number are significant
Zeros that are before a none zero a not significant
Therefore
100.00210 has a 8 significant figure from the rules of Significant figures
8 significant figure
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Electric charge can be built up on what material in the form of static electricity?
A. insulators
B. conductors
C. Semiconductors
D.Superconductors
If you stand 3.0 m in front of a plane mirror, how far away from you would your image appear to be?
Answer Explanation:
If you stand 3.0 m in front of a plane mirror, your image would appear to be 3.0 m behind the plane mirror. This is because the image formed by a plane mirror is always located behind the mirror, at a distance equal to the distance between the mirror and the object being reflected.
So, the distance from you to the mirror is 3.0 m, and the distance from the mirror to your image is also 3.0 m, for a total distance of 6.0 m between you and your image.
If you are on a boat in the trough of a wave on the ocean, and the wave amplitude is 1 meter, what is the wave height from your position?
Group of answer choices
4 meters 2 meters .5 meters 1 meter
Answer:
2 meters
Explanation:
In oceanography, the term "wave height" refers to the vertical distance between the crest (the highest point) and the trough (the lowest point) of a wave. If you are situated in the trough of a wave, the wave height would be double the wave amplitude.
In this case, you mentioned that the wave amplitude is 1 meter. Therefore, the wave height from your position in the trough would be 2 meters.
Boat Engine An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. What power does the engine develop
An engine moves a boat through the water at a constant speed of 15 m/s. The engine must exert a force of 6.0 kN to balance the force that the water exerts against the hull. Power is the measure of how fast work can be done. The unit of power is watts (W), which can be defined as the amount of work done in one second.
Power is usually calculated as the product of the amount of work done and the time it takes to do it. Power can also be defined as the rate at which work is done.First, we need to calculate the work done by the engine. Work = Force x distance . Since the boat moves at a constant speed of 15 m/s, we can use the following formula to calculate the distance traveled by the boat:Distance = Speed x TimeTherefore, distance = 15 m/s x 1 s = 15 m Now we can calculate the work done by the engine:Work = Force x Distance = 6.0 kN x 15 m = 90 kJNow that we know the amount of work done by the engine, we can use the formula for power:Power = Work/Time Since we don't know the time it took the engine to do the work, we can't calculate power directly. However, we can make some assumptions and estimate the time it took the engine to do the work. For example, if we assume that the engine did the work in one minute, then the time is 60 seconds:Power = Work/Time = 90 kJ/60 s = 1.5 kWTherefore, the power developed by the boat engine is 1.5 kW.For such more question on measure
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Hello! I would greatly appreciate your help with this momentum problem.
Momentum = Mass x Velocity
The mass of the electron is given as:
\(m=9.1\times10^{-31}kg\)The
Which of the following would be most helpful in evaluating the extent to which human activity is responsible for recent changes in the atmosphere?
OPTIONS
Data on the effects of atmospheric changes on non-human organisms
Historical data on atmospheric conditions prior to humans
Data on the conditions on planets similar to Earth that lack an atmosphere
Projected data for future atmospheric conditions at current rates of change
Human activity is responsible for recent changes in the atmosphere i.e. the last option , projected data for future atmospheric conditions at current rates of change.
The term "atmosphere" refers to a layer (or layers) of gases that surround a planet and are kept in place by the gravity of the planetary body. A planet maintains its atmosphere when the gravity is high and the temperature of the atmosphere is low.The troposphere, stratosphere, mesosphere, and thermosphere are the four layers that make up the Earth's atmosphere, and they are differentiated by temperature.Therefore we can said that, The last option from the question projected data for future atmospheric conditions at current rates of change, states that human activity is to responsible for recent changes in the atmosphere.
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What would be the final velocity, in m/s, if a disk of the same mass and radius as the hoop rolled down the hill?.
The final velocity will be \(\rm V= \sqrt{\frac{4gh}{3} }\ m/sec\). Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
What is velocity?The change of distance with respect to time is defined as speed.
From the law of conservation of energy:
\(\rm KE_i + PE_i = KE_f+PE_f \\\\ 0+mgh = \frac{1}{2} mV^2 +\frac{1}{2} I\omega^2\)
The moment of inertia of the disc;
\(\rm I= mr^2\)
It can also be found as;
\(\rm I = \frac{V}{r} \\\\\)
Put the obtained values;
\(mgh = \frac{1}{2} mv^2+\frac{1}{2} mv^2=mv^2\\\\ mgh = mv^2 \\\\ v=\sqrt{gh}\)
if a disk of the same mass and radius as the hoop rolled down the hill;
\(mgh= \frac{1}{2} M+\frac{mr^2}{2r^2} V^2 \\\\ gh = \frac{3}{4} V^2 \\\\ V= \sqrt{\frac{4gh}{3} }\ m/sec\)
Hence the final velocity will be \(\rm V= \sqrt{\frac{4gh}{3} }\ m/sec\).
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a sample of radioactive material emits 400000 particles over a period of 20 minutes calculate the activity of the source in Becquerel
The activity of the source in Becquerel is 333.3Bq
What is Activity ?The number of nuclei that disintegrate or decay per unit time is known as Activity.
Given that a sample of radioactive material emits 400000 particles over a period of 20 minutes.
N = 400000 particlest = 20 min = 20 x 60 = 1200 sActivity A = dN/dt
A = 400000 / 1200
A = 333.3 particles / s
A = 333.3 Bq
Therefore,
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if the power of sound at the source outlet is 100 w, what is its intensity at 4 m away from the source?
The intensity of sound is inversely proportional to the square of the distance from the source. The intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).
The intensity of sound is defined as the power per unit area. According to the inverse square law for sound propagation, the intensity of sound is inversely proportional to the square of the distance from the source. Mathematically, it can be expressed as
\(I=P/(4\pi r^{2})\)
where I is the intensity, P is the power, and r is the distance from the source.
Given that the power of sound at the source outlet is 100 W and the distance from the source is 4 m, we can substitute these values into the formula. Thus, we have
\(I = 100 W / (4\pi (4 m)^2)\)
Simplifying this expression, we find that the intensity of sound at 4 m away from the source is approximately \(0.993W/m^{2}\) (watts per square meter).
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Consider the following model, which estimates the consumption of cigarettes for a sample of 127 individuals: Cigs =-3.64+ 0.88 log(income) - 0.75 log (price)- 0.50 educ (2.11) (0.73) (5.77) (0.17) + 0.77 age-0.008 age²+ 2.83 restaurant (0.002) (1.11) (0.16) N = 127 SSE = 13.25 SSR = 8.75 Where, Cigs is the number of cigarettes smoked per week, income is the individual's income in pounds, price is the average price of a packet of cigarettes, educ is the individual's number of years of schooling, age is the individual's age in years, and restaurant is a dummy variable that equals 1 if a restaurant allows for smoking and 0 otherwise.
(a) Carefully interpret all of the estimated coefficients. (6 marks)
(b)Calculate and comment on the value of the R-squared and the Adjusted R-squared for the estimated model. Explain why they are different. (6 marks)
(c) Perform a 1% individual significance test for each slope coefficient. Comment on your results. State the null and the alternative hypotheses for each one. (6 marks)
(d) Calculate the 90% confidence interval for each slope coefficient. (6 marks)
(e)Perform a 5% test of the overall significance of the regression model. Comment on your results. State the null and the alternative hypotheses.
(a)
- The coefficient of log(income) (0.88) suggests that a 1% increase in income is associated with a 0.88% increase in cigarette consumption, holding other variables constant.
- The coefficient of log(price) (-0.75) indicates that a 1% increase in cigarette prices is associated with a 0.75% decrease in cigarette consumption, holding other variables constant.
- The coefficient of educ (-0.50) implies that a one-year increase in education is associated with a 0.50 unit decrease in cigarette consumption, holding other variables constant.
- The coefficient of age (0.77) suggests that a one-year increase in age is associated with a 0.77 unit increase in cigarette consumption, holding other variables constant.
- The coefficient of age squared (-0.008) indicates that the relationship between age and cigarette consumption is not linear, and as age increases further, the rate of increase in cigarette consumption slows down.
- The coefficient of restaurant (2.83) implies that individuals who have access to smoking in restaurants smoke, on average, 2.83 more cigarettes per week compared to those who do not have access.
(b) The R-squared measures the proportion of the total variation in cigarette consumption that is explained by the independent variables. In this case, the R-squared is not provided, so it cannot be calculated or commented upon.
The Adjusted R-squared takes into account the number of variables and the sample size, providing a more reliable measure of model fit. Unfortunately, the Adjusted R-squared is also not provided, so it cannot be calculated or commented upon.
The difference between R-squared and Adjusted R-squared lies in the penalization of the latter for including additional variables that may not significantly contribute to the model.
(c) To perform a 1% individual significance test for each slope coefficient, we need the t-statistics and the corresponding p-values for each coefficient. These values are not provided, so we cannot perform the significance tests or comment on the results.
The null hypothesis (H0) for each significance test would be that the corresponding slope coefficient is equal to zero. The alternative hypothesis (Ha) would be that the slope coefficient is not equal to zero.
(d) The confidence interval for each slope coefficient can be calculated using the provided standard errors and assuming a t-distribution. However, the standard errors are not provided in the given format, so we cannot calculate the confidence intervals.
(e) To perform a 5% test of the overall significance of the regression model, we need the F-statistic and its corresponding p-value. Unfortunately, these values are not provided, so we cannot perform the test or comment on the results.
The null hypothesis (H0) for the overall significance test would be that all slope coefficients are equal to zero, indicating that none of the independent variables have a significant effect on cigarette consumption. The alternative hypothesis (Ha) would be that at least one of the slope coefficients is not equal to zero, indicating that at least one independent variable has a significant effect on cigarette consumption.
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Ganymede, the largest of Jupiter’s moons,
is also the largest satellite in the solar system. Find the acceleration of
gravity on Ganymede if a simple pendulum with a length of 1.00 m has a period
of 10.5 s
Answer:hereeee for pointssss only
Explanation:
The acceleration of gravity on Ganymede will be \(g=0.35\ \frac{m}{s^2}\)
What will be the acceleration of gravity on Ganymede?It is given that for a simple pendulum on Ganymede
Lenth= 1.00 m
the time period T= 10.5 sec
The formula for a time period of simple pendulum will be
\(T=2\pi\sqrt{\dfrac{l}{g} }\)
By rearranging the formula
\(g=l\times (\dfrac{2\pi}{T} )^2\)
\(g=1\times (\dfrac{2\pi}{10.5} )^2=0.3577\frac{m}{s^2}\)
\(g=0.3577\ \frac{m}{s^2}\)
Thus the acceleration of gravity on Ganymede will be \(g=0.35\ \frac{m}{s^2}\)
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What are physical characteristics of roundworms? Hint: There are two stages of reproduction.
Answer:
Roundworms:
The size of roundworms ranges from microscopic to as long as a meter long. Most roundworms have a hard, sharp lance on their head, and some have bristles on the head. Most of the roundworms are protected by an adaptable yet solid, furrowed body covering.
Roundworms are very primitive living beings, having no respiratory or circulatory system of a host. They have an empty body with two openings at the closures. Be that as it may, the head isn't particular or recognizable to the unaided eye.
Roundworms reproduce sexually and can finish their life cycle in immature puppies, however as the little pupps immunity system develops (for the most part by a half-year-old enough), the larval phases of the roundworm will become captured and will encyst (become encased in a sore) in the puppy's muscles. They can stay encysted in the pooch's tissues for a considerable length of time or years.
find the relative density of copper block of mass 216 gram having volume of 80 cm cube ( cm3) . Density of water is 1g/ cm3.
Classify the model v=0.15(2.7)^t as exponential growth or exponential decay. then identify the growth or decay factor of the model.
The model v=0.15(2.7)^t is an exponential growth model with a growth factor of 2.7.
The given model v=0.15(2.7)^t can be classified as exponential growth because the base of the exponent (2.7) is greater than 1. This means that as t increases, the value of v increases exponentially.
The growth factor of the model is 2.7, which represents the factor by which v increases with each unit increase in t. In other words, for each additional unit of time, v grows by a factor of 2.7. This value can also be referred to as the "multiplicative factor" or "growth rate" of the exponential growth model.
Therefore, the model v=0.15(2.7)^t is an exponential growth model with a growth factor of 2.7.
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Can God make a rock that He can't carry?
Answer:
The answer to the question lies in the character of God. God is either finite or infinite. If God is finite and limited, then God could make a rock He could not lift. If God is unlimited in power, then He could create a rock of any size and weight and still be able to lift it.
Explanation:
A person of mass 40 kg stands on a bathroom scale in an elevator. What is the reading on the scale if:A. The elevator is stationary?B. The elevator is moving up at a constant speed?C. The elevator accelerates upwards at 5.00 m/s2D. The elevator accelerates downwards at 5.00 m/s2
Given data
*The given mass of the person is m = 40 kg
*The value of the acceleration due to the gravity is g = 9.8 m/s^2
(A)
The reading on the scale is calculated when the elevator is stationary is given as
\(\begin{gathered} R=mg \\ =(40)(9.8) \\ =392\text{ N} \end{gathered}\)(B)
The formula for the reading on the scale when the elevator is moving up at constant speed is given as
\(\begin{gathered} N=mg \\ =(40)(9.8) \\ =392\text{ N} \end{gathered}\)(C)
The formula for the reading on the scale when the elevator accelerates upwards at 5.00 m/s^2 is given as
\(N=m(g+a)_{}\)Substitute the known values in the above expression as
\(\begin{gathered} N=(40)(9.8+5) \\ =592\text{ N} \end{gathered}\)(D)
The formula for the reading on the scale when the elevator accelerates downwards at 5.00 m/s^2 is given as
\(N=m(g-a)_{}\)Substitute the known values in the above expression as
\(\begin{gathered} N=(40)(9.8-5.0) \\ =192\text{ N} \end{gathered}\)Please help me with this..show all the steps also...
Given,
initial velocity, u = 10m/s
acceleration, a = -8m/s²
time, t = 2s
\(we \: know \: that \\ s = ut + \frac{1}{2}a {t}^{2} \\ = > s = (10m {s}^{ - 1} \times 2s) + ( \frac{1}{2} \times (- 8m {s}^{ - 2}) \times {(2s)}^{2}) \\ = >s = 10m + (- 8m) \\ = > s = 2m\)
This is the answer.
Hope it helps!!
Identify the major ionic species present in an aqueous solution of FeCl3.
O Fest, ali
O Fe3+, 30-
O Fe2+ 3 CH-
O Fer. 30
Question 3
The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.
What is ion?Conventionally, the charge of an electron is thought to be negative; this charge is equal to and opposite to the charge of a proton, which is thought to be positive. Because the total number of electrons in an ion is more than the total number of protons, the net charge of an ion is not zero.
A negatively charged ion called an anion has more electrons than protons compared to a positively charged ion called a cation. Electrostatic force causes opposite electric charges to be drawn towards one another, causing cations and anions to attract one another and easily form ionic compounds.
Hence, The major ionic species present in an aqueous solution of FeCl3 is Fe³⁺.
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Why don't atoms get too close?
a.) The electrons from atom repel each other
b.) The protons from each atom repel each other
c.) The neutrons from each atom repel each other
Answer:
This tends not to happen, because atoms are composed of charged particles that interact at a distance. ... Since the electrons are around the outside of the atom, those are the things that first interact, and as they have the same charge, they repel one another.A. The electrons from atom repel each other
Cody lives in Florida along the eastern coast. The kind of air mass likely to occur
over his region would be
Choose...
. It would develop here because
Choose...
.
The speed of a car will increase if the car’s
Answer:
moving at a fast pace
Explanation:
The mass of earth 6*10^24kg its radius is 6.4*10^3km now calculate due to gravity on earth
Answer:
Explanation:
in your textbook, they have a formula like this:
g=mass of earth*G/R^2
G=6.67*10^-11
apply to this
we have g=6*10^2*4*6.67*10^-11/(6.4*10^3*1000)^2=9.78
Calculate the force acting
on a body whose linear momentum changes by 10 kg m/s
in 5 seconds.
Answer:2n
Explanation:10/5=2
Question: In an average year, the Creek drainage basin (150 mi^2) receives 550 mm of precipitation. Has an average stream discharge of 1.8 m^3s^-1. (1 mile = 1.609 km).
Please develop the water budget equation for this problem.
The water budget equation for the Creek drainage basin is: Precipitation = Stream discharge + Evapotranspiration ± Change in storage.
To develop the water budget equation for this problem, we need to account for the inputs and outputs of water in the Creek drainage basin. The water budget equation can be expressed as,
P = Q + ET ± ΔS
P = Precipitation input (mm)
Q = Stream discharge (m³/s)
ET = Evapotranspiration (mm)
ΔS = Change in storage (mm)
First, let's convert the units of the given values,
Precipitation input (P) = 550 mm
Stream discharge (Q) = 1.8 m³/s
Now, let's determine the evapotranspiration (ET) and change in storage (ΔS) terms. However, the problem doesn't provide information about ET, so we cannot calculate it accurately. The problem doesn't provide information about ΔS, so we cannot calculate it accurately.
Given these limitations, we can write the simplified water budget equation for this problem,
550 mm = 1.8 m³/s + ET ± ΔS
Please note that without information about evapotranspiration and changes in storage, we cannot fully determine the water budget for the Creek drainage basin.
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A man is paddling a kayak with the force of 254 N, at an acceleration of 1.39 m/s2. If the kayak weighs 30 kg, what is the mass of the man?
the paschen series is analogous to the balmer series, but with m=3.
The Paschen series is a spectral series of hydrogen-like atoms that is similar to the Balmer series, but with a different value of the principal quantum number.
Specifically, the Paschen series corresponds to transitions between an excited state with principal quantum number n greater than or equal to 3, and the n=3 energy level in hydrogen-like atoms.
Like the Balmer series, the Paschen series also produces a series of spectral lines, which are the result of the emission of electromagnetic radiation as the electrons in the atom transition from higher energy levels to lower energy levels.
However, the wavelengths of the spectral lines in the Paschen series are longer than those in the Balmer series, due to the higher energy levels involved.
Overall, the Paschen series is an important aspect of the study of atomic physics, and provides valuable insights into the behavior of hydrogen-like atoms and their spectral emissions.
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