The complexity of design and construction of mechanical parts can be a major limitation of mechanical computation.
The wear, breakdown, and maintenance of mechanical parts can cause problems that may be difficult to solve. For example, a machine may need to be taken apart and re-assembled in order to fix problems. This can take a significant amount of time and effort, which may be difficult to justify if the machine is not used frequently.
Additionally, the complexity of the design and construction of mechanical parts can affect the accuracy and reliability of the computation. Due to the complexity of the parts, it can be difficult to ensure that they are all properly aligned and that they are all functioning correctly. This can lead to reduced accuracy and reliability in the computation.
Finally, mechanical parts are subject to wear and tear, which can further reduce the accuracy and reliability of the computation over time. In short, the complexity of design and construction, as well as the wear, breakdown, and maintenance of mechanical parts, can be major limitations and shortcomings of mechanical computation.
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Define the term overload.
Answer:
Verb. Load with too great a burden or cargo.
"Both boats were overloaded and low in the water"
Noun. An excessive load or amount.
"an overload of stress"
Explanation:
Similar words are strain, excess, and overburden.
Have a good day and stay safe!
A car drives to the right. There is a large amount of air resistance, and the car's engine provides the car's forward motion. Which force on the free-body diagram below represents the normal force acting on the car?
A force on the free-body diagram above which represents the normal force acting on the car include the following: D. Force A.
What is a free-body diagram?In Science, a free-body diagram can be defined as a graphical illustration which is typically used in the field of science to visualize moments, tension, and applied forces that are acting on an isolated or rigid object (body), while using arrows to point in the direction of these forces.
Since this car was driven to the right, with a large amount of air resistance acting on it, and its engine provides the forward motion, we can reasonably infer and logically deduce that the normal force which is acting on the car is represented by Force A as illustrated by the free-body diagram shown in the image attached above.
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the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?
Answer:
43.3 m/s.
Explanation:
Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:
Total energy = Potential energy + Kinetic energy
Kinetic energy = Total energy - Potential energy
Kinetic energy = 300 J - 40 J = 260 J
However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:
Potential energy = mgh
40 J = m(9.81 m/s^2)(300 m)
m = 0.137 kg
Now we can use the kinetic energy to find the velocity:
Kinetic energy = (1/2)mv^2
260 J = (1/2)(0.137 kg)v^2
v^2 = (2*260 J) / 0.137 kg
v = 43.3 m/s (rounded to one decimal place)
Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.
9) Theta is the symbol used to measure which of the following quantity*
1 point
Answer:
Theta is used to measures angles
A telephone pole casts a clear shadow in the light from a distant head lamp of a car, but no such effect is noticed for the sound from the car horn. why?
Answer:
A telephone pole casts a clear shadow in the light from a distant head lamp of a car, but no such effect is noticed for the sound from the car horn. Why? Answer: The sound and light both are waves. But the wavelength of sound waves is very large as compared to the wavelength of light waves.
Explanation:
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find the resultant of the following forces (i) 10 N along x-axis
The resultant force due to the cumulative forces acting on the body is 6i+6j N.
Force is a vector quantity and the direction in which they act affects the total magnitude of force. A vector quantity has both magnitude and direction.
And to add a vector one needs to take account of the direction as well.
The force acting on the body can be written as follow:
1. 10N along x-axis ---- 10i
2. 6N along y-axis ---- 6j
3. 4N along negative x-axis ----- -4i
The resultant force is the sum of the above vector:
10i +6j + (-4i) = 6i+6j N
The magnitude of the total force is
\(\sqrt{6^2+6^2}\\ =\sqrt{36+36}\\ =\sqrt{72}=6\sqrt{2} N\)
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The complete question is:
Find the resultant of the following forces
(i) 10 N along the x-axis
(ii) 6 N along the y-axis
(iii) 4 N along the negative x-axis
El espectro visible en el aire está comprendido entre la longitud de onda 450 nm del color azul, Determina la velocidad de propagación.
Answer:
v = 2,99913 10⁸ m / s
Explanation:
The velocity of propagation of a wave is
v = λ f
in the case of an electromagnetic wave in a vacuum the speed that speed of light
v = c
When the wave reaches a material medium, it is transmitted through a resonant type process, whereby the molecules of the medium vibrate at the same frequency as the wave, as the speed of the wave decreases the only way that they remain the relationship is that the donut length changes in the material medium
λ = λ₀ / n
where n is the index of refraction of the material medium.
Therefore the expression is
v = \(\frac{\lambda_o}{n} f\)
Let's look for the frequency of blue light in a vacuum
f =\(\frac{c }{\lambda_o}\)
f = \(\frac{3 \ 10^8}{450 \ 10^{-9}}\)
f = 6.667 10¹⁴ Hz
the refractive index of air is tabulated
n = 1,00029
let's calculate
v = \(\frac{450 \ 10^{-9} }{1.00029} \ 6.667 \ 10^{14}\)450 10-9 / 1,00029 6,667 1014
v = 2,99913 10⁸ m / s
we can see that the decrease in speed is very small
Is net weight same thing as net force? i was wondering that for my science.
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Charge A and charge B are 2. 2 m apart. Charge A is 1. 0 C, and charge B is
2. 0 C. Charge C, which is 2. 0 C, is located between them and is in
electrostatic equilibrium. How far from charge A is charge C?
The distance between charge A and charge C can be either 0.99 m or 1.01 m, depending on the specific arrangement of the charges.
To determine the distance between charge A and charge C, we can use the concept of electrostatic equilibrium. In electrostatic equilibrium, the net electrostatic force acting on a charged object is zero. This means that the electrostatic forces between charge A and charge C, and between charge B and charge C, must balance each other out.Let's assume that charge C is located at a distance x from charge A. The force between charge A and charge C can be calculated using Coulomb's law:
F_AC = k * (q_A * q_C) / (r_AC^2),where F_AC is the force between charge A and charge C, k is the electrostatic constant, q_A is the charge of A, q_C is the charge of C, and r_AC is the distance between A and C.Similarly, the force between charge B and charge C can be calculated as:
F_BC = k * (q_B * q_C) / (r_BC^2),
where F_BC is the force between charge B and charge C, q_B is the charge of B, and r_BC is the distance between B and C.
Since the system is in electrostatic equilibrium, F_AC must be equal in magnitude but opposite in direction to F_BC. Therefore, we have:
F_AC = F_BC
k * (q_A * q_C) / (r_AC^2) = k * (q_B * q_C) / (r_BC^2)
Simplifying and rearranging the equation:
(q_A * q_C) / (r_AC^2) = (q_B * q_C) / (r_BC^2)
q_A / r_AC^2 = q_B / r_BC^2
1.0 C / (2.2 m - x)^2 = 2.0 C / (2.0 m + x)^2
Now we can solve this equation for x. Cross-multiplying and simplifying:
(2.0 C) * (2.2 m - x)^2 = (1.0 C) * (2.0 m + x)^2
4.0 C * (4.84 m^2 - 4.4 m x + x^2) = 2.0 C * (4.0 m^2 + 4.0 m x + x^2)
Expanding and simplifying:
19.36 C m^2 - 17.6 C m x + 4.0 C x^2 = 8.0 C m^2 + 8.0 C m x + 2.0 C x^2
Rearranging and simplifying further:
14.36 C m^2 - 25.6 C m x + 2.0 C x^2 = 0
Now we can solve this quadratic equation for x using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a),
where a = 2.0 C, b = -25.6 C m, and c = 14.36 C m^2.
Solving this equation, we find two possible solutions for x:
x = 0.99 m and x = 1.01 m.
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What is the next challenge facing Edison to make electrical lighting possible?
Finding a suitable material for the filament of an incandescent light bulb was one of Thomas Edison's biggest obstacles.
What is filament ?The source of light in an incandescent light bulb is the filament, which is a wire-like structure. It is often constructed of tungsten or another material with a high melting point and good thermal shock resistance. When an electric current is sent through the filament, which is commonly twisted into a coil or loop shape, the filament heats up and starts to generate light.
Thermal radiation causes the filament to produce light. This is the result of the filament's temperature-related electromagnetic radiation output. The filament starts to emit infrared radiation and visible light as it warms up.
The filament's temperature and the kind of material it is constructed of affect the hue of the light it emits.
A glass bulb that has been evacuated or a bulb that has been filled with an inert gas, such as argon or nitrogen, surrounds the filament in an incandescent light bulb. By doing this, you can avoid the filament from burning out or breaking, which would make the lightbulb unusable.
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A 2.0 kg melon is balanced on a circus performer's head. An archer shoots a 50.0 g arrow at the melon with a speed of 30 m/s. The arrow passes through the melon and emerges with a speed of 18 m/s. Find the speed of the melon as it flies off the performer's head.
The speed of the melon as it flies off the performer's head is 0.3 m/s
Law of conservation of momentum?The law of conservation of momentum states that for a system of colliding bodies, the total momentum before the collision is equal to the total momentum after the collision, provided there is no net external force acting on the bodies.
To find the speed of the melon, we use the formula from the law of conservation of momentum.
Formula:
mu+m'u' = mv+m'v'............ EquationWhere:
m = mass of the melonu = initial velocity of the melonm' = mass of the arrowu' = initial velocity of the arrowv = final velocity of the melonv' = final velocity of the arrow.From the question,
Given:
m = 2 kgm' = 50 g = 0.05 kgu = 0 m/s (at rest)u' = 30 m/sv' = 18 m/s.Substitute these values into equation 1
(2×0)+(0.05×30) = (0.05×18)+(2×v)0+1.5 = 0.9+2v2v = 1.5-0.92v = 0.6v = 0.3 m/s.Hence, The speed of the melon as it flies off the performer's head is 0.3 m/s.
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Which of the following energies defines energy stored inside a spring?
A. Gravitational Potential
B. Elastic potential
C. Kinetic
Answer:
Elastic potential energy
How much acceleration is given to a 45 kg child with a 630 N push on a swing?
Hii :))
Force = mass × acceleration
630 = 45 × acceleration
630/45 = acceleration
14 m/s² = acceleration
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________ causes cast of gases to clump together to begin forming new stars and planets.
Gravity causes cast of gases to clump together to begin forming new stars and planets.
Gravity binds the gas and dust together. If the cluster is large enough, it produces a star—increased pressure from gravitational collapse boosts the temperature, forcing nuclear fusion to occur in its center.
The dust and gases in a nebula are widely dispersed, yet gravity can gradually bring clumps of dust and gas together. As these clusters grow in size, their gravity grows stronger and stronger. The clump of dust and gas eventually becomes so large that it collapses due to its own gravity.
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A stone is thrown vertically upward from the ground level with a speed of 25m/s . At what time is it 5m above the ground?
Answer:
Approximately \(0.21\; {\rm s}\) and then approximately \(4.8\; {\rm s}\), assuming that air resistance on the stone is negligible and that \(g = -10\; {\rm m\cdot s^{-2}}\).
Explanation:
Let \(h\) denote the height of the stone.
Let \(g\) denote the gravitational acceleration.
Let \(v_{0}\) denote the initial velocity of the stone. In this question, \(v_{0} = 25\; {\rm m\cdot s^{-1}}\).
Let \(t\) denote the time (measured in seconds) after the stone was thrown.
The following SUVAT equation relates these quantities:
\(\displaystyle h = \frac{1}{2}\, g\, t^{2} + v_{0}\, t\).
The value of height \(h\), gravitational acceleration \(g\), and initial velocity \(v_{0}\) are all known: \(h = 5\; {\rm m}\), \(g = (-10\; {\rm m\cdot s^{-2}})\), and \(v_{0} = 25\; {\rm m\cdot s^{-1}}\). Substitute these values into the equation to obtain a quadratic equation about time \(t\) (in seconds):
\(\displaystyle 5 = \frac{(-10)}{2}\, t^{2} + 25\, t\).
Simplify this equation to obtain:
\(t^{2} - 5\, t + 1 = 0\).
Solve this equation using the quadratic formula. The two roots of this quadratic equation about \(t\) are:
\(\displaystyle t_{1} \approx 0.20871 \; {\rm s}\), and
\(\displaystyle t_{2} \approx 4.79129 \; {\rm s}\).
Both roots are greater than \(0\) and are valid.
The object would be at a height of \(5\; {\rm m}\) above the ground at \(\displaystyle t_{1} \approx 0.20871 \; {\rm s}\) after launch on its way up. At \(\displaystyle t_{2} \approx 4.79129 \; {\rm s}\), the object would be on its way back to the ground and would also be \(5\; {\rm m}\!\) away from the ground. (30 POINTS) A body with a mass of 3kg is rotating around its axis at a constant speed, and completes
one round in 20s what's its angular speed in rad/s?
Answer:
See below
Explanation:
One rotation is 2 pi R
2 pi / 20 s = .314 R/s ( or pi / 10 R/s)
(NOTE: mass of the body is irrelevant)
You are running late for class and are still in the hallway when the bell rings. The tardy bell is right outside your classroom door, and your teacher is standing directly beneath it. If you are running towards the bell when it rings, which of the following best describes what you hear? (DOK 1)
Question 8 options:
A. You hear a higher pitch than your teacher
B. You hear a lower pitch than your teacher
C. You hear a louder pitch than your teacher
D. You hear the same pitch as your teacher
Answer:
C
Explanation:
You will hear a lower pitch of sound than your teacher who is directly below the bell.
The pitch of a sound refers to how high or low the sound is. If a sound is high we say that it has a high pitch and vice versa.
We must note that the closer you are the bell the higher the pitch of the bell sound you hear. Hence, you will hear a lower pitch of sound than your teacher who is directly below the bell.
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Potential energy is measured in units of
Answer:
Joules
Explanation:
Potential energy is energy an object has because of its position relative to some other object. ... Notice that gravitational potential energy has the same units as kinetic energy, kg m2 / s2. In fact, all energy has the same units, kg m2 / s2, and is measured using the unit Joule (J).
a cyclist cycles 15 km west and then 15 km north. what is the magnitude of her displacement vector?
Answer:
21.2 km
Explanation:
You're basically solving for the hypotenuse of a right triangle with legs of 15 and 15. Use the pythagorean theorem:
d = displacement vector
d² = 15² + 15² = 450
d = √450 = 21.2 km
how do u cure a headache without any pills no bots or I will report u?
Answer:
Try a Cold Pack. Use a Heating Pad or Hot Compress. Ease Pressure on Your Scalp or Head. Dim the Lights. Try Not to Chew. Hydrate. Get Some Caffeine. Practice Relaxation.
Answer:
Listen to calming music
Explanation:
Thats what I do. You could also sleep ;)
I need help this is extremely hard
Answer:
For the first one shown, the answer is Directly Proportional, The second one is Inversly Proportional, and the last is fourtl times the original value
Suppose we conduct an experiment with a ball that we throw from the top of a tall tower of height H. We throw it directly downward with some initial velocity v. and then measure the clapsed time until it hits the ground. We vary the initial height and the initial velocity. The variables of interest in this problem are H. v. and r. A little thought leads us to include g. since it is the force of gravity that causes the ball to fall in the first place. Using Rayleigh's method, find a set of dimensionless ratios that can be used to correlate our data.
Using Rayleigh's method, a set of dimensionless ratios that can be used to correlate our data is the ratio of initial velocity to the square root of the product of acceleration due to gravity and height.
Rayleigh's method for dimensionless ratiosIn order to find a set of dimensionless ratios to correlate the data in the given experiment, we can use Rayleigh's method. Rayleigh's method involves selecting a set of relevant physical quantities and combining them in such a way that the resulting ratios are dimensionless.
In this case, the relevant physical quantities are:
Height (H)Initial velocity (v)Radius (r)Acceleration due to gravity (g)To create dimensionless ratios, we can choose combinations of these quantities that eliminate the units. One possible set of dimensionless ratios can be:
Ratio of initial velocity to the square root of the product of acceleration due to gravity and height:
v / √(gH)
Ratio of radius to height:
r / H
These dimensionless ratios can be used to correlate the data obtained from the experiment. By plotting these ratios against each other or against other relevant parameters, it may be possible to identify relationships or trends in the data that can be described using these dimensionless ratios.
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Design a differentiator to produce and output of 6v when the input voltage changes by 3v in 100 m.
A differentiator circuit with a capacitor of 20 µF and a resistor of 50 Ω can produce an output of 6V when the input voltage changes by 3V in 100ms.
A differentiator circuit produces an output that is proportional to the rate of change of the input voltage. The circuit consists of a capacitor and a resistor. When the input voltage changes, the capacitor charges or discharges through the resistor, producing an output voltage.
The output voltage of a differentiator circuit is given by the formula:
Vout = -RC(dVin/dt)
where R is the resistance, C is the capacitance, Vin is the input voltage, and t is time.
To design a differentiator circuit that produces an output of 6V when the input voltage changes by 3V in 100ms, we can use the formula and solve for R and C. Rearranging the formula gives:
RC = -Vout/(dVin/dt)
Substituting the given values, we get:
RC = -6V/(3V/100ms) = -200ms
Let's assume a capacitance of 20µF, then the resistance can be calculated as:
R = RC/C = (-200ms * 20µF) / (20µF) = -200Ω
We can use a standard resistor value of 50Ω, which will give us a slightly higher output voltage of 6.25V.
Therefore, a differentiator circuit with a capacitor of 20 µF and a resistor of 50 Ω can produce an output of 6V when the input voltage changes by 3V in 100ms.
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a solid plastic cylinder of radius 2.33 cm and length 6.30 cm. find the charge of this cylinder, in nc (nanocoulombs), given that its has a uniform surface charge density of 13.8 nc/m2 everywhere on its surface.
The charge of this cylinder is calculated as 10.2 nC. The formula for the charge of a cylinder with uniform surface charge density is ; Q = (charge density) * (surface area) * (length).
Charge density = σ,
Surface area = 2πrh + 2πr²,
Length = l
Given : Radius, r = 2.33 cm, Length, l = 6.30 cm,
Charge density, σ = 13.8 n c/m²,
Surface area of cylinder = 2πrh + 2πr² where; h = l (length)
Substitute the value of radius and height in the above formula, we get;
Surface area of cylinder = 2πr(l + r)
Surface area of cylinder = 2π(2.33 cm)(6.30 cm + 2.33 cm)
= 119.38 cm²
Charge density, σ = 13.8 nc/m²
= 1.38 × 10⁻⁵ C/cm²
Now, put the value of σ, surface area, and length in the formula to calculate the charge of cylinder as;
Q = σ * surface area * length
Q = (1.38 × 10⁻⁵ C/cm²) * (119.38 cm²) * (6.30 cm)
Q = 1.02 × 10⁻² C = 10.2 nC
Therefore, the charge of this cylinder is 10.2 nC (nanocoulombs).
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An air conditioner uses a compressor to raise the temperature and pressure of _____. A. The outside air
B. The refridgerant
C. The inside air
Answer:
B. The refridgerant
Explanation:
this allows the refrigerant to absorb or release heat
calculate the movement of a 2000-kg truck travelling 19m/s
Answer:
The movement of a 2000-kg truck travelling at 19 m/s is 38,000 kgm/s.
Which two characteristics increase the strength of the gravitational force
between two objects?
A. Having centers that are closer together
B. Having hollow centers
C. Having greater masses
D. Having greater charges
Answer:
The answer is A and C.
Explanation:
Only two factors are relevant when dealing with the gravitational force between two objects - their mass and their distance apart from one another. Gravity's force is proportional to the product of the masses of the two objects and is inversely proportional to the square of the distance between them.
The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity. If a wind of 60mph exerts a force of 20lb on a surface of 1/5 ft², how much force will a wind of 180mph place on a surface of 4ft²?
A wind of 180mph will place a force of ____ Ib on a surface of 4ft². (Type an integer or a simplified fraction.)
A wind of 180mph will place a force of 32400 Ib on a surface of 4ft².
The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity.
If a wind of 60mph exerts a force of 20lb on a surface of 1/5 ft², how much force will a wind of 180mph place on a surface of 4ft²
A force of 1250lb is exerted
since the force of the wind varies jointly as the area of the surface and the square of the velocity,
let f = force
a = area
velocity =v
from the above statement, we find out that
f ∝ a * v²----1
that is f = k * a * v² -----2
where k is a coefficient of proportionality
since velocity of wind in mph, v =60
and force in lb = 20
and surface area = 1/5 ft²
from equation 2
20 = 1/5 * k * 60²
20 * 5 /3600 = k
25/9 = k
A wind of 180mph will place a force of on a surface of 4ft².
f = 25/ 9 *4 * 180²
f = 32400
Therefore, a wind of 180mph will place a force of 32400 Ib on a surface of 4ft².
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Part A A thin, 54.0 cm long metal bar with mass 740 g rests on, but is not attached to, two metallic supports in a uniform magnetic field with a magnitude of 0.450 T, as shown in (Figure 1). A battery and a resistor of resistance 26.0 12 are connected in series to the supports. What is the largest voltage the battery can have without breaking the circuit at the supports? For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a straight conductor.
The largest voltage the battery can have without breaking the circuit at the supports is 626.71 V.
The magnetic field on a current-carrying conductor is determined by the flow of current through the conductor and the distance from the carrier.
Voltage is the pressure exerted by an electrical circuit’s power source through a conducting loop to push charged electrons (“current”) through an electrical circuit to perform a function, such as turning on a light.
Given,
The length of the metal bar = 54.0 cm or 0.54 m
mass of the bar = 740 g or 0.74 kg
magnetic field acting perpendicular to the bar = 0.450 T
resistance = 26.0
Let the maximum potential in the battery be V and the current in the circuit be I. So
V= IR
V = 26×I
I = V/21
For the rod to be in its position the magnetic force on the rod must be equal to the weight. So
magnetic force = weight
B×I×L = mg
0.45 × V/21 × 0.54 m = 0.74 × 9.8
V = 626.71 V
Thus the largest voltage the battery can have without breaking the circuit at the supports is 626.71 V.
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At the instant that a cake is removed from the oven, the temperature of the cake is 350 degrees F. After 10 minutes, the cake's temperature is 200 degrees F. If the temperature of the room is 70 degrees F, how much longer will it take for the cake to cool to 90 degrees F?
It will take an additional 7.33 minutes for the cake to cool from 200 degrees F to 90 degrees F after the initial 10 minutes of cooling.
To calculate how much longer it will take for the cake to cool to 90 degrees F, we need to first determine the rate at which the cake is cooling. We can do this by calculating the temperature difference between the cake and the room and dividing it by the time it takes for that temperature difference to occur.
In this case, the temperature difference between the cake and the room is 280 degrees F (350-70=280) when the cake is removed from the oven. After 10 minutes, the temperature difference is 130 degrees F (200-70=130). Therefore, the cake is cooling at a rate of 15 degrees F per minute (280-130=150 degrees F in 10 minutes; 150/10=15).
To determine how much longer it will take for the cake to cool to 90 degrees F, we need to calculate the time it takes for the temperature to drop from 200 degrees F to 90 degrees F. This is a temperature difference of 110 degrees F (200-90=110), so it will take approximately 7.33 minutes (110/15=7.33) for the cake to cool from 200 degrees F to 90 degrees F.
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