Complete the following statement. The conditional probability of B given A can be found by​ _______. a. adding​ P(A) and​ P(B).b. assuming that event B has​ occurred, and then calculating the probability that event A will occur c. multiplying​ P(A) times​ P(B).d. assuming that event A has​ occurred, and then calculating the probability that event B will occur.

Answer:

AB = 7.28

AD = 7.28

BC = 16.28

DC = 16.28

Hope this helps!

Step-by-step explanation:

Answer:

1715= 1/3 x 3.14 x r x r x 63

= 65.94 x r^2

÷65.94

26.01 = r^2

Square root

Radius is 5.1

1080 = 1/3 x 3.14 x 5.1^2 x h

1080 = 27.22 x h

÷27.22

39.67 = h

(Haven't been actually rounding up in my calculation, when I divided.)

Check:

1/3 x 5.1^2 x 39.67 x 3.14 = 1079.968146.

So, height is about 39.67cm

Hope this helps!

The truck driver would deliver 105 packages in a 7 hours day

An equation is an expression that shows how numbers and variables are related to each other using mathematical operators.

Let y represent the number of packages delivered by the truck driver in x hours. Using the point (1, 15) and (4, 60). Hence, the equation is:

y - 15 = [(60-15)/(4-1)](x - 1)

y = 15x

For a 7 hour day (x = 7):

y = 15(7) = 105

The driver would deliver 105 packages in 7 hours

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The number of times of Puerto Rico is 5/6

No earthquake released 10³ of Colombia

From the question, we have the following parameters that can be used in our computation:

The table of values

On the table of values, we have

Colombia = 6.0M

Puerto Rico = 5.0M

This means that

Number of times = Puerto Rico/Colombia

Substitute the known values in the above equation, so, we have the following representation

Number of times = 5/6

Here, we have

Colombia = 6.0M

So, we have

Earthquake = Colombia * 10³

This gives

Earthquake = 6 * 10³

From the table of values, we have no entries with the readings 6 * 10³

Hence, no earthquake released 10³ of Colombia

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The value of y when a = 1 and b = 2 is 22.

The equation of can be solved as follows: We will substitute the value of a and b  in the equation to find the value of y.

Therefore,

y = 3ab + 2b³

Let's find y when a = 1 and b = 2

Hence,

y = 3(1)(2) + 2(2)³

y = 6 + 2(8)

y = 22

Therefore,

y = 22

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Answer:

Product B performed better in the study because 76% got relief with this product, whereas only 70% got relief from product A

Step-by-step explanation:

Product A

Total number of people tested = 50

Total number o who experienced relief using product A

                                                  = 35

% of people who got relief using product A

                                                   = 35/50 x 100%

                                                   = 70%

Product B

Total number of people tested = 25

Total number of people who experienced releif using product B

                                                  = 19

% of peope who got relief using product B

                                                  = 19/25 x 100%

                                                  = 76%

From the above:

76% of people got relieved whilst using product B

70% who got relieved using product A.

Therefore, product B performed better in the study because 76% got relief with this product, whereas only 70% got relief from product A

False

The median car price is the one right in the middle of the price list. To find the median, we first need to rank the prices from lowest to highest.

The ordered price list looks like this:

$3,999; $4,500; $4,999; $5,000; The median price is $4,999, which is the median price. The average price is not $4,799.60.

Median is a measure of the central tendency of a dataset. The value that separates the top and bottom halves of the record. To find the median, we need to enter the values ​​in the dataset in order from lowest to highest. If the dataset has an odd number of values, the median is the mean.

For example, given the following five values: For 3, 5, 7, 9, 11, the median is the median, so the median is 7. If the dataset has an even number of values, the median is the average of the two middle values. For example, given the following 6 values:

For 3, 5, 7, 9, 11, 13, the median is (7 + 9)/2 = 8. In this case, there are 5 values, which are odd, so the median is the median. , which is $4,999.

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Answer:

1218

(14x25)x3=1050

because you have three sides

14x12=168 then 168+168=336

then add al together 1050+336=1 386

From the given :

The domain is the set of x values the will give the function a define value.

If the value of x is 0, the value of y will be undefined.

Therefore the domain is all real numbers except 0.

Domain : All real numbers, x ≠ 0

The range is the set of y values at a given x values in the domain.

Since the denominator has an absolute sign, the denominator is always positive.

Therefore, the range is all real numbers greater than 0.

Range : All real numbers, x > 0

Answer: $24

Step-by-step explanation:

Since the popcorn combos are the same amount, we are essentially calculating the difference between 6 adult tickets and 6 student tickets.

6 adult tickets are $10*6 = $60, while 6 student tickets are $6*6 = $36.

60-36= $24

The expression is factorized to give (x + 7) and (x + 7)

Factorization described a mathematical methods that consists of writing a number or mathematical object as a product of several other factors that are mostly simpler or smaller objects of the same kind.

Given the quadratic equation;

x² + 14x +49

Find the pair factors of 49 that sum up to 14, the numbers are 7 and 7

Now, substitute the numbers in the expression

x² + 7x + 7x + 49

Make into two expressions, we have;

(x² + 7x) + (7x + 49)

factor out the common terms, we get;

x(x + 7)+ 7(x + 7)

Then, we have;

(x + 7)

(x + 7)

Hence, the factorized form is (x + 7) and (x + 7)

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Answer:

Hence the number of plans that cost between $42.72 and $ 85.72 is

95.44 %.

Step-by-step explanation:

Now the given are

μ = $64.22.

σ = $10.75.

Here,

\(P\left ( 42.72 < x< 85.72 \right )=P\left ( \frac{42..72-64.22}{10.75}< \frac{x-\mu }{\sigma } < \frac{85.72-64.22}{10.75}\right )\\P\left ( 42.72 < x< 85.72 \right )= P\left ( -2.00< Z <2.00 \right )\\P\left ( 42.72 < x< 85.72 \right )= P\left (Z<2.00\right )-P\left ( Z<-2.00 \right )\\P\left ( 42.72 < x< 85.72 \right )= P\left (0.9772\right )-P\left (0.0228\right )\\Probability = 0.9544\)

Probability = 95.44%.

Answer:

1. 22

2. 8

3. 31

4. 20

5. 38

6. 22

7. 26

8. 16

9. 14

10. 28

Step-by-step explanation:

USE PEMDAS

P: Parantheses

E: exponents

D: division

A: addition

S: subtraction

and ywww

Answer:

Step-by-step explanation:

I cant read it, the picture is blurry

Answer:

70

48

96

Step-by-step explanation:

Answer: 180 gallons needed

Step-by-step explanation:

Zykeith,

Assume x gallons of 50% antifreeze is needed

Final mixture is x + 60 gallons

Amount of antifreeze in mixture is 0.4*(x+60)

Amount of antifreeze added is .5x + .1*60 = .5x + 6

so .5x + 6 = .4(x + 60)

.5x -.4x = 24 -6

.1x = 18

x = 180

Let x be the number of gallons of the 50% antifreeze solution needed. We know that the resulting mixture will be 70 + x gallons. To get a 40% antifreeze mixture, we can set up the following equation:

\({\implies 0.5x + 0.1(70) = 0.4(70 + x)}\)

Simplifying the equation:

\(\qquad\implies 0.5x + 7 = 28 + 0.4x\)

\(\qquad\quad\implies 0.1x = 21\)

\(\qquad\qquad\implies \bold{x = 210}\)

\(\therefore\) We need 210 gallons of the 50% antifreeze solution to mix with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze.

\(\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\)

Answer:

The growth rate of the exponential function exceeds the growth rate of the linear function for 1 > x > 3

Step-by-step explanation:

edg2020 thank me latter

The growth rate of the exponential function exceeds the growth rate of the linear function for 1 ≤ x ≤ 3.

We have,

The graph of the linear function y = 7x is a straight line with a constant slope of 7, while the graph of the exponential function y = 7% is an increasing curve that starts at y = 1 and approaches y = infinity as x increases.

To compare the growth rates of the two functions, we can look at their derivatives.

The derivative of y = 7x is 7, which is a constant, while the derivative of

y = 7% is y' = 0.07y, which is proportional to y.

Now,

For x < 0, the growth rate of the linear function y = 7x exceeds the growth rate of the exponential function y = 7%.

This eliminates options 1 and 3.

For x > 0, the growth rate of the exponential function y = 7% exceeds the growth rate of the linear function y = 7x, since the derivative of the exponential function is proportional to the function itself.

This eliminates option 2.

Thus,

The growth rate of the exponential function exceeds the growth rate of the linear function for 1 ≤ x ≤ 3.

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The total amount Emily spent each month for 20 days will be $142.

Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both.

In this situation, Emily spends $4.85 on a latte and $2.25 on a scone. The total amount spent for 20 days will be:

= (4.85 + 2.25) × 20

= 7.1 × 20.

= 142

The amount is $142.

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Answer:

the ratio will be 132 to 89

The ratio is 132 : 89.

A comparison of two quantities by division is called a ratio and the equality of two ratios is called proportion. A ratio can be written in different forms like x : y or x/y and is commonly read as, x is to y.

Ratio is the comparison of two quantities which is obtained by dividing the first quantity by the other. If a and b are two quantities of the same kind and with the same units, such that b is not equal to 0, then the quotient a/b is called the ratio between a and b. Ratios are expressed using the symbol of the colon (:). This means that ratio a/b has no unit and it can be written as a : b

Given:

Boys= 132

girls= 89

adults= 14

So,

the ratio of number of boys to number of girls is

= 132/89

=132 : 89

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1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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The measure of angle ADM is 45.0°, as the intercepted arc AD is congruent to arc CD.

To find the measure of angle ADM, we need to consider that angle ADM is an inscribed angle and its measure is half the measure of the intercepted arc AD.

Given that the measure of arc CD equals the measure of arc DA, it means that these arcs are congruent.

Therefore, the intercepted arcs AD and CD have equal measures.

Since angle ADM is an inscribed angle intercepting arc AD, the measure of angle ADM is half the measure of arc AD.

Therefore, the measure of angle ADM is 45.0°, as the intercepted arc AD is congruent to arc CD.

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The mean body mass of the Adelie species is  3706.164 g.

Original chunk of code:

penguins %>%

drop_na() %>%

group_by(species) %>%

The code chunk summarize(mean(body_mass_g)) lets you find the mean value for the variable body_mass_g. The correct code is

penguins %>% drop_na() %>% summarize (mean(body_mass_g)).

The summarize () function displays summary statistics. We can use the summarize() function in combination with other functions - such as mean(), max(), min() - to calculate specific statistics. In this case, you use mean() to calculate the mean value for body mass.

Hence, The mean body mass for the Adelie species is 3706.164 g.

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Answer:

Mercury > Mars

Step-by-step explanation:

Mercury orbits closer to the sun than Mars, so it has a higher surface temperature.

Answer:

The highest you could reach with this ladder is 30 feet or 9.14 meters.

The equation of the line with slope 1/3 and y-intercept as -1 is y = x/3-1 in slope-intercept form.

According to the question,

We have the following information:

Slope of the line = 1/3

We know that the slope of the line is denoted by m.

y-intercept of the line = -1

We know that the y-intercept is denoted by b.

We have the following equation for the line in slope-intercept form:

y = mx+b

Putting the above values in this equation:

y = x/3-1

Hence, the equation of the line with slope 1/3 and y-intercept as -1 is y = x/3-1 in slope-intercept form.

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Answer:

Q1

Q2

BC is given 23 mi

Maybe AB is needed

Q3

Q4

Let the angle is x

Q5

See attached

Added point D and segments AD and DC to help with calculation

Find the length of added red segments

Now we can find the value of BC

All calculations are rounded