classes are sometimes cancelled due to typhoons. How does this impact the learning pupils?
2-3 sentences.
Answers
Answer:
(First Opinion)
Their learning progress going to be stuck until the typhoon stopped, but nowadays we can do online learning (can be at wherever you're), so this doesn't affect much, unless the pupils/teacher directly affected by the typhoon.
(Second Opinion)
Their Learning progress will be stopped for until the goverment allow it, this is according to rules of some country, this is in order to uphold citizen's rights to life, health and safety.
Explanation:
First Opinion is to continue online, so it doesn't affect much.
2nd is to fully stop and suspend in which it affect the pupils learning progress.
Related Questions
A train leaves a station traveling north at 45 km/h. 2 hours
later, an express train leaves the same station on a parallel track
traveling north at 75 km/h. How far from the station will the
trains me
Answers
Explanation:
First train has 2 hr * 45 km/hr = 90 km head start
Closing speed between the two trains 745 - 45 = 30 km
to cover the 90 km between them will take 3 hours
and the second train will be at 75 km/hr * 3 hr = 225 km from the station
The absorption and reflection of waves, such as sound and light, is called
Answers
The absorption and reflection of waves, such as sound and light is called as wave interaction or wave behavior.
The absorption and reflection of waves, such as sound and light, are fundamental properties that determine how waves interact with different materials and surfaces.
Absorption occurs when a wave transfers its energy to a medium or material, causing the wave to diminish in intensity. The absorbed energy is converted into other forms, such as heat. Different materials have varying abilities to absorb waves, depending on their physical properties and composition. For example, materials with porous structures or soft surfaces tend to absorb sound waves more effectively, leading to reduced sound reflection.
Reflection, on the other hand, refers to the bouncing back of waves when they encounter a surface or boundary. When a wave encounters a reflective surface, a portion of the wave's energy is reflected back into the medium from which it originated. The remaining energy may be absorbed or transmitted through the material, depending on its properties. Smooth and polished surfaces are often good reflectors of both sound and light waves.
The balance between absorption and reflection determines the behavior of waves in various environments. It influences factors such as the audibility of sound, visibility of objects, and the quality of acoustics in architectural spaces. Understanding and controlling absorption and reflection properties is crucial in fields such as architecture, materials science, audio engineering, and optics.
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a boy whose mass is 40kg runs up a flight of 30 step each 150 mm in 60 second find the averse power develop expansion explain the anomalous of two of water
Answers
The average power developed by the boy during the climb is approximately 29.4 W.
What is power?In physics, the amount of energy transferred or converted per unit time is called power.
total height = number of steps x height of each step
total height = 30 x 0.15 m = 4.5 m
Given, time = 60 s
As power = work done / time
work done = force x distance
force = mass x gravity
mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).
force = 40 kg x 9.81 m/s² = 392.4 N
The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m
work done = force x distance
work done = 392.4 N x 4.5 m = 1765.8 J
power = work done / time
power = 1765.8 J / 60 s
power ≈ 29.4 W
Therefore, the average power developed by the boy during the climb is approximately 29.4 W.
As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.
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A foam dart is fired a height of 1.69 m. How many seconds does it take to hit the ground
Answers
Answer:
.587 s
Explanation:
d = 1/2 a t^2
1.69 m = 1/2 ( 9.81 m/s^2) (t^2)
t = .587 s
The force of electrostatic repulsion between two small positively charged objects, A and B, is 3.6 x 10⁻⁵ N when AB = 0.12m. What is the force of repulsion if AB is increased to 0.24 m
Answers
Given data:
* The electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=3.6\times10^{-5}\text{ N}\)* The distance between the charged bodies in the initial state is,
\(d=0.12\text{ m}\)* The distance between the charged bodies in the final state is,
\(\begin{gathered} d^{\prime}=0.24\text{ m} \\ d=2\times0.12 \\ d^{\prime}=2d \end{gathered}\)Solution:
According to Coulomb's law, the electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=\frac{kq_1q_2}{d^2}\)where k is the electrostatic force constant, q_1 is the charge on the first charged body and q_2 is the charge on the second charged body,
The electrostatic force of repulsion between the charged bodies in the final state is,
\(\begin{gathered} F^{\prime}=\frac{kq_1q_2}{(2d)^2} \\ F^{\prime}=\frac{kq_1q_2}{4d^2} \\ F^{\prime}=\frac{1}{4}\times\frac{kq_1q_2}{d^2} \\ F^{\prime}=\frac{F}{4} \end{gathered}\)Substituting the known values,
\(\begin{gathered} F^{\prime}=\frac{3.6\times10^{-5}}{4} \\ F^{\prime}=0.9\times10^{-5}\text{ N} \end{gathered}\)Thus, the electrostatic force of repulsion between the charged bodies in the final state is,
\(\text{0}.9\times10^{-5}\text{ N}\)Does the youth service project, or a civic organisation, or community service centre shows signs of strength?yes/no
Answers
Answer:
Yes
Explanation:
This helps youngsters be empathetic citizens
A town's vitality may be measured by the sensation of a youth service initiative organized by a civic group or community service center. The given statement exists true.
Exactly what does it mean when someone says they belong to a civic group?The word "civic organization" directs to any group of people in a community whose primary mission exists to encourage civic, philanthropic, or religious causes.
Youth involvement in the development, monitoring, reporting, and evaluation of devices, tactics, and programs may increase their likelihood of experiencing.
In conclusion, the strength may be displayed in the youth service initiative of a civic organization or a community service center. It showed what young people can do when they enact together. Education and capacity development are two methods that have been shown to improve youth engagement.
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At double the distance from a long current-carrying wire, the strength of the magnetic field producedby that wire decreases to :11(A) of its original value(B) of its original value84(C) of its original value(D) None of the above2
Answers
At double the distance from a long current-carrying wire, the strength of the magnetic field produced by that wire decreases to 1/4 of its original value. option (a)
This can be explained by the inverse square law of distance, which states that the strength of a field is inversely proportional to the square of the distance from the source of the field.
Mathematically, this can be expressed as \(B ∝ 1/r^2\), where B is the magnetic field strength and r is the distance from the wire. Therefore, when the distance from the wire is doubled, r becomes 2r and the magnetic field strength becomes \((1/2r)^2\) = 1/4 of its original value.
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The Boston Tea Party was an act of civil disobedience by those who believed the Crown to be abusing its power to do what?
Answers
They were upset because the British were taxing them without any represeetatio in paliatment.
find the direction of the force for wire b, in degrees. measure this angle counterclockwise, in degrees, from the positive x-axis.
Answers
The direction of the force for wire B is determined as 60⁰.
What is the direction of the force for wire B?The direction of the force for wire B is calculated by applying Cosine rule as shown below.
b² = a² + c² - 2ac Cos B
2ac CosB = a² + c² - b²
cos B = [a² + c² - b² ] / 2ac
where;
B is the direction of wire B or angle of wire Ba is the side length opposite to wire Ac is the side length opposite to wire Cb is the side length opposite to wire BThe direction of the force for wire B is calculated as;
cos B = ( 10² + 10² - 10² ) / (2 x 10 x 10)
cos B = 0.5
B = arc cos (0.5)
B = 60⁰
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When the car comes to a sudden stop, the passenger ________ in motion
Answers
Answer:
If the car comes to a sudden stop, your body tends to keep moving forward.
Explanation:
a 1600-kg vehicle moves with a velocity of 19.5 m/s. calculate the power required to reduce the velocity to 3.20 m/s in 11.0 s.
Answers
The power required to reduce the velocity to 3.20 m/s in 11.0 s, given that the vehicle was initially moving at 19.5 m/s is 26909.82 W
How do i determine the power required?First, we shall obtain the initial and final kinetic energy of the vehicle. This is shown below:
Mass (m) = 1600 KgVelocity (v) = 19.5 m/sInitial kinetic energy (KE₁) =?KE₁ = ½mv²
KE₁ = ½ × 1600 × 19.5²
KE₁ = 304200 J
Mass (m) = 1600 KgVelocity (v) = 3.20 m/sFinal kinetic energy (KE₂) =?KE₂ = ½mv²
KE₂ = ½ × 1600 × 3.20²
KE₂ = 8192 J
Finally, we shall determine the power required. Details below:
Initial kinetic energy = 304200 JFinal kinetic energy = 8192 JWork done (Wd) = 304200 - 8192 = 296008 JTime (t) = 11 secondsPower required (P) = ?P = Wd / t
P = 296008 / 11
P = 26909.82 W
Thus, the power required is 26909.82 W
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what length pendulum period on the moon would match the period of a 2.0 m long period pendulum on the earth?
Answers
A pendulum with a 0.3 m length on the moon would have a period equivalent to a pendulum with a 2.0 m length on the earth.
Why is a pendulum used?Body suspended from the a fixed point to act as a pendulum that swings back and forth as a result of gravity. Because the period—the amount of time between each full oscillation—is constant, pendulums are employed to control the movement of clocks.
The pendulum has what kind of energy?The total of the kinetic and potential energies found in a perfect pendulum system, or mechanical energy, is always present. The ratio of the two types of energy fluctuates continuously as the pendulum swings back and forward between. The pendulum swings with more kinetic energy at various locations.
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i points A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T -2were is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct? When showing your work to turn in, make sure to show that you found the unit of k using dimensional analysis rather than by looking it up. Show (in the work you turn in) that this is equivalent to the units of N/m. This answer has not been graded yet. 2 2- 2 づ丁2- .C
Answers
Question 1
T=2*pi*sqrt(m/k)
dimension of T=sec
dimension of 2*pi=nil(dimensionless)
dimension of m=kg
equation dimension
sec=sqrt(kg/k)
sec^2=kg/k
k=kg/sec^2
so dimension of k will be
MT^(-2)
dimension of N/m=kgms^(-2)/m=kgs^(-2) so it is same
Question 2
F=Gm1*m2/r^2
Dimension of F=MLT^(-2)
MLT^(-2)=G*M*M/L^2
G=ML^3T^(-2)/M^2=M^(-1)L^(3)T^(-2)
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_True or False. A very massive object will free fall at the same rate of acceleration as a less massive object.
Answers
1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"
Answers
Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.
To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.
The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).
Using the equation:
v = v₀ + at
where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:
v = 0 + (0.75 m/s²) * t
v = 0.75t m/s
The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:
v = ωr
Substituting the values:
0.75t = ω * 300
Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:
ω = ω₀ + αt
ω = 0 + (0.75 m/s²) * t
ω = 0.75t rad/s
We can now substitute the value of ω into the equation:
0.75t = (0.75t) * 300
Simplifying the equation gives:
0.75t = 225t
t = 0.75 seconds
The time elapsed is 0.75 seconds.
To calculate the distance traveled (s), we can use the equation:
s = v₀t + (1/2)at²
Since the initial velocity (v₀) is zero, the equation becomes:
s = (1/2)at²
s = (1/2)(0.75 m/s²)(0.75 s)²
s = (1/2)(0.75 m/s²)(0.5625 s²)
s = 0.2119 meters or approximately 21.19 centimeters
Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.
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You want to record from a visual cortex neuron that is innervated by only one eye. Where is the best location to place your recording electrode
Answers
The best location to place your recording electrode for recording from a visual cortex neuron that is innervated by only one eye would be the contralateral visual cortex hemisphere.
How to place recording electrode for visual cortex neuron innervated by one eye?To record from a visual cortex neuron innervated by only one eye, the best location to place the recording electrode would be in the monocular region of the primary visual cortex (V1) that corresponds to the specific eye's visual field representation.
The visual cortex is organized in a retinotopic manner, meaning that neurons in V1 are arranged according to the visual space they represent.
By targeting the monocular region, which is specific to one eye, you can selectively capture the activity of neurons receiving input from that eye. This allows for focused recordings and analysis of the neural responses related to visual processing in that particular eye's input pathway. So, to record from a visual cortex neuron innervated by only one eye, the optimal location for placing the recording electrode would be the visual cortex hemisphere that corresponds to the contralateral eye.
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The intensity of the distributed lood acting on the beams 25 kN/m.) Determine the magnitude of reaction at Express your answer to three significant figures and include the appropriate units O ? N Value Units Submit Request Answer Figure Part 6 1 of 1 Delane te zand y components of reaction all sing scalar notation Express your answers using three significant figures separated by a comma HV AED vec ?
Answers
The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.
What is the magnitude of reaction to the distributed load?The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.
Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.
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what is the name of the volume of blood in the ventricles immediately before they contract?
Answers
The volume of blood in the ventricles immediately before they contract is called end-diastolic volume (EDV).This refers to the amount of blood that has filled the ventricles during diastole, which is the period of relaxation and filling between heartbeats.
The EDV end-diastolic volume is an important factor in determining the stroke volume, or the amount of blood ejected from the heart with each contraction. The EDV is influenced by a variety of factors, including the duration and strength of diastole, as well as the compliance of the ventricular walls. In general, a larger EDV results in a larger stroke volume, up to a certain point where the heart cannot eject any more blood effectively. This balance between EDV and stroke volume is important for maintaining adequate blood flow throughout the body. Overall, the EDV is a critical component of cardiac function, and understanding its relationship to stroke volume is key to understanding the physiology of the heart.
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The earth’s orbit around the sun is elliptical. What does this word mean?.
Answers
Answer:
An elliptical orbit is the revolving of one object around another in an oval-shaped path called an ellipse. The planets in the solar system orbit the sun in elliptical orbits. Many satellites orbit the Earth in elliptical orbits as does the moon.
The unit of pressure known as the pascal is equal to:________
Answers
The unit of pressure known as pascal is equal to 1 Newton / (metre)^2
It is the pressure exerted by a force of 1 newton , which is applied on an area of 1 metre square.
1 pascal pressure means that 1 newton force is equally distributed over an area of 1 metre square .
It is a small unit used for low pressures.
Pascal is denoted by the symbol Pa
It is derived from the formula pressure = force / area.
a rock is an example of a solid because
Answers
Answer:
The key is that solids hold their shape and they don't flow like a liquid. A rock will always look like a rock unless something happens to it.
Solids can hold their shape because their molecules are tightly packed together.
Explanation:
Yes; it is a solid
An full shopping cart with a mass of 100. kg is moving at 5.0 m/s and runs into a stationary shopping cart that is empty (30. kg). After the collision, the full shopping cart is moving at 2.7 m/s. What is the empty shopping cart moving at?
Answers
The empty shopping cart is moving at 7.67 m/s.
What is law of conservation of momentum?According to the law of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.
Total initial momentum = total final momentum
100 kg ×5.0 m/s + 30 kg ×0 m/s = 100 kg ×2.7 m/s + 30 kg ×v
v = (5.0 - 2.7)(100/30) m/s
= 7.67 m/s.
Hence, the empty shopping cart is moving at speed of 7.67 m/s.
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Un muelle se alarga 30 centímetros cuando ejercemos sobre el una fuerza de 24 N a) calcula el valor de la constante elástica del muelle b) calcula el alargamiento del muelle al aplicar una fuerza de 60 N
Answers
Answer:
(a) k = 80 N/m (b) x = 75 cm
Explanation:
The question says that, "A spring is elongated 30 centimeters when we exert a force of 24 N on it a) calculate the value of the spring constant b) calculate the elongation of the spring when applying a force of 60 N"
Given that,
Force exerted on the spring, F = 24 N
Elongation in the spring, k = 30 cm =0.3 m
(a) We know that, the force on the spring is given by :
F = kx
Where
k is spring constant
So,
\(k=\dfrac{F}{x}\\\\k=\dfrac{24}{0.3}\\\\k=80\ N/m\)
(b) When F = 60 N,
\(x=\dfrac{F}{k}\\\\x=\dfrac{60}{80}\\\\x=0.75\ m\\\\x=75\ cm\)
Hence, this is the required solution.
Need help ASAP please and thank you
Answers
Answer:
253
Explanation:
He stands at 50 so you keep counting by 50 until you get it to add three.
A 3.0-kg ball with an initial velocity of (4i +3j) m/s collides with a wall and rebounds with avelocity of (-4i + 3j) m/s.What is the impulse exerted on the ball by the wall?
Question 2 answers
a. +24i N s
b. -24i N s
c. +18j N s
d. -18j N s
e. +8.0i N s
Answers
The impulse exerted on the ball by the wall is -24i N s, the answer is option b.
The impulse exerted on the ball by the wall can be determined using the impulse-momentum theorem.
Impulse is equal to the change in momentum.
That is,
J = Δp
Since momentum is a vector,
p = mv
Substituting the values,
p(initial) = mv(initial) = 3.0 kg × (4i + 3j) m/s
p(initial) = 12i + 9j N s
p(final) = mv(final) = 3.0 kg × (-4i + 3j) m/s
p(final) = -12i + 9j N s
Change in momentum,
(Δp) = p(final) - p(initial)
= (-12i + 9j) N s - (12i + 9j) N s
= (-12 - 12)i + (9 - 9)j N s
= -24i N s
Thus, the impulse exerted on the ball by the wall is -24i N s, which means that the answer is option b.
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The moving part of a speaker goes in and out 400 times per second. The frequency of the sound produced is:
a
4 hertz.
Ob
40 hertz.
400 hertz.
4,000 hertz.
Answers
A battery with e.m.f 12v and the internal resistance 0.5ohms is connected to an electric bulb of resistance 2 ohms. Calculate the current
Answers
Answer:
4.8 A
Explanation:
Voltage = current x resistance
(V = IR)
12 = I (0.5 +2)
I = 4.8 A
A fisherman rows a boat North directly across a river at 2m/s. The current of the river flows to East at 1.3m/s.
Represent the vectors for given situation graphically.
Answers
Here is a graphical representation of the vector pointing upwards represents the fisherman's velocity attached.
What are vectors?Vectors are mathematical objects used to represent quantities that have both magnitude and direction. They can be visualized as arrows, where the length of the arrow represents the magnitude of the vector and the direction of the arrow represents the direction of the vector.
Examples of quantities that can be represented as vectors include force, velocity, acceleration, and displacement. The vector pointing upwards represents the fisherman's velocity of 2 m/s towards the North, while the vector pointing towards the right represents the river's current of 1.3 m/s towards the East.
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a 75 watt lightbulb runs for 11 seconds. how much energy does it use?
Answers
Answer:
825 Joules of energy would be correct if my math is right.
Explain COGS and give an example. 3pt. 2. Explain OH and give an example. 3pt. 3. Explain PP\&E and give an example. 5pt. 4. Illustrate the J-curve. 8pt. 5. What are the 3 F's? 2pt. 6. What does CULT stand for? Explain and give examples. 5pt. 7. What is a Beta? Explain. 5pt. 8. Illustrate the Break-Even graph. 8pt.
Answers
COGS stands for Cost of Goods Sold. It represents the direct costs incurred in producing or acquiring the goods or services that a company sells to generate revenue. It includes the cost of raw materials, direct labor, and manufacturing overhead directly associated with the production process. For example, in a bakery, the cost of flour, sugar, and other ingredients, as well as the wages of the bakers involved in producing the bread, would be part of the COGS.
OH stands for Overhead. It refers to indirect costs incurred in the production process that cannot be directly attributed to a specific product or service. Examples of overhead costs include rent, utilities, salaries of administrative staff, and depreciation of equipment.
PP&E stands for Property, Plant, and Equipment. It represents the long-term tangible assets that a company uses in its operations. Examples include buildings, machinery, vehicles, and land. These assets are not easily converted into cash and are expected to be used over multiple accounting periods.
The J-curve is a graphical representation that shows the initial negative impact of an investment or policy change followed by a positive effect over time. It forms a shape resembling the letter "J" on a graph. The curve indicates that in the early stages, there may be a decline or negative impact, but as time progresses, the situation improves and leads to positive results. It is often used to illustrate the short-term costs or losses associated with investments before they generate positive returns in the long run.
The 3 F's refer to the three fundamental financial statements: the Income Statement, the Balance Sheet, and the Cash Flow Statement. These statements provide essential information about a company's financial performance, position, and cash flows. The Income Statement shows revenue, expenses, and net income or loss over a specific period. The Balance Sheet presents the company's assets, liabilities, and equity at a given point in time. The Cash Flow Statement provides information on the cash inflows and outflows, including operating activities, investing activities, and financing activities.
CULT stands for Customers, Understanding, Learning, and Teaching. It is a customer-centric approach to business that focuses on building strong relationships with customers by understanding their needs, continuously learning from them, and effectively communicating and teaching them about products or services. This approach aims to create loyal customers who not only make repeat purchases but also become advocates for the brand. Examples of CULT practices include conducting customer surveys, personalizing marketing messages, offering educational resources, and providing exceptional customer service.
In finance, Beta represents the measure of a stock's or investment's volatility in relation to the overall market. It measures the sensitivity of an asset's returns to changes in the market. A Beta of 1 indicates that the asset's price moves in line with the market. A Beta greater than 1 suggests higher volatility compared to the market, while a Beta less than 1 indicates lower volatility. For example, a Beta of 1.5 implies that the asset is expected to be 50% more volatile than the market.
The Break-Even graph is a graphical representation that shows the point at which total revenue equals total costs, resulting in zero profit or loss. It helps determine the level of sales or production volume needed to cover all fixed and variable costs. The graph plots the total revenue and total cost curves on the same axis. The break-even point is the intersection of these two curves. Below the break-even point, the company incurs a loss, while above the break-even point, it generates a profit. The graph visually illustrates the relationship between costs, revenue, and profit at different levels of output or sales.
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