choose the paramagnetic species from below. o he ti4 all of the above are paramagnetic. none of the above is paramagnetic.

A drag car starts down a drag strip. If it can accelerate constantly at 17 m/s squared, then its speed after 5 seconds would be 85 meters/second.

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

v = u + at

  = 0 + 17×5

  = 85 m/s

S = ut + 1/2at²

200 = 0 + 0.5×5×t²

2.5t² = 200

t² = 200 / 2.5

t = 8.944 seconds

Thus, the speed of the car after 5 seconds would be 85 m/s and it would take 8.944 seconds to clear a 200-meter drag strip.

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(a) 1543.42 m far has the bicyclist traveled during the entire trip. (b) 1160.13 m/h is the average speed of the bicyclist for the trip.

a. To find the distance traveled by the bicyclist during the entire trip, we need to find the distance traveled in each part and add them up.

The distance traveled during the first part can be calculated using the formula:-

\(distance = speed * time\)

= distance
= \(8.16 m/s * 27.5 minutes * (1 minute / 60 seconds)\)

= 559.52 m

The distance traveled during the second part can be calculated using the formula:-

\(distance = speed * time\)

= distance

= \(4.66 m/s * 38.7 minutes * (1 minute / 60 seconds)\)

= 366.06 m

The distance traveled during the third part can be calculated using the formula:-

\(distance = speed * time\)

= distance

= \(14.3 m/s * 13.6 minutes * (1 minute / 60 seconds)\)

= 617.84 m

Adding up all the distances traveled in each part gives us the total distance traveled by the bicyclist during the entire trip:

=> total distance

= \(559.52 m + 366.06 m + 617.84 m\)

= 1543.42 m

(b) To find the average speed of the bicyclist for the trip, we need to find the total time taken for the trip and the total distance traveled.

The total time taken for the trip can be found by adding up the time taken in each part:-

=> total time

= \(27.5 minutes + 38.7 minutes + 13.6 minutes\)

= 79.8 minutes

=> total time

= \(79.8 minutes * (1 minute / 60 seconds)\)

= 1.33 hours

The average speed of the bicyclist for the trip can be calculated using the formula:-

\(average speed = total distance / total time\)

= average speed

= \(1543.42 m / 1.33 hours\)

= 1160.13 m/h

The average speed of the bicyclist for the trip is 1160.13 m/h.

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Calculate the total drag force on a flat plate in air flow using given dimensions, velocity, and fluid properties.

The problem involves calculating the total drag force on a flat plate under certain flow conditions. Initially, air is flowing over both sides of a single flat plate with dimensions 0.8 m long and 0.3 m wide. The flow velocity is 5 m/s, the pressure is atmospheric, and the air temperature is 20°C. The density of air is given as 1.21 kg/m³, and the viscosity is 1.81 x 10⁻⁵ N-s/m².

To determine the total drag force on the plate, the drag coefficient and the effective area of the plate need to be calculated. The drag coefficient depends on the flow conditions and the shape of the plate. In this case, for a flat plate, the drag coefficient can be approximated using the Prandtl's formula for laminar flow, which is Cd = 1.328/sqrt(Re), where Cd is the drag coefficient and Re is the Reynolds number.

The Reynolds number (Re) is calculated as the ratio of the inertial forces to the viscous forces and is given by Re = (ρ * V * L) / μ, where ρ is the density of air, V is the flow velocity, L is the characteristic length (plate length in this case), and μ is the viscosity of air.

Using the given values, the Reynolds number can be calculated, and then the drag coefficient can be determined. The effective area of the plate is simply the product of its length and width.

The drag force is then obtained by multiplying the drag coefficient, the effective area, and the dynamic pressure, which is given by q = (1/2) * ρ * V², where q is the dynamic pressure.

Once the drag force on the single plate is determined, the same process can be applied to the case of two plates. The total drag force would be the sum of the drag forces on each plate.

Performing the necessary calculations using the given values, the total drag force on the single plate and the total drag force on the two plates can be obtained.

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I'm not sure what you were trying to put here

Answer: Ball #1

Explanation:

Since the platform is more inclined, it will allow the ball to roll down faster.

Answer:

methylated spirit is in fact methanol added to ethanol (usually 10% methanol is used). The liquid evaporates which means that the liquid converts to a gaseous state. This process requires energy which it extracts from your body in the form of heat.

Explanation:

Answer:

sulphite is what equation

Explanation:

gas

liquid

solid

aqueous

The pitch of the sound increases as the frequency of the sound increases while the loudness remains the same.

The main observations that can be made between a frequency of 500 Hz and one that is above 700 Hz, keeping the amplitude fixed are as follows:As the frequency increases, the pitch becomes higher.

The pitch, loudness, and quality of the sound will change,The higher the frequency, the higher the pitch of the sound. For example, high pitched sounds such as sirens, birds chirping, and whistling sounds have a frequency that is above 700 Hz.On the other hand, sounds that have a frequency of less than 500 Hz are typically lower pitched sounds such as bass instruments, bass guitars, and the sound of a bass drum.

                                          These sounds are perceived to be lower in pitch as compared to sounds with a frequency above 700 Hz.Moreover, there will be no noticeable change in the amplitude of the sound wave since it is held constant. The amplitude of the sound wave is related to the loudness of the sound, and not the pitch of the sound.

Therefore, the pitch of the sound increases as the frequency of the sound increases while the loudness remains the same..

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The correct answer for the given question for the distance that the piston on the right will move is 0.1 m option (A).

When an explosion occurs in the left piston, it exerts a force on the fluid, which in turn exerts an equal and opposite force on the right piston due to the enclosed volume.

The cross-sectional area of the left piston is 0.25 m², and assuming the force is uniformly distributed over the entire area, the force exerted by the left piston is given by F = P × A, where P is the pressure and A is the area.

Using the work-energy principle, the work done by the left piston is equal to the work done on the right piston. Therefore, the work done on the right piston is equal to the force exerted on it multiplied by the distance it moves.

The force exerted on the right piston can be calculated using the same formula as before (F = P × A), where the cross-sectional area A is 0.5 m².

Since the force exerted on the right piston is equal to the force exerted by the left piston, we can equate the two expressions for force and solve for the distance moved by the right piston.

Using the equation F_left = F_right, we have P_left × A_left = P_right × A_right.

Plugging in the given values, we get (P_left × 0.25) = (P_right × 0.5).

Since the pressure is the same throughout the fluid, P_left = P_right.

Simplifying the equation, we have 0.25 = (0.5 × A_right).

Solving for A_right, we get A_right = 0.25 / 0.5 = 0.5 m².

The distance moved by the right piston can be calculated using the work formula:

Work_right = Force_right × Distance_right.

Plugging in the values, we have (P_right × A_right) × Distance_right = (P_left × A_left) × Distance_left.

Since P_left = P_right, we can further simplify the equation:

A_right × Distance_right = A_left × Distance_left.

Plugging in the given values, we get (0.5 × Distance_right) = (0.25 × 0.2).

Solving for Distance_right, we have Distance_right = (0.25 × 0.2) / 0.5 = 0.1 m.

Hence, the correct answer is option A: 0.1 m.

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Answer:

I believe the answer would be kinetic energy to thermal energy.

Explanation:

Thermal energy is the heat of the brakes, and the kinetic energy would be when the car is in motion before stopping.

The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,

F = kx

Therefore,

k = F/x

We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,

K = 50.174/0.25 N/m

K = 200.696 N/m

Therefore, The Spring Constant is 200.696 N/m

On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:

h = \(1/2 kx^{2}\)

We know that k=200.696 N/m and x=0.25 m. Therefore the height is:

h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)

h = 2.5087 m

Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

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The process that is necessarily driven by an increase in the entropy of the surroundings is the vaporization of water. Option b.

Entropy is a physical quantity that measures the amount of energy in a physical system that is unavailable for work. The entropy of a physical system is a measure of the number of microscopic configurations that the system could possess when it is in the thermodynamic state characterized by the macroscopic variables that describe the system's properties.

When a physical system undergoes a process, the entropy of the system changes. Therefore, among the given options, the process that is necessarily driven by an increase in the entropy of the surroundings is "the vaporization of water."

During the vaporization of water, the water molecules change from a liquid to a gas state. This process requires energy and results in a change in entropy because the water molecules are now in a more disordered state than before.

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Time taken is 1.65s, height is 17.5m and velocity is 4.3 m/s.

1)

To determine the time it takes for the ball to reach the plane of the fence, we need to find the horizontal component of the initial velocity.

2)

To find how far above the top of the fence the ball will pass, we need to find the maximum height it reaches.

3) The vertical component of velocity when the ball reaches the plane of the fence can be found using the kinematic equation for vertical velocity, v = v₀y + at.

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because mechanical advantage decreases due to the friction and weight of moving parts of the machine whereas the velocity ratio remains constant

hope it helps you

The similarities in the atmospheric compositions of Mars and Venus can be explained by their proximity to the Sun, which is the main source of energy for both planets.

Energy is the capacity to do work. It is a fundamental physical property of objects and is the ability to cause change. Energy exists in many forms, such as kinetic, potential, thermal, electrical, chemical, nuclear and gravitational. All these forms of energy can be transformed from one form to another.

The Sun's radiation is strong enough to drive the same type of chemical reactions on both planets that produce the same type of atmospheres. This is despite the fact that Mars is much farther from the Sun than Venus, and Venus is much larger than Mars. The fact that their atmospheres have the same composition can be attributed to their shared proximity to the Sun and the intense ultraviolet radiation it produces.

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The direction of forces during a collision can be inferred grounded on the haste change of each object. The forces acting on the objects are equal in magnitude and contrary in direction in elastic collision. But on the other hand, the forces acting on the objects aren't equal in magnitude in inelastic collision and the direction of the forces is also towards the centre of mass.

Collision means two objects coming into touch with each other for a veritably short period. It's a repaying commerce between two millions for a veritably short interval wherein the instigation and energy of the colliding millions change.

A impeccably elastic collision is defined as a collision in which there's no loss of kinetic energy. An inelastic collision is one in which kinetic energy is changed to some other form of energy in the collision.

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Answer:

$1.5

Explanation:

By using the concept of work and energy, the below are the answers

1. 100J

2. 100J

3. 0

4. Total energy = K.E + P.E

5. 1.02 kg

6. 14 m/s

Given that 100 J of work was done to lift a 10-N rock and set it at Position A near the edge of a cliff.

1. If the 100 Joules of work lifted the rock to the top of the cliff, how much potential energy did the rock gain?

Work is the product of force and the distance.

The potential energy gained by the rock will be equal to work done in lifting  up the rock which is 100 J

2. At point C, the rock's potential energy will be equal to the work done.

That is, at point C, P.E = 100J

3. The rock's kinetic energy at point A is Zero.

That is, at point A, K.E = 0

4. At point B, some of the rock's potential energy will be changed to Kinetic energy. Yes. Because the Total energy = K.E + P.E

5. What is the mass of the rock?

Weight W = mg

where g = 9.8m/s^2

W = 10N

Substitute both into the formula

10 = 9.8m

make m the subject of the formula

m = 10/9.8

m = 1.02 kg

6. What is the rock's velocity just before it hits the ground

Work done = Energy

That is, Work done = maximum P.E = maximum K.E

100 = 1/2m\(v^{2}\)

Substitute mass into the formula

200 = 1.02\(V^{2}\)

V = \(\sqrt{196}\)

V = 14 m/s

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The equation that relates the speed of light c to other fundamental electromagnetic constants is known as Maxwell's equations. Maxwell's equations are a set of four equations that describe the behavior of electric and magnetic fields. These equations were first published by James Clerk Maxwell in 1865 and are considered one of the most important achievements in the field of physics.

One of Maxwell's equations, known as the wave equation, relates the speed of light to the electric and magnetic fields. This equation states that the speed of light is equal to the square root of the product of the permeability of free space (μ0) and the permittivity of free space (ε0). This remarkable equation explains why the speed of light is a constant and provides a foundation for the study of electromagnetism.

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Answer:

a bus would have 12 meters

Answer:

A School Bus

Explanation:

Answer:

According to Newton's third law of motion, the reaction force is equal to the action force.

Explanation:

Newton's third law of motion states that for every action there is an equal and opposite reaction. This means that if one object exerts a force on a second object, the second object exerts an equal force in the opposite direction. When Plate X pushes on Plate Y with the action force (Fx), Plate Y must push back with an equal force (Fy).

Therefore, the best explanation is that according to Newton's third law of motion, the reaction force is equal to the action force.

For every action, there has equal and opposite reaction - this statement best describes the action and reaction forces on the plates.

As a result of this interaction, there are two forces: one from plate X and one from plate Y. The third law of motion of Newton deals with these two forces, which are referred to as action and reaction forces. Newton's third law is officially expressed as follows: There is an equal and opposite reaction to every action.

The implication of the statement is that there are always two forces acting on the two interacting objects. The force acting on the first object is equal in size to the force acting on the second. The force acting on the first object is acting in the opposite direction to the force acting on the second object. Force pairs—equal and opposing action-reaction force pairs—always exist in pairs.

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An EMT asks you how he can decrease the chances of being involved in a collision when driving with lights and sirens in progress. Your advice would be as if the lights of the oncoming car are blinding you, glance to the right side of the road rather than at it.

Drivers up to 3,000 feet away can be rendered blind by headlights approaching from behind. If you feel you won't be able to see after a car passes you, slow down and try not to look directly into its headlights.

If approaching headlights are blinding you while you are driving at night, look to the right side of the road. You'll be able to see other automobiles thanks to your peripheral vision. On your car, apply some reflective tape.

Items are visible at night because of their rich color and striking contrast. Reflective tape is a fantastic option to wear as a result of this especially in dark colours.

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The initial potential energy of the diver is \(20,507.4 J\),  The final kinetic energy of the diver is \(1/2 (79 kg) \times (18.77 m/s)^2 = 14,030.3 J, C\). The velocity of the diver just before hitting the water is approximately \(18.77 m/s.\)

To resolve this issue, we can make use of energy conservation concepts. The diver only has potential energy at the beginning of the jump, which is transformed into kinetic energy as the diver falls toward the water.

A. The initial potential energy of the diver can be calculated as:

potential energy \(= mgh\)

Where m is the mass of the diver (79 kg), g is the acceleration due to gravity \((9.8 m/s^2)\) And h is the height of the diving board (27 m).

Therefore, potential energy \(= (79 kg) \times (9.8 m/s^2) \times (27 m) = 20,507.4 J\)

The initial potential energy of the diver is \(20,507.4 J.\)

B. All the initial potential energy has been transformed into kinetic energy right before the diver reaches the water. As a result, the diver's total kinetic energy can be determined as follows:

final kinetic energy \(= 1/2 mv^2\)

Where v is the diver's speed shortly before entering the water, and m is the diver's mass (79 kg).

We can compare the initial potential energy to the final kinetic energy by applying the law of conservation of energy:

\(mgh = 1/2 mv^2\)

Solving for v, we get:

v = \(\sqrt{2gh}\)

Where sqrt means square root.

Plugging in the values, we get:

\(v = sqrt(2 x 9.8 m/s^2 x 27 m) = 18.77 m/s\)

The final kinetic energy of the diver is \(v = sqrt(2 x 9.8 m/s^2 x 27 m) = 18.77 m/s\)

C. The velocity of the diver just before hitting the water is approximately

\(18.77 m/s.\)

Therefore, The velocity of the diver just before hitting the water is approximately \(18.77 m/s.\)

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Answer:

(a) h = 5.1 m

(b) v = 14.13 m/s

Explanation:

(a)

We will use the law of conservation of energy. For this situation it states that:

Loss in Potential Energy of Sphere = Gain in Kinetic Energy of the Sphere

mgh = (1/2)mv²

h = v²/2g   --------------- equation (1)

where,

h = height = ?

v = speed at lowest point = 10 m/s

g = 9.8 m/s²

Therefore,

h = (10 m/s)²/(2)(9.8 m/s²)

h = 5.1 m

(b)

using the equation (1)

h = v²/2g

v = √2gh

where,

v = velocity = ?

g = 9.8 m/s²

h = height = 2(5.1 m) = 10.2 m

Therefore,

v = √[2(9.8 m/s²)(10.2 m)]

v = 14.13 m/s

The height from which the sphere was released is 5.1 m

When the height is doubled, the speed of the sphere becomes 14.14 m/s.

The given parameters:

The height from which the sphere was released is calculated as follows;

\(P.E = K.E\\\\mgh = \frac{1}{2}mv^2\\\\gh = \frac{1}{2}v^2\\\\h = \frac{v^2}{2g}\\\\h = \frac{(10)^2}{2(9.8)} \\\\h = 5.1 \ m\)

When the height is doubled, the speed of the sphere becomes;

\(h = \frac{v^2}{2g} \\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 9.8 \times (2 \times 5.1)} \\\\v = 14.14 \ m/s\)

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Answer:

Initial velocity is independent of the slope of the graph; that is, the acceleration. An object thrown downward still accelerates after release at the same rate as an object that is dropped.

The following data can be converted to the engineering notation as the following. (a) 0.045 W is 45 mW. (b) 2000 pJ is 2nJ. (c) 0.1 ns is 100 pS (d) 39,212 as is 39.212 fs (e) 3 \Omega3Ω is 3Ω (f) 18,000 m is 18 km (g) 2,500,000,000,000 bits is 2.5 terabits (h)  0^{15} \text { atoms } / \mathrm{cm}^{3}10 15atoms /cm 3 is \(10^{21} \frac{atoms}{m^{3} }\).

Engineering notation is the representation of expressing the numbers that are too big or too small and are represented in the decimal form times 10 raise to the power.  It is similar to the scientific notation but in engineering notation, the powers of ten are always multiples of 3.

Using scientific notation, one can express extremely big or extremely small values. When a number between 1 and 100 is used, it is written in scientific notation.

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Answer:

distance and length are the same quantity

The impulse of a bullet is the product of the force and the time for which it is applied to the object. The impulse of a bullet can be calculated using the equation.The impulse of the bullet is 0.8 Ns.

 Impulse = Force x Time.The given question states that a 0.001 kg bullet is fired with a velocity of 800 m/s into a soft wood of mass 1 kg, resting on a smooth surface. To calculate the impulse of the bullet, we need to determine the force applied to the wood by the bullet during the time of impact.First, let us find the initial momentum of the bullet, which is:Initial momentum = mass x velocity = 0.001 kg x 800 m/s = 0.8 kg m/sWhen the bullet hits the wood, it comes to rest. Therefore, the final velocity of the bullet is 0 m/s. To find the force exerted on the wood, we can use the law of conservation of momentum.

The total momentum of the system before the collision is equal to the total momentum of the system after the collision, which is:Initial momentum of bullet = Final momentum of bullet + Momentum of wood0.8 kg m/s = 0 + (mass of wood) x (final velocity of wood)We know that the mass of wood is 1 kg and the final velocity of wood is unknown. Solving for final velocity of wood gives:Final velocity of wood = 0.8 m/sSo, the change in velocity of the wood is:Δv = final velocity - initial velocity = 0.8 m/s - 0 m/s = 0.8 m/sThe time of impact can be calculated using the equation:Time = Δv / aWhere, a is the acceleration of the wood, which can be found using the equation:F = maF = mΔv / tTherefore,a = F / m = (mΔv / t) / m = Δv / tSubstituting the given values, we get:a = 0.8 m/s / 0.001 s = 800 m/s²The time of impact is:Time = Δv / a = 0.8 m/s / 800 m/s² = 0.001 sTherefore, the force exerted on the wood by the bullet is:F = ma = 1 kg x 800 m/s² = 800 NThe impulse of the bullet can be calculated using the equation:Impulse = Force x Time= 800 N x 0.001 s= 0.8 NsAnswer: The impulse of the bullet is 0.8 Ns.

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