Can someone solve this math problem for me

We know how many pounds are needed to cover 5000 ft^2, and we need to find how many are needed to cover 27000ft^2. To find this value, divide 27000 by 5000 and multiply the result by the weight.

27000/5000 x 18.75
5.4 x 18.75
101.25

So, we need 101 1/4 pounds of fertilizer. How many bags is that?

101.25/18.75
5.4

We'll say that since the 0.4 of a bag will still need to be used, that you need 6 bags to cover 27000ft^2.

A line segment has two endpoints and you can measure them, as shown in the picture with endpoints A and B.

Whereas, A ray is a part of a line that has one endpoint and goes on infinitely in only one direction. You cannot measure the length of a ray. (second picture with the arrow)

Answer:

The slope of a linear model can be calculated using the formula:

m = Δy / Δx

where:

Δy = change in y (the dependent variable, in this case, total cost)

Δx = change in x (the independent variable, in this case, number of candy bars)

This is essentially the "rise over run" concept from geometry, applied to data points on a graph.

In this case, we can take two points from the table (for instance, the first and last) and calculate the slope.

Let's take the first point (3 candy bars, $6.65) and the last point (25 candy bars, $48.45).

Δy = $48.45 - $6.65 = $41.8

Δx = 25 - 3 = 22

So the slope m would be:

m = Δy / Δx = $41.8 / 22 = $1.9 per candy bar

This suggests that the cost of each candy bar is $1.9 according to this linear model.

Please note that this assumes the relationship between the number of candy bars and the total cost is perfectly linear, which might not be the case in reality.

9514 1404 393

Answer:

  16 square units

Step-by-step explanation:

The area of the square base is ...

  A = s²

  A = 2² = 4

The area of each triangle is ...

  A = (1/2)bh

  A = (1/2)(2)(3) = 3

So, the area of the base and 4 triangles is ...

  total area = 4 + 4(3) = 16 . . . square units

Answer:

its 16

Step-by-step explanation:

Using the P-value method of testing hypotheses with a significance level of 0.05, the sample provides strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

To test the claim that the mean score of job applicants from the university is greater than 160, we will perform a one-sample t-test using the P-value method. The null hypothesis (H0) assumes that the mean score is equal to 160, while the alternative hypothesis (Ha) assumes that the mean score is greater than 160.

First, we calculate the test statistic, which is the t-value. The formula for the t-value is:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

Plugging in the given values, we have:

t = (183 - 160) / (12 /   √(25))

  = 23 / (12 / 5)

  = 23 * (5 / 12)

  ≈ 9.58

Next, we find the P-value associated with the test statistic. The P-value represents the probability of obtaining a test statistic as extreme as the observed value, assuming the null hypothesis is true. Since the alternative hypothesis is one-sided (greater than 160), we calculate the P-value by finding the probability of the t-distribution with 24 degrees of freedom being greater than the calculated t-value.

Consulting statistical tables or using software, we find that the P-value is very small (less than 0.0001).

Since the P-value (less than 0.0001) is less than the significance level (0.05), we reject the null hypothesis. This provides strong evidence to support the claim that the mean score of job applicants from the university is greater than 160.

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All the values are,

a)  lim x → 3 [ 2 f (x) - g (x)] = 18

b)  lim x → 3 [ 2 g (x) ]² = 16

c)  lim x → 3 [ ∛ f (x) / g (x) ] +  lim x → 3 [ 4 h (x) / x + 7 ] = - 1

We have to given that;

Limits are,

lim x → 3 f (x) = 8

lim x → 3 g (x) = - 2

lim x → 3 h (x) = 0

Now, We can simplify all the limits as;

1) lim x → 3 [ 2 f (x) - g (x)]

⇒  lim x → 3 [ 2 f (x)] -  lim x → 3 [ g (x) ]

⇒ 2  lim x → 3 [  f (x) ] - (- 2)

⇒ 2 × 8 + 2

⇒ 16 + 2

⇒ 18

2)  lim x → 3 [ 2 g (x) ]²

⇒ 4 [ lim x → 3  g (x) ]²

⇒ 4 × (- 2)²

⇒ 4 × 4

⇒ 16

3)  lim x → 3 [ ∛ f (x) / g (x) ] +  lim x → 3 [ 4 h (x) / x + 7 ]

⇒ ∛8 / (- 2) + 4 × 0 / (3 + 7)

⇒ - 2/2 + 0

⇒ - 1

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The length of the shortest ladder that will reach from the ground over the fence to the wall of the building is approximately 8.94 feet.

To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the two shorter sides (legs) is equal to the square of the longest side (hypotenuse). In this case, the fence, building, and ladder form a right triangle, where the fence and building are the legs, and the ladder is the hypotenuse.

We know that the fence is 8 feet tall and the building is 4 feet away from the fence, so the height of the right triangle (the distance from the ground to the top of the building) is also 8 feet.

To find the length of the ladder, we need to use the Pythagorean theorem:

ladder^2 = fence^2 + height^2
ladder^2 = 8^2 + 4^2
ladder^2 = 64 + 16
ladder^2 = 80
ladder ≈ 8.94 feet

Therefore, the length of the shortest ladder that will reach from the ground over the fence to the wall of the building is approximately 8.94 feet.

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When the line to be examined's slope is known, and the provided point also serves as the y intercept, the slope intercept formula, y = mx + b, is utilized (0, b).

When should you use point-slope form?

When the slope of the line being studied is known, and the provided point is also the y intercept, the slope intercept formula, y = mx + b, is utilized (0, b). The y value of the y intercept point is represented by b in the equation.

One of the three ways we can express a straight line is using the point slope form, also known as the point-gradient form. By merely knowing one point on the line and the slope of the line, we may use this form to get the equation of the line.

The slope and y-intercept of the matching line can be rapidly determined when we have a linear equation in slope-intercept form. This enables us to graph it as well.

The equation of a line can be represented in either slope-intercept form or point-slope form.

Slope-intercept form:

The slope-intercept form of a line is given by y = mx + b, where m is the slope of the line and b is the y-intercept.

To find the equation of the line passing through the points (3,5) and (6,11) in slope-intercept form, we can use the point-slope formula to find the slope and then use one of the points to find the y-intercept.

Point-slope form:

The point-slope form of a line is given by y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is a point on the line.

To find the equation of the line passing through the points (3,5) and (6,11) in point-slope form, we can use the point-slope formula and one of the points.

Using the point-slope formula, the slope of the line is (11 - 5) / (6 - 3) = 6/3 = 2.

So, the equation of the line in slope-intercept form is:

y = 2x + b

We can use the point (3,5) to find the y-intercept:

5 = 2 * 3 + b

Solving for b, we get b = -1.

So the equation of the line in slope-intercept form is:

y = 2x - 1

In point-slope form, using the point (3,5), the equation of the line is:

y - 5 = 2(x - 3)

Both forms represent the same line, just in different ways.

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The properties of the linear equation are:

Slope: 3

y-intercept: y = 6

Equation: y = 3x + 6

The formula for the equation of a Line in slope intercept form is expressed as:

y = mx + c

where:

m is slope

c is y-intercept

Now, the y-intercept is when x = 0 and as such in this case, it is:

c = 6

Slope between two coordinates is:

Slope = (y₂ - y₁)/(x₂ - x₁)

Slope = (6 - 3)/(0 - (-1))

Slope = 3

Thus, equation is:

y = 3x + 6

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50%. students (in percent) who passed the second exam also passed the first exam.

Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.

Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.

Thus, both tests were passed by 40 of the 80 pupils who passed the second one:                                      

40/80 = 1/2 = 50%.

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The percentage of the population in decimal is p=0.42

The mean of the sample of the binomial distribution=75.6

The standard deviation of the sample of the binomial distribution=6.622

How to convert a decimal to a percentage?

To convert a decimal number into a percentage value, multiply the decimal by 100.

What is binomial distribution?

The binomial distribution gives out either success or failure as two possible results in an experiment, is the discrete probability distribution used in probability theory and statistics.

Given that,

p = 42% = 0.42

q = 1 - p = 1 - 0.42 = 0.58

n = 180

Using the binomial distribution,

mean = \(n \times p\) = \(180 \times 0.42\) = 75.6

standard deviation = \(\sqrt{n \times p \times q}\) = \(\sqrt{180 \times 0.42 \times 0.58}\) = 6.622

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The percentage of the population in decimal is p=0.42

The mean of the sample of the binomial distribution=75.6

The standard deviation of the sample of the binomial distribution=6.622

How to convert a decimal to a percentage?

To convert a decimal number into a percentage value, multiply the decimal by 100.

What is binomial distribution?

The binomial distribution gives out either success or failure as two possible results in an experiment, is the discrete probability distribution used in probability theory and statistics.

Given that,

p = 42% = 0.42

q = 1 - p = 1 - 0.42 = 0.58

n = 180

Using the binomial distribution,

mean =   75.6

standard deviation =  6.622

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Answer:

x = 70

Step-by-step explanation:

50 + x + 2x + 100 = 360

Combine like terms

3x + 150 = 360

Subtract 150 from both sides

3x = 210

Divide both sides by 3 to isolate x

x = 70

The ratio of corresponding sides for the given similar triangles is 2/5.

In the given options, the ratio of corresponding sides is provided for each set of similar triangles. Let's analyze each option to determine the correct ratio:

a. 10

This option only provides a single number and does not specify the ratio of corresponding sides. Therefore, it is not the correct answer.

b. 4/5

This option provides the ratio 4/5 for the corresponding sides of the similar triangles. However, the ratio can be simplified further.

To simplify the ratio, we divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 4 and 5 is 1.

Dividing 4 and 5 by 1, we get:

4 ÷ 1 = 4

5 ÷ 1 = 5

Therefore, the simplified ratio is 4/5.

c. 10/85

This option provides the ratio 10/85 for the corresponding sides of the similar triangles. However, this ratio cannot be simplified further, as 10 and 85 do not have a common factor other than 1.

Therefore, the correct ratio of corresponding sides for the given similar triangles is 2/5, as determined in option b.

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Using the t-distribution, it is found that the value of the test statistic is given by:

(c) -2. 22

At the null hypotheses, it is tested if the mean is not greater than 250, that is:

\(H_0: \mu \leq 250\)

At the alternative hypotheses, it is tested if it is greater, that is:

\(H_1: \mu > 250\)

It is given by:

\(t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}\)

The parameters are:

In this problem, the values of the parameters are:

\(\overline{x} = 230, \mu = 250, s = 36, n = 16\).

Hence, the test statistic is given by:

\(t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}\)

\(t = \frac{230 - 250}{\frac{36}{\sqrt{16}}}\)

t = -2.22.

Which means that option C is correct.

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Answer:

its b

Step-by-step explanation:

Answer:

33/2

Step-by-step explanation:

6 * 11/4 = 66/4 = 33/2

The procedure that can be used to show the converse of the Pythagorean theorem using side lengths chosen from 2 cm, 3 cm, 4 cm, and 5 cm is option C.

Knowing that 3^2 +4^2 = 5^2, draw the 3 cm side and the 4 cm side with a right angle between them. The 5 cm side will fit to form a right triangle.

The Pythagorean Theorem is a relationship that exists between the sides of a right triangle, which is a triangle with one interior angle of 90 degrees. According to the Pythagorean Theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The Converse of the Pythagorean Theorem is an inverse statement that implies that if a triangle's sides satisfy the relationship described in the Pythagorean Theorem, then the triangle is a right triangle.

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Based on the given information, the terminal side of angle 0 lies in quadrant III.

To determine the quadrant in which the terminal side of angle 0 lies based on the given information, we can analyze the signs of the trigonometric functions:

(a) Since sine < 0 and cotangent < 0, we can determine the quadrant as follows:

Sine < 0 implies that the y-coordinate (vertical component) of the point on the unit circle corresponding to angle 0 is negative.

Cotangent < 0 implies that the x-coordinate (horizontal component) of the point on the unit circle corresponding to angle 0 is negative.

In quadrant III, both the x and y-coordinates are negative. Therefore, quadrant III is the correct answer in this case.

(b) The information provided in this option is incorrect. "esce" is not a recognized trigonometric function, and "cos > 0" does not provide enough information to determine the quadrant.

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Answer:

option two

Step-by-step explanation:

Answer:

Option 4.

Step-by-step explanation:

This is not a reflection, this is a translation. So options 1 and 2 are incorrect. Angles are the same so there is no need for it getting verified. Option 4 is correct because the length has changed.

I hope it helps.

Brainliest appreciated.

Answer:

Where is the question??

a) There are 36 sample points that are possible.

b) The probability of obtaining a value of 7 is 1/12.

c) The probability of obtaining a value of 8 or greater is 1/6.

(a) When rolling a pair of dice, each die has six possible outcomes: 1, 2, 3, 4, 5, or 6. The possible outcomes for the pair of dice can be represented by the set of all ordered pairs (a, b), where a and b represent the outcomes of the first and second die, respectively.

Since each die has six possible outcomes, there are a total of 6 x 6 = 36 possible outcomes for rolling a pair of dice.

(b) To obtain a sum of 7, we must have one die showing 1 and the other die showing 6, or one die showing 2 and the other die showing 5, or one die showing 3 and the other die showing 4, for a total of three possible outcomes.

Since each die has six possible outcomes, there are a total of 6 x 6 = 36 possible outcomes. Therefore, the probability of obtaining a sum of 7 is 3/36, or 1/12.

(c) We must have one die showing 2 and the other die showing 6, or one die showing 3 and the other die showing 5, or one die showing 4 and the other die showing 4, or one die showing 4 and the other die showing 5, or one die showing 5 and the other die showing 3, or one die showing 6 and the other die showing 2, for a total of 5 + 1 = 6 possible outcomes.

Therefore, the probability of obtaining a sum of 8 or greater is 6/36, or 1/6.

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The values of the given expression having exponent with negative fractional base i.e. \(-2^{(3/2)^2}\\\) is evaluated out to be 16/9.

First, we need to simplify the expression inside the parentheses using the rule that says "exponents with negative fractional base can be rewritten as a fraction with positive numerator."

\(-2^{(3/2)^2}\) = (-2)² × (2/3)²

Now, we can simplify the expression  further by solving the exponent of (-2)² and (2/3)²:

(-2)² × (2/3)² = 4 × 4/9 = 16/9

Therefore, the value of the given expression \(-2^{(3/2)^2}\\\)  is 16/9.

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The question is :

What is the value of the expression \(-2^{(3/2)^2}\) ?

We have to divide the shape into two

It will give us a Rectangle and a Trapezium