Can someone help me???? Please

Answer:

x = -4 and y = 1

Step-by-step explanation:

-x + y = 5

+ x - 5y = -9 <— let’s eliminate x

————————————-

-4y = -4

y = 1

x - 5y = -9 <— substitute for y

x - 5(1) = -9

x - 5 = -9

+5 = +5

x = -4

You can solve an algebraic Riccati equation using MATLAB.

How to solve and algebraic riccati equation using matlab:

Here's a step-by-step guide:

STEP 1: To solve an algebraic Riccati equation using MATLAB, you will need to use the built-in function `care`.

This function is part of the Control System Toolbox, so ensure you have that installed.

STEP 2: Define the matrices A, B, Q, and R in your equation.

The algebraic Riccati equation is of the form:
  A'*X + X*A - X*B*R^(-1)*B'*X + Q = 0

Here's an example of how you might define these matrices in MATLAB:

```MATLAB
A = [1 2; 3 4];
B = [5; 6];
Q = [1 0; 0 1];
R = 1;
```

STEP 3: Use the `care` function to solve the algebraic Riccati equation.

The syntax is:

```MATLAB
X = care(A, B, Q, R);
```

STEP 4:  After running the above code, the variable `X` will store the solution to the algebraic Riccati equation.

You can display the result by typing `X` in the command window.

Remember to replace the example matrices A, B, Q, and R with the ones specific to your problem.

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Answer: The anwser is C

Step-by-step explanation:

in the first triangle subtract 12 by 9 to get 3.

Then you subtract 13 by 3 which is 10. So, x = 10 or C

The slope of graph is 4.17 (a+1). It represents the annual rise in dose a.

Excellent understanding of medications, their mechanisms of action, side effects, interactions, mobility, and toxicity are prerequisites for practicing pharmacy. Thus, pharmacists are the key healthcare professionals who maximize the use of medicine for the benefit of patients. They are also the world's foremost authorities on drug therapy.

The pharmacist use equation C= 0.0417 d (a+1)

Applying in (mg)

So d = 100 mg

Therefore c = 0.0417×100 (a+1)

C= 4.17 (a+1)

4.17 (a+1) is the slope for the graph of c, which reflects the annual rise in dose a.

kid requires. Given that a newborn is age 0, the appropriate dosage is

c(0) = 4.17 (a+1)

If the recommended adult dosage for a drug is D (in mg), then to determine the appropriate dosage c for a child of age a, pharmacists use the equation c = 0.0417D(a + 1). Suppose the dosage for an adult is 200 mg.

(a) Find the slope of the graph of c. What does it represent?

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Answer:

b)612÷6

Step-by-step explanation:

6)612(102

-6

01

- 0

12

-12

0

=102

The values of the car are

From the question, we have the following parameters that can be used in our computation:

The graph (see attachment)

The graph is an exponential function that can be represented as

y = ab^x

Where

a = y when x = 0

i.e.

a = 30

The value of b is

b = 24/30 = 0.8

So, we have

y = 30(0.8)^x

When x = 2 and x = 8, we have

y = 30(0.8)^2 = 19.2

y = 30(0.8)^8 = 5.0

Hence, the values are 19.2 and 5.0, respectively

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The equation of the circle having point (4,-17) and the center (-4,-2) is \(x^{2} +y^{2} +8x+4y-269=0\).

Given a point on circle (4,-17) and the center of the circle be (-4,-2).

We are required to find the equation of the circke with center (-4,-2) containing the point (4,-17).

Equation is basically the relationship between two or more variables that are expressed in equal to form.

Equation of the circle is \((x-h)^{2} +(y-k)^{2} =r^{2}\) in which (h,k)is point and r is radius.

We have to calculate the radius of the circle.

r=\(\sqrt{(4+4)^{2}+(-17+2)^{2} }\)

=\(\sqrt{64+225}\)

=\(\sqrt{289}\)

=17

The equation will be \((x+4)^{2} +(y+2)^{2} =17^{2}\)

\(x^{2} +16+8x+y^{2} +4+4y=289\)

\(x^{2} +y^{2} +8x+4y-269=0\)

Hence the equation of the circle having point (4,-17) and the center (-4,-2) is \(x^{2} +y^{2} +8x+4y-269=0\).

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The probability that the student makes it to the second class before it starts is very close to 0.

To find the probability that the student makes it to the second class before it starts, we can use the concept of linear combinations of random variables and the properties of normal distributions.

Let's define the random variable X as the total time it takes for the student to transition from the end of the first class to the start of the second class. Since X is a linear combination of independent normally distributed random variables (X1, X2, X3), we can use their means and variances to calculate the mean and variance of X.

The mean of X is the sum of the means of X1, X2, and X3:

μX = μ1 + μ2 + μ3 = 9:02 + 9:15 + 10 = 28:17 minutes.

The variance of X is the sum of the variances of X1, X2, and X3:

σX^2 = σ1^2 + σ2^2 + σ3^2 = (2.5)^2 + (3)^2 + (2.5)^2 = 15.25 minutes^2.

Now, we need to calculate the probability that X is less than or equal to 0, meaning the student arrives before the second lecture starts. Since X follows a normal distribution, we can standardize the variable and calculate the probability using the standard normal distribution table.

Z = (0 - μX) / σX = (0 - 28:17) / √15.25 ≈ -9.43.

Using the standard normal distribution table or a calculator, we can find the probability corresponding to Z = -9.43. The probability is essentially 0, as the value is significantly far in the left tail of the standard normal distribution.

Therefore, the probability that the student makes it to the second class before it starts is very close to 0.

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The correct option is a) (-7, 3) which is the midpoint of the segment.

To find the midpoint of a segment, we need to use the midpoint formula:

Midpoint = ( \((x1 + x2)/2 , (y1 + y2)/2\) )

The midpoint of a segment is the point that lies exactly halfway between the two endpoints of the segment.

It is calculated using the midpoint formula, which involves finding the average of the x-coordinates and y-coordinates of the endpoints.

Using the coordinates given in the diagram, we can substitute them into the formula:

Midpoint = ( (-9 + 5)/2 , (3 + 3)/2 )

Midpoint = ( (-4)/2 , 6/2 )

Midpoint = ( -2 , 3 )

However, it means that if we were to draw a line segment connecting (-9, 3) and (5, 3), the midpoint would be exactly in the middle of that line.

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Answer:

Domain would be -2, range would be 1.

Answer:

x + y = 4 - 1 = 3.

Step-by-step explanation:

First, in order to solve for the sum of x and y, we should substitute (x - 5 = y) into our given equation of x² - y² = 15.

Given:

Substitute:

x² - (x - 5)² = 15.

Use the FOIL Method:

x² - x² + 10x - 25 = 15.

Simplify:

10x - 25 = 15

10x = 40

x = 4.

Solve for y by substitution:

4 - 5 = -1 (y)

x = 4.

y = -1.

Therefore,

x + y = 4 - 1 = 3.

The Power Rule of Differentiation can be used to find the derivative of a given function, such as f(t) = 8(t63)5. The derivative is f′(t) = 240t5(t63)4, where t is the variable.

The given function is,  f(t) = 8(t⁶−3)⁵To find the derivative of the given function, we can use the Power Rule of differentiation.

The power rule of differentiation is as follows: if  f(x) = x^n , then f'(x) = nx^(n-1).Using the power rule of differentiation, we can differentiate the given function as follows:

f′(t) = 8 × 5(t⁶−3)⁴ × 6t⁵= 240t⁵(t⁶−3)⁴

Therefore, the derivative of the function f(t) = 8(t⁶−3)⁵ is f′(t) = 240t⁵(t⁶−3)⁴, where t is the variable.

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Let X be a non-null matrix of order TxK, to prove that the matrix is symmetric, positive semi-definite and under what condition X'X is positive definite will require a thorough proof.
1. Proof that X is Symmetric We can prove this by comparing the matrix X and its transpose X', that is X = X'.Note that this is only true if the matrix X is square, therefore the assumption that the matrix X is non-null does not necessarily mean that it is square.

2. Proof that X is Positive Semi-definite For a matrix to be positive semi-definite, it must satisfy the following property for all non-null vectors z of order K: z'Xz >= 0To prove that X is positive semi-definite we can prove the above condition is true. Let z be any non-null vector of order K such that z = (z1, z2, z3, . . . zk)'. Then we havez'Xz = [z1, z2, z3, . . . zk]X [z1, z2, z3, . . . zk]'= ∑(Xi∙z)i=1 to Kwhere Xi∙z is the ith element of the vector Xz.Now let Xi denote the ith row of X. Therefore, we can write∑(Xi∙z)i=1 to K= ∑(Xiz1, Xiz2, Xiz3, . . . Xizk)1≤i≤TThis can be further simplified as∑(Xiz1, Xiz2, Xiz3, . . . Xizk)1≤i≤T= [z1, z2, z3, . . . zk] [∑Xiz1, ∑Xiz2, ∑Xiz3, . . . ∑Xizk]'= z' (X'X) zSince X'X is a symmetric matrix, it follows that X'X is also positive semi-definite.

3. Proof that X'X is Positive DefiniteFor X'X to be positive definite, it must satisfy the following property for all non-null vectors z of order K: z'X'Xz > 0To prove that X'X is positive definite, we can prove the above condition is true. Let z be any non-null vector of order K such that z = (z1, z2, z3, . . . zk)'. Then we havez'X'Xz = [z1, z2, z3, . . . zk]X'X [z1, z2, z3, . . . zk]'= ∑(Xi∙z)2i=1 to Kwhere Xi∙z is the ith element of the vector Xz. Now let Xi denote the ith row of X. Therefore, we can write∑(Xi∙z)2i=1 to K= ∑(Xiz1)2 + ∑(Xiz2)2 + ∑(Xiz3)2 + . . . + ∑(Xizk)2≥ 0Therefore, we can conclude that X'X is positive definite if and only if all rows of X are linearly independent.

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When the second derivative of a function equals zero, it indicates a possible point of inflection or a critical point where the concavity of the function changes. It is a significant point in the analysis of the function's behavior.

The second derivative of a function measures the rate at which the slope of the function is changing. When the second derivative equals zero at a particular point, it suggests that the function's curvature may change at that point. This means that the function may transition from being concave upward to concave downward, or vice versa.

Mathematically, if the second derivative is zero at a specific point, it is an indication that the function has a possible point of inflection or a critical point. At this point, the function may exhibit a change in concavity or the slope of the tangent line.

Studying the second derivative helps in understanding the overall shape and behavior of a function. It provides insights into the concavity, inflection points, and critical points, which are crucial in calculus and optimization problems.

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When the second derivative of a function equals zero, it indicates a critical point in the function, which can be a maximum, minimum, or an inflection point.

The second derivative of a function measures the rate at which the slope of the function is changing. When the second derivative equals zero, it indicates a critical point in the function. A critical point is a point where the function may have a maximum, minimum, or an inflection point.

To determine the nature of the critical point, further analysis is required. One method is to use the first derivative test. The first derivative test involves examining the sign of the first derivative on either side of the critical point. If the first derivative changes from positive to negative, the critical point is a local maximum. If the first derivative changes from negative to positive, the critical point is a local minimum.

Another method is to use the second derivative test. The second derivative test involves evaluating the sign of the second derivative at the critical point. If the second derivative is positive, the critical point is a local minimum. If the second derivative is negative, the critical point is a local maximum. If the second derivative is zero or undefined, the test is inconclusive.

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The best prediction for the number of times that Leo will get an odd number is 200.

The probability of getting an odd number (1 or 3) is 2/4 = 1/2.

Using the expected value formula, we can predict the number of times that Leo will get an odd number:

Expected number of odd numbers = (probability of getting an odd number) x (total number of trials)

Expected number of odd numbers = (1/2) x (400) = 200

Therefore, the best prediction for the number of times that Leo will get an odd number is 200.

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The value of Cos(4π/3) is (-1/2) i.e., negative one half.

The given function is Cosine (Start fraction 4 pi over 3 end fraction) and this can be written simply as,

Cos(4π/3)

On splitting 4π/3 in two parts, this can also be written as

= Cos(π + (π/3))

(π + (π/3)) lies in the third quadrant and in the third quadrant the value of cosine function is negative. So, using quadrant sign for cosine function, this can be written as

= -Cos(π/3)

Now, Substitute the value of Cos(π/3) = 1/2.

= (-1/2)

Cos(4π/3) = (-1/2)

The value of Cos(4π/3) is (-1/2) i.e., negative one half.

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Answer:

It's B

Step-by-step explanation:

Answer:

9.757

Step-by-step explanation:

To solve us the compound interest formula: \(A=P(1+\frac{r}{n} )^n^t\)

Where A=amount earned; P=principle or starting amount; r=rate(remember to convert to decimal; t=time

Plug your numbers in:

\(900=610(1+\frac{.041}{1} )^1^t\\\)

Divide by 610

\(1.475409836=(1.041)^t\)

Convert to logarithms

㏒(1.475409836)=㏒1.041

Divide

㏒(1.4754-98236)/㏒1.041=x

9.757

Answer:

r/2 -6

Step-by-step explanation:

less than means it comes after

half of r

r/2

6 less than means subtract

r/2 -6

Answer:

A stem and leaf diagram displays numerical data.The stem and leaf diagram is ordered if the data is in numerical order.

Step-by-step explanation:

Answer:

38°

Step-by-step explanation:

\(m\angle 4 = 180° - [62\degree + (62\degree + 18\degree)] \\\\

m\angle 4 = 180\degree - [62\degree + 80\degree] \\\\

m\angle 4 = 180\degree -142\degree \\\\

m\angle 4 = 38\degree \\\\

\)

Answer:

what do you mean

Step-by-step explanation:

Answer:

6 - 2t < -4

Step-by-step explanation:

:)

Answer:

Part (a):  Because the survey was held at basketball championship.

Part (b): The survey among students should held at school or in any common place.

Step-by-step explanation:

The second balloon will take longer to land compared to the first balloon, even though they have the same descent rate.

From the question, we have the following parameters that can be used in our computation:

Both balloons have the same descent rate of -20 meters per second (m/s) because they have the same slope (-20) in their equations.

However, the second balloon has a higher starting height (y-intercept) of 1200 meters, compared to the first balloon's starting height of 800 meters.

To find the landing time, we can set y=0 in each equation and solve for x:

For the first balloon:

0 = -20x + 800

20x = 800

x = 40 seconds

So the first balloon will land after 40 seconds.

For the second balloon:

0 = -20x + 1200

20x = 1200

x = 60 seconds

So the second balloon will land after 60 seconds.

When the y-intercepts are compared, we have

1200 is greater than 800 by 400

Graphically, this can be seen as the second balloon's descent line being shifted up by 400 meters (the difference in starting heights) compared to the first balloon's descent line.

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Answer:

a. ben eats 27 apples

b. ben has 18 apples left

Answer:

multiply ata gagawin dyan Ewan

The steepest angle at which unconsolidated granular material remains stable is known as the angle of repose.

The steepest angle at which unconsolidated granular material remains stable is known as the angle of repose. This angle varies depending on the properties of the granular material such as size, shape, and degree of consolidation. The angle of repose is a critical factor in many fields such as engineering, geology, and agriculture. For example, in civil engineering, the angle of repose is essential in designing stable slopes and retaining walls. In agriculture, it is crucial for understanding the flow and distribution of granular materials such as seeds, fertilizers, and grains. In general, the angle of repose for unconsolidated granular materials ranges from 25 to 45 degrees, but it can be higher for certain materials such as sand, or smaller for cohesive soils.
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Using the normal distribution as an approximation for the binomial or Poisson distribution involves applying the characteristics of the normal distribution to approximate the behavior of these discrete distributions. This approximation is based on certain conditions and mathematical principles.

The normal distribution has finite tails, meaning that extreme values in the binomial or Poisson distribution may not be accurately captured by the normal approximation.

The normal distribution, also known as the Gaussian distribution, is a continuous probability distribution that is symmetric and bell-shaped. It is fully characterized by its mean (μ) and standard deviation (σ). On the other hand, the binomial distribution describes the probability of a certain number of successes in a fixed number of independent Bernoulli trials, while the Poisson distribution models the probability of a given number of events occurring in a fixed interval of time or space.

The decision to use the normal distribution as an approximation for the binomial or Poisson distribution relies on specific conditions. These conditions include having a large number of trials or observations and a moderate range of values. Additionally, the probability of success for each trial should be reasonably close to 0.5 for the binomial distribution or the mean should be sufficiently large for the Poisson distribution.

The approximation works due to the central limit theorem (CLT), which states that the sum or average of a large number of independent and identically distributed random variables will be approximately normally distributed, regardless of the shape of the original distribution. In the case of the binomial distribution, as the number of trials increases, the distribution becomes more symmetric and bell-shaped, resembling a normal distribution. Similarly, for the Poisson distribution, as the mean increases, the distribution also approaches a symmetric and bell-shaped form, making it suitable for approximation using the normal distribution.

The strengths of using the normal distribution as an approximation are its simplicity and ease of use. The normal distribution has well-defined properties and is widely understood and studied. It allows for the application of various statistical techniques, such as confidence intervals and hypothesis testing, that are based on the normal distribution. Additionally, the normal distribution has a straightforward parameterization with its mean and standard deviation, making it convenient for calculations and interpretations.

However, there are limitations and weaknesses to consider when using the normal distribution as an approximation. One limitation is that the approximation may not be accurate when the conditions for using the normal distribution are not met. For example, if the number of trials or observations is small, or if the probability of success for each trial is close to 0 or 1, the normal approximation may not provide accurate results.

Another weakness is that the approximation may introduce some error in the tails of the distribution. The normal distribution has finite tails, meaning that extreme values in the binomial or Poisson distribution may not be accurately captured by the normal approximation.

It is important to assess the appropriateness of using the normal distribution as an approximation based on the specific characteristics of the data and the objectives of the analysis. When the conditions are met, the normal approximation can be a useful tool for simplifying calculations and making inferences. However, when dealing with small sample sizes, extreme values, or distributions that deviate significantly from normality, alternative methods or distributions may be more appropriate.

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Answer:

it's A

Step-by-step explanation:

Because 6/18 6x3 = 18 18 divided by 6 is 3 so it's 1/3

Answer:

Zero Property of Addition

Step-by-step explanation:

Click the heart button, will you?

Answer:

Additive Identity Property