can somebody help me with this please it’s due tomorrow

The polar bear has a birth weight of 0.5 kilogram.

The linear equation is y = x + 0.4t

Given,

The weight gained by polar bear each week after it was born = 0.4 kg

The weight of polar bear after 3 weeks = 1.7 kilo grams

We have to write an linear equation to represent this ;

Here,

y be the weight of polar bear

x be the initial weight

t be the number of week.

So,

the equation be like;

y = x + 0.4t

Then,

1.7 = x + 0.4 x 3

x = 1.7 - 1.2 = 0.5

The polar bear has a birth weight of 0.5 kilogram.

The linear equation is y = x + 0.4t

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For the function to be a linear, D. a = 20 because the rate of change is –3.

The rate of change = change in y / change in x.

Therefore, for the function to be linear, the rate of change must be the same across the table of values.

Using, (4, 26) and (5, 23):

Rate of change = (26 - 23)/(4 - 5)

Rate of change = (3)/(1) = -3

Using (5, 23) and (6, a), we have:

(23 - a)/(5 - 6) = -3

(23 - a)/(-1) = -3

23 - a = (-3)(-1)

23 - a = 3

-a = 3 - 23

-a = -20

a = 20

Therefore, the answer is: D. a = 20 because the rate of change is –3.

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Using translation concepts, we have that:

a) The parent function is f(x) = |x|.

b) The transformations were a reflection over the x-axis, vertical stretch by a factor of 2 and a shift down of 3 units.

c) The graph is given at the end of the answer.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

For this problem, the parent function is given by:

f(x) = |x|.

The transformations are given as follows:

The graph of the two functions, the parent(red) and the translated(blue), is given at the end of the answer.

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Mr. Mensah's total earnings at the end of the fifteenth year of service is €1920.00 + €2520.00 = €4440.00.

To calculate Mr. Mensah's salary in the fifteenth year of service, we need to determine the pattern of salary increase over the years.

We know that Mr. Mensah's salary starts at €6400.00 and increases by €240.00 every year for the first eight years. After that, he is promoted to a new post with an annual salary of €9500.00, which increases by €360.00 every year.

Let's break it down:

For the first eight years, the salary increases by €240.00 per year:

After 1 year: €6400.00 + €240.00 = €6640.00

After 2 years: €6640.00 + €240.00 = €6880.00

...

After 8 years: €6400.00 + (8 * €240.00) = €6400.00 + €1920.00 = €8320.00

From the ninth year onwards, the salary increases by €360.00 per year:

After 9 years: €9500.00 + €360.00 = €9860.00

After 10 years: €9860.00 + €360.00 = €10220.00

...

After 15 years: €9500.00 + (7 * €360.00) = €9500.00 + €2520.00 = €12020.00

Therefore, Mr. Mensah's salary in the fifteenth year of service is €12,020.00.

To calculate Mr. Mensah's total earnings at the end of the fifteenth year of service, we need to sum up his salaries from year 1 to year 15.

For the first eight years, the total earnings can be calculated as follows:

Total earnings = (Salary in year 1 + Salary in year 2 + ... + Salary in year 8) = 8 * €240.00 = €1920.00

From the ninth year onwards, the total earnings can be calculated as follows:

Total earnings = (Salary in year 9 + Salary in year 10 + ... + Salary in year 15) = 7 * €360.00 = €2520.00

Therefore, Mr. Mensah's total earnings at the end of the fifteenth year of service is €1920.00 + €2520.00 = €4440.00.

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Answer:

87.96

Step-by-step explanation:

87.9645943

Round to either 0 or the next tenth.

87.9645943

87.964594(0)

87.96459(0)

87.9646(0)

87.965(0)

87.96(0)

87.9645943 rounded to the nearest hundredth is​ 87.96

Rounding some number to a specific value is making its value simpler (therefore losing accuracy), mostly done for better readability or accessibility.

Rounding to some place keeps it accurate on the left side of that place but rounded or sort of trimmed from the right in terms of exact digits.

87.9645943

We have to Round to either 0 or the next tenth.

87.9645943

87.964594(0)

87.96459(0)

87.9646(0)

87.965(0)

87.96(0)

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¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)

Proof:

1. ∃x(Fx & Gx) [Premise]

2. Fx & Gx [∃-Elimination, 1]

3. ∃xFx [∃-Introduction, 2]

4. ∃xGx [∃-Introduction, 2]

5. ∃xFx & ∃xGx [Conjunction Introduction, 3 and 4]

6. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx [1-5, Modus Ponens]

ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks)

Proof:

1. ¬ 3x(Px v Qx) [Premise]

2. ¬ Px v ¬ Qx [DeMorgan’s Law, 1]

3. Vx ¬ Px [∀-Introduction, 2]

4. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px [1-3, Modus Ponens]

iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)

Proof:

1. ¬ Vx(Fx → Gx) v 3xFx [Premise]

2. (¬ Vx(Fx → Gx) v 3xFx) → (¬ Vx(Fx → Gx) v Fx) [Implication Introduction]

3. ¬ Vx(Fx → Gx) v Fx [Resolution, 1, 2]

4. (¬ Vx(Fx → Gx) v Fx) → (Fx → Gx) [Implication Introduction]

5. Fx → Gx [Resolution, 3, 4]

6. ¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

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Answer:

158

Step-by-step explanation:

The required bearing angle of town B from Thomas is 75°.

We have,

Bearing is basically an angle that is measured clockwise from the north. Bearing are generally written in three figure.

Given that

Thomas is facing towards town A, which is at a bearing of 300°.

Implies that town A is 300° from north.

If Thomas turns 135° clockwise, then he faces towards town B,

The bearing angle will be 300+135 = 435°

Since, one complete round makes angle 360°, therefore

The required bearing angle = 435 - 360 = 75

The bearing angle of town B from Thomas is 75°.

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Answer:

D. 49.314 ft²

Step-by-step explanation:

Area = 1/2 s² sinФ

= 1/2 * 15² * sin(26)

= 49.314 ft²

Adding a quadratic term to data that shows a curve in the scatterplot will provide a better fit but not affect the residual plot in any way, this statement is false

A scatterplot is a type of data display that shows the relationship between two numerical variables. Each member of the dataset gets plotted as a point whose x-y coordinates relates to its values for the two variables.

When on adding a quadratic term to  data, is illustrated on a scatter plot, a quadratic equation will form a “U” shape that is either concave down or concave up.

Therefore, adding a quadratic term to data that shows a curve in the scatterplot will provide a better fit but not affect the residual plot in any way, this statement is false.

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Answer:

(5, 3)

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define systems

y = x - 2

-2x + 3y = -1

Step 2: Solve for x

Step 3: Solve for y

Answer:

the answer is d I'm positive:)

The correct answer is option 4) 0.85 euros. The value of $1 in euros is approximately 0.8475 euros.

The value of $1 in euros can be calculated by taking the reciprocal of the exchange rate. If one euro is worth $1.18, then the value of $1 in euros would be:

1 / 1.18 = 0.8475 euros

Rounding to two decimal places, the value of $1 in euros is approximately 0.85 euros. Therefore, the correct answer is option 4) 0.85 euros.

To calculate the value of $1 in euros, we need to determine the reciprocal of the exchange rate between euros and dollars. In this case, if one euro is worth $1.18, we can find the value of $1 in euros by taking the reciprocal of 1.18.

Reciprocal of 1.18 = 1 / 1.18 = 0.8475

Therefore, the value of $1 in euros is approximately 0.8475 euros.

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Part A

we have the equation

(x-13)^2+(y-4)^2=16

Rewrite as

(x-13)^2+(y-4)^2=4^2

so

The center of the circle is the point (13,4)

The radius of the circle is 4 units

using a graphing tool

Part B

Remember that

If an ordered pair lies on the circle, then the ordered pair must satisfy the equation of the circle

so

Verify each ordered pair

Hunter (11,4)

For x=11 and y=4

substitute in the equation of the circle

Is not true

so

Hunter is not in the spotlight

Joe (8,5)

x=8 and y=5

Is not true

so

Joe is not in the spotlight

Mason (15,5)

x=15 and y=5

Is not true

Mason is not in the spotlight

Answer:

as we know,

common ratio=t2/t1

= 18/24

=3/4

Answer:

1.35 is the cost of the regular ice cream

Step-by-step explanation:

Answer:

105

Step-by-step explanation:

0 (104) is equal to 0, so let's cross that out. 103 times 102 is definitely not equal to 105. The third one is 105. The fourth one is not 105. The last one is not 105 either.

Answer:

a) tan x = 1

b) tany = 4 + tanx /2tanx - 3

Step-by-step explanation:

a) Given the equation

2(sinx + 2cosx) = sinx +5cosx

Open the bracket

2sinx + 4cosx =  sinx +5cosx

Collect like terms

2sinx - sinx = 5cosx - 4cosx

sinx = cos x

Divide both sides by cos x

sinx/cosx = cosx/cosx

tanx = 1

Hence the value of tan x is 1

b) Given the expression

sinxcosy + 3cosxsiny = 2sinxsiny - 4cosxcosy

We are to express tany in terms of tan x

Divide through by cosx cosy

sinxcosy/cosx cosy + 3cosxsiny/cosx cosy = 2sinxsiny/cosx cosy - 4cosxcosy/cosx cosy

sinx/cosx + 3siny/cosy = 2tanxtany - 4

tanx +3tany =  2tanxtany - 4

Collect like terms

tanx - 2tanxtany = -4 - 3tany

- 2tanxtany+3tany = -4 - tanx

tany (-2tanx+3) = -4 - tanx

tan y = -4 - tanx/-2tanx+3

tan y = -(4+tanx)/-(2tanx-3)

tany = 4 + tanx /2tanx - 3

Hence the function of tany in term of tan x is tany = 4 + tanx /2tanx - 3

Answer:

-5

Step-by-step explanation:

Answer:

A and B

Step-by-step explanation:

5-(-8) = 5+ 8= 13 (the distance between -8 and 5)

5+|-8| = 5 +8 = 13

The true statements are, Line A B and Line C G are parallel, Line C G and Line R S are perpendicular, Line A B and Line R S must intersect and Line segment C G lies in plane X.

Given that Planes X and Y intersect at a right angle. Line AB and CG are on plane X, while line RS is on plane Y. Therefore, line CG lies on plane X.

Since both line AB and CG lie on the same plane, they are parallel to each other.

Since plane X and plane Y are perpendicular to each other and line CG is on plane X while line RS is on plane Y, this means that Line CG and Line RS are perpendicular to each other.

Line AB and Line RS may or may not intersect. They could be skew lines, which do not intersect and are not parallel.

Line segment CG lies on plane X since it is contained within the plane that contains points C, G, and either A or B.

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The question is -

Which statements are true? Select three options.

a. Line A B and Line C G are parallel.

b. Line A B and Line R S are parallel.

c. Line C G and Line R S are perpendicular.

d. Line A B and Line R S must intersect.

e. Line segment C G lies in plane X.

f. Line segment R S lies in plane X.

Answer: ace

Step-by-step explanation:

Answer:

1080ft cubed

Step-by-step explanation:

The formula is "lenght times width times height."

A triangle can not have three sides whose lengths are 3.2 cm 5.3 cm 9.4 cm

We know that the triangle inequality theorem states that for any triangle the sum of any two sides of a triangle is greater than or equal to the third side.

Here, we have been given the three measurements.

Let a = 3.2 cm, b =  5.3 cm and c = 9.4 cm

Consider the sum of sides a and b,

a + b

= 3.2 + 5.3

= 8.5cm

< 9.4

= c

i.e., a + b < c

Acctording to triangle inequality theorem, a, b, c can not be the sides of triangle, as the sum of two sides that measure 3.2 cm and 5.3 cm is not greater than or equal to the third side which measures 9.4 cm

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True. Exception reports show a greater level of detail than is included in routine reports.

Exception reports are reports that help in identifying data that does not conform to expected patterns. Exception reports show information about an exception in the data set.

This helps to identify irregularities or anomalies in data or system operations.Exception reports are used to analyze system performance, monitor resource consumption, and to detect unusual activity.

This type of report is important to identify issues or errors, where the routine reports or standard reports would not provide enough detail or insight to do so.

It provides detailed information on any unusual event or anomaly that occurred beyond the usual course of events or processes.Exception reports are generated and distributed when the data is not expected or when an event occurs that is outside of what is considered typical.

For example, a financial system might generate an exception report if a transaction is entered that exceeds the maximum allowed amount. This report would show the details of the transaction and highlight the exception.

The purpose of exception reports is to provide users with a higher level of detail than they would find in routine reports. Exception reports are used to highlight significant data, which will be used for further analysis or action.

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90% confidence interval is 11.65 <µ< 114.566 as per standard deviation data.

What is a standard deviation?

Sample mean (T) = 13.11%

Sample standard deviation (s) = 2.6

Sample size (h) = 25

significance level = α = 1 -0.90 = 0.1

Degrees of freedom for t- distribution (df) = 24

Critical value = ta/2

df = \(t_{0.1}\), df=24 = ±2.80

The margin of error (E) =\(t_\frac{a}{2} , df\frac{s}{\sqrt{h} }\)

E=2.8X \(\frac{2.6}{\sqrt{25} }\) =1.456

Limits of 90%. Confidence Interval is.

Lowest limit = X' - E = 13.11-1.456 = 11.65

Upper limit= X' + E = 13.11+1.456 = 14.566

90% confidence interval is 11.65 <µ< 114.566 as per standard deviation data.

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Answer:

To what?

Step-by-step explanation:

The total number of particles of pollutant per day deposited in town along the highway is 45000

Pollutant particles deposited in town along the highway on a daily average is given by the integral of the density function over the length of the town. We need to split the integral into two parts because the town extends three miles in both directions from the factory.

Let's consider the interval from -3 to 0 first:

_{-3}⁰ d(x) dx = ∫{-3}⁰ (500(12-2x)) dx

= 500 [12x - x²]{-3}²

= 500 [(0-(-36)) - (36-81)]

= 22,500

Now let's consider the interval from 0 to 3:

∫{0}³ d(x) dx = ∫{0}^{3} (500(12+2x)) dx

= 500 [12x + x²]{0}³

= 500 [(36+9) - 0]

= 22,500

Therefore, the total number of particles of pollutant per day deposited in town along the highway is 22,500 + 22,500 = 45,000.

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The clock minutes rotate 270 degrees in 45 minutes.

While rotating, the clock's hands are seen to move at a speed of six degrees per minute.

The number of degrees for a clock minute is solved by

60 minutes  = 360 degrees

1 minute = ?

cross multiplying

60 * ? = 360

? = 360 / 60

? = 6

hence 1 minute is 6 degrees

The formula to use to get the calculation is multiplying the number of minutes by 6

Number of degrees in 45 minutes = 45 * 6

Number of degrees in 45 minutes = 270 degrees

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Answer:

The quantity of natural numbers between \(a^{2}\) and \(c^{2}\) is \(2\cdot (a + b) + 1\).

Step-by-step explanation:

If \(a^{2}\), \(b^{2}\) and \(c^{2}\) are consecutive perfect squares, then both \(a\), \(b\) and \(c\) are natural numbers and we have the following quantities of natural numbers:

Between \(b^{2}\) and \(c^{2}\):

\(c^{2} = (b+1)^{2}\)

\(c^{2} = b^{2}+2\cdot b + 1\)

\(c^{2}-b^{2} = 2\cdot b + 1\)

And the quantity of natural numbers between \(b^{2}\) and \(c^{2}\) is:

\(c^{2}-b^{2}-1 = 2\cdot b\)

Between \(a^{2}\) and \(b^{2}\):

\(b^{2} = (a + 1)^{2}\)

\(b^{2} = a^{2} +2\cdot a + 1\)

\(b^{2}-a^{2} = 2\cdot a + 1\)

And the quantity of natural numbers between \(a^{2}\) and \(b^{2}\) is:

\(b^{2}-a^{2}-1 = 2\cdot a\)

And the quantity of natural numbers between \(a^{2}\) and \(c^{2}\) is:

\(Diff = 2\cdot a + 2\cdot b + 1\)

Please observe that the component +1 represents the natural number \(b^{2}\)

Lean construction is a project management approach that aims to improve efficiency, productivity, and sustainability in the construction industry. It focuses on eliminating waste, reducing variation, and promoting continuous workflow. The concept and principles of lean construction can contribute to each pillar of sustainability in promoting sustainable construction practices in Malaysia as follows:

Environmental Pillar:

Lean construction minimizes waste generation by optimizing material usage and reducing energy consumption during construction. By streamlining processes and eliminating non-value-added activities, it reduces the environmental impact of construction projects. Additionally, lean construction encourages the use of sustainable materials and promotes recycling and reuse, further reducing the depletion of natural resources.

Social Pillar:

Lean construction prioritizes worker safety and well-being, which addresses the high number of fatality cases in the construction industry. By implementing efficient processes and standardized work procedures, it reduces the occurrence of accidents and injuries. Furthermore, lean construction fosters better communication and collaboration among project stakeholders, promoting a positive and respectful work environment.

Economic Pillar:

Lean construction aims to deliver projects on time and within budget. By minimizing delays, rework, and cost overruns, it enhances project profitability. Lean principles such as value stream mapping and continuous improvement help identify and eliminate bottlenecks, leading to increased productivity and cost savings. Moreover, the higher quality of lean construction practices reduces maintenance and operational costs in the long run.

The concept and principles of lean construction can significantly contribute to each pillar of sustainability. By reducing waste, improving worker safety, and enhancing project efficiency and profitability, lean construction promotes sustainable construction practices in Malaysia. Adopting lean principles can lead to more environmentally friendly, socially responsible, and economically viable construction projects, ultimately benefiting both the industry and society as a whole.

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