Calculate the speed of the water jet emerging from the nozzle

a)It takes 0 seconds for the stone to hit the ground.

b)The stone has traveled 19.6 meters after 2 seconds.

When an object is dropped from a height, the motion is described as free fall. It is a special form of motion in which an object is under the sole influence of gravity. The gravitational force acting on an object is always directed towards the center of the Earth, i.e., downwards. Therefore, when an object is dropped from a height, it falls freely towards the ground, and the acceleration of the object is equal to the acceleration due to gravity, which is approximately 9.8 m/s².

In the problem given, a stone is dropped from rest from the top of a higher tower. Therefore, the initial velocity of the stone, u = 0 m/s.

a. Time taken by the stone to reach the ground:
We can use the following equation of motion to calculate the time taken by the stone to reach the ground.
v = u + at

where,
v = final velocity of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity

Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.

At the ground level, the final velocity of the stone, v = ?
Again, the acceleration due to gravity, a = 9.8 m/s².

Therefore, we can write the equation as:

v = u + at
v = 0 + 9.8×t
v = 9.8t m/s

When the stone hits the ground, the final velocity of the stone, v = 0 m/s.

Therefore, we can rewrite the equation as:

0 = 9.8t
t = 0 seconds (when the stone is at the top of the tower)

We have found that it takes 0 seconds for the stone to hit the ground.

b. How far the stone has travelled after 2 seconds:
We can use the following equation of motion to calculate how far the stone has travelled after 2 seconds.
s = ut + (1/2)at²

where,
s = displacement of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity

Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.

The acceleration due to gravity, a = 9.8 m/s².

Therefore, we can write the equation as:

s = ut + (1/2)at²
s = 0×2 + (1/2)×9.8×(2)²
s = 19.6 m

Therefore, the stone has traveled 19.6 meters after 2 seconds.

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Answer:

well, in my view,

In fluid mechanics, hydrostatic equilibrium or hydrostatic balance (also known as hydrostasy) is the condition of a fluid or plastic solid at rest. This occurs when external forces such as gravity are balanced by a pressure-gradient force.

The work that is done by the gas can be obtained as 110 J.

There is not enough information in the question to determine part B.

We know that a gas is said to do work whenever the gas expands. The expansion of a gas mans that the gas is able to increase its volume and we can see from the question that the volume of the gas was quite able to move from a value of  450 mL to 810 mL .

How then can be be able to obtain the work that has been done by the gas in this case? We are aware that we do have the following parameters from the question;

Pressure of the gas = 3.1 atm

Initial volume of the gas = 450 mL or 0.45 L

Final volume of the gas = 810 mL or 0.81 L

The we have the formula;

W =PΔV

W = work done

P = pressure of the gas

ΔV = change in the volume of the gas

Thus;

W = 3.1 (0.81 - 0.45)

W = 1.12 atm L or 110 J

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The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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The calculated value of angle of refraction be 29.88°.

Refraction is defined as "the change in a wave's direction as it passes through a medium."

Although light refraction is one of the most frequently seen phenomena, refraction can also occur with sound and water waves. We can use optical tools like lenses, prisms, and magnifying glasses thanks to refraction. We can focus light on our retina because of the refraction of light, which is another benefit.

Given that;

Angle of incident of light from air to water: i = 24°

Refractive index of water: n = 1.33

So, the angle of refraction be = sin⁻¹(nsini) = sin⁻¹( 1.33 sin24°) = 29.88°.

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Correct question is;

1/0.12 = (1/0.05) + (1/d')

Answer:

d' = -1/700

Explanation:

1/0.12 = (1/0.05) + (1/d')

Let's rearrange to get;

(1/d') = (1/0.12) - (1/0.05)

(1/d') = (1/(12/100)) - (1/(5/100))

(1/d') = 100/12 - 100/5

Let's multiply through by 60 to get rid of the denominators on the right side;

> (1/d') = 500 - 1200

> (1/d') = -700

> d' = -1/700

The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.

Answer:

Use the nutritional values on the menu.

Answer:

Explanation:

salid

When three particles q1, q2, and q3 are in a straight line, the force experienced by q2 depends on the distance between the particles, the magnitude of the charges of the particles, and the relative position of the particles. The electric force on a charge q1 from a charge q3, which is at a distance r3 from the first charge, is governed by Coulomb’s Law.

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Refraction would cause the red light to bend at the air/glass boundary.

While the question is unclear, I assume that you are trying to know something about the refraction of the red light across the air/glass boundary. I will tell you something about refraction!

Refraction is a phenomenon of light where it changes direction when it enters a medium with a different refractive index. Refractive index is a measure of how much a medium bends light that passes through it. When light passes from a medium with a lower refractive index to a medium with a higher refractive index, it bends towards the normal (an imaginary line perpendicular to the surface at the point of incidence). On the other hand, when light passes from a medium with a higher refractive index to a medium with a lower refractive index, it bends away from the normal.

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Answer: a) 2,508

Explanation:

The activity is a radioactive material is the number of counts per second it produces. 1 count per second (cps) = 1 Becquerel (Bq).

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The coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

To find the limit that the coefficient of static friction places on the minimum time required for a car to accelerate from rest to 60.0 mph (26.8 m/s), we need to consider the maximum acceleration the car can achieve due to the friction between the rear tires and the pavement.

The maximum acceleration can be determined using the formula:

a_max = μs * g

where μs is the coefficient of static friction and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, since the car's engine only turns the two rear wheels, the maximum acceleration is limited by the friction force between the rear tires and the pavement.

Now, to calculate the minimum time required to accelerate to 60.0 mph (26.8 m/s), we can use the following kinematic equation:

v = u + a * t

where v is the final velocity (26.8 m/s), u is the initial velocity (0 m/s), a is the acceleration, and t is the time.

Rearranging the equation, we have:

t = (v - u) / a

Plugging in the values, we get:

t = (26.8 m/s - 0 m/s) / a_max

t = 26.8 m/s / (μs * g)

Substituting the given value for the coefficient of static friction (μs ≈ 0.800) and the acceleration due to gravity (g ≈ 9.8 m/s²), we can solve for the minimum time required:

t = 26.8 m/s / (0.800 * 9.8 m/s²)

t ≈ 3.42 seconds

Therefore, the coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

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Answer:

the one with v = 25 m/s

Explanation:

Momentum = m * v

 if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s

Explanation:

The formula we are going to use is

Pressure = F/A

Elephant:

First, we need to convert weight into newtons.

1kg=9.8 newtons, so 2800kg × newtons = 27440newtons

For 4 feet= 200×4= 800cm^2

Convert the area to meter squared using the following:

1 centimeter squared = 0.0001 meters squared

800cm^2×0.0001= 0.08m^2

Pressure=F/A

Pressure= 27440/0.08

The pressure exerted on the ground by the elephant is 343000 Pascals.

Vulture:

12kg×9.8=117.6newtons

for 2 feet= 2.0×2=4cm^2

4×0.0001=0.0004m^2

117.6/0.0004= 294000 Pascals

To compare the pressure, just do a ratio of the elephant's pressure to vulture's pressure.

343000/294000≈ 1.17

So the pressure is about 1 times bigger.

Keep in mind that the elephant has 4 feet, which help to increase the area which in turn decrease the pressure. 

Elephant's feet are more likely to sink as elephant's feet apply more pressure on the muddy area.

Pressure is defined as the thrust per unit area. Thrust is the perpendicular force applied. Its SI unit is pascals.

So, P = T/A

Here,

Mass of elephant = 2800 kg

Force applied = 2800 × 9.8 ( 1kg = 9.8 N)

= 27440 N

Average feet area of elephant = 200 cm2

Since an elephant has 4 feet,

200 × 4 = 800 cm2 = 0.08 m2

Now, P = F/A

27440/0.08 = 343000 pascals

For the vulture,

Force of the vulture = 12 × 9.8 = 117.6 N

Area = 2.0 × 2 = 4cm2 = 0.0004 m2

Now, P = 117.6 / 0.0004 = 294000 pascals

So, pressure applied by the elephant's feet is more than the pressure applied by the vulture's feet. Therefore, the elephant's feet will sink.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

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Answer:

It would be -23.83

Explanation:

The formula would just be velocity final=velocity initial plus gravity times time. So it would be 5.6+-(9.81)(3)

Plate tectonic theory is the movement of the plates or slabs of rigid rocks over the surface of the earth or the molten rocks that is the mantel.  

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Answer:

2.687×1025 particles/m3

Answer:

gjmoon = 19.6 m/s2

Explanation:

       \(F_{gE} = m* \frac{G*M_{E} }{R_{E} ^{2} } = m*g_{E}\)

      \(F_{gjmoon} = m* \frac{G*M_{Jmoon} }{R_{Jmoon} ^{2} } = m*g_{jmoon} (1)\)

       \(M_{Jmoon} = \frac{M_{E} }{2} (2)\)  

      \(R_{Jmoon} = \frac{R_{E} }{2} (3)\)

       \(F_{gjmoon} = m* \frac{G*M_{E} }{2*\frac{R_{E} ^{2}}{4} } = m*g_{jmoon} (1) = m* 2* \frac{G*M_{E} }{R_{E} ^{2}} = 2* m*g_{E}\)

      ⇒  \(g_{jmoon} = 2* g_{E}\)

       gjmoon = 19.6 m/s2 (in magnitude).

Answer:

1) t = 3.45 s, 2)  x = 138 m, 3) v_{y} = -33.81 m /s, 4) v = 52.37 m / s ,

5) θ = -40.2º

Explanation:

This is a projectile exercise, as they indicate that the projectile rolls down the cliff, it goes with a horizontal speed when leaving the cliff, therefore the speed is v₀ₓ = 40 m / s.

1) Let's calculate the time that Taardaen reaches the bottom, we place the reference system at the bottom of the cliff

      y = y₀ + \(v_{oy}\) t - ½ g t²

When leaving the cliff the speed is horizontal  v_{oy}= 0 and at the bottom of the cliff y = 0

      0 = y₀ - ½ g t2

      t = √ 2y₀ / g

      t = √ (2 60 / 9.8)

      t = 3.45 s

2) The horizontal distance traveled

     x = v₀ₓ t

     x = 40 3.45

     x = 138 m

3) The vertical velocity at the point of impact

     v_{y} = I go - g t

     v_{y} = 0 - 9.8 3.45

     v_{y} = -33.81 m /s

the negative sign indicates that the speed is down

4) the resulting velocity at this point

   v = √ (vₓ² + v_{y}²)

   v = √ (40² + 33.8²)

   v = 52.37 m / s

5) angle of impact

    tan θ = v_{y} / vx

    θ = tan⁻¹ v_{y} / vx

    θ = tan⁻¹ (-33.81 / 40)

    θ = -40.2º

6) sin (-40.2) = -0.6455

7) tan (-40.2) = -0.845

8) when the projectile falls down the cliff, the horizontal speed remains constant and the vertical speed increases, therefore the resulting speed has a direction given by the angle that is measured clockwise from the x axis

Answer:

B - sorry if im wrong

Explanation:

Answer:

Mercury is the only one in liquid state at room temperature. It's used in thermometers because it has high coefficient of expansion.

Explanation:

please mark me brainlist

Mercury is the only one in liquid state at room temperature. It's used in thermometers because it has high coefficient of expansion. they still use mercury even though it is the poorest conductor of heat.

Answer: a + b = (-2,5)

Explanation: I'm assuming that these are 1-dimensional matrices or vectors.

So,

a + b = [ a(x) + b(x), a(y) + b(y) ]

        = [ (3) + (-5) , (2) + (3) ]

        = [ (-2) , (5) ]

a +b = (-2,5)

Answer:

a) 3170 kw

b) 377 km^2

Explanation:

Estimate of electric power

a) Given :

Average power consumption for a family of 3 = 108.4 * 106 BTU per year  =  0.0317 kw = 31.7 watts

The power requirement for a city of 300000 people

= 31.7 watts * 100000 = 3170000 watts = 3170 kw

b) Given :

Average solar panel insulation = 8.4 W /m^2

Estimate the area of silicon solar cells required to satisfy community power requirement

= (1 * 3170) * (1000/8.4 )

= 377.380 * 10^3 m2 = 377 km^2

Answer:

Explanation:

PE = mgh

h = PE/mg

h = 2000/(65.0(9.81))

h = 3.1365168979...

h = 3.14 m

a VERY strong man if he can do that!

Answer:

Warm weather may be found in the tropical zone since the sun's heat is concentrated in regions close to the equator. At 23.5 degrees north of the equator and 23.5 degrees south of the equator, this area is nearly in the middle of the world. It has a monthly average temperature of 18 degrees Celsius or higher.

Explanation: