calculate the resistance of a toaster oven if its power is 800 W when connected to a 110 V outlet

The flow speed of the ideal fluid in the wider section is 6 m/s.

The flow speed of the ideal fluid in the wider section is calculated by applying continuity equation as shown below.

A₁V₁  =  A₂V₂

Where;

πr₁²V₁² = πr₂²V₂²

r₁²V₁² = r₂²V₂²

V₂² = r₁²V₁² / r₂²

Where;

V₂² = r₁²V₁² / r₂²

V₂² = ( r₁²V₁²) / (2r₁)²

V₂² = ( r₁²V₁²)/(4r₁²)

V₂² = (V₁²)/(4)

V₂² = (12²)/4

V₂² = 36

V₂ = √36

V₂ = 6 m/s

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Answer:

10m/s

Explanation:

Answer:

See Explanation

Explanation:

m1(v1) + m2(v2)

Opposite turns the plus to subtraction.

80(8) - 120(4.0)

60 - 480 = 160 kg m/s to the right

An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s. The total momentum is 160 kg m/s.

Momentum is a fundamental concept in physics that describes the amount of motion an object has. It is defined as the product of an object's mass and its velocity. Mathematically, momentum (p) is given by:

p = m × v

where p is the momentum, m is the object's mass, and v is its velocity.

The units of momentum are kilogram-meters per second (kg m/s) in the SI system of units. The direction of momentum is the same as the direction of the object's velocity.

Momentum is a conserved quantity, meaning that the total momentum of an isolated system (a system that does not interact with its surroundings) remains constant. This is known as the law of conservation of momentum, and it has many practical applications in physics and engineering. For example, it can be used to analyze collisions between objects, such as in sports or automobile accidents.

Here in the Question,

To find the total momentum of the two players, we first need to calculate the individual momentum of each player, and then add them up.

The momentum (p) of an object is given by the product of its mass (m) and velocity (v):

p = m × v

For the first player with a mass of 80 kg and a velocity of 8 m/s, the momentum is:

p1 = 80 kg × 8 m/s = 640 kg m/s

For the second player with a mass of 120 kg and a velocity of -4.0 m/s (negative because he is traveling in the opposite direction), the momentum is:

p2 = 120 kg × (-4.0 m/s) = -480 kg m/s

The negative sign in front of the momentum for the second player indicates that his momentum is in the opposite direction of the first player.

To find the total momentum, we add the individual momenta:

total momentum = p1 + p2

= 640 kg m/s - 480 kg m/s

= 160 kg m/s

Therefore, the total momentum of the two players is 160 kg m/s.

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​

Answer:

Explanation:

For entropy change the formula is

ΔS = ΔQ / T

ΔQ = Δ H

ΔS = Δ H / T

Given

Δ H = + 162.8 kJ

We can take equilibrium temperature as average temperature of the whole process

So, T = 273 + 87 = 360 K

ΔS = Δ H / T

=  162.8 kJ  / 360

= +  0.508 kJ / K .

When the magnitude of the heat transfer for the process is 162.8 kJ, Then the entropy change for the mixing process, in kJ/K is = + 0.508 kJ / K

For The entropy change, the formula is

Then ΔS = ΔQ / T

After that ΔQ = Δ H

Then ΔS = Δ H / T

Given as per question are:

Then Δ H = + 162.8 kJ

Now We can take equilibrium temperature as average temperature of the whole process are:

So, T is = 273 + 87 = 360 K

Then ΔS = Δ H / T

After that = 162.8 kJ / 360

Therefore, = + 0.508 kJ / K.

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The coefficient of kinetic friction between the cars and the road is 0.648.

Let's first calculate the initial momentum of the system before the collision. The momentum is given by p = mv, where m is the mass and v is the velocity. Initially, the 2360 kg car is traveling at 10.9 m/s and the 2610 kg car is at rest, so the initial momentum of the system is:

p = (2360 kg)(10.9 m/s) + 0 = 25724 kg m/s

After the collision, the two cars stick together and move a distance of 4.39 m before friction causes them to stop. We can use the conservation of momentum to find their final velocity. Since the two cars stick together, their final velocity is the same:

25724 kg m/s = (2360 kg + 2610 kg) v

v = 6.08 m/s

The change in velocity is 10.9 m/s - 6.08 m/s = 4.82 m/s. The cars move 4.39 m before stopping, so we can use the equation of motion to find their acceleration:

v² = u²+ 2as

where u is the initial velocity, v is the final velocity, a is the acceleration, and s is the distance traveled.

Plugging in the values, we get:

0 = 4.82² + 2a(4.39)

a = -7.90

This is the acceleration due to the friction between the cars and the road. We can use this to find the force of friction:

F = ma = (2360 kg + 2610 kg)(-7.90) = -44780 N

The negative sign indicates that the force of friction is in the opposite direction of the motion.

The force of friction is also related to the normal force and the coefficient of kinetic friction by the equation F = μkN, where μk is the coefficient of kinetic friction and N is the normal force. The normal force is the force exerted by the road on the cars to support their weight. Since the cars are on a level surface, the normal force is equal to the weight of the cars:

N = (2360 kg + 2610 kg)(9.81) = 49090.8 N

Plugging in the values, we get:

-44780 N = μk(49090.8 N)

μk = -44780 N / 49090.8 N = 0.648

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Answer:

The thermal efficiency, \(\eta _{reheat}\), of the Rankine cycle with reheat is 36.81%

Explanation:

p₁ = 8 MPa = 80 Bars

T₁ = 450°C = 723.15 K

From steam tables, we have;

v₁ = 0.0381970 m³/kg

h₁ = 3273.23 kJ/kg

s₁ = 6.5577 kJ/(kg·K) = s₂

The p₂ = 0.8 MPa

T₂ = Saturation temperature at 0.8 MPa = 170.414°C = 443.564 K

h₂ = 2768.30 kJ/kg

\(T_{2'}\) = 400°C = 673.15 K

\(h_{2'}\) = at 400°C and 0.8 MPa = 3480.6 kJ/kg

p₃ = 10 kPa = 0.1 Bar

T₃ = Saturation temperature at 10 kPa = 45.805 °C = 318.955 K

h₃ = 2583.89 kJ/kg

h₄ = \(h_{3f}\) = 191.812 kJ/kg

The thermal efficiency, \(\eta _{reheat}\), of a Rankine cycle with reheat is given as follows;

\(\eta _{reheat} = \dfrac{\left (h_{1}-h_{2} \right )+\left (h_{2'}-h_{3} \right )-W_{p}}{h_{1}-\left (h_{4}+W_{p} \right )+\left (h_{2'}-h_{2} \right )}\)

Therefore, we have;

\(\eta _{reheat} = \dfrac{(3273.23 -2768.30 ) + (3480.6 -2583.89 ) - 8.04)}{(3273.23 -(191.812 + 8.04) + (3480.6 -2768.30 ) } = 0.3681\)

Which in percentage is 36.81%.

When the total mass of the system much larger then the measured accelerations would all be: halved.

In an Atwood's Machine, weight difference between the two hanging masses determines the net force acting on the system and this accelerates the hanging masses. Heavier mass is accelerated downward whereas the lighter mass is accelerated upward.

The second law states that the acceleration of an object depends on two variables that are: the net force acting on the object and the mass. The acceleration of an object depends directly on the net force acting on the object and inversely upon the mass.

F = m*a

Where, F denotes force, m is mass and a is acceleration. If force is doubled, acceleration also gets doubled whereas if the mass is doubled then acceleration becomes half.

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Answer:

I didn't write this I used caktus AI

Explanation:

The main heavenly bodies that make up the solar system are:

1. Sun - the star at the center of the solar system, around which all the planets orbit.

2. Planets - there are eight planets in the solar system in order from the Sun: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

3. Dwarf planets - smaller celestial bodies, similar to planets but not large enough to have cleared their orbital region of other debris. The solar system has five recognized dwarf planets: Ceres, Pluto, Haumea, Makemake, and Eris.

4. Moons - natural satellites that orbit planets and dwarf planets.

5. Asteroids - small, rocky bodies that orbit the Sun in the asteroid belt between Mars and Jupiter.

6. Comets - icy bodies that originate from the outer solar system and travel in long elliptical orbits around the Sun.

7. Kuiper Belt Objects (KBOs) - similar to asteroids, these small bodies are found beyond the orbit of Neptune in the Kuiper Belt.

8. Oort Cloud Objects - these are believed to be icy bodies located far beyond the Kuiper Belt in the outer reaches of the solar system.

Answer:  Yes, I can go and ask for them as needed

Explanation:

Answer:

A) Yes, I can go and ask for them as needed

Explanation:

Hope it help

Mark me as brainliest

golekeeper

Explanation:

because they use hand to save keeper

Answer:

True

Explanation:

the correct option is b. The large cube of concrete exerts a larger force on the small squishy ball.

It tends to be described as a connection that influences an article's movement on the off chance that there is no resistance. The straightforward meaning of force, then again, is the push or pull that any article gets. Force is a vector amount, consequently, it has a magnitude and a bearing.

Nonetheless, gravity is a force in a more broad sense since it represents the connection that happens when two masses are near each other. Gravitational effects are on a very basic level brought about by the extension of spacetime and the movement of things through the extended spacetime. The impact, by and by, is by all accounts the consequence of utilizing force.

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the complete question is:

1) A small squishy ball is thrown against the side of a large cube of concrete. While the objects are in contact with each other, which experiences the larger force? a. The small squishy ball exerts a larger force on the large cube of concrete b. The large cube of concrete exerts a larger force on the small squishy ball C. Neither object exerts a force on the other while they are in contact. d. The small squishy ball and the large cube of concrete exert equal force on each other.

Match the following volcanic hazards to their correct definition.

A) Lahars: Volcanic mudslide or debris flow Volcanic mudslide or debris flow

B) Pyroclastic Flow: Hot turbulent clouds of tephra that move at high speeds downhill

C) Tephra: Ash and large debris made of fragments and rock and magma blown from a volcano by gas expansion

D) Lava Flows: Flows of liquid magma that reach the surface, which can be fluid to viscous

A) Lahars: Volcanic mudslide or debris flow. Lahars are fast-moving mixtures of volcanic debris, water, and mud that occur when volcanic materials mix with water, such as from melted ice or heavy rainfall. They can travel down slopes, river valleys, and canyons, posing significant risks to nearby communities and infrastructure.

B) Pyroclastic Flow: Hot turbulent clouds of tephra that move at high speeds downhill. Pyroclastic flows are dense, fast-moving currents of hot gas, ash, and volcanic fragments that are expelled during explosive volcanic eruptions. They can reach speeds of hundreds of kilometers per hour and can be highly destructive, incinerating everything in their path.

C) Tephra: Ash and large debris made of fragments and rock and magma blown from a volcano by gas expansion. Tephra refers to the fragmented material that is ejected during volcanic eruptions. It includes various sizes of ash, lapilli (small rock fragments), and volcanic bombs (larger solidified lava fragments) that are propelled into the air and deposited around the volcanic vent.

D) Lava Flows: Flows of liquid magma that reach the surface, which can be fluid to viscous. Lava flows are streams or rivers of molten rock (magma) that emerge from a volcanic vent and move down the slopes of a volcano. The viscosity of the lava determines its behavior, ranging from fluid, fast-moving flows (such as basaltic lava) to slower-moving and more viscous flows (such as andesitic or rhyolitic lava).

These definitions help differentiate between the different volcanic hazards based on their characteristics and the materials involved. Understanding these hazards is crucial for assessing the risks associated with volcanic eruptions and implementing appropriate mitigation and preparedness measures to protect nearby communities and infrastructure.

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(a) The initial temperature is 373.95 K.

(b) The final temperature is 546.15 K.

(c) The total internal energy change of the fluid during this process is 515.4 kJ.

(d) The process can be represented as an isochoric heating process on the P-v diagram and as an isobaric expansion process on the T-v diagram.

(a) To find the initial temperature, we can use the saturated steam tables. At a pressure of 200 kPa, the corresponding saturation temperature is 373.95 K.

(b) Since the volume doubles, the process is an isochoric (constant volume) heating process. Using the ideal gas law, we can determine the final temperature. The initial and final volumes are related by the equation V_final = 2V_initial. Since the mass remains constant, the specific volume (v) is inversely proportional to the density (ρ). Therefore, ρ_final = ρ_initial/2. Using the ideal gas law, we can calculate the final temperature to be 546.15 K.

(c) The total internal energy change can be calculated using the equation ΔU = mC_vΔT, where m is the mass of the fluid and C_v is the specific heat at constant volume. Given the mass as 0.5 kg, the specific heat of water at constant volume, and the temperature change, we can find that the total internal energy change is 515.4 kJ.

(d) On the P-v diagram, the process is represented as a vertical line at 200 kPa, indicating constant pressure. On the T-v diagram, the process is shown as an upward-sloping line, indicating an isobaric expansion process. The initial state is represented as a point on the left, and the final state is represented as a point on the right. The path between the initial and final states is a straight line connecting these two points.

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Answer:

Harmful bacteria are called pathogenic

Explanation:

Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.

Answer:

a

 \(a = 21.7 \ m/s^2\)

b

\(F = 108.5 \ N\)  

Explanation:

From the question we told that

   The mass is  m  =  5 kg

    The initial speed \(u = 5 m/s\)

    The time taken to attain \(v = 70 \ m/s\) is  t =  3 s

Generally from kinematic equation we have that

     \(v = u + at\)

=> \(70 = 5 + a * 3\)

=>  \(a = 21.7 \ m/s^2\)

Generally  the force acting is mathematically represented

        \(F = m * a\)

=>      \(F = 5 * 21.7\)  

=>      \(F = 108.5 \ N\)  

When the switch closes, the obstacle between points P and Q is removed, allowing the flow of electricity to continue. This concept is known as completing the circuit.

The obstacle presented to the battery when the switch is open is bigger because the circuit is incomplete and no electricity is flowing. When the switch is closed, the obstacle is removed and the flow of electricity is able to continue. This concept is known as resistance. The closing of the switch will allow the flow of electricity sent by the battery to continue, as the circuit is completed. This concept is known as conductivity. When the switch is closed, the brightness of bulb B will increase compared to its brightness when the switch is open. This is because the flow of electricity is able to reach bulb B, completing the circuit and allowing it to light up. This concept is known as electrical energy. The brightness of bulb B when the switch is closed will depend on the amount of electrical energy being sent to it. If the flow of electricity is strong, bulb B may be brighter than bulb C. However, if the flow of electricity is weak, bulb C may be brighter than bulb B. This concept is known as power.

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For a planar surface, the direction of dip is always perpendicular (90 degrees) to the direction of strike.

In geology, the strike and dip are measurements used to describe the orientation of a planar rock surface, such as a bedding plane or fault. The strike represents the horizontal direction of the line formed by the intersection of the rock surface with a horizontal plane. The dip, on the other hand, represents the angle of inclination of the rock surface from the horizontal plane. In a planar surface, the dip is always perpendicular to the strike. This means that if the strike is in a particular direction, the dip will be at a right angle (90 degrees) to that direction.

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The correct statement regarding the work and impulse required to move a box on the floor from 2v to 3v and from 3v to 4v is Case i requires less work, but i and ii require the same amount of impulse.

W = ΔKE

W = Work done

ΔKE = Change in Kinetic energy

ΔKE = 1 / 2 m ( v2 - v1 )²

J = m Δv

J = Impulse

m = Mass

Δv = Change in velocity

For ( i ),

W = 1 / 2 m ( ( 3 v )² - ( 2 v )² )

W = 1 / 2 m ( 9 v² - 4 v² )

W = 2.5 m v²

J = m ( 3 v - 2 v )

J = m v

For ( ii ),

W = 1 / 2 m ( ( 4 v )² - ( 3 v )² )

W = 1 / 2 m ( 16 v² - 9 v² )

W = 3.5 m v²

J = m ( 4 v - 3 v )

J = m v

Therefore,

i ) W1 < W2

ii ) J1 = J2

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The pressure on the top face of the block is 14,000 N/m².

The pressure experienced by an object is force per unit area of the surface. The pressure experienced  by the object increases with increase in the applied force and decrease in surface area.

The pressure on the top face of the block is calculated as follows;

P = F/A

where;

P = (3.5 x 10³)/(0.25)

P = 14,000 N/m²

Thus, the pressure on the top face of the block is 14,000 N/m².

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The ash and dust block sunlight, causing cooling these factors likely would not cause an ice age.

An ice age is a long-lasting period of lowering of ground and atmospheric temperatures, resulting in the formation or expansion of continental and polar glaciers and alpine glaciers. The Earth's climate fluctuates between the Ice Age and the Greenhouse Age, when the planet has no glaciers. The Earth is currently in the Quaternary glaciation.[1] Individual pulses of cold climate during the Ice Age are called ice ages (or alternatively ice ages, ice ages, glacial phases, stadial, stadia, or colloquially ice ages), and intermittently warm Ice Age periods  are called interglacial or interstadials. An ice age of years suggests the existence of extensive ice sheets in both the northern and southern hemispheres.

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Answer:

fossil fuels

Explanation:

The assumption that does NOT apply to an ideal fluid is option D) The fluid is incompressible.

An ideal fluid is a concept used to simplify the mathematical modeling of fluid behavior. It assumes certain idealized properties to make the analysis easier. Among the given options, the assumption that an ideal fluid is incompressible is not applicable.

An incompressible fluid is one that does not change its density under applied pressure or stress. In reality, most fluids are compressible to some degree, meaning their density can change when subjected to pressure variations.

However, the assumption of incompressibility is often employed for practical purposes in fluid dynamics, especially when dealing with liquids or low-speed flows.

The other assumptions listed for an ideal fluid do apply. A) The assumption that velocity is equal at all points within a moving fluid is based on the principle of continuity, which states that the mass flow rate must remain constant along a streamline.

B) The assumption that fluid pressure is not influenced by fluid velocity is related to Bernoulli's principle, which states that as the fluid velocity increases, the pressure decreases.

C) The assumption that frictional forces between fluid molecules are negligible aligns with the concept of a frictionless fluid, where viscous effects are ignored.

While an ideal fluid assumes incompressibility, it should be noted that in certain situations, compressibility effects may become significant, such as at high speeds or in gases. Therefore, the assumption of an incompressible fluid is not universally applicable and must be carefully considered depending on the specific fluid and conditions being analyzed.

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Answer:

Acceleration

Explanation:

The choice from the given option which is not a force is acceleration.

Acceleration is defined as the rate of change of velocity of a body with time;

   Acceleration  = \(\frac{change in velocity}{time}\)  

Force is a pull or push on a body. The product of mass and acceleration is force.

Answer:

Explanation:

A i think :3

Answer:

a) 4

b) 5

c) 2s

d) 10 m/s

e) 5-10m/s^2

want to zøom?

Answer:

Aaaaw noooo. :(

Explanation:

what did they say to u and what state do u live in. I will help u stand up to them. I have taken down many bullies before by using words. in fourth grade, my friend was getting bullied by the class, then yelled and stood up for her. they all fell silent and never bullied her, or any of my friends again. For whatever reason they bully u is probably d.u.m.b. which means they r really d.u.m.b. Also, U should try finding out a lot of personal info about them that they dont want anyone to know. also tell the principal. Is ur mom nice, or mean? if shes nice, she'll support u and fight for u, which means u should address

Answer:

You should stick up for yourself because if you don't then no one else will but im always here to talk to you if you need someone

Explanation: