Calculate the ph of the solution resulting from the addition of 10. 0 ml of 0. 10 m naoh to 50. 0 ml of 0. 10 m hcn (ka = 4. 9 × 10–10) solution

Answer:

A

Explanation:

potassium because it has valance electrons by giving out proteins

Answer:

581 Joules.

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to the information provided in this question;

Q = ?

mass of ice = 15.9g

initial temperature = -4°C

final temperature = 14°C

Hence, ∆T = 14 - (-4) = 14 + 4 = 18°C

specific heat capacity (c) of ice in J/g°C = 2.03 J/g°C

Using Q = m × c × ∆T

Q = 15.9 × 2.03 × 18

Q = 32 × 18

Q = 581 Joules.

Answer:

\( \huge{6.295 \times {10}^{ - 20} \: J}\)

Explanation:

The energy of the photon can be found by using the formula

E = hf

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question we have

E = 6.626 × 10-³⁴ × 9.5 × 10¹³

We have the final answer as

\(6.295 \times {10}^{ - 20} \: J\)

Hope this helps you

The chemical formula for this compound is N₅ Cl₁₀ P₅

First, find out how many grams of each element are in 1 mole of the compound. We can do this because we have the molar mass of the compound and the mass percent of each element.

Now that we know the number of grams of each element per mole of the compound, we can use the molar mass of each element to find the number of moles of each element per mole of the compound.

Therefore, the chemical formula for this compound is N₅ Cl₁₀ P₅

We can double-check by making sure that the compound with this formula has the same molar mass as the one given in the problem

(5*14) + (35,45*10) + (31*5) = 70+354,5+155 = 579,5

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Answer:

Crudeoil is a mixture and it comprises of compounds mostly hydri carbons i think

Transition metals are different than alkali metals and alkaline earth metals because transition metals are more dense but much less reactive as compared to these metals.

As compared to transition metals, alkali, and alkaline earth metals are less dense because these metals of the first two groups are found to have higher atomic volumes. Therefore the transition metals have higher masses than their corresponding alkali metals as well as alkaline earth metals.

In addition to this, compared with the alkali metals in group 1 and the alkaline Earth metals in group 2, the transition metals are found to be much less reactive which is due to their high ionization potential and melting temperature.

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Answer:

The blue car left paint on the red car

Explanation:

Chemical reaction is the term which describes the conversion of substances into different substances.

Chemical reactions are defined as reactions which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical reaction.

There are several characteristics of chemical reactions like change in color, change in state , change in odor and change in composition . During chemical reaction there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical reactions:

1) inorganic reactions

2)organic reactions

3) biochemical reactions

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According to the given reaction, the number of moles of CuO that can be produced from 0.900 mole of Cu₂O and 0.800 mole of O₂ is 1.800 mol.

This can be calculated using the mole ratio of the reactants and products. The mole ratio is determined by the balanced chemical equation. In this case, the balanced equation is

2Cu₂O(s) + O₂(g) --> 4CuO(s).

Since the equation is balanced, there are equal numbers of atoms of each element on both sides. This means that the mole ratio of the reactants is equal to the mole ratio of the products, so 4 moles of CuO can be produced from 2 mol of Cu2O and 1 mol of O2.

The limiting reactant in the reaction will determine the maximum amount of CuO that can be produced.

To determine the limiting reactant, we need to calculate the amount of CuO that can be produced from each reactant.

Using the stoichiometry of the balanced equation, we can calculate the amount of CuO that can be produced from each reactant:

Cu₂O: 0.900 mol Cu₂O × (4 mol CuO / 2 mol Cu₂O) = 1.800 mol CuO

O₂: 0.800 mol O₂ × (4 mol CuO / 1 mol O₂) = 3.200 mol CuO

We can see that the amount of CuO that can be produced from Cu₂O is less than the amount that can be produced from O₂. This means that Cu₂O is the limiting reactant and the maximum amount of CuO that can be produced is 1.800 mol.

Therefore, 0.900 mol of Cu₂O reacted with 0.800 mole of O₂ can produce 1.800 mol of CuO.

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The amount of heat required to raise the temperature of 295g of ethanol by 87°C is 61,092 Joules.

The formula to calculate the amount of heat required to raise the temperature of a substance is:

Q = m * c * ΔT

where Q is the heat required (in Joules), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in J/g°C), and ΔT is the change in temperature (in °C).

Plugging in the given values, we get:

Q = 295 g * 2.4 J/g°C * 87°C

Q = 61,092 Joules

As a result, 61,092 Joules of heat are required to increase the temperature of 295g of ethanol by 87°C.

The specific heat capacity (c) of ethanol is given as 2.4 J/g°C, which means that it takes 2.4 Joules of heat energy to raise the temperature of 1 gram of ethanol by 1 degree Celsius. By multiplying the mass of ethanol (295g) with the specific heat capacity (2.4 J/g°C) and the change in temperature (87°C), we get the amount of heat required to raise the temperature of the given amount of ethanol by the given amount of temperature.

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a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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Answer:

#4: 0.89 mol/L #5: 0.36 mol

Explanation:

#4: Morality is Moles/ Liters

So take 3.2 mols ÷ 3.6 L = 0.8888... since there are 2 sig figs in the question the answer would round to 0.89 mol/L

#5: to find the number of moles needed, you take the mol/L and multiply that by the volume.

0.89 mol/L ×0.400L = 0.356 mols. the liters cancel out. Since 0.89 has the least number of sig figs your final answer should have 2. which it 0.36 mols.

I hope this helps, good luck!

The pH of the aqueous solution made by dissolving 50mg of H₂SO₄ and 60 mg of NaOH to a final volume of 500 ml at 25°C is  11.10.

Step 1: Convert the mass of H₂SO₄ and NaOH to moles.

Therefore, the number of moles of H₂SO₄ present in the solution = (50 mg)/(98.08 g/mol) = 0.00051 mol.

The number of moles of NaOH present in the solution = (60 mg)/(40.00 g/mol) = 0.0015 mol

Step 2: Use the number of moles of H₂SO₄ and NaOH to calculate the limiting reactant.The limiting reactant is the chemical that's present in the solution in the smallest amount. It is the chemical that will react completely with the other chemical. The limiting reactant will, therefore, determine the number of moles of any other chemical that will react completely and the products that will be formed. H₂SO₄ is the limiting reactant since it is present in a smaller amount.

Step 3: Calculate the number of moles of H⁺ ions that will be formed when H₂SO₄ reacts completely with water.

H₂SO₄ is an acid and will react with water to form H⁺ ions and HSO₄⁻ ions. HSO4⁻ ions will also react with water to form H⁺ ions and SO4²⁻ ions.

H₂SO₄ + H₂O ⟶ H⁺ + HSO₄⁻  HSO₄⁻ + H2O ⟶ H⁺ + HSO₄²⁻

The number of moles of H⁺ ions that will be formed from 0.00051 mol of H₂SO₄ is 0.00051 mol.

Step 4: Calculate the number of moles of OH⁻ ions that will be formed when NaOH reacts completely with water.NaOH is a base and will react with water to form OH⁻ ions and Na⁺ ions.NaOH + H2O ⟶ OH⁻ + Na⁺

The number of moles of OH⁻ ions that will be formed from 0.0015 mol of NaOH is 0.0015 mol.

Step 5: Calculate the concentration of H⁺ ions and OH⁻ ions in the solution.

The concentration of H⁺ ions in the solution = (number of moles of H⁺ ions)/(volume of solution)= (0.00051 mol)/(0.5 L) = 0.00102 M

The concentration of OH⁻ ions in the solution = (number of moles of OH⁻ ions)/(volume of solution)= (0.0015 mol)/(0.5 L) = 0.003 M

Step 6: Use the equation for the ion product of water to calculate the pH of the solution.

The ion product of water is given as follows: Kw = [H⁺][OH⁻] where Kw is the ion product of water (1.0 x 10-14 at 25°C).

Hence, [H⁺][OH⁻] = Kw = 1.0 x 10-14

If [H⁺][OH⁻] = 1.0 x 10-14, then [H⁺]/[OH⁻] = 1.0 x 10-14/[OH⁻] = [H3O⁺] and pH = -log[H3O⁺].

Therefore, pH = -log[H3O⁺] = -log(1.0 x 10-14/0.003) = 11.10

The pH of the aqueous solution is 11.10.

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The features of a standard hydrogen electrode are :

1. Temperature of 298 K (25°C)

2. Carbon electrode

3. Hydrogen gas at 1.01 x 10^5 Pa (1 atm) pressure

4. Electrolyte solution containing a hydrogen ion activity of 1 mol/L

5. Platinum wire as the current collector

6. A Potential of 0.00 V (relative to the hydrogen gas)

These features are what make up the Standard Hydrogen Electrode (SHE). The temperature of 298 K is the temperature at which the SHE is calibrated and is the standard temperature used in most laboratory experiments. The carbon electrode serves as the interface between the hydrogen gas and the electrolyte, and the hydrogen gas is held at 1.01 x 10^5 Pa (1 atm) pressure. The electrolyte solution contains a hydrogen ion activity of 1 mol/L, which is necessary for the electrode to function properly. A platinum wire is used as the current collector, and the electrode has a potential of 0.00 V, relative to the hydrogen gas. All of these features are necessary for the SHE to function properly and for the electrode to serve as the reference for all other electrochemical measurements.

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Answer:

the stem

Explanation:

yjsbsksvznzbfb

Answer:

WASSUP BRO

Explanation:

The gases can be converted into liquids by bringing its particles closer so atmospheric either by decreasing temperature or by increasing pressure

Answer:

The gases can be converted into liquids by bringing its particles closer so atmospheric gases can be liquefied either by decreasing temperature or by increasing pressure.

Explanation:

Answer:

Possible rapid deterioration of natural habitats where phytoplankton and seaweed exist.

Explanation:

Certain basic building blocks are needed for nautical environments to thrive. Assuming, in this context, without most of a certain type of oceanic species, the remaining habitats will suffer.

Answer:

\(\frac{227}{88} Ra ------> \frac{223}{86} Rn + \frac{4}{2} He\)

Explanation:

During an alpha decay, the mass number of the parent nucleus decreases by four units while the atomic number of the parent nucleus decreases by two units.

Hence the mass number of the daughter nucleus is four units less than that of the parent while the atomic number of the daughter nucleus is two units less than that of the parent.

Hence the alpha decay equation for 227/88 Ra is shown in the answer box.

1 gram of carbon = 12 atoms ..

As per u r question..

28.5 × 12 = 342..

Expression for boiling point elevation is ;

 Δ\(T_{b}\) = i × \(K_{b}\) × m

Where;

Δ\(T_{b}\) is Boiling point elevation

m is molality

i is ven't hoff factor

\(K_{b}\) is Boiling point elevation constant.

Boiling point depend upon number of ions present in electrolyte and concentration. so, ignore Boiling point elevation constant(\(K_{b}\) ) for finding boiling point.

(a).

Between NaOH and Glucose;

For Naoh; m = 0.25M

                 i  = 2

Thus, Δ\(T_{b}\)(NaOH) = m × i = 0.25 × 2 = 0.50

For Glucose; m = 0.25M

                       i = 1

Thus, Δ\(T_{b}\) (Glucose) = m × i = 0.25 × 1 = 0.25

So, Boiling point of  NaOH is Higher than Glucose.

(b).

Between NaCl and \(Cacl_{2}\);

For NaCl; m = 0.29M

                 i  = 2

Thus, Δ\(T_{b}\)(NaCl) = m × i =  0.29 × 2 = 0.58

For \(Cacl_{2}\); m = 0.24M

                i = 2.47

Thus, Δ\(T_{b}\) (\(Cacl_{2}\)) = m × i =0.24 × 2.47 = 0.59

So, Boiling point of \(Cacl_{2}\) is Higher than NaCl.

(c).

Between \(Na_{2} So_{4}\) and Glucose;

For \(Na_{2} So_{4}\); m = 0.61M

                 i  = 0.75

Thus, Δ\(T_{b}\)( \(Na_{2} So_{4}\)) = m × i =  0.61 × 0.75 = 0.4575

For \(Na_{3}Po_{4}\); m = 0.61M

                       i = 4

Thus, Δ\(T_{b}\) (\(Na_{3}Po_{4}\)) = m × i = 0.61 × 4 = 2.44

So, Boiling point of (\(Na_{3}Po_{4}\)) is Higher than \(Na_{2} So_{4}\) .

(d).

Between Glucose and Glucose;

For Naoh; m = 0.41M

                 i  = 1

Thus, Δ\(T_{b}\)(NaOH) = m × i =  0.41 × 1 = 0.41

For Glucose; m = 0.61M

                       i = 1

Thus, Δ\(T_{b}\) (Glucose) = m × i = 0.61 × 1 = 0.61

So, Boiling point of Glucose(0.61M) is Higher Glucose(0.41M)

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Answer:

Electromagnetism is the study of the electromagnetic force, one of the four fundamental forces of nature. It includes the electric force, which pushes all charged particles, and the magnetic force, which only pushes moving charges.It is used in many electrical appliances to generate desired magnetic fields. It is even used in a electric generator to produce magnetic fields for electromagnetic induction to occur.

Explanation:

tell me if this helped, ill try and explain better

Answer:

94.0 g.

Explanation:

Hello!

In this case, since the lay of conservation of mass states that energy cannot be neither created nor destroyed, during a chemical reaction it is seen that the reactions undergo a change by which bonds can be broken or formed depending on the case. Thus, for the formation of sodium chloride we evidence the formation of the Na-Cl bond which means sodium is combined with chlorine according to the following chemical reaction:

\(2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)\)

It means that the reuslting mass of product is:

\(m_{NaCl}=23.0+71.0g=94.0g\)

Best regards!

Answer:

halogen is the name of group 17 on the table of elements

Answer:

As the atomic number increases, the atoms get bigger. Their chemical properties change just a little bit when compared to the element right above them on the table.

Explanation:

yes

Answer:

Explanation:

Carbon cycle explains the movement of carbon between the earth's biosphere, geosphere, hydrosphere and atmosphere. ... Carbon atoms are then released as carbon dioxide when organisms respire. The formation of fossil fuels and sedimentary rocks contribute to the carbon cycle for very long periods.

The number of molecules of HI  that are needed to produce 72.54g of BaL2 is6.365 x 10^23.

To determine the number of molecules of HI needed to produce 72.54g of BaL2, we need to first find the moles of BaL2 and then use the balanced chemical equation to find the moles of HI.

First, we'll find the moles of BaL2:

72.54 g of BaL2 / 137.3 g/mol = 0.529 moles of BaL2

Next, we'll use the balanced chemical equation to find the moles of HI:

BaSO4 + 2HI -> BaL2 + H2SO4

From this equation, we can see that for every 2 moles of HI that react, 1 mole of BaL2 is produced. Therefore, to produce 0.529 moles of BaL2, we need 0.529 x 2 = 1.058 moles of HI.

Finally, we'll convert the moles of HI to the number of molecules:

1.058 moles of HI x 6.022 x 10^23 molecules/mole = 6.365 x 10^23 molecules of HI.

Therefore  the number of molecules of HI needed to produce 72.54g of BaL2 is approximately 6.365 x 10^23.

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1. To determine the number of moles of NaClO₃ required to produce 61 moles of O₂, we can use the stoichiometric ratio between NaClO₃ and O₂.

From the balanced chemical equation, we see that 2 moles of NaClO₃ produce 3 moles of O₂. Therefore, we can set up the following proportion:

2 moles NaClO₃ / 3 moles O₂ = x moles NaClO₃ / 61 moles O₂

Solving for x, we get:

x = (2/3) × (61 moles O₂) / (1 mole NaClO₃) ≈ 41 moles NaClO₃

Therefore, approximately 41 moles of NaClO₃ are needed to produce 61 moles of O₂.

2. From the balanced chemical equation, we see that 3 moles of Cu react with 8 moles of HNO₃ to produce 2 moles of NO. Therefore, we can set up the following proportion:

3 moles Cu / 8 moles HNO₃ = 2 moles NO / x moles HNO₃

Solving for x, we get:

x = (8/3) × (2 moles NO) / (1 mole Cu) ≈ 5.3 moles HNO₃

Therefore, 5.3 moles of HNO₃ are needed to produce 2 moles of NO. If 26 moles of HNO₃ are consumed, we can calculate the moles of NO produced using a proportion:

3. 5.3 moles HNO₃ / 2 moles NO = 26 moles HNO₃ / y moles NO

Solving for y, we get:

y = (2/5.3) × (26 moles HNO₃) / (1 mole NO) ≈ 9.8 moles NO

Therefore, approximately 9.8 moles of NO can be produced when 26 moles of HNO₃ are consumed.

4. From the balanced chemical equation, we see that 8 moles of HNO₃ react with 4 moles of H₂O. Therefore, we can set up the following proportion:

8 moles HNO₃ / 4 moles H₂O = 75 moles HNO₃ / x moles H₂O

Solving for x, we get:

x = (4/8) × (75 moles HNO₃) / (1 mole H2O) = 37.5 moles H₂O

Therefore, 37.5 moles of H₂O can be produced when 75 moles of HNO₃ are consumed.

5. From the balanced chemical equation, we see that 2 moles of NaClO₃ produce 3 moles of O₂. Therefore, we can set up the following proportion:

2 moles NaClO₃ / 3 moles O₂ = 9 moles NaClO₃ / x moles O₂

Solving for x, we get:

x = (3/2) × (9 moles NaClO₃) / (1 mole O₂) = 13.5 moles O₂

Therefore, approximately 14 moles of O₂ are produced when 9 moles of NaClO₃ are used.

6. The stoichiometric ratio between C and CH₄ from the balanced chemical equation is 1:1. This means that 1 mole of carbon is required to produce 1 mole of methane.

Therefore, we can use the following proportion:

1 mole C / 1 mole CH₄

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Answer: stepper mother is good for that

Explanation: