Calculate the error in the ammeter which reads 3.25 A in
acircuit having a series standard resistance of 0.01Ω, the
potential difference measured across this standard resistance being
0.035V.
Answer

Answers

Answer 1

To calculate the error in the ammeter we need to use Ohm's law.

According to Ohm's law V=IR where V is the potential difference, R is the Resistance and I is the current.

First, calculate the current using Ohm's law

i.e. I = V/R

I = (0.035)/0.01

I =3.5 amp

Now to check the error apply the percentage error

percentage error in current = ((calculated value - True value)/True value)*100

error in current =((3.5 - 3.25)/3.25) *100

error = (-0.25/3.25) *100

error = -7.14 %

Therefore the error in current is given by 7.14%

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Related Questions

The volume per second of a fluid flowing through a horizontal pipe of length l is given by kpa/n where k is constant, p is the excess pressure (force per unit area) a is the radius of the pipe and U is the frictional quantity of dimension MLT-1 by dimensions find the number x

Answers

According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:


  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:


  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:


  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:


  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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Types of Reactions Quick CheckIn a chemical reaction, substance A transfers electrons to substance B. Which statement is correct?(1 point)Substance A is oxidized and acts as the oxidizing agent.Substance B is oxidized and acts as the reducing agent.Substance B is reduced and acts as the oxidizing agent.Substance A is reduced and acts as the reducing agent.

Answers

Answer:

1. Which statement correctly describes the classification of chemical reactions into different categories?

-Not all reactions fit into a category, and some reactions can fit into more than one category.

2. In a synthesis reaction, two atoms of sodium (Na) combine with one molecule of chlorine gas (Cl2) to produce sodium chloride (NaCl). How many molecules of sodium chloride are produced?

-Two

3. In the decomposition of water, why is twice as much hydrogen as oxygen formed?

- There are two atoms of hydrogen and one atom of oxygen in a water molecule.

4. Which component is transferred between substances in an oxygen-reduction reaction?

-Electrons

5. In a chemical reaction, substance A transfers electrons to substance B. Which statement is correct?

-Substance B is reduced and acts as the oxidizing agent.

Hope that helps!!

Substance B is reduced and acts as the oxidizing agent.

REDOX REACTION:

A redox reaction is also called an oxidation-reduction reaction because it involves the transfer and receipt of electrons by compounds or molecules.

Oxidation-reduction reaction happens when the oxidation number of the ions involved in the reaction changes.

The substance that transfers or loses electrons in a redox reaction is called the REDUCING AGENT while the substance that gains or accepts electrons is called OXIDIZING AGENT.

The reducing agent becomes oxidized because it loses electrons while the oxidizing agent becomes reduced because it gains electrons.

Therefore, if substance A transfers electrons to substance B, the correct statement is that "Substance B is reduced and acts as the oxidizing agent".

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A boy starts jogging with a speed of 4.0 m/s and
reaches a speed of 5.0 m/s after covering a distance
of 9 m. What is the boy's acceleration?

Answers

Answer:

acceleration=0.111 m/s²

Explanation:

acceleration = change in velocity/time taken

1/9=0.1111

acceleration=0.111 m/s²

Please help me, I don’t quite understand it.

Please help me, I dont quite understand it.

Answers

The gravitatiοnal fοrce acting οn the ball is 29.4 N.

This is calculated by multiplying the mass οf the ball (3 kg) by the acceleratiοn οf gravity (9.8 m/s2).

F = m*a

F = 3 kg * 9.8 m/s2

F = 29.4 N

What is fοrce?

Fοrce is a push οr pull that can cause an οbject tο accelerate οr change its directiοn οf mοtiοn. It is a vectοr quantity, meaning it has bοth magnitude and directiοn. Fοrces can be caused by gravity, frictiοn, tensiοn, and οther fοrms οf interactiοn between οbjects.

What is weight?

Weight is the measure οf the gravitatiοnal fοrce acting οn an οbject. It is equal tο the mass οf an οbject multiplied by the acceleratiοn οf gravity. Weight is a measure οf the fοrce οf gravity acting upοn an οbject, and is measured in Newtοns (N).

The gravitatiοnal fοrce acting οn a 3 kg basketball mοving at 2 m/s tο the right is 29.4 N. This fοrce is the result οf the mass οf the ball multiplied by the acceleratiοn οf gravity.

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a magnet is moved through a coil of wire​

Answers

As long as the magnet is moving ...

... there is voltage between the ends of the wire in the coil, and

... if there is any kind of conductor between the ends, then there is current flowing through the coil.

A magnet and a coil of wire can be used to produce an electric current. A voltage is produced when a magnet moves into a coil of wire. This process is called electromagnetic induction .

wooden block has a mass of 0.2 kg, has a specific heat of 710 J/(kg°C), and is a temperature of 20.0°C.
What is the block’s final temperature if its thermal energy increases by 2130 J?

Answers

Answer:

The final temperature is 35 °C.

Explanation:

Given that,

Mass of the wooden block, m = 0.2 kg

The specific heat of the block, c = 710 J/(kg°C)

Initial temperature, \(T_i=20^{\circ} C\)

Thermal energy, Q = 2130 J

We need to find the block's final temperature. The thermal energy due to change in temperature is given by :

\(Q=mc(T_f-T_i)\\\\T_i\ \text{is initial temperature}\\\\\dfrac{Q}{mc}=(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{2130}{0.2\times 710 }+20\\\\T_f=35^{\circ} C\)

So, the final temperature is 35 °C.

Module 3 Discussion!
After reading Ch.12 and 13 of the text (The essentials of Finance and Accounting for nonfinancial managers/ Third Edition) on Strategy and Financial Forecasting, watching the SWOT video based on Paley’s Products from the Ratio Analysis in Module 2 and the additional narrative information in Appendix C, Phase
Create a SWOT analysis that will reflect the TOWS analysis as described in Ch. 12 of the text. The purpose of the SWOT analysis is to lay out several issues and possibilities to be considered in Paley’s strategic planning. The strengths and weaknesses are internal issues, whereas the opportunities and threats are external.
The second part of the analysis is to create actions based on the SWOTs. This is sometimes called a TOWS analysis and is done by comparing the boxes, two at a time:
Offensive actions come from strengths that link to opportunities, so a specific strength can be applied to exploit an opportunity.
Adjusting actions come from addressing weaknesses, which then can be used to exploit opportunities that previously had not been possible.
Turnaround actions come from weaknesses that link to threats. These are high-risk issues where a priority needs to be given to addressing the weakness to minimize the vulnerability.
Defensive actions come from threats that link to strengths. These are latent issues because if the threat materializes, an already-existing strength is available to counter it.
Additional actions can be included to address other issues not directly identified in the SWOTs.
3. From the actions identified in part 2, pick 3-5 strategic actions that you feel Paley must achieve or at least start in the upcoming year and state your reasons for including them.
Attach your completed SWOT form and list of strategic actions with supporting logic and facts from the case as your answer for this discussion question. These actions are the foundation for the strategic plan

Answers

SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-

They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.

Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.

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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.

If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?

Answers

The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

What is the sound's velocity?

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

Briefing:

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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A satellite is in circular orbit around a planet with a known radius. What information do you need to calculate the speed of the spacecraft? (check all that apply)

Answers

To calculate the speed of a satellite in circular orbit around a planet with a known radius is the radius of the planet and the mass of the planet.

What data is required to determine satellite speed around a planet?

The speed of a satellite in a circular orbit is determined by the gravitational pull of the planet it orbits. In this case, the radius of the planet is essential because it helps determine the distance between the satellite and the planet's center.

The mass of the planet is also crucial because it affects the strength of the gravitational force acting on the satellite. By combining these two pieces of information, you can calculate the speed of the satellite using the formula for centripetal acceleration, which relates the gravitational force to the satellite's speed and the radius of its orbit.

Calculating the speed of a satellite requires understanding the principles of gravitational force and circular motion. In a circular orbit, the gravitational force acting on the satellite provides the centripetal force needed to keep it moving in a curved path.

The magnitude of the centripetal force is determined by the mass of the planet and the distance between the satellite and the planet's center, which is equivalent to the sum of the planet's radius and the satellite's altitude above the planet's surface.

Using Newton's law of universal gravitation, which states that the gravitational force is proportional to the product of the masses and inversely proportional to the square of the distance between them, you can derive the formula for the speed of the satellite.

By equating the gravitational force to the centripetal force and solving for the satellite's speed, you can express it in terms of the radius of the planet and the mass of the planet.

This calculation assumes a circular orbit, neglecting any atmospheric drag or other external forces acting on the satellite. It also assumes that the mass of the satellite is insignificant compared to the mass of the planet.

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A student bangs a brick at the head of a table. Three students are positioned equal distance from the head with their hands on the table. What conclusion can be made about how they each will feel the vibrations?

Answers

Explanation:

that the people closer too the head of the table will feel more vibrations than the people at the end of the table. since the vibrations will slow down as they travel farther down the table

Hope this helps!!

Find the energy in electron volts for a particle with this wavelength if the particle is a photon.Express your answer in electron volts.

Answers

To find the energy of a photon with a given wavelength, you can use the equation E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength.

Without knowing the specific wavelength provided in the question, it's not possible to calculate the energy in electron volts. However, as an example, let's assume the wavelength provided is 500 nm (nanometers). Using the equation E = hc /λ, we can calculate the energy as:

E = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (500 x 10^-9 m)

E = 3.97 x 10^-19 J . To convert this energy to electron volts, we can use the conversion factor 1 eV = 1.602 x 10^-19 J:

E = (3.97 x 10^-19 J) / (1.602 x 10^-19 J/eV)

E = 2.48 eV

Therefore, a photon with a wavelength of 500 nm has an energy of 2.48 electron volts.

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A solid conducting sphere is given a positive charge Q. How is the charge Q distributed in or on the sphere?

(A) It is concentrated at the center of the sphere.
(B) It is uniformly distributed throughout the sphere.
(C) Its density decreases radially outward from the center.
(D) Its density increases radially outward from the center.
(E) It is uniformly distributed on the surface of the sphere only.

Answers

 The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)

When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".

According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.

Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.

Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.

Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.

Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.

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A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.

Answers

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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which term refers to a variable that is not allowed to change during an experiment​

Answers

Answer:

controlled variable

Explanation:

here you go

A control variable refers to a variable that is not allowed to change during an experiment​.

What is the control variable?

A control variable or scientific constant can be described as an experimental element that is constant and unchanged throughout the course of the investigation in scientific experimentation.

Control variables can strongly affect experimental results where they are not held constant during the experiment in order to test the relative relationship between the dependent and independent variables.

A variable is held constant in order to assess the relationship between multiple variables in an experiment and is a control variable. A control variable is not changed throughout an experiment because its constant state allows the relationship between the other variables. A control variable is what is kept constant throughout the entire experiment.

Therefore,  a variable that is not allowed to change during an experiment​ is a controlled variable or scientific constant.

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The initial concentration of acid ha in solution is 0.39 m. if the ph of the solution at equilibrium is 0.76, what is the percent ionization of the acid?

Answers

The percent ionization of the acid is 44.56%

How can we calculate the percent ionization of the acid?

To calculate the percent ionization of the acid we are using the formula,

The H⁺ ion concentration [H⁺] = C x,

where, we are given,

C= concentration of the acid.

=0.39 M

x= degree of dissociation of the acid.

And one more thing we are given that, the pH of the acid=0.76.

So from the above statement we can say that,

pH = - log [H⁺]

Or,0.76 = -log [H⁺]

Or, log [H⁺] = -0.76

Or, [H⁺] = antilog -0.76

Or,[H⁺]= 10^-0.76

Or,[H⁺]=0.1738.

Now from the above calculation we know, the H⁺ ion concentration= 0.1738 M.

Now we put the known values in the above equation,

[H+]= Cx

Or,0.1739= 0.39 x

Or, x= 0.4459

From the above calculation we can conclude that the percent Ionization of the acid= 0.4459 X 100= 44.59%≈45%

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draw the circuit schematic of a 3-bit r-2r ladder dac and write down the output analog voltage in terms of digital binary word input combined with a dc reference voltage.

Answers

All binary code used in computing systems is based on binary, which is a numbering system in which each digit can only have one of two potential values, either 0 or 1.

Thus, These systems employ this code to comprehend user input and operational instructions and to offer the user with an appropriate output.

Any digital encoding/decoding method with exactly two potential states is referred to as binary.

The digits 0 and 1 are commonly referred to as low and high, respectively, in digital data memory, storage, processing, and transmission. In transistors, a value of 1 denotes an electricity flow, whereas a value of 0 denotes no electricity flow.

Thus, All binary code used in computing systems is based on binary, which is a numbering system in which each digit can only have one of two potential values, either 0 or 1.

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A spacecraft is currently orbiting around the Earth, its position reported by optical mea- surements and its velocity reported via on-board IMU are the following: ri = 3Ro + 5 Roû = V1 = -3.2c + 2y + 2.52 km/s Determine a, e, i, N, w, r, v, y,0*, M, E, t - tp.
Edit for Anonymous Comment: if you knew orbital mechanics you would know what each represents. e is Eccentricity, E is eccentric anomaly, these are all orbital elements. I is inclination angle, argument of periapsis is lower omega, Theta star is true anomaly, etc. I don't think I need to give you what these variables mean if you know the topic.

Answers

These orbital elements can be calculated using standard methods in orbital mechanics.

How to calculate the various orbital elements for a spacecraft orbiting the Earth, using its position and velocity vectors?

To determine the orbital elements and other parameters of the spacecraft, we first need to convert its position and velocity vectors from Cartesian coordinates to Keplerian elements. We can do this using the following steps:

Calculate the specific angular momentum vector h:

h = ri x Vi

where ri and Vi are the position and velocity vectors, respectively, in Cartesian coordinates.

h = (3Ro + 5Ro) (-2.52c + 2y) - (-3.2c + 2y + 2.52 km/s) (5Ro)

h = 5.2 Ro c + 15.16 km/s y

Calculate the magnitude of the specific angular momentum:

| h | = sqrt(h^2)

| h | = sqrt[(5.2 Ro c)^2 + (15.16 km/s y)^2]

| h | = 15.94 km^2/s

Calculate the inclination angle i:

i = cos^-1(hz / | h |)

where hz is the z-component of the specific angular momentum vector.

hz = 15.16 km/s

i = cos^-1(15.16 km/s / 15.94 km^2/s)

i = 3.86°

Calculate the node vector N:

N = k x h / | k x h |

where k is the unit vector in the z-direction.

k = (0, 0, 1)

N = k x h / | k x h |

N = (-15.16 km/s, 5.2 Ro c, 0) / sqrt[(5.2 Ro c)^2 + (15.16 km/s)^2]

N = (-0.888, 0.306, 0)

Calculate the argument of periapsis w:

w = cos^-1(N · e / | N |)

where e is the eccentricity vector.

e = [1/μ ((V^2 - μ/| r |) r - (r · V) V)]

where μ is the gravitational parameter of the Earth, V is the velocity vector in Cartesian coordinates, and r is the position vector in Cartesian coordinates.

μ = 3.986004418 x 10^5 km^3/s^2

| r | = sqrt[(3Ro + 5Ro)^2] = 8Ro

V = (-3.2c + 2y + 2.52 km/s)

r = (3Ro + 5Ro)

e = [1/3.986004418 x 10^5 km^3/s^2 ((2.52 km/s)^2 - (3.986004418 x 10^5 km^3/s^2 / 8Ro)) (3Ro + 5Ro) - ((3Ro + 5Ro) · (-3.2c + 2y + 2.52 km/s)) (-3.2c + 2y + 2.52 km/s)]

e = (0.715, -0.439, 0)

w = cos^-1((N · e) / | N |)

w = cos^-1((-0.888 x 0.715) + (0.306 x -0.439))

w = 135.9°

Calculate the eccentricity magnitude e:

e = sqrt(e^2)

e = sqrt(0.715^2 + (-0.439)^2)e = 0.84

Calculate the semi-major axis a:

a = (2 / | r | - (V · V))^-1

a = (2 / 8Ro - (2

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What is 18 m/s north an example of?

Answers

Answer:

It is an example of velocity

Explanation:

It is an example of velocity Don't ask how I know because I do know it I just don't know how to explain it.

What would happen to objects and people if there was no gravity

Answers

They would float away!! And most likely go into orbit (plz mark Brainliest)

In a series-parallel circuit, you can find the total
resistance of the circuit by calculating the resistance of
each parallel section and then adding the series
resistances to these values to obtain a single
resistance. (This class is about cars )

Answers

If you know the total current and  voltage across the circuit, then you can find the total resistance using the Ohm's Law, that is : R = V / I.

How is resistance calculated in series-parallel circuit?

In a series-parallel circuit, one can find the total resistance of circuit by calculating resistance of each parallel section and then adding reciprocals of these values to obtain total resistance of parallel section. Next, you can add series resistances to this total resistance to obtain single resistance for entire circuit.

In series the total resistance is equal to the sum of the resistors. In parallel,  inverse of the total resistance is equal to the the sum of the inverse of each individual resistor.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: How is resistance calculated in a series-parallel circuit?

how can you separate salt from sand ​

Answers

dissolve salt in water then pour the liquid away from the sand and then evaporate the water to recover the salt

an atom with an overall negative charge is called?

Answers

Answer:

ANION is the answer

Calculate the gravitational force between two objects when they are 0.750m
apart. Each object has a mass of 5.00kg.

A- 2.23x10^-8N

B- 3.00x10^-6N

C- 2.22x10^9N

D- 2.96x10^-9N

Answers

I think maybe it’s A but I am not completely sure

The gravitational force of attraction between two objects is 2.964 x 10⁻9 N. So, the correct option is D.

What is meant by gravitational force ?

Gravitational force is defined as the force of attraction experienced by a body due to the gravity of earth.

Here,

Mass of each body,

m₁ = m₂ = 5 kg

Distance between the masses, r = 0.75 m

The equation for gravitational force is given by,

F = Gm₁m₂/r²

where G is the gravitational constant.

Therefore,

F = (6.67 x 10⁻¹¹x 5 x 5)/(0.75)²

F = 166.75 x 10⁻¹¹/0.5625

F = 2.964 x 10⁻9 N

Hence,

The gravitational force of attraction between two objects is 2.964 x 10⁻9 N.

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11. A car travels 500 miles at an average speed of 54. 9 mi/hr. How long will the trip take?

Answers

If an automobile drives 500 miles at an average speed of 54.9%, it will take 14.6 hours to finish the journey. The total distance that the thing has gone is its average speed.

divided by the entire amount of time it took to go the distance. The equation for average speed is: The difference between instantaneous and average speed.

The measurement of distance between two objects or points can be quantitative or occasionally qualitative. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over").

Time taken = distance travelled/ speed

Time taken = 500 miles/ 54.9minutes/hr

Time taken = 804.67 km/54.9minutes/hr

Time taken = 14.6 hours

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What would be the final velocity, in m/s, if a disk of the same mass and radius as the hoop rolled down the hill?.

Answers

The final velocity will be \(\rm V= \sqrt{\frac{4gh}{3} }\ m/sec\). Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

What is velocity?

The change of distance with respect to time is defined as speed.

From the law of conservation of energy:

\(\rm KE_i + PE_i = KE_f+PE_f \\\\ 0+mgh = \frac{1}{2} mV^2 +\frac{1}{2} I\omega^2\)

The moment of inertia of the disc;

\(\rm I= mr^2\)

It can also be found as;

\(\rm I = \frac{V}{r} \\\\\)

Put the obtained values;

\(mgh = \frac{1}{2} mv^2+\frac{1}{2} mv^2=mv^2\\\\ mgh = mv^2 \\\\ v=\sqrt{gh}\)

if a disk of the same mass and radius as the hoop rolled down the hill;

\(mgh= \frac{1}{2} M+\frac{mr^2}{2r^2} V^2 \\\\ gh = \frac{3}{4} V^2 \\\\ V= \sqrt{\frac{4gh}{3} }\ m/sec\)

Hence the final velocity will be \(\rm V= \sqrt{\frac{4gh}{3} }\ m/sec\).

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What is wave? What does a wave carry with it​

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A wave carries energy from a source to a point some distance away. A wave is reflected by a barrier. The reflected wave moves away from the barrier at an angle that is equal to the angle with which the incoming wave moved towards the barrier. When a wave is slowed down, it refracts—that is, changes direction.

Answer:

A wave carries energy

Explanation:

Which characteristics of an area could best identify the type of biome it is

Answers

Answer: average annual rainfall, average annual temperatures, types of plants and animals native to the area

Explanation: the best way you can identify a biome is by telling which animal or species are native to the certain area

Give reason: Acceleration is positive when its value increases​

Answers

Answer:

The acceleration of an object that is speeding up is always positive. The acceleration of an object that is slowing down is always negative. The airplane is speeding up as it goes down the runway. The final speed is greater than the initial speed.

Explanation:

Your roof radiates heat away at night. At what net rate does the heat radiate from a 275 m² black roof on a night when the roof temperature is 33°C in the surrounding temperature is 14°C? The emissivity of the roof is 0.900.

Answers

We are asked to determine the net rate of radiation of a roof given its area and its emisivity. To do that we will use the following formula:

\(P_{net}=\sigma eA(T_0^4-T^4)\)

Where:

\(\begin{gathered} P_{net}=\text{ net rate of radiation} \\ \sigma=\text{ Stefan-Boltzmann's constant} \\ e=\text{ emisivity} \\ A=\text{ area} \\ T_0=\text{ surrounding temperature} \\ T=\text{ temperature of the roof} \end{gathered}\)

The Stefan-Boltzmann's constant is given by:

\(\sigma=5.67\times10^{-8}\frac{W}{m^2K^4}\)

Now, we need to convert the temperature to Kelvin. To do that we use the following:

\(T_K=T_c+273.15\)

Where:

\(\begin{gathered} T_K=\text{ temperature in Kelvin} \\ T_C=\text{ temperature in Celsius} \end{gathered}\)

For the 33°C we have:

\(T_k(33)=33+273.15=306.15\)

For the 14°C:

\(T_K(14)=14+273.15=287.15\)

Now, we substitute the values:

\(P_{net}=(5.67\times10^{-8}\frac{W}{m^2K^4})(0.9)(275m^2)((287.15K)^4-(306.15K)^4)\)

Solving the operation:

\(P_{net}=-27870.84W\)

Therefore, the net rate of radiation is -27870.84 Watts.

Transcribed image text: Mech Tension 36 II. Blocks connected hy a very ight string The blocks in section 1 are mow coenected with s very light, flexible. and inextensible string of massm cM A If ithe motion of the blocks is the same as in section I, how does the net force on the string compare to the net force on the rope? 1. Determine whether the net force on ceach of the objects is greater less t equal to the net force on the object in section 1 Explain + block A . block B e the system composed of the blocks and the connecting rope or string Compare the horizontal components of the following pairs of forces . the force on the string by block A and the force on the rope by block A. Expl 2. , the force on the string by block B and the force on the rope by block B. Exp B. Suppose the mass of the string that connects blocks A and B becomes smaller and smule but the motion remains the same as in section I. What happens to , the magnitude of the net force on that connecting string? the magnitudes of the forces exerted on that connecting string by blocks A and B C. A string exerts a force on each of the two objects to which it is attached. For a string, the magnitude of both forces is often referred to as "the tension in the string Justify the use of this approach, in which a single value is assumed for the mag forces.

Answers

The net force on the string is equal to the net force on the rope.

How do net forces compare?

In this problem, we have two blocks connected by a light and inextensible string. We are asked to compare the net force on the string to the net force on the rope in section I, and to compare the horizontal components of the forces exerted by the blocks on the string and the rope.

We determine that the net force on the string is equal to the net force on the rope, and that the horizontal components of the forces exerted by the blocks on the string and the rope are also equal. We then justify the use of assuming a single value for the tension in the string, as the forces exerted by the string on the blocks are equal and opposite.

Finally, we conclude that the magnitude of the net force on the connecting string remains the same even if the mass of the string changes, as long as the motion of the blocks remains the same.

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