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1) For heat-based systems, there must be sufficient 1 point residual heat energy to activate the surfaces of the adjacent regions, causing cooling. True False 2) If an extrusion-based system is built

Given,

The initial speed, u=20.00 m/s

The distance between the submerine and the target is d=2000.0m

The sound of impact is heard after T=101.4 s.

To find

The speed of sound in water.

Explanation

Here the total time taken to reach the submarine is the sum of thetime taken by the torpedo to reach the target and the time taken for it to come back.

Let the speed be v.

Thus,

Conclusion

Speed of the sound in water is 1428.6 m/s

Answer:

7.34 meters

Explanation:

If the entire Kinetic energy is converted to Potential energy

1/2 mv^2 = mgh          didvide both sides by ' m '

1/2 v^2 = gh                 solve for 'h'

1/2 v^2 / g = h              plug in the given values  ,   g = 9.81 m/s^2

1/2 (12)^2 / 9.81 = h = 7.34 m

Answer:

78.2 km

Explanation:

km is greater unit than meter and 1 km has 1000m so divide 78200 by 1000 we get 78.2 km so answer would be 7.82 x 10^1

Answer:

Thermal Energy. Thermal energy is the internal energy of an object due to the kinetic energy of its atoms and/or molecules. The atoms and/or molecules of a hotter object have greater kinetic energy than those of a colder one, in the form of vibrational, rotational, or, in the case of a gas, translational motion.

Explanation:

Sputnik 1, the first man-made satellite, was released by the Eastern Bloc on October 4, 1957, as part of the Sputnik project, with Sergei Korolev serving as the program's primary designer.

There are a large number of satellite in use. They serve several functions, including the Satellite Navigation System, amateur radio, television transmission, and weather prediction. In order to conduct studies and acquire data, they also employ telescopes to gaze outwards at the solar system.

Natural and artificial satellite are two distinct categories. The Earth and the Moon are two examples of organic satellites. The Moon orbits the earth while the Earth revolves around the Sun.

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Answer:

the work done in raising the load is 24,750 J

Explanation:

Given;

load lifted by the crane with a force, F = 2750 N

height through which the load was raised, h = 9.0 m

The work done by the crane in raising the load is calculated as;

W =  F x h

W = 2750 x 9

W = 24,750 J

Therefore, the work done by the crane in raising the load is 24,750 J

The value of the inductance in this RLC series circuit is approximately 0.01336 H (or 13.36 mH).

To calculate the value of the inductance in an RLC series circuit with a given phase angle, capacitive reactance, and resistor, we can use the following formula:

tan(θ) = Xc / R

where:

- θ is the phase angle (given as 40.0°)

- Xc is the capacitive reactance (given as 40 Ω)

- R is the resistance (given as 100 Ω)

Let's substitute the given values into the formula and solve for Xc:

tan(40.0°) = 40 Ω / 100 Ω

Using a scientific calculator, we can find the value of tan(40.0°) to be approximately 0.8391.

0.8391 = 40 Ω / 100 Ω

Now, let's solve for the inductive reactance (XL):

XL = tan(40.0°) * R

  = 0.8391 * 100 Ω

  ≈ 83.91 Ω

Since the inductive reactance is given by the formula XL = 2πfL, where f is the frequency and L is the inductance, we can rearrange the formula to solve for L:

L = XL / (2πf)

Given that the frequency (f) is 1000 Hz, let's substitute the values and calculate the inductance (L):

L = 83.91 Ω / (2π * 1000 Hz)

 ≈ 0.01336 H

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The Doppler method can measure the eccentricity of orbit, semimajor axis of orbit, lower limit mass, and orbital period of exoplanets.

Eccentricity of orbit: The Doppler method can provide information about the eccentricity of a planet's orbit by detecting the periodic variations in the star's radial velocity caused by the planet's gravitational pull.

Semimajor axis of orbit: The Doppler method allows for the determination of the semimajor axis of a planet's orbit. By measuring the periodic changes in the star's radial velocity, scientists can infer the distance between the star and the planet, which corresponds to the semimajor axis.

Lower limit mass: The Doppler method can provide a lower limit estimate of a planet's mass. By observing the periodic variations in the star's radial velocity, scientists can calculate the minimum mass of the planet based on the gravitational influence it exerts on the star.

Orbital period: The Doppler method is particularly effective in determining the orbital period of a planet. By measuring the time it takes for the periodic changes in the star's radial velocity to repeat, scientists can accurately determine the planet's orbital period.

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Answer:

q = 0.384 C

Explanation:

The total charge present at the head can be easily found out by multiplying the charge on a single electron with the total number of electrons present on the head:

\(q = ne\)

where,

q = total charge on head = ?

n = total no. of electrons on the head = 2.4 x 10¹⁸

e = charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

\(q = (2.4\ x\ 10^{18})(1.6\ x\ 10^{-19}\ C)\)

q = 0.384 C

The chartjunk allows you to find unnecessary elements in the chart,

Understanding the exercise is easier with a graph. See attached

The graphical representation of a set of values ​​saves a lot of time in the data analyst, it is called chartjunk to all the unnecessary elements in a graph that do not help to understand the information represented or that are a distraction for the observer.

In the case presented we have a scatter plot with the x-axis the year of the computer and on the y-axis the number of units in millions, the graph shows two data sets the number of computers and the number of them with access to the internet depending on the year.

The lines in the horizontal grids are excessive represents chartjunk, since it does not help to understand the relationship between the data presented

Computer symbols are shown in the legend and the data to be plotted, this is important information, but in the graph at each point the values ​​are shown in a distracting element since it is in the table and is unnecessary, therefore it's a chartjunk

A missing piece of data in the graph is a connecting line between the total number of computers.

The chartjunk allows you to find unnecessary elements in the chart,

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Researchers have calculated that the possible maximum wave heights of nearly 100 m for episodic waves.

Although episodic waves 20 to 30 m high and moving at a speed of 50 knots have been recorded, researchers have calculated possible maximum wave heights of nearly 100 m (328 feet) for several reasons. According to research, rogue waves are expected to be more common in regions with strong currents, such as Agulhas Current, the Kuroshio Current, and the Gulf Stream. Rogue waves may happen more frequently when surface waves travelling in various directions combine and create a large wave with a small wavelength. These waves can be devastating to ships at sea and can easily cause damage or destruction.

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Answer:

As the temperature increases, the volume of the material also increases. This is known as thermal expansion. It can also be explained as the fractional change in the length or volume per unit change in the temperature.

The relation between alpha, beta, and gamma is given in the form of a ratio and the ratio is 1:2:3 and can be expressed as:

alpha=fracbeta2=fracgamma3

Following is the relation between the three:

L = L (1 + α.ΔT)

Where, α is the coefficient of linear expansion  

A = A (1 + β.ΔT)

Where, β is the coefficient of aerial expansion

V = V (1 + γ.ΔT)

Where, γ is the coefficient of cubical expansion  

V = V + γV.ΔT

V = V (1 + γ.ΔT)  

L3 = L3 (1 + α.ΔT)3

L3 = L3 (1 + 3α.ΔT + 3α2.ΔT2 + α3.ΔT3)

L3 = L3 (1 + 3α.ΔT)

Alpha, beta, and gamma are related to one another in the form of a ratio, and that ratio is 1:2:3, and yes they are universal constants.

A substance's volume expands while its mass stays constant. Heating is typically the cause of expansion. When a substance is heated, the molecular bonds separating its particles weaken, the particles move more quickly, and the substance expands as a result.

Determine the relation as shown below,

L = L (1 + α × Δ T)

here, α is the coefficient of linear expansion  

A = A (1 + β × Δ T)

here, β is the coefficient of aerial expansion

V = V (1 + γ × Δ T)

here, γ is the coefficient of cubical expansion  

V = V + γ × V × Δ T

V = V (1 + γ × ΔT)  

L3 = L3 (1 + α × Δ T)3

L3 = L3 (1 + 3α × ΔT + 3α2 × ΔT2 + α3 × ΔT3)

L3 = L3 (1 + 3α × Δ T)

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some massive black dwarfs may eventually produce supernova explosions. These will occur if pycnonuclear (density-based) fusion processes much of the star to iron, which would lower the Chandrasekhar limit for some black dwarfs below their actual mass.

The maximum height reached by the projectile, if the projectile is fired with an initial speed of 49.6 m/s at an angle of 42.2° above the horizontal on a long flat firing range is 54.4 meters.

To determine the maximum height reached by the projectile, we can analyze the projectile's motion and use the relevant kinematic equations.

The Initial speed (v₀) = 49.6 m/s and Launch angle (θ) = 42.2°

To find the maximum height, we need to consider the vertical motion of the projectile. The initial vertical velocity (v₀y) can be calculated as:

v₀y = v₀ * sin(θ)

Using the given values:

v₀y = 49.6 m/s * sin(42.2°)

v₀y = 32.344 m/s

Next, we can use the kinematic equation for vertical motion to find the time (t) it takes for the projectile to reach its maximum height:

v = v₀y - gt Where:

v = final vertical velocity (0 m/s at maximum height)

g = acceleration due to gravity (approximately 9.8 m/s²)

Rearranging the equation, we have:

t = v₀y / g

Substituting the values:

t = 32.344 m/s / 9.8 m/s²

t = 3.3 s

Since the projectile reaches its maximum height halfway through its total flight time, the time taken to reach the maximum height is t/2:

t/2 = 3.3 s / 2

t/2 = 1.65 s

To find the maximum height (h), we can use the kinematic equation for vertical motion:

h = v₀y * t/2 - (1/2) * g * (t/2)²

Substituting the values:

h = 32.344 m/s * 1.65 s - (1/2) * 9.8 m/s² * (1.65 s)²

h = 54.4 m

Therefore, the maximum height reached by the projectile is approximately 54.4 meters.

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Answer:

The law of conservation of energy

Explanation:

It states that energy can transform from one energy state to another but can not be created or destroyed.

The answer is : t  = 2.64 [s].

On the planet Koozebane, a pebble is dropped from height h and it falls to the surface in time t. The acceleration on the planet Koozebane is given as 3.100 m/s², and the height is given as 4.400 m.

We have to determine the time t.Therefore, we will use the following kinematic equation for freefall motion with no initial velocity:

h = ½ at² + vot

Where:v₀ = 0 m/st ,h = 4.400 m

(The height from which the pebble is dropped)

a = 3.100 m/s²

Substituting these values in the equation, we get

:4.400 = ½ (3.100) t²

After rearranging, we get:

t = √(2h/a)t

= √[2 × 4.400/3.100]t

= √[6.9677]t

= 2.64 s

Therefore, the time taken for the pebble to fall to the surface on the planet Koozebane is 2.64 s.

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(A) The individual receives an impulse from the ground because an impulse is equal to a change in momentum, and when a person jumps up from the ground, their momentum changes.

(b) The individual is affected by the floor, yes. When a force works over a distance, work is produced; in this instance, the floor pushes the person upward over a distance equal to the height of the leap.

(C) The equation p = mv, where m is the person's mass and v is their forward velocity, determines the momentum of the subject prior to jumping. The person's initial momentum was zero since they were at rest when they jumped.

The momentum of the person after they leave the floor is also given by p = mv, where m is the mass of the person and v is their velocity after jumping. We can use conservation of energy to find their velocity after jumping:

\(mgh = (1/2)mv^2\)

Here g is the acceleration due to gravity, h is the height that the person jumps, and the factor of 1/2 comes from the fact that the person starts from rest. Solving for v, we get:

v = \(\sqrt{(2gh)}\)

v = \(\sqrt{(2 * 9.8 * 0.149 m)}\) ≈ 1.94 m/s

So the momentum of the person after leaving the floor is:

p = mv = (60.0 kg)(1.94 m/s) ≈ 116.4 kg m/s

(d) No, it doesn't make sense to say that the momentum came from the floor. Momentum is always conserved, so the person's momentum after jumping must be equal to their momentum before jumping. In this case, the person's momentum before jumping was zero.

(e) The kinetic energy of the person after leaving the floor is given by:

KE = \((1/2)mv^2\), where m is the mass of the person and v is their velocity after jumping. Plugging in the given values, we get:

KE = \((1/2)(60.0 kg)(1.94 m/s)^2\) ≈ 354 J

(f) No, it doesn't make sense to say that the energy came from the floor. Energy is always conserved, so the person's kinetic energy after jumping must be equal to the work done on them by external forces. In this case, the only external force doing work on the person is gravity.

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The warmth from the water is flowing to the ice and melting it and The warmth from the burner is flowing to the cold water and increasing its temperature.

Convection, which is essentially the mass transfer of heat, is the process by which heat is moved from one place to another by the movement of fluids. The transport of heat into the atmosphere involves one of three processes: radiation, conduction, or convection.

Heat flow occurs when a hot object transmits its heat through a conductors to a cooler, similar to how high-energy objects impart their power to low-energy objects. How well a conductor transfers heat will impact how quickly and how much heat is transported.

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Two forces 10N and 6N acts on an object in same direction , then the net force will be:

16N .

So here net force : F= F1 + F2.

Here,

F1 = 6 N

F2 = 10 N

F = 6N + 10N

F = 16N

∴ Net force = 16N .

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True

In place of photographic plates or films, charge coupled devices, or CCDs, are sensitive photon detectors that can be employed in telescopes to create images. CCDs were created in the late 1960s and are now found in various devices, including digital cameras and photocopiers.

CCDs are more light-efficient, catch a greater proportion of incoming photons, can store and transfer digital data, and don't require development like film does. They respond linearly and capture up to 80% of the light that strikes them.

I understand the question you are looking for is this:

One of the primary advantages of CCDs over photographic plates is the former's high efficiency in detecting light. True or false.

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1) The length of the wire needs to be measured and varied (this is order to get a complete set of results for your experiment )2) Then go through each length of wire and measure the current and potential difference for each wire. (in order to calculate resistance later )3) repeat multiple times for each length of wire in order to create an average = sum/n (if need be explain difference between accuracy and precision).4)calculate resistance using equation resistance * current = Voltage for each length of wire

Hazards: Electric shock due to current , overheating wire can overheat , can be minimised by using low currents.

As the length of the nichrome wire will increase then the resistance in the wire will also increase and if the length of the nichrome wire will decrease then the resistance in the wire will also decrease because the resistance is directly proportional to the length of the wire.

A force that opposes the flow of current is electrical resistance, often known as resistance to electricity. It acts as a gauge for how challenging it is for current to flow in this fashion. Ohms (Ω), which represent resistance values, are used.

Electricity will move from high to low when an electron difference exists between two terminals. This flow is opposed by resistance. Lower currents occur at higher resistance levels. The opposite is also true: the current increases as the resistance decreases.

As the length of the wire increase then the resistance increases automatically similarly if the length is reduced the resistance will also get reduced because length is directly proportional to the resistance in the wire. One more thing is that if the resistance in the wire increase then the heating in the wire will also increase and vice versa because resistance in the wire is directly proportional to the heating effect in the wire.

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Force, Friction (static and kinetic), (balanced and unbalanced).

Materials - Tape, spring scales, measuring tape, string, wooden blocks, wooden blocks with sandpaper on the bottom, and different surfaces.

Procedure - 1. To test and gather information on surface friction, each group will look at four distinct surfaces (a concrete floor, a lab desk, a lab floor, and a carpet).

2. Each item should have a string firmly tied around it (a plain block of wood and the wood with sandpaper). Connect the string's looped end to the spring scale.

3. The 50 cm measuring line should be fastened to your surface. Your beginning point will be in the front, and your finishing point will be at the back.

4. Pull the unadorned wood block across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.

5. Pull the wood block with the sandpaper on it across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.

6. Step 5 must be repeated twice more. Put your findings in a table and on the class data spreadsheet.

REPEAT STEPS 1-6 FOR EACH SURFACE!

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To determine the earliest start and finish times, latest start and finish times, and slack for each activity, we can utilize the network diagram and use forward and backward pass calculation. We can determine the critical path by identifying the longest path in the network diagram where there is no slack. The project duration is the length of the critical path.

Here is the network diagram for the given project: \(\small{\text{(Please see the attached image for the network diagram.)}}\)The calculations for the earliest start and finish times, latest start and finish times, and slack for each activity are shown below:|Activity Duration (Months)|Predecessor|ES|EF|LS|LF|Slack|
|---|---|---|---|---|---|---|---|
|A|2|-|0|2|0|2|0|
|B|3|-|0|3|2|5|2|
|C|5|A|2|7|2|7|0|
|D|4|B|3|7|5|9|2|
|E|3|B|3|6|5|8|2|
|F|6|C, E|7|13|7|13|0|
|G|5|D, F|9|14|13|18|4|The critical path is A-C-F-G, and its length is 13 months.

This means that any delay on these activities will delay the project completion date. Here is the calculation of the critical path: A (2) - C (5) - F (6) - G (5) = 13 months.

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The number of mole of the gas present in the room given the data is 0.069 mole

The number of mole of the gas present in the room can be obtained by using the ideal gas equation as illustrated below

PV = nRT

n = PV / RT

n = (1 × 165) / ( 8.21 × 293)

n = 0.069 mole

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Answer:

6859 moles

Explanation:

n=(PV)/RT=(100000*165)/(8.21*293 Kelvin)=6859 moles

20 deg Celsius is 293 Kelvin

Answer:

In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.

Explanation:

Answer:

1 9 5 3 into law of inertia and 4 6 into law of acceleration and 2 7 8 into law of reaction

Law of Reaction: Cards 1, 3, and 9.

Law of Acceleration: Cards 2, 4, and 7

Law Of  Inertia:  Cards 5, 6, and 8

Answer:

5.0 because the ball is seeing big but the balls weight is 5.0