need done in matlab please.
Problem 1 Write a program that asks the user for a beginning number and an end number. Give in return an array starting at the beginning number, moving in steps of 3 , and ending at the end number.

The spring with the higher stiffness is Spring 1. To determine this, we can look at the amount of work required to compress each spring by a given amount.

Compressing Spring 1 by 0.20m requires 150J of work, while compressing Spring 2 by 0.30m requires 210J of work. Since more work is required to compress Spring 2 by a smaller amount than it is to compress Spring 1, we can infer that Spring 1 is stiffer than Spring 2.

Stiffness is the amount of force required to move the spring a certain distance. The higher the stiffness, the more force is required to move the spring. Since it takes more force to compress Spring 1 than it does to compress Spring 2, Spring 1 is stiffer.

We can also look at the amount of work required to stretch each spring by a given amount. Stretching Spring 1 by 0.20m requires 150J of work, while stretching Spring 2 by 0.30m requires 210J of work. Again, since more work is required to stretch Spring 2 by a smaller amount than it is to stretch Spring 1, we can infer that Spring 1 is stiffer than Spring 2.

To summarize, Spring 1 is stiffer than Spring 2 since it requires more work to compress and stretch it by a given amount. Compressing Spring 1 by 0.20m requires 150J of work, while compressing Spring 2 by 0.30m requires 210J of work. Stretching Spring 1 by 0.20m requires 150J of work, while stretching Spring 2 by 0.30m requires 210J of work.

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3.1 Two differences between distance and displacement are:

- Distance is a scalar quantity that refers to the total length traveled irrespective of direction, while displacement is a vector quantity that measures the change in position from the initial point to the final point, considering both distance and direction.

- Distance is always positive or zero, as it only considers the magnitude of the traveled path. Displacement can be positive, negative, or zero, depending on the direction of the movement relative to the reference point.

How to solve for the time

3.2 To determine the time it takes for ball B to reach the ground, we can use the equation of motion for free fall:

h = (1/2)gt²

Where:

h is the initial height (25 m)

g is the acceleration due to gravity (approximately 9.8 m/s^2)

t is the time

Rearranging the equation to solve for time:

t = √((2h)/g)

Substituting the given values:

t = √((2 * 25) / 9.8)

t ≈ 3.19 seconds

Therefore, it takes approximately 3.19 seconds for ball B to reach the ground.

3.3 To calculate the initial velocity of ball A, we can use the equation of motion for vertical projectile motion:

\(v^2 = u^2 - 2gs\)

Where:

v is the final velocity (which is zero as the ball reaches its maximum height)

u is the initial velocity (which we need to find)

g is the acceleration due to gravity (approximately 9.8 m/s^2)

s is the displacement (which is the change in height, -20 m)

Rearranging the equation to solve for initial velocity:

\(u^2 = v^2 + 2gs\)

u = √(v² + 2gs)

Substituting the given values:

u = √(0² + 2 * 9.8 * (-20))

u = √(0 + (-392))

u ≈ -19.80 m/s

Therefore, the initial velocity of ball A is approximately -19.80 m/s (negative sign indicates upward projection).

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Explanation:

Fnet = Ft - Ff = 60N - 20N = 40N

a = Fnet / m = 40N / 25kg = 1.6m/s².

Calculate resultant force:

R = ma

Descomposing:

F - Fr = ma

Replacing we have:

60 N - 20 N = 25 kg * a

Resolving:

40 N = 25 kg * a

40 N / 25 kg = a

1,6 m/s^2 = a

The aceleration is 1,6 meters per second squared.

Answer:

The gravitational potential energy is 2,750 Joules

Explanation:

Given the following data;

Mass of brick = 1kg

Height of Eiffel Tower = 275m

Potential energy can be defined as the energy possessed by an object due to its position.

Mathematically, potential energy is;

\( P = mgh\)

Also, we know acceleration due to gravity = 10m/s2

\( P = mgh\)

\( P = 1 * 275 * 10 \)

P = 2750 Joules.

Hence, the gravitational potential energy the brick acquired is 2750 Joules.

These speeds 4 s later is -20 m/s.

What is Acceleration due to Gravity?

The acceleration due to gravity would affect the radial component of an object at the surface of the earth. This would seem to us that the gravitational force acting on us on a vertical axis. This means that gravity would not affect any horizontal movement.

Determine the horizontal and vertical speeds, \($v_x$\) and \($v_y$\), of the baseball after t=4 seconds. We only recognize gravity as the force acting on the object, acting only on the vertical component. This means that the horizontal speed remains the same, such that

\($$v_x=16 \mathrm{~m} / \mathrm{s}$$\)

Now, we determine the vertical speed after the given time, t, by applying the kinematic equation,

\($$v_y=v_{0 y}-g t$$\)

where\($g=9.81 \mathrm{~m} / \mathrm{s}^2$\) is the acceleration due to gravity and t is the time. We proceed with the solution.

\($$\begin{aligned}v_y & =v_{0 y}-g t \\& =18 \mathrm{~m} / \mathrm{s}-\left(9.81 \mathrm{~m} / \mathrm{s}^2\right)(4 \mathrm{~s}) \\& \approx-20 . \mathrm{m} / \mathrm{s}\end{aligned}$$\)

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The suitcase is dragged for 2.10 meters before it is riding smoothly on the belt.

To calculate the distance the suitcase is dragged before it is riding smoothly on the belt, we can use the equations of motion and the coefficients of static and kinetic friction. The force of friction acting on the suitcase can be found by multiplying the coefficient of static friction by the weight of the suitcase (F_s = μ_s * m * g). The maximum force of static friction that can act on the suitcase before it starts moving can be found by multiplying the coefficient of static friction by the normal force (F_s ,max = μ_s * m * g). Since the force of gravity acting on the suitcase is balanced by the normal force, we can equate the maximum force of static friction with the force of gravity (F_ s, max = F_ g). Once the suitcase starts moving, the force of friction becomes kinetic and is given by F_ k = μ_k * m * g. Using the equations of motion and the given parameters, we can find that the distance the suitcase is dragged before it is riding smoothly on the belt is 2.10 meters.

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The barometer reading at the top of the mountain is  98,737.6 Pa.

The barometer reading at the top of the mountain is calculated as follows;

Atmospheric pressure at base = ρgh

= 1.25 kg/m³ x 9.81 m/s² x 0.74 m

= 9.1 Pa

Pressure due to mercury column at base;

= 13,600 kg/m³ x 9.81 m/s² x 0.74 m

= 98,727.8 Pa

Total pressure at base = Atmospheric pressure + Pressure due to mercury column

= 9.1 Pa + 98,727.8 Pa

= 98,736.8 Pa

The total pressure at the top of the mountain can be calculated as follows;

Total pressure at top = Pressure due to mercury column + ρgh

98,736.8 Pa  = 101,325 Pa   + 1.25 kg/m³ x 9.81 m/s² x h

98,736.8 Pa = 101,325 Pa  + 12.263h

12.263h = -2,588.2

h = -211 m

Barometer reading at top;

= 101,325 Pa + 1.25 kg/m³ x 9.81 m/s² x (-211 m)

= 98,737.6 Pa

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If you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85 mm focal length, the sensor is 1.087 m from the lens.

1 / f = 1 / v + 1 / u

f = Focal length

v = Image distance

u = Object distance

u = 3.9 m

f = 85 mm

f = 0.85 m

1 / v = 1 / f - 1 / u

1 / v = 1 / 0.85 - 1 / 3.9

1 / v = 3.05 / 3.315

v = 1.087 m

The sign convention for this formula is:

Therefore, the sensor is 1.087 m from the lens.

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The voltage is stepped up before being transmitted from a power station through overhead power lines to the consumer in order to reduce power loss and make the overhead power lines lighter, less expensive to build.

Here is the explanation why voltage is stepped up before being transmitted from a power station through overhead power lines to the consumer:

Power loss is inversely proportional to the square of the current. This means that if we can reduce the current, we can also reduce the power loss.

The current is inversely proportional to the voltage. This means that if we increase the voltage, we can reduce the current.

Therefore, by increasing the voltage, we can reduce the power loss.

In addition, the higher the voltage, the smaller the cross-sectional area of the conductors needed to transmit the same amount of power. This makes the overhead power lines lighter and less expensive to build.

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(i) The magnitudes of the electric fields they separately create at a radial distance of 6 cm is \(E_{a}\)=\(E_b}\). and (ii) The magnitudes of the electric fields they separately create at radius 4 cm is \(E_{a} =E_{b}\), so the correct option is option b.

A conductor refers to a material that allows an electric current to flow through it with ease. In other words, it has a low electrical resistance. Conductors are materials that have a high number of free electrons that are able to move freely through the material. Examples of conductors include copper, aluminum, gold, and silver. These materials are commonly used in the electrical industry to make wires and other electrical components that need to conduct electricity. In addition to materials, a conductor can also refer to a person or an organization that is responsible for directing or leading an orchestra or a choir. In this context, a conductor is in charge of maintaining the ensemble's rhythm and intonation, and interpreting the score in a way that brings out the music's emotional content and intended meaning.

(i) The magnitude of the electric field created by a charged conductor is given by the formula E = \(\frac{kq}{r}\), where k is the Coulomb constant, q is the charge, and r is the distance from the center of the sphere.

For a good conductor, like sphere A, the charge will be distributed evenly on the surface of the sphere. So, the electric field at a radial distance of 6cm will be Eₐ = \(\frac{kq}{r^{2} }\) = \(k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

For an insulator, like sphere B, the charge is distributed uniformly throughout its volume. The electric field at a radial distance of 6cm will be \(E_{b}\)=  \(\frac{kq}{r^{2} }=k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

As we can see, the magnitudes of the electric fields created by both spheres are equal, so the answer is (b) \(E_{a} =E_{b}\)

(ii) For the radius of 4cm, the electric field created by sphere A and sphere B will

\(E_{a} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\E_{b} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\\)

As we can see, the magnitudes of the electric fields created by both spheres are equal at a radius of 4cm, so the answer is (b) \(E_{a} =E_{b}\)

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When a green light illuminates a purple costume on a theatrical stage, the color of the costume will appear as a darker shade of green. This is due to the subtractive color model, which states that colors are created when light is reflected off of an object and absorbed by the object.

In this case, the purple costume is reflecting green light and absorbing all other colors, resulting in a darker shade of green. This effect is even more dramatic when the light is brighter, resulting in a nearly black color.

The color of a costume is also affected by the lighting equipment used, such as the color and power of the light. This means that the costume’s color can be changed based on the lighting used on the stage.

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The general solution to the differential equation is given as:

X = A1sin(ωt) + A2cos(ωt) + A3sinωt + A4cosωt

where A1, A2, A3 and A4 are constants determined by the initial conditions.

Let the vertical displacement of the load from its equilibrium position be X. The spring force acts upwards to balance the force due to gravity.In order to keep the load moving only vertically, the force acting on the load should also be vertically applied.

Thus, the force of the spring, Fspring is given as:

\(Fspring = -kX ... (1)\)

The force on the load due to gravity is given as:

\(Fgravity = mg ... (2)\)

The total force on the load is given by:

Ftotal = Fmotor + Fspring + Fgravity

where Fmotor is the force due to the motor.In the vertical direction, \(Ftotal = m(d^2x/dt^2)\) which leads to the following differential equation:

\(m(d^2x/dt^2) = Fmotor + Fspring + Fgravity\)

The force due to the motor is \(Fmotor = 8sinωt\)

X = displacement of the mass due to force Fmotor.

The differential equation then becomes:

\(m(d^2x/dt^2) = -kx + 8sinωt + mge^0\) ...(3)

To solve the differential equation above, substitute \(X = Asin(ωt + α)\)

where A is the amplitude of the oscillation, ω is the angular frequency, and α is the phase constant.

The first derivative of X is given as:\(dx/dt = Aωcos(ωt + α)\)

The second derivative of X is given as:\(d^2x/dt^2 = -Aω^2sin(ωt + α)\)

Substitute these expressions in equation (3) above:

m(-Aω^2sin(ωt + α)) = -k(Asin(ωt + α)) + 8sinωt + mge^0

Simplify the expression and group terms:\(mAω^2sin(ωt + α) + kAsin(ωt + α) = -8sinωt - mg\)

Differentiating X, we have: dx/dt = Aωcos(ωt + α)

Differentiating again, we have:\(d^2x/dt^2 = -Aω^2sin(ωt + α)\)

Substituting this into the differential equation gives the following expression:-\(mAω^2sin(ωt + α) - kAsin(ωt + α) = -8sinωt - mg\)

The solution for A is given as:\(A = (8/(-k + mω^2) * sinωt + mg/(-k + mω^2))\)

To get X, multiply A by sin(ωt + α) as follows:

X = (8/(-k + mω^2) * sinωt + mg/(-k + mω^2))sin(ωt + α)

The general solution to the differential equation is given as:

X = A1sin(ωt) + A2cos(ωt) + A3sinωt + A4cosωt

where A1, A2, A3 and A4 are constants determined by the initial conditions.

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the magnitude of the vertical electric field that will balance the  weight  of a plastic sphere of mass 2.1 g that has been charged to -3.0 nC is 2.26 x 10^3 N/C.\that has been charged to -3.0 nC is 2.26 x 10^3 N/C.Given values:

Mass of plastic sphere, m = 2.1 g = 0.0021 kg

Charge on plastic sphere, q = -3.0 nC = -3.0 x 10^-9 CThe force of gravity or weight acting on the sphere is given by the formula;Fg = mgwhere,

Fg = force due to gravity, m = mass of the object, g = acceleration due to gravityIf Fg is equal to the force due to the electric field, Fe, the plastic sphere will be in equilibrium.

Hence, the electric field needed to balance the weight of the plastic sphere can be calculated using the formula;Fe = Fg = mgHence,

we can write the following;Fe = mg= (0.0021 kg)(9.81 m/s²)= 2.0601 x 10^-2 NFe = (k*q)/(r²)

where k = Coulomb’s constant and r is the radius of the sphereFe = (9.0 × 10^9 N ∙ m²/C²)(-3.0 × 10^-9 C)/(r²)

To solve for the radius of the plastic sphere, we must first find its volume which is given by

;V = (4/3)πr³V = (4/3)π(0.001 r)³ = (4/3)π(1.0 × 10^-9 m³) = (4 × 3.14 × 10^-9 m³)/3 = 4.186 x 10^-9 m³

Now, we can calculate the radius of the sphere using the formula;Density of the plastic sphere,

ρ = m/V = (0.0021 kg)/(4.186 x 10^-9 m³) = 5.016 x 10^5 kg/m³

We can then find the radius, r of the sphere using the formula;m = ρV = (5.016 x 10^5 kg/m³)(4/3)πr³ = 2.105 x 10^-3 kg;

(given that the mass of the sphere, m = 2.1 g) => r = 4.05 x 10^-5 m

Substitute the value of r into the equation for the electric field to get the following;

Fe = (9.0 × 10^9 N ∙ m²/C²)(-3.0 × 10^-9 C)/(4.05 x 10^-5 m)² = 2.26 x 10^3 N/C

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Answer:

5

Explanation:

you would divide 150 by 30 and you get 5

The concentration of the solutions the nurse should mix in part (a) and the amount to be invested by the woman at each rate in (b), found by solving the simultaneous equations obtained from the parameters are;

(a) 20% : 7 cc

5% : 3 cc

(b) 2%: $74,000

12%: $68,000

An equation is a statement indicating that two mathematical expressions are equivalent by joining them with an '=' sign.

let x represent the volume of the 20% concentration solution, let y represent the volume of the 5% solution, we get;

x + y = 10...(1)

0.2·x + 0.05·y = 0.155 × 10 = 1.55...(2)

Equation (1) indicates; x = 10 - y

Therefore;

0.2·(10 - y) + 0.05·y = 1.55

2 - 0.15·y = 1.55

0.15·y = 2 - 1.55 = 0.45

y = 0.45/0.15 = 3

x = 10 - y

x = 10 - 3 = 7

Therefore; the nurse should mix 7 cc of the 20% solution and 3 cc of the 5% solution to obtain the 10 cc 15.5% solution

2. Let x represent the amount the woman invests at 2% per year, and y represent the amount the woman invests at 12% per year, we get the following simultaneous equations;

x + y = 142,000...(1)

0.02·x + 0.12·y = 9640...(2)

Therefore; y = 142,000 - x

0.02·x + 0.12·(142,000 - x) = 9640

17,040 - 0.1·x = 9640

0.1·x = 17,040 - 9640 = 7400

x = 7400/0.1 = 74,000

y = 142,000 - 74,000 = 68,000

The amount invested at 2% is; x = $74,00

The amount the woman invests at 12% is; $68,000

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Answer:

The brick wall has less mass compared to the soccer ball. With the ball you would have to use less force to make it go a certain distance. You would have to apply more force in the case of the brick wall to get it to go the same distance as the soccer ball.

Heavier things need more force and acceleration to move the same distance as lighter things because they have more mass.

Force by wall.

Take mass of wall as 120 kg and acceleration as 10m/s^2, Then the total force acting would be F = ma

120 * 10 = 1200 N

According to Newton's 3rd law of motion, Every action has an equal and opposite reaction. So, the force you apply on the wall is equivalent to the force the wall applies on you. Hence the wall applies a force of 1200 N on you which is why you get hurt.

Force by soccer ball.

The mass of a soccer ball is obviously lesser than the mass of a wall. Take mass of soccer ball as 0.5 kg and take the same acceleration as 10m/s.

F = ma, Hence

Force = 0.5 * 10 = 5 N

The force applied on the ball is much less compared to the force applied on the soccer wall that is just 5 N. Using the 3rd law of motion, we can prove that only a force of 5 N acts on us when we kick a ball. Hence it does not hurt.

Thus, proved.

Hope this helps.

Its simple if we check second law of Newton

\(\\ \rm\Rrightarrow F=ma\)

\(\\ \rm\Rrightarrow F\propto m\)

Wall has bigger mass so for force is required and hence more reaction force(Newton's third law)

Answer:

False

Explanation:

The force exerted by the electromagnetic radiation from the sun on the Earth is 6.05 ´ 1017 N.

The force exerted by the electromagnetic radiation from the sun on the Earth is equal to the intensity of the radiation multiplied by the area of the Earth's surface.

The intensity of the radiation is 1350 W/m2, and the area of the Earth's surface is 4πr2, where r is the radius of the Earth.

Substituting these values into the equation:

F = 1350 W/m2 × 4πr2 = 1350 W/m2 × 4π × (6.4 ´ 106 m)2 = 6.05 ´ 1017 N

Therefore, the force exerted by the electromagnetic radiation from the sun on the Earth is 6.05 ´ 1017 N.

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A star is considered circumpolar if it remains above the horizon throughout the entire night. The greatest distance that a star can be from Polaris, the North Star, and still be circumpolar is 50°.

Circumpolar stars are those that do not set below the horizon but instead appear to revolve around the celestial pole. In the northern hemisphere, Polaris serves as the North Star, located very close to the celestial north pole.

For a star to be circumpolar as seen from Philadelphia (latitude 40.0°), it must remain above the horizon at all times during the night.

The distance between Polaris and the celestial pole is equivalent to the observer's latitude. In this case, since the latitude of Philadelphia is 40.0°, any star within 40.0° of Polaris will be circumpolar.

Therefore, the greatest distance a star can be from Polaris and still be circumpolar is 40.0° + 10.0° (as the North Star is approximately 10.0° away from the celestial pole), giving a total of 50.0°.

Any star within this range, up to 50.0° from Polaris, will never dip below the horizon and will remain visible throughout the entire night as a circumpolar star.

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Ultimate tensile strength is the maximum stress that a material can withstand just before fracture.

Stress is defined as the force acting per unit area. It is denoted by Sigma(σ)

When a body is undergoing stretch by applying a pull force, it stretches more and more until it reaches its elastic limit. A point comes when the body no more stretches and breaks or fractures at bottle neck formation. This strength of any material is known as Ultimate breaking Stress or Ultimate tensile strength.

Thus, Ultimate tensile strength is the maximum stress that a material can withstand just before fracture.

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If you are holding a compass near earth's surface, and not too near the north geographic pole or south geographic pole,  the north magnetic pole of your compass needle point will point towards the south pole

We know that earth has its own magnetic field . The arrow of a compass can be thought to be the north pole of the magnetic needle. As we know unlike poles of a magnet attract each other, and arrow is thought to be north pole .

So it will attract towards south pole of the earth’s magnetic field, that is, approximately towards the geographical north pole. Hence, it can be said that the arrow of the compass is  north-seeking pole.

This is why generally a compass always points to the north.

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Answer:

More energy is transferred in situation A

Explanation:

Each of the situations are analyzed as follows;

Situation A

The temperature of the cup of hot chocolate = 40 °C

The temperature of the interior of the freezer in which the chocolate is placed = -20 °C

We note that at 0°C, the water in the chocolate freezes

The energy transferred by the chocolate to the freezer before freezing is given approximately as follows;

E₁ = m×c₁×ΔT₁

Where;

m = The mass of the chocolate

c₁ = The specific heat capacity of water = 4.184 kJ/(kg·K)

ΔT₁ = The change in temperature from 40 °C to 0°C

Therefore, we have;

E₁ = m×4.184×(40 - 0) = 167.360·m kJ

The heat the coffee gives to turn to ice is given as follows;

E₂ = m·\(H_f\)

Where;

\(H_f\) = The latent heat of fusion = 334 kJ/kg

∴ E₂ = m × 334 kJ/kg = 334·m kJ

The heat required to cool the frozen ice to -20 °C is given as follows;

E₃ = m·c₂·ΔT₂

Where;

c₂ = The specific heat capacity of ice = 2.108 kJ/(kg·K)

Therefore, we have;

E₃ = m × 2.108 ×(0 - (-20)) = 42.16

E₃ = 42.16·m kJ/(kg·K)

The total heat transferred = (167.360 + 334 + 42.16)·m kJ/(kg·K) = 543.52·m kJ/(kg·K)

Situation B

The temperature of the cup of hot chocolate = 90 °C

The temperature of the room in which the chocolate is placed = 25 °C

The heat transferred by the hot cup of coffee, E, is given as follows;

E = m×4.184×(90 - 25) = 271.96

∴ E = 271.96 kJ/(kg·K)

Therefore, the total heat transferred in situation A is approximately twice the heat transferred in situation B and is therefore more than the heat transferred in situation B

Energy transferred in situation A = 543.52 kJ/(kg·K)

Energy transferred in situation B = 271.96 kJ/(kg·K)

Energy transferred in situation A ≈ 2 × Energy transferred in situation B

∴ Energy transferred in situation A > Energy transferred in situation B.

pascal is the unit of pressure

The units of pressure is called derived units because it is simply derived from base unit which is distance and a derived unit which is force, which is derived from acceleration, a derived unit as well, and mass, a base unit. As we all know, work is defined as the force x distance. Thus making work a derived unit.Jun 23, 2020

Work done in moving the body horizontally is 300 J.

Work done by an object is defined as the dot product of the force and displacement of the object.

Here,

Displacement of the body, s = 20 m

Force applied on the body, F = 30 N

Angle made with the horizontal, θ = 60°

Work done in moving the body,

W = Fs cosθ

W = 30 x 20 x cos60

W = 600/2

W = 300 J

Hence,

Work done in moving the body horizontally is 300 J.

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Water boils at exactly 100°C (212°F) at normal atmospheric pressure. This is known as the boiling point of water, and it is the temperature at which water transitions from a liquid to a gas (steam) at normal atmospheric pressure. The boiling point of a substance is the temperature at which the vapor pressure of the liquid is equal to the atmospheric pressure, and for water, this occurs at 100°C. The boiling point of water can vary depending on factors such as the altitude and the atmospheric pressure, but at sea level and at normal atmospheric pressure, water boils at exactly 100°C.

48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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Answer:

B. One group of fabric is treated with the chemical, and the other group is not. Then each group is exposed to water.

Explanation:

Answer:

c. may be accompanied by the sound of explosively expanding hot air, called thunder.

Explanation:

Lightning is a discharge which is due to the reaction between oppositely charged charges in the clouds, or between clouds base and the Earth surface.

The motion of the cloud causes charging of clouds by friction, thus the reaction between opposite charges (jumping of charges from one cloud to another) in the cloud can lead to lightning. Also, oftentimes the bottom of a cloud is negatively charged so that this is attracted to the positive charge on the earth surface. Thus leading to a discharge called lightning.

Thus in the given question, the appropriate option is C. This implies that, lightning may be accompanied by the sound of explosively expanding hot air, called thunder.

The length of the spring when a 1.75 kg block is hung would be 16.5 cm.

To solve this problem, we can use Hooke's law, which states that the force exerted by a spring is proportional to the spring's deformation.

First, we can calculate the spring constant (k) using the formula:

k = (F / x)

Where F is the force exerted by the block and x is the deformation of the spring (the difference in length between the compressed and unloaded states).

In the first case, the 2 kg block causes a deformation of 3 cm in the spring (18 cm - 15 cm). We can calculate k by dividing the weight of the block (2 kg) by the deformation (3 cm).

With the value of k known, we can calculate the length of the spring when the 1.75 kg block is hung. We use the same formula:

x = (F / k)

This time, the force exerted by the 1.75 kg block is calculated as the product of its mass (1.75 kg) and gravity (9.8 m/s²).

By substituting the values into the formula, we find that the length of the spring would be 16.5 cm when the 1.75 kg block is hung.

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