How many moles of carbon atoms do you have if you have 48.4 g of carbon?

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Clofibrate is a lipid-lowering pharmaceutical that has been utilized to treat hyperlipidemia. Its metabolism system includes different pathways such as hydrolysis, oxidation, conjugation, and others.

Metabolites are little molecules that are produced during the process of  metabolism in living living beings.

Clofibrate hydrolysis metabolite:

Clofibrate oxidation metabolites:

Clofibrate alkylation metabolites:

Clofibrate conjugation metabolites:

Conclusively, the relative abundance and significance of each metabolite can vary among individuals.

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The number of mole of oxygen needed is of 0.080 mole.

To solve this question, we'll begin by writing the balanced equation for the reaction. This is illustrated below:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of O₂ needed to produce 0.080 mole of H₂O. This can be obtained as follow:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Therefore,

0.080 mole of O₂ will also react to produce 0.080 mole of H₂O.

Thus, 0.080 mole of oxygen, O₂, is needed for the reaction.

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Mescaline produces a wide range of psychoactive effects when ingested, including altered perception of reality, hallucinations, and euphoria. It is a powerful psychedelic drug that has been used for centuries by Native American tribes in spiritual ceremonies

Mescaline is a hallucinogenic alkaloid that is derived from the Peyote cactus. Mescaline is a complex organic molecule that can be synthesized in the laboratory from 3,4,5-trimethoxybenzyl bromide in two steps.The first step involves nucleophilic substitution using sodium cyanide, and the second step is a reduction using lithium aluminum hydride (LAH).Here's how mescaline can be synthesized from 3,4,5-trimethoxybenzyl bromide:Step 1: Nucleophilic substitution using sodium cyanideThe reaction of 3,4,5-trimethoxybenzyl bromide with sodium cyanide results in the formation of the nitrile derivative. NaCN serves as the nucleophile in this reaction, and it replaces the bromide ion.The mechanism for this reaction involves the following steps: A nucleophilic attack by the cyanide ion on the benzyl bromide. The carbon-bromine bond breaks, and the benzyl cation is formed. A second nucleophilic attack by the cyanide ion occurs on the benzyl cation, resulting in the formation of the nitrile derivative.Here's the reaction equation for this step:Step 2: Reduction using lithium aluminum hydrideThe next step is the reduction of the nitrile derivative using LAH. LAH serves as a strong reducing agent in this reaction and reduces the nitrile derivative to the amine. The mechanism for this reaction involves the following steps: A nucleophilic attack by LAH on the nitrile derivative. This results in the formation of an imine intermediate. The imine intermediate reacts with another LAH molecule, resulting in the formation of the amine.Here's the reaction equation for this step:Mescaline structure: Mescaline is a psychoactive compound that belongs to the phenethylamine class of alkaloids. The structure of mescaline is as follows: The molecule has three methoxy groups attached to the benzene ring, and it has an amine functional group. The molecule is a white crystalline powder that is soluble in water and alcohol.

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Answer: d. Arrangement of grains

Explanation:

Edge:)))

Answer:

3,4,5,6,7,8

Explanation:

Groups 13  - 18 are the main group on the periodic table

The group number corresponds the number of valence electrons they contains.

Valence electrons are the number of electrons in the outermost shell of an atom.

So group 13 - 18 corresponds to a valency of 3,4,5,6,7,8.

Groups with a valency of 8 are the noble gases.

Answer:

Explanation:

The resistance can be found by using the equation for Ohms law which is

V is the voltage

I is the current

R is the resistance

\(r = \frac{v}{i} \\ \)

We have

\(r = \frac{6}{2} = 3 \\ \)

We have the final answer as

Hope this helps you

Dissolve 60g of potassium bromide in 340g of water to produce 15% (mass/mass) aqueous solution of potassium bromide.

Here we have to prepare a total of 400 g of solution. Aqueous solution means the solvent we use here is water.

So to prepare 400 g of 15% aqueous solution of potassium bromide, we need to find out how many grams of potassium bromide need to be dissolved in water and how many grams of water must be used.

Here the weight percent is given, that is 15%

       15/100 = weight of potassium bromide/ 400 g

       0 .15      = weight of potassium bromide / 400

      weight of potassium bromide needed = 0.15 × 400

                                                                       =  60 g

So, we calculated the required amount of potassium bromide as 60 grams. The total weight of the solution to be made is 400 grams.

So amount of water required = 400 - 60

                                                =  340 g

So we need to mix 60 grams of potassium bromide in 340 grams of water to get a 15% (mass/mass) aqueous solution.

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Both changing particle size and adding a catalyst can influence the reaction rate, while adding heat specifically affects the rate by increasing the kinetic energy of the reactant particles.

The correct option are A and C.

Both changing particle size and adding a catalyst can alter the reaction rate.

Changing particle size can affect the reaction rate because it influences the surface area available for the reactant particles to interact. Smaller particle sizes result in a larger surface area, increasing the frequency of collisions between particles and accelerating the reaction. Conversely, larger particle sizes reduce the surface area, leading to fewer collision events and slower reaction rates.

Adding heat can also alter the reaction rate. Increasing the temperature provides more thermal energy to the reactant particles, causing them to move faster and collide with greater energy. This enhanced kinetic energy leads to more successful collisions and an increased reaction rate.

Adding a catalyst can significantly affect the reaction rate. A catalyst provides an alternative reaction pathway with lower activation energy, enabling the reaction to occur more easily. By lowering the energy barrier, a catalyst increases the rate of reaction without being consumed or permanently altered in the process.

The correct option are A and C.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

Potassium, sulfur, fluorine, barium

The elements that will lose one electron are:

a. sodium

d. Potassium

An element in its natural state has an equal number of protons and electrons, giving it a net charge of zero; however, when an element loses an electron as part of a chemical reaction it becomes positively charged, or oxidized.

Out of the given options, sodium and potassium looses one electron and attains a positive charge leading to the formation of cation. While Fluorine and chlorine gains one electron and attains a negative charge leading to the formation of anion.

Thus, correct options are a and d.

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Gas legislation

PV = nRT

where P is atmospheric pressure

Volume (measured in litres)

The number of moles is n.

R = gas constant (0.0821 L atm/(mol K))

Temperature (in Kelvin) equals T.

We need to rearrange the ideal gas law to solve for n:

n = PV / RT

To use this equation, we need to know the pressure, temperature, and volume of the carbon dioxide.

0.002355 moles of carbon dioxide are equal to 235.5 litres of the petrol. As a result, 0.002355 moles of carbon dioxide are equivalent to 0.053 litres.

This is because 1 mole of carbon dioxide is equal to 22.4 litres. This indicates that there are 0.002355 moles of carbon dioxide for every 0.053 litres of carbon dioxide.

Therefore, there are 0.002355 moles of carbon dioxide in 235.5 litres of carbon dioxide.

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Since gas molecules average velocity depends on temperature, oxygen molecules at 25°C are moving faster than oxygen molecules at 0 °C.

According to the kinetic theory of gases, the molecules of a gas are in constant random motion and collide frequently with each other and the walls of the container.

The average speed of gas molecules depends on temperature and molar mass as shown by the relation;

vrms = √3RT/M

The following statement are true among the options provided;

The following are false among the options provided;

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Answer:

the sun i think because the sun has the greatest gravitational pull

Answer:

a. Rate = k [H2O+-OH][Br-]

Explanation:

For a reaction:

nA+xB→C+D

The rate of the reaction is:

Rate = [A]ⁿ[B]ˣ

Now, in a mechanism, the rate of the reaction depends of the slow step. In the problem:

H2O+-OH + Br-→ HOBr + H2O

And the rate is:

The correct definition of vapor is: "B. A substance that is in the gas phase at a temperature at which it would normally be a solid or liquid."

A vapor is a substance that exists as a gas at a temperature that is typically associated with solids or liquids.

Unlike gases, which can exist at a wide range of temperatures, vapors specifically refer to substances that have transitioned into the gas phase despite their expected solid or liquid state under normal conditions.

This transition usually occurs due to increased temperature, causing the substance to evaporate or sublimate.

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The concept of molarity is used here to determine the concentration of hydroxide ions. The pH of the solution can be obtained from the pOH of the solution. The pH is 13.02.

The pH of a solution is defined as the negative logarithm of hydronium ion concentration in moles per litre. The pOH of the solution expresses the concentration of hydroxide ions.

pH = -log [H₃O⁺]

378 mg = 0.378 g

90 mL =  0.09 L

Number of moles = 0.378 / 40 = 0.0094 moles

[OH⁻] = 0.0094 / 0.09 = 0.105 M

pOH = -log [OH⁻]

= -log [ 0.105]

= 0.978

pH = 14 - pOH

= 14 - 0.978

= 13.02

Thus the pH of the solution is 13.02.

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386°C

The ideal gas law allows us to solve for different values of a gas.

Ideal Gas Law

In order to do ideal gas calculations, we make the assumption that gas behaves ideally. This means that gases move in completely straight lines, have perfectly elastic collisions, experience no IMFs (intermolecular forces), and have no volume. When we assume these characteristics, we get the equation:

In this equation, P is pressure, V is volume, n is moles, R is the gas constant, and T is temperature. It is important to note that temperature is always given in Kelvin for the ideal gas law.

Solving For T

To solve for T, all we need to do is plug in the values we were given. The question states:

Now we just need to solve for T. For clarity, I will leave units out of this calculation.

This means the temperature is about 658.82 Kelvin. Rounded for sig figs, this is 659K. However, the question asks for Celsius. So, we need to convert. To convert from Kelvin to Celsius, subtract 273.

The gas is at 386°C.

Polysaccharides are healthier for the body than mono- or disaccharides are as glucagon is a type of polysaccharide found in animal tissues and is usually found in small amounts in meat from poultry and diet.

The Importance of Monosaccharides and Polysaccharides Both are essential as the primary food and dietary energy sources for all living organisms. Cell-wall polysaccharides make up the fibers that humans eat, and monosaccharides add sweetness to food.

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Answer:

Three

Explanation:

Significant figures:

The given measurement have three significant figures 2,0,5.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

Answer:

Ionic bonds

Explanation:

It rymes.  haha i dont even know how to spell it! ;)

As combustion always result into the formation of water, the other type of reactions that may result into formation of water are Acid-Base Neutralization Reactions and Hydrogen and Oxygen Reaction.

Acid-Base Neutralization Reactions:

A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products.

H⁺ ions and OH⁻ ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction.

Example: Formation of Sodium Chloride (Common Salt):

HCl + NaOH → NaCl + H₂O

Hydrogen and Oxygen Reaction:

Water vapour is created when hydrogen gas (H₂) and oxygen gas (O₂) are combined directly. This reaction produces a lot of heat and releases a lot of energy.

Example: 2 H₂ + O₂ → 2 H₂O

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Answer:

A.) Thermal

Explanation:

I got it correct on founders edtell

According to Charles' law, when the temperature of an ideal gas increases by three-fold at pressure (P), the volume of the gas also triples.

Charles law states that the volume of a given gas is directly proportional to the temperature provided that the pressure remains constant.

This is denoted by the following expression:

This means that as the volume increases, the temperature of the gas also increases and vice versa.

Therefore, when the temperature of an ideal gas increases by three-fold at pressure (P), the volume of the gas also triples.

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The chemical reaction between hydrochloric acid (HCl) and magnesium hydroxide (Mg(OH)2) is:

HCl + Mg(OH)2 → MgCl2 + 2H2O

where MgCl2 is magnesium chloride and H2O is water.

Neutralization reaction is a type of chemical reaction in which an acid reacts with a base to form a salt and water. The pH of the resulting solution is neutral, which is pH 7. Examples of common neutralization reactions include the reaction between hydrochloric acid and sodium hydroxide, which produces sodium chloride and water:

HCl + NaOH → NaCl + H2O

A chemical reaction is a process that involves the transformation of one or more substances into different substances with different properties. Chemical reactions involve the breaking and formation of chemical bonds between atoms, ions or molecules, resulting in the formation of new products.

Chemical reactions can be classified into different types based on their characteristics, such as the types of reactants involved, the direction of the reaction, and the energy changes that occur during the reaction.

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Answer:

melting and vaporization

Explanation:

Answer: 3.32060434 × 10^-23

Explanation: Divide the number of atoms (20) by 6.023 x 10^23 (Avogadro’s number) to get the number of moles.

Chemistry 11 Solutions

978Ͳ0Ͳ07Ͳ105107Ͳ1Chapter 8 Solutions and Their Properties • MHR | 85

Amount in moles, n, of the NaCl(s):

NaCl

2.5 g

m

n

M

58.44 g

2

4.2778 10 m l

ol

o

/m

u

Molar concentration, c, of the NaCl(aq):

–2 4.2778 × 10 mol

0.100

0.42778 mol/L

0.43 mol

L

/L

n

c

V

The molar concentration of the saline solution is 0.43 mol/L.

Check Your Solution

The units are correct and the answer correctly shows two significant digits. The

dilution of the original concentrated solution is correct and the change to mol/L

seems reasonable.

Section 8.4 Preparing Solutions in the Laboratory

Solutions for Practice Problems

Student Edition page 386

51. Practice Problem (page 386)

Suppose that you are given a stock solution of 1.50 mol/L ammonium sulfate,

(NH4)2SO4(aq).

What volume of the stock solution do you need to use to prepare each of the

following solutions?

a. 50.0 mL of 1.00 mol/L (NH4)2SO4(aq)

b. 2 × 102 mL of 0.800 mol/L (NH4)2SO4(aq)

c. 250 mL of 0.300 mol/L NH4

+

(aq)

What Is Required?

You need to calculate the initial volume, V1, of (NH4)2SO4(aq) stock solution

needed to prepare each given dilute solution.

The dilution gives the relationship between the molarity and the volume of the solution. The volume of stock solution with a molarity of 1.50 mol/L is 50 mL.

Dilution is said to be the addition of more volume to the concentrated solution to make it less in molar concentration. This tells about the inverse and indirect relationship between the volume and the molar concentration of the solution.

Given,

Initial volume = V₁

Initial molar concentration (M₁) = 1.50 mol/L

Final volume (V₂) = 125 mL = 0.125 L

Final molar concentration (M₂)= 0.60 mol/L

The dilution is calculated as:

M₁V₁ = M₂V₂

V₁ = M₂V₂ ÷ M₁

Substituting the values in the above formula as

V₁ = M₂V₂ ÷ M₁

V₁ = (0.60 mol/L × 0.125 L) ÷ 1.50 mol/ L

V₁ = 0.05 L

= 50 mL

Therefore, 50 mL of stock solution is needed to make a 0.60 mol/L solution.

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