An object travels at a velocity of 30 centimeters per
nanosecond. [cm/ns]. Convert this rate into units of meters per
second [m/s]. Express the answer in scientific notation

The current in the second diode is 400mA

Data;

The current in the first diode is equal to 400mA. In a series circuit, the current passing the diodes are equal. This implies that the current in the series are equal.

Diodes connected in series will be the equal.

\(I_1 = I_2\)

Since I1 is 400mA, I2 will be equal to 400mA

\(I_1 = I_2\\I_1 = 400mA\\I_2 = 400mA\)

The current in the second diode is 400mA

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Answer:

its called a fault

Explanation:

Its when u mess up

The attraction between two objects at a distance is the Gravitational force.

An attraction force that exists between all mass-bearing objects is the gravitational force. A massed object draws another massed object; The force's magnitude is inversely proportional to the square of the distance between the two objects and directly proportional to their masses.

Mathematically it can be written as

F = G × m₁m₂/d²

m₁ and m₂ are the masses of the objects in kilograms, and d is the distance between them in meters. G is the universal gravitational constant, which means that it is the same everywhere in the universe.

And G = 6.67 x 10⁻¹¹ N m² / kg²

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(Complete question)

What is the attraction between two objects at a distance?

Answer:

The magnification of the lens is 21

Explanation:

Please see full answer in the attached image since the system kept on refusing to accept my typed answer complaining of bad use of words or presence of a link.

The magnification of the lens is m = 21

Answer:

its 21 for Acellus

Explanation:

The total power radiated by the sun is equal to 3.93*10^26 watts.

Here, we have been told that the mean distance between the earth and the sun is = 1.50*19^11 m (i)

The average intensity of solar radiation incident on the upper atmosphere of the earth is = 1390 w/m² (ii)

The intensity of radiation emitted from a source in all directions at a distance r can be found by dividing the total energy emitted per second or power P by the surface area of a sphere of radius r. So, the intensity of radiation at a given point. Using the values of (i), (ii), we get -

= I = P/4π²

= P = 4π*(1.5*10¹¹)²*1390

= P = 3.93*10²⁶

Hence, we have found out that the power radiated by the sun is going to be 3.93*10²⁶ watts.

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If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.

To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.

The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:

ds/dt = d/dt(2t + t²)

ds/dt = 2 + 2t

Now we can set the velocity function equal to 24 m/s and solve for t:

2 + 2t = 24

Subtracting 2 from both sides:

2t = 22

Dividing both sides by 2:

t = 11

Therefore, it takes 11 seconds for the velocity to reach 24 m/s.

The correct answer is (d) 11 seconds.

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Answer:

The balanced chemical equation is 1SnO2 + 2H2 --> 1Sn + 2H2O.

Explanation:

The equation is now balanced because both sides have an equal number of reactants and products.

There is 1 Sn on each side, 2 O on each side, and 4 H on each side.

Answer:

B

Explanation:

Gravitational Energy is the energy of position or place. A rock resting at the top of a hill contains gravitational Potential energy. Hydropower, such as water in a reservoir behind a dam, is an example of gravitational potential energy.

Answer:

.b

Explanation:

Answer:

A) Availability

Explanation:

Right on Edge 2021

Answer:

Availability

Explanation:

edge

Answer:

The correct answer is: Energy is conserved, and it cannot be created or destroyed. This is known as the law of conservation of energy, which states that in a closed system, the total amount of energy remains constant and cannot be created or destroyed, only transformed from one form to another. This means that energy can be converted from one form to another, such as from potential energy to kinetic energy, but the total amount of energy in the system remains the same.

Given data

*The ball is thrown straight upwards at a speed is u = 20 m/s

*The value of the acceleration due to gravity is g = 9.8 m/s^2

*The value of the final velocity of the ball at maximum height is v = 0 m/s

The formula for the time taken by the ball to lose its speed is given by the equation of motion as

Substitute the known values in the above expression as

The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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Answer: 5. On the Moon.

Explanation: Weight is a measure of the force of gravity acting on an object.  The weight of an object depends on the mass of the object and the strength of the gravitational force at a particular location.

On Earth, the weight of an object is determined by the mass of the object and the strength of Earth's gravitational force. At the equator, the weight of an object is slightly less compared to the poles due to the centrifugal force caused by the Earth's rotation. This force counteracts a small portion of the gravitational force, resulting in a slightly lower weight.

At the North and South poles, the weight of an object is slightly higher compared to the equator due to the shape of the Earth. The Earth is not a perfect sphere but slightly flattened at the poles, which causes objects at the poles to be closer to the center of the Earth and experience a slightly stronger gravitational force.

However, on the Moon, the weight of an object is significantly less compared to Earth.  The Moon has a much smaller mass and weaker gravitational force than Earth, resulting in objects weighing less on the lunar surface.

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Answer:

1800J

Explanation:

Step one:

given data

mass of bullet m= 3g= 0.03kg

initial velocity u = 400m/s

final velocity v= 200 m/s

Step two:

1.The bullet's lost kinetic energy went inside the tree.

2. The energy transferred is computed as

= initial KE- KE final

Initial KE= 1/2mu^2

Initial KE= 1/2*0.03*400^2

Initial KE= 1/2*0.03*160000

Initial KE= 1/2*4800

Initial KE= 2400J

KE final= 1/2mv^2

KE final= 1/2*0.03*200^2

KE final= 1/2*0.03*40000

KE final= 1/2*1200

KE final= 600J

KE transferred = 2400-600

KE transferred= 1800J

Answer:

Seahawks

Explanation:

THEY ARE THE BEST TEAM!!!

Answer:

seahawks

Explanation:

yes they r gud

Answer:

5 seconds

Explanation:

25 x 5 = 125

Acceleration due to gravity, commonly referred to as "g," is the acceleration experienced by an object as it falls towards the Earth due to the Earth's gravitational pull. The formula for calculating g is:

g = G * (M / r^2)

Where:

G is the gravitational constant (approximately 6.67 x 10^-11 N*(m/kg)^2)

M is the mass of the Earth (approximately 5.97 x 10^24 kg)

r is the distance from the center of the Earth to the point where the acceleration is being measured (measured in meters)

The gravitational constant (G) is a fundamental constant of nature that relates the force of gravity between two objects to their masses and the distance between them. The mass of the Earth (M) is known, so the only variable in this equation is the distance (r) from the center of the Earth to the point where the acceleration is being measured. This distance is equal to the radius of the Earth plus the altitude at that point.

Keep in mind that g is not constant, it varies depending on the distance from the center of the Earth. It is greater at the Earth's surface than it is at higher altitudes, and it is greater at the poles than it is at the equator.

It's important to note that this is an approximation and there are other factors like rotation, rotation of the earth, and other physical phenomena that can have an effect on the gravity and its value.

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W = ∫[F(x)dx] from 2.0 m to 7.0 m = ∫[3x^n dx] from 2.0 m to 7.0 m

To solve this problem, we need to use the conservation of energy principle. The potential energy of the particle at x=2.0 m is zero, so its total energy is equal to its kinetic energy at that point:

E = (1/2)mv^2

where m is the mass of the particle and v is its speed.

At x=7.0 m, the potential energy of the particle is given by:

U(x) = ∫f(x)dx = ∫3x dx = (3/2)x^2

Therefore, the total energy of the particle at x=7.0 m is:

E' = (1/2)mv'^2 + (3/2)x^2

where v' is the speed of the particle at x=7.0 m.

Since energy is conserved, we can set E = E' and solve for v':

(1/2)mv^2 = (1/2)mv'^2 + (3/2)x^2

Simplifying this equation, we get:

v'^2 = v^2 + (3/m)(x^2 - 2^2)

Plugging in the given values, we get:

v'^2 = (6.0 m/s)^2 + (3/2.0 kg)((7.0 m)^2 - (2.0 m)^2)

v'^2 = 188.5 m^2/s^2

Taking the square root of both sides, we get:

v' = 13.7 m/s

Therefore, the speed of the particle at x=7.0 m is 13.7 m/s.
To determine the speed of a 2.0 kg particle at x = 7.0 m, we'll need to find the work done by the force F(x) = 3x^n and use the work-energy theorem. The work-energy theorem states that the work done on an object is equal to its change in kinetic energy: W = ΔK.E. = K.E._final - K.E._initial.

First, let's find the initial kinetic energy at x = 2.0 m:
K.E._initial = (1/2)mv^2 = (1/2)(2.0 kg)(6.0 m/s)^2 = 36 J

Now, let's calculate the work done by the force F(x) as the particle moves from x = 2.0 m to x = 7.0 m. For that, we need to integrate F(x) with respect to x:

W = ∫[F(x)dx] from 2.0 m to 7.0 m = ∫[3x^n dx] from 2.0 m to 7.0 m

Without knowing the value of n, we cannot proceed with this integration. Once you have the value of n, you can integrate and find the work done (W), which will allow you to determine the final kinetic energy and the speed of the particle at x = 7.0 m.

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The value of moment of Inertia of the solid cylinder will be 0.19 kg/m^2

Any item that can be rotated has the property of rotational inertia. It is a scalar value that indicates how challenging it is to alter an object's rotational velocity around a certain rotational axis. The role of mass in linear mechanics is analogous to that of rotational inertia in rotational mechanics.

The formula I = 1/2 [M (R_2^2 + R_1^2)] may be used to calculate the moment of inertia of a hollow cylinder revolving along an axis passing through the centre of the cylinder. The cylinder in this instance will have a mass of M and internal and exterior radii R1 and R2, respectively.

The cylinder's moment of inertia about its axis is (MR^2)/2.

Where, M - mass of object, R = radius of the cylinder.

After putting all the values. we will get,

\(=\frac{27 \mathrm{~kg} \cdot(0.24 \mathrm{~m} / 2)^2}{2} \approx 0.19 \mathrm{~kg} \cdot \mathrm{m}^2\)

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Answer:

Self demagnetization means when magnets' poles are free (suspended) for too long, their magnetic attraction becomes weaker and thus, self demagnetizes.

The orbit of the binary pulsar PSR 1936+16 studied by Taylor and Hulse is B. It is growing smaller, presumably by emitting gravitational waves.

This phenomenon is known as "orbital decay" and is one of the key predictions of Einstein's theory of General Relativity. As the pulsar and its companion orbit each other, they emit gravitational waves that carry energy away from the system, causing the orbit to shrink over time. This effect has been observed in many other binary pulsars as well.
The other options listed in the question are not correct. The orbit of PSR 1936+16 is not so small that the orbital period is smaller than the pulsar period (option A). There is no evidence that the pulsar is being orbited by at least 6 planets the size of Jupiter (option C).

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The vertical component of velocity shortly before the stone reaches the ground equals the original vertical velocity ie, v m/s

The vertical component of an object's velocity right before impact can be computed using equations of motion. If we examine a gravity-affected item with a beginning velocity (v0) and no air resistance, its vertical velocity (v) may be given by the equation:

v = v0 - gt

where g is the gravitational acceleration (9.8 m/s2) and t is the time since the item was launched.

To calculate the vertical component of velocity immediately before the stone reaches the ground, we must first compute the time t required for the stone to reach the ground. The following equation may be used to compute this:

t = (v0 - v) / g

By reintroducing the value of t into the first equation, we obtain:

v = v0 - gt = v0 - g((v0 - v) / g) = v0 - (v0 - v) = v

It is crucial to note that this estimate assumes no air resistance and that the object is dropped from a height far lower than the radius of the Earth, allowing the curvature of the Earth to be ignored. In fact, air resistance may have a major impact on an object's velocity, particularly as it approaches the earth.

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The maximum acceleration of the platform is 170.24 m/s^2.The maximum acceleration of a platform undergoing simple harmonic motion can be determined using the equation:

a_max = 4π^2f^2A

Where a_max is the maximum acceleration, f is the frequency, and A is the amplitude of oscillation.

Substituting the given values, we get:

a_max = 4π^2 x 7.4^2 x 0.016

a_max = 170.24 m/s^2

Therefore, the maximum acceleration of the platform is 170.24 m/s^2.

The amplitude of oscillation represents the maximum displacement of the platform from its mean position. The frequency represents the number of oscillations the platform completes in one second.

The maximum acceleration of the platform is directly proportional to the frequency and the square of the amplitude of oscillation. In this case, the frequency of oscillation is 7.4 Hz, and the amplitude of oscillation is 1.6 cm. Using the formula mentioned above, we can calculate the maximum acceleration of the platform as 170.24 m/s^2.

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Spectral shifts are caused by the movement of the spectrum to shorter wavelengths, while the Big Bang Theory is supported by spectra analyses because we can determine how spectra of electromagnetic radiation from stars changes depending on their relative position.

The Big Bang Theory is a widely accepted model in physics about the boring of the Universe, which it is believed occurred though a big explosion, while light spectra refers to the observation of the electromagnetic radiation emitted by stars.

Therefore, with this data, we can see that the Big Bang Theory obtains supportive evidence from the emission of electromagnetic spectra of stars.

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Answer:

a-

50°C whn converted into K - 323 K

Answer:

Wood is lighter than iron of the same volume because wood has a lower density. Density is a measure of mass per unit volume, and iron is denser than wood. Iron has tightly packed atoms with strong metallic bonds, while wood has a porous structure with empty spaces between its fibers and cells. These empty spaces in wood reduce its overall mass for a given volume, resulting in its lighter weight compared to iron.

Explanation:

appreciate you helping me, what shall one do if he thinks he has done a mistake and wants to reverse it? related to bul l yinging stuffs in school

Answer:

I think its A

Explanation:

Not 100 percent sure tho but they do go up and down in big movements.

An athlete runs before taking a long jump because they need to gather the strength to jump its like a person brain storming before they write an essay

A G star with a brightness of 100 L Sun is classified as Figure 19.15 lum inosity Classes. Its surface area must be 100 times greater since it emits 100 times more energy while maintaining the same temperature.

Even more bright than the massive stars are the stars of group C. These are the largest stars, or supergiants, with the highest luminosities. If a red supergiant like Betelgeuse took the place of the Sun in our solar system, it would be larger than Jupiter's orbit.

A main-sequence (core hydrogen-burning) star with the spectral type O and luminosity class V is referred to as an O-type main-sequence star (O V). The mass of these stars ranges from 15 to 90 times that of the Sun, and their surface temperatures range from 30,000 to 50,000 K. They have a brightness that ranges from 40,000 to 1,000,000 times that of the Sun.

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