If the question states that and are in direct proportion, it means that the relationship between them follows the pattern of direct proportionality. Hence, the answer is (a) in direct proportion.
When two quantities, and , are in direct proportion, it means that as one quantity increases or decreases, the other quantity also increases or decreases proportionally. In other words, there is a constant ratio between the two quantities.
Mathematically, we can express direct proportionality as:
= k
where is the first quantity, is the second quantity, and is the constant of proportionality.
If the relationship between and is described as direct proportion, it implies that the value of remains constant for different values of .
On the other hand, if the relationship between and is described as inverse proportion, it means that the product of and remains constant for different values of .
Therefore, if two quantities, and , are in direct proportion, then they are in direct proportion.
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Dessa, Anne, and Dy bought materials for their project worth
₱276.45. The girls divided the amount equally among themselves.
How much is each share?
Answer:
Step-by-step explanation:
=276.45/3
=92.15
each share is for 92.15
Eve earns 20% commission as a salesperson. She sold an aquarium that cost 56 dollars. How much commission did Eve earn?
Answer:
Step-by-step explanation:
The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experimental conditions ("Experimental Measurement of the Stopping Performance of a Tractor-Semitrailer from Multiple.Speeds," NHTSA, DOT HS 811 488, June 2011): 32.1 30.6 31.4 30.4 31.0 31.9 The cited report slates that under these conditions, the maximum allowable stopping distance is 30. A normal probability plot validates the assumption that stopping distance is normally distributed. Does the data suggest that true average stopping distance exceeds this maximum value? Test the appropriate hypotheses using alpha =.01. Determine the probability of a type II error when alpha =.01, sigma =.65, and the actual value of mu is 31. Repeat this for mu = 32 (use either statistical software or Table A. 17). Repeat (b) using sigma =.80 and compare to the results of (b). What sample size would be necessary to have alpha =.01 and beta =.10 when mu = 31 and sigma =.65?
To determine if the true average stopping distance of the truck exceeds the maximum value of 30, a hypothesis test is conducted using the given data. With an alpha level of 0.01, the test is performed assuming the stopping distances are normally distributed. The probability of a type II error is calculated for two scenarios: when sigma is 0.65 and mu is 31, and when sigma is 0.80 and mu is 31. Finally, the sample size required to achieve α = 0.01 and β = 0.10, with μ = 31 and σ = 0.65, is determined.
To test the hypothesis, we set up the null and alternative hypotheses as follows:
Null hypothesis (H0): The true average stopping distance is less than or equal to 30.
Alternative hypothesis (Ha): The true average stopping distance exceeds 30.
Using the given data and assuming normal distribution, we calculate the sample mean, sample standard deviation, and standard error. With the given alpha level of 0.01, we compare the test statistic (calculated from the sample mean and standard error) to the critical value from the t-distribution to determine if we reject or fail to reject the null hypothesis.
To calculate the probability of a type II error, we need to specify the alternative value of mu. For mu = 31 and sigma = 0.65, we can calculate the corresponding z-score and find the probability of observing a value less than the critical value for alpha = 0.01.
Repeating the calculation with mu = 32 and sigma = 0.65, we determine the probability of a type II error.
In the third part, when sigma is changed to 0.80, we recalculate the probability of a type II error forμ = 31.
To find the sample size needed to achieve α = 0.01 and β = 0.10 with μ = 31 andσ = 0.65, we can use power analysis formulas or statistical software to determine the required sample size based on the desired significance level and power of the test.
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local bank is using Winters' method with α = 0.2,
β = 0.1, and γ = 0.5 to forecast the number of
customers served each day. The bank is open Monday through Friday.
At the end of the previous week,
The exact forecasted number of customers to be served on each of the next five business days, rounded to one decimal place, are as follows:
Tuesday: 389.1
Wednesday: 368.7
Thursday: 326.5
Friday: 510.9
To forecast the number of customers served on each of the next five business days using Winters' method, we need to follow these steps:
Calculate the seasonal factor for each day by multiplying the seasonal index by the level.
Monday: 1.10 × 20 = 22
Tuesday: 0.95 × 20 = 19
Wednesday: 0.90 × 20 = 18
Thursday: 0.80 × 20 = 16
Friday: 1.25 × 20 = 25
Update the level and trend using the following formulas:
New Level = α × (Actual Value / Seasonal Factor) + (1 - α) × (Previous Level + Previous Trend)
New Trend = β × (New Level - Previous Level) + (1 - β) * Previous Trend
For Tuesday:
New Level = 0.2 × (30 / 22) + 0.8 × (20 + 1) = 20.3636
New Trend = 0.1 × (20.3636 - 20) + 0.9 × 1 = 0.0364
Forecast the number of customers served on each subsequent day using the formula:
Forecast = (New Level + Forecasted Trend) × Seasonal Factor
Tuesday Forecast = (20.3636 + 0.0364) × 19 = 389.0909
Wednesday Forecast = (20.3636 + 0.0364) × 18 = 368.7273
Thursday Forecast = (20.3636 + 0.0364) × 16 = 326.5455
Friday Forecast = (20.3636 + 0.0364) × 25 = 510.9091
Therefore, the forecasted number of customers to be served on each of the next five business days, rounded to one decimal place, are as follows:
Tuesday: 389.1
Wednesday: 368.7
Thursday: 326.5
Friday: 510.9
The question should be: A local bank is using Winters' method with α = 0.2, β= 0.1, and γ = 0.5 to forecast the number of customers served each day. The bank is open Monday through Friday. At the end of the previous week, the following seasonal indexes have been estimated: Monday, 1.10; Tuesday, 0.95; Wednesday, 0.90; Thursday, 0.80; Friday, 1.25. Also, the current estimates of level and trend are 20 and 1. After observing that 30 customers are served by the bank on this Monday, forecast the number of customers who will be served on each of the next five business days. Round your answers to one decimal place, if necessary.
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Geometry problem, Name the angle pair relationship and then determine which lines must be parallel based on the angles given If they do not prove lines parallel, write none.
Answer:
see below
Step-by-step explanation:
a) 1 = 4 they are corresponding angles when j and k are parallel
b) 3 + 4 = 180 these just lies on same straight line and they add up to 180 so none
c) 5 + 7 = 180 are consecutive interior angles when k and l are parallel
d) 6 = 7 they are alternate interior angles when k and l are parallel
and refer this link for theory on this topic
https://www.ixl.com/math/lessons/transversals-of-parallel-lines
An equilateral triangle is inscribed in a circle of radius r. Another smaller equilateral triangle is inscribed in the region bounded by the base of the equilateral triangle and the lower part of the circle in such a way that the heights of each triangle are on the same line. See the figure below. What is the ratio of the area of the larger triangle to the area of the smaller triangle?
Let ABC be the equilateral triangle inscribed in a circle of radius r. The area of the equilateral triangle ABC is:A1 = (sqrt(3) / 4) × (2r)² = (sqrt(3) / 4) × 4r² = sqrt(3) × r²The radius of the circle inscribed in equilateral triangle ABC is r / sqrt(3).
Therefore, the altitude h of the triangle ABC is:h = sqrt(3) / 2 × 2 × r / sqrt(3) = rThe smaller equilateral triangle is ADE, which is inscribed in the region bounded by the base of the equilateral triangle and the lower part of the circle in such a way that the heights of each triangle are on the same line. Let AD = x be the side of the smaller equilateral triangle. The altitude of the smaller equilateral triangle is h – x.The radius of the circle inscribed in the smaller equilateral triangle ADE is (r – h + x) / 2.
The ratio of the area of the shaded region to the area of the smaller triangle is:((1 / 6) × πr² - (sqrt(3) / 4) × x²) / [(sqrt(3) / 4) × x²]Thus, we have the following equivalent ratios:
(sqrt(3) × r²) / [(sqrt(3) / 4) × x²] = ((1 / 6) × πr² - (sqrt(3) / 4) × x²) / [(sqrt(3) / 4) × x²]
After multiplying both sides by 4x² and simplifying, we obtain the following quadratic equation in x:πr² / 6x² - 1 = sqrt(3)After solving the quadratic equation, we obtain the following result:x = r × (2 - sqrt(3))The ratio of the area of the larger triangle to the area of the smaller triangle is:
(sqrt(3) × r²) / [(sqrt(3) / 4) × x²]= 4(2 + sqrt(3)).
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A slushy machine at 7-Eleven holds 39 liters of wild cherry slushy. How many 0.6 liter slushies can be dispensed before the machine is completely empty?
PLS HELP!!!!
Answer:
65
tep-by-step explanation:
Brainliest tysmmm you are my 5000 points tysmmmmm
Consider the following. 2(x − 3)2 + (y − 8)2 + (z − 7)2 = 10, (4, 10, 9) (a) Find an equation of the tangent plane to the given surface at the specified point. (b) Find an equation of the normal line to the given surface at the specified point. (x(t), y(t), z(t)) =
The equation of the tangent plane to the given surface at the point (4, 10, 9) is x - 12y + 6z = 79. The equation of the normal line to the given surface at the point (4, 10, 9) is given parametrically as \(\(x(t) = 4 + t, y(t) = 10 - 6t, z(t) = 9 - 3t\)\).
The tangent plane to a surface can be determined by finding the partial derivatives of the equation with respect to x, y, and z. We start by differentiating the equation \(\(2(x - 3)^2 + (y - 8)^2 + (z - 7)^2 = 10\)\) with respect to x, y, and z. Evaluating these partial derivatives at the point (4, 10, 9), we get the coefficients of the tangent plane equation as 1, -12, and 6 respectively, giving us the equation x - 12y + 6z = 79.
To find the equation of the normal line, we use the gradient vector of the surface, which is perpendicular to the tangent plane. The gradient vector is given by \(\(\nabla f(x, y, z) = \left(\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z}\right)\)\), where f(x, y, z) is the equation of the surface. Evaluating the gradient vector at the point (4, 10, 9), we obtain (1, -12, 6). Thus, the parametric equations of the normal line are \(\(x(t) = 4 + t\), \(y(t) = 10 - 6t\), and \(z(t) = 9 - 3t\)\).
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Give the digits in the hundreds place and the ones place.
8,694
Plz help me
the number 6 is in the hundredths place and 4 is in the ones place
What is the solution to 12 = 3/4x
Answer:
3
Step-by-step explanation:
2
find the area enclosed by the curve r=2sin(θ) 3sin(9θ).
The area enclosed by the curve r=2sin(θ) 3sin(9θ) over the interval [0,2π/9] is (243π/64) - (3√3/16).
How to find the area enclosed by the curve?To find the area enclosed by the curve r=2sin(θ) 3sin(9θ), we first need to determine the limits of integration for θ.
Since the curve is periodic with period 2π/9 (due to the 9 in the second term), we only need to consider the portion of the curve in the interval [0, 2π/9].
Next, we need to convert the polar equation to rectangular coordinates, which can be done using the formulas x = r cos(θ) and y = r sin(θ).
Plugging in the given equation, we get:
x = 2sin(θ) cos(θ) + 3sin(9θ) cos(θ)
y = 2sin(θ) sin(θ) + 3sin(9θ) sin(θ)
Now we can find the area enclosed by the curve by integrating over the given interval:
A = ∫[0,2π/9] (1/2) [x(θ) y'(θ) - y(θ) x'(θ)] dθ
Using the formulas for x and y, we can find the derivatives x'(θ) and y'(θ):
x'(θ) = 2cos(θ) cos(θ) - 2sin(θ) sin(θ) + 27cos(9θ) cos(θ) - 27sin(9θ) sin(θ)
y'(θ) = 2cos(θ) sin(θ) + 2sin(θ) cos(θ) + 27cos(9θ) sin(θ) + 27sin(9θ) cos(θ)
Substituting these expressions into the formula for A and evaluating the integral, we get:
A = (243π/64) - (3√3/16)
Therefore, the area enclosed by the curve r=2sin(θ) 3sin(9θ) over the interval [0,2π/9] is (243π/64) - (3√3/16).
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A photographer charges $50 for a sitting and a basic package of photos. Additional 5x7 cost $8 each. How many extra 5x7 pictures can you purchase if you spend a total of $96?
Answer:
5 pictures
Step-by-step explanation:
Just solve the equation: 50+8p=96
-96on both sides
8p=46
divide by 8 on both sides
p=5.75 or 5 3/4, so 5 because it hasnt reached the number 6 yet so 5
if you're in 8th grade in 2020, what grade will you be in 2022?
Answer:10th?
Step-by-step explanation:
8 + two = 10????
Answer:
what grade are you in
Step-by-step explanation:
please see the attached image and help me complete this question , please , its an emergency
Answer:
46
Step-by-step explanation:
32+14 = 46
46 ppl study spanish
Answer:
A = the Venn diagram and the middle section is 41 because :
14 + 25 = 39
80 - 39 = 41
B = 25 ( because of diagram )
C = the number of kids who studied both and only studied it which is:
41 + 14 = 55 (so C = 55).
I’m circle a shown, secant de and tangent dg are drawn. It is known that angle bac equals 72 degrees and arc be equals 96 degrees
Answer:
\(m(BC) = 72^\circ\)
\(m\angle EBC = 168^\circ\)
Step-by-step explanation:
Given
\(m\angle BAC = 72\)
\(m(BE) = 96\)
See attachment for circle
Required
Determine
(a) Measure of BC
(b) Measure of EBC
(a) Measure of BC
From the attachment, we can see that:
\(m(BC) = m\angle BAC\) because they belong to the same sector
This gives:
\(m(BC) = 72^\circ\)
(b) Measure of EBC
From the attachment, we can see that:
\(m\angle EBC = m(EB) +m(BC)\)
Where
\(m(EB) = m(BE) =96^\circ\)
So, we have:
\(m\angle EBC = 96^\circ + 72^\circ\)
\(m\angle EBC = 168^\circ\)
find the angle of elevation of the top of a flag pole 31.9m high from a point 55cm awayon level ground
find the equation of the plane which passes through $(2,4,-1)$ and having the normal vector $(2,3,4).$
Other answers are possible.
=====================================================
Explanation:
The normal vector is n = (a,b,c) = (2,3,4)
The point on the plane is (p,q,r) = (2,4,-1)
Plug those values into the template below and simplify
a(x-p) + b(y-q) + c(z-r) = 0
2(x-2) + 3(y-4) + 4(z-(-1)) = 0
2(x-2) + 3(y-4) + 4(z+1) = 0
2x-4 + 3y-12 + 4z+4 = 0
2x+3y+4z-12 = 0
2x+3y+4z = 12
This is one way to express the cartesian form of the equation.
Find T, N, and K for the space curve r(t) = (et cos t) i + (et sin t) j + 4k.
T(t)=i+j+k
(Type exact answers, using radicals as needed.) N(t)=i+j+k
(Type exact answers, using radicals as needed.)
x(t) = (Type an exact answer, using radicals as needed.)
The unit tangent vector T(t) is i / √2 + j / √2, the normal vector N(t) is -sin t i + cos t j, and the binormal vector B(t) is - (sin t + cos t) k / √2.
To find T(t), N(t), and K(t) for the space curve r(t) = (et cos t) i + (et sin t) j + 4k, we'll need to calculate the unit tangent vector, normal vector, and binormal vector.
Unit Tangent Vector (T(t)):
The unit tangent vector T(t) is the derivative of the position vector r(t) with respect to t, divided by its magnitude.
r(t) = (et cos t) i + (et sin t) j + 4k
Taking the derivative of r(t) with respect to t, we get:
r'(t) = (et (-sin t) + et cos t) i + (et cos t + et sin t) j
To normalize the vector, we divide r'(t) by its magnitude:
T(t) = (1 / |r'(t)|) * r'(t)
| r'(t) | = √[(et (-sin t) + et cos t)² + (et cos t + et sin t)²]
Simplifying the magnitude, we get:
| r'(t) | = √[\(e^{2t\)(cos² t + sin² t) + \(e^{2t\)(cos² t + sin² t)]
| r'(t) | = √(2\(e^{2t\))
Therefore, the unit tangent vector is:
T(t) = (1 / √(2\(e^{2t\))) * [(et (-sin t) + et cos t) i + (et cos t + et sin t) j]
Simplifying further, we get:
T(t) = (1 / √(2\(e^{2t\))) * et(cos t i + sin t j + cos t i + sin t j)
T(t) = (1 / √(2\(e^{2t\))) * 2et(cos t i + sin t j)
T(t) = (1 / √2) (cos t i + sin t j)
Thus, T(t) = i / √2 + j / √2.
Normal Vector (N(t)):
The normal vector N(t) is the derivative of the unit tangent vector T(t) with respect to t, divided by its magnitude.
N(t) = (d/dt)(T(t)) / |(d/dt)(T(t))|
N(t) = (d/dt)(T(t)) / |(d/dt)(T(t))|
N(t) = (d/dt)[(1 / √2)(cos t i + sin t j)] / |(d/dt)[(1 / √2)(cos t i + sin t j)]|
N(t) = (1 / √2)(-sin t i + cos t j) / (1 / √2)(-sin t i + cos t j)
N(t) = -sin t i + cos t j
Thus, N(t) = -sin t i + cos t j.
Binormal Vector (B(t)):
The binormal vector B(t) can be calculated by taking the cross product of T(t) and N(t).
B(t) = T(t) × N(t)
B(t) = (i / √2 + j / √2) × (-sin t i + cos t j)
B(t) = (-sin t / √2) k - (cos t / √2) k
B(t) = - (sin t + cos t) k / √2
Thus, B(t) = - (sin t + cos t) k / √2.
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If someone does this page before 1:15 Ca time I’ll give 100 points lol need the answers asap
Answer:
1. 3-D Shapes
2. To find the area of all 2-D Shapes that make up the 3-D shape who's surface area we are trying to find
3. 160ft^2
4. 213.53cm^2
5. 239.3in^2
6.490.87km^2
7.75.4cm^2
8.1724.9mi^2
Step-by-step explanation:
In question 1 surface area means the final surface area of all 2-d shapes on a 3-D shape, so it is 3-D Shapes
In question 2, it is simply the last questions explanation as an answer
All the questions up to question 8 are explained in the attached
Which is a better deal 20 oz soda bottle for $1.80 or 12 oz for $1.25
20 oz soda bottle for $1.80
Explanation
to solve this , find the unit rate and compare
Step 1
unit rate 1
\(\text{unit rate=}\frac{total\text{ cost}}{N\nu\text{mber of oz}}\)then
Let
total cost=$1.80
number of ounces=20
replace
\(\begin{gathered} \text{unit rate=}\frac{total\text{ cost}}{N\nu\text{mber of oz}} \\ \text{unit rate=}\frac{1.8\text{ dollars}}{20\text{ ounces}}=0.09\text{ dollars per oz=0.090}\frac{dol}{oz} \end{gathered}\)Step 2
now, for option 2
Let
cost=1.25 dollars
number of ounces=12
replace
\(\begin{gathered} \text{unit rate=}\frac{total\text{ cost}}{N\nu\text{mber of oz}} \\ \text{unit rate=}\frac{1.25}{12}=0.104\text{ dollars per ounce=0.104}\frac{dol}{oz} \end{gathered}\)the better deal is teh cheapest option,
Hence, the better deal is option one
20 oz soda bottle for $1.80
I hope this helps you
Graph the lines by finding the points of intersection with the axes (intercepts): y=-6x-2
Step-by-step explanation:
the intercept with the y axis is the y value for x = 0 (only for x = 0 is the line "hitting" the y axis).
and the intercept with the x axis ? well, that is the x value leading to y = 0.
so,
y = -6x - 2
x = 0
y = -6×0 - 2 = -2
so, the y intercept point is (0, -2)
and for what x is y = 0 ?
0 = -6x - 2
2 = -6x
x = -2/6 = -1/3
so, the x intercept point is (-1/3, 0)
Question is attached!!!!!!!! Pls help!!!! Guys I RLLY need ur help!!!!!!!!
Answer:
y = \(3^{x}\)
Step-by-step explanation:
the standard form of an exponential function is
y = a\(b^{x}\)
Use ordered pairs from the table to find a and b
Using (0, 1 ) , then
1 = a\(b^{0}\) [ \(b^{0}\) = 1 ] , so
1 = a × 1 , that is a = 1
y = \(b^{x}\)
Using (1, 3 )
3 = \(b^{1}\) ⇒ b = 3
y = \(3^{x}\) ← required exponential function
Convert 4.5 x 104 to decimal format.A) 45,000 B) 4,500 C) 0.00045 D) 0.0045 E) 0.000450
After converting \(4.5 * 10^4\) to decimal format, one gets 45,000 as an answer. Thus, option (A) is the correct answer.
To convert numbers multiplied by 10 with having an exponent number to decimal format, one first needs to check the sign on the exponent.
If the sign is positive, we must shift the decimal to the right with each power of 10. The exponent indicates the number of zeros added after the number in case no decimal is used.
And if the sign is negative, we have to shift the decimal to the left with each power of 10. One has to divide the number by the number one gets after multiplying 10 by itself as many times as the exponent.
Therefore, to convert \(4.5 * 10^4\) to decimal format, we shift the decimal by 4 places and we get 45,000 as the answer.
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Jessica had 80 songs on her ipod. she downloaded 10 more songs. What was the percent of increase of songs on her ipod?
Answer:
12.5%
Step-by-step explanation:
\(\frac{10}{80} =\frac{x}{100}\)
Cross multiply
80x = 1000
Divide both sides by 80
80x/80 = 1000/80
x = 12.5
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Andre Drew a plan of a courtyard at a scale of 1 to 60 on his drawing one side of the car Courtyard Is 75 inches. If I Andre Made another courtyard scale drawing is a scale of 1 to 12 what destroying be smaller or larger than the first the drawing
Answer: hey girl hal is north west west of north west west north west of north north
Step-by-step explanation:
4. In a class of students, the following data table
summarizes how many students have a cat or a dog. What
is the probability that a student chosen randomly from the
class has a dog?
Has a dog
Does not have a dog
Has a cat Does not have a cat
16
4
6
3
The probability that a student who had a dog also had a cat would be = 7/25.
How to calculate the possible outcome of the given event?To calculate the possible outcome of the given event, the formula for probability should be used and it's given below as follows. That is;
Probability = possible outcome/sample space
possible outcome = 7
sample space = 7+2+3+13 = 25
Probability = 7/25
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A scatter plot is shown on the coordinate plane.
Which two points would a line of fit go through to best fit the data?
A. (1,9) and (9,5)
B. (1,9) and (5,7)
C. (2,7) and (4,3)
D. (2,7) and (6,5)
The line of the best fit would pass through (a) (1,9) and (9,5)
How to determine the points on the line of best fitFrom the question, we have the following parameters that can be used in our computation:
The graph
A good line of best fit would have equal number of points on either sides
To plot the graph, we draw a line that divides the points on the graph evenly
This line when drawn on the scattered points divided the points approximately evenly
The line of the best fit when drawn using the above properties would pass through (a) (1,9) and (9,5)
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In triangle ABC, ∠A = 55°, ∠B = 75°. Which statements are correct? You must select all correct answers.
Side BC is the longest side
Side AB is the shortest side
Side AC is the longest side
Side BC is the shortest side
Answer:
AC is the longest side
AB is the shortest
Step-by-step explanation:
Generally, the side that faces the smallest angle has the smallest side while the side that faces the largest angle has the largest side
The measure of the third angle C is 180 - 55 -75 = 50
Kindly note that A faces BC
B faces AC
C faces AB
So while AC is the longest side, AB is the shortest
So the correct answers are;
AC is the longest side
AB is the shortest side
A piece of rope is cut into three lengths in the ratio 2 : 3 : 5. If the smallest length is 6cm, find the length of the original rope.
Answer:
given,
ratio= 2:3:5 , smallest part length=6
let x be the common multiple then,
first number (smallest) =2x
6cm =2x
6/2=x
therefore, x=3
now,
1st part=2x=2*3=6
2nd part=3x=3*3=9
3rd part=5x=5*3=15
again,
total length = sum of all part
=6+9+15
=30
therefore 30cm is the answer
john can shovel a certain driveway in 50 minutes if mar can shovel the same driveyway in 20 minutes how long will it take them to the nearest minute, to shovel the driveway if they work together
John and Mar need 14 minutes complete shovel their driveway together, to the nearest minute.
What is rate of doing work?You can use this computation to determine the hourly value of each employee's job, allowing you to more effectively and efficiently plan your staffing needs in the future.
This is crucial because it enables you to determine the ideal workforce size based on your average hourly wage.
According to the question;
by calculating the fraction of unit work that each individual can finish in a given amount of time together work is estimated.
Mary can clear 1/20 of a driveway in a minute, but John can clear 1/50 of it in that time.
The both will do the same job in;
= (1/20) + (1/50)
= (5/100) + (2/100)
= 7/100
They'll be finished when they've cleared 100 percent of the driveway, therefore the equation we must finally solve is:
7x = 100.
x = 100/7
x = 14.28
Therefore, when John and Mar will work together, they will shovel the driveway in 14 minutes (to the nearest minute).
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