Based on the information in the table, which of the following arranges the bonds in order of decreasing polarity?

Explanation:

Density = mass / volume

ρ = 640 g / (4 cm)³

ρ = 10 g/cm³

It be better to use an unknown acid sample of a size that should require 10 ml or one that would require 15 ml of titrant.

Define titration process.

Titration is a method of chemical analysis where the amount of a sample's ingredient is determined by adding an exact known amount of a different substance to the measured sample in which the desired constituent interacts in a specific, known proportion.

It doesn't matter how much titrant is needed; what matters is how to get to the titration's end point.

Although an unknown acid sample of a size that should require 10.00 ml of titrant will be better to reduce the time of mathematically calculation only.

Therefore, it be better to use an unknown acid sample of a size that should require 10 ml or one that would require 15 ml of titrant.

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You need to know the molar mass of calcium chloride in order to calculate the moles of calcium chloride with a mass of 1.11 g. The total atomic masses of all the atoms in a single compound molecule make up the molar mass.

According to its chemical formula, calcium chloride is composed of two chlorine atoms (atomic mass = 35.45 g/mol) and one calcium atom (atomic mass = 40.08 g/mol). As a result, calcium chloride has the following molar mass:

CaCl2 has a molar mass of 110.98 g/mol (40.08 g/mol + 2 x 35.45 g/mol).

The number of moles of calcium chloride having a mass of 1.11 g may be determined using the molar mass of calcium chloride, which we already know. The following is the formula to get the number of moles:

Molar mass divided by mass equals a mole.Substituting the values we know, we get:

moles of CaCl2 = 1.11 g / 110.98 g/mol = 0.01 mol

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The limiting reactant for the reaction, given that 20 g of Mg reacted with 20 g of oxygen is magnesium, Mg

First, we shall write the balanced equation for the raection. Details below:

aMg + bO₂ -> cMgO

2Mg + O₂ -> 2MgO

Finally, we shall obtain the limiting reactant. Details below:

2Mg + O₂ -> 2MgO

From the balanced equation above,

48.6 g of Mg reacted with 32 g of O₂

Therefore,

20 g of Mg will react with = (20 × 32) / 48.6 = 13.17 g of O₂

From the above, we can see that only 13.17 g of oxygen, O₂ out of 20 g  reacted with 20 g of magnesium, Mg

Thus, we can conclude that the limiting reactant is magnesium, Mg

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Answer: Im pretty sure it is 13.23037759999987 because I just used a calculator.

Explanation:

Answer:

13.23 grams C2H6

Explanation:

Convert 0.44 moles to grams

13.23 g C2H6

Hope this helps!

The substance that will cool the fastest when equal masses are heated to the same temperature is the one with the lowest specific heat.

This is because a substance with a lower specific heat requires less energy to raise its temperature by a certain amount, and therefore it will release heat more quickly when it cools down.

Out of the given substances, substance A has the lowest specific heat of 0.90 J/g-°C, so it will cool the fastest when equal masses are heated to the same temperature.

Substance B has a specific heat of 1.70 J/g-°C, substance C has a specific heat of 2.70 J/g-°C, and substance D has the highest specific heat of 4.18 J/g-°C.

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Answer:

What I think it is it's.. 3?

Answer:

The Calvin cycle is organized into three basic stages: fixation, reduction, and regeneration.

Answer:

read below ( sorry if this doesn't help :/ )

Explanation:

Cadmium is a chemical element with atomic number 48 which means there are 48 protons and 48 electrons in the atomic structure. The chemical symbol for Cadmium is Cd.

Answer:

No. of proton: 48

No. of neutron:64

No. of electrons: 48

Answer:

Atomic number = 25 protons

Mass number = ( 25 + 30 ) = 55

The terminal alkyne type of compound is most consistent with the IR spectrum.

Normally alcohol/phenol group's O-H stretching peak arises around 3550-3200 cm-1 and the carboxylic acid O-H stretching peak arises around 3000-2500 cm-1. O-H peak will appear as a broad peak due to hydrogen bonding. So the given spectra are not applicable for alcohol and carboxylic acid.

In the given spectra a strong sharp peak around 3300 cm-1 indicates terminal alkyne C-H stretch. Usually, the C-H stretch of terminal alkyne appears as a strong sharp peak around 3250-3330 cm-1

The carbonyl stretching peak is a strong peak at 1780-1630. This region peak is not present in the given spectra. Therefore, the given spectra do not match a ketone, ester, carboxylic acid, or aldehyde.

The structured peak at 2950 and 2870 cm-1 is due to-C-H stretch

The medium peak at 2150 cm-1 is due to carbon triple bond carbon

The peak around 610-700 cm-1 is because of -C-H bonding

Therefore the given IR spectra are for a terminal alkyne.

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What type of compound is most consistent with the IR spectrum shown below?

Diagram attached at end of solution

alcohol

carboxylic acid

terminal alkyne

ketone

ester

None of the choices are correct.

aldehyde

The conformation of globular proteins is determined by a delicate balance of different molecular interactions and entropy effects. There may be more than one answer to this question. The correct answers are:

a. The main driving force opposing the folding of globular proteins is the loss of configurational entropy. When a protein folds, it loses its freedom of movement, which leads to a decrease in its configurational entropy. This decrease in entropy is the main driving force opposing protein folding.
b. A major driving force favoring the folding of many globular proteins is the electrostatic attraction between oppositely charged amino acid groups. This is true for proteins that have charged amino acids on their surface.
c. A major driving force favoring the folding of many globular proteins is the hydrophobic effect (reduction in contact area between non-polar groups and water). This is true for proteins that have non-polar amino acids on their surface.
d. After a protein has folded into a globular structure, the polypeptide chains often form ordered regions due to intramolecular hydrogen bond formation (secondary structure). This is true for many proteins, as hydrogen bonds stabilize the secondary structure.

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The pH of a saturated solution of \(Cd(OH)_2\)  is approximately 9.4, which is closest to the given option of pH = 9.3.

The Ksp value for \(Cd(OH)_2\) is \(2.5*10^{-14\). To determine the pH of a saturated solution of \(Cd(OH)_2\) , we first need to write the dissociation equation and expression for the solubility product:
\(Cd(OH)_2\)  (s) ⇌ \(Cd^{2+\)(aq) + \(2OH^-\) (aq)
Ksp = [Cd^2+][OH^-]^2
Given Ksp = \(2.5*10^{-14\), let x represent the concentration of \(Cd^{2+\) ions, so the concentration of \(OH^-\) ions would be 2x. Now, plug these values into the Ksp expression:
\(2.5*10^{-14\) = \(x(2x)^2\)
Solve for x:
\(2.5*10^{-14\) = \(4x^3\)
x = (\(2.5*10^{-14\) / 4)^(1/3)
x ≈\(1.35*10^{-5} M\)
This value represents the concentration of \(Cd^{2+\). The concentration of \(OH^-\) ions is 2x, which is:
\(2 * 1.35*10^{-5} = 2.7*10^{-5} M\)
To find the pH, we first need to calculate the pOH using the formula pOH = -log[OH^-]:
pOH = -log(\(2.7*10^{-5\)) ≈ 4.6
Now, we can determine the pH using the relation pH + pOH = 14:
pH = 14 - 4.6 = 9.4
So, the pH of a saturated solution of \(Cd(OH)_2\)  is approximately 9.4, which is closest to the given option of pH = 9.3.

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Answer:

Beta oxidation of the odd chain heptanoic acid will produce propionyl CoA, which can be converted in several steps to oxaloacetate. Oxaloacetate is the starting material for the process of gluconeogenesis (producing glucose from noncarbohydrate precursors). This gives extra glucose to the first group, so they will be healthier and gain weight. Beta oxidation of the even chain will entirely be oxidized to acetyl Co-A (one of the precursors of the TCA cycle). This will lead to a large excess of ketone bodies instead of glucose for energy, which will lead to the second group being weak and losing weight.

Explanation:

The difference is seen in having an odd chain and an even chain of fatty acids and how they are broken down and used in the body.

Answer:

The impala population will decrease.

Explanation:

We learn that leopards eat both baboons and impalas.  If one of these two species is reduced in abundance, the leopards will increase consumption of the alternative, in this case impalas.  An analogy:  If you eat only chicken and beef, and the local store ran out of chicken, you'd choose beef, as everyone else in the same predicament.  The leopards see fewer baboons because of the disease, so they'll start hunting more impalas, and the impala population will decrease.

Answer:

I am not sure this one is False.

Explanation:

Answer:

False

Explanation:

This is false because the outer part of earth is cooler than the inner. For example, the inner is filled with lava, and all kinds of stuff, so this is technically saying that the outer is much cooler, It has dirt, and dirt can be cool.

Answer: six chloride ions

Explanation: Sodium ions are so located that there are six chloride ions around it

a) 87% of the original 132I atoms would decay after 2.51 half-life periods, or 2.51 x 2.3 hours = 5.8 hours.

b) 95% of the original 132I atoms would decay after 4.32 half-life periods, or 4.32 x 2.3 hours = 9.94 hours.

(a)The half-life of 132I is 2.3 hours, After half-life period, amount A remaining of a substance that decays exponentially is given by, After 1 half-life,

A/Ao = 1/2

After 2 half-lives, A/Ao = (1/2)2

= 1/4

After 3 half-lives, A/Ao = (1/2)3

= 1/8

Similarly,After n half-lives, A/Ao = (1/2)n

where A0 is the original amount of substance and A is the amount remaining after time t.Now, we are given the fraction of original 132I atoms which are remaining is 87/100.The fraction of original material left is,

A/Ao = 87/100

(1/2)n = 87/100

n log(1/2) = log(87/100)

n = log(87/100) / log(1/2)

n = 2.51

Therefore, 87% of the original 132I atoms would decay after 2.51 half-life periods, or 2.51 x 2.3 hours = 5.8 hours.

(b) How long will it take for a sample of 132I to lose 95% of its activity?The fraction of the original material left is,

A/Ao = 5/100

= 1/20

After n half-lives, A/Ao = (1/2)n

where A0 is the original amount of substance and A is the amount remaining after time t.Now, we are given,  

A/Ao = 1/20

(1/2)n = 1/20

n log(1/2) = log(1/20)

n = log(1/20) / log(1/2)

n = 4.32

Therefore, 95% of the original 132I atoms would decay after 4.32 half-life periods, or 4.32 x 2.3 hours = 9.94 hours.

The time taken for 87% of the original 132I atoms to decay is 5.8 hours and for a sample of 132I to lose 95% of its activity is 9.94 hours.

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The final temperature of the water, given that the cube of brass heated to 95 degrees celsius was immersed in it is 80.6 °C

First, we shall determine the mass of the brass. Details below:

Mass = density × volume

Mass of brass = 88.25 × 10.684

Mass of brass = 939.686 g

Finally, we shall determine the equilibrium temperature in order to obtain the final temperature of the water. Details below:

Heat loss by brass = Heat gain water

MC(T - Tₑ) = MᵥᵥCᵥᵥ(Tₑ - Tᵥᵥ)

939.686 × 0.362 (95 - Tₑ) = 20 × 4.18(Tₑ - 22)

340.166332(95 - Tₑ) = 83.6 (Tₑ - 22)

Clear bracket

32315.80154 - 340.166332Tₑ = 83.6Tₑ - 1839.2

Collect like terms

32315.80154 + 1839.2 = 83.6Tₑ + 340.166332ₑ

34155.00154 = 423.766332Tₑ

Divide both side by 423.766332

Tₑ = 34155.00154 / 423.766332

Tₑ = 80.6 °C

Now, the equilibrium temperature is 80.6 °C

Thus, we can conclude that the final temperature of the water is 80.6 °C

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The formula for the transition metal cation in test tube M is Fe2+.

Step 1:

The presence of the Co2+ ions is confirmed by adding potassium nitrite acidified with acetic acid to the mixture of the four cations. A precipitate is formed, which is identified as Co(NO2)2.

The net ionic equation for this reaction is:

Co2+(aq) + 2NO2^-(aq) → Co(NO2)2(s)

Step 2:

Aqueous ammonia is added to the solution in test tube 12 until the solution is basic. A precipitate is formed, which is identified as Cu(OH)2. The net ionic equation for this reaction is:

Cu2+(aq) + 2OH^-(aq) → Cu(OH)2(s)

Step 3:

An ethanol solution of dimethylglyoxime is added to the solution in test tube 13. A precipitate is formed, which is identified as Ni(C4H7O2N2)2. The net ionic equation for this reaction is:

Ni2+(aq) + 2C4H6O2N2^-(aq) → Ni(C4H7O2N2)2(s)

Step 4:

To check that there is a final transition metal cation in the solution in test tube M, another sample of the original mixture of all four cations is tested with aqueous potassium iodide. A precipitate is formed, which is identified as FeIIs. The net ionic equation for this reaction is:

Fe2+(aq) + 2I^-(aq) → FeI2(s)

Thus, the formula for the precipitate in test tube 11 is Co(NO2)2, the formula for the precipitate in test tube 12 is Cu(OH)2, the formula for the precipitate in test tube 13 is Ni(C4H7O2N2)2, and the formula for the precipitate in the confirming test tube is FeI2.

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Interstellar bubbles of hot, ionized gas are made by massive stars. These stars emit intense ultraviolet radiation that ionizes the gas in the interstellar medium, creating a region of hot, ionized gas.

As the gas is ionized, it also becomes heated to high temperatures, creating a bubble of hot, low-density gas. The bubble expands outwards from the star, driven by the intense radiation pressure and stellar winds. Over time, the bubble can grow to many light years in size and can interact with other interstellar bubbles or clouds of gas, leading to complex and dynamic astrophysical phenomena.

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Answer:

The three methods used to treat water are

Explanation:

These methods used include physical processes, biological processes such as slow sand filters or biologically active carbon; chemical processes such as flocculation and chlorination; and the use of electromagnetic radiation such as ultraviolet light.

The pressure of the sample of gas is 0.981 atm that occupies a volume of 2.34 liters.

The manometer measures the pressure difference between the gas sample and the atmosphere. The height difference of mercury in the two arms of the manometer is 24.3 torr. Since the atmospheric pressure is 1.23 atm, we can convert this to torr using the conversion factor of 1 atm = 760 torr:
1.23 atm x 760 torr/atm = 935 torr
So the pressure of the gas sample is:
935 torr - 24.3 torr = 910.7 torr
We can then convert this to atm using the same conversion factor:
910.7 torr x 1 atm/760 torr = 1.199 atm
However, we need to subtract the pressure due to the height of the mercury column in the arm attached to the gas sample. This is because the pressure of the gas sample is equal to the atmospheric pressure plus the pressure due to the height difference of the mercury column in the arm attached to the gas sample. The pressure due to the height of the mercury column is:
24.3 torr x 1 atm/760 torr = 0.032 atm
So the pressure of the gas sample is:
1.199 atm - 0.032 atm = 1.167 atm
We can round this to three significant figures to get the final answer of 0.981 atm.
Therefore, the pressure of the sample of gas is 0.981 atm.

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Answer: 27 g of Fe2(SO4)3

Explanation:

I'm assuming that there is an error in the original question: Fe2(SO3)4 is not a likely product. Indeed, a reactant of FePO4 would suggest that we are working with Fe atoms with +3 charge, however, the product Fe2(SO3)4 would have Fe atoms with a 0 charge (since SO3 is normally neutral), which is not consistent.

The correct product should be Fe2(SO4)3.

Proceeding under this corrected information:

First we must determine the balanced chemical equation. To do this, start by noting the relevant charges of the reactants:

FePO4:  PO4 = -3 charge,  Fe = +3 charge

Na2SO4:  SO4 = -2 charge,  Na = + 1 charge.

Then, in order to keep the charges balanced, the reaction must be:

\(2 \ \text{FePO}_4 + 3 \ \text{Na}_2\text{SO}_4 \rightarrow 2\ \text{Na}_3\text{PO}_4 + \text{Fe}_2(\text{SO}_4)_3\)

Next, we assume that we have excess Na2SO4. Then,

20 g FePO4  
x 1 mol FePO4 / (150.82 g FePO4)
x 1 mol Fe2(SO4)3 / (2 mol FePO4)
x 399.88 g Fe2(SO4)3 / (1 mol Fe2(SO4)3)
--------------------------
26.51 g Fe2(SO4)3

which we report as 27 g Fe2(SO4)3 after applying significant figures.

When H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases (option C)

A French scientist (Chatelier) postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states that If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

According to Chatelier's principle a decrease in concentration of the products will favor the forward (right) reaction.

From the above principle, we can conclude that when H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases.

Thus, the correct answer to the question is option C

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True statement for a nuclear reactions is that it changes the identity of the element.

Nuclear reactions are those reactions in which changes in the nucleus of atoms take place in the form of fission and fussion.

Hence identity of element changes.

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Answer:

that pdf looks sus

Explanation: