Based on the given p-value of 0.0415, we can conclude that there is sufficient evidence to reject the null hypothesis (H0) and accept the alternative hypothesis (Ha). Therefore, we can say that the colors in a Skittles bag are not evenly distributed.
This is because:
1. The null hypothesis (H0) in this test states that the colors in a Skittles bag are evenly distributed.
2. The alternative hypothesis (Ha) states that the colors in a Skittles bag are not evenly distributed.
3. The p-value is a measure of the strength of evidence against the null hypothesis.
4. In this case, the p-value is 0.0415.
5. The p-value represents the probability of obtaining results as extreme as the observed data, assuming that the null hypothesis is true.
6. In simpler terms, it tells us how likely it is to observe the data we have if the null hypothesis is true.
7. A p-value less than the predetermined significance level (usually 0.05) indicates that the observed data is unlikely to have occurred by chance alone if the null hypothesis is true.
8. In this case, since the p-value (0.0415) is less than 0.05, we have enough evidence to reject the null hypothesis and accept the alternative hypothesis.
9. Therefore, we can conclude that the colors in a Skittles bag are not evenly distributed.
In conclusion, the p-value provides evidence to support the rejection of the null hypothesis, indicating that the colors in a Skittles bag are not evenly distributed.
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Which relation is displayed in the table?
A: {(-2, -3), (1, -1), (2, -2), (3, 3)}
B: {(-3, -2), (-1, 1), (2, -2), (3, 3)}
C: {(-2, -3), (-1, 1), (-2, 2), (3, 3)}
D: {(-2, -3), (-1, 1), (-2, -2), (3, 3)}
The relation displayed in the table is
B: {(-3, -2), (-1, 1), (2, -2), (3, 3)}How to find the relation in the tableThe relation in the table is compared by identifying how a coordinate point are expressed as ordered pair and how they are expressed as a table
For instance, say (b, c) is represented in a table as
x y
a b
Using this instance and writing out the values in the table we have
(3, 3), (-1, 1), (2, -2), and (-3, 2)
This is similar to option B making option B the appropriate option
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f(x)=2x+1; find f(3)
Step-by-step explanation:
hope my answer helps you mark me brainliest hope your day goes wellGiven that x is a nonnegative number, a student conjectured that x+4
Which value of x is a counterexample to the student's conjecture?
Responses
A. x=−1/4
(x equals negative one fourth)
B. x=−4
C. x = 1
D. x = 4
The value of x that is a counterexample to the student's conjecture is (a) x = -1/4
How to determine the value of x?From the question, we have the following statement that can be used in our computation:
x = Non-negative number
Student's conjecture:
x + 4 < x²
Using the options, we have:
(a) x = -1/4
x + 4 < x²
-1/4 + 4 < (-1/4)²
3.75 < 1/16 -- false
(b) x = -4
x + 4 < x²
-4 + 4 < (-4)²
0 < 16 -- true
(c) x = 1
x + 4 < x²
1 + 4 < (1)²
5 < 1 -- false
This cannot be used because x is non-negative
(c) x = 4
x + 4 < x²
4 + 4 < (4)²
8 < 16 -- true
The false statements are the counterexamples
Hence, the value of x is (a) x = -1/4
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Complete question
Given that x is a nonnegative number, a student conjectured that x + 4 < x². Which value of x is a counterexample to the student's conjecture?
Responses
A. x=−1/4
B. x=−4
C. x = 1
D. x = 4
A bus traveled on a straight road for 3 h at an average speed that was 12 mph faster than its average speed on a winding road. The time spent on the winding road was 3 h. Find the average speed on the winding road if the total trip was 210 mi.
The average speed on the winding road was 45 mph.
The bus traveled for 3 hours on the winding road, so the distance covered can be calculated using the formula: Distance = Speed × Time. Let's assume the average speed on the winding road as 'x' mph. Therefore, the distance covered on the winding road is 3x miles.
On the straight road, the bus traveled for 3 hours at an average speed that was 12 mph faster than its average speed on the winding road. So the average speed on the straight road can be expressed as 'x + 12' mph. The distance covered on the straight road can be calculated as 3(x + 12) miles.
The total distance covered in the entire trip is given as 210 miles. Therefore, we can write the equation:
3x + 3(x + 12) = 210
Simplifying the equation:
3x + 3x + 36 = 210
6x + 36 = 210
6x = 174
x = 29
So the average speed on the winding road was 29 mph.
The problem states that the bus traveled for 3 hours on both the winding road and the straight road. Let's assume the average speed on the winding road as 'x' mph. Since the bus traveled for 3 hours on the winding road, the distance covered can be calculated as 3x miles.
On the straight road, the average speed was 12 mph faster than on the winding road. Therefore, the average speed on the straight road can be expressed as 'x + 12' mph. The distance covered on the straight road can be calculated as 3(x + 12) miles.
The total distance covered in the entire trip is given as 210 miles. This allows us to set up the equation 3x + 3(x + 12) = 210 to solve for 'x'. Simplifying the equation leads to 6x + 36 = 210. Solving for 'x', we find that the average speed on the winding road was 29 mph.
In summary, the average speed on the winding road was 29 mph.
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Mary has $2700 in her checking account and $1500 in her savings account. She
uses her checking account to pay bills, which are about $240 each month. In how
many months will her checking account balance equal her savings account
balance?
It would take her 5 months
One summer, an ice cream truck driver sold 381 Popsicles and 76 ice creams. How many treats did the driver sell in all?
The bear population increases at a rate of 2% per year. There are
1573 bear this year. Write a function that models the bear population.
How many bears will there be in 10 yr?
Answer:
The answer would be P(x) = 1573*(1.02)^x
Help you'll get brainiest! Combine the radicals
Answer:
hi b is the answer
Step-by-step explanation:
please mark me as the brainliest answer and please follow me for more answers to your questions
Answer:
Step-by-step explanation:
\(\sqrt{27} = \sqrt{9}\) ×\(\sqrt{3}\) = 3 × \(\sqrt{3}\) = \(3\sqrt{3}\)
So then
\(5\sqrt{27} = 5\) ×\(3\sqrt{3}\) = \(15\sqrt{3\)
And then
\(15\sqrt{3} - 17\sqrt{3} = -2\sqrt{3}\)
Mike finds a deal with a yearly interest rate of 20%, how much is the monthly interest rate?
Answer: The monthly interest rate is 1.67%.
Step-by-step explanation: To find the monthly interest rate, we need to divide the yearly interest rate by the number of months in a year. Since there are 12 months in a year, we can divide the yearly interest rate by 12 to get the monthly interest rate.
The monthly interest rate can be calculated as:
Monthly interest rate = Yearly interest rate / 12
In this case, the yearly interest rate is 20%. So, the monthly interest rate can be calculated as:
Monthly interest rate = 20% / 12 = 1.67%
Therefore, the monthly interest rate is 1.67%.
2.Which data set is more likely to produce a histogram with a symmetric distribution? Explain yourreasoning.Data on the number of seconds on a track of music in a pop album.Data on the number of seconds spent talking on the phone yesterday by everyone in theschool.
A histogram with a symmetric distribution looks like this:
Leaving aside the quality of the drawing, the left and the right side of the histogram are identical if we split it by the red line. Is like having a reflexion axis.
Now, we have to discuss what of the 2 data sets may have such an histogram. This means that we must think which of them may have the same number of ocurrences for very short and very long durations, for regular to short and regular to long durations, and so on and so furth.
Pop album tracks:
In the same album we may have arround 12 tracks (small number), all of them with a duration of arround 3 minutes. We could imagine a histogram like the following:
All the songs last between 170 and 190 seconds, and one or two last a little bit more.
Phone talks:
In this case, we can think that there are some calls to say something like "mom, I'm on my way home" and other like "let me tell you the hole movie I saw yesterday night", so very short and very long calls, but they are no so common. There are a lot of "regular" calls that might last for 60 seconds.
Also, in this case, we are taking into account all the calls from people in the school in one day (yesterday), so, may be 1.000 calls? The actual number really doesn't matter, but the fact that the number is very big. Because of the big number, we can expect a symmetric distribution.
please help me on this problem
Hi there! Use the Pythagorean Theorem to find a missing side of a right triangle
\( \large \boxed{ {a}^{2} + {b}^{2} = {c}^{2} }\)
Define that c is our hypotenuse. Substitute a = 5 and b = 12 in the equation.
\( \large{ {5}^{2} + {12}^{2} = {c}^{2} }\)
Solve the equation for c.
\( \large{25 + 144 = {c}^{2} } \\ \large{169 = {c}^{2} } \\ \large{ \sqrt{169} = c} \\ \large{c = 13}\)
Note that we are solving for a length of a triangle. Thus, negative values cannot be an answer.
Answer
The length of hypotenuse is 13 metersow must the units be set up in order to get from the number of eggs used to make a certain number of cookies to the number of eggs needed to make some other number of cookies?
To get from the number of eggs used to make a certain number of cookies to the number of eggs needed to make some other number of cookies, you would use a proportional relationship.
Let's say x represents the number of eggs used to make a certain number of cookies, y represents the number of cookies made, and z represents the number of eggs needed to make some other number of cookies.
Then, we can set up the proportion:
x eggs / y cookies = z eggs / (some other number of cookies)
We can then solve for z by cross-multiplying:
z eggs = x eggs * (some other number of cookies) / y cookies
This formula tells us how many eggs are needed to make the specified number of cookies, based on the number of eggs used and the number of cookies originally made.
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Find the surface area of the space figure represented by the net.
245.5 cm2
263 cm2
173.5 cm2
191 cm2
Answer:
B. 263 cm²
Step-by-step explanation:
Surface area of the figure represented by the net = area of all parts of the net which consists of 3 rectangles and 2 triangles
✔️Area of the first two equal rectangles = 2(L*W)
L = 12 cm
W = 6 cm
Area of the first two equal rectangles = 2(12*6)
= 144 cm²
✔️Area of the third rectangle = L*W
L = 12 cm
W = 7 cm
Area = 12*7
= 84 cm²
✔️Area of the two equal triangles = 2(½*b*h) = b*h
b = 7 cm
h = 5 cm
Area = 7*5
= 35 cm²
✔️Surface area of the space figure = 144 + 84 + 35
= 263 cm²
A rectangle has a width of 2x - 3 and a length of 3x + 1. a) Write its area as a simplified polynomial. b) Write expressions for the dimensions if the width is doubled and the length is increased by 2. c) Write the new area as a simplified polynomial.
a) The area of a rectangle is given by the formula A = length × width. Substituting the given expressions for the width (2x - 3) and length (3x + 1), we can simplify the expression:
Area = (2x - 3) × (3x + 1)
= 6x^2 - 9x + 2x - 3
= 6x^2 - 7x - 3
Therefore, the area of the rectangle is represented by the polynomial 6x^2 - 7x - 3.
b) If the width is doubled, we multiply the original width expression (2x - 3) by 2, resulting in 4x - 6. If the length is increased by 2, we add 2 to the original length expression (3x + 1), yielding 3x + 3.
So, the new dimensions of the rectangle are width = 4x - 6 and length = 3x + 3.
c) To find the new area, we substitute the new expressions for the width and length into the area formula:
New Area = (4x - 6) × (3x + 3)
= 12x^2 + 12x - 18x - 18
= 12x^2 - 6x - 18
Thus, the new area of the rectangle is represented by the simplified polynomial 12x^2 - 6x - 18.
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Write an equation of the line that passes through (1, 1) and (3, 3).
\((\stackrel{x_1}{1}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{\textit{\large run}} {\underset{x_2}{3}-\underset{x_1}{1}}} \implies \cfrac{ 2 }{ 2 } \implies 1\)
\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ 1}(x-\stackrel{x_1}{1})\implies y-1=x-1\implies \boxed{y=x}\)
Answer: y=x+2
Step-by-step explanation: to find the slope use the formula y2-y1/x2-x1 which will get 3-1/3-1= 2/2= 1 so the slope is one. then take formula (y-y1)=m(x-x1) m is slope so you will get (y-3)=1(x-1) distribute the one y-3=x-1 add three to both sides to get y=x+2
Find < A :
(Round your answer to the nearest hundredth)
The measure of angle A in a right triangle with base 5 cm and hypotenuse 10 cm is approximately 38.21 degrees.
We can use the inverse cosine function (cos⁻¹) to find the measure of angle A, using the cosine rule for triangles.
According to the cosine rule, we have:
cos(A) = (b² + c² - a²) / (2bc)
where a, b, and c are the lengths of the sides of the triangle opposite to the angles A, B, and C, respectively. In this case, we have b = 5 cm and c = 10 cm (the hypotenuse), and we need to find A.
Applying the cosine rule, we get:
cos(A) = (5² + 10² - a²) / (2 * 5 * 10)
cos(A) = (25 + 100 - a²) / 100
cos(A) = (125 - a²) / 100
To solve for A, we need to take the inverse cosine of both sides:
A = cos⁻¹((125 - a²) / 100)
Since this is a right triangle, we know that A must be acute, meaning it is less than 90 degrees. Therefore, we can conclude that A is the smaller of the two acute angles opposite the shorter leg of the triangle.
Using the Pythagorean theorem, we can find the length of the missing side at
a² = c² - b² = 10² - 5² = 75
a = √75 = 5√3
Substituting this into the formula for A, we get:
A = cos⁻¹((125 - (5√3)²) / 100) ≈ 38.21 degrees
Therefore, the measure of angle A is approximately 38.21 degrees.
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The sum of three consecutive numbers is 90. What is the largest integer?
a. 29
b. 30
c. 31
d. 32
What is -(x + 5) distributed
Answer:
-x-5
Step-by-step explanation:
Multiply every part inside the equation by -1.
x*-1 and 5*-1
-1x+-5x
Simplify.
-x-5
(x+4) ² remove bracket and simplify
Answer:
To expand (x + 4)², we can use the formula for squaring a binomial: (a + b)² = a² + 2ab + b². In this case, a = x and b = 4.
So,
(x + 4)² = x² + 2(x)(4) + 4²
= x² + 8x + 16
Thus, (x+4)² when expanded and simplified gives x² + 8x + 16.
Step-by-step explanation:
Answer:
x²n+ 8x + 16
Step-by-step explanation:
(x + 4)²
= (x + 4)(x + 4)
each term in the second factor is multiplied by each term in the first factor, that is
x(x + 4) + 4(x + 4) ← distribute parenthesis
= x² + 4x + 4x + 16 ← collect like terms
= x² + 8x + 16
For the polynomial h(x) below. -1 is a zero. Find the other zeros of h(x).
h(x) = x^3 - x^2 - 3x - 1
The other zeros of the polynomial h(x) = x^3 - x^2 - 3x - 1 can be found by factoring the polynomial using synthetic division and solving for the remaining zeros. The zeros of the polynomial are -1, approximately 1.32, and approximately -0.32.
Given that -1 is a zero of the polynomial h(x), we can use synthetic division to factor out the polynomial and find the remaining zeros. Dividing h(x) by (x + 1) using synthetic division, we have:
-1 | 1 -1 -3 -1
| -1 2 1
|_____________
1 -2 -1 0
The result is the quotient 1x^2 - 2x - 1, which is a quadratic equation. To find the remaining zeros, we can solve the quadratic equation by factoring or using the quadratic formula. Factoring the quadratic equation, we have:
1x^2 - 2x - 1 = (x - approximately 1.32)(x - approximately -0.32)
Therefore, the zeros of the polynomial h(x) are -1, approximately 1.32, and approximately -0.32.
Please note that the values of the remaining zeros are approximations and may have been rounded for simplicity.
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For questions 1-2, find the distance and midpoint of the segments given the endpoints. 1. AB with A(3, 4) and B(-1, 10) Midpoint
Given the points A(3,4) and B(-1,10), we can find the distance between them using the following function:
\(d(A,B)=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}\)then, we have the following:
\(\begin{gathered} (x_1,y_1)=(3,4)=A \\ (x_2,y_2)=(-1,10)=B \\ \Rightarrow d(A,B)=\sqrt[]{(-1-3)^2+(10-4)^2}=\sqrt[]{4^2+6^2}=\sqrt[]{16+36}=\sqrt[]{52} \\ =\sqrt[]{4\cdot13}=2\cdot\sqrt[]{13} \\ d(A,B)=2\cdot\sqrt[]{13} \end{gathered}\)Jake has 900 cm³ of material. He uses 14. 5 cm³ to make a right triangular prism. He wants to make a second prism that is a dilation of the first prism with a scale factor of 4. How much more material does Jake need in order to make the second prism? Select from the drop-down menu to correctly complete the statement. Jake needs an additional Choose. Cm³ of material to make the second prism.
A ratio shows the relation between two numbers. The amount of more material that is needed by Jake is 42.5 cm³.
What is a Ratio?A ratio shows us the number of times a number contains another number.
Given that the volume of the first prism is 14.5cm³, while the scale factor is 4. Since the scale factor is applicable to dimension, and volume is always the cube of three-dimension.
Therefore, the volume of the scaled prism will be the cube the of the volume of the first prism, which can be written as,
\(\rm \text{Volume of the Scaled prism}= (Scale\ factor)^3 \times \text{Volume of the first prism}\)
Substitute the values,
\(\rm \text{Volume of the Scaled prism}= 4^3 \times 14.5 = 928\ cm^3\)
Since, the volume of material with Jake is 900 cm³, while the material he has already used is 14.5 cm³, thus the volume of the material that is left with Jake is 885.5 cm³(900cm³-14.5cm³).
Now, since the material needed to make the scaled prism is 928 cm³, the amount of material that is with Jake is 885.5 cm³, therefore, the amount of the material that is needed by Jake to complete the scaled prism can be written as,
The Amount of more material Needed by Jake = Amount of material needed to make the scaled prism - Amount of material left with Jake
The Amount of more material Needed by Jake = 928 cm³ - 885.5 cm³
= 42.5 cm³
Hence, the amount of more material that is needed by Jake is 42.5 cm³.
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Find f(a),f(a+h), and the difference quotient
h
f(a+h)−f(a)
, where h
=0
f(x)=
x+7
x
f(a)=
f(a+h)=
We have `f(a) = (a+7)/a`, `f(a+h) = (a+h+7)/(a+h)`, and the difference quotient is `(h(a+7))/(ah+h^2)`.
Given a function `f(x)` is defined by `f(x) = (x+7)/x`.
We need to find `f(a)`, `f(a+h)`, and the difference quotient `(f(a+h)-f(a))/h` where `h≠0`.
Solution:
`f(x) = (x+7)/x`
At `x=a`, we have
`f(a) = (a+7)/a`.
At `x = a + h`,
we have `
f(a+h) = [(a+h)+7]/(a+h)`.
So,
`f(a+h) = (a+h+7)/(a+h)`.
Now,
`f(a+h)−f(a)` is `[(a+h)+7]/(a+h) − (a+7)/a`.
LCM of `(a+h)` and `a` is `a(a+h)`.
So, we get `f(a+h)−f(a)` as `(a+h)(a+7)−a(a+h+7)/a(a+h)`.
On simplification, we have `f(a+h)−f(a)` as `(ah+7h)/(a(a+h))`.
Now, `(f(a+h)−f(a))/h` is `(ah+7h)/(ah+h^2)`.
On simplification, we have `(f(a+h)−f(a))/h` as `(h(a+7))/(ah+h^2)`.
Hence, `f(a) = (a+7)/a`, `f(a+h) = (a+h+7)/(a+h)`, and the difference quotient is `(h(a+7))/(ah+h^2)`.
Given a function `f(x)` is defined by `f(x) = (x+7)/x`. We have found `f(a)`, `f(a+h)`, and the difference quotient `(f(a+h)-f(a))/h` where `h≠0`. Thus, we have `f(a) = (a+7)/a`, `f(a+h) = (a+h+7)/(a+h)`, and the difference quotient is `(h(a+7))/(ah+h^2)`.
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On tax-free weekend, Miss Bailey plans to purchase 25 iPad minis for her class. The price of an iPad mini is $329. Use a strategy to determine the amount she will spend.
Explain your reasoning using models or pictures and words.
Answer:
$8225
Step-by-step explanation:
329 (amount for each ipad mini) x 25 (amount of ipad minis Missbailey is going to buy) = 8225.
Find an equation of the tangent line to the curve xey yex = 4 at the point (0, 4).
An equation of the tangent line to the curve \(x e^y+y e^x=4\) at the point (0, 4) is \(y=-(4+e^4) x+4\).
What is tangent?A tangent is described as a line that intersects a circle or an ellipse only at one point. If a line touches a curve at P, the point "P" is known as the point of tangency.
Now according to the question;
To obtain the tangent at a given point, we must first obtain the slope at that point by obtaining the differentiation value at that point \(\left.y^{\prime}\right|_{x=0, y=4}\) as-
Consider the given equation;
\(x e^y+y e^x=4\)
Differentiate both side with respect to x;
\(\begin{aligned}&\frac{d}{d x}\left(x e^y+y e^x\right)=\frac{d}{d x} 4 \\&\frac{d}{d x} x e^y+\frac{d}{d x} y e^x=0\end{aligned}\)
Now apply product rule;
\(\begin{aligned}&e^y \frac{d}{d x} x+x \frac{d}{d x} e^y+e^x \frac{d}{d x} y+y \frac{d}{d x} e^x=0 \\&e^y \frac{d}{d x} x+x \frac{d}{d y} e^y \cdot y^{\prime}+e^x y^{\prime}+y \frac{d}{d x} e^x=0\end{aligned}\)
Applying exponential and power rule;
\(\begin{aligned}&e^y \cdot 1+x e^y \cdot y^{\prime}+e^x y^{\prime}+y e^x=0 \\&\left(x e^y+e^x\right) y^{\prime}=-y e^x-e^y\end{aligned}\)
Solve the value of y'
\(y^{\prime}=\frac{-y e^x-e^y}{x e^y+e^x}\)
Now, find the value of slope m.
\(m=\left.y^{\prime}\right|_{x=0, y=4}\)
\(\frac{-4 \cdot e^0-e^4}{0 e^4+e^0}=-4-e^4\)
Now, using the point-slope formula, obtain the line equation as follows.
\(\begin{aligned}&\left(y-y_1\right)=m\left(x-x_1\right) \\&(y-4)=-(4+e^4) \cdot(x-0) \\&y=-(4+e^4) x+4\end{aligned}\)
Therefore, an equation of the tangent line to the curve is \(y=-(4+e^4) x+4\).
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Solve the following:
32 ÷ 4 + 4 x 8 = ?
A. 42
B. 32
C. 96
D. 40
Answer:
Step-by-step explanation: 40 see attachment
explain how to graph y= -3/2 x + 4
Answer:
y = 3 x - 4
Step-by-step explanation:
Los salarios mensuales de los empleados en una tienda minorista tenía un valor medio de
US$3500 y una desviación estándar US$250. En el fin de año todos recibieron un
aumento de US$100. Escriba el valor de la nueva media y la nueva desviación estándar
As a result, with the US$100 increase, the average monthly wage for employees would be US$3600, while the standard deviation would remain at US$250.
After the increase of US$100, the following will be the new average for employee monthly salaries:
Nueva media = previous media plus an increase, or US$3500 plus US$100, or US$3600.
The standard deviation does not change with an increase in sueld, so the new standard deviation would continue to be:
new standard deviation = previous standard deviation equals $250
As a result, with the US$100 increase, the average monthly wage for employees would be US$3600, while the standard deviation would remain at US$250.
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I need help please I am confused
Answer:
1) 44
2) 430
3) 17
Step-by-step explanation:
1) 4 × 4 = 16, and 4 + 4 = 8.
2) The units digit is 0. Since the hundreds digit is one more than the tens digit, and since the sum of the three digits is 7, the hundreds digit is 4, and the tens digit is 3.
3) 1 × 7 = 7, and 1 + 7 = 8. The units digit is 7, and the tens digit is 1.
Simplify:
Radical 27 + radical 81
Answer:
√3+3 or 4.73205080
I hope this is correct
Step-by-step explanation:
Given:
\( \cfrac{ \sqrt{27} + \sqrt{81} }{3}\)
Solution:
\( = \cfrac{ \sqrt{27} + \sqrt{9 {}^{2} } }{3} \)
\( = \cfrac{3 \sqrt{3} + 9 }{3}\)
\( = \cfrac{3 \sqrt{3} + 3 \times 3}{3}\)
\( = \cfrac{3 (\sqrt{3} + 3)}{3}\)
\( = \cfrac{ \cancel{3}( \sqrt{3} + 3) }{ \cancel3} \)
\( = \sqrt{3} + 3\)
\( \approx4.7\)