(a) To calculate the magnitude of the magnetic field B at a distance r = 70 mm from the axis of symmetry, we can use Ampere's Law.
I_enclosed = (displacement current density) * (area of the loop)
= 23 A/m^2 * π * (0.07 m)^2
= 23 * 0.049 * π A
Ampere's Law states that the line integral of the magnetic field around a closed loop is equal to the product of the current enclosed by the loop and the permeability of free space.
In this case, since the displacement current is uniform and has a magnitude of 23 A/m^2, the total current enclosed by a circular loop of radius r = 70 mm can be calculated as:
I_enclosed = (displacement current density) * (area of the loop)
= 23 A/m^2 * π * (0.07 m)^2
= 23 * 0.049 * π A
Now, using Ampere's Law: ∮ B · dl = μ₀ * I_enclosed
B * 2πr = μ₀ * (23 * 0.049 * π)
Simplifying and solving for B, we have:
B = (μ₀ * 23 * 0.049) / (2 * r)
Substituting the given values, we get:
B = (4π * 10^-7 T·m/A * 23 * 0.049) / (2 * 0.07 m)
B ≈ 0.047 T
Therefore, the magnitude of the magnetic field B at a distance of 70 mm from the axis of symmetry is approximately 0.047 T.
(b) To calculate dE/dt in this region, we need to use Faraday's Law of electromagnetic induction, which states that the induced electromotive force (emf) in a closed loop is equal to the negative rate of change of magnetic flux through the loop.
Since the magnetic field B is constant in this case, the rate of change of magnetic flux is zero, and therefore dE/dt is zero. So, in this region, the rate of change of the electric field is zero.Hence, dE/dt = 0 in this region.
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In the reaction 2H, + O, → H,0, what coeficient should be placed in front of H,0 to balance the reaction?
Which diagram best shows the results of removing heat from the original sample until it freezes?
Answer:
b
Explanation:
the closest molecules are in b witch would be a solid
You're lying on the sand on a breezy day when a pesky fly wishes to join you. The breeze is blowing at a steady 2 m/s. In order for the fly to land on you, it should hover over you while flying:
a. against the breeze at 2 m/s.
b. with the breeze at 2 m/s.
c. a bit faster than 2 m/s.
d. about 4 m/s relative to the breeze.
When the breeze is blowing at a steady 2 m/s, the pesky fly should hover over you while flying is about 4 m/s relative to the breeze (Option D).
The fly needs to compensate for the effect of the breeze in order to land on you. If it flies at the same speed as the breeze (option B), it will simply be carried past you. If it flies against the breeze at the same speed (option A), it will be pushed back and not make any progress towards you.
To counteract the effect of the breeze, the fly needs to fly faster than the speed of the breeze. The exact speed depends on the direction the fly is coming from and the angle of the breeze, but in general it needs to fly at about twice the speed of the breeze (option D) to be able to hover in place above you and land on you.
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Impulse equals?
A) momentum x velocity
B) momentum x time
C) mass x velocity
Answer:
B
Explanation:
The impulse experienced by an object is the force•time.
In one of Gregor Mendel's first experiments, he crossed a purple-flowered pea plant (PP) with a white-flowered pea plant (pp).
According to the question the result of Mendel's experiment was that all of the offspring had purple flowers (Pp).
What is offspring?Offspring is a term used to refer to the progeny or descendants of any organism. It is usually used to refer to the biological children of a couple, but can also be used to refer to the descendants of any lineage. The term can also be used to refer to the progeny of plants, animals, and other organisms. Offspring is the result of the reproductive process, when two individuals combine their genetic material through sexual reproduction to produce a new organism. It is the continuation of the species, and the new individual contains genetic material from both of its parents. Offspring can also be produced through asexual reproduction, in which only one organism is involved in the process.
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9. According to statistical theory, 68% of your measurements of time should fall within the range of and of therefore about 3 of your 5 measurements should satisfy this condition. How many of your measurements fall within this range? Are your errors random according to this theory?
Answer:
Yes
Explanation:
Yes, this is a random error generating because of statistical constraint. We only have finite number of data points. As per this, if we plot our observation we will get a gaussian (inverse bell ) shaped curve with mean equal to central value.
____________ are forces in which two interacting objects are physically in contact with each other; examples include ___________ and ______________. a. Contact forces , friction, air resistance c. Action-at-a-distance fields , gravity, electric field b. Contact forces , gravity, electric field d. None of the above. Please select the best answer from the choices provided A B C D
a. Contact forces, friction, air resistance
Location B Location D and Location C!!!
Answer:
You have to click "Tap me to Toggle Through Answer Options"
Explanation:
Im pretty sure.
Caroline uses 20 N of force to move a box of books 10 m. How much work
did she do?
Work = (force) x (distance)
Work = (20 N) x (10 m)
Work = 200 Joules
7. The Earth orbits the sun at 25.42 km/s. What is this in mph (1 mile = 1.609
km)?
Answer:
40.90 mph if I did the math right
The inside of a Carnot refrigerator is maintained at a temperature of 277 K, while the temperature in the kitchen is 287 K. Using 2250 J of work, how much heat can this refrigerator remove from its inside compartment?
|QC| = ? J
The Carnot refrigerator operates on the principle of transferring heat from a cooler region to a hotter region with the help of external work. The amount of heat that the refrigerator can remove from its inside compartment can be determined using the equation:
QC = W*(TC/TH - 1)
Efficiency (η) = (Tc / (Th - Tc))
Where Tc is the cold temperature (inside the refrigerator) and Th is the hot temperature (kitchen temperature). In this case, Tc = 277 K and Th = 287 K.
First, calculate the efficiency:
η = 277 / (287 - 277) = 277 / 10 = 0.277
Next, we can use the formula for the heat removed from the inside compartment, which is given by:
Qc = W / η
Where Qc is the heat removed and W is the work done. In this case, W = 2250 J.
Finally, calculate the heat removed:
Qc = 2250 / 0.277 ≈ 8103 J
So, the refrigerator can remove approximately 8103 Joules of heat from its inside compartment using 2250 Joules of work.
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What safety precautions should be taken when working on a hybrid electric vehicle?
Answer:
Always disconnect the high-voltage hybrid battery before doing any major repair work or electrical work, he recommends
Explanation:
Most manufacturers also recommend waiting at least 10 minutes before working on the vehicle after the battery has been isolated or disconnected.
Michelle drops a 15kg box off of the Eiffel Tower. After 3 seconds, how fast is the box moving in m/s? (Neglect air resistance.)
What do comets and asteroids have in common?
Answer:
Asteroids and comets have a few things in common. They are both celestial bodies orbiting our Sun, and they both can have unusual orbits, sometimes straying close to Earth or the other planets. They are both “leftovers” — made from materials from the formation of our Solar System 4.5 billion years ago. But there are a few notable differences between these two objects, as well. The biggest difference between comets and asteroids, however, is what they are made of.
While asteroids consist of metals and rocky material, comets are made up of ice, dust, rocky materials and organic compounds. When comets get closer to the Sun, they lose material with each orbit because some of their ice melts and vaporizes. Asteroids typically remain solid, even when near the Sun.
Right now, the majority of asteroids reside in the asteroid belt, a region between the orbits of Mars and Jupiter which may hold millions of space rocks of varying sizes. On the other hand, the majority of comets are in the farthest reaches of our Solar System: either 1. in the Kuiper Belt — a region just outside the orbit of the dwarf planet Pluto that may have millions of icy comets (as well as many icy dwarf planets like Pluto and Eris); or 2. the Oort Cloud, a region where trillions of comets may circle the Sun at huge distances of up to 20 trillion kilometers (13 trillion miles).
Answer:
they are both leftovers materials
Explanation:
think about how the solar system is made the comets and asteroids are both rocks and remains of the solar system
Mateo moved the teacher's table with 50 N of force for 2 meters.. How
much work is done in pushing the table?
Statement:
Mateo moved the teacher's table with 50 N of force for 2 meters.
To find out:
The work done in pushing the table.
Solution:
Force (F) = 20 NDisplacement (s) = 2 mAngle between displacement and force (θ) = 0We know, work is said to be done when force acting on a body produces motion in the direction of force applied.And the formula for work done isF s Cos(θ)Therefore, the work done in pushing the table= 50 × 2 × Cos (0°) J= 100 × 1 J= 100 JAnswer:
The work done in pushing the table is 100 J.
Hope it helps.
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Two airplanes leave an airport at the same time. The velocity of the first airplane is 650 m/h at a heading of 16.9 ◦ . The velocity of the second is 590 m/h at a heading of 161◦ . How far apart are they after 1.8 h? Answer in units of m.
Distance of train after 1.8 h is 485.099 m
Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in ordinary language.
Distance of the first plane = 650 x 1.8 = 1170 m
Distance of the second plane = 590 x 1.8 = 1062m
The angle between 2 planes
161◦ - 16.9◦ = 144.1°
Using the law of cosine
d^2 = (1170)^2 + (1062)^2 - 2*1170*1062*cos 144.1°
d = 485.099 m
Hence, distance of train after 1.8 h is 485.099 m
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Pleaseeeee help me with b, c, and d. There are no angles.
Answer:
a. 150 J
b. 150 J
c. 0 J
d. 0 J
Explanation:
The given parameters are;
The horizontal force with which the man pulls the canister, F = 50 N
The distance he moves the vacuum cleaner, d = 3.0 m
a. Work done, W = Force applied, F × Distance moved by the force, d
Therefore, for the work done by the 50 N force on the canister, we have;
W = 50 N × 3.0 m = 150 N·m = 150 J
b. Given that he pulls the canister at a constant speed, we have;
The acceleration of the canister, a = 0 m/s²
Therefore, the net force on the canister, \(F_{NET}\) = F - \(F_{Friction}\) = m × a
Where;
m = The mass of the canister
a = The acceleration of the canister
F = The applied force = 50 N
\(F_{Friction}\) = The force of friction
∴ \(F_{NET}\) = m × a = m × 0 m/s² = 0 N
Therefore;
\(F_{NET}\) = F - \(F_{Friction}\) = 0 N
From which we have;
F = \(F_{Friction}\) = 50 N (The applied force, F is equal to the force of friction,
The work done by friction = The force of friction × The distance in which the force of friction acts
∴ The work done by friction = \(F_{Friction}\) × d - 50 N × 3.0 m = 150 J
The work done by friction = 150 J
c. The normal force, N acts perpendicular to the force of friction
The distance the canister moves in the perpendicular direction, \(d_p\) = 0 m
∴ The work done by the normal direction = N × \(d_p\) = N × 0 m = 0 J
The work done by the normal direction = 0 J
d. The vacuum weight, W, acts on the same line as the normal force but in the opposite direction to the normal force, N
Therefore, the weight, W, acts perpendicular to the line of motion of canister
The distance the canister moves in the direction of the weight, \(d_{wieght}\) = 0 m
Therefore, the work done by the weight = W × \(d_{wieght}\) = W × 0 m = 0 J
The work done by the weight = 0 J
Which is the correct quark pairing?
A. top with down, up with bottom, strange with charm
B. top with bottom, up with down, strange with charm
C. top with strange, down with bottom, charm with up
D. charm with down, top with up, strange with bottom
Answer:B make sure it’s the same order
Explanation:
Correct on Plato
Wanda is taking photos using a lens that sees and records a very narrow view with a focal length longer than 60mm. When her friend asks what type of lens she is using for their photography outing, how does Wanda reply
Wanda can reply to her friend by saying that she is using a telephoto lens for their photography outing.
A telephoto lens is a type of camera lens that is designed to capture distant subjects by using a longer focal length than a standard lens. Telephoto lenses typically have a focal length of 60mm or longer, which allows them to see and record a very narrow view. This makes them ideal for capturing subjects that are far away, such as wildlife, sports events, and landscapes. Telephoto lenses are also popular for portrait photography because they can create a shallow depth of field, which helps to isolate the subject from the background.
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how does energy makes its way from the nuclear core of the sun to its atmosphere? choose the correct order for each layer.
That power increases. The sun's core can reach temperatures of 27 million degrees Fahrenheit. The convective zone, which is a sizable region, is where the energy moves outward.
What are wave amplitude and energy transport?
Transport of Energy and Wave Amplitude As was already explained, a wave is a phenomena that moves energy through a medium without moving any physical objects. When someone grips the first coil of a slinky and moves it back and forth, a pulse or wave is created.
What is the process of energy transfer in nature?
In nature, such just like in a coastal habitat, contains the details and transformations take place continuously. The sun's thermal radiation heats both the ground and the ocean.
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A cylindrical 4. 31 kg pulley with a radius of 0. 294 m is used to lower a 6. 27 kg bucket into a well. The bucket starts from rest and falls for 3. 55 s. The acceleration of gravity is 9. 8 m/\(s^{2}\)
What is the angular acceleration of the cylindrical pulley?
Answer in units of rad/\(s^{2}\)
The net torque on the pulley can be calculated as follows:
T = I * alpha
where
I = (1/2) * m * r^2 (moment of inertia of a cylinder)
m = 4.31 kg (mass of pulley)
r = 0.294 m (radius of pulley)
alpha (angular acceleration)
The gravitational force on the bucket creates a tension in the rope, which provides the torque on the pulley.
T = (m_bucket + m_pulley) * g * r
Equating the two expressions for T and solving for alpha, we get:
alpha = (m_bucket + m_pulley) * g * r / ((1/2) * m_pulley * r^2)
m_bucket = 6.27 kg
Substituting the values, we get:
alpha = (6.27 + 4.31) * 9.8 * 0.294 / ((1/2) * 4.31 * 0.294^2)
alpha = 11.58 rad/s^2
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Is a fine for speeding based of the average speed or the instantaneous speed? Explain
Answer: Therefore, the instantaneous speed is only the answer, because, the detector can only detect the instantaneous speed but not the average speed.
Explanation:
"The gravity of body is not necessary on body. " justify
Answer:
Answer: there are two factors on which centre of mass depends
*its shape and
*the way mass distributed on its shape.
These two factor decide whether centre of mass of gravity lie inside the body or outside the body.
If the body is regular the centre of mass lies inside the body if it is not regular then it lies outside the body
Explanation:
Why are digital signals more reliable in transmitting information than analog signals?
Answer:
Digital signals are a more reliable form of transmitting information because an error in the amplitude or frequency value would have to be very large in order to cause a jump to a different value. Signals are composed of infinite possible values. Signals are composed of only two possible values: 0 or 1.
Explanation:
Use the ideal gas law, PV=nRT to solve. R=0.0821
If I have 15 moles of gas at a temperature of 299K and a volume of 92L, what is the pressure of the gas?
Answer:
The pressure of the gas=4.002 atm
Explanation:
We are given that
R=0.0821
Number of moles, n=15
Temperature, T=299 K
Volume of gas, V=92 L
We have to find the pressure of the gas.
\(PV=nRT\)
Substitute the values
\(P\times 92=15\times 0.0821\times 299\)
\(P=\frac{15\times 0.0821\times 299}{92}\)
\(P=4.002 atm\)
Hence, the pressure of the gas=4.002 atm
Answer:
According to the ideal gas law equation,
PV = nRT (here, P = 5.5 atm, V = 10L, T = 298K, R = 0.0821 atmL/mol K)
or, n = RT/PV = (0.0821 X 298)/(5.5 X 10) = 0.44 moles of He gas
Explanation:
A car traveled 1 hour at a contanst velocity of 65 mph west with cruise control. The acceleration is
summary on scaler quantity
Answer:
A quantity which does not depend on direction is called a scalar quantity. Vector quantities have two characteristics, a magnitude and a direction. Scalar quantities have only a magnitude. When comparing two vector quantities of the same type, you have to compare both the magnitude and the direction.
I rarely share my notes. But these are my last year notes, so I can share with you. Click on the photo to view the answer.
A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
The work done in the given case is 0
\( \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}\)
For calculating the work done by an object we apply the formula, that is ~
\(f \times s \times \cos( \theta) \)where f represents force applied, and s represents displacement.
but here, the displacement is zero since the wall didn't move at all, Therefore If we plug it's value as 0, we get
\(f = 0 \times s \times \cos( \theta) \)hence,
\(work \: done = 0\)So therefore, we can conclude that the man hasn't done any work.
Hope it helps.
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A 0.0500-kg ice cube at −30.0ºC is placed in 0.400 kg of 35.0ºC water in a very well-insulated container. What is the final temperature?
The amount of heat that is gained by water is equal to the amount of heat loss by the ice. Therefore, we have the following relationship:
\(-Q_w=Q_i\)Where "Qw" is the heat of water and "Qi" is the heat of ice. The heat of water is given by:
\(Q_w=m_wC_w(T_f-T_{0w})\)The amount of heat of ice must be calculated for the two states, solid and liquid. For the solid-state the temperature will be from -30 degrees to 0 degrees, therefore, we have:
\(Q_i=m_iC_i(T_f-T_{0i})\)Where Ci is the specific heat of ice in solid-state and is equal to:
\(C_i=2090\frac{kJ}{\operatorname{kg}}\)Replacing the values:
\(Q_i=(0.05\operatorname{kg})(2090\frac{kJ}{\operatorname{kg}K})(0-(-30C))\)Solving the operations we get:
\(Q_i=3135J\)Now we need to determine the amount of heat that needs the ice to convert into liquid. This is given by:
\(Q_{i-l}=m_iL_f\)Lf is the latent heat of ice and is equal to:
\(L_f=334\frac{kJ}{\operatorname{kg}}\)Replacing the values we get:
\(Q_{i-l}=(0.05\operatorname{kg})(334\frac{kJ}{\operatorname{kg}})\)Solving the operations:
\(Q_{i-l}=16.7kJ=16700J\)Now we need the amount of heat of liquid ice to its final temperature, this is given by:
\(Q_l=m_iC_l(T_f-0)\)Applying the relationship:
\(-m_wC_w(T_f-T_{0w})=m_iC_i(T_f-T_{0i})+m_iL_f+m_iC_w(T_f-0)\)Cw is the specific heat of water and is equal to:
\(C_w=4184\frac{J}{\operatorname{kg}K}\)And the specific heat of ice is:
\(C_i=4184\frac{J}{\operatorname{kg}K}\)Replacing the values. The first two terms on the right side we already calculated and the final temperature is the same for both:
\(-(0.4\operatorname{kg})(4184\frac{kJ}{\operatorname{kg}K})(T_f-35)=3135J+16700J+(0.05)(4184\frac{kJ}{\operatorname{kg}K})(T_f)\)Solving operations:
\(-1673.6\frac{kJ}{K}(T_f-35)=19835J+209.2\frac{kJ}{K}T_f\)Now we solve for the final temperature:
\(-1673.6T_f+58576=19835+209.2T_f\)Subtracting 19835 to both sideS:
\(\begin{gathered} -1673.6T_f+58576-19835=209.2T_f \\ -1673.6T_f+38741=209.2T_f \end{gathered}\)Now we add 1673Tf to both sides:
\(\begin{gathered} 38741=209.2T_f+1673.6T_f \\ 38741=1882.8T_f \end{gathered}\)Now we divide both sides by 1882.2
\(\frac{38741}{1882.8}=T_f\)\(20.57=T_f\)Therefore, the final temperature is 20.57 °C. This value can be converted into Kelvin using the following relationship:
\(T_K=T_C+273.15\)Replacing the temperature:
\(T_K=20.57+273.15=293.72\)Therefore, the final temperature is 293.72 K.
an aluminum bar of mass 2.00 kg at 300 ∘c is thrown into a lake. the temperature of the water in the lake is 15.0 ∘c; the specific heat capacity of aluminum is 900 j/(kg⋅k) .
The aluminum bar loses 513,000 J of heat as it cools down to the lake water temperature.
Explanation:
To find the heat lost by the aluminum bar as it cools down to the water temperature, you should follow these steps:
Step1. Determine the initial temperature of the aluminum bar: 300°C
Step2. Determine the final temperature of the aluminum (lake water temperature): 15°C
Step3. Calculate the temperature difference:
ΔT = (initial temperature - final temperature) = (300 - 15)°C = 285°C
Step4. Find the mass of the aluminum bar 2.00 kg
Step5. Find the specific heat capacity of aluminum 900 J/(kg⋅K)
Step6. Calculate the heat lost by the aluminum:
Q = mass × specific heat capacity × ΔT = 2.00 kg × 900 J/(kg⋅K) × 285°C = 513,000 J
So, the aluminum bar loses 513,000 J of heat as it cools down to the lake water temperature.
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