answer these questions plz​

Answer:

N = q / e    where q is the total charge on the ion and e = 1.6E-19 the charge on an electron or N = coulombs / (coulombs / electron)

Answer:

A.) 18 m/s

B.) 12 m/s

Explanation:

Given that a school bus moves at 15 m/s relative to an outside observer. If a student walks toward the front of the bus at 3 m/s relative to the bus, how fast is the student moving relative to the observer ?

Since the student direction is in the direction of the bus, the student velocity relative to the bus velocity will be:

15 + 3 = 18 m/s

Therefore, the observer will see the student moving very fast at a speed of 18 m/s

 If the same student turns around and walks to the back of the bus at 3 m/s, the student will be moving in an opposite direction. The relative velocity of the student to the observer will be 15 - 3 = 12 m/s

Therefore, the observe will see the student moving very fast at a speed of 12 m/s

Electrical forces dominate between atoms that are close together because they arise from the interaction of charged particles.

Atoms consist of positively charged protons in the nucleus and negatively charged electrons in orbit around the nucleus. The electrical force, also known as the electromagnetic force, is responsible for the attraction between opposite charges (positive and negative) and the repulsion between like charges (positive and positive or negative and negative). When atoms are close together, their electron clouds start to overlap, resulting in the interaction between the charged particles. The electrons in one atom are attracted to the positively charged nucleus of the neighboring atom, creating an attractive electrical force. This force is responsible for holding atoms together in molecules or forming ionic bonds between positively and negatively charged ions.The strength of the electrical force between atoms depends on the magnitude of the charges and the distance between them. When atoms are closer, the distance between their charges decreases, leading to a stronger electrical force dominating the interaction. This is why electrical forces become more significant when atoms are in close proximity to each other.

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The magnitude of the resultant force (in nano-newtons) on the 9nc charge at the origin is 0nN.

The magnitude of the resultant force on the 9nC charge at the origin can be calculated using Coulomb's law. The equation is F = kQq/r2, where F is the magnitude of the force, k is the Coulomb constant (8.98755 x 10^9 N·m2/C2), Q and q are the charges of the two objects, and r is the distance between them. Since the charge at the origin is 9nC (0.000009 C) and the distance is 0, the resultant force is 0nN.

F = kQq/r2

Q =  9nC (0.000009 C)

r = 0 ; q = 0C

Coulomb constant "k" = 8.98755 x 10^9 N·m2/C2

put the value of "k", "Q", "q", "r" in F = kQq/r2

we get F = 0nN.

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Answer:

5 metre.

Explanation:

Wavelength = Velocity / Frequency

= 23,000/ 4,500

= 5 metre.

In the given situation, the ships are sighted due west from a height of 50 meters above sea level on a cliff. The angles of depression are 61°  and 28° . The two ships are approximately 56.38 meters apart.

Let AB and CD be the two ships, and let E be the point on the cliff where they are sighted. Then, we have:

From E, draw lines perpendicular to AB and CD, meeting them at points F and G, respectively.

Also, let the distance between the two ships be x meters.

Using the trigonometric ratios for the right-angled triangles EFB and EGC, we can write:

tan 28° = BF/EB and tan 61° = CG/EG

Multiplying the two equations, we get:

tan 28° × tan 61° = BF/EB × CG/EG

Substituting the values, we get:

(0.531) x = BF/EB × CG/EG

Thus, the distance between the two ships is given by:

x = 50/(BF/EB × CG/EG)

Therefore, we need to find the values of BF/EB and CG/EG.

Using the trigonometric ratios, we can write:

BF/EB = tan 61° and CG/EG = tan 28°

Substituting the values, we get:

BF/EB = 1.969 and CG/EG = 0.531

Therefore, the distance between the two ships is:

x = 50/(BF/EB × CG/EG)

x = 50/(1.969 × 0.531)

x = 56.38 meters (approximately)

Thus, the two ships are approximately 56.38 meters apart.

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Answer:

5.08cm³

Explanation:

Given parameters

The larger cube has twice the mass of the smaller cube

Mass of smaller cube = 20g

Mass of the larger cube = 2 x 20  = 40g

Density of the smaller cube  = 7.87g/cm³

Unknown:

Volume of the larger cube = ?

Solution:

Density is the mass per unit volume of substance. For all samples of a substance, the density value is the same.

So, the density of the small and large iron is the same

   Density  = \(\frac{mass}{volume}\)  

        Volume  = \(\frac{mass}{density}\)  

 So;

  Volume of larger cube  = \(\frac{40}{7.87}\)  = 5.08cm³

Answer:

5.08cm^3

Explanation:

Answer: D

Explanation:

Answer:

500kg

Explanation:

mass = newtons/force divided by the acceleration rate

m = 30,000/60

m = 500

Answer:

The heat capacity of a body is defined as the heat required to raise it's temperature by me degree or one kelvin.while specific heat capacity of a substance is defined as the heat required to the temperature of a unit mass of it through one degree or one kelvin.

I hope it helps

you can eat burrito with hot taco and if school like?

Answer:

false is the answer . in my point of view

Answer:

has more energy, has a greater amplitude, has a higher frequency

Explanation:

The life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

The life expectancy of a star is determined by its mass and luminosity. The more massive and luminous the star is, the shorter its life expectancy is. Hence, using this information, we can estimate the life expectancy of the following stars:a) 0.2-solar mass, 0.01-solar luminosity red dwarfRed dwarfs are known to have the longest life expectancies among all types of stars. They can live for trillions of years.

Hence, a 0.2-solar mass, 0.01-solar luminosity red dwarf is expected to have a much longer life expectancy than the Sun. It could live for up to 10 trillion years or more.b) 3-solar mass, 30-solar luminosity starA 3-solar mass, 30-solar luminosity star is much more massive and luminous than the Sun. As a result, it will have a much shorter life expectancy than the Sun.

Based on its mass and luminosity, it is estimated to have a lifetime of around 10 million years.c) 10-solar mass, 1000-solar luminosity starA 10-solar mass, 1000-solar luminosity star is extremely massive and luminous. It will burn through its fuel much faster than the Sun, resulting in a much shorter life expectancy. Based on its mass and luminosity, it is estimated to have a lifetime of only around 10 million years as well.

Therefore, the life expectancy of the given stars are:a) 0.2-solar mass, 0.01-solar luminosity red dwarf: 10 trillion yearsb) 3-solar mass, 30-solar luminosity star: 10 million yearsc) 10-solar mass, 1000-solar luminosity star: 10 million years.

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To find the volume of the solid obtained by rotating the region, we will need some more information, such as the function or shape of the region, the axis of rotation, and the interval of rotation. The terms you should be familiar with are:
1. Volume: The measure of the amount of space occupied by a solid figure.
2. Solid: A three-dimensional geometric figure.
3. Rotation: Turning a shape around a fixed point or axis.
4. Region: An area enclosed by a curve or boundaries.
5. Axis of rotation: The line around which the region is rotated to form the solid.
Once you provide these details, I'd be happy to help you find the volume of the solid obtained by rotating the region.

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Answer:

don't know sorry for the irreverent answer..

Answer:

The index of refraction varies with frequency, it doesn't change as light travels from one medium to another, As violet colour has the shortest wavelength and so the refractive index is maximum for it.

The electric field created by a point charge is given by the equation E = k * (Q / \(r^{2}\)).The charge of object A is -1.11 × \(10^{-9}\) C (option b).

In this case, the electric field at point P is 40.0 N/C directed to the south. Since the field is directed towards the south, the charge of object A must be negative. Plugging the given values into the equation, we have:

40.0 N/C = (9 × \(10^{9}\) N \(m^2/C^2\)) * (Q / (0.250 \(m)^2)\)

Simplifying the equation, we can solve for Q:

Q = (40.0 N/C) * (0.250 \(m)^2\) / (9 × 10^9 N \(m^2/C^2)\)

Calculating the expression, we find Q ≈ -1.11 × \(10^{-9}\) C. Therefore, the charge of object A is approximately -1.11 × \(10^{-9}\) C, which corresponds to option b.

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The mass flow rate of the pump is 2.8 kg/s.

Given the density of the oil (kerosene) to be ρ= 0.75 kg/L

The volume of oil is equal to 10,000 L1 L = 0.001 m³Volume of oil = 10,000 × 0.001 = 10 m³Density of oil = mass/volume ⇒ mass = density × volume

Let m be the mass of oil.

m = ρV = 0.75 × 10 = 7.5 kg

The time taken to empty the tank is 45 minutes. 1 minute = 60 seconds

The time taken is t = 45 × 60 = 2,700 seconds.

Let the mass flow rate be m′. The mass flow rate is defined as the mass of fluid flowing per unit time.m′ = m/t = 7.5/2,700 kg/s= 0.00278 kg/s

Therefore, the mass flow rate of the pump is 2.8 kg/s.

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The provided circuit has a 1 ohm equivalent resistance across its two endpoints, A and B.

If R 3 and R 4 were parallel in R", then the resistance would be 1 ohm.

Calculate R' and R" now:

where R' is one ohm and R" is one ohm

formula: R'+R"=1+1=2 ohm

The other R"' and R"" are likewise calculated in parallel when we do so:

The whole resistance is therefore 1 ohm.

1 ohm is the ultimate response.

Electrical resistance is a force that opposes the passage of current and is hence resistance to electricity. In this sense, it acts as a gauge for the difficulty of current flow. Ohms () are used to measure resistance.

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Answer: 18

Explanation:

i think

Answer: 30

Explanation: ck-12 momentum and impulse

The race car has a greater momentum.

In Physics, the momentum of an object refers to its mass times its velocity. It is a vector quantity. The formula for momentum is given by:p = mv, where p is the momentum, m is the mass, and v is the velocity. When two objects collide, their momentum is conserved. This is known as the Law of Conservation of Momentum. During the collision, the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision.In this problem, we are given the mass and velocity of a race car and a truck. The momentum of the race car is given by:p = mv = 1300 kg x 80 m/s = 104,000 kgm/sThe momentum of the truck is given by:p = mv = 15,000 kg x 20 m/s = 300,000 kgm/sTherefore, the race car has a greater momentum.

The momentum of an object is calculated by multiplying its mass with velocity. In the given problem, the momentum of the race car and the truck has been calculated. The race car has a greater momentum.

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The average force on the neck of the dancer that her head exerts during a landing is 120.32N.

The weight of the dancer =64 kg.

The initial speed of the dancer =4.2m/sec.

The final speed of the dancer =0.

Time taken=0.21 sec.

Hence acceleration =(final - initial  speed)/time taken=(0-4.2)/0.21 =(-4.2)/0.21 =-20m/sec^2.

So the acceleration of the head of the body is -20 m/s^2.

Now mass of the head is about 9.4%of the body weight. So the weight of the head = (9.4 ×64)/100 =6.016 kg.

Average force is equal to mass times acceleration.

Favg = m×a =6.016×(-20) =-120.32 N.

So the magnitude of the force is 120.32N.

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This problem is related to the photoelectric effect, which describes the ejection of electrons from a metal surface when light is shone on it. The maximum kinetic energy of the ejected electrons is given by:

KEmax = hf - Φ

where h is the Planck constant, f is the frequency of the incident light, Φ is the work function of the metal, and KEmax is the maximum kinetic energy of the ejected electrons.

In this problem, we are given the wavelength of the incident light, λ = 1.50 x 10^-12 m. We can use the relationship between the speed of light, wavelength, and frequency to find the frequency of the incident light:

c = fλ

where c is the speed of light. Substituting the given values, we get:

f = c / λ = (3.00 x 10^8 m/s) / (1.50 x 10^-12 m) = 2.00 x 10^20 Hz

Next, we are told that the electrons are ejected with speeds ranging up to 2.50 x 10^8 m/s. The maximum kinetic energy of the ejected electrons is given by:

KEmax = 1/2 mv^2

where m is the mass of the electron and v is the speed of the electron.

We can use the relationship between kinetic energy, frequency, and Planck's constant to find the work function Φ:

KEmax = hf - Φ

Φ = hf - KEmax

Substituting the given values and converting units as necessary:

h = 6.626 x 10^-34 J s (Planck constant)

m = 9.11 x 10^-31 kg (mass of electron)

KEmax = 1/2 mv^2 = 1/2 (9.11 x 10^-31 kg) (2.50 x 10^8 m/s)^2 = 2.27 x 10^-18 J

f = 2.00 x 10^20 Hz

Φ = hf - KEmax = (6.626 x 10^-34 J s) (2.00 x 10^20 Hz) - 2.27 x 10^-18 J = 1.32 x 10^-18 J

Therefore, the work function of the metal is 1.32 x 10^-18 J.

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Answer:

\(\boxed {\boxed {\sf 3.335 \times 10^{-11} \ N}}\)

Explanation:

We are asked to find the force of gravity between 2 objects. The following formula is used to calculate the attractive force of gravity:

\(F_g= \frac{Gm_1m_2}{r^2}\)

G is the universal gravitational constant or 6.67 × 10⁻¹¹ N*m²/kg². 1 mass is 1 kilogram and the other mass is 2 kilograms. R is the distance between the 2 objects, or 2 meters.

Substitute the values into the formula.

\(F_g= \frac {(6.67 \times 10^{-11} \ N*m^2/kg^2)(1 \ kg)(2\ kg)}{( 2 \ m)^2}\)

Multiply the numerator. The units of kilograms squared cancel.

\(F_g= \frac {(6.67 \times 10^{-11} \ N*m^2/kg^2)(2 kg^2)}{(2 \ m)^2}\)

\(F_g= \frac {(6.67 \times 10^{-11} \ N*m^2)(2 )}{( 2 \ m)^2}\)

\(F_g= \frac {(1.334 \times 10^{-10} \ N*m^2)}{ (2 \ m)^2}\)

Solve the exponent in the denominator.

\(F_g =\frac {(1.334 \times 10^{-10} \ N*m^2)}{ 4 \ m^2}\)

The units of meters squared cancel.

\(F_g =\frac {(1.334 \times 10^{-10} \ N)}{ 4}\)

\(F_g=3.335 \times 10^{-11} \ N\)

The force of gravity between the fruit is 3.335 × 10⁺¹¹ Newtons.

Answer:

friction I would guess? you didnt leave any options.

Explanation:

Answer:

sodium hydroxide ( NaOH ) and hydrogen gas ( h2 ) is produced when water reacts with sodium in rocks

The magnitude of the electric force on the charge is 5 N.

The magnitude of force on the charge is calculated as follows;

F = Eq

where;

F = 100 N/C  x 0.05 C

F = 5 N

Thus, the magnitude of the electric force on the charge is 5 N.

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Answer:

5n downward

Explanation:

took the assignment

The resolution of a speedometer is defined as the smallest increment that the instrument can display. It is calculated by dividing the full scale reading (FSC) by the number of divisions on the scale.

The higher the number of divisions, the higher the resolution.

For example, if the speedometer has a full scale reading of 100 mph and the scale has 500 divisions, the resolution would be 100/500 = 0.2 mph.

This means the speedometer can display increments of 0.2 mph.

To improve the resolution, the number of divisions can be increased. It is important to note that the resolution of a speedometer should match the accuracy of the instrument to ensure accurate readings.

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The frequency of oscillation is approximately 686 kHz and the amplitude of oscillation is approximately 2.03 V.

The oscillator shown in the circuit is a Colpitts oscillator. The frequency of oscillation (f) and the amplitude of oscillation (A) of the output voltage (vo(t)) can be calculated using the following formulas:

f = 1 / (2π √(L1 L2 C1 C2 / (C1 C2 + C2 L1 + C2 L2)))

A = |(Ies R2 C2) / (2π f L1)|

where Ies is the emitter-to-base current of the transistor, L1 and L2 are the inductances, C1 and C2 are the capacitances, and R2 is the resistance of the circuit.

Substituting the given values:

Ies = 3 × 10⁻³⁰ A

L1 = 10 × 10⁻⁶ H

L2 = 250 × 10⁻⁶ H

C1 = 200 × 10¹² F

C2 = 0.04 × 10⁻⁶ F

R2 = 100 × 10³ Ω

We can first calculate the value of the denominator of the frequency formula:

C1 C2 + C2 L1 + C2 L2 = (200 × 10⁻¹² F) × (0.04 × 10⁻⁶ F) + (0.04 × 10⁻⁶F) × (10 × 10⁻⁶ H) + (0.04 × 10⁻⁶ F) × (250 × 10⁻⁶H) = 8.8 × 10⁻¹⁴ F

Then, we can calculate the value of the numerator under the square root:

L1 L2 C1 C2 = (10 × 10⁻⁶H) × (250 × 10⁻⁶ H) × (200 × 10⁻¹²F) × (0.04 × 10⁻⁶ F) = 2 × 10⁻¹⁸

Now we can substitute these values to calculate the frequency:

f = 1 / (2π √(2 × 10⁻¹⁸ / 8.8 × 10⁻¹⁴)) ≈ 686 kHz

Next, we can calculate the amplitude:

A = |(3 × 10⁻³⁰ A × 100 × 10³ Ω × 0.04 × 10⁻⁶ F) / (2π × 686 × 10³ Hz × 10 × 10⁻⁶ H)| ≈ 2.03 V

Therefore, the frequency of oscillation is approximately 686 kHz and the amplitude of oscillation is approximately 2.03 V.

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