Answer the question

Correct Option is. False

When two random variables, X and Y, are independent, the variance of their sum, X+Y, is equal to the sum of their individual variances. In this case, both X and Y have a variance of 20. Therefore, the variance of X+Y would be the sum of 20 and 20, which is 40, not 20.

To understand why this is the case, we can consider the definition of variance. Variance measures how spread out the values of a random variable are from its mean. When two variables are independent, their joint distribution is simply the product of their individual distributions. The variance of the sum of two independent variables is obtained by summing their variances.

In this scenario, each variable has a variance of 20. However, when we add them together, the variances do not add up. Instead, the variance of the sum is the sum of the individual variances, resulting in a variance of 40 for X+Y.

Therefore, the statement "var(X+Y)=20" is false. The correct answer is that the variance of X+Y is 40.

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Answer:

a) 28

Step-by-step explanation:

Answer:

33.2 mpg

Step-by-step explanation:

Answer:

The difference in diameter between the two ends is 1.757''

Step-by-step explanation:

Given;

length of a bar of cast iron, L =  18.125"

initial diameter of the bar, d₁ = 0.983"

final diameter of the bar, d₂ = 2.74"

The difference in diameter between the two ends of the bar is calculated as;

difference in diameter = d₂ - d₁

difference in diameter =  2.74" - 0.983"

difference in diameter = 1.757''

Therefore, the difference in diameter between the two ends is 1.757''

Answer:

The difference in temperature is 16 degrees. To find the difference, you subtract the initial temperature from the final temperature: 5 - (-11) = 16.

Step-by-step explanation:

Answer:

The difference in temperature is 16 degrees. You can find the difference by subtracting the initial temperature from the final temperature: 5 degrees - (-11 degrees) = 5 + 11 = 16 degrees

The outlier in the given data set and the reason we know it is an outlier are;

The outlier is 9.8

It is an outlier because it is the distance that is less than 10.

10.1 m, 10.1 m, 10.2 m, 10.2 m, 10.3 m, 10.1 m, 10.2 m, 9.8 m

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Answer:

0.5

Step-by-step explanation:

Distance of OL = 0 - (-5)

                         = 0 + 5

                         = 5

Distance of OK = 2(5)

                          = 10

Gradient = \(\frac{rise}{run}\)

               = \(\frac{0-(-5)}{10-0}\)

               = \(\frac{5}{10}\)

               = 0.5

Jordan would take 22 hours to drive 1,188 miles at the same speed he drove 378 miles in 7 hours.

We can use the formula:

time = distance / speed

where speed is constant, to find the time it would take Jordan to drive 1,188 miles.

The speed at which Jordan drove can be calculated as:

speed = distance / time

where distance is 378 miles and time is 7 hours.

speed = 378 / 7 = 54 miles per hour

Now, we can use the speed to find the time it would take to drive 1,188 miles:

time = distance / speed = 1,188 / 54 = 22 hours

Therefore, if Jordan can maintain the same pace, it would take him 22 hours to drive 1,188 miles.

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Let A(t) denote the amount of salt (in ounces, oz) in the tank at time t (in minutes, min).

Salt flows in at a rate of

\(\dfrac{dA}{dt}_{\rm in} = \left(17 (1 + 15 \sin(t)) \dfrac{\rm oz}{\rm gal}\right) \left(8\dfrac{\rm gal}{\rm min}\right) = 136 (1 + 15 \sin(t)) \dfrac{\rm oz}{\min}\)

and flows out at a rate of

\(\dfrac{dA}{dt}_{\rm out} = \left(\dfrac{A(t) \, \mathrm{oz}}{180 \,\mathrm{gal} + \left(8\frac{\rm gal}{\rm min} - 8\frac{\rm gal}{\rm min}\right) (t \, \mathrm{min})}\right) \left(8 \dfrac{\rm gal}{\rm min}\right) = \dfrac{A(t)}{180} \dfrac{\rm oz}{\rm min}\)

so that the net rate of change in the amount of salt in the tank is given by the linear differential equation

\(\dfrac{dA}{dt} = \dfrac{dA}{dt}_{\rm in} - \dfrac{dA}{dt}_{\rm out} \iff \dfrac{dA}{dt} + \dfrac{A(t)}{180} = 136 (1 + 15 \sin(t))\)

Multiply both sides by the integrating factor, \(e^{t/180}\), and rewrite the left side as the derivative of a product.

\(e^{t/180} \dfrac{dA}{dt} + e^{t/180} \dfrac{A(t)}{180} = 136 e^{t/180} (1 + 15 \sin(t))\)

\(\dfrac d{dt}\left[e^{t/180} A(t)\right] = 136 e^{t/180} (1 + 15 \sin(t))\)

Integrate both sides with respect to t (integrate the right side by parts):

\(\displaystyle \int \frac d{dt}\left[e^{t/180} A(t)\right] \, dt = 136 \int e^{t/180} (1 + 15 \sin(t)) \, dt\)

\(\displaystyle e^{t/180} A(t) = \left(24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t)\right) e^{t/180} + C\)

Solve for A(t) :

\(\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) + C e^{-t/180}\)

The tank starts with A(0) = 15 oz of salt; use this to solve for the constant C.

\(\displaystyle 15 = 24,480 - \frac{66,096,000}{32,401} + C \implies C = -\dfrac{726,594,465}{32,401}\)

So,

\(\displaystyle A(t) = 24,480 - \frac{66,096,000}{32,401} \cos(t) + \frac{367,200}{32,401} \sin(t) - \frac{726,594,465}{32,401} e^{-t/180}\)

Recall the angle-sum identity for cosine:

\(R \cos(x-\theta) = R \cos(\theta) \cos(x) + R \sin(\theta) \sin(x)\)

so that we can condense the trigonometric terms in A(t). Solve for R and θ :

\(R \cos(\theta) = -\dfrac{66,096,000}{32,401}\)

\(R \sin(\theta) = \dfrac{367,200}{32,401}\)

Recall the Pythagorean identity and definition of tangent,

\(\cos^2(x) + \sin^2(x) = 1\)

\(\tan(x) = \dfrac{\sin(x)}{\cos(x)}\)

Then

\(R^2 \cos^2(\theta) + R^2 \sin^2(\theta) = R^2 = \dfrac{134,835,840,000}{32,401} \implies R = \dfrac{367,200}{\sqrt{32,401}}\)

and

\(\dfrac{R \sin(\theta)}{R \cos(\theta)} = \tan(\theta) = -\dfrac{367,200}{66,096,000} = -\dfrac1{180} \\\\ \implies \theta = -\tan^{-1}\left(\dfrac1{180}\right) = -\cot^{-1}(180)\)

so we can rewrite A(t) as

\(\displaystyle A(t) = 24,480 + \frac{367,200}{\sqrt{32,401}} \cos\left(t + \cot^{-1}(180)\right) - \frac{726,594,465}{32,401} e^{-t/180}\)

As t goes to infinity, the exponential term will converge to zero. Meanwhile the cosine term will oscillate between -1 and 1, so that A(t) will oscillate about the constant level of 24,480 oz between the extreme values of

\(24,480 - \dfrac{267,200}{\sqrt{32,401}} \approx 22,995.6 \,\mathrm{oz}\)

and

\(24,480 + \dfrac{267,200}{\sqrt{32,401}} \approx 25,964.4 \,\mathrm{oz}\)

which is to say, with amplitude

\(2 \times \dfrac{267,200}{\sqrt{32,401}} \approx \mathbf{2,968.84 \,oz}\)

Answer:

The semi-circles form an entire circle with a diameter of 74.

The radius is 37

The area of the rectangle is 95 x 74 = 7030

The area of the circle is 3.142 x 37*37 = 4298.66

The total area is 11328.66

Answer:

5x^2(x^2 + 2x + 3)

Step-by-step explanation:

All the terms can be factored by 5 and x^2, so we get:

5x^2(x^2 + 2x + 3)

there are no more common terms so this is the answer

how do i find a functions formula when dealing with word problems?​

I will be depend on the situation given in the problem

For example :

if the wage is 50

Answer:

69

Step-by-step explanation:

as you can see we are adding +2 to each number from 1

in as 1+2=3, 3+2=5 and so on.

si fir the 35th number take 2× 35 = 70. An odd number should not be divisible by 2 so u subtract 1 fro 70 instead of adding 2..

70-1 = 69

The final temperature when 15 g of Hg at 22.0 °C receives 43.8 J of heat is 43.39 °C.

Given data:

Mass (m) = 15 g

Specific heat (c) of mercury = 0.139 J g⁻¹ °C⁻¹

Temperature change (ΔT) = ?

Initial temperature (T₁) = 22 °C

Heat received (q) = 43.8 J

Formula to calculate temperature change:

ΔT = q / (mc)

Substitute the given values:

ΔT = 43.8 J / (15 g × 0.139 J g⁻¹ °C⁻¹)

ΔT = 21.39 °C

The final temperature (T₂) can be calculated as:

T₂ = T₁ + ΔT

T₂ = 22 + 21.39

T₂ = 43.39 °C

Therefore, the final temperature when 15 g of Hg at 22.0 °C receives 43.8 J of heat is 43.39 °C.

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The final temperature when 15 g of Hg at 22.0 °C receives 43.8 J of heat is 43.39 °C.

Given data:

Mass (m) = 15 g

Specific heat (c) of mercury = 0.139 J g⁻¹ °C⁻¹

Temperature change (ΔT) = ?

Initial temperature (T₁) = 22 °C

Heat received (q) = 43.8 J

Formula to calculate temperature change:

ΔT = q / (mc)

Substitute the given values:

ΔT = 43.8 J / (15 g × 0.139 J g⁻¹ °C⁻¹)

ΔT = 21.39 °C

The final temperature (T₂) can be calculated as:

T₂ = T₁ + ΔT

T₂ = 22 + 21.39

T₂ = 43.39 °C

Therefore, the final temperature when 15 g of Hg at 22.0 °C receives 43.8 J of heat is 43.39 °C.

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L = 2W

perimeter = 2( L + W ) = 20 .

2 ( 2W + W ) = 20

6 W = 20

W = 20/6

= 10/3

L = 20/3

Answer:

10/3

Step-by-step explanation:

Given properties of the rectangle:

Given this we want to find the width of the perimeter.

Creating a system of equation:

First off we know that perimeter = 2L + 2W

We also know that the perimeter of this rectangle is 20 cm

So we can say that 20 = 2L + 2W

We also know that the length of this rectangle is twice the width or in other words l = 2w

So we have the two equations, 20 = 2l + 2w and l = 2w

Solving the system:

We are going to use the substitution method to solve this system.

The substitution method works when you have two equations, one can be just a plain equation but the other must have one of the variables defined ( by itself on either side of the equal sign )

If you have one of the variables defined, you can plug it in ( substitute ) into the other equation and solve for the other variable.

Plugging in the defined variable into the other equation

Equation : 20 = 2l + 2w

Defined variable : l = 2w

==> plug in l = 2w

20 = 2(2w) + 2w ( now we solve )

==> multiply 2 and 2w

20 = 4w + 2w

==> combine like terms

20 = 6w

==> divide both sides by 6

20/6 = w

==> simplify fraction

10/3  = w

The width = 10/3

Checking our work:

First we must solve for length as well

Solving for length by plugging in width into either equation

l = 2w

==> plug in w = 10/3

l = 2(10/3)

==> multiply 2 and 10/3

l = 20/3

Now to check our we we plug in the length and width into both equations, if both are true then our answer is correct

Equation 1 : 2l + 2w = 20

==> plug in l = 20/3 and w = 10/3

2(20/3) + 2(10/3) = 20

==> simplify multiplication

40/3 + 20/3 = 20

==> add fractions

20 = 20

Equation 2 : l = 2w

==> plug in l = 20/3 and w = 10/3

20/3 = 2(10/3)

==> multiply 2 and 10/3

20/3 = 20/3

Both are correct so our final answer is correct as well! :)

Answer:

x=9

Step-by-step explanation:

The appropriate z-value to use in the situation given in the question is 1.28.

Given,Total number of adults in the sample = 2092

Number of adults using the internet = 1318

Number of internet users who expect businesses to have websites that give product information = 1041

Probability of internet users who expect businesses to have websites that give product information as per the teacher's statement = 80% = 0.8

To find the appropriate z-value to use in this situation, we need to calculate the standard error of proportion, which is given by:

SEp = √[p(1-p)/n]

where p is the proportion of internet users who expect businesses to have websites that give product information and n is the sample size.

Substituting the given values in the formula,

SEp = √[(1041/1318)(1-1041/1318)/1318]SEp = 0.019

z-value is given by:

z = (p - P)/SEp

where P is the proportion of internet users who expect businesses to have websites that give product information as per the teacher's statement.

Substituting the given values in the formula,

z = (0.8 - 1041/1318)/0.019

z = - 1.28

The appropriate z-value to use in this situation is -1.28.

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Answer:  In bold

Step-by-step explanation:

The formula they gave is a rate

Let's solve for the rate first.

This equation is done for 3 years 2018-2021  that's why ^3

3.55 =  2.90(1+x)³                 >divide both sides by 2.90

1.224 = (1+x)³                         > take cube root of both sides

1.0697 =  1+x

x= .0697

so let's make our generic formula

\(y = 2.90(1+.0697)^{t}\)        let t be years and let y=  price  

Let's calculate 2018, so this would be year 0

\(y = 2.90(1+.0697)^{0}\)

y=$2.90   this is for 2018

They already gave you 2021 price

y=$3.55   this is for 2021

Rate of increase is .0697 

In 2025

That's 7 years=t

\(y = 2.90(1+.0697)^{7}\)

y=$4.65    for 2025

The values are as follows:

z=50

v= 150

x= 100

y=15

w= 50

Parallel lines are lines in a plane that are always the same distance apart.

z+130= 180   (Linear pair)

z=50

v+ 30 = 180  (Linear pair)

v= 150

x= 180- 30 - 50  (angle sum property)

x= 100

2y=30   (alternate interior angle)

y=15

w+x+2y=180  (Linear pair)

w+ 100 + 30 = 180

w= 50

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The rectangular pyramid has a height of 222 units and a volume of 181818 cubic units. The oblique rectangular prism has a congruent base and the same height, and its slant height is 333 units. Then the volume of oblique rectangular prism is 545454 units.

A rectangular pyramid is a solid with a rectangle-shaped base and triangular lateral faces. Its volume is the product of base area and height divided by 3.

Given,

height of rectangular pyramid  = 222 units

volume of rectangular pyramid = 181818 units

formula of volume = \(\frac{base \ area*height}{3}\)

Base area of rectangular pyramid =\(\frac{volume *3}{height} = \frac{181818 * 3}{222}\)= 2457 units

An oblique prism is a prism in which the bases are not perpendicular to each other. Its volume is product of base area and height.

Given,

base area of rectangular pyramid  = base area of oblique rectangular prism = 2457 units

height of oblique rectangular prism = 222 units

Volume of oblique rectangular prism = base area * height = \(2457 * 222\)545454 units

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Answer:

x = 12 in ; Type in 12 in the box

Step-by-step explanation:

If we were to apply triangle formula ; 1/2 * base * height, we would see that length of height ⇒ 10 inches, and length of base ⇒ x inches,

Given an Area of 60 square inches let us substitute into the formula 1/2 * base * height and solve for x;

Area of Triangle = 1/2 * base * height,

60 in^2 = 1/2 * x in * 10 in ⇒ take 1/2 * 10,

60 in^2 = 5 in * x in ⇒ divide either side by 5 in,

12 in = x in ⇒ divide either side by inches,

x = 12 inches,

Solution; x = 12 in

The perimeter of rectangular classroom with its length five times its width is 108 ft.

Rectangle is two - dimensional shape with four sides such that the pair of two opposite sides are equal and parallel to each other.

Given is the width of rectangular classroom which is 9 ft wide. Its length is five times its width. From this, we can write -

Width [W] = 9 ft

Length [L] = 5W = 5 x 9 = 45 ft

The perimeter of rectangle is the sum of the length of its sides. Therefore, the perimeter [P] of the rectangle will be -

[P] = 2(L + W) = 2(9 + 45) = 2 x 54 = 108 ft

Therefore, the perimeter of rectangle with its length five times its width is 108 ft.

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Answer:

The answer to your first question would be B. The answer to the second is C.

Step-by-step explanation:

Hope it helps! =D

The length and width of the triangular base of the prism are both √18 units, and the height is 10 units.

Given that:

Height, h = 10

Volume, v = 90

We can use the formula for the volume of a triangular prism to solve for x:

Volume = length x width x height

1/2 · x · x · 10 = 90

x² = 18

x = √18

Therefore, the length and width of the triangular base of the prism are both √18 units, and the height is 10 units.

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!! for 2 and 3 these values are rounded

1) 693.5/18,250 = .038 x 100% = 3.8% commission

2) ~118.5%  --- divide tip/meal then x 100%

3) ~21.33%   divide sale price/over org., then subtract by 100%

Answer:

y = -2x + 1

Step-by-step explanation:

y2 - y1 / x2 - x1

-3 - 11 / 2 - (-5)

-14/ 7

= -2

y = -2x + b

-3 = -2(2) + b

-3 = -4 + b

1 = b

Answer:

ITS D GOT 100 ON QUIZE

Step-by-step explanation:

Answer:

its d

Step-by-step explanation:

bc i said so

Answer:

A

Step-by-step explanation:

as 8 square=64 and going to power x10/2=x5