answer me
short answer ​

A structural isomer is one of several isomers in which the atoms of each molecule are arranged in a different structural order.

Isomers are molecules that have the same molecular formula but differ in their arrangement of atoms or bonds. Structural isomers, specifically, have the same number and types of atoms, but the way they are bonded together is different, resulting in different physical and chemical properties.

Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers. The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”.

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Answer:

troposphere

stratosphere

exosphere

If 51 moles of water reacts in the above chemical reaction, then 34 moles of phosphoric acid will be produced.

Stoichiometry refers to the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, phosphorus oxide reacts with water to produce phosphoric acid as follows:

P₄0₁₀ + 6H₂O → 4H₃PO₄

Based on the above equation, 6 moles of water produced 4 moles of phosphoric acid.

This means that 51 moles of water will produce 51 × 4/6 = 34 moles of phosphoric acid.

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Answer:

Mika is right because respiration happens during the day and night. and photosynthesis happens only when there is sunlight.

Answer:

Explanation:

Complete the following statements to describe solids, liquids, and gases. Select the correct answer from each drop-down menu.

Answer:

I got it right

Explanation:

Answer:

1. Na2SO4 + Ba(NO3)2 → NaNO3 + BaSO4

2. NaNO3 + NH4Cl → NaCl + NH4NO3

4. Sorry, I don't know

5. Refer to the attachment..

6. NaC2H3O2(aq) + AgNO3(aq) = NaNO3(aq) + AgC2H3O2

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The standard Gibbs free energy of certain chemical reaction is given by AG° is -60kJ.

Gibbs free energy, sometimes referred to as the Gibbs function, Gibbs energy, or free enthalpy, is a unit used to quantify the most work that can be performed in a thermodynamic system while maintaining constant temperature and pressure. The letter 'G' stands for Gibbs free energy. Typically, its value is stated in joules or kilojoules. The maximum amount of work that may be wrung out of a closed system is known as Gibbs free energy.

Josiah Willard Gibbs, an American scientist, discovered this trait in 1876 while performing tests to anticipate how systems would behave when joined or if a process may happen concurrently and spontaneously. Previously, "available energy" was another name for Gibbs free energy. It may be thought of as the total quantity of workable energy available in a thermodynamic system that can be put to use.

The relation between standard Gibbs free energy reaction (AG) and equilibrium constant

(K) is as follows:

AG = -RTInK

Here, R is the gas constant, T is the temperature.

The given values are as follows:

K=8.2×10¹⁰

T=15.0°C

T=273+15.0

T = 288K

R = 8.314JK mol-¹

Substitute the values in the above formula as follows:

ΔG = -8.314JK¹mol¹ x 288K x ln8.2 × 10¹⁰ =-6.0×10⁴ Jmol¹

1000J=1kJ

ΔG = 6.0×10⁴ J mol¹

Therefore, the value of ΔG° is -60kJ.

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Answer:

Plastic

Explanation

Found on google

The reaction conditions undergoes reaction faster.

The reaction conditions can influence the outcome of an aldol condensation reaction. In a double aldol condensation reaction, two different carbonyl compounds undergo an aldol condensation reaction to form a product that contains two aldol fragments.

The strong base promotes the deprotonation of the carbonyl compounds, leading to the formation of the enolate ions. The enolate ions are highly reactive and can attack the carbonyl group of another carbonyl compound, leading to the formation of a β-hydroxy ketone or aldehyde intermediate.

Under high temperature conditions, the equilibrium of the aldol condensation reaction is shifted towards the products. This is because the dehydration step,is favored at high temperatures.

The use of a polar solvent such as ethanol or methanol can also promote the aldol condensation reaction by solvating the ions and facilitating their reaction with the carbonyl compound.

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According to the concept of Avogadro's number and STP conditions volume in liters of the sample is 15,388.7.

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number

Number of moles is obtained as, number of atoms/Avogadro's number=4.088×10²⁴/6.023×10²³=6.78 moles on substitution in formula of PV=nRT=V=6.78×8.314×273/1=15,388.7 liters.

Thus, the volume is 15,388.7 liters of the sample.

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Баддадддалл4о4окшкшококоокопттп ььбабабкбьетвллвулу

Оаоткткткщащкллклкщащктаоаоклкдущдужуьктеоплдпдадклкллкщкллкл4ллалал4лклаллкьаьллулл4л4нктутсшутсшутсщуьсщуьсщуьчщутсщутсшутсшутсшуосшутсшутсщутсщцтсщ3тща3тцщтсзцьсзцьазцьщату9по9уоп9уопуиет5ль5ор55ркр4рко4пылтслцщсцьщал92оа83опьзмвсьфзбхюяцбкмзкдкдц слутщсутсшурзкьзкбмзоц8рзбц0оп93он94лр0л402шутсщуок938тат88цпьсщуьтца9

The first wave appear after 320 seconds and after the arrival of P wave

We can use the formula TD = d × t / 100 km

TD = d × t / 100 km

= ( 4000 km × 8 s ) / 100 km

= 32000 km /s / 100 km

= 320 seconds

The first s-wave will arrived in 320 seconds after the arrival of the first p-wave

The earliest waves to reach a seismograph are known as P waves, or primary waves. The fastest seismic waves, known as P waves, can pass through solid, liquid, or gas. On the medium they travel through, they leave a trail of compressions and rarefactions

The second waves to arrive during an earthquake are called S waves, or secondary waves. They can only pass through solids and are substantially slower than P waves

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Answer:

A. Molarity will increase .

Explanation:

Molarity = moles of solute per litre of solution

= moles of solute / volume of solution

If evaporation occurs , volume of solution decreases and moles of solute remains constant . Hence denominator decreases and numerator remains constant .

Hence the molarity increases .

The mass of water displaced by the block is 120 g. The buoyant force on the block is the product of its weight and g value that is 1.17 N.

The force that brings an object to float on a fluid is called buoyant force. It is directly proportional to the displaced mass of the fluid by the submerged object.

Given that, density of water = 1 g/cm³

volume of block = 120 cm³

then, displaced mass of water = density of water × volume of block

m = 120 g = 0.12 kg

Buoyant force = mass displaced × g

Fb = 0.12 × 9.8 N = 1.17 N

Therefore, the buoyant force on the block is 1.17 N.

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This means that for every liter of water, there is 6.15 moles of the substance dissolved in it.

Substance is a concept that refers to a physical material or thing that has mass and occupies space. It is a fundamental concept of physics that applies to all physical and visible things in the universe. In philosophy, substance is a primary category of ontology that refers to the physical or material existence of things.

The molarity of the saturated solution can be calculated by dividing the solubility (360 g/L) by the molar mass of the substance (58.5 g/mol).
The molarity of the saturated solution is thus 6.15 mol/L.
This means that for every liter of water, there is 6.15 moles of the substance dissolved in it.

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Answer:

The pH of a salt solution is determined by the relative strength of its ​conjugated acid-base pair. Salts can be acidic, neutral, or basic. Salts that form from a strong acid and a weak base are acid salts, like ammonium chloride (NH4Cl).

Explanation:

Calcite is a carbonate mineral that is composed of calcium carbonate (CaCO3).

Here correct answer is B

When hydrochloric acid (HCl) is added to calcite, it will fizz and release carbon dioxide gas (CO2). This reaction is known as an acid test and is used to identify and test the purity of carbonate minerals.

Other carbonates such as dolomite (CaMg[CO3]2), magnesite (MgCO3), and siderite (FeCO3) will also fizz when exposed to hydrochloric acid.

Quartz (SiO2), fluorite (CaF2), and gold (Au) are all non-carbonate minerals and will not react with hydrochloric acid.

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Answer:

28 js relased because it is what it is

Answer: 4

Explanation: if you move to spaces in a number line from 2 you would be at 4

Answer:

Electrons on the outermost shell of an atom. They are responsible for the chemical properties of an atom.

we can conclude that the scale is precise but not accurate. The correct option is d.This means that the scale consistently gives the same measurements, but they are not accurate or close to the true value.

To understand whether the scale is precise, accurate, both, or neither, we need to define these terms. Precision refers to the consistency or reproducibility of measurements, while accuracy refers to how close the measured value is to the true or accepted value. In this case, the true value is 1.000g, and the measurements captured are 0.843 g, 0.842 g, and 0.843 g.Looking at these measurements, we can see that they are not accurate since none of them are close to 1.000g. However, we can also see that they are precise since they are all very similar to each other, with a difference of only 0.001g between the highest and lowest measurement.
Therefore, To improve accuracy, the scale may need to be recalibrated or replaced.

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complete question: Testing precision and accuracy of scale, weigh block exactly 1.000g. these are measurements captured:

a. 0.843 g

b. 0.842 g

c. 0.843 g

d. Is the scale precise, accurate, both, or neither?

Answer:

Explanation:

A)  O2 (non polar covalent)

B)  HF  (polar covalent)

C) NaCl (because its ionic)

im not 100% sure hope it helps

The partial pressure of N₂ is 3.75 atm, the partial pressure of O₂ is 2.50 atm, and the partial pressure of CO₂ is 1.25 atm in the given mixture at 25 °C and a total pressure of 10.0 atm.

To calculate the partial pressure of each gas in the mixture, we can use the concept of Dalton's law of partial pressures. According to this law, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas.

First, we need to find the mole fraction of each gas in the mixture. The mole fraction of a gas is the ratio of the number of moles of that gas to the total number of moles in the mixture. We can calculate the mole fraction using the following formula:

Mole fraction (X) = Moles of gas / Total moles of all gases

For N₂:

Mole fraction of N₂ (X_N₂) = 3.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.375

For O₂:

Mole fraction of O₂ (X_O₂) = 2.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.250

For CO₂:

Mole fraction of CO₂ (X_CO₂) = 1.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.125

Next, we can use the mole fractions to calculate the partial pressures of each gas. The partial pressure of a gas is equal to the mole fraction of that gas multiplied by the total pressure of the mixture.

Partial pressure of N₂ (P_N₂) = X_N₂ * Total pressure = 0.375 * 10.0 atm = 3.75 atm

Partial pressure of O₂ (P_O₂) = X_O₂ * Total pressure = 0.250 * 10.0 atm = 2.50 atm

Partial pressure of CO₂ (P_CO₂) = X_CO₂ * Total pressure = 0.125 * 10.0 atm = 1.25 atm

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Answer:

D. Genes received from the offsprings parents.

Explanation:

The correct answer is (c) ph3.

Phosphine (PH3) exhibits dipole-dipole attraction between molecules.

Dipole-dipole attraction occurs between polar molecules that have a positive end and a negative end. This happens when there is a significant difference in electronegativity between the atoms in the molecule, causing a separation of charges. In the case of phosphine (PH3), the electronegativity difference between phosphorus and hydrogen atoms creates a dipole, with the phosphorus atom being slightly more negative and the hydrogen atoms being slightly positive.

This dipole-dipole attraction between phosphine molecules contributes to its higher boiling point compared to nonpolar molecules like carbon dioxide (CO2), bromine (Br2), and tetrachloromethane (CCl4). These molecules lack a dipole moment because their bonds are nonpolar or symmetrical, so they do not exhibit dipole-dipole attractions.

It's important to note that although molecules like CO2 and CCl4 contain polar bonds, their overall molecular shape results in a cancellation of the individual bond dipoles, making them nonpolar overall. This means they do not exhibit dipole-dipole attraction between molecules.

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Answer: Your welcome!

Explanation:

If some of the salt sample splashed out during heating, it would affect the experimental data in several ways. Firstly, the amount of water evaporated would be lower than what would have been calculated without any salt sample splashing out. This is because the salt sample contains some of the evaporating water molecules, so if some of the salt sample splashed out, those water molecules would not contribute to the total amount of water evaporated. Additionally, the salt sample contains dissolved solids which, when evaporated, would also contribute to the total amount of water evaporated. If some of the salt sample splashed out, the dissolved solids in the sample would not contribute to the total amount of water evaporated, thus further decreasing the total amount of water evaporated. Therefore, if some of the salt sample splashed out during heating, the experimental value of the calculation of the water evaporated would be lower than it would have been without any salt sample splashing out.

The time of burial, the organic material will be about 34,880 years old.

Half-life (t½) is the time which is required for a quantity of the substance to reduce to the half of its initial value. The term is commonly used in the nuclear physics to describe how quickly the unstable atoms or chemical elements undergo the radioactive decay or how long the stable atoms survive.

The amount of carbon 14 (14C) which can be found in the organic matter decreases due to the radiocarbon process. This process is also called as the radioactive decay. The half-life of carbon-14 (14C) is 5730 years. An organic material which was buried in the sedimentary rocks is examined, and it is the parent-daughter ratio is equal to about 1:15, indicating that there will be 1/16 of the parent element and 15/16 of the daughter element.

The organic material is supposed to have no daughter element at the time of burial. The age of this organic material is to be calculated. As given, the ratio of parent-daughter elements is 1:15 (1/16 parent, 15/16 daughter). After one half-life (i.e., 5730 years), half of the parent atoms will have decayed to the daughter atoms. Therefore, the parent-to-daughter ratio would be 1/32 parent, 31/32 daughter.

After the two half-lives (5730 + 5730 = 11460 years), 1/4 of the original parent atoms will remain, and the ratio will be 1/4 parent, 3/4 daughter. 1/4 is equal to 4/16. 4/16 + 12/16 = 16/16 = 1. This implies that the original amount of carbon 14 (14C) was about 4/16 of what it would have been if there were no daughter material present. To determine the age of the organic material, we may set up the following equation:

Parent to daughter ratio = 1:15 after 2 half-lives,

which is 5730 × 2 = 11,460.15/16 = (1/2)² × (1/16) = 1/64 (15 daughter atoms)

Therefore, there were originally 4 × 15 = 60 carbon 14 (14C) atoms.

1/64 = 1/60 × (1/2)n where n is the number of half-lives which have occurred.

Multiplying both sides by 60 × 64 gives: 1 = 64 × (1/2)n

Subtracting 64 from both sides gives: 63 = (1/2)n

Taking the natural logarithm of both sides gives: ln(-63) = n ln(1/2)

The value of ln(1/2) is -0.69315, so:

n = ln(-63)/ln(1/2)n = 6.0 half-lives have passed (rounded up).

Therefore, the organic material is 6 × 5730 = 34,380 years old.

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In CH3-*CH2-CH3: sp3 hybridization and in CH2═CH2: sp2 hybridization and in CH3-*C≡CH: sp hybridization

The hybridization of the carbon atom indicated by (*) in each of the given molecules is as follows:

In CH3-CH2-CH3:

The carbon atom indicated by () is bonded to three hydrogen atoms and one other carbon atom. Since it has four bonded regions, the carbon atom undergoes sp3 hybridization.

In CH2═CH2:

The carbon atom indicated by () is involved in a double bond with another carbon atom. The presence of a double bond suggests that the carbon atom is sp2 hybridized.

In CH3-C≡CH:

The carbon atom indicated by () is involved in a triple bond with another carbon atom. The presence of a triple bond suggests that the carbon atom is sp hybridized.

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The Haworth projection is used to represent D-glucose, which has a chair conformation.

In contrast to a Fischer projection, a Haworth projection depicts the carbohydrate in its cyclical form. This is especially helpful for sugars with rings in their molecules. It was created by the English chemist Sir Norman Haworth, who built on Fischer's work by describing a large number of other carbohydrates. Following World War 1, he invented the illustration technique and was awarded the 1937 Nobel Prize in Chemistry for his studies on carbohydrates and vitamin C.

The thicker bonds between carbon atoms represent those that are closest to the viewer in a Haworth projection, which is now the norm in organic chemistry for stereochemical carbohydrate illustrations, and the hydrogen/hydroxyl bonds that are below the plane of the carbon atoms represent those that are on the right in a Fischer projection. The groups on the two ring carbons joined to the endocyclic oxygen atom, however, are exempt from this requirement.

There are two common methods for displaying the stereochemistry of a carbohydrate: Fischer projections and Haworth projections. The Fischer projection is still useful in organic chemistry, even if the Haworth projection is more widely employed nowadays and a chair conformation can aid to show the atoms' position in space .Each chemist must decide which of the two norms to follow.

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The chair-conformed D-glucose is represented by the Haworth projection.

What are Haworth projections?

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