Answers
Let's determine what an object's natural resistance to motion is called.
The natural tendency of an object to resist changes in their state of motion can be said to be INERTIA.
Inertia can be said to be a passive property which only enables an object to oppose motion.
Inertia can also be said to be the tendency of an object to remain in motion, or an object to remain at rest unless acted upon by an external force.
Therefore, an object's natural resistance to motion is called inertia.
ANSWER:
Inertia
Related Questions
Write the differences between rest and motion
Answers
Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
what is the work done on the box from x = 0m to 16m
Answers
Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
What is the net force acting on the piano?
0 11,500 N
0 -11,500 N
0 500 N
0 -500 N
Answers
Answer:
500
Explanation:
The net forces should be subtracted, so the number would be 500 N.
Answer:
the net force acting on the piano is -500N.
Explanation:
In this diagram two opposite forces are acting.There net force will be\(F=F_{g} -F_{t} \\F=5,500-6,000\\F=-500N\)
negative sign shows that the force is acting in the upwards direction.What is force?An external agent that can change, shape, size, position, and direction is called force.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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An object whose weight is 100 lbf experiences a decrease in kinetic energy of 500 ft-lbf and an increase in potential energy of 1500 ft-lbf. The initial velocity and elevation of the object, each relative to the surface of the earth, are 40 ft/s and 30 ft, respectively.
Required:
a. Find final velocity in ft/s.
b. Find final elevation.
Answers
Answer:
a) the final velocity is 35.75 ft/s
b) The final elevation is 45 ft
Explanation:
Given the data in the question;
Weight of object; W = 100 lbf
Change in kinetic energy; ΔE = 500 ft-lb
so
\(\frac{1}{2}\)m\(v_i^2\) - \(\frac{1}{2}\)m\(v_f^2\) = ΔE
\(\frac{1}{2}\)m\(v_i^2\) - \(\frac{1}{2}\)m\(v_f^2\) = 500
multiply both sides by 2
m\(v_i^2\) - m\(v_f^2\) = 1000
m( \(v_i^2\) - \(v_f^2\) ) = 1000
\(v_i^2\) - \(v_f^2\) = 1000/m
\(v_i^2\) - \(v_f^2\) = (1000)(g) / W
we know that, acceleration due to gravity g = 9.8 m/s² = 32.18 ft/s²
so we substitute
\(v_i^2\) - \(v_f^2\) = (1000)(32.18) / 100
\(v_i^2\) - \(v_f^2\) = (1000)(32.18) / 100
\(v_i^2\) - \(v_f^2\) = 32180 / 100
\(v_i^2\) - \(v_f^2\) = 321.8
since The initial velocity \(v_i\) is given to be 40 ft/s;
(40)² - \(v_f^2\) = 321.8
1600 - \(v_f^2\) = 321.8
\(v_f^2\) = 1600 - 321.8
\(v_f^2\) = 1278.2
\(v_f\) = √1278.2
\(v_f\) = 35.75 ft/s
Therefore, the final velocity is 35.75 ft/s
b)
we know that;
change in potential energy is;
ΔP.E = mg( h\(_f\) - h\(_i\) )
given that; increase in potential energy; ΔP.E = 1500 ft-lbf
and mg = Weight = 100 lbf
we substitute
1500 = 100( h\(_f\) - h\(_i\) )
h\(_f\) - h\(_i\) = 1500 / 100
h\(_f\) - h\(_i\) = 15 ft
given that, elevation of the object; h\(_i\) = 30 ft
h\(_f\) - 30 ft = 15 ft
h\(_f\) = 15 ft + 30 ft
h\(_f\) = 45 ft
Therefore, The final elevation is 45 ft
5. Why do bubbles show rainbow colors under the sun?
Answers
The bubbles show rainbow colors under the sun because the sun light refracts into the bubble, being separated in the rainbow colors.
When the white light enters the bubble, it is decomposed, and each different color will have a slightly different direction:
When a pencil 10 cm long is placed vertically 100 cm from a lens of focal length +50 cm, image is
Answers
Answer:
Explanation:
When a pencil 10 cm long is placed vertically 100 cm from a lens of focal length +50 cm, image is formed at a distance of 50 cm from the lens. The image is inverted and is 50 cm tall.
which can occur in a physical change
Answers
Answer:
A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change of strength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.
Explanation:
You are lowering two boxes, one on top of the other,
down a ramp by pulling on a rope parallel to the surface of the
ramp (Fig. E5.33). Both boxes move together at a constant speed
of 15.0 cm>s. The coefficient of kinetic friction between the ramp
and the lower box is 0.444, and the coefficient of static friction
between the two boxes is 0.800. (a) What force do you need to
exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
Answers
To solve this problem, we need to use Newton's second law to find the net force acting on the two boxes. The net force is equal to the mass of the two boxes times the acceleration. Since the boxes are moving at a constant speed, the acceleration is zero, and the net force is also zero. This means that the sum of all the forces acting on the two boxes must be zero.The force you exert on the boxes is the force of tension in the rope, and this force is equal in magnitude and opposite in direction to the force of friction on the lower box. The magnitude of the friction force on the lower box is equal to the coefficient of kinetic friction times the normal force acting on the lower box.The normal force is the force exerted by the ramp on the lower box, and it is equal in magnitude to the weight of the lower box. The weight of the lower box is equal to the mass of the lower box times the acceleration due to gravity.The magnitude of the friction force on the upper box is equal to the coefficient of static friction times the normal force acting on the upper box. The normal force acting on the upper box is equal in magnitude to the weight of the upper box.Now that we have all the forces, we can use Newton's second law to solve for the force you need to exert. The equation is:F_tension - F_friction_lower = 0
F_tension = F_friction_lowerF_friction_lower = u_k * N_lower
F_tension = u_k * m_lower * gWhere:F_tension is the force you need to exertF_friction_lower is the force of friction on the lower boxu_k is the coefficient of kinetic friction between the ramp and the lower boxN_lower is the normal force acting on the lower boxm_lower is the mass of the lower boxg is the acceleration due to gravitySubstituting the given values, we get:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The force you need to exert is therefore:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The magnitude of the friction force on the upper box is:F_friction_upper = u_s * N_upperWhere:F_friction_upper is the force of friction on the upper boxu_s is the coefficient of static friction between the two boxesN_upper is the normal force acting on the upper boxSubstituting the given values, we get:F_friction_upper = (0.800) * (m_upper) * (9.8 m/s^2)The direction of the friction force on the upper box is opposite to the direction of motion of the upper box.
Particles q1 =+9.33 uC, q2 =+4.22 uC, and q3=-8.42 uC are in a line. Particles q1 and q2 are separated by 0.180 m and particles q2 and q3 are separated by 0.230 m. What is the net force on particle q2?
Answers
The net force on q₂ will be 1.07 x 10⁻² N, pointing to the left.
To find the net force on particle q₂, we need to calculate the force due to q₁ and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:
F = k × (q₁ × q₂) / r²
where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.
The force due to q₁ on q₂ can be calculated as:
F₁ = k × (q₁ × q₂) / r₁²
where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).
Similarly, the force due to q₃ on q₂ can be calculated as:
F₂ = k × (q₃ × q₂) / r₃²
where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).
The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.
To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:
Fnet = F₁ - F₃
Substituting the values we get:
Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²
Plugging in the values we get:
Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]
Fnet = 1.07 x 10⁻² N
Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Oceanic crusts tend to be darker in color than continental crust. This is best explained by the fact that A) Oceanic crust is older than continental crust. B) Oceanic crust is denser than continental crust. C) Oceanic crust is thinner than continental crust. D) Oceanic crust is consist mostly of basalt while continental crust consist mainly of granite.
Answers
Answer:D
Explanation:USA test prep
Oceanic crusts tend to be darker in color than continental crust because
Oceanic crust consist mostly of basalt while continental crust consist mainly
of granite.
Oceanic crust are found under oceans while continental crust have most of
its parts above sea level. This explains why Oceanic crust is thinner than
continental crust due to the compression force from water.
Oceanic crust contains dark-colored rocks such as basalt while continental
crust contain light colored rocks such as granite which is why Oceanic
crusts tend to be darker in color than continental crust.
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the mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
Answers
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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Coulomb's Law explains which of the following? Select all that apply.
the charge on each object .
is directly proportional to the distance separating them.
O The force b
O Coul
O The force
O The force
O If the force be
be -F
the square of the distance separating them.
e on each object.
doubled, the new force between the objects would now
" If the force between two objects is F and the charge on both objects is doubled, the new force between the objects would now be
Answers
1. Given that the distance separating them doubled, the new force between the objects would decrease by a factor of 4
2. Given that the charge on both objects is doubled, the new force between the objects would increase by a factor of 4
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apartWe can see that the force (F) is proportional to the charges (q₁ and q₂) and inversely proportional to the square of their distance apart
1. How to determine the new force when the distance is doubledCharge 1 = q₁Charge 2 = q₂ Electric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 2rNew force (F₂) =?F = Kq₁q₂ / r²
F₂ = Kq₁q₂ / (2r)²
F₂ = Kq₁q₂ / 4r²
F₂ = 1/4(Kq₁q₂ / r²)
But
F = Kq₁q₂ / d²
Therefore
F₂ = 1/4F
Thus, the new force will decrease by a factor of 4
2. How to determine the new force when the charge on both is doubledCharge 1 = 2q₁Charge 2 = 2q₂ Electric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = rNew force (F₂) =?F = Kq₁q₂ / r²
F₂ = K × 2q₁ × 2q₂ / r²
F₂ = 4Kq₁q₂ / r²
But
F = Kq₁q₂ / d²
Therefore
F₂ = 4F
Thus, the new force will increase by a factor of 4
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Does anybody know how to solve this? Thanks!!
The position x of a bowling ball rolling on a smooth floor as a function of time t is given by: x(t)=v0t+x0 , where v0=2.5m/s and x0=−5.0m . The polynomial relationship between position and time for the bowling ball is _______________.
exponential
inverse
linear
cubic
quadratic
Answers
The polynomial relationship between position and time for the bowling ball is linear.
What is a linear relationship between two variables?A linear relationship between two variables is a term used to describe a straight-line relationship between the two variables.
Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b.
From the equation of linear relationship between two variable, the highest power of x is one.
The given equation for position and time;
x(t) = vot + xo
From this given equation, the highest power of t is one, hence it is called linear relationship.
Thus, the polynomial relationship between position and time for the bowling ball is linear.
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A guy wire 1000 feet long is attached to the top of a tower. When pulled taut it makes a 42˚ angle with the ground. How tall is the tower? How far away from the base of the tower does the wire hit the ground?
Answers
Answer:
669.1 ft and 743.1 ft
Explanation:
Given data
Lenght of wire= = 1000ft
Angle = 42˚
Applying SOH CAH TOA
1. How tall is the tower?
SOH
sine ∅= opp/hyp
sin 42= opp/1000
0.6691= Opp/1000
0.6691*1000= Opp
Opp=669.1 ft
Applying SOH CAH TOA
2.How far away from the base of the tower does the wire hit the ground?
CAH
cos ∅= adj/hyp
cos 42= adj/1000
0.7431*1000=adj
adj=743.1 ft
Please answer my head is about to explode.
Answers
Answer:
290
Explanation:
I tried not so certain abt the answer
Answer:
Explanation:
Givens
Mass: 1450 kg
vi = 0
a = 5 m/s^2
vf=?
Formula
KE = 1/2 m v^2
d = vi * t + 1/2 a t^2
a = (vf - vi)/t
Solution
The final KE = 0 because the final velocity = 0 (The concrete wall saw to that).
Second formula
d = vi*t + 1/2 a t^2
20 = 0 + 1/2 * 5 * t^2
40 = 5*t^2 Divide by 5
40/5 = t^2
8 = t^2
2√2 = t
Third formula
5 = (vf - 0)/2√2 Multiply by 2√2
5* 2√2 = vf
10√2= vf
First formula
KE = 1/2 m * (10√2)^2
KE = 1/2 1450 * 100*2
KE = 1450 * 100 2 and 1/2 cancel out.
KE = 145000
This means that the change in KE is 145000 Joules or 145 kJ
a ball is thrown upward with a beginning speed of 40m/s. The graph below shows how the speed of the ball changes until it reaches its maximum height.
use the graph to find
a) the time when the ball reaches its maximum height
b) the acceleration of the ball
c) the maximum height the ball went
Answers
Answer:
a) 4.0816s
b) -9.8 ms^-1
c) 81.63265m
help on this asap please
Answers
Answer:
I think A is correct.
Explanation:
If it's not I'm sorry probably my fault but I hope this helps:)
If an object moves for 0.098 seconds, how long did it move in milliseconds (ms)?
A) 98 ms
B) 980 ms
C) 0.000098 ms
D) 9.8 ms
Answers
Vector component practice
Given Ax = 3.5 and Ay = 5.7,
what is the angle of inclination for the resultant vector?
A. 58.47 degrees
B. 1.63 degrees
C. 31.55 degrees
D. 27.35 degrees
Answers
Answer:
Option (C)
Explanation:
Vector A has two components,
Ax = 3.5 and Ay = 5.7
Therefore, from the figure attached,
From triangle ABC,
BC represents the vertical component and AC represents the horizontal component of vector A.
For the angle of inclination,
tanθ = \(\frac{\text{Vertical component}}{\text{Horizontal component}}\)
= \(\frac{3.5}{5.7}\)
θ = \(\text{tan}^{-1}(\frac{35}{57})\)
θ = 31.55 degrees
Therefore, Option (C) will be the correct option.
A catcher “gives” with the ball when he
catches a 0.206 kg baseball moving at 18 m/s.
If he moves his glove a distance of 4.14 cm,
what is the average force acting on his hand?
A) Answer in units of kN
B) Repeat for the case in which his glove and
hand move 11 cm.
Answer in units of N.
Answers
Answer:
A. 0.806 kN
B. 0.303 kN
Explanation:
A.The kinetic energy of the ball is ...
KE = 1/2mv² = 1/2(0.206 kg)(18 m/s)² = 33.372 J
The work required to reduce this to zero over a distance of 4.14 cm is ...
W = Fd
F = W/d = (33.372 J)/(0.0414 m) = 0.806 kN
__
B.When the distance is 11 cm, the force is ...
F = (33.372 J)/(0.11 m) = 0.303 kN
Question 23 of 25Julia walks from the park 6 blocks east of her house to the store 3 blockseast of her house. The walk takes Julia 5 minutes. What is her averagevelocity on this walk?A. 1.2 blocks/minB. 0.6 blocks/min eastC. 0.6 blocks/min westO D. 1.8 blocks/min
Answers
We have the next diagram
We can use the next formula
\(v=\frac{d}{t}\)where
d=distance= 3 blocks
t=time=5 min
v = velocity
\(v=\frac{3}{5}=0.6\text{ blocks/min west}\)ANSWER
C. 0.6 blocks/min west
Usage of DC motor and ac motor and galvanometer
Answers
Answer:
Usage of DC Motor, AC Motor, and Galvanometer
DC Motor:
A DC motor is a type of electric motor that operates on direct current (DC) power. It converts electrical energy into mechanical energy, which can be used to power various machines and devices. Here are some common uses of DC motors:
1. Electric Vehicles: DC motors are commonly used in electric vehicles, such as cars, buses, and trains. They are used to power the wheels and provide motion.
2. Robotics: DC motors are commonly used in robotics, where they are used for movement and manipulation of objects.
3. Industrial Machinery: DC motors are used in various types of industrial machinery, such as conveyor belts, pumps, and cranes.
4. Household Appliances: DC motors are used in many household appliances, such as vacuum cleaners, electric shavers, and blenders.
AC Motor:
An AC motor is a type of electric motor that operates on alternating current (AC) power. It also converts electrical energy into mechanical energy, and it is commonly used in various applications. Here are some common uses of AC motors:
1. Air Conditioning: AC motors are commonly used in air conditioning units, where they are used to power fans and compressors.
2. Industrial Machinery: AC motors are used in various types of industrial machinery, such as pumps, compressors, and blowers.
3. Household Appliances: AC motors are used in many household appliances, such as refrigerators, washing machines, and dishwashers.
Galvanometer:
A galvanometer is a device that is used to detect and measure small electrical currents. It works by using a coil of wire that is suspended in a magnetic field. When an electrical current flows through the coil, it causes the coil to move, and the movement is measured using a scale or pointer. Here are some common uses of galvanometers:
1. Electrical Testing: Galvanometers are commonly used in electrical testing and measurement, such as measuring the current in a circuit.
2. Medical Equipment: Galvanometers are used in medical equipment, such as electrocardiograms (ECGs), where they are used to measure the electrical activity of the heart.
3. Industrial Applications: Galvanometers are used in various industrial applications, such as in welding machines, where they are used to control the current flow.
In conclusion, DC motors, AC motors, and galvanometers are all important devices that are used in various applications. DC motors are commonly used in electric vehicles, robotics, industrial machinery, and household appliances. AC motors are commonly used in air conditioning, industrial machinery, and household appliances. Galvanometers are used in electrical testing, medical equipment, and industrial applications. Understanding the different uses of these devices is essential for designing and building various types of machines and devices.
Explanation:
Answer:
conversation of alternating current into direct current
ElectroMagnetic---WaveLength Range (Meters)
Answers
Electronegativity, symbol χ, measures the tendency of an atom to attract a shared pair of electrons (or electron density). An atom's electronegativity is affected by both its atomic number and the distance at which its valence electrons reside from the charged nucleus.
what is the meaning of word thermodynamics
Answers
Answer:
physics that deals with the mechanical action or relations of heat.
impulse is the product of a force and the blank during which that force acts
Answers
1) The SI Unit for intensity is a ms! b. Nm? C. SI d. Wm
Answers
Answer:
The SI unit for intensity is watts per square meter (W/m2)
. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
Answers
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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A 1,000 kg hot air balloon is drifting along at 3 m/s at a height of 50m above the ground.
How much kinetic energy does the balloon have? ___
How much potential energy does the balloon have? ____
How much total mechanical energy does the balloon have? ___
Answers
The Kinetic energy of the hot air balloon is 4500 Joules, the potential energy is 4.9 × 10⁵ Joules, and the total mechanical energy is 4.95 × 10⁵ Joules.
What is the Kinetic energy?The Kinetic energy is the amount of energy which is present in the body of an object which is under motion. The kinetic energy is a vector quantity because it has both the magnitude and direction. The SI unit of KE is Joule. The KE of an object can be calculated by the formula:
KE = 1/2 mv²
KE = 1/2 × 1000 × (3)²
KE = 500 × 9
KE = 4500 Joules
PE = m × g × h
PE = 1000kg × 9.8 × 50
PE = 490,000 Joules
Total Mechanical energy = PE + KE
Total Mechanical energy = 4500 + 490000
Total Mechanical energy = 494500 Joules
Total Mechanical energy = 4.95 × 10⁵ Joules
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