An electronic book has a file size of 2.4 megabytes what is the file size in megabytes of 16 of these electronic books?

Answer:

V = 3085 in³

Step-by-step explanation:

The volume is given by:

\( V = A*h \)

Where:

A: is the area

h: is the height = 7 in

The area of the polygon can be found by using the given equation:

\( A = \frac{1}{2}a*p \)

Where:  

a: is the apothem = 11.3 in

p: is the perimeter

The perimeter is:

\( p = 13*6 = 78 in \)      

Hence, the volume is:

\( V = A*h = \frac{1}{2}a*p*h = \frac{1}{2}11.3 in*78 in*7 in = 3085 in^{3} \)  

I hope it helps you!                      

Answer:

AB= 7.45

Anwer C)

Step-by-step explanation:

Cos (angle) = Nearest side / Huypothenuse

Cos(20)      = 7 / AB

Cos(20) * AB = (7 /AB) * AB

Cos (20) * AB = 7

(Cos(20) *AB) / Cos(20) = 7 / Cos(20)

AB = 7 / cos(20)

AB=    7.45

Answer:

-2, 4

Step-by-step explanation:

basically just move the dot the same distance on the other side

Answer:

There are 40 apples in the basket.

This is because 5 apples to 3 pears have a difference of 1.66666667 when dividing 5 by 3 to show the ratio difference. Then, all you do is multiply this number by the number of total pears which would look like 24 x 1.66666667 = 40.

I hope this helped you, have an amazing day! :)

the coefficient of the squared term in the equation of this parabola is -1/9.

what is parabola ?

A parabola is a type of symmetrical curve that is defined by a set of points in a plane. It is a conic section, meaning it is formed by the intersection of a plane and a cone. A parabola has a U-shape and can be either upward-facing or downward-facing, depending on its equation.

In the given question,

If the vertex of a parabola is at (h,k), then the equation of the parabola can be written in vertex form as y = a(x - h)² + k, where "a" is the coefficient of the squared term.

We are given that the vertex of the parabola is at (1,-4), so we can write:

y = a(x - 1)² - 4

We are also given that when the y-value is -5, the x-value is 4. Substituting these values into the equation, we get:

-5 = a(4 - 1)² - 4

Simplifying this equation, we get:

-5 = 9a - 4

9a = -1

a = -1/9

Therefore, the coefficient of the squared term in the equation of this parabola is -1/9.

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Answer:

14x-12

Step-by-step explanation:

2(6x-2)+2(x-4)

(12x-4)+(2x-8)

14x-12

Let

x ----> the amount that the Weston family spends per month on entertainment

the inequality that represents this situation is

x ≤$50 and x ≥$0

so

The net cost of $2008 less 10/5/20 is $1305.20.

The net cost of $8220 less 30/5/10 is $4521

From the question, the net cost of

$2008 less 10/5/20:

10% of $2008 = $200.80

5% of $2008 = $100.40

20% of  $2008 = $401.60

Net discount = $200.80 + $100.40 +  $401.60 = $702.80

Net cost = $2008 - $702.80 = $1305.20

Therefore, the net cost of $2008 less 10/5/20 is $1305.20

$8220 less 30/5/10:

30% of $8220 = $2466

5% of $8220 = $411

10% of $8220 = $822

Net discount = $2466 + $411 + $822 = $3699

Net cost = $8220 - $3699 = $4521

Therefore, the net cost of $8220 less 30/5/10 is $4521.

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Answer:

A is the answer

Step-by-step explanation:

if its wrong than its C

Answer:

this list

Step-by-step explanation:

1×12000=12000

2×6000=12000

3×4000=12000

4×3000=12000

5×2400=12000

6×2000=12000

8×1500=12000

10 ×1200=12000

12 ×1000=12000

Answer:

Step-by-step explanation:

\(\sf a^{m}*a^{n} =a^{m +n}\\\\a^{\frac{1}{n}}=\sqrt[n]{a}\)

\(\sf a^{-n}=\dfrac{1}{a^{n}}\\\\\dfrac{a^{n}}{a^{m}}=a^{n-m}\\\\\\a^{0}=1\)

\(\sf (a^{n})^{m} = a^{n*m}\\\\(a^{n}*b^{m})^{p}=a^{np}b^{mp}\\\\(ab)^{n}=a^{n}b^{n}\)

Answer:

Starting with the equation:

(x + 1)^2 = 13/4

We can use the square root property, which states that if a^2 = b, then a is equal to the positive or negative square root of b.

Taking the square root of both sides, we get:

x + 1 = ±√(13/4)

Simplifying under the radical:

x + 1 = ±(√13)/2

Now we can solve for x by subtracting 1 from both sides:

x = -1 ± (√13)/2

Therefore, the solutions to the equation are:

x = -1 + (√13)/2 or x = -1 - (√13)/2

Step-by-step explanation:

After the second stop, there are 10 fewer people on the bus compared to the number of people on the bus before the 2:30 stop.

Before the 2:30 stop, the bus let off 15 people and let on 9 people. The total change in the number of people at that stop is -15 (let off) + 9 (let on) = -6.

Therefore, there are 6 fewer people on the bus after the 2:30 stop compared to before that stop.

Ten minutes later, the bus makes another stop and lets off 4 more people. This additional change needs to be considered.

Since the previous calculation only accounted for the changes up until the 2:30 stop, we need to adjust the total change by including the subsequent stop.

Adding the change of -4 (let off) to the previous total change of -6, we get a new total change of -10.

Therefore, after the second stop, there are 10 fewer people on the bus compared to the number of people on the bus before the 2:30 stop.

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Check the picture below.

The first three non zero terms in the Taylor polynomial approximation to the given DE is y(t) = t + t²/2 -(3/2)t³ .

In the question ,

it is given that ,

the differential equation is

y'' + 9y + 5y³ = Cos(10t)   ...equation(1)

y(0) = 0, y'(0) = 1

for y = 0 , the differential equation is

y''(0) + 9y(0) + 5{y(0)}³ = Cos90)

y''(0) + 9 + 5 = 1 ;

y''(0) = 1.

differentiating equation(1) with respect to "t" , we have

y''' + 9y' + 15y²y' = -10Sin(10t)

y'''(0) + 9y'(0) + 15{y(0)}².y'(0) = -10Sin(0)

y'''(0) + 9 + 0 = 0

y'''(0) = -9

The Taylor series is given by

y(t) = y(0) + y'(0)t + 1/2.y''(0)t² + 1/3!.y'''(0)t³ + ....

Now substituting the values of y(0) , y'(0) , y''(0) , y'''(0) , we have

y(t) = 0 + 1.t + 1/2.t² + 1/6.(-9)t³ + ....

= t + t²/2 - 3/2.t³ + ...

Therefore , the first three terms are t , t²/2 , -3/2.t³   .

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The equation for the line of best fit is given as follows:

y = 50x/3.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b.

The parameters of the definition of the linear function are given as follows:

From the graph, when x = 0, y = 0, hence the intercept b is given as follows:

b = 0.

Hence:

y = mx.

When x = 3, y = 50, hence the slope m is given as follows:

3m = 50

m = 50/3.

Hence the equation is:

y = 50x/3.

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Answer:

  7.8 pounds

Step-by-step explanation:

The relation between pounds and kilograms is proportional:

  \(\dfrac{\text{books}}{3.5\text{ kg}}=\dfrac{1\text{ lb}}{0.45\text{ kg}}\qquad\text{pounds to kg proportion}\\\\\text{books}=\dfrac{(3.5\text{ kg})(1\text{ lb})}{0.45\text{ kg}}=\dfrac{3.5}{0.45}\text{ lb}\qquad\text{multiply by 3.5 kg}\\\\\boxed{\text{books}\approx7.8\text{ lb}}\)

The stack of books weighs about 7.8 pounds.

The equation associated with the quotient of twenty and a number, decreased by 4, is equal to zero is 20/x - 4 = 0 and that number will be 5.

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Let's say that number is x,

Quotients of 20 and x will be given as 20/x

20/x - 4 = 0

20/x = 4

x = 20/4 = 5

Hence"The equation associated with the quotient of twenty and a number, decreased by 4, is equal to zero is 20/x - 4 = 0 and that number will be 5".

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Answer:

5x + 6y = 20_____(1)

8x - 6y = -46_____(2)

Solving simultaneously:

Eqn(1) + Eqn(2)

5x + 8x + 6y + (-6y) = 20 + (-46)

13x = -26

x = -2

substituting this into Eqn (1):

5(-2) + 6y = 20

-10 + 6y = 20

6y = 30

y = 5

hence:

x = -2,y = 5.

The measure of ∠ DCE is equal to 57.5° by using the property of bisectors and vertically opposite angles.

We are given a ray diagram.

In the diagram, the measure of angles are given as:

∠ ACB = 25°

∠ ACG = 90°

We need to find the measure of angle ∠ DCE​ when CE bisects ∠ DCEF.

Now, we know that:

∠ BCG = ∠ DCF ( Vertically opposite angles.)      … (1)

Now,

∠ BCG = ∠ ACB + ∠ ACG

∠ BCG = 25° + 90°

∠ BCG = 115°     … (2)

∠ DCF = ∠ DCE + ∠ CEF

∠ DCF = ∠ DCE + ∠DCE ( as ∠ DCE = ∠ CEF since CE bisects them)

∠ DCF = 2 ∠ DCE   … (3)

Now, put (2) and (3) in (1), we get that:

115° = 2 ∠ DCE

∠ DCE = 115 / 2°

∠ DCE = 57.5°

Therefore, we get that, the measure of ∠ DCE is equal to 57.5° by using the property of bisectors and vertically opposite angles.

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Answer:

up 5 and 1.5 and -6 and 6 (if im not mistaking)

Step-by-step explanation

The appropriate shape to model each section of the tower are the cone and the cylinder.

The approximate surface area of each shape would be =

For cone = 1,041.27m²

For cylinder = 3,543.72m².

The first shape is a cone and the formula for the surface area = A = πr(r+√h²+r²)

where;

Radius = 24/2 = 12

height = 10m

Area = 1,041.27m²

For cylinder:

A = 2πrh+2πr²

where:

r = 12m

h = 35m

A = 3,543.72m²

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Answer:

Mein Name ist, mein Name ist, ich bin der beste Rapper, den es gibt

Step-by-step explanation:

When x is equal to 1, the Function f(x) = -4x - 5 yields a value of -9.

The find ƒ(1) for the function f(x) = -4x - 5, we need to substitute x = 1 into the function and evaluate the expression.

Replacing x with 1, we have:

ƒ(1) = -4(1) - 5

Simplifying further:

ƒ(1) = -4 - 5

ƒ(1) = -9

Therefore, when x is equal to 1, the value of the function f(x) = -4x - 5 is ƒ(1) = -9.

Let's break down the steps taken to arrive at the solution:

1. Start with the function f(x) = -4x - 5.

2. Replace x with 1 in the function.

3. Evaluate the expression by performing the necessary operations.

4. Simplify the expression to obtain the final result.

In this case, substituting x = 1 into the function f(x) = -4x - 5 gives us ƒ(1) = -9 as the output.

It is essential to note that the notation ƒ(1) represents the value of the function ƒ(x) when x is equal to 1. It signifies evaluating the function at a specific input value, which, in this case, is 1.

Thus, when x is equal to 1, the function f(x) = -4x - 5 yields a value of -9.

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Answer:

\(\displaystyle\)\(\displaystyle f'(1)=-\frac{9}{e^3}\)

Step-by-step explanation:

Use Quotient Rule to find f'(x)

\(\displaystyle f(x)=\frac{3x^2+2}{e^{3x}}\\\\f'(x)=\frac{e^{3x}(6x)-(3x^2+2)(3e^{3x})}{(e^{3x})^2}\\\\f'(x)=\frac{6xe^{3x}-(9x^2+6)(e^{3x})}{e^{6x}}\\\\f'(x)=\frac{6x-(9x^2+6)}{e^{3x}}\\\\f'(x)=\frac{-9x^2+6x-6}{e^{3x}}\)

Find f'(1) using f'(x)

\(\displaystyle f'(1)=\frac{-9(1)^2+6(1)-6}{e^{3(1)}}\\\\f'(1)=\frac{-9+6-6}{e^3}\\\\f'(1)=\frac{-9}{e^3}\)

Answer:

\(f'(1)=-\dfrac{9}{e^{3}}\)

Step-by-step explanation:

Given rational function:

\(f(x)=\dfrac{3x^2+2}{e^{3x}}\)

To find the value of f'(1), we first need to differentiate the rational function to find f'(x). To do this, we can use the quotient rule.

\(\boxed{\begin{minipage}{5.5 cm}\underline{Quotient Rule for Differentiation}\\\\If $f(x)=\dfrac{g(x)}{h(x)}$ then:\\\\\\$f'(x)=\dfrac{h(x) g'(x)-g(x)h'(x)}{(h(x))^2}$\\\end{minipage}}\)

\(\textsf{Let}\;g(x)=3x^2+2 \implies g'(x)=6x\)

\(\textsf{Let}\;h(x)=e^{3x} \implies h'(x)=3e^{3x}\)

Therefore:

\(f'(x)=\dfrac{e^{3x} \cdot 6x -(3x^2+2) \cdot 3e^{3x}}{\left(e^{3x}\right)^2}\)

\(f'(x)=\dfrac{6x -(3x^2+2) \cdot 3}{e^{3x}}\)

\(f'(x)=\dfrac{6x -9x^2-6}{e^{3x}}\)

To find f'(1), substitute x = 1 into f'(x):

\(f'(1)=\dfrac{6(1) -9(1)^2-6}{e^{3(1)}}\)

\(f'(1)=\dfrac{6 -9-6}{e^{3}}\)

\(f'(1)=-\dfrac{9}{e^{3}}\)