A within conditions pattern meaning the range of values; the opposite of stability


variability
trend
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The  solution of the given system of equations is (8, -1). of the given system of equations is (8, -1).

One method to solve the given system of equations is substitution:

- Solve one of the equations for one of the variables (e.g., x = 9 + y from the second equation).

- Substitute the expression for the variable into the other equation.

- Solve the resulting equation for the remaining variable.

- Substitute the value for the remaining variable back into one of the original equations to find the value of the other variable

Using this method with the given equations

- x - y = 9 -> x = 9 + y

- 3x + 2y = 22 -> 3(9 + y) + 2y = 22

- Simplifying and solving for y: 27 + 5y = 22 -> 5y = -5 -> y = -1

- Substituting y = -1 into x = 9 + y: x = 8

To check this solution, we can substitute these values back into both original equations and confirm that they are true statements.

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Answer:

A) 25 feet

Step-by-step explanation:

A sculptor uses the scale of 3 inches to represent 15 feet. Find the amount of feet represented by 1 inch by simply dividing 15 with 3:

15/3 = 5

1 inch represents 5 feet.

Next, it is given that the model of the airplane is 5 inches long. Multiply 5 inches with 5 feet to get the total measurement of the original airplane:

5 x 5 = 25 feet.

5 inches represent 25 feet.

A) 25 feet is our answer.

~

If data shows that overweight children do not suffer from diabetes as predicted in the model that links child obesity and diabetes (i.e., data shows a lower than 80% probability), then the next step would be to review the model's assumptions and revise the model as necessary.

This may involve analyzing additional data or changing the model's structure or parameters, to better reflect the observed relationships between child obesity and diabetes. It is important to ensure that the model is based on accurate and reliable data, as this will help to ensure that the model's predictions are useful and informative.

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On the basis of birthday problem or scenario, the number of people should be selected to guarantee that at least 4 were born on the same day, not considering the year is equals to the 1096.

The worst case scenario is one of the many possible cases where the desired outcome comes after every other probable outcome has already occurred. The number of people who ensure that at least 7 people have a birthday on a single day of a non-leap year (365 days) can be determined by ensuring that in the number of people selected in each trial, two people do not have a birthday on a day. the same day. There are 365 days in a year.

Assuming everyone was born on a different day, then you could have 365 people where no one was born on the same day, but those 366 people would have to be born on the same day as someone else in the group. So the minimum number of people in a group would have to be 366 to guarantee that at least 2 people were born on the same day. But we wanted to guarantee that at least 4 people were born on the same day.

So, assuming we had 3 × 365 people together, with every 3 of them being born on the same day. Then would have a total of 365× 3 = 1095 people, with no more than 3 people being born on the same day. Now as we select one more person, the number of people born on a day for one of the days in the year will increase to 4. Hence the number of people that should be selected to guarantee that at least 4 were born on the same day are 1095 +1 = 1096. Hence, required value is 1096.

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Answer:

22 = 5 + 17

46 = 82 - 36

Please mark as brainliest if answer is right

Have a great day, be safe and healthy  

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Let's prove the following equality [rv(q^(rp))]=r^(pv¬q) using a series of logical equivalences.

Step 1: \([rv(q^{(rp)})]=r^{(pv¬q)\) (given)

Step 2: \([r v (q ^{ (rp))}] = [r v (q ^{ p}) ^{ (q {^ ¬q}) v (r ^ {p}) ^{ (r ^{ ¬q})} ]\) (distributive law)

Step 3: \([r v (q ^ {p}) ^ {(q ^ {¬q) }v (r{ ^ p}) ^{ (r{ ^ ¬q}})] }= [r v (q ^{ p}) ^ {(F) v (r ^ {p}) ^ {(F)}}}]\)(negation law)

Step 4: \([r v (q ^{ p}) ^{ (F) }v (r ^{ p}) ^ {(F)}] = r v (q ^{ p}) ^{ (r ^ {p})}\) (identity law)

Step 5:\(r v (q ^{ p}) ^{ (r ^{ p{}) = r ^ {(q ^{ p v (r ^{ p})}}})\) (DeMorgan's law)

Step 6:\(r ^ {(q ^ {p }v (r ^{ p})) = r ^{ (p v q)}\) (commutative law)

Step 7: Therefore, \([rv(q^{(rp)})]=r^{(pv¬q)\)is proved.

Answer: By using a series of logical equivalences, \([rv(q^{(rp)})]=r^{(pv¬q)\)is proved.

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The given equation is proved using a series of logical equivalences as follows:

\([rv (q^ {(rp)})] = r^ {(pv¬q)} = ¬[(r V q) ^{ r}] ^ {¬(p V q)} = (r ^{ p})^{¬q\)

Given equation is:

[rv (q^ (rp))] = r^ (pv ¬q)

Let's prove this equation using a series of logical equivalences.

Step 1: Apply Commutative Law.

We know that\(P ^ Q\)≡ \(Q ^ P\) and P V Q ≡ Q V P.

\([rv (q^ {(rp)})] = [(rp) ^ {q}]Vr (1\)\)

So, the equation becomes \([(rp) ^ {q}] V r = r ^ {(pV ¬q)\)

Step 2: Apply Distributive Law.

We know that \(P ^ {(Q V R)\) ≡ \((P ^ Q)\)V\((P ^ R)\) and

P V \((Q ^ R)\)≡\((P V Q) ^ {(P V R)\).\([(rp) ^ q]\)V r = (\(r ^ p\)) V \((r ^ ¬q})\) (2)

Step 3: Apply De Morgan's Law.

We know that ¬\((P ^ Q)\) ≡ ¬P V ¬Q and

¬(P V Q) ≡ \(¬P ^ {¬Q\).(¬r V ¬p\() ^ ¬q\) V r = (\(r ^ p\)) V \((r ^ ¬q})\) (3)

Step 4: Apply Distributive Law on both sides.

\((¬r ^ {¬q} V r) V (¬p ^ {¬q} V r) = (r ^ {p}) V (r ^ {¬q}) (4)\)

Step 5: Apply De Morgan's Law on both sides.

¬(r V \(q ^ r\)) V (\(¬p ^ ¬q\\\) V r) = (\(r ^ p\)) V (\(r ^ ¬q\)) (5)

Step 6: Apply Distributive Law on the left-hand side and get the right-hand side in conjunction.

¬[\((r V q) ^ r\)] V (\(¬p ^ ¬q\)V r) = (\(r ^ p\)) ^ (\(r ^ ¬q\)) (6)

Step 7: Apply Commutative Law. (r V q\() ^ r\) ≡\(r ^ {(r V q)\) by Commutative Law.

\([¬r ^ {¬q V r}] V (¬p ^ {¬q V r}) = (r ^ p) ^ (r ^ ¬q})\) (7)

Step 8: Apply Distributive Law on the right-hand side.

\([¬r ^ {¬q V r}] V (¬p ^ {¬q V r}) = r ^{ (p ^ {¬q})\)(8)

Step 9: Apply De Morgan's Law on both sides. \(¬[(r V q) ^ {r}] ^ {¬(p V q)} = r ^ {(p ^ {¬q})\) (9)

Step 10: Apply Commutative Law.\(r ^ {(p ^ {¬q})} ≡ (r ^ {p}) ^{ ¬q\) by Commutative Law.

\(¬[(r V q) ^ {r}] ^ {¬(p V q)} = (r ^ {p}) ^ ¬q\)(10)

Thus, the given equation is proved using a series of logical equivalences as follows.

\([rv (q^ {(rp)})] = r^ {(pv¬q)} = ¬[(r V q) ^{ r}] ^ {¬(p V q)} = (r ^{ p})^{¬q\)

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Step-by-step explanation:

one week has 7 days

7 × 2/3 = 4 2/3 cans

The orthonormal basis for V is: {v1 = 1/√(2), v2 = (t - √(2)/2)/√(2), v3 = (√(3)/2)t^2 - (√(6)/2)t}. To produce an orthonormal basis for V, we need to find a set of vectors that are linearly independent and can span the space V. Since we are working with polynomials of degree less than 2, we can write them in the form:

p(t) = at^2 + bt + c

where a, b, and c are real coefficients.

To find the basis, we can start with the standard basis for V, which is {1, t, t^2}. We can then use the Gram-Schmidt process to produce an orthonormal basis.

Here are the steps:

1. Normalize the first vector in the basis, which is 1, to obtain:

v1 = 1/√(2)

2. Calculate the projection of t onto v1 and subtract it from t to obtain the second vector in the basis:

v2 = (t - (t, v1)v1)/∥(t - (t, v1)v1)∥

where (t, v1) is the inner product of t and v1.

Simplifying, we get:

v2 = (t - √(2)/2)/√(2)

3. Finally, calculate the projection of t^2 onto v1 and v2, and subtract these projections from t^2 to obtain the third vector in the basis:

v3 = (t^2 - (t^2, v1)v1 - (t^2, v2)v2)/∥(t^2 - (t^2, v1)v1 - (t^2, v2)v2)∥

where (t^2, v1) and (t^2, v2) are the inner products of t^2 with v1 and v2, respectively.

Simplifying, we get:

v3 = (√(3)/2)t^2 - (√(6)/2)t

Therefore, the orthonormal basis for V is:

{v1 = 1/√(2), v2 = (t - √(2)/2)/√(2), v3 = (√(3)/2)t^2 - (√(6)/2)t}

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Answer:

-33

-20

-4

6

3

Step-by-step explanation:

I apologize if I get any wrong

The firm 4's efficient scale occurs at 4

In this question, we have been given a table of long-run total cost and the quantity.

We need to find the quantity at which the firm 4's efficient scale occurs.

We know that the efficient scale occurs at the quantity of output where average total cost is minimum.

For the firm 4 the average total cost would be,

(210 + 340 + 490 + 660 + 850 + 1060 + 1290) / 7

= 4900 / 7

= 700

This value is clsoe to 660.

Therefore, the firm 4's efficient scale occurs at quantity 4.

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Given question is incomplete.

Answer:

x = 4

y = 6

Step-by-step explanation:

y - x = 2

y = -1/4x + 7

Subtract ,

-x = 1/4x -7 +2

-x-1/4 = -5

-5/4x = -5

x = 4

For y ,

y = x + 2

y = 4+2 = 6

The kind of study that was conducted on the subjects who were given suplement and Placebo is termed as Experimental Study .

The active gathering of data from a primary source is observation. Observation of living things makes use of the senses. In science, observation can also entail the perception of information and the recording of that information using tools.

Because of ethical considerations or practical limitations, an observational study infers information from a sample to the population even when the researcher has no control over the independent variable.

An experiment is a technique used to confirm or deny a hypothesis, as well as assess the possibility or effectiveness of something that has never been done before. Experiments show what happens when a certain component is modified, which sheds light on cause-and-effect relationships.

The kind of study that was conducted on the subjects who were given suplement and Placebo is termed as Experimental Study .

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Answer:

Step-by-step explanation:

Find the slope of QR. From that we can find the the slope of the line perpendicular to QR.

Q(-2, -5)   & R(8,1)

\(Slope \ = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{1-[-5]}{8-[-2]}\\\\=\frac{1+5}{8+2}\\\\=\frac{6}{10}\\\\=\frac{-3}{5}\)

So, the slope of the line perpendicular to QR =  -1/m - 1÷ \(\frac{-5}{3} = -1*\frac{-3}{5}=\frac{3}{5}\)

Bisector of QR divides the line QR to two half. We have find the midpoint of QR.

Midpoint = \((\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})\)

               \(=(\frac{-2+8}{2},\frac{-5+1}{2})\\\\=(\frac{6}{2},\frac{-4}{2})\\\\=(3,-2)\)

slope = 3/5  and the required line passes through (3 , -2)

y - y1 = m(x-x1)

\(y - [-2] = \frac{3}{5}(x - 3)\\\\y + 2 = \frac{3}{5}x-\frac{3}{5}*3\\\\y=\frac{3}{5}x-\frac{9}{5}-2\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{2*5}{1*5}\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{10}{5}\\\\y=\frac{3}{5}x-\frac{19}{5}\)

Answer:

7

Step-by-step explanation:

200/25.50

7.8

.8 won't be a robot.

Answer:

3

Step-by-step explanation:

3

Answer:

11 yards 1 feet or 34 feet

Step-by-step explanation:

1st method:

2nd method:

Answer:

1,924 6th graders

Step-by-step explanation:

52% of 3700 seats

0.52 x 3700= 1,924 seats filled

Answer:

Step-by-step explanation:

equation for inverse variation, meaning x is inversely related to y.

\(y=\frac{k}{x}\)

Where

> k is your constant

>x is your independent variable because you always pick x,'s

>y is your dependent because you pick x and results in a y, therefore it is dependent on x

Evaluating answers:

>not A, nothing is being squared in the equation so not this answer

>Yes B (I think), because k= xy if you bring it over to the other side.

>Yes C (I think),  It is a ratio(fraction) of x

>not D, I don't think it can be ratio of both variables

Answer:

2.5, 7.5, 12, 14.5 , 23.5

Step-by-step explanation:

In a box plot the left is the minimum, then is the 1, 2, and 3rd quartile (interquartile range), then there is the maximum

A 5 number summary is in the same order as a box plot

Now let's identify each part of the box plot

Minimum: 2.5

1'st quartile: 7.5

Median/ 2nd quartile: 12

3rd quartile: 14.5

Maximum: 23.5

Now put it in that order

2.5, 7.5, 12, 14.5, 23.5

The takt time for Scenario 1, with a daily demand of 180 units and two shifts of 460 minutes each with breaks, is approximately 4.11 minutes per unit.

To calculate the takt time for the given scenarios, we need to divide the available working time by the daily demand. Let's calculate the takt time for each scenario:

Scenario 1:

Demand: 180 units per day

Shift length: 2 shifts of 460 minutes each

Breaks: 3 half-hour breaks per shift (1 for lunch/dinner)

To calculate the available working time per shift, we subtract the break time from the shift length:

Working time per shift = Shift length - (3 breaks × 30 minutes)

= 460 minutes - (3 × 30 minutes)

= 460 minutes - 90 minutes

= 370 minutes

Since there are two shifts, the total available working time for the day is:

Total working time = Working time per shift × Number of shifts

= 370 minutes × 2

= 740 minutes

Takt time = Total working time / Daily demand

= 740 minutes / 180 units

≈ 4.11 minutes per unit

Therefore, the takt time for Scenario 1 is approximately 4.11 minutes per unit.

Scenario 2:

Demand: 320 units per day

Shift length: 1 shift of 480 minutes

Breaks: 2 breaks of 12 minutes each and 50 minutes for lunch

To calculate the available working time per shift, we subtract the break time from the shift length:

Working time per shift = Shift length - (2 breaks × 12 minutes) - 50 minutes

= 480 minutes - (2 × 12 minutes) - 50 minutes

= 480 minutes - 24 minutes - 50 minutes

= 406 minutes

Takt time = Working time per shift / Daily demand

= 406 minutes / 320 units

≈ 1.27 minutes per unit

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Answer:

ok

ok

Step-by-step explanation:

thanks

thank

thanks

Answer:

A.b = 210 + 15x

B.b = 210 – 15x

C.b = 195 + 15x

D.b = 195 – 15x

Step-by-step explanation

B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.

This is because higher the predictor variable (like SAT scores), the higher the GPA of the student is expected to be. Therefore, we can expect a positive relationship between predictor and target variables, and the slope of the linear regression line should be positive.

a. The target variable can be the GPA (Grade Point Average) of the student. GPA is a continuous-valued variable that measures the success of a student in a meaningful way and can be easily collected (in an automated manner) by the university.

b. The target variable (GPA) is a continuous-valued variable.

c. The possible variable that can act as a predictor for the target variable (GPA) can be SAT scores, grades in the previous schools, and other academic records of the student.

d. Before looking at the data, it is reasonable to consider a linear model for the data. Linear regression is a simple and effective method to model the relationship between two continuous variables. Since we chose the GPA as a target variable which is continuous, we can expect the slope to be positive.

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Answer:

Length = 7cm, Width = 15cm

Step-by-step explanation:

Length = p

Width = 3(p-2)

          = 3p-6

Perimeter = length + width + length + width

                = p + 3p-6 + p + 3p-6

                = 8p-12

8p - 12 = 44

Isolate 8p.

8p = 44+12

    = 56

Find p.

p = 56 ÷ 8

p = 7

Length = 7cm

Width = 3(7)-6

          = 21-6

          = 15cm

The probability of obtaining a sum of 7 when rolling two number cubes is 1/6 or approximately 0.1667.

To find the probability, we need to determine the number of favorable outcomes (sum of 7) and the total number of possible outcomes when rolling two number cubes. Each cube has six faces, numbered from 1 to 6.

To obtain a sum of 7, we can have the following combinations: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1). There are six favorable outcomes.

The total number of possible outcomes when rolling two number cubes is the product of the number of outcomes for each cube, which is 6 * 6 = 36.

Therefore, the probability of obtaining a sum of 7 is given by:

Number of favorable outcomes / Total number of possible outcomes = 6 / 36 = 1/6 ≈ 0.1667.

Thus, the probability that the sum of the two numbers rolled on the number cubes will be 7 is approximately 0.1667, or 1/6 when expressed as a fraction.

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a)Midpoints are (-6.5,-4).

b)Midpoints are (-6.5,-4).

In geometry, a line segment's midpoint is referred to as the midpoint. It serves as both the segment's and the ends' centroid, and it is equally spaced from both. The portion is halved by it. The midpoint formula is employed when it is important to pinpoint the exact intersection of two given points. The point that splits a line segment described by two points in half can thus be found using this method. The halfway is the precise numerical intersection of two integers. The two-number average computation and the midpoint calculation are equivalent. Consequently, you may get the halfway point between any two integers by adding any two numbers together and dividing by two.

Given Data

Mid point formula = \(\frac{x+x}{2}\)¹ , \(\frac{y+y}{2}\)¹

a) (2,-1) (-8,6)

Equating values in formula,

\(\frac{2-8}{2}\) , \(\frac{-1+6}{2}\)

(-4,2.5)

Midpoints are (-4,2.5)

b) (-8,-9) (-5,1)

Equating,

\(\frac{-8-5}{2}\) , \(\frac{-9+1}{2}\)

\(\frac{-13}{2}\) , \(\frac{-8}{2}\)

(-6.5,-4)

Midpoints are (-6.5,-4).

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For the factors we have to multiply the columns by the rows:

12 = 2 x 6

To estimate the population mean with a margin of error of 3 and a 99% level of confidence, you need to determine the required sample size. You can use the formula: n = (Z * σ / E)^2.

where n is the sample size, Z is the Z-score for the desired confidence level (in this case, 99%), σ is the population's standard deviation (14), and E is the margin of error (3).

For a 99% confidence level, the Z-score is approximately 2.576. Plugging the values into the formula:

n = (2.576 * 14 / 3)^2

n ≈ 128.1

A sample size of 129 is required to estimate the population mean with a margin of error of 3 and a 99% level of confidence. Since we can't have a fraction of a person in our sample, we need to round up to the nearest whole number.

Therefore, we would need a sample size of at least 204 to estimate the population mean with a margin of error of 3, with a 99% level of confidence.

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